Which characteristic involves cleavage and fracture?

the way a mineral breaks apart
the color of a mineral’s powder
the light that is reflected from a mineral’s surface
the number and angle of crystal faces of a mineral

Answer:

electron has a constant velocity in the north direction and accelerates in the west direction, the electron is accelerating and its velocity on this axis increasing in the west direction.

Explanation:

In this exercise we are asked about the speed of the electron

The electric force is F = q E

the charge of the electron is q = -e = - 1.6 10-19 C

If we use Newton's second law

Y axis (North-south direction)

       \(v_{y}\) = cte

X axis (East-West direction)

      F = m a

     - e E = m a

      a = - e / m E

whereby electron has a constant velocity in the north direction and accelerates in the west direction, the electron is accelerating and its velocity on this axis increasing in the west direction.

Answer:

The two main types of bonds formed between atoms are ionic bonds and covalent bonds.

Explanation:

Hope this helped <3

Answer:

The appropriate answer is "0.9152 seconds".

Explanation:

The given values are:

Maximum speed,

v = 8.85 m/s

Acceleration,

u = 9.67 m/s²

Now,

⇒ \(v = u+at\)

By putting the values, we get

⇒ \(8.85=0+9.67t\)

⇒      \(t=\frac{8.85}{9.67}\)

⇒         \(=0.9152 \ second\)    

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

Answer:

Net torque in positive direction:

Fz = -450 * cos 30 deg * 1.5 = -585 N-M

Fz = 200 * 3.5 = 700 N-M

Net F = 115 N-M

Torque is generally defined as L = R X F

X cross Y = Z     normal coordinate system

Note that Z will be out of the page giving the positive value for the torque.

Answer:

1568 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 80 Kg

Distance (d) = 5 m

Coefficient of kinetic friction (μ) = 0.4

Workdone (Wd) =?

Next, we shall determine the normal reaction. This can be obtained as follow:

Mass (m) = 80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal reaction (N) =?

N = mg

N = 80 × 9.8

N = 784 N

Next, we shall determine force of friction. This can be obtained as follow:

Coefficient of kinetic friction (μ) = 0.4

Normal reaction (N) = 784 N

Force of friction (F) =?

F = μN

F = 0.4 × 784

F = 313.6 N

Finally, we shall determine the work done. This can be obtained as follow:

Distance (d) = 5 m

Force of friction (F) = 313.6 N

Workdone (Wd) =?

Wd = F × d

Wd = 313.6 × 5

Wd = 1568 J

Thus, the workdone is 1568 J

The object will fall through a distance of 638.45 m.

Considering the question given above, the following data were obtained:

Time (t) = 11.3 s

NOTE: Acceleration due to gravity (g) = 10 m/s²

We can obtain the height as illustrated below:

H = ½gt²

H = ½ × 10 × 11.3²

H = 5 × 127.69

Therefore, the distance the object will fall is 638.45 m

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Answer:

\(38.3\ \text{m/s}\)

\(32.14\ \text{m/s}\)

6.55 seconds

\(52.65\ \text{m}\)

\(254.84\ \text{m}\)

Explanation:

u = Initial velocity of rock = 50 m/s

\(\theta\) = Angle of throw = \(40^{\circ}\)

g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

Horizontal component is given by

\(u_x=u\cos\theta\\\Rightarrow u_x=50\times \cos40^{\circ}\\\Rightarrow u_x=38.3\ \text{m/s}\)

The horizontal component of the velocity is \(38.3\ \text{m/s}\)

Vertical component is given by

\(u_y=u\sin\theta\\\Rightarrow u_y=50\times \sin40^{\circ}\\\Rightarrow u_y=32.14\ \text{m/s}\)

The horizontal component of the velocity is \(32.14\ \text{m/s}\)

Time of flight is given by

\(t=\dfrac{2u\sin\theta}{g}\\\Rightarrow t=\dfrac{2\times 50\sin40^{\circ}}{9.81}\\\Rightarrow t=6.55\ \text{s}\)

The hang time of the rock is 6.55 seconds

Maximum height is given by

\(h=\dfrac{u^2\sin^2\theta}{2g}\\\Rightarrow h=\dfrac{50^2\sin^240^{\circ}}{2\times 9.81}\\\Rightarrow h=52.65\ \text{m}\)

Maximum height is \(52.65\ \text{m}\)

Range is given by

\(d=\dfrac{u^2\sin2\theta}{g}\\\Rightarrow d=\dfrac{50^2\sin(2\times40)^{\circ}}{9.81}\\\Rightarrow d=254.84\ \text{m}\)

The range is \(254.84\ \text{m}\)

Answer:

8 divided by 12 is 1.6

Explanation:

. .......

