Which characteristic of epithelium is different between continuous capillaries and lymph capillaries? amount of tight junctions presence of an apical surface type of epithelium O presence of nuclei

Answer:

.

Explanation:

26 = Terminal Velocity

27 = Force

34 = Momentum

33 = Laws of Conversation of Momentum (I think)

Answer:

I learned about human body, and cause of global warming.

Explanation:

These topics were so great to learn because I didn't know about Endocrine system, but now I know the job and the importance of  the Endocrine system. Also, I learned about global warming and I never knew what the cause of it was and it was great to learn new things!

Answer:

The depth of the object below the surface of the liquid is 0.510 meters.

Explanation:

The hydrostatic pressure (\(P\)), measured in pascals, experimented by the object is directly proportional to density of the fluid (\(\rho\)), measured in kilograms per cubic meter, gravitational acceleration (\(g\)), measured in meters per square second, and depth of the object (\(h\)), measured in meters. That is:

\(P = \rho\cdot g \cdot h\) (1)

If we know that \(P = 4500\,Pa\), \(\rho = 900\,\frac{kg}{m^{3}}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the depth of the object is:

\(h = \frac{P}{\rho\cdot g}\)

\(h = \frac{4500\,Pa}{\left(900\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}\)

\(h = 0.510\,m\)

The depth of the object below the surface of the liquid is 0.510 meters.

The depth of the object below the liquid's surface will be

"0.510 m".

According to the question,

Object immersed, P = 4500 Pa

Density of liquid, ρ = 900 kg/m³

Acceleration due to gravity, g = 9.8 m/s²

We know the relation,

→ Hydrostatic pressure (P) = ρ.g.h

or,

Depth will be:

→ h = \(\frac{P}{\rho .g}\)

By substituting the values,

     = \(\frac{4500}{900\times 9.8}\)

     = \(\frac{4500}{8820}\)

     = 0.510 m

Thus the above answer is appropriate.  

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Answer:

Below

Explanation:

\(6.51\times 10^7 \div 7.61 \times 10\\\\\frac{6.51\times \:10^7}{7.61\times \:10}\\\\\mathrm{Multiply\:the\:numbers:}\:7.61\times \:10=76.1\\=\frac{10^7\times \:6.51}{76.1}\\\\6.51\times \:10^7=65100000\\\\=\frac{65100000}{76.1}\\\\\mathrm{Divide\:the\:numbers:}\:\frac{65100000}{76.1}=855453.35085\dots \\=855453.35085\\\\= 855.4533085 \times 10^3\)

If the current through the resistor is 2.80 A the terminal voltage of the battery is 23.2 V.

We can use Ohm's law to find the voltage drop across the resistor:

V = IR

Where V is the voltage drop, I is the current through the resistor, and R is the resistance.

Substituting the given values, we get:

\(V = (2.80)*(4.00) = 11.2 V\)

This is the voltage drop across the resistor. The voltage across the battery terminals will be higher than this by the amount of the battery's internal resistance, which we can assume to be negligible. Therefore, the terminal voltage of the battery is:

\(V_{Ter} = V + V_r\)

Where \(V_r\) is the voltage drop across the resistor.

\(V_{Ter}= 11.2 V + 12.0 V = 23.2 V\).

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Given data

*The weight of the box is W = 500 N

*The distance of the plank from the fulcrum is d = 5 m

*The given force at a distance from the fulcrum is D = 10 m

The minimum force is required to lift the box is given by the net torque as

Substitute the known values in the above expression as

Hence, the minimum force is required to lift the box is F = 250 N

(a) In a parallel-flow arrangement, the outlet temperature of the water and the air can be determined using the energy balance equation. The heat transfer rate between the water and the air is equal to the product of the water mass flow rate, specific heat capacity of water, and the change in temperature of the water:

Similarly, the heat transfer rate between the air and the water is equal to the product of the air mass flow rate, specific heat capacity of air, and the change in temperature of the air:

Since the heat exchanger is operating under fully-developed flow conditions, the outlet temperature of the water and the air can be found by equating the heat transfer rates:

By substituting the given values, including the specific heat capacities of water and air, and solving the equations, the outlet temperatures of the air and water can be calculated.

(b) In a counter-flow arrangement, the outlet temperatures of the air and water can be determined using a similar energy balance equation. However, in this case, the change in temperature of the air is taken as the difference between the outlet and inlet temperatures of the air:

Again, by equating the heat transfer rates, substituting the given values, and solving the equations, the outlet temperatures of the air and water in a counter-flow arrangement can be calculated.

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Answer:

negatively

Explanation:

To find the spherical convex mirror radius, learn the focal length and magnitude.

What is focal length?

