which axis will serve as the neutral axis? (you must provide an answer before moving to the next part.)

The beam of light from the lighthouse is moving at a speed of approximately 10π km/minute along the shoreline when it is 1 km away from point P.

To determine the speed at which the beam of light from the lighthouse is moving along the shoreline when it is 1 km away from the point P, we need to consider the relationship between angular velocity, linear velocity, and distance.

Given that the lighthouse makes five revolutions per minute, we can determine its angular velocity (ω) using the formula:

ω = 2πn

where n is the number of revolutions per unit of time. In this case, n is equal to 5 revolutions per minute. Substituting the values, we have:

ω = 2π * 5 = 10π radians per minute

Now, to find the linear velocity (v) of the beam of light along the shoreline, we can use the relationship between angular velocity, linear velocity, and distance. This relationship is given by:

v = r * ω

where r is the distance from the center of rotation (in this case, the lighthouse) to the point at which we want to measure the velocity.

In this scenario, the distance from the lighthouse to the shoreline (point P) is given as 3 km. However, we are interested in finding the velocity when the beam of light is 1 km from point P. Therefore, we need to consider a new distance (r) of 1 km.

Substituting the values into the equation, we have:

v = 1 km * (10π radians per minute)

v = 10π km/minute

Therefore, the beam of light from the lighthouse is moving at a speed of approximately 10π km/minute along the shoreline when it is 1 km away from point P.

In summary, the speed of the beam of light from the lighthouse along the shoreline is determined by the angular velocity of the lighthouse and the distance from the center of rotation to the point of interest. In this case, with an angular velocity of 10π radians per minute and a distance of 1 km, the beam of light is moving at a speed of approximately 10π km/minute.

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When comparing three different ways of having a ball move down through the same height each circumstance, the acceleration varies.

The Earth's mass is what generates gravity. Your body's mass is affected by the combined gravitational pull of all of its mass. That is what gives you authority. If you were on a planet with a lower mass than Earth, you would also weigh less than you do now.

Every object in the universe that has mass is drawn to every other object, regardless of their size or location. Gravity exists whether you are on the Moon, the Earth, or far out in space. Gravity does not require air or an atmosphere to operate.

The acceleration of a body brought on by the force of the earth's gravitational field is known as the acceleration due to gravity, or simply g. This force can be expressed mathematically as mg, where m is the body mass.

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The linear (tangential) velocity of the lateral malleolus at frame 2 using the central difference formula is 0.42.

(A) To calculate the angle of the leg at frame 4, we need to use the given data and the formula.
Angle of leg = arctan(y/x)

Where x and y are the corresponding values in the table.

For frame 4,x = -0.206, y = 0.979 Angle of leg = arctan(0.979/-0.206)

≈ -79.67 degrees

Therefore, the angle of the leg at frame 4 is approximately -79.67 degrees.

(B) To calculate the linear (tangential) velocity of the lateral malleolus at frame 2 using the central difference formula, we need to use the given data and the formula.

The formula for the central difference is: f'(x) = (f(x+h) - f(x-h))/2h where f(x) is the function, h is the step size, and f'(x) is the derivative of the function.

Let's find the tangential velocity at frame 2 using the data for lateral malleolus displacement over time. Using the central difference formula:

f'(x) = (f(x+h) - f(x-h))/2h

where x = 2, h = 0.01, and f(x)

= lateral malleolus displacement at frame

2f'(2) = (f(2+0.01) - f(2-0.01))/2*0.01f'(2)

= (-0.2256 - (-0.234))/0.02f'(2)

= 0.42

Therefore, the linear (tangential) velocity of the lateral malleolus at frame 2 using the central difference formula is 0.42.

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Answer:

yes.................

The exponential form of the given number is (-7)⁴. 6⁵.

Exponent is the term used to describe a way to represent huge numbers using powers. In other words, the exponent describes how many times a number has been multiplied by itself.

A number that appears as a superscript over another number is the exponent. In other words, it means that the base has been elevated to a particular level of power. Other names for the exponent are index and power. mn indicates that m has been multiplied by itself n times if m is a positive number and n is its exponent which can be said as the m raised to n.

The given numbers are,

(-7) . (-7) . (-7) . (-7) . 6. 6 . 6 . 6 . 6

So, 7 is multiplied by itself 4 times and 6 is multiplied by itself 5 times.

Therefore, it can be written in the exponential form as,

(-7)⁴. 6⁵

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A constant force of 1.25N

Explanation:

This is a kinematics problem.

First find acceleration,

then use F = ma to find force.

