Which describe colloids? Check all that apply. Heterogeneous mixtures have large dispersed particles may have a uniform appearance are made up of at least two substances will settle out over time.

Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Answer:

Shortest distance between 2 points is called displacemen.

Explanation:

This is because displacement means the distance between 2 points or really the negative distance.

Answer:

acceleration goes on increasing during uniform motio

this is wrong

Explanation:

Because during uniform motion acceleration is always zero .

Answer:69.8

Explanation:

Answer:

410.196 J/[kg*°C].

Explanation:

1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;

2) the specific heat of copper is:

\(c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].\)

The blood interacts with the bicarbonate, C03²-, from the acid to balance it when acid is supplied to the blood buffer system.

A buffer is a substance that can withstand a pH shift when acidic or basic substances are added. Small additions of acid or base can be neutralized by it, keeping the solution's pH level largely constant. For procedures and/or reactions that call for certain and stable pH ranges, this is significant.

Buffer solutions can resist the pH change when a strong acid or base is added sparingly. A strong acid and also its salt can be used as a buffer. It is a mixture of sodium acetate and acetic acid, CH3COOH + CH3COONa.

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Answer: it’s not A3X3

Explanation:

1. AX

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The amount of sulfur-33 isotopes are present in 10000 sulfur atoms are 76. It can be calculated by multiple the abundance of sulfur with total atoms.

In the term of chemistry,  natural abundance generally can be defined as the abundance of isotopes of a chemical element as naturally found on a planet. The relative atomic mass of these isotopes in the term of chemistry can be defined as the atomic weight listed for the element in the periodic table.

The amount of sulfur-33 isotopes are present in 10000 sulfur atoms = natural abundance of sulfur x total sulfur atoms

The amount of sulfur-33 isotopes are present in 10000 sulfur atoms = 0,76% x 10000

The amount of sulfur-33 isotopes are present in 10000 sulfur atoms = 0,0076 x 10000

The amount of sulfur-33 isotopes are present in 10000 sulfur atoms = 76 isotopes of sulfur 33

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The concentration of the MgCl2 solution, prepared by dissolving 23.80 g of solute in enough water to form 500 mL of solution, is approximately 0.1258 M.

To determine the concentration of a MgCl2 solution, we need to calculate the amount of solute (MgCl2) dissolved in the solution and express it in terms of concentration, typically in units of molarity (M).

Given that 23.80 g of MgCl2 was dissolved in enough water to form 500 mL of solution, we can start by converting the volume from milliliters to liters:

Volume of solution = 500 mL = 500/1000 = 0.5 L

Next, we calculate the moles of MgCl2 using its molar mass. The molar mass of MgCl2 is the sum of the atomic masses of magnesium (Mg) and two chlorine (Cl) atoms:

Molar mass of MgCl2 = 24.305 g/mol (Mg) + 2 * 35.453 g/mol (Cl) = 95.211 g/mol

Moles of MgCl2 = mass of MgCl2 / molar mass of MgCl2 = 23.80 g / 95.211 g/mol

Now, we can calculate the concentration using the moles of solute and the volume of the solution:

Concentration (Molarity) = Moles of solute / Volume of solution

Concentration = moles of MgCl2 / 0.5 L

Finally, we substitute the calculated values:

Concentration = (23.80 g / 95.211 g/mol) / 0.5 L

Concentration = 0.5 * (23.80 g / 95.211 g/mol)

Concentration ≈ 0.1258 mol/L or 0.1258 M

Therefore, the concentration of the MgCl2 solution is approximately 0.1258 M.

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Analog signals transmit information for such things as audio, video, and various physical measurements.

Analog signals represent continuous and varying quantities, such as sound waves or voltage levels, in a proportional manner.

These signals provide a more accurate representation of the original data, allowing for a faithful reproduction of the information being transmitted.

In the context of audio, analog signals are used to transmit sounds, whether it's music, speech, or any other auditory content. Similarly, analog signals are employed in video transmission to convey visual information,

enabling the display of images, movies, and television broadcasts.Analog signals are also utilized in various physical measurements, such as temperature, pressure, and voltage.

These signals enable the measurement and transmission of real-time data from sensors and instruments to monitoring systems or data acquisition devices.

Overall, analog signals are fundamental in transmitting and capturing a wide range of information, ensuring accurate representation and faithful reproduction of the original data in various fields and applications.

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Answer:

The answer is

Explanation:

The density of a substance can be found by using the formula

From the question

mass of cork = 2.88 g

volume = 12 mL

The density is

\( density = \frac{2.88}{12} \)

We have the final answer as

0.24 g/mL

Hope this helps you

ClO3-: The chlorine atom carries a single negative charge.

ClO4-: The chlorine atom carries a single negative charge.

NO3-:The nitrogen atom does not carry any charge, and the molecule as a whole carries a single negative charge.

