The device that detects light in the ultraviolet and infrared spectrums in order to alert occupants to fires is called a Flame Detector.
This device typically uses UV and IR sensors to identify the unique light signatures emitted by flames, allowing it to quickly and accurately detect fires and provide alerts to ensure occupant safety. A flame detector is a sensor created to recognize the presence of a flame or fire and act accordingly, enabling flame detection. Depending on the installation, possible responses to a flame detection include sounding an alarm, turning off a fuel line (such as a propane or a natural gas line), and turning on a fire suppression system.
When employed in industrial furnaces, for example, their purpose is to certify that the furnace is operating properly. They can also be used to turn off the ignition system, however frequently they don't do anything more than alert the operator or control system.
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pls help with my science homework
3b
A. Time taken for swing of a pendulum is 2.3 seconds per swing.
B. To find the time for one swing more accurately, the student can increase the number of swings, use a stopwatch with higher precision, minimize external disturbances, and repeat the experiment to calculate the average time.
The time taken for 20 swings of a pendulum is 46 seconds. To find the time for one swing, we need to divide the total time by the number of swings.
a. Time for one swing: 46 seconds / 20 swings = 2.3 seconds per swing.
To find the time for one swing more accurately, the student can employ the following techniques:
1. Increase the number of swings: By measuring the time for a larger number of swings, the student can reduce the impact of measurement errors and obtain a more precise average time. For example, measuring the time for 100 swings and then dividing by 100 would provide a more accurate estimate.
2. Use a stopwatch or timer with higher precision: Using a stopwatch or timer that provides more decimal places or higher precision can help capture smaller time intervals more accurately. This can reduce rounding errors and improve the accuracy of the measurement.
3. Minimize external disturbances: To ensure accurate timing, it is important to minimize external disturbances that may affect the pendulum's motion, such as air drafts or vibrations. Conducting the experiment in a controlled environment can help reduce these disturbances and enhance measurement accuracy.
4. Repeat the experiment: Performing the measurement multiple times and calculating the average time can help account for any inconsistencies or random errors in the measurements. This can lead to a more reliable and accurate estimate of the time for one swing.
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two common sources of irreversibilities that cause the differences between ideal and actual vapor-compression refrigeration cycles are:
Two common sources of irreversibilities that cause differences between ideal and actual vapor-compression refrigeration cycles are "pressure drops" and "heat exchange inefficiencies".
1. Pressure Drops: In an ideal vapor-compression cycle, there are no pressure losses in the refrigerant as it flows through the system. However, in actual systems, pressure drops occur in the evaporator, condenser, and connecting pipes due to friction and other factors.
These pressure losses lead to a decrease in the performance of the refrigeration cycle, as more work is required by the compressor to maintain the desired pressure levels.
To minimize pressure drops, engineers design systems with proper pipe sizing, smooth surfaces, and minimal bends or fittings.
2. Heat Exchange Inefficiencies: The second source of irreversibilities is the inefficiency in the heat exchange process between the refrigerant and its surroundings. In an ideal cycle, heat transfer between the refrigerant and the environment is assumed to be perfectly efficient.
However, in real systems, heat exchange is never 100% efficient due to factors like imperfect contact between heat exchange surfaces, temperature differences, and the presence of thermal resistances.
This results in a decrease in the overall efficiency of the refrigeration cycle. Engineers work to improve heat exchanger designs and optimize the system layout to enhance heat transfer and minimize inefficiencies.
By addressing these two sources of irreversibilities, engineers can develop more efficient and effective vapor-compression refrigeration systems that approach the ideal cycle's performance.
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Think about the reasons behind the cost of the Birkin bag and explain why it costs $60,000 in your own words. Do you think that this is a good marketing strategy? Why? Can you think of any other products (clothes / elctronics / anything) that use the same strategy? Does it work?
