Which choices are solutions to the following equatior
Check all that apply. X^2 -5x=-9/4

Answer:

Use colon method

Step-by-step explanation:

So it is more easy

Answer:

Non-linear and decreasing so B

Step-by-step explanation:

It is non-linear as it is not a straight line

It's also going down so its decreasing

The probability of A and B occurring simultaneously (P(A ∩ B)) is c. 0.00.

In this scenario, A and B are stated to be mutually exclusive events. Mutually exclusive events are events that cannot occur at the same time. This means that if event A happens, event B cannot happen, and vice versa.

Given that P(A) = 0.4 and P(B) = 0.5, we can deduce that the probability of A occurring is 0.4 and the probability of B occurring is 0.5. Since A and B are mutually exclusive, their intersection (A ∩ B) would be an empty set, meaning no outcomes can be shared between the two events. Therefore, the probability of A and B occurring simultaneously, P(A ∩ B), would be 0.

To further clarify, let's consider an example: Suppose event A represents flipping a coin and getting heads, and event B represents flipping the same coin and getting tails. Since getting heads and getting tails are mutually exclusive outcomes, the intersection of events A and B would be empty. Therefore, the probability of getting both heads and tails in the same coin flip is 0.

In this case, since events A and B are mutually exclusive, the probability of their intersection, P(A ∩ B), is 0.

Therefore, the correct answer is: c. 0.00

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Answer:

this is math not English

Step-by-step explanation:

If you struggle when you're learning new information, you'll remember it better later on.

Hope it helps:)

Answer:

£3691 (nearest pound)

Step-by-step explanation:

Consider the rate of compound interest is r and the initial amount of savings is P, hence

\(P \ + \ P \ \times \ r \ = \ P \ (\ 1 \ + \ r \ ) \qquad (Final \ amount \ for \ the \ 1st \ year ) \\ \\ \ P \ (\ 1 \ + \ r \ ) \ + \ P \ (\ 1 \ + \ r \ ) \ \times \ r \ = \\ \ P\ ( \ 1\ + \ r \ ) \ ( \ 1 \ + \ r \ ) \ = \ P \ {( \ 1 \ + \ r \ )}^2 \qquad (Final \ amount \ for \ the \ 2nd \ year) \\ \\ \ P \ {(\ 1 \ + \ r \ )}^2 \ + \ P \ {(\ 1 \ + \ r \ )}^2 \ \times \ r \ = \\ \ P\ {( \ 1\ + \ r \ )}^2 \ ( \ 1 \ + \ r \ ) \ = \ P \ {( \ 1 \ + \ r \ )}^3 \\ \\ (Final \ amount \ for \ the \ 3rd \ year)...\)  

Therefore, the final amount of savings after nth years of compund interest is

\(P \ {( \ 1 \ + \ r \ )}^n\).

Given that 4.2% compound interest was used for the first 4 years to a savings of £2350, thus

\(Final \ amount \ for \ the \ first \ 4 \ years \ = \ 2350 \ {( \ 1 \ + \ \frac{4.2}{100} \ )}^4 \ = \ 2770.36\)

Then, taking the final amount of savings previously into an initial amount for the next 6 years with 4.9% compound interest.

\(2770.36 \ {( \ 1 + \frac{4.9}{100} \ )}^6 \ = \ 3691.40 \ = \ 3691 \ (nearest \ pound)\)

Answer:

73 ,,,,,,,,,,,,,,,,,,,,,,,

Temperature of refrigerators - Cannot determine. Horsepower of race car engines - Ratio. Marital status of school board members - Nominal. Ratings of television programs - Ordinal. Ages of children enrolled in a daycare - Interval

The level of measurement for the temperature of refrigerators cannot be determined based on the given information. The temperature could potentially be measured on a nominal scale if the refrigerators were categorized into different temperature ranges. However, without further context, it is not possible to determine the specific level of measurement.

The horsepower of race car engines can be measured on a ratio scale. Ratio scales have a meaningful zero point and allow for meaningful comparisons of values, such as determining that one engine has twice the horsepower of another.

The marital status of school board members can be measured on a nominal scale. Nominal scales are used for categorical data without any inherent order or ranking. Marital status categories, such as "married," "single," "divorced," etc., can be assigned to school board members.