Certainly! Here are the drawings of the molecules you requested:

1. ClO3-

   O

    |

Cl - O

    |

   O [-

2. ClO4-

   O

    |

Cl - O

    |

   O

    |

   O [-

3. NO3-

   O

    ||

N - O

    |

   O [-

4. SO3

 O

 ||

S - O

 ||

 O

Please note that for SO3, it does not carry any charge (neutral molecule), as requested.

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Answer:

convection

Explanation:

Answer: Convection is correct because of the currents that are placed when the heat comes up and the cooler liquid is going to the bottom!!!

Answer:

Elements are in the same amounts but they are different compound. So it is False:)

Explanation:

Good luck and stay safe!!

The pressure of the gas inside the cylinder is 52.90 atm

Given is the number of moles of gas, the temperature and the volume of the gas and we need to find the pressure of the gas inside the cylinder, for this we can use the ideal gas law equation:

PV = nRT

Where:

P = Pressure of the gas (in units of pressure, such as atm)

V = Volume of the gas (in liters)

n = Number of moles of the gas

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature of the gas (in Kelvin)

First, let's convert the temperature from Celsius to Kelvin:

T = 25.0 °C + 273.15 = 298.15 K

Now we can substitute the values into the ideal gas law equation:

P × 12.5 L = 27.0 moles × 0.0821 L·atm/(mol·K) × 298.15 K

Simplifying the equation:

P × 12.5 L = 661.2587 L·atm

Dividing both sides by 12.5 L:

P = 661.2587 L·atm / 12.5 L

P ≈ 52.90 atm

Therefore, the pressure of the gas inside the cylinder is approximately 52.90 atm.

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We can use the ideal gas law equation to determine the pressure of a gas within a cylinder:

PV = nRT

Where:

P is the pressure of the gas (in units of pressure, such as atm)

V is the volume of the gas (in units of volume, such as liters)

n is the number of moles of the gas

R is the ideal gas constant (0.0821 L·atm/(mol·K))

T is the temperature of the gas (in units of temperature, such as Kelvin)

we need to convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 25.0 °C + 273.15

T(K) = 298.15 K

Now we can plug the data into the ideal gas law equation as follows:

P * 12.5 L = 27.0 moles * 0.0821 L·atm/(mol·K) * 298.15 K

Simplifying the equation:

P = (27.0 moles * 0.0821 L·atm/(mol·K) * 298.15 K) / 12.5 L

Calculating the pressure:

P ≈ 5.046 atm

As a result, the gas inside the cylinder is under a pressure of about 5.046 atm.

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From the balanced equation, we can see that 3 moles of CaSO4 and 2 moles of H3PO4 are produced for every 3 moles of H2SO4 that react with 1 mole of Ca3(PO4)2.

Thus, we can use stoichiometry to calculate the amount of products formed when 10.0 moles of H2SO4 react with enough Ca3(PO4)2:

moles of CaSO4 produced = 10.0 moles H2SO4 × (3 moles CaSO4 / 3 moles H2SO4) = 10.0 moles CaSO4

moles of H3PO4 produced = 10.0 moles H2SO4 × (2 moles H3PO4 / 3 moles H2SO4) = 6.67 moles H3PO4

To calculate the mass of each product, we need to know their molar masses. The molar mass of CaSO4 is 136.14 g/mol, and the molar mass of H3PO4 is 98.00 g/mol. Thus, we can use these molar masses to convert the moles of products to grams:

mass of CaSO4 produced = 10.0 moles CaSO4 × 136.14 g/mol = 1361.4 g CaSO4

mass of H3PO4 produced = 6.67 moles H3PO4 × 98.00 g/mol = 653.86 g H3PO4

Therefore, when 10.0 moles of H2SO4 react with enough Ca3(PO4)2, 1361.4 grams of CaSO4 and 653.86 grams of H3PO4 are produced.

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A precipitate of lead(II)chloride forms when 120.0 mg of NaCl is dissolved in 0.250 L of 0.12 M lead(II)nitrate. This is true

Explanation :

True, a precipitate of lead(II)chloride forms when 120.0 mg of NaCl is dissolved in 0.250 L of 0.12 M lead(II)nitrate. To confirm this, we can use the Ksp value of PbCl2 and compare it with the reaction's Q value.

1. Calculate the moles of NaCl:
120.0 mg NaCl * (1 g / 1000 mg) * (1 mol NaCl / 58.44 g NaCl) ≈ 0.00205 mol NaCl

2. Calculate the concentration of Cl- ions:
[Cl-] = 0.00205 mol NaCl / 0.250 L ≈ 0.0082 M

3. Calculate the concentration of Pb2+ ions:
[Pb2+] = 0.12 M (since it is already given)

4. Calculate the reaction quotient, Q:
Q = [Pb2+] [Cl-]^2 = (0.12 M) * (0.0082 M)^2 ≈ 8.07 × 10^-6

5. Compare Q and Ksp:
Since Q (8.07 × 10^-6) is greater than Ksp (1.7 × 10^-5), a precipitate of lead(II)chloride will form.

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Answer:

Sodium hydroxide

Explanation:

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Nitric acid is a proton donor. (Acids are widely known as proton donors and the other cpds are bases).

