The choice which is equivalent to the given expression is \(3x \sqrt{2x}\). The correct option is D. \(3x \sqrt{2x}\)
Simplifying an expressionFrom the question, we are to determine the expression which is equivalent to the given expression
The given expression is
\(\sqrt{6x^{2} } \times\sqrt{3x}\)
This can be written as
\(\sqrt{6x^{2} \times 3x}\)
= \(\sqrt{18x^{2} \times x}\)
= \(\sqrt{9x^{2} \times 2x}\)
= \(\sqrt{9x^{2} } \times \sqrt{2x}\)
= \(3x\times \sqrt{2x}\)
= \(3x \sqrt{2x}\)
Hence, the choice which is equivalent to the given expression is \(3x \sqrt{2x}\). The correct option is D. \(3x \sqrt{2x}\)
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Pls help it’s due soon
Answer: the answer is c!
Step-by-step explanation:
the front side of a doghouse is shown in this scale drawing The height of the door in the drawing is 2 inches and the width is 3.5 inches. ... Using the scale given, enter the actual height, in feet, of the doghouse door.
Answer:
So, every one inch in the real dog house would be equal to .4 on the scale drawing.
So,
8/.4= 20
10/.4= 25
So, the dog house is 20 by 25 inches.
The question asked for the area.
20*25= 500
The real dog house has an area of 500 in^2.
I hope this helps!
Step-by-step explanation:
In vSphere, a bound physical NIC can be configured to transmit and receive Jumbo Frames. What is the Maximum Transmission Unit (MTU) for Jumbo Frames in vSphere
In vSphere, the Maximum Transmission Unit (MTU) for Jumbo Frames can be configured to a maximum size of 9000 bytes.
Jumbo Frames refer to Ethernet frames that exceed the standard Maximum Transmission Unit (MTU) size of 1500 bytes. These larger frames can offer certain benefits, such as reducing network overhead and improving overall network performance in specific use cases.
In vSphere, the MTU for Jumbo Frames can be configured to a maximum size of 9000 bytes. This means that the network interface card (NIC) can transmit and receive Ethernet frames with a payload size of up to 9000 bytes. It is important to note that for Jumbo Frames to work effectively, all devices and components in the network path, including switches and routers, must also support and be configured for Jumbo Frames.
By configuring a bound physical NIC in vSphere to support Jumbo Frames with an MTU size of 9000 bytes, it allows for the transmission of larger frames, which can improve network performance and efficiency in environments where Jumbo Frames are beneficial and supported.
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shinji is considring 2 diffrent layouts if a gardwen. He needs to put a length of fence around whicever layout he choose wich layout needs more fencing and how much
Shinji is considering two different layouts for a garden. He needs to put a length of fence around whichever layout he chooses.
Which layout needs more fencing and how much?
We cannot determine which layout needs more fencing without knowing the dimensions of both layouts. Please provide more information such as the length and width of each layout. Then, we can calculate the perimeter of each layout to determine which layout needs more fencing.
Note: A fence is typically used to surround a garden to prevent unwanted visitors and animals from entering the garden.
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the symbol ∪ represents the union of events. the union of two events a and b results in an event that contains all the sample points of event a or event b or both events.
The union of events A and B combines their sample points, and the probability of the combined event can be calculated using the formula P(A ∪ B) = P(A) + P(B) - P(A ∩ B). This formula ensures that shared sample points are not double-counted. The probability of either event A or event B occurring, P(A ∪ B), is equal to 200.
The symbol ∪ represents the union of events. When two events, A and B, are combined through union, the resulting event contains all the sample points that belong to event A or event B or both events. The probability of the combined event, denoted as P(A ∪ B), can be calculated using the formula P(A ∪ B) = P(A) + P(B) - P(A ∩ B), where P(A) represents the probability of event A, P(B) represents the probability of event B, and P(A ∩ B) represents the probability of their intersection.
The maximum probability for the combined event is 1.0, which indicates certainty. This occurs when event A and event B are identical or when they have a non-empty intersection. On the other hand, the probability of the combined event is 0 if there are no shared sample points between events A and B, indicating that they are mutually exclusive.
To calculate the probability of either event A or event B occurring, we use the formula P(A ∪ B) = P(A) + P(B) - P(A ∩ B). We add the individual probabilities of A and B and then subtract the probability of their intersection, which avoids double-counting the shared sample points.
For example, let's assume P(A) = 150 and P(B) = 170, while P(A ∩ B) = 120. Substituting these values into the formula, we get:
P(A ∪ B) = 150 + 170 - 120 = 200
Therefore, the probability of either event A or event B occurring, P(A ∪ B), is equal to 200.
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Assuming the distribution for 2009 is approximately normally distributed, estimate how many of the 61 days in 2009 the dow decreased by more than 1%
Number of the 61 days in 2009 the Dow decreased by more than 1% is 0.514.
Given that, 61 days in 2009 the Dow decreased by more than 1%.
What is normal distribution?Normal distribution, also known as the Gaussian distribution, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.
In 2009
z = (1- (-0.198))/2.331
= 0.514
In 2010
z = (1-0.078)/0.821
= 1.123
Therefore, number of the 61 days in 2009 the Dow decreased by more than 1% is 0.514.
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From 1900 to 1960, The life expectancy (in years) increased at a relatively constant rate of 0.401 years. In 1942, the life expectancy was 62.9 years old.
In what year will the life expectancy reach 75 years old?
The life expectancy will reach 75 years old in the year 1970.
We have,
Let's start by defining the variables:
L = life expectancy in years
t = time in years since 1900
We know that from 1900 to 1960, life expectancy increased at a constant rate of 0.401 years per year.
So, we can write the following equation to represent the relationship between L and t:
L = 0.401t + b
where b is the life expectancy in 1900.
To find b, we can use the fact that the life expectancy in 1900 was around 47 years old.
b = 47
So, the equation becomes:
L = 0.401t + 47
We also know that in 1942, the life expectancy was 62.9 years old.
So, we can use this information to find the value of t in 1942:
62.9 = 0.401t + 47
Solving for t, we get:
t = (62.9 - 47) / 0.401 = 39.15
In 1942,
t = 39.15.
To find the year when the life expectancy reaches 75 years old, we can plug in L = 75 into the equation and solve for t:
75 = 0.401t + 47
Solving for t.
t = (75 - 47) / 0.401 = 69.82
So, the life expectancy will reach 75 years old in the year:
1900 + 69.82 = 1969.82
Therefore,
The life expectancy will reach 75 years old in the year 1970.
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165% of the value is 3795 kg what is the original value
Answer:
Answer: 2300kg. formulate:: 3795kg/165%Calculate 3795kg/165%: : 2300kg.
Step-by-step explanation:
Jerry started doing sit-ups every day. The first day he did 17 sit-ups. Every day after that he did 4 more sit-
ups than he had done the previous day. Today Jerry did 73 sit-ups. Write an equation that could be solved
to find the number of days Jerry has been doing sit-ups, not counting the first day. Let n represent the
number of days.
An equation that can help lerry to find the number of dave hahachoon daina cancis aivor
Answer:
5
Step-by-step explanation:
y= 4x+17
73=4x+17 (subtract 17 by both sides)
20=4x (divide by both sides)
5= x, 5 days
A solution to the equation 4x+2y=20 must also be a solution to which of the following equations?1) 8x+2y=402) 2x+2y=103) 2x+y=104) 4x+4y=40
As given by the question,
There are given that the equation:
\(4x+2y=20\)Now,
First, suppose any number, for which the given equation has satisfied.
So, the number is, x = 2 and y = 6
Then,
Put both values into the given equation
\(\begin{gathered} 4x+2y=20 \\ 4(2)+2(6)=20 \\ 8+12=20 \\ 20=20 \end{gathered}\)Then,
Put the same value of x and y into the given option and check whether it is satisfied:
So,
From option 3:
\(\begin{gathered} 2x+y=10 \\ 2(2)+6=10 \\ 4+6=10 \\ 10=10 \end{gathered}\)Hence, the correct option is 3.
Find the missing quotient
?
____
30( 240
Answer:
8
Step-by-step explanation:
30( 240=8
30x9=240
Have amazing day!
6. Roberta started the year with $125 in a savings account. She has been adding money at a rate of $15 per week. Write an equation in the form y = mx + b that represents the total amount of money (y) in the account after x weeks.
Answer:
y=15x+125
Step-by-step explanation:
Hope this helps!
Grant plans to evaporate enough water from 22 gallons of a 16% ammonia solution to make a 24% ammonia solution. Which equation can he use to find n, the number of gallons of water he should remove?
3.52 (22 minus n) = 0.24
StartFraction 22 minus n Over 3.52 EndFraction = StartFraction 24 Over 100 EndFraction
StartFraction 3.52 Over 22 minus n EndFraction = StartFraction 24 Over 100 EndFraction
3.52 + (22 minus n) = 0.24
The equation that he used to find n, the number of gallons of water he should remove is 3.52 / (22 - n) = 24 / 100. Option C is correct.
Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.
Amount of ammonia in the solution 16% x 22 gallons = 3.52 gallons
The proportion of ammonia remains the same as the water evaporates, but the total composition of the solution is decreased by the amount of water that evaporates.
Quantity of ammonia = 3.52 gallons
Quantity of water after evaporation = 22 - n
Composition of ammonia after evaporation of water, 24% = 24/100
Now the percentage of ammonia after evaporates
Quantity of ammonia / Remaining water = 24%
3.52 / (22 - n) = 24 / 100
Thus, the equation that he used to find n, the number of gallons of water he should remove is 3.52 / (22 - n) = 24 / 100.
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PLEASE HELP! MIDDLE SCHOOL MATH! The dot plot below shows the number of baskets made by Elena over 12 practice sessions. What is the mean absolute deviation (MAD) for Elena's data? (The mean is marked by the red triangle)
Answer:
I suck at math so sorry
Answer:
Elena’s MAD: 2
Step-by-step explanation:
24 ÷ 12 = 2
Find the surface area of the figure. Round your answers to the nearest hundredth, if necessary.
8 in
5.5 in
6.9 in
8 in
8 in
The surface area of the rectangular prism with dimensions 8 in by 5.5 in by 6.9 in is 274.3 square inches.
To find the surface area of the figure, we need to first identify the shape. Based on the given dimensions, it appears to be a rectangular prism. To calculate the surface area of a rectangular prism, we need to find the area of each of its six faces and add them together.
The formula for the surface area of a rectangular prism is 2lw + 2lh + 2wh, where l, w, and h represent the length, width, and height of the prism, respectively.
Plugging in the given dimensions, we get:
2(8 x 5.5) + 2(8 x 6.9) + 2(5.5 x 6.9)
= 88 + 110.4 + 75.9
= 274.3
Therefore, the surface area of the figure is 274.3 square inches. Since the question asks us to round our answer to the nearest hundredth, and the answer is already in decimal form, we do not need to round.
In summary, the surface area of the rectangular prism with dimensions 8 in by 5.5 in by 6.9 in is 274.3 square inches.
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Question 10
Describe the translation from preimage P(9. 1.5) to image P'(12, 1)). (x, y)
The translation from preimage P(9. 1.5) to image P'(12, 1)) in ordered pair is (3, -0.5)
What is translation?Translation refers to a type of transformation that involve a straight line movement.