Answer:
In terms of both price and availability, the Birkin bag is as elusive as it is exclusive. For more than two decades, the bag has been the most sought item in the handbag industry. For such a modest bag, that's a lot of staying power (in looks alone, the design itself takes some 18 hours and is done by a single craftsman).
Of course, it's likely that the bag's rarity is what keeps it at the top of every want list. It is difficult, for example, to stroll into a Hermès store and buy a bag –– even if you could afford to pay the minimum price of $10,000. No, you have to be on an elite list to receive a Birkin.
Explanation:
There are alot more things like the Birkin Bag that use the same marketing skills and it works for alot of companies.
which of the following could be a good of electricity
Answer:
there is no picture to see
what should have happened to the grand unified force as the universe expanded and cooled at an age about
Grand unified force thermodynamically isolated its internal energy as the universe expanded and cooled at an age about.
The universe's evolution has been split into eras by cosmologists and astronomers.The Planck Era was followed by the Grand Unified Theory Era, which is the third stage of the evolution of the universe.Every era saw significant changes, so it is crucial to investigate what transpired there.Between 10-43 seconds and 10-35 seconds, the Grand Unified Theory Era took place. Such a brief period of time. This brief period of time is hard to imagine.Light has not yet been created in this era. Because of certain circumstances, such as high temperature and high pressure, particles and molecules still cannot bind.To learn about universe's evolution-
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help needed fast, I'm not good at physics, look at picture below ( I posted another page aswell, take a look on my profile) part #2
Answer:
I’d say the air outside the hemisphere is more free than from the inside of the hemisphere.
Explanation:
hope this help!
Explain what is happening in this
induction example.
Answer:
An electrical field duh
Explanation:
None needed self explanitory
The distance between Earth and the Moon was determined by measuring the time it took for light waves from Earth to travel to the Moon and back. Why was it not possible to use sound waves for this experiment?
Answer: there is no sound in space
Explanation: there is no vacum in space for sound to travel, therfore no sound waves
For water, which takes more energy, melting or evaporating?
Answer:
melting
Explanation:
that works best
what are the main obstacles Gey and his assistants faced in their effort to grow cells.
Make a claim about the time interval between lunar phases.
I will mark as BRAINLIEST ✨
just pls help ASAP
due by 4:00pm
plss
Answer:
The Lunar month is the time period for the moon to complete ONE revolution around Earth. SIDEREAL MONTH: 27.3 days SYNODIC MONTH: 29.5 days
A 1.5 kg ball is kicked with an initial velocity of 26 m/s at an angle of 30 degrees above the horizontal. How far did the ball go before returning to the ground? Answer in meters.
ANSWER ASAP!!! I AM GIVING EXTRA POINTS!!!! PLEASSEEE HELP!!!
The maximum height travelled by the ball before returning to the ground is 8.62 m.
What is the maximum height travelled by the ball?The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.
H = (u²sin²θ) / 2g
where;
u is the initial velocity of the ballθ is the angle of projection of the ballg is acceleration due to gravityH = (26² (sin 30)²) / (2 x 9.8)
H = 8.62 m
Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.
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Calculate the gravitational force between two bodies of masses 10kg and 55kg, if they are placed at a distance of 2m apart.
Answer:
F = 9.177*10^-9N
Explanation:
Gravitational force between the two bodies is expressed as;
F = GMm/r²
Given tha
M = 55kg
m = 10kg
r = 2m
G = 6.67408 × 10-11 m³ kg-1 s-2
Substitute;
F = GMm/r²
F = 6.67408 × 10-11*55*10/2²
F = 3,670.744× 10-11/4
F = 9.177*10^-9N
What two locations in the eye bend light?
a block of unkown material is submerged in water. light in the water is incident on the block at an angle of 31. the angle of refraction in the block is 27. what is the speed of light int his material?
The speed of light in the material is around 2.02 × 10⁸ m/s based on angle of incidence and refraction.
