which compound has the smaller bond dissociation energy for its carbon-chlorine bond, ch3cl or (ch3)3ccl?

Answer:

670,385k

Explanation:

The major organic products and complete detailed mechanism for the given reactions are as follows:

1. CohisMgBr:

Mechanism:

The reaction between a Grignard reagent and an aldehyde or ketone is known as a Grignard reaction.

The reaction of the Grignard reagent with the carbonyl carbon of the aldehyde or ketone results in the formation of an alcohols molecule. So, in this reaction, the Grignard reagent will react with the carbonyl carbon of the aldehyde to form a secondary alcohol.

Major organic product: Secondary alcohol

2. NaH:

Mechanism:

The reaction of an alkene with a strong base, such as sodium hydride, leads to the formation of an alkene anion. The anion nucleophilic attacks the electrophilic carbonyl carbon, resulting in the formation of a new carbon-carbon bond.

Major organic product: Alkene

3. H3O+:

Mechanism:

The reaction of a tertiary alcohol with a strong acid, such as hydrochloric acid, results in the removal of the alcohol functional group.

In the presence of water, the acid catalyzes the protonation of the hydroxyl group, resulting in the formation of a carbocation.

Major organic product: Alkene

4. Bu-Li:

Mechanism:

The reaction of a ketone with butyl lithium results in the formation of a ketone anion.

The anion nucleophilic attacks the electrophilic carbonyl carbon, resulting in the formation of a new carbon-carbon bond.

Major organic product: Ketone

5. Acetone:

Mechanism:

In the presence of a strong acid, such as sulfuric acid, the hydroxyl group of the alcohol is protonated.

The resulting water molecule is eliminated, and the carbocation intermediate is formed.

The carbocation intermediate can then be attacked by a nucleophile to form a new carbon-carbon bond.

Major organic product: Alkene

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Answer:

yea I'm also looking for this question to .

Answer:

basically...

Explanation:

you gotta do this --> :)

Treatment of DCS may involve Recompression in a hyperbaric chamber.

Hence, Option (3) is correct answer.

DCS is Decompression Sickness which is followed by recompression in a hyperbaric chamber. They prevent long term effects.  It is also known as generalized barotrauma. It occur mostly in Scuba divers.

The sign and symptoms of DCS are

Thus from the above conclusion we can say that Treatment of DCS may involve Recompression in a hyperbaric chamber.

Hence, Option (3) is correct answer.

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Rutherford conducted a famous experiment called the gold foil experiment.

He took a skinny sheet of gold foil. He used a special gadget to shoot alpha particles undoubtedly charged debris on the gold foil. most debris passed straight thru the foil like the foil was now not there. They bombarded very skinny sheets of gold foil with fast-shifting alpha debris. Rutherford found that a small percent of alpha debris had been deflected at massive angles, which could be explained by using an atom with a very small, dense, definitely-charged nucleus at its middle.

Rutherford designed an experiment to apply the alpha particles emitted via a radioactive element as probes to the unseen global atomic structure. If Thomson changed into correct, the beam might move immediately through the gold foil. most of the beams went via the foil, however, some have been deflected. Ernest Rutherford postulated the nuclear structure of the atom, determined alpha and beta rays, and proposed legal guidelines for radioactive decay. In 1911, Rutherford, Marsden, and Geiger determined the dense atomic nucleus by bombarding a thin gold sheet with the alpha particles emitted through radium.

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Answer: the correct option is E.

Explanation : Phosphoric acid has three acid dissociation constants, Ka1, Ka2, and Ka3. To get the pH of 0.330 M phosphoric acid we use the acid dissociation constant of Ka1, which is 7.5 x 10^-3. We also have to make an assumption that all the H3PO4 ionizes and that the concentrations of H3PO4 and H2PO4^- are equal.Step 1H3PO4(aq) + H2O(l) ⇌ H2PO4^-(aq) + H3O^+(aq)Ka1 = [H2PO4^-] [H3O^+] / [H3PO4]where [H2PO4^-] and [H3O^+] are the same.Step 2Since H3PO4 is a weak acid, we can assume that the change in concentration is small as compared to the initial concentration of 0.330M.

Thus, we can make an assumption that the [H3PO4] initial - [H3O^+] = [H3PO4] initial. Therefore, the initial concentration is equal to the equilibrium concentration. Hence,[H3O^+] = √(Ka1[H3PO4] initial) = √(7.5 × 10^-3 × 0.330) = 0.060 MStep 3pH = -log[H3O^+] = -log(0.060) = 1.22Since the pH of 0.330 M phosphoric acid is 1.22 and 1.22 is not an option given, we need to check if the answer is an approximation.

The answer that is an approximation of 1.22 is 1.30 (option E), thus the pH of 0.330 M phosphoric acid is approximately equal to 1.30. Hence, the correct option is E.