The type of movements related to translation includes
updownleft rightThe up and down movements are on the vertical direction controlled by the y coordinate. In the question, the preimage moved form 1.5 to 1
hence we say
the image moved 0.5 units down from the preimageThe left right movement is controlled by the x coordinate. The preimage moved from 9 to 12 ⇒ 9 + 3. Hence we say that
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The entire area under the standard normal distribution curve? can be any value cannot be negative can be any positive value can be any positive value larger than 1
The entire area under the standard normal distribution curve is always positive even if the z value is negative.
The normal distribution, it's useful to think of the standard deviation as being steps away from the mean. One step to the right or one step to the left is considered one standard deviation away from the mean. Two steps to the left or two steps to the right are considered two standard deviations away from the mean. Likewise, three steps to the left or three steps to the right are considered three standard deviations from the mean.
The probability of the outcome of an experiment is never negative, although a quasi probability distribution allows a negative probability, or quasi probability for some events. These distributions may apply to unobservable events or conditional probabilities.
Therefore,
The value can be negative can be any positive value can be any positive value larger than 1.
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helppppppppppppppppppppppp meeeeeeeeee
consider the two way frequency table shown below, for events A B C D X and Y.
Total = 125
P ( A and X )= 11/ total = 11/125= 0.088
P (B and X ) = 26/125 = 0.208
P (C l X ) = 6 /70 = 0.085
P (Bl Y) = 10/55 = 0.18
P (YlC)=12/55 =0.21
From least to greatest
0.085-0.088-0.18-0.208-0.21
P (C l X ) -P ( A and X -P (Bl Y))-P (B and X )-P (YlC)
in how many ways can 345 be written as the sum of an increasing sequence of two or more consecutive positive integers? (a) 1 (b) 3 (c) 5 (d) 6 (e) 7
There is only one way 345 can be written as the sum of an increasing sequence of two or more consecutive positive integers. The correct answer is A) 1.
To find the number of ways 345 can be written as the sum of an increasing sequence of two or more consecutive positive integers, we need to consider the factors of 345.
First, let's find the prime factorization of 345: 345 = 3 * 5 * 23.
Now, let's focus on factor 23. Since the sequence needs to have at least two consecutive positive integers, the smallest possible sequence would be 23 and 24. We can see that any larger sequence would have a sum greater than 345.
Therefore, the only possible way to write 345 as the sum of an increasing sequence of two or more consecutive positive integers is 23 + 24.
Hence, the answer is option (a) 1.
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The rectangular floor of a classroom is 26 feet in length and 36 feet in width. A scale drawing of the floor has a length of 13 inches. What is the perimeter, in inches, of the floor in the scale drawing?
HURRYYY I NEED HELP AGAIN!
Answer: 62 inches
Step-by-step explanation:
26÷13 =2
so 2 is the scale factor
so 36÷2= 18
18+18+13+13=62
I HOPE THAT HELPED
A store owner notes that 1 out of 4 customers do not make a purchase. How many customers need to come into the store in order for the owner to make 85 sales?
Answer:
340 customers.
Step-by-step explanation:
1 out of 4 = 25% purchase rate
85 × 4 = 340
To check our work:
25% of 340 = 0.25 × 340 = 85
PX,PY, and PZ are the perpendicular bisectors of ARST. Find PS and XT.
Answer:
PS = 82.8 ; XT = 46.1
Step-by-step explanation:
PZ = \(\sqrt{TP^2 - TZ^2}\) = √(82.8² - 76.5²) = √1003.59
TZ = SZ = 76.5
PS = \(\sqrt{PZ^2 +SZ^2}\) = √(1003.59 + 5852.25) = 82.8 units
XT = RX = 46.1 units
is it possible to have a series of true conditional statements that lead to a false conclusion? explain.
Answer:
Step-by-step explanation:
I think not because if a series of true conditional statements then it won't lead to a false conclusion
A random survey asked two samples of 100 high school students how much time they spend on homework each night. A 4-column table with 2 rows. Column 1 has entries Sample 1, Sample 2. Column 2 is labeled 0 to 30 minutes with entries 38, 41. Column 3 is labeled 31 to 60 minutes with entries 42, 36, Column 4 is labeled 61 to 90 minutes with entries 20, 23. Which inference is true? More students spend 0-30 minutes on homework than spend 31-60 minutes. More students spend 31-60 minutes on homework than spend 0-30 minutes. About the same number of students spend 0-30 minutes on homework as spend 31-60 minutes. More students spend 61-90 minutes on homework than spend 0-30 minutes.
Based on the given data, the inference that is true is: More students spend 0-30 minutes on homework than spend 31-60 minutes.
In Sample 1, there are 38 students who spend 0-30 minutes on homework, while in Sample 2, there are 41 students in the same category. The total number of students spending 0-30 minutes is 38 + 41 = 79.
In Sample 1, there are 42 students who spend 31-60 minutes on homework, while in Sample 2, there are 36 students in the same category. The total number of students spending 31-60 minutes is 42 + 36 = 78.
Comparing the two categories, we see that the number of students spending 0-30 minutes (79) is greater than the number of students spending 31-60 minutes (78). Therefore, the true inference is that more students spend 0-30 minutes on homework than spend 31-60 minutes.
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length of a rod: engineers on the bay bridge are measuring tower rods to find out if any rods have been corroded from salt water. there are rods on the east and west sides of the bridge span. one engineer plans to measure the length of an eastern rod 25 times and then calculate the average of the 25 measurements to estimate the true length of the eastern rod. a different engineer plans to measure the length of a western rod 20 times and then calculate the average of the 20 measurements to estimate the true length of the western rod. suppose the engineers construct a 90% confidence interval for the true length of their rods. whose interval do you expect to be more precise (narrower)?
The engineer measuring the western rod with a sample size of 20 is expected to have a more precise (narrower) confidence interval compared to the engineer measuring the eastern rod with a sample size of 25.
The engineer who measures the length of the western rod 20 times and calculates the average is expected to have a more precise (narrower) confidence interval compared to the engineer who measures the length of the eastern rod 25 times.
In statistical terms, the precision of a confidence interval is influenced by the sample size. The larger the sample size, the more precise the estimate tends to be. In this case, the engineer measuring the western rod has a sample size of 20, while the engineer measuring the eastern rod has a sample size of 25. Since the sample size of the western rod is smaller, it is expected to have a narrower confidence interval and therefore a more precise estimate of the true length of the rod.
A larger sample size provides more information and reduces the variability in the estimates. It allows for a more accurate estimation of the population parameter. Therefore, the engineer with a larger sample size is likely to have a more precise interval.
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Twice the difference of a number and 9 is equal to 2
Answer:
x = 10
Step-by-step explanation:
Let's break down the sentence and translate it into an equation:
"Twice the difference of a number and 9" means 2 times (x - 9), where x is the number.
"Is equal to 2" means = 2.
Putting it all together, we get:
2(x - 9) = 2
Simplifying:
2x - 18 = 2
Adding 18 to both sides:
2x = 20
Dividing by 2:
x = 10
So the solution is x = 10.
The 2020 senior class from a high school raised funds for an end of the year prom at Club Dance. It costs $4,000 to rent out Club Dance plus $20 per student for food and drinks.
Write an equation for the number of students could attend if the senior class raised 11,000 dollars.
Answer:
4000 + 20x = 11,000
Step-by-step explanation:
4000 + 20x = 11,000
20x = 7,000 (subtract 4,000 from 11,000)
7,000/2 = 3500
Answer:
35000
Step-by-step explanation:
1111=1323+33+ 1.666
Help!
JH is a mid-segment of KLM. Find the value of x.
JH = mid-segment of triangle KLM.
ML = 22
(1/2)(ML) = 11
JH = (1/2)(ML) = x
So, x = 11.
how to solve 5x^2+6=f(x)
Answer:
Step-by-step explanation:
f(x)=5x²+6
it is an upward parabola with vertex at (0,6)