Firstly we will calculate the refractive index of the block followed by calculation of speed of light. The formula to be used for first is-
\( n_{2}\) = \( n_{1}\) × \( sin_{theta 1}\)/\( sin_{theta 2}\)
We know that refractive index of water is 1.33. So, the refractive index of material is -
\( n_{2}\) = 1.33 × sin 31/sin 27
\( n_{2}\) = 1.33× 0.5/0.45
Performing multiplication and division
\( n_{2}\) = 1.48
Now, the speed of light will be calculated using the formula-
v = c/\( n_{2}\)
v = 3×10⁸/1.48
v = 2.02 × 10⁸ m/s.
Hence, the speed of light is 2.02 × 10⁸ m/s.
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The reservoir stores 6 500 000 m3 of water. The density of the water is 998 kg/m3. Calculate the mass of water in the reservoir. Give your answer in standard form.
Answer:
Mass = 64,870,000,000 kilograms
Explanation:
Given the following data;
Density = 998 kg/m³
Volume = 6,500,000 m³
To find the mass of water in the reservoir;
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
Density = mass/volume
Making mass the subject of formula, we have;
Mass = density * volume
Mass = 998 * 6,500,000
Mass = 64,870,000,000 kilograms
Describe the energy of the skier at location W.*
At point W, potential energy is greatest and kinetic energy is least.
At point W, potential energy is least and kinetic energy is greatest.
At point W, potential energy and kinetic energy are the same.
Answer:
The description of the energy of the skier at point W is,
At point W, potential energy is greatest and kinetic energy is least
Explanation:
The given parameters are;
The highest point of the skier's path = Point W
The lowest point of the skier's path = Point X
The height of the peak after point X = Intermediate between point W and point X
The potential energy of the skier, P.E. = m·g·h
The kinetic energy of the skier, K.E. = 1/2·m·v²
The total mechanical energy of the skier, M.E. = P.E. + K.E.= Constant
Where;
m = The mass of the skier
g = The acceleration due to gravity = 9.8 m/s²
h = The height of the skier
v = The velocity of the skier
Therefore, the P.E. of the skier is highest at the highest point of the skier's path which is the point W, where h = Maximum
Similarly, the potential energy of the skier will be lowest at point X which is the lowest point on the skier's path
From P.E. + K.E. = constant, the kinetic energy will be least at point W, where the potential energy is highest.
Therefore, the description of the energy of the skier at point W is that the potential energy is greatest and kinetic energy is least.
A scientific law seeks to explain why an event ocurred
True or false
I thank it’s true hope u have a good day
According to the Law of Reflection, a light ray strikes a mirror ________________________________.
moves into the mirror at a slightly different angle.
continues moving through the mirror in the same direction.
bounces off the mirror towards the direction it came from.
bounces off the mirror at the same angle it hits the solid surface.
Answer:
bounces off the mirror at the same angle it hits the solid surface.
Explanation:
According to the Law of Reflection, a light ray strikes a mirror at the point of incidence bounces off the mirror at the same angle it hits the solid surface.
The incident ray and the reflected ray lie in the same plane
The angle of incidence is equal to the angle of reflection as a ray of light reflects off a solid surface.
So,
correct answer is ''bounces off the mirror at the same angle it hits the solid surface.''
Which of these things do you NOT want to have in your experiment? *
-A dependent variable
-An independent variable
-A constant
-A confound
write the poem titled is Handcuffs and write a dairy entry over two days as the speaker who is in prison.
Explanation:
The slum children in an elementary school look pathetic. Their hairs are uncombed. They look pale and shabby. They are undernourished and diseased
Which of the following is an example of a dry lubricant? oil grease graphite petroleum
ANSWER ASAP WILL GIVE BRAINLIEST!
Answer:
Dry lubricants or solid lubricants are materials that, despite being in the solid phase, are able to reduce friction between two surfaces sliding against each other without the need for a liquid oil medium.
Explanation:
Answer:
Your answer is graphite :) Have a nice day
Explanation:
Hey guys, can you please help me with this question?