Answer:

acceleration = change in velocity / change in time

acceleration = 14/10

acceleration = 1.4/s^2

The distance between two charges is 1.075 cm.

The distance between the charges is calculated using Coulomb's law as shown below;

F = kq1q2/r²

Fr² = kq1q2

r² = kq1q2/F

r = √( kq1q2/F)

where;

r = √( 9 x 10⁹ x 20 x 10⁻⁶ x 18 x 10⁻⁶/2.8 x 10⁴)

r = 0.01075 m

r = 1.075 cm

Thus, the distance between two charges is 1.075 cm.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer: B. Sally remains in the operating room at all times and avoids leaning

on tables.

Explanation: took the quiz.

The statement that demonstrates proper maintenance of a Sterile field is Sally remains in the operating room at all times and avoids leaning on tables.

Sterile field refer to a section area that is set apart in order to place sterile surgical drapes on the patient's surgical site and also on the stand that will hold in place the sterile instruments and other items needed during surgery.

The purpose of the sterile field is to minimize the population of microbes.

Therefore, The statement that demonstrates proper maintenance of a Sterile field is Sally remains in the operating room at all times and avoids leaning on tables.

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Answer:

mark me brainliest

Explanation:

The change of temperature at absolute scale is. A. 3.73 K

Answer:

373K

Explanation:

300°c - 200°c =100°c

Absolute scale means Kelvin scale so

0°c= 273°c

100°c = 100 + 273

=373K

Answer:

The answer is "\(4,500 - 225 \ V\)".

Explanation:

Using formula for calculating the Voltage:

\(M_1=12.5\\\\M_2=250\\\\V_1=4,500 \\\\\bold{\text{Formula: }}\\\\\to \bold{\frac{m_1}{m_2}=\frac{V_2}{V_1}}\\\\\to \frac{12.5}{250}=\frac{V_2}{4,500}\\\\\to 0.05=\frac{v_2}{4,500}\\\\\to 0.05\times 4,500= V_2\\\\\to V_2=225\\\\\)

Hence the range of accelerating in voltage is \(4,500 - 225 \ V\)

Answer:

  7) 5 m/s

  8) 1.5 m/s

  9) -9 m/s^2

  10) 2.2 m/s

  11) 5 s

Explanation:

These problems make use of the relations:

  a = ∆v/∆t

  d = 1/2at^2 . . . . acceleration to/from rest

  v^2 = 2ad . . . . . acceleration to/from rest

In each case, choose the formula appropriate to the question, fill in the given values, and solve for what's missing.

__

7) v^2 = 2ad

  v = √(2(9.8 m/s^2)(1.5 m)) = √(29.4 m^2/s^2) ≈ 5 m/s

__

8) d = 1/2at^2

  a = 2d/t^2 = 2(75 m)/(10 s)^2 = 1.5 m/s^2

__

9) a = ∆v/∆t

  a = (-45 m/s)/(5 s) = -9 m/s^2

__

10) a = ∆v/∆t

  ∆v = a·∆t = (0.09 m/s^2)(10 s) = 0.9 m/s

Vivian's final speed is the initial speed plus the change in speed:

  1.3 m/s + 0.9 m/s = 2.2 m/s

__

11) a = ∆v/∆t

  ∆t = ∆v/a = (0.50 cm/s -0.75 cm/s)/(-0.05 cm/s^2) = -.25/-.05 s = 5 s

We will have the following:

The option that is not representative of a type of wave is "Phase", all the other options are representatives of waves,

Answer: Physical weathering

Explanation:

The value of 3993 BTUs in Joules is 4212838.0195 Joules.

The correct statement is " A dry cell battery has magnetic properties.", The correct option is C.

A dry cell battery does generate its own magnetic field due to the flow of electric current through the battery.

The magnetic field is created by the movement of charged particles (electrons) within the battery. This magnetic field is relatively weak and is not typically strong enough to be used for practical applications outside of the battery itself.

So, the magnetic properties of the dry cell battery are important for understanding its behavior within an electrical circuit.

Therefore, The correct answer is option C.

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Answer:

W = 68.6 N

Explanation:

Given that,

Force acting on a right side = 30 N

Mass of the object, m = 7 kg

The force of friction acting on the car = 3 N

We need to find the weight of the object.

The weight of an object is given by :

W = mg

Substitute all the values,

W = 7 × 9.8

W = 68.6 N

So, the weight of the object is 68.6 N.

The minimum stopping distance of the car is determined as 8 m.