The ratings of television programs, such as "poor," "fair," "good," and "excellent," can be measured on an ordinal scale. Ordinal scales represent data with ordered categories or ranks, but the differences between categories may not be equal or measurable.

The ages of children enrolled in a daycare can be measured on an interval scale. Interval scales have equal intervals between values, allowing for meaningful differences and comparisons. Age, measured in years or months, can be represented on an interval scale.

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Answer:

(x + 1) (3x + 5)

Step-by-step explanation:

Let's check

(x + 1) (3x + 5)

3x² + 5x + 3x + 5

3x² + 8x + 5

So, (x + 1) (3x + 5) is the correct answer.

The sample  should consist of  180 students at least in order for the dean take to ensure this is true.

since we are provided a standard deviation of 2.6 hours, we need to find the sample size at most of 0.5 hours. Since we know

E = z∗ σ/√n, where z is the score,σ is the standard deviation and n is the sample size. According to this case, z∗ will be 2.576 since the dean wants 99% confidence.  so the sample size will be

n=(z∗σ /E)^2

   = (2.57* 2.6/0.5)^2

  =  179.43 =  180

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The 2007 National Survey of Children's Health found that first-generation children had higher rates of some health conditions than second- or third-plus-generation children, but lower rates of other conditions.

The survey looked at weighted and age-standardized percent distributions of health conditions for first-, second-, and third-plus-generation children, by race/ethnicity.

The results showed that first-generation children had higher rates of allergies, asthma, and developmental problems than second- or third-plus-generation children. However, first-generation children had lower rates of overweight and obesity than second- or third-plus-generation children.

The differences in health conditions between the three generations of children were not consistent across all race/ethnic groups. For example, first-generation black children had higher rates of overweight and obesity than second- or third-plus-generation black children.

However, first-generation Hispanic children had lower rates of overweight and obesity than second- or third-plus-generation Hispanic children.

The reasons for the differences in health conditions between the three generations of children are not fully understood. However, some possible explanations include differences in access to healthcare, differences in cultural beliefs about health, and differences in socioeconomic status.

The findings of the National Survey of Children's Health suggest that it is important to consider the generation of a child when assessing their health needs.

Children from different generations may have different risk factors for certain health conditions, and they may also have different access to healthcare. It is important to provide culturally-sensitive care to all children, regardless of their generation.

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Answer:

They are the same length, and they intersect. Hope this helps!

Using the concepts of probability, we got that  0.063 is the probability of picking a blue marble randomly out of a bag of 6 blue marbles, 3 black marbles, and 8 orange marbles while rolling a 3 on a 6-sided dice at the same time

We know very well that probability is defined as the fraction of number of favorable outcomes to the total number of outcomes.

Here, we are rolling a 6-faced dice.

Getting 3 on the top face of dice is same as the any number getting from 1 to 6 on the top face of the dice.

So, every number has equal probability to come on the top face,  therefore the probability of getting 3 on the top face of dice is (1/6)

Now, similarly total number of marbles in the bag=6 blue +3 black+8 orange marble=17 marbles.

Now, picking one marble from 17 marble is can be done in \(^1^7C_1\)  ways, similarly  choosing 1 blue marble from 6 marble can be done in \(^6C_1\) ways.

So, probability of picking 1 blue marble randomly=6/17

Now, the probability of picking 1 blue marble from 17 marbles along with rolling dice probability is given by =(6/17)×(1/6)=(1/17)=0.063

Hence, the probability of picking a blue marble randomly out of a bag of 6 blue marbles, 3 black marbles, and 8 orange marbles while rolling a 3 on a 6-sided dice at the same time is 0.063

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Answer:

k < -1 or k > 11

Step-by-step explanation:

Given quadratic equation:

\(3x^2-x+ k = kx-1\)

First, rearrange the given quadratic equation in standard form ax² + bx + c = 0:

\(\begin{aligned}3x^2-x+ k &= kx-1\\3x^2-x+ k-kx+1&=0-kx+1\\3x^2-x-kx+ k+1&=0\\3x^2-(1+k)x+ (k+1)&=0\end{aligned}\)

\(3x^2-(1+k)x+ (k+1)=0\)

Comparing this with the standard form, the coefficients a, b and c are:

\(\boxed{\begin{minipage}{7 cm}\underline{Discriminant}\\\\$\boxed{b^2-4ac}$ \quad when $ax^2+bx+c=0$\\\\when $b^2-4ac > 0 \implies$ two real roots.\\when $b^2-4ac=0 \implies$ one real root.\\when $b^2-4ac < 0 \implies$ no real roots.\\\end{minipage}}\)

If the quadratic equation has two distinct roots, its discriminant is positive.