The focal length of a thin lens in air is measured from the lens's center to its primary foci, also known as focal points. The focal length of a converging lens, such as a convex lens, is positive and determines how far a collimated light beam must travel to focus on a single point.

What is magnitude?

Magnitude typically refers to size or distance. By comparing the size and motion speed of the object, we can relate magnitude to movement. The object's or quantity's size determines its magnitude.

R=0.123m

Focal length E= R/2

E= - 0.0615m.

Therefore, the focal length is 0.0615m.

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Answer:

A) Moving them farther apart

Explanation:

     Increasing the distance between the two metal spheres will increase the amount of electrical attraction, hence answering your question.

     Since their charges are already equal, there will not be repelling

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

2m 13\(\frac{1}{3}\)s

Explanation:

1.5m = 1s

200m = \(\frac{200}{1.5}\) × 1s

          = 133\(\frac{1}{3}\)s

          = 2m 13\(\frac{1}{3}\)s

Answer:

c

Explanation:

Answer:

This is equal to 1.9 kilometers.

Explanation:

For every foot it is 0.0003048 so multiply this number by 6500 and get your answer. Hope this helps have a good day

Answer: it's an electronic device

Explanation: it's where you store and process data, it acts according to the instructions given to it in a variable program.

Sorry if this wasn't the answer you were looking for.

Answer:

i) Power = Force * Velocity = 1100 * 15 = 16500 W = 16.5 kW(ii)  Find the value of k first: F = 400 + k(15^2)                                              k = 28/9    F = 400 +(28/9)(30^2) = 320

Explanation:

Answer:

Try lookin those questions up on Brainly

Explanation:

Answer:

Here's a list of a few reasons behind cracked or chipped walls:

Moisture-laden walls

Weather conditions

Incompatibility with the surface

Inferior-quality paints

Let’s discuss each of them one by one.

Explanation:

Lots of moisture

In a house, bathroom and kitchen are the two places where there is a lot of moisture and dampness. Therefore, you will see that these places are the first to report the problem of flaky paint. When moisture is absorbed, it passes through various coats of paint, removing the adhesive that sticks the paint to the wall. Therefore, you can spot paint coming off in the form of flakes or like a banana peel. This shows the extra moisture in the walls need to be addressed immediately.

Too much sunlight

Paint often chips off walls due to high temperatures. If direct sunlight hits the walls all day, it can cause the paint to dry out faster. The oil paints start to crack, while latex paints lose their quality to stick to the walls.

Incompatible paints

When painting, it is extremely important to use the same kind of paint on the surface that’s being coated. For instance, if it is latex paint, it isn’t compatible with oil-based paints and shouldn’t be painted on top of each other. If you are planning to use the leftover oil-paint as a second coat over the base coat of latex paint, then be prepared to see the paint coming off sooner than expected.

Also, make sure the surface on which you are about to paint is compatible with the paint you are using. For instance, smooth surfaces require a certain kind of paint and layering that keeps the coating intact. For uneven surfaces, it’s better to go for textured paint. It is important to prime and prep the surface first before applying a coat of paint to make sure the paint doesn’t come off easily.

Low-quality paints

Some paints seem good, especially to your wallet, but once you use them, you will face bad consequences. Inferior-quality paints do not adhere to the walls properly and also do not give a nice finish once the paint job is done. To avoid cracks in the walls, do not use low-quality or expired paints.

the magnitude of the magnetic field at the center of the loop is 1.15 × 10⁻⁴ T.

Given data:

Number of turns (n) = 20Radius of the loop

(r) = 16.3 cm

Current (I) = 0.565 A

Magnetic field at the center of the loop can be calculated by using the formula:

B = μ₀nI/2r

Where,

μ₀ is the permeability of free space.

Magnetic field formula in the case of a flat circular loop can be defined as B = μ₀NI/2R,

where μ₀ is the permeability of free space, N is the number of turns in the loop, I is the current in the loop, and R is the radius of the loop.

Substituting the given values in the formula, we get:

B = (4π×10⁻⁷ N/A²) × (20 turns) × (0.565 A) / (2 × 16.3 cm)

B = 1.15 × 10⁻⁴ T

Therefore, the magnitude of the magnetic field at the center of the loop is 1.15 × 10⁻⁴ T.

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The height of the cliff is approximately 60.5 feet.

When an object is dropped from a height and falls freely under the force of gravity, its speed increases until it reaches the ground.

The relationship between the height, speed, and acceleration due to gravity can be described using the equation:

\(v^2 = u^2 + 2gh\)

where v is the final velocity (88 ft/s), u is the initial velocity (0 ft/s), g is the acceleration due to gravity (32 ft/s^2), and h is the height of the cliff.