Answer:

64 mL.

Explanation:

From the question given above, the dimension of box is:

Dimension = 2 cm × 4 cm × 8 cm

Thus, the volume of the box is:

Volume = 2 cm × 4 cm × 8 cm

Volume = 64 cm³

Finally, we shall convert 64 cm³ to mL. This can be obtained as follow:

Recall:

1 cm³ = 1 mL

Therefore,

64 cm³ = 64 cm³ × 1 mL / 1 cm³

64 cm³ = 64 mL

Therefore, the volume of the box in millilitres (mL) is 64 mL.

Answer: C

Explanation:

Answer: as a relatively high boiling point high specific heat connotation adhesion and density

Explanation:

water molecules are polar so they form hydrogen bonds this gives water unique properties

A, O and D

and its sulfur luv ♡ not sulphur

Answer:

Nucleus

Protons and neutrons

elements

periods

groups

Explanation:

Can I have brainliest?

Answer:

1. Nucleus

2. neutrons, protons

3. elements

4. periods

5. columns

Explanation:

Hope this help :>

The cell membrane which is more fat permeable will be present at the end of the process.

Solvent extraction is a very important method if separating mixtures. The principle of solvent extraction is based on the idea of like dissolves like. A substance dissolves in the component of the system in which it is most soluble.

If a cell extract is dissolved in a nonpolar solvent, the cell membrane which is mostly permeable to nonpolar molecules will dissolve most in the solvent.

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Answer:

A. chlorophyll

Explanation:

Plants use chlorophyll the most & I took the test.

The principal mechanism for sugar dissolving in water is dissociation. Sugar dissolving in water involves a process of solvation or hydration.

The polar water molecules surround the sugar molecules and break down their structure. The principal mechanism for sugar dissolving in water is not dissociation. Sugar dissolves in water due to a process called solvation, which involves the sugar molecules being surrounded by polar water molecules, breaking down the structure of the sugar.

Dissociation refers to the separation of ions or molecules in a substance that was formerly united. It occurs when an ionic compound dissolves in water, breaking down into its constituent ions. When sugar dissolves in water, it does not ionize or break down into separate ions; rather, it dissolves into individual sugar molecules.

Hence, the principal mechanism for sugar dissolving in water is solvation, not dissociation.

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1. Energy level is the discrete energy value possessed by an electron when it is in an orbital.

2. Sublevel is part of a main energy level consisting of one or two more electrons of the sublevel energy

In quantum chemistry, the electrons' state of motion within the electrostatic field produced by stationary nuclei is referred to as their electronic structure. Both the electrons' wave functions and the energies connected to them are covered by this phrase. In order to solve the aforementioned clamped-nuclei problem, quantum mechanical equations must be solved.

The Born-Oppenheimer approximation leads to problems with the electronic structure. One of the two steps in understanding a molecular system's quantum mechanical motion is the electronic structure problem, along with nuclear dynamics. Most electronic structure problems require the use of modern computers, with the exception of a small number of straightforward issues like atoms that resemble hydrogen.

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Answer:

n = 0.288 moles

Explanation:

Given mass = 32 g

The molar mass of CaCl₂ is:

M = 40.078 + 2(35.453)

= 110.98 g/mol

We need to find the number of moles in 32 g of CaCl₂. Let there are n no of moles.

\(n=\dfrac{\text{Given mass}}{\text{Molar mass}}\\\\=\dfrac{32}{110.98}\\\\=0.288\)

So, there are 0.288 moles in 32 g of CaCl₂

The molarity of a 3.555 M solution of procaine hydrochloride, which has a density of 1.102 g/ml, is 0.003555 M.

Given information:

Procaine hydrochloride (mw = 272.77 g/mol) is used as a local anesthetic.

The density of a 3.555 M solution is 1.102 g/mL.

To find the molarity of a 3.555 M solution, we need to use the below formula:

Molarity (M) = Number of moles of solute / Volume of solution in Liters1.

Calculate the number of moles of solute

The molecular weight of procaine hydrochloride (C13H20N2O2.HCl) is 272.77 g/mol.3.555 M solution means 3.555 moles of solute present in 1 liter of solution.

Number of moles = Molarity × Volume of solution in Liters

Number of moles = 3.555 × 1 L

Number of moles = 3.5552.

Calculate the volume of the solution in milliliters

1 L of solution will have a mass of 1102 grams because the density of the solution is 1.102 g/mL.

Volume of the solution = mass of solution / density of the solution

Volume of the solution = 1102 g / 1.102 g/mLVolume of the solution = 1000 mL

Finally, substituting the values in the molarity formula:

Molarity (M) = Number of moles of solute / Volume of solution in Liters

Molarity (M) = 3.555 moles / 1000 mL (1 L = 1000 mL)Molarity (M) = 0.003555 M

Therefore, the molarity of a 3.555 M solution of procaine hydrochloride, which has a density of 1.102 g/ml, is 0.003555 M.

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