\(b^2-4ac > 0\)

Substitute the values of a, b and c into the discriminant:

\((-1 - k)^2-4(3)(k+1) > 0\)

Simplify:

\((-1 - k)(-1-k)-12(k+1) > 0\)

\(1+2k+k^2-12k-12 > 0\)

\(k^2+2k-12k+1-12 > 0\)

\(k^2-10k-11 > 0\)

Factor the left side of the inequality:

\(k^2+k-11k-11 > 0\)

\(k(k+1)-11(k+1) > 0\)

\((k-11)(k-1) > 0\)

If we graph the quadratic k² - 10k - 11, it is a parabola that opens upwards (since its leading coefficient is positive), and crosses the x-axis at k = -1 and k = 11. Therefore, the curve will be positive (above the x-axis) either side of the x-intercepts, so when k < -1 or k > 11.

Therefore, the range of values of k for which the given quadratic equation has two distinct roots is:

\(\boxed{k < -1 \; \textsf{or} \;k > 11}\)

Answer:

x=-1

Step-by-step explanation:

Step 1: Factor

\(x^{2} +2x+1\) => \((x+1)(x+1)\)

Step 2: Solve for x.

\(x+1=0\)

   \(-1\)     \(-1\)

-----------------

\(x=-1\)

Answer:

$154

Step-by-step explanation:

Hope this helps :)

Given information:

The uncertainty is 1 mm.

The given number is 4.0.

The answer to the given question is: 4.0±0.1

Explanation:The given number is 4.0, and the uncertainty is 1 mm.

Now, as the given number has only one significant figure, we need to represent the answer with only one decimal place.

To do so, we count the decimal places of the uncertainty.

Here, the uncertainty is 1 mm, so it has one decimal place.

Therefore, the answer to two significant figures is: 4.0±0.1.

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Answer:

18

Step-by-step explanation:

3 times 6 equals 18

===================================================

Explanation:

Any triangle prism is composed of 2 parallel triangular faces (base faces), along with 3 rectangular lateral faces.

The bottom triangle face has a base of 10 cm and a height of 4 cm. The area is 0.5*base*height = 0.5*10*4 = 20 square cm. Two of these triangles combine to an area of 2*20 = 40 square cm. We'll use this later.

The lateral surface area of any prism can be found by multiplying the perimeter of the base by the height of the prism. The base triangle has side lengths 5, 8 and 10. The perimeter is 5+8+10 = 23. So the lateral surface area is (perimeter)*(height) = 23*9 = 207

Add this to the total base area we got earlier and the answer is 40+207 = 247. The units are in square cm, which we can write as cm^2.

Answer:

m∠1 = 84°

Step-by-step explanation:

according to the corresponding angles postulate, we can extend the line and put 51 degrees as that angle.

because we know the sum of a triangle's angles is 180, we do 180-51-33=96

a line is 180 degrees, 180-96=84

Answer:

whT type of question is this

Joanna can form 341 different monetary amounts using the given bills.

To find out how many different monetary amounts Joanna can form using the given bills, we need to consider all possible combinations.

First, let's list down the possible number of bills for each denomination:

- $1 bill: 0 to 2 bills

- $5 bill: 0 to 2 bills

- $10 bill: 0 to 2 bills

- $20 bill: 0 to 2 bills

- $50 bill: 0 to 2 bills

- $100 bill: 0 to 2 bills

Now, let's calculate the different monetary amounts for each combination of bills:

- For each denomination, there are 3 possibilities (0, 1, or 2 bills).

- Therefore, there are a total of \(3^6\) = 729 combinations.

However, we need to exclude the combination where no bills are used, as it will result in $0. So, we subtract 1 from the total combinations.

