Which data description techniques are NOT appropriate for visualising an attribute "Hair Colour", which has values "Black/Blue/Red/Orange/Yellow/White"? Select all that apply. bar chart step chart nor

Answer:

n = 10

Step-by-step explanation:

Using the rule of exponents

• \(a^{m}\) × \(a^{n}\) = \(a^{(m+n)}\)

• \((a^m)^{n}\) = \(a^{mn}\)

Then

2² × \(2^{n}\) = \((2^4)^{3}\)

\(2^{2+n}\) = \(2^{12}\)

Since the bases on both sides are equal, both 2 then equate exponents

2 + n = 12 ( subtract 2 from both sides )

n = 10

Answer:

x=1

Step-by-step explanation:

Answer:

x=1

Step-by-step explanation:

4x−7=−3x

Step 1: Add 3x to both sides.

4x−7+3x=−3x+3x

7x−7=0

Step 2: Add 7 to both sides.

7x−7+7=0+7

7x=7

Step 3: Divide both sides by 7.

7x

7

=

7

7

x=1

The required first term is 100 and the common ratio is 1.1 and the 11th term is 285.

Geometric progression is a sequence of series whose ratio with adjacent values remains the same.

Here,
Orignal price iss 100
Appreciates 10% each year,
So price on next year = 100 + 100 * 10 / 100
So the price next year = 110
Similarly price on the next year becomes in a series = 100, 110, 121,
Now, the first term of geometric progression = 100
Common difference = 110 / 100 = 1.1
11 the term = 100 * 1.1 ¹¹
11the term = 285

Thus, the required first term is 100 and the common ratio is 1.1 and the 11th term is 285.

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The constant of proportionality of the equation is 29.4

If the amount of money an accountant makes, m, is directly proportional to the time taken, this is expressed as:

m = kh

where;

k is the variation constant

Given that the amount of money an accountant makes, m, for working h hours is represented by the equation m = 29.4h, the variation constant is calculated as:

29.4h = kh

k = 29.4

Hence the constant of proportionality of the equation is 29.4

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Answer:

aftet 12 years they will have same population and the population will be 400

The expression that should be used to calculate the final cost of the gas grill is: Final cost = (1 - 0.4)*199 * 1.06.

What is percentage?

Percentage is a way of expressing a number or proportion as a fraction of 100. It is represented by the symbol "%".

To calculate the final cost of the gas grill, we need to find the discounted price after the 40% off and then add the sales tax of 6%.

The discounted price can be calculated by subtracting 40% of the original price from the original price:

Discounted price = original price - 40% of original price

Discounted price = 199 - 0.4*199

Discounted price = 119.4

The final cost can be calculated by adding the sales tax of 6% to the discounted price:

Final cost = discounted price + 6% of discounted price

Final cost = 119.4 + 0.06*119.4

Final cost = 126.38

So, the final cost of the gas grill after the sale and sales tax is $126.38.

Therefore, the expression that should be used to calculate the final cost of the gas grill is:

Final cost = (1 - 0.4)*199 * 1.06.

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Answer:

9=-57

Step-by-step explanation:

39+4

43

43+14

57

So 39+4+(-57)=-14

\(\\ 1. (3x ^{2} + 2xy + 7) - (6x ^{2} - 4xy + 3) \\ = 3x ^{2} + 2xy + 7 - 6x ^{2} + 4xy - 3 \\ = 3x ^{2} - {6x}^{2} + 2xy + 4xy + 7 - 3 \\ = { - 3x}^{2} + 6xy + 4 \\ 2. \: {9x}^{2} - 2x + 3 - ( {4x}^{2} + 7x - 5) \\ = 9x ^{2} - 2x + 3 - 4x ^{2} - 7x + 5 \\ = {9x}^{2} - {4x}^{2} - 2x - 7x + 3 + 5 \\ = {5x}^{2} - 9x + 8 \\ 3. \: {x}^{2} - 5x + 6 \\ = {x}^{2} - (3 + 2)x + 6 \\ = {x}^{2} - 3x - 2x + 6 \\ = x(x - 3) - 2(x - 3) \\ = (x - 3)(x - 2) \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment\)

Answer with step by step explanation

\((1)(3 {x}^{2} + 2xy + 7) - (6 {x}^{2} - 4xy + 3) \\ 3 {x}^{2} + 2xy + 7 - 6 {x}^{2} + 4xy - 3 \\ = - 3 {x}^{2} + 6xy + 4\)

\((2)9 {x}^{2} - 2x + 3 - (4 {x}^{2} + 7x - 5) \\ 9 {x}^{2} - 2x + 3 - 4 {x}^{2} - 7x + 5 \\ = 5 {x}^{2} - 9x + 8\)

\((3) {x}^{2} - 5x + 6 \\ {x}^{2} - 3x - 2x + 6 \\ x(x - 3) - 2(x - 3) \\ (x - 2)(x - 3)\)

hope this helps

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good luck! have a nice day!

Answer:

30 gallons solution 4% and 10 gallons solution 8%

Step-by-step explanation:

4x+8y=40•5 and x+y=40

x=40-y

4(40-y)+8y=200

160-4y+8y=200

4y=200-160

4y=40 => y=10 (gallons solution 8%)

=> x=40-10=30 (gallons solution 4%)

30 gallons solution 4% and 10 gallons solution 8%

the rectangular coordinates corresponding to the polar coordinates (5, π/6) are approximately (4.33, 2.5).

To convert polar coordinates to rectangular coordinates, you can use the following formulas:

Given polar coordinates (r, θ), where r represents the distance from the origin (or pole) to the point, and θ represents the angle between the positive x-axis and the line connecting the origin to the point:

Rectangular coordinate x = r * cos(θ)

Rectangular coordinate y = r * sin(θ)

Here's a step-by-step process for converting polar coordinates to rectangular coordinates:

1. Identify the given polar coordinates (r, θ).

2. Use the formula x = r * cos(θ) to calculate the rectangular coordinate x.

3. Use the formula y = r * sin(θ) to calculate the rectangular coordinate y.

4. The rectangular coordinates (x, y) represent the equivalent representation of the given polar coordinates.

For example, let's say we have polar coordinates (r, θ) = (5, π/6). To convert these to rectangular coordinates:

x = 5 * cos(π/6) = 5 * (√3/2) = 5√3/2 ≈ 4.33

y = 5 * sin(π/6) = 5 * (1/2) = 5/2 = 2.5

So, the rectangular coordinates corresponding to the polar coordinates (5, π/6) are approximately (4.33, 2.5).

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The value of the probability p(x > 105.0) for the given normal random variable is found as 0.6915.

For the stated question -

The formula for the z score -

z = (x - μ)/σ

In which,

μ = 140  and σ = 20

Put the values-

z = (150 - 140)/20

z = 0.5

p(x > 105.0) = p(z > 0.5)

p(x > 105.0) = 0.6915

Thus, the value of the probability p(x > 105.0) for the given  normal random variable is found as 0.6915.

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The complete question is-

suppose x is a normal random variable with μ = 140  and σ = 20 and find p(x > 105.0).

Answer:

D. – 5.58, -61, 61, 44, 7.25, $

hope this helps..:))))

Answer:

\(y=3x+6\)

Step-by-step explanation:

Equation of the line

The equation of the line in slope-intercept form is:

\(y=mx+b\)

Being m the slope and b the y-intercept.

We are given two points for the required line: The x-intercept is -2, thus the point is (-2,0), and the y-intercept b=6 represents the point (0,6).

Since the value of b is 6, we use the first point to find the slope:

\(0=m(-2)+6\)

Solving:

m=3

The correct equation of the line is:

\(\boxed{y=3x+6}\)

Answer:

c. x=1,000

Step-by-step explanation:

log x = 3

Imagine that it's log10 x = 3

So, x =  10^3 (10 to the third power)

x = 10 * 10 * 10

x = 1,000

The taxable income of Marcel and Stephanie is less than their annual salary because they are allowed to make deductions from their income before calculating their taxable income.

These deductions include contributions to retirement plans, health insurance premiums, and other eligible expenses. The amount of deductions varies depending on factors such as the type of expense and the individual's tax filing status.

Thus, the taxable income is the amount of income that is subject to taxation, and it is generally lower than the individual's annual salary. In the case of Marcel and Stephanie, their taxable incomes are calculated by subtracting their deductions from their respective annual salaries.

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Complete Question:

Why are Marcel's and Stephanie's taxable incomes less than their annual salary? Marcel's annual salary is $30,000 and his income is $17,450. Stephanie's annual salary is $50,000 and her income is $37,600.

Answer:

C:  (-8, 2)

Step-by-step explanation:

Given parabola:

\(y=-\dfrac{1}{8}x^2-2x-4\)

For the quadratic equation in the form y = ax² + bx + c, the x-value of the vertex is -b/2a.  

Therefore, the x-value of the vertex of the given parabola is:

\(\implies x=-\dfrac{b}{2a}=-\dfrac{-2}{2\left(-\frac{1}{8}\right)}=-8\)

To find the y-value of the vertex, input x = -8 into the given equation:

\(\implies y=-\dfrac{1}{8}(-8)^2-2(-8)-4=4\)

Therefore, the vertex (h, k) of the parabola is (-8, 4).

The focus of the parabola is (h, k+p) where:

Therefore:

\(\implies \textsf{Focus}=\left(-8,4+\dfrac{1}{4\left(-\frac{1}{8}\right)}\right)=\left(-8,2)\)

In this the correct choice is: D. There are no relative maxima and no relative minima.

The given function is y = \(x^{3}\) - 12x + 3. To find the relative maxima and minima, we need to calculate the first and second derivatives of the function.

First, let's find the first derivative: y' = 3\(x^{2}\) - 12

Now, let's find the second derivative: y'' = 6x

To apply the second-derivative test, we need to determine the critical points by setting the first derivative equal to zero and solving for x:

3\(x^{2}\) - 12 = 0

\(x^{2}\)- 4 = 0

(x - 2)(x + 2) = 0

From this equation, we find that x = 2 and x = -2 are the critical points.

Now, let's evaluate the second derivative at these critical points:

y''(2) = 6(2) = 12

y''(-2) = 6(-2) = -12

Since the second derivative at x = 2 is positive (12 > 0) and the second derivative at x = -2 is negative (-12 < 0), the second-derivative test tells us that there are no relative maxima or minima. Therefore, the correct choice is D. There are no relative maxima and no relative minima for the given function.

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The complete question is:

Test for relative maxima and minima. Use the second-derivative test, if possible. y=x3 - 12x + 3 Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. O A. The relative maxima occur at x = 2. The relative minima occur at -2. (Type integers or simplified fractions. Use a comma to separate answers as needed.) The relative maxima occur at x=-2. There are no relative minima. (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) O C. The relative minima occur at x = 2 . There are no relative maxima. (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) OD. There are no relative maxima and no relative minima.

Nanometer is a more easier way to represent the length of a virus as it can be represented the length in integer form.

The same attribute is expressed using a unit conversion, but in a different unit of measurement. For instance, time can be stated in minutes rather than hours, and distance can be expressed in kilometers, feet, or any other measurement unit instead of miles.

One nanometer is equal to 1 x 10⁻⁶ mm, which means that in 1 millimeter there are 1,000,000 nm

A length measurement using the metric system. One billionth of a meter is known as a nanometer. The thickness of a typical human hair is 60,000 nanometers. Light wavelengths and the separations between atoms in molecules may both be measured using nanometers.

1 nanometer = 10⁻⁶ mm

30 nanometer = 30 * 10⁻⁶ mm = 3* 10⁻⁵ mm

Nanometer is a more easier way to represent the length of a virus as it can be represented the length in integer form.

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Answer:

m>2 is the correct answer

Answer:

m > 2

Step-by-step explanation:

The arrow is pointing to the right, so m must be larger than 2. When the 'alligator mouth' is pointing to m, that means m is a higher number. It is the > symbol instead of ≥ because the circle is NOT filled in, so therefore NOT equal to or more than.

The answer is number 2 , or

m > 2

Answer:

23%

Step-by-step explanation:

322 ÷ 1400 = 0.23 = 23%

Step-by-step explanation:

The increase in draft will be 6.28 cm.

Given, the dimensions of the vessel are 100 m × 10 m × 6 m and it is floating upright in salt water on an even keel at 4.5 m draft.

Amidships compartment is 15 m long and contains timber cargo.

The stowage factor of timber is 1.4 m³/tonne and the relative density of timber is 0.8.

The volume of the compartment = Length × Breadth × Depth

= 15 m × 10 m × 6 m

= 900 m³

The weight of the timber = volume × relative density= 900 m³ × 0.8= 720 tonnes

The stowage space required = weight of timber ÷ stowage factor

= 720 tonnes ÷ 1.4 m³/tonne

= 514.29 m³

Due to the damage in the amidship compartment, its volume is reduced by 50% = 900 m³ ÷ 2

= 450 m³

Thus, the stowage space available after the bilging = total volume of the compartment – bilge volume

= 900 m³ – 450 m³

= 450 m³

The available stowage space can accommodate 450 ÷ 1.4= 321.43 tonnes of cargo.

Draft increase = (Loaded displacement - Light displacement) ÷ (Waterplane area × Waterplane coefficient)

The volume of the underwater part of the ship before bilging = 100 m × 10 m × 4.5 m

= 4500 m³

The volume of the underwater part of the ship after bilging = 100 m × 10 m × 4 m

= 4000 m³

The light displacement of the ship = (100 m × 10 m × 6 m × 1025 kg/m³) - 321.43 tonnes

= 6157142.86 kg

The displacement of the ship after loading timber = light displacement + weight of timber

= 6157142.86 kg + 720000 kg

= 6877142.86 kg

The waterplane area = Length × Breadth

= 100 m × 10 m

= 1000 m²

The waterplane coefficient for the given box-shaped vessel is 0.98 (given)

Therefore, the increase in draft of the vessel = (6877142.86 kg - 6157142.86 kg) ÷ (1000 m² × 0.98)

= 6.28 cm (approx.)

Therefore, the increase in draft will be 6.28 cm.

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The given information is,

→ Length (l) = 7 ft

→ Breadth (b) = 4 ft

→ Height (h) = 4 ft

Formula we use,

→ l × b × h

The volume of cuboid will be,

→ l × b × h

→ 7 × 4 × 4

→ [ 112 ft³ ]

Hence, the volume is 112 ft³.

Answer:

x = 3/4 n

Step-by-step explanation:

-3(x+n)=x

Distribute

-3x-3n = x

Add 3x to each side

-3x-3n+3x= x+3x

3n = 4x

Divide by 4

3/4n = 3x/3

3/4 n = x

Answer:

-32

Step-by-step explanation:

7^2 = 49

3^4 = 81

49-81=

-32

Answer:

Therefore, the book value of the equipment at the end of year four (including year four) is $2,880.

Step-by-step explanation:

To calculate the book value of the equipment at the end of year four using the MACRS method with GDS recovery period of five years, we can use the following steps in Excel:

1. Open a new Excel spreadsheet and create the following headers in row 1: Year, Cost, Depreciation Rate, Annual Depreciation, Cumulative Depreciation, and Book Value.

2. Fill in the Year column with the years 1 through 6 (since the truck has a life of six years).

3. Enter the cost of the truck, $12,000, in cell B2.

4. Use the following formula in cell C2 to calculate the depreciation rate for each year:

=MACRS.VDB(B2, 5, 5, 1, C1)

This formula uses the MACRS.VDB function to calculate the depreciation rate for each year based on the cost of the truck (B2), the GDS recovery period of five years, the useful life of six years, the salvage value of $2,000, and the year (C1).

5. Copy the formula in cell C2 and paste it into cells C3 through C7 to calculate the depreciation rate for each year.

6. Use the following formula in cell D2 to calculate the annual depreciation for each year:

=B2*C2

This formula multiplies the cost of the truck (B2) by the depreciation rate for each year (C2) to get the annual depreciation.

7. Copy the formula in cell D2 and paste it into cells D3 through D7 to calculate the annual depreciation for each year.

8. Use the following formula in cell E2 to calculate the cumulative depreciation for each year:

=SUM(D$2:D2)

This formula adds up the annual depreciation for each year from D2 to the current row to get the cumulative depreciation.

9. Copy the formula in cell E2 and paste it into cells E3 through E7 to calculate the cumulative depreciation for each year.

10. Use the following formula in cell F2 to calculate the book value of the equipment for each year:

=B2-E2

This formula subtracts the cumulative depreciation for each year (E2) from the cost of the truck (B2) to get the book value.

11. Copy the formula in cell F2 and paste it into cells F3 through F7 to calculate the book value for each year.

12. The book value of the equipment at the end of year four (including year four) is the value in cell F5, which should be $2,880.

Catalytic fixed-bed reactors are commonly used in the chemical industry for the production of chemicals, petroleum products, and other materials.

These reactors work by allowing a reactant gas to flow through a bed of solid catalyst particles, which cause the reaction to occur. The reaction products flow out of the reactor and are collected for further processing.

The design equations for a steady-state reaction in a fixed bed catalytic reactor are based on the principles of mass and energy balance. Here are the design equations for this type of reactor:

Mass balance:For the reactant, the mass balance equation is: (1) 0 =  +  + where:F0 = molar flow rate of reactant at inletF = molar flow rate of reactant at outletFs = molar flow rate of reactant absorbed by catalyst particlesFi = molar flow rate of reactant lost due to reaction.

For the products, the mass balance equation is:

(2) (0 − ) = ( − ) + where:Yi = mole fraction of component i in the inlet feedY = mole fraction of component i in the outlet productYs = mole fraction of component i in the catalystEnergy balance:

For a fixed-bed catalytic reactor, the energy balance equation is: (3)  = ∆ℎ0 − ∆ℎ +  + where:W = net work done by the reactor∆Hr = enthalpy change of reactionF0 = molar flow rate of reactant at inletF = molar flow rate of reactant at outletWs = work done by the catalystQ = heat transfer rate.

Fixed-bed catalytic reactors are widely used in the chemical industry to produce chemicals, petroleum products, and other materials. The reaction process occurs when a reactant gas flows through a solid catalyst bed. A steady-state reaction can be designed by mass and energy balance principles.

This type of reactor's design equations are based on mass and energy balance. Mass and energy balances are critical to the design of a reactor because they ensure that the reaction is efficient and safe. For the reactant, the mass balance equation is F0=F+Fs+Fi where F0 is the molar flow rate of the reactant at the inlet, F is the molar flow rate of the reactant at the outlet, Fs is the molar flow rate of the reactant absorbed by catalyst particles, and Fi is the molar flow rate of the reactant lost due to reaction.

For the products, the mass balance equation is Yi(F0−Fi)=Y(F−Fs)+YsFs, where Yi is the mole fraction of component i in the inlet feed, Y is the mole fraction of component i in the outlet product, and Ys is the mole fraction of component i in the catalyst.

The energy balance equation is

\(W=ΔHradialF0−ΔHradialF+Ws+Q\),

where W is the net work done by the reactor, ΔHr is the enthalpy change of reaction, F0 is the molar flow rate of reactant at the inlet, F is the molar flow rate of reactant at the outlet, Ws is the work done by the catalyst, and Q is the heat transfer rate.

Mass and energy balances are crucial when designing a fixed-bed catalytic reactor, ensuring that the reaction is efficient and safe.

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Answer:  To solve this problem, let's denote the legs of the isosceles right triangle as x and the hypotenuse as h. We are given that the legs are increasing in length at a rate of dx/dt, and we need to find the rates of change of the area and the hypotenuse.

a) To find the rate at which the area of the triangle is changing when the legs are m long, we can use the formula for the area of a right triangle:

Area = (1/2) * base * height

In an isosceles right triangle, the base and height are the same and equal to the length of the legs, x.

Area = (1/2) * x * x = (1/2) * x^2

Now, we can differentiate the area with respect to time, t, using the chain rule:

d(Area)/dt = (1/2) * 2x * dx/dt = x * dx/dt

d(Area)/dt = (1/2) * 2x * dx/dt = x * dx/dt

Therefore, the rate at which the area of the triangle is changing when the legs are m long is x * dx/dt.

b) To find the rate at which the area of the triangle is changing when the hypotenuse is m long, we need to express the length of the legs in terms of the hypotenuse using the Pythagorean theorem.

In an isosceles right triangle, the length of the hypotenuse, h, is equal to sqrt(2) times the length of the legs, x.

h = sqrt(2) * x

We can solve this equation for x:

x = h / sqrt(2)

Now, substitute this expression for x in the formula for the area of the triangle:

Area = (1/2) * x * x = (1/2) * (h / sqrt(2))^2 = (1/2) * h^2 / 2 = h^2 / (4 * sqrt(2))

Differentiating the area with respect to time, t, using the chain rule:

d(Area)/dt = (2h/ (4 * sqrt(2))) * dh/dt = h / (2 * sqrt(2)) * dh/dt

Therefore, the rate at which the area of the triangle is changing when the hypotenuse is m long is (h / (2 * sqrt(2))) * dh/dt.

c) To find the rate at which the length of the hypotenuse is changing, we differentiate the equation h = sqrt(2) * x with respect to time, t:

dh/dt = sqrt(2) * dx/dt

Therefore, the rate at which the length of the hypotenuse is changing is sqrt(2) times the rate at which the length of the legs is changing (dx/dt).

Answer:

AC = 10

Step-by-step explanation:

We can use proportions to solve

AB         AC

------ = -----------

DE        DF

5        AC

---- = -------

3        6

Using cross products

5*6 = 3 AC

30 = 3AC

Divide by 3

30/3 = AC

10 = AC

Answer:

Step-by-step explanation:

❁ Hello! ❁

AB/DE = AC/DF => 5/3 = AC/6

5/3 = AC/6

5 × 6 = 3 × AC

30 = 3 × AC

30 ÷ 3 = AC

10 = AC

Success! ☺️

Answer:

60 degrees

Step-by-step explanation:

just add 33 and 27

Answer:

60°C

Step-by-step explanation:

27 - (-33) = 27+33 = 60