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The concentration of urea in weight-percent 6.50%, in mole fraction is 0.0206 and in the concentration of urea in the solution in molarity is 1.12 M.

a) To express the concentration of urea in weight-percent:

First, we need to calculate the total mass of the solution:

Total mass = mass of solute + mass of solvent = 66.0 g + 950 g = 1016.0 g

Then, we can calculate the weight-percent concentration of urea:

Weight-percent = (mass of solute/total mass) x 100%

Weight-percent = (66.0 g/1016.0 g) x 100%

Weight-percent = 6.50%

Therefore, the concentration of urea in the solution in weight-percent is 6.50%.

b) To express the concentration of urea in mole fraction:

First, we need to calculate the number of moles of urea:

Number of moles = mass of solute/molar mass of urea

Molar mass of urea = 2(14.01 g/mol) + 1(12.01 g/mol) + 1(16.00 g/mol) = 60.06 g/mol

Number of moles = 66.0 g/60.06 g/mol = 1.099 mol

Then, we can calculate the mole fraction of urea:

Mole fraction = moles of solute/(moles of solute + moles of solvent)

Moles of solvent = mass of solvent/molar mass of water = 950 g/18.02 g/mol = 52.71 mol

Mole fraction = 1.099/(1.099 + 52.71) = 0.0206

Therefore, the concentration of urea in the solution in mole fraction is 0.0206.

c) To express the concentration of urea in molarity:

Molarity = moles of solute/volume of solution in liters

Volume of solution = mass of solute + mass of solvent/density of solution = (66.0 g + 950 g)/1.018 g/mL = 978.4 mL = 0.9784 L

Molarity = 1.099 mol/0.9784 L = 1.12 M

Therefore, the concentration of urea in the solution in molarity is 1.12 M.

Exercise:

To compare the concentrations of 0.50 M NaCl and 0.25 M SrCl2 in µg/mL, we need to calculate the number of micrograms of each salt per milliliter of solution:

For 0.50 M NaCl:

Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Concentration in µg/mL = 0.50 mol/L x 58.44 g/mol x 1000 µg/mg = 29,220 µg/mL

For 0.25 M SrCl2:

Molar mass of SrCl2 = 87.62 g/mol + 2(35.45 g/mol) = 198.52 g/mol

Concentration in µg/mL = 0.25 mol/L x 198.52 g/mol x 1000 µg/mg = 49,630 µg/mL

Therefore, the concentration of 0.25 M SrCl2 is larger than the concentration of 0.50 M NaCl when expressed in µg/mL.

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A spectrophotometry experiment involves spectrophotometer, blank solution ,sample solutions and cuvette .

Spectrophotometry is a method to measure how much a chemical substance absorbs light by measuring the intensity of light as a beam of light passes through sample solution. The basic principle is that each compound absorbs or transmits light over a certain range of wavelength.

This measurement can also be used to measure the amount of a known chemical substance. Spectrophotometry is one of the most useful methods of quantitative analysis in various fields such as chemistry, physics, biochemistry, material and chemical engineering and clinical applications.

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Answer:

The Machine exerts a force of 9N.

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 30 m/s

Time (t) = 0.5 s

Acceleration (a) = (v-u)/t

= (30-0)/0.5 m/s²

= 30/0.5 m/s²

= 60 m/s²

Mass = 0.15 kg

Force = Mass*Acceleration

= 0.15*60 N

= 9 N

Answer:

The Machine exerts a force of 9N.

Explanation:

Plato

Answer:

N2O3= Dinitride Trioxide

CO= Carbon Oxide

SO3= Sulfide Trioxide

Explanation:

Di= 2

Tri= 3

Answer:

0 lone pairs

Explanation:

The dispersion and mixing of particles would be made easier through the application of ultrasonic waves.

Ultrasonic waves can facilitate the dispersion and mixing of particles in an experimental procedure. When ultrasonic waves are applied, they generate high-frequency sound waves that create alternating compression and rarefaction waves in a liquid medium.

These waves produce tiny bubbles due to the phenomenon of cavitation. During cavitation, the bubbles rapidly expand and collapse, creating localized areas of high pressure and temperature.

This process exerts mechanical forces on the surrounding particles, leading to their effective dispersion and mixing. The energy from ultrasonic waves helps to break down agglomerates, disperse fine particles, and enhance the overall homogeneity of the mixture.

The application of ultrasonic waves can be particularly beneficial in procedures such as sample preparation, emulsification, dispersion of nanoparticles, and dissolution of substances. It improves the efficiency and effectiveness of processes that require uniform distribution and thorough mixing of components.

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When the flame turns on and heats the gas inside the hot air balloon, the volume of the gas increases.