A rectangular container of base 50 cm by 30 cm is filled with water to a depth of 5 cm. How much is the pressure exerted at the base? (Take p= 1000 kg/m3 and g=10m/s)
Answer:
the pressure exerted at the base of the container is 490 N/m²
Explanation:
Given;
density of water, ρ = 1,000 kg/m³
base of the rectangular container, = 50 cm by 30 cm
height of water in the tank, h = 5 cm = 0.05 m
The pressure exerted at the base of the container is calculated as;
P = ρgh
where;
g is acceleration due to gravity = 9.8 m/s²
P = 1000 x 9.8 x 0.05
P = 490 N/m²
Therefore, the pressure exerted at the base of the container is 490 N/m²
Plz help me I will mark brainlieat Ques. Write down name and molecular formula of a
Compound which gives hydrogen ion and sulphate on
in solution state. In which colour is the methyl Orange
changed after treating with this compound? Why?
Write name of salt when the same compound is
treated with sodium hydroxide Write down chemical
equation
when the distance between two stars decreases by one-third, the force between them group of answer choices increases to twice as much. increases to nine times as much. decreases by one-third. decreases by one-half.
When the distance between two stars decreases by one-third, the force between them increases to nine times as much.
Let's assume the initial distance between the stars is represented by "d." When the distance decreases by one-third, it becomes (2/3)d.
According to the inverse square law, the force between the stars is proportional to 1/d^2. So, initially, the force between the stars can be represented as F0 = k/(d^2), where k is a constant of proportionality.
After the distance decreases to (2/3)d, the force between them becomes F1 = k/((2/3)d)^2
= 9k/(4d^2)
= (9/4)(k/(d^2)).
Comparing F1 to F0, we can see that F1 is (9/4) times F0, which means the force increases by a factor of 9/4 or 2.25 times. Therefore, the correct answer choice is: "Increases to nine times as much."
It is important to note that none of the provided answer choices match the actual behavior described by the inverse square law. The force should increase by a factor of 2.25, not 2 or 9, and it does not decrease by one-third or one-half.
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Write the relation between mass and weight of a body
Answer:
\(\text{Weight} = \text{Mass} \times \text{Gravitational acceleration}\)
Explanation:
(a) Calculate the initial momentum of each object and write the result in rectangular form.(b) Calculate the momentum of the combined mass after collision and write the result in polar form.(c) Calculate the final velocity after collision and write the result in polar form.
Given data:
Mass of ball is,
\(m_b=5.75\text{ kg}\)Magnitude of initial velocity of ball is,
\(v_{ib}=5.75\text{ m/s}\)Direction of initial velocity of ball with respect to x-axis is,
\(\theta=30^o\)Magnitude of initial velocity of embeds is,
\(v_{ie}=2.50\text{ m/s}\)Direction of initial velocity of embeds with respect to x-axis is,
\(\theta_e=140^0\)Formula of momentum is as follows:
\(\vec{P}=m\vec{v}\ldots(1)\)Initial momentum of ball,
Component of velocity of ball along x-axis is as follows:
\(v_{ibx}=v_{ib}\cos \theta\)Substitute known values above equation,
\(\begin{gathered} v_{ibx}=6.34\times\cos 30^o \\ v_{ibx}=5.49\text{ m/s} \end{gathered}\)Component of velocity of ball along y-axis is as follows:
\(\begin{gathered} v_{iby}=v\sin \theta \\ v_{iby}=6.34\times\sin 30^o \\ v_{iby}=3.17\text{ m/s} \end{gathered}\)Therefore, momentum of ball is as follows:
\(\begin{gathered} \vec{P}=m(v_{ibx}\hat{i}+v_{iby}\hat{j}) \\ \vec{P}=5.75\text{ kg(5.49}\hat{i}+3.17\hat{j}) \\ \vec{P}=(31.5675\hat{i}+18.2275\hat{j})kg\text{ }\cdot\text{ m/s} \end{gathered}\)Component of velocity of embeds along x-axis,
\(\begin{gathered} v_{iex}=v_{ie}\cos \theta_e \\ v_{iex}=2.50\times140^o \\ v_{iex}=-1.915\text{ m/s} \end{gathered}\)Component of velocity of embeds along y-axis,
\(\begin{gathered} v_{iey}=v_{ie}\sin \theta_e \\ v_{iey}=2.50\times\sin 140^o \\ v_{iey}=1.61\text{ m/s} \end{gathered}\)Initial momentum of embeds is as follows:
\(\begin{gathered} \vec{P}=m_e(v_{iex}\hat{i}+v_{iey}\hat{j}) \\ \vec{P}=3.85\text{ kg(}-1.915\hat{i}+\hat{1.61\hat{j}})\text{ m/s} \\ \vec{P}=(-7.37\hat{i}+6.20\hat{j})\text{ kg}\cdot\text{ m/s} \end{gathered}\)Part-B:
After collision if both objects are stick together, this type of collision is called plastic collision.