Therefore, Joanna can form 729 - 1 = 728 different monetary amounts.

However, we also need to consider that Joanna only has $372. So, we need to eliminate the combinations that exceed this amount.

Starting with the highest denomination, let's calculate the maximum number of bills Joanna can use without exceeding $372:

- $100 bill: She can use either 0 or 1 bill (0 or 1 * $100 = $0 or $100).

- $50 bill: She can use either 0, 1, or 2 bills (0, 1, or 2 * $50 = $0, $50, or $100).

- $20 bill: She can use either 0, 1, or 2 bills (0, 1, or 2 * $20 = $0, $20, or $40).

- $10 bill: She can use either 0, 1, or 2 bills (0, 1, or 2 * $10 = $0, $10, or $20).

- $5 bill: She can use either 0, 1, or 2 bills (0, 1, or 2 * $5 = $0, $5, or $10).

- $1 bill: She can use either 0, 1, or 2 bills (0, 1, or 2 * $1 = $0, $1, or $2).

By considering all the possible combinations and the maximum amount Joanna can form without exceeding $372, we find that she can form 341 different monetary amounts using the given bills.

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Answer:

2,323. 13 dollars

Therefore, the components of vector E⃗ are Ex = 1 and Ey = -11. Thus, E⃗ = (1, -11).

To solve this equation, let's break it down component-wise. Given:

E⃗ = 2A⃗ + 3B⃗

We can write the equation in terms of its components:

Ex = 2Ax + 3Bx

Ey = 2Ay + 3By

We are also given the components of vectors A⃗ and B⃗:

Ax = 5

Ay = 2

Bx = -3

By = -5

Substituting these values into the equation, we have:

Ex = 2(5) + 3(-3)

Ey = 2(2) + 3(-5)

Simplifying:

Ex = 10 - 9

Ey = 4 - 15

Ex = 1

Ey = -11

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Answer:

(rounded)17.2=Q

Step-by-step explanation:

Q= 13/cos41

To estimate the regression in the given model Yi = B0 + B1Xi + B2Ziui, where the variance of Ui is Σi^2 = Σ(zi^2), you can use the method of weighted least squares (WLS). The weights for each observation can be determined by the inverse of the variance of Ui, that is, wi = 1/zi^2.

In the given model, Yi = B0 + B1Xi + B2Ziui, the error term Ui is assumed to have a constant variance, given by Σi^2 = Σ(zi^2), where zi represents the individual values of Z.

To estimate the regression coefficients B0, B1, and B2, you can use the weighted least squares (WLS) method. WLS is an extension of the ordinary least squares (OLS) method that accounts for heteroscedasticity in the error term.

In WLS, you assign weights to each observation based on the inverse of its variance. In this case, the weight for each observation i would be wi = 1/zi^2, where zi^2 represents the variance of Ui for that particular observation.

By assigning higher weights to observations with smaller variance, WLS gives more importance to those observations that are more precise and have smaller errors. This weighting scheme helps in obtaining more efficient and unbiased estimates of the regression coefficients.

Once you have calculated the weights for each observation, you can use the WLS method to estimate the regression coefficients B0, B1, and B2 by minimizing the weighted sum of squared residuals. This involves finding the values of B0, B1, and B2 that minimize the expression Σ[wi * (Yi - B0 - B1Xi - B2Ziui)^2].

By using the weights derived from the inverse of the variance of Ui, WLS allows you to estimate the regression in the presence of heteroscedasticity, leading to more accurate and robust results.

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Answer:

that is in standard form?? are u talking about monomials?

Step-by-step explanation:

The total amount Bea spent if there is a 7% sales tax rate and she gives a 20% tip is $33.40. option B

Total = $2.50 + $8.50 + $25.30

= $26.30

Sales tax = 7%

= 7% × $26.30

= 0.07 × 26.30

= $1.841

Tips = 20%

= 20% × $26.30

= 0.20 × 26.30

= $5.36

Total cost = $26.30 + $1.841 + $5.36

= $33.401

Approximately,

$33.40

Therefore, the total amount Bea spent if there is a 7% sales tax rate and she gives a 20% tip is $33.40. option B

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Answer:

Step-by-step explanation:

A side walk has a length of 75.00  which is 2953 inches ^v^