This is because as the temperature of a gas increases, the molecules in the gas move faster and collide more frequently, creating a greater pressure. This increase in pressure causes the gas to expand, which results in an increase in volume. Therefore, when the flame turns on and heats the gas inside the hot air balloon, the gas molecules move faster, collide more frequently, and create a greater pressure, causing the gas to expand and the volume to increase.

This phenomenon can be explained using the Gas Laws, specifically Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature, as long as the pressure and the amount of gas remain constant.

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0.54g is the mass of carbon in  0.045 moles of carbon. Elementary particles shared the same quantity of matter.

A body's mass is an inherent attribute. Until the discoveries of the atom as well as particle physics, it was thought to be tied to the amount of matter inside a physical body. It was discovered that various atoms and elementary particles shared the same quantity of matter.

mole = given mass/ molar mass

substituting all the given values in the above equation, we get

0.045 moles = mass/ 12

mass =0.045×12= 0.54g

Therefore, 0.54g is the mass of carbon in  0.045 moles of carbon.

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Examples of mass media include published images, television and radio broadcast recordings, newspaper and the  magazine articles, commercials, sheet music, and the music that has been recorded for the widespread circulation.

There are several levels at which the individuals or institutions were involved in the creation and dissemination of a given mass media product, depending on the product that has been asked in the question.

A magazine article that has a lot of the mediation between the author and the reader compared to that of a mass-produced source like a 'zine or a personal blog which is  an editor, a copy editor, a publisher, an advertisers, a legal restrictions, etc.

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Answer:

As in ratio?

16 and 12 are both divisible by 4 (4x3 = 12 and 4x4 = 16)

Ratio of dogs to cats from 16 : 12 to

4 : 3

Answer:

4/3

Explanation:

have a nice day

We may include hydrogen-bonding as one type as it is a particular instance of dipole-dipole interaction. The London dispersion forces are the other sort of interaction.

Hydrogen bonds form between nearby hydrogen and oxygen atoms of adjacent water molecules in the case of water. A bond called a hydrogen bond is produced by the attraction between individual water molecules.

Hydrogen bonding is the strongest of all the intermolecular forces that are present in water. If it is compared to the London Dispersion Force and dipole-dipole attraction, it is the strongest intermolecular force of attraction.

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Answer:

The answer is lemonade.

Weaker acids are those which tend to have a higher pH from 4 to at least 6 stronger acids have low pH from 2 and below that's from 2 to 0.

Hope this helps

Hope

Answer:

H2O2

Explanation:

I know it's been awhile since the question was asked but for future people like me its H2O2 I got it right in the quiz.

The whole-number multiple is obtained by dividing its molar mass (34.02 g/mol) by the empirical formula mass. H₂O₂ is the molecular formula of a compound that is composed of 94.1% O and 5.9% H with a molar mass of 34g.

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound. The molar mass of a material is a bulk attribute rather than a molecular one.

The mass of 6.022 × 10²³ atoms, molecules, or formula units of a material are equal to its molar mass, which is the mass of 1 mole of that substance represented in grams per mole.

Molar mass is a crucial factor to consider while planning an experiment. The molar mass enables you to calculate the quantity you should weigh out on your scale when testing theories that call for specified amounts of a material.

Thus, H₂O₂ is the molecular formula of a compound that is composed of 94.1% O and 5.9% H with a molar mass of 34g.

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I would believe the answer is sound energy because the sound that orchestral gives off, gives off some energy even though it isn't necessarily comparable to other sources of energy.

Hope that helped!

Answer:

yes yes yes yes yes yes yes yes yes yes

To calculate the root mean square velocity and kinetic energy of F2, Cl2, and Br2 at 298K, we need to use the kinetic theory of gases.

The root mean square velocity of a gas can be calculated using the formula:

v_rms = √(3kT/m)

where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the molar mass of the gas.

The kinetic energy of a gas can be calculated using the formula:

E_k = (1/2)mv_rms^2

At 298K, the root mean square velocity and kinetic energy of F2, Cl2, and Br2 can be calculated as follows:

F2:

molar mass = 2 * 18.998 g/mol = 37.996 g/mol

v_rms = √(3 * 8.314 J/mol*K * 298K / 37.996 g/mol) = √(0.0244) m/s

E_k = (1/2) * 37.996 g/mol * (0.0244 m/s)^2 = 0.0167 J/mol

Cl2:

molar mass = 2 * 35.453 g/mol = 70.906 g/mol

v_rms = √(3 * 8.314 J/mol*K * 298K / 70.906 g/mol) = √(0.0132) m/s

E_k = (1/2) * 70.906 g/mol * (0.0132 m/s)^2 = 0.0051 J/mol

Br2:

molar mass = 2 * 78.918 g/mol = 157.836 g/mol

v_rms = √(3 * 8.314 J/mol*K * 298K / 157.836 g/mol) = √(0.0064) m/s

E_k = (1/2) * 157.836 g/mol * (0.0064 m/s)^2 = 0.0016 J/mol

To rank the halogens with respect to their rate of effusion, we need to consider the root mean square velocity of each gas. The rate of effusion of a gas is directly proportional to the root mean square velocity of the gas, which is the velocity of the gas particles. Therefore, the gas with the higher root mean square velocity will effuse faster than the gas with the lower root mean square velocity.

From the above calculation, we can see that the root mean square velocity of F2 is the highest, followed by Cl2, and then Br2. Therefore, the halogens can be ranked in terms of their rate of effusion as follows:

F2

Cl2

Br2

So Fluorine(F2) will effuse faster than Chlorine(Cl2) and Bromine(Br2)

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Answer:

6) λ  =  0.84 × 10⁻⁸ m

7) λ  =  0.84 × 10⁻⁶ m

Explanation:

6) Given data:

Wavelength of photon = ?

Frequency of photon = 3.56 × 10¹⁶ Hz

Solution:

Formula:

Speed of radiation = frequency × wavelength

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s  = 3.56 × 10¹⁶ Hz ×  λ

λ  =  3×10⁸ m/s   / 3.56 × 10¹⁶ s⁻¹

λ  =  0.84 × 10⁻⁸ m

7) Given data:

Wavelength of photon = ?

Frequency of photon = 6.15 × 10¹⁴ Hz

Solution:

Formula:

Speed of radiation = frequency × wavelength

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s  =  6.15 × 10¹⁴ Hz ×  λ

λ  =  3×10⁸ m/s   /  6.15 × 10¹⁴ Hz s⁻¹

λ  =  0.84 × 10⁻⁶ m

Answer:

A temporary magnet allows the user to determine when it is magnetic.

A temporary magnet allows the user to determine when it is magnetic.

A magnet that keeps its magnetic properties over an extended length of time is called a permanent magnet. Examples include iron, nickel, cobalt, and some alloys made of rare earth metals.

When they are in a strong magnetic field, temporary magnets simply behave like permanent magnets.

They lose their magnetic when the field is removed, in contrast to permanent magnets. Temporary magnets include things like paperclips, iron nails, and other materials of a similar kind.

Therefore, A temporary magnet allows the user to determine when it is magnetic.

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Answer:

element A has a mass of 2 units, while an atom of element B

has a mass of 5 units, what would be the mass of the

compound A3 B2

Explanation:

Classification of chemical reaction is as follows:

1. Addition reaction

2. Oxidation-reduction reaction

3. Isomerization reaction

4.  Nucleophilic substitution reaction

1. Ethene undergoes an addition reaction with bromine, where the double bond is broken, and each carbon atom forms a single bond with a bromine atom.

2. The oxidation-reduction reaction involves the conversion of 2-propanol to acetone through the loss of hydrogen atoms (oxidation) and gain of oxygen atoms (reduction).

3. The isomerization reaction occurs when glucose is enzymatically converted to fructose, leading to a rearrangement of the atoms within the molecule to form an isomer.

4. The reaction between methyl chloride and sodium hydroxide involves the substitution of a chlorine atom in methyl chloride by a hydroxide ion, resulting in the formation of methanol. This is a nucleophilic substitution reaction.

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Complete question is:

classify each chemical reaction as an addition, oxidation-reduction, isomerization, or nucleophilic substitution.

1) Ethene (C2H4) reacts with bromine (Br2) to form 1,2-dibromoethane (C2H4Br2).

2) 2-propanol (C3H8O) is oxidized to form acetone (CH3COCH3).

3) Glucose (C6H12O6) is converted to fructose (C6H12O6) in the presence of an enzyme.

4) Methyl chloride (CH3Cl) reacts with sodium hydroxide (NaOH) to form methanol (CH3OH).

Answer:

in w

Explanation:

first blood enter renal artery which enter glomerous( where blood is filtrated) and then to Bowman carpusle(take the filtrated blood)

and then to proximal tubular(absorbed salt) and then to loop of hanle (y)(absorb water) and then to distal tubule then to ureter (z) and then to renal vein(x)(to go to urinary bladder)

The most stable contributor's structure is the genuine structure of the resonance hybrid. The delocalization of electrons is what stabilizes the resonance hybrid. The potential resonance forms are quickly interconverted by a resonance hybrid.

Equivalent resonance types equally contribute to the hybrid's overall structure. Consider the resonance hybrid structure of a carboxylate group as an example. Different resonance contributors do not always contribute equally to the hybrid structure until they are equivalent to one another in terms of stability, as is the case for the carboxylate group, which has equivalent contributions from A and B as shown in the given figure. One resonance structure will more closely resemble the “actual” (hybrid) structure than another if it is more stable (lower in energy) than the other.

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