Momentum of system remains constant before plastic collision and after plastic collision.
Hence,
\(\vec{P}+\vec{P}_e=\vec{P}_f\)\(\text{Here }\vec{\text{P}}_f\text{ is momentum of combine mass after collision}\)Substitute known values in above equation,
\(\begin{gathered} \vec{P}_f=(31.5675\hat{i}+18.2275\hat{j})+(-7.37\hat{i}+6.20\hat{j})_{} \\ \vec{P}=(24.1975\hat{i}+24.4275\hat{j})\text{ kg}\cdot\text{ m/s} \end{gathered}\)Polar form of momentum of combined mass is as follows:
Magnitude of momentum of combined mass is as follows:
\(\begin{gathered} P_f=\sqrt[]{(24.1975)^2+(24.4275)^2} \\ P_f=34.38\text{ kg}\cdot\text{ m/s} \end{gathered}\)Direction of momentum of combined mass,
\(\begin{gathered} \theta_f=\tan ^{-1}\frac{P_{fy}}{P_{fx}} \\ \theta_f=\tan ^{-1}(\frac{24.4275}{24.1975}) \\ \theta_f=45^o \end{gathered}\)Polar form of momentum,
\(P_f=(34.38\text{ kg}\cdot m/s,45^o)\)Part-C:
Final velocity of system is as follows:
\(\begin{gathered} \vec{P}_f=m_c\vec{v} \\ (24.1975\hat{i}+24.4275\hat{j})kg\text{ }\cdot\text{ m/s =}(5.75\operatorname{kg}+3.85\text{ kg)}\vec{\text{ v}} \\ \vec{v}=(\frac{24.1975}{9.6}\hat{i}+\frac{24.4275}{9.6}\hat{j}) \\ \vec{v}\text{ =(2.52}\hat{\text{i}}+2.54\hat{j})\text{ m/s} \end{gathered}\)Magnitude of final velocity is as follows:
\(\begin{gathered} v=\sqrt[]{2.52^2+2.54^2} \\ v=3.58\text{ m/s} \end{gathered}\)Direction of final velocity with respect to x-axis,
\(\begin{gathered} \theta_{fv}=\tan ^{-1}(\frac{2.54}{2.52}) \\ \theta_{fv}=\tan ^{-1}(1.00) \\ \theta_{fv}=45^o \end{gathered}\)Polar form of final velocity,
\(v=(3.58m/s,45^o)\)Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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how do newtons first and third laws describe the motion of an object?
Answer:
Newton's laws of motion relate an object's motion to the forces acting on it.
Explanation:
In the first law, an object will not change its motion unless a force acts on it. ... In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
When a mixture contains substances that are not evenly mixed, it is called Group of answer choices Compound Heterogeneous Mixture Homogeneous Mixture Pure Substance
Answer:
it is called Group of heterogeneous mixture
Explanation:
Because heterogeneous means uneven or with different compositions
So not evenly mixed will be heterogeneous mixture
Answer:
c
Explanation:
because thats it