The minimum stopping distance of the car is calculated as follows;

d = (u²)/(2a)

where;

when the minimum stopping distance = 2 m, initial velocity = 40 km/hr = 11.11 m/s

2 = (11.11²)/(2a)

a = (11.11²)/(2 x 2)

a = 30.86 m/s²

when the speed becomes 80 km/h, the minimum stopping distance is calculated as;

u = 80 km/h = 22.22 m/s

d = (22.22² )/ (2 x 30.86)

d = 8 m

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Answer:

The smart car hit with the greater force

Explanation:

Despite the trailers weight, the smart car moves with more speed and momentum than that of the trailer...

I don't even understand what I'm typing

Both will exert equal and opposite force on each other.

When a tractor-trailer and a smart car collide head-on, we can determine the relative forces experienced by each vehicle using Newton's second law of motion.

According to this law, the force acting on an object is equal to the rate of change of its momentum.

Let's consider the tractor-trailer as object 1 with mass \(\(M_1\)\) and velocity \(\(V_1\)\), and the smart car as object 2 with mass \(\(M_2\)\) and velocity \(\(V_2\)\).

The force exerted on object 1 due to object 2 \((\(F_{12}\))\) can be calculated as:

\(\[F_{12} = M_1 \cdot \frac{{dV_1}}{{dt}}\]\)

Similarly, the force exerted on object 2 due to object 1 \((\(F_{21}\))\) can be calculated as:

\(\[F_{21} = M_2 \cdot \frac{{dV_2}}{{dt}}\]\)

Since the collision is head-on, the direction of the forces will be opposite for the two objects.

To determine which object experiences a greater force, we need to compare the magnitudes of \(\(F_{12}\) and \(F_{21}\)\) = 0 by Newton's third law.

Thus, both will exert equal and opposite force on each other.

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Answer:

\(u= 10 \frac{m}{s} \\ t = 10 \: s \\ a = .5 \frac{m}{ {s}^{2} } \\ v = x \\ v = u + at \\ x = 10 + .5 \times 10 \\ x = 10 + 5 \\ x = 15 \frac{m}{s} \\ thank \: you\)

Answer:

15m/s

Explanation:

a=(Vf-Vi)/t

0.5m/s^2=(Vf-10m/s)/10s

when we solve this Vf=15m/s^2

Answer:

a) F= 324N

b) u = 518.4

Explanation:

a/ 2 soft colliders: mv1^2 + mv2^2 = MV^2

<=> 0.024*450^2 +0.967*0^2=(0.024+0.976)V^2

<=>V= 69.71 m/s

v^2-v0^2= 2as

0^2 - (69.71)^2 = 2a*7.5

<=> a= -324m/s^2

We have: -F = ma (because F is resistance, it is negative)

-F= 1*-324

F= 324N

Therefore, the force that makes the two bodies at rest is 324N.

b) We have the formula: F pulling force - F friction = ma

<=> MV^2 - umg = ma

<=> 1*(69.71)^2 - u*10 = -324

<=> u = 518.4

So the coefficient of friction is 518.4

The correct answer is 5828.675 J.

Given combined mass 4kg and mass of bullet 150gm=0.150kg.

Total mass= 4+0.150=4.150kg

Velocity=53 m/s

Kinetic energy = \(\frac{1}{2} *m*v^{2}\) =0.5*4.150*\(53^{2}\) =5828.675 J

Kinetic energy is a type of power that an item or particle possesses as a result of motion. When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and consequently obtains kinetic energy. A moving object or particle's kinetic energy, which depends on both mass and speed, is one of its characteristics. Any combination of motions, including translation (or travel along a path from one location to another), rotation about an axis, and vibration, may be used as the type of motion.

A body's translational kinetic energy is equal to  \(\frac{1}{2} *m*v^{2}\) , or one-half of the product of its mass, m, and square of its velocity, v.

a trolley and a sandbag have a combined mass of 4 kg. a bullet with a mass of 150 gram is fired towards the trolley and is lodged in the sand bag immediately after the Collision, on the trolley and sandbag in combination with the bullet, move backwards at 53 metre per second calculate the kinetic energy of the trolley , with the sandbag and bullet ,directly after the Collision ​

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Answer:

Explanation:

  a )

from lens makers formula

\(\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})\)

f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face

putting the values

\(\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})\)

1.462 = 2 - 1 / r₂

1 / r₂ = .538

r₂ = 1.86 cm .

= 18.6 mm .

b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\(\frac{1}{v} - \frac{1}{u} = \frac{1}{f}\)

\(\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}\)

\(\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}\)

.5555 - .04

= .515

v = 1.94 cm

c )

magnification = v / u

= 1.94 / 25

= .0776

size of image = .0776 x size of object

= .0776 x 10 mm

= .776 mm

It will be a real image and it will be inverted.

Answer:

wet with high humidity

Explanation:

i took the test  

Explanation: