Which contains the most moles: 10 g of hydrogen gas, 100 g of carbon, or 50 g of lead?

Gien the energy storages:

• Pumped Hydroelectric

• Flywheel

• Compressed Air

• Thermal Energy

Let's match the correct description to the type of energy storage.

• Pumped hydroelectric:

This is a type of hydroelectric storage. Here, the water is stored in an upper reservoir.

Therefore, the correct description is energy stored in water as gravitational potential energy.

• Flywheel

A flywheel is a device that stores rotational energy.

Therefore, the correct description is energy stored as kinetic rotational energy.

• Compressed Air:

For compressed air, the correct description is:

Energy is transferred to air that is forced under the ground at high pressure

• Thermal Energy:

This energy is possessed by an object due to the movement of particles in the object. It is produced when a temperature rise causes atoms and molecules to move faster.

Therefore, the correct description is Energy is used to cool water or make ice which can be used later for cooling when energy needs are high.

ANSWER:

Pumped Hydroelectric <==> Energy stored in water as gravitational potential energy.

Flywheel <==> Energy stored as kinetic rotational energy.

Compressed Air <==> Energy is transferred to air that is forced under the ground at high pressure

Thermal energy <==> Energy is used to cool water or make ice which can be used later for cooling when energy needs are high.

Answer:

Photosynthesis is a process used by plants and other organisms to convert light energy into chemical energy that, through cellular respiration, can later be released to fuel the organism's activities.

Explanation:

As water freezes below 4°C, the volume of the liquid shrinks and water molecule motion slows. When the temperature rises over 4 °C, the water molecules spread out and take up more space, increasing the volume.

Due to the peculiar property of water known as "Anomalous Expansion of Water," when 1 liter of water is cooled from 4°C to 0°C, the volume of the water starts to grow. Between 4°C and 0°C, water expands abnormally.

Water volume reduces as it is heated from 0°C to 4°C because the water's density will be maximum

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The frequency at which the capacitive reactance is 375 ω and the Capacitance of 3.25 μF is 131 s⁻¹.

Capacitance is the ability or capacity of the substance to collect and store electrical energy and the unit of capacitance is Farad (F). Capacitive reactance is the term that measures the opposition to current flow in the AC circuits and the unit of capacitive reactance is the ohm(Ω).

From the given,

The capacitive reactance (Xc) = 375ω

capacitance (C) = 3.25μF

capacitive reactance Xc = 1/(2π×f×C)

Frequency (f) = 1/(2π×Xc×C)

                     = 1/(2×3.14×375×3.25×10⁻⁶)

                     = 131 s⁻¹.

Thus, the frequency of the capacitive reactance is 131 s⁻¹.

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The reading on a vernier caliper can be represented as 45.75mm.

1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.

2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.

3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.

4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.

5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.

6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.

7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.

8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.

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The following list is the correct statement about the astronomer's scale of the brightness of stars and other objects based on the magnitude system:

In astronomy, magnitude is a unit used to describe how luminous a star or other celestial body is. The magnitude attributed to an object decreases as it becomes brighter. The brightest stars were found in the first magnitude class, which had six classes of magnitude. The scale of absolute magnitude. The brightness of an object is simply measured in terms of its absolute magnitude at a standard distance of 10 parsecs (32.6 light-years).

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Answer:

D.

The radioactive wastes it produces can spread to any part of the environment.

Explanation:

Fission is the name given to the splitting of a heavy nucleus into two medium-mass nuclei. Fission is said to be induced if it results from the absorption of a neutron to form an unstable nucleus that decays by fission. The induced fission usually produces further neutrons accompanying the fission fragments.

Answer:  D. The radioactive wastes it produces can spread to any part of the environment

Explanation:

Answer:

Refer to the step-by-step Explanation.

Step-by-step Explanation:

Simplify the equation with given substitutions,

Given Equation:

\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)

Given Substitutions:

\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)

Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)

Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the left-hand side of the equation:

\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

Simplifying the third term.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)

\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)

"R²'s" cancel, we are left with:

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)

We have like terms, combine them.

\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)

Each term has an "m" in common, factor it out.

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)

Now we have the following equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)

\(\hrulefill\)

Simplifying the right-hand side of the equation:

\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)

\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)

Now we have the equation:

\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

\(\hrulefill\)

Now solving the equation for the variable "v":

\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)

Dividing each side by "m," this will cancel the "m" variable on each side.

\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)

Subtract the term "gh" from either side of the equation.

\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)

Multiply each side of the equation by "10/7."

\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)

Now squaring both sides.

\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)

Thus, the simplified equation above matches the simplified equation that was given.  

The displacement covered will be 9.85 km

The distance covered will be = 10 + 4 + 1 = 15 km

using Pythagoras theorem

\(H^{2} = P^{2} + B^{2}\)

H  = \(\sqrt{4^{2} + 9^{2} }\)

H  = \(\sqrt{97}\)

H   = 9.85 km

The displacement covered will be 9.85 km

The distance covered will be = 10 + 4 + 1 = 15 km

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The charge R is positive and the charge L is negative hence, the correct option is option D.

The electric charges are of two types and they are positive and negative charge. There is an attractive force between the two charges. The electric field is formed around the charges and the electric field is denoted by using field lines around it.

The field lines are emerging from positive charge and end up in a negative charge. The field lines never intersect with each other. Hence, from the given, the field lines emerging from the positive charge(R) and end up in the negative charge(L).

Hence, the ideal solution is option D.

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Answer:

1,86

Explanation:

V=V0+a x t

8 m/s=0 m/s + a x 4,3 s

8m/s=a x 4,3 s

a= 8m/s / 4,3 s

a=1,86

V=Last speed

V0=Initial speed

a=acceleration

t=time

Chromatography is a laboratory technique for separating a mixture into its components.

What is Chromatography?

This is a laboratory technique for separating mixture. The mixture is dissolved in a liquid solvent (gas or liquid) called the mobile phase, which passes it through a system (column, capillary tube, plate, or sheet) to which the material is attached, called the stationary phase. Because different constituents of a mixture have different affinities for the stationary phase and are retained for different periods of time depending on their interaction with its surface, the constituents move with different apparent velocities in the moving fluid, causing them to separate. The separation is based on the differential partitioning of the mobile and stationary phases. Subtle differences in the partition coefficient of the compound result in differential retention in the stationary phase and thus affect the separation.

Chromatography can be analytical or preparative . The reason of analytical chromatography is to separate the components of a mixture for later use and then form of purification.This process is associated with higher costs due to the manufacturing method. Analytical chromatography is usually performed on smaller amounts of material and aims to determine the presence of analytes or measure their relative proportion in a mixture. The two types are not mutually exclusive.

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Answer:75.3 seconds

Explanation:

Using conservation of momentum, the initial momentum of the cannon and the projectile is equal to the final momentum of the cannon and the projectile:

m_cannon * v_cannon = (m_cannon + m_projectile) * v_final

where m_cannon is the mass of the cannon, v_cannon is the initial velocity of the cannon, m_projectile is the mass of the projectile, and v_final is the final velocity of the cannon and projectile together.

Substituting the given values gives:

210 kg * 0 m/s - 1 kg * 610 m/s = (210 kg + 1 kg) * v_final

Solving for v_final gives:

v_final = -1.83 m/s

The negative sign indicates that the cannon and projectile are moving in the opposite direction after the firing.

The time required to bring the cannon to rest can be found using the equation:

F_resistive = m_cannon * a

where F_resistive is the resisting force, m_cannon is the mass of the cannon, and a is the acceleration of the cannon.

Substituting the given values gives:

1,700 N = 210 kg * a

Solving for a gives:

a = 8.10 m/s^2

The time required to bring the cannon to rest can be found using the kinematic equation:

v_final = v_initial + a * t

where v_initial is the initial velocity of the cannon, which is equal to the muzzle velocity of the projectile, and v_final is zero. Solving for t gives:

t = -v_initial / a

Substituting the given values gives:

t = -610 m/s / 8.10 m/s^2 = 75.3 s

Therefore, the time required to bring the cannon to rest is 75.3 seconds.

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Answer:

The Rutherford model was devised by the New Zealand-born physicist Ernest Rutherford to describe an atom. Rutherford directed the Geiger–Marsden experiment in 1909, which suggested, upon Rutherford's 1911 analysis, that J. J. Thomson's plum pudding model of the atom was incorrect.

Atomic theory year: 1911

Explanation:

Hope this helps, Merry Christmas, and have a good day

Explanation:

13x - 26 + 39 = 0

13x=26-39

13x=-13

x= -1

\(13x-26+39=0\\\\\implies 13x +13 = 0\\\\\implies 13x = -13\\\\\implies x = -\dfrac{13}{13}\\\\\implies x = -1\)

Answer:

B. 2.5

not 2.5m because IMA is unitless.

The identical mechanical advantage of the inclined plane is 2.5.

The concept of work, which asserts that work produced through a basic machine (the lever) is equal to the work input, forms the basis for the mechanical advantage of the inclined plane. The length of the slope divided by the height of the inclined plane represents the inclined plane's mechanical advantage.

Given parameters:

Length of the inclined plane; d = 5 m.

Height of the inclined plane; h = 2 m.

So, identical mechanical advantage (IMA) of the inclined plane is = Length of the inclined plane ÷ Height of the inclined plane

= 5 m/2 m

= 2.5.

Hence, the  identical mechanical advantage (IMA) of an inclined plane that is 5m long and 2m high is 2.5.

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Answer:

619.2 Hz and 582.5Hz

Explanation:

Given that

Frequency of the generator, F(s) = 600 Hz

Length if the rope, r = 1 m

Speed of whirling, w = 100 rpm

For starters, we find the speed of the generator, v(g)

v(g) = r.w

It should be noted, however, that we are to convert the speed of whirling from rpm to rad/s, thus

100 rpm = 100 * 2π/60 rad/s

100 rpm = 200π/60

100 rpm = 620.4 / 60

100 rpm = 10.47 rad/s

Now, we use this to find the speed of the generator

v(g) = r.w

v(g) = 1 * 10.47

v(g) = 10.47 m/s

When approaching the generator, the frequency is calculated as

F(a) = F(s) / [1 - (v(g)/v)]

F(a) = 600 / [1 - (10.47/343)]

F(a) = 600 / 0.969

F(a) = 619.2 Hz

On the other hand, the receding generator frequency is

F(r) = F(s) / [1 + (v(g)/v)]

F(r) = 600 / [1 + (10.47/343)]

F(r) = 600 / 1.030

F(r) = 582.5 Hz

Therefore, we can conclude that the highest and lowest frequency is 619.2 Hz and 582.5 Hz respectively

Answer:

Explanation:

the answer is b

Answer:

Explanation:

its unbalanced

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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A marble rolls off a tabletop 1.15 m high and hits the floor at a point 4 m away from the edge of the table in the horizontal direction,

This is further explained below.

Generally, the equation for motion is mathematically given as

S= ut + 0.5at²

Therefore

y = Voy t + 0.5gt^2

1 = 0.5x 98 x 6²

1=4.9t^2

\(t=\sqrt{0.2041 }\)

t= 0.45 seconds.

b) Horizontal motions are uniform.

V=Horizontal displacement/time

V=1/0.45

V=2.22m/s

C)

Vx: 2.22 m/s At bottom,

Vy² = Voy² + 2as

Vy² = 2x95x1

Vy² = 19.6

Total velocity

\(VT=\sqrt{( 2.22 m/)^2+19.6}\)

VT=4.95 m/s

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Therefore the reaction force at wall A is -W.

Reaction is an action in response to a stimulus or event. It can be an emotional, physical, or mental response that occurs in the body and mind. When something happens, the body and mind react to it. For example, when someone hears a loud noise, they will usually flinch, jump, or take a deep breath. Reaction is a natural response to stimuli and can be both positive and negative. It can be as simple as feeling a slight smile when someone compliments you or as complex as feeling fear when faced with a dangerous situation. Reactions vary depending on the individual, their upbringing, and their environment.

Assuming the weight of the item is W and the reaction force at wall A is R, then the equation of equilibrium is:

W + R = 0

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Answer:

true, there are certain forms of bacteria in water that can cause permanent brain damage (although its rare) so further contamination of water can lead to higher chances of contracting serious illnesses caused by such bacteria.

Answer:

Mass and velocity are both directly proportional to the momentum. If you increase either mass or velocity, the momentum of the object increases proportionally. If you double the mass or velocity you double the momentum.

Explanation:

Answer:

see explanation

Explanation:

Answer:

a. 13.22 m/s

b. 16.32

c. 1.664 s

d. 13.58

e. 3.328

f. 40.0m

Explanation:

This is basically what the guy said, i dunno if you saw the letters, but he added some at the end of every answer.

Answer:

liquid.

Explanation:

That is almost the definition of a liquid. So the answer is a liquid.

Answer:

a = 7.749 ft/s²

Explanation:

First to all, we need to convert all units, so we can work better in the calculations.

The horizontal acceleration is asked in ft/s² so the units of speed will be the same. The Work is in BTU and we need to convert it in ft.lbf in order to get the acceleration and final speed in ft/s:

W = 10 BTU * 778.15 Lbf.ft / BTU = 7781.5 lbf.ft

Now, to get the acceleration we need to get the final speed of the object first. This can be done, by using the following expression:

W = ΔKe  (1)

And Ke = 1/2mV²

So Work would be:

W = 1/2 mV₂² - 1/2mV₁²

W = 1/2m(V₂² - V₁²)    (2)

Finally, we need to convert the mass in lbf too, because Work is in lbf, so:

m = 55 lb * 1 lbf.s²/ft / 32.174 lb = 1.7095 lbf.s²/ft

Now, we can calculate the final speed by solving V₂ from (2):

7781.5 = (1/2) * (1.7095) * (V₂² - 20²)

7781.5 = 0.85475 * (V₂² - 441)

7781.5/0.85475 = (V₂² - 400)

9103.83 + 400 = V₂²

V₂ = √9503.83

V₂ = 97.49 ft/s

Now that we have the speed we can calculate the acceleration:

a = V₂ - V₁ / t

Replacing we have:

a = 97.49 - 20 / 10

Hope this helps

The hypothesis will be:

H₀ = The amount of salt added to ice will not affect the rate at which the ice will melt.

H₁ =  The amount of salt added to ice will affect the rate at which the ice will melt.

The independent variable which is can be changed by increasing the rate of salt added to the equation.

The dependent variable which is ice will change or melt in response as it will decrease if the rate of the salt added increases.

Salt does not really lower the temperature of an ice cubes, it is known to just lowers their freezing point, that is lowers their melting point.

Note that if salt is around, ice cubes are known to be colder to be solid, and they tend to melt at a temperature that is said to be lower than the freezing point of pure water.

If  the ionic compound salt is known to be added, it tends to lowers the freezing point of the water, which implies that the ice on the ground is not able to freeze that layer of water at all.

Therefore, The hypothesis will be:

H₀ = The amount of salt added to ice will not affect the rate at which the ice will melt.

H₁ =  The amount of salt added to ice will affect the rate at which the ice will melt.

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