By rearranging the equation, we can solve for h:

\(h = (v^2 - u^2) / (2g)\)

Plugging in the given values, we get:

\(h = (88^2 - 0^2) / (2 * 32) \\ = 60.5 feet\)

Therefore, the height of the cliff is approximately 60.5 feet.

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The number of oscillations of the toy in a second is 1.25.

The given parameter:

The frequency of an object is calculated as follows;

\(f = \frac{n}{t} \\\\\)

where;

The number of oscillations of the toy in a second is calculated as follows;

\(1.25 = \frac{n}{1} \\\\n = 1.25\)

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We are given that an object is launched with an initial height and we are asked to determine its maximum height. To do that we will determine first the time it takes the object to reach the maximum height which is given by the following formula:

Where:

Replacing the values we get:

Solving the operations we get:

Now, to determine the height associated with this time we will use the following formula:

Where:

In this case, the initial height is 40 meters. Replacing the known values:

Solving the operations:

Therefore, the maximum height the ball reaches measured from the ground is 64.61 meters.

Now we are asked to determine the final velocity of the object. To do that, we will use the following formula:

Where:

Now we solve for the final velocity first by adding the square of the initial velocity:

Now we take the square root to both sides:

Replacing the known values:

Solving the operations:

Therefore, the final velocity is 35.6 meters per second directed towards the ground.

Now we are required to determine the time the object stays in the air. To do that we will use the following formula:

We will solve for "t" first by subtracting the initial velocity from both sides:

Now we divide both sides by the acceleration of gravity with the negative sign:

Now we replace the values, but we need to have into account that since the final velocity is directed towards the ground its sign is negative:

Solving the operations:

Therefore, the cannonball's total time is 5.87 seconds.

(a) The value of C is 12.17 V/mm.

(b) The electric field is 27.04 N/m².

(c) The force is 1.90 x 10⁻¹⁷ N.

a) To determine the value of C, we first need to calculate x, which is the distance from the cathode to the anode. Using the given distance between the cathode and anode (13.6 mm), we can calculate x as 6.8 mm. We can then use this value of x, along with the given potential difference between the electrodes (264 V), to calculate the value of C using the equation C = V/x4/3:

C = 264 V/6.84/3 = 12.17 V/mm4/3

b) The electric field between the electrodes is given by Ex = -dV/dx. Using the result from part (a) for C and the given distance between the electrodes (13.6 mm), we can obtain a formula for Ex as a function of x:

Ex = -(12.17 V/mm4/3) x (4/3)x-5/3 =27.04 N/m²

c) The force on an electron when the electron is halfway between the electrodes can be calculated using the equation F = qEx, where q is the charge of the electron. Using the result from part (b) for Ex, we can calculate the force on an electron at x = 6.8 mm as:
F = -1.60 x 10⁻¹⁹ C x (-11.9 V/mm1/3)

F = 1.90 x 10⁻¹⁷ N

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Answer:

C. seismographs

Explanation:

Theirs another name for seismographs but c is correct

Answer:

Luge

Explanation:

Explanation:

if the runner maintains an average speed of 5.5 m/s

we can use the formula

vt = d

hence the answer would be:

5.5 × (30 × 60)

note: we have to convert meter to second which is the SI unit.

answer: 4950 meters

Answer:6m

Explanation:

I guessed the answer and it was right. It was not the tall ones like 16 or 150 because it only took 1.1 second

Given that,

A penny takes 1.1 seconds to hit the ground.

To find,

How high up is the window?

Solution,

When the penny is dropped, its initial velocity is equal to 0 i.e.\(u=0\). The second equation of motion is used to find the relation between position and time. The second equation of motion is :

\(s=ut+\dfrac{1}{2}at^2\)

Where

s is the distance

a is acceleration

Here, s = the height of the window from the ground and a = g i.e. acceleration due to gravity

So,

\(s=\dfrac{1}{2}gt^2\)

Put all the values,

\(s=\dfrac{1}{2}\times 9.8\times (1.1)^2\\\\s=6.05\ m\)

or

\(s=6\ m\)

Answer:

The window is \(6\ m\) high. The correct option is (d).

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Galaxy a is receding from us at x km/s, while galaxy b’s recession velocity is 3x km/s. Based on Hubble’s law, it implies that the galaxy b is twice as far from us as galaxy a.

Hubble's Law states that the recessional velocity of a galaxy (that is, the speed at which it is moving away from us) is proportional to its distance from us. If a galaxy is moving away from us faster, it is further away than a galaxy that is moving away from us slower. In this case, galaxy a is receding from us at x km/s, while galaxy b’s recession velocity is 3x km/s. This indicates that galaxy b is twice as far from us as galaxy a.

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