Given:

mass = .5kg

delta x = 20m

t = 4s

a = ?

Friction = 0

From the kinematics equations:

delta x = Vi + (1/2)at^2

Plug in terms that are given:

20m = 0 + (1/2)a(4^2)

(2*20m)/(16s^2) = a

40m/(16s^2)= 2.5m/s^2

Now use F = ma to find force exerted on object.

F = (0.5kg)*(2.5m/s^2)

F = 1.25N

Answer:

Push - The most common form of force is a push through physical contact (like a lawnmower or shopping cart)

Pull - You can apply a force by directly pulling on an object (like pulling a wagon)

Explanation:

-- you sit on a chair

-- gravity pulls something down

-- water pushes a log up to float

-- air holds the skin of a balloon out, in a ball-shape

-- my dog bites a bone

-- air holds the tires of my car out, in donut shapes

-- a book presses on a table

-- my shoes press down on the floor

-- my feet press down on the bathroom scale

-- the bathroom scale presses up on my feet

-- gravity pulls the Earth up toward me

Answer: see example due to variation of factor

Explanation:    w = m x g

Weight= Mass (in kg) x Gravity (9.8m/s)

To get to kg from lbs take your weight divide by 2.2lbs well get you to kg

Example

Let's say a boy weighs 145lbs

145kg/2.2lbs=66kg

Now we use the equation

w=m x g

65kg*9.81m/s=637.65N

The broken pieces of the plates overlie a ductile layer known as asthenosphere.

Plate tectonics is a scientific hypothesis that explains the movement of Earth's lithosphere. Plate tectonics also explains the formation of mountains, volcanoes, and the occurrence of earthquakes. The Earth's lithosphere is composed of the Earth's crust, both continental and oceanic, and the uppermost part of the mantle. The lithosphere is divided into several plates that fit together like a puzzle. These plates are in constant motion, driven by the motion of molten rock in the Earth's mantle.

The plate boundaries can interact with one another in various ways. Divergent plate boundaries are where new lithosphere is created as the plates move apart. At convergent plate boundaries, one plate is forced beneath another. Transform plate boundaries are where plates slide past each other in a sideways movement.

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Answer:

Well before every single shift.

Explanation:

I acutally learned this yesterday

The initial moments after the Big Bang and the current universe have a few things in common like Expansion; Radiation; Structure formation; etc.

Expansion: The universe has been expanding since the Big Bang, and this expansion is still happening. The initial moments after the Big Bang were characterized by a period of rapid inflation, and this expansion has continued to shape the structure of the universe we see today.

Radiation: The universe was filled with intense radiation in the initial moments after the Big Bang, and this radiation still exists in the form of the cosmic microwave background (CMB) radiation.

This radiation is thought to have been produced about 380,000 years after the Big Bang and has been traveling through space ever since, providing us with valuable information about the early universe.

Formation of structure: The initial moments after the Big Bang set the stage for the formation of the large-scale structure of the universe we observe today, such as galaxies, stars, and planets. The tiny fluctuations in the density of matter in the early universe were amplified by gravitational attraction over time, leading to the formation of these structures.

However, there are also many differences between the early universe and the universe as it exists now. For example, the universe was much hotter and denser in the early moments after the Big Bang, and there were no stars or galaxies yet.

The universe has also undergone many complex physical processes over billions of years, such as the formation of black holes and the evolution of stars, that were not present in the early universe.

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Answer:

Explanation:

Since the bell is at rest in an elevated position, we can assume that it only has potential energy.

U=mgh is the formula for potential energy where U=potential energy, m= mass, g=acceleration due to gravity, and h=height.

Plug in known variables....

U=200kg*9.8m/s^2*45m

U=88200 joules of potential energy or letter D.

Answer:

annular solar eclipse

Explanation:

An annular solar eclipse happens when the Moon covers the Sun's center, leaving the Sun's visible outer edges to form a "ring of fire" or annulus around the Moon. It happened because the apparent size of the Moon is smaller than that of the Sun

Answer:

annular solar eclipse

Explanation:

a solar eclipse happens when the moon covers the sun centre

Answer:

20

Explanation:

\(100 \times 0.2 = 20\)

Answer:

1.96 kg * m2/s2

Explanation:

Answer:

41.57.

Explanation:

Sometimes if you type in google "area of a regular hexagon, it will give you a calculator you can use to solve your math questions.

Answer:

d = 96 meters

Explanation:

a = acceleration

t = time

d = distance

\(d = \frac{1}{2} \times a \times {t}^{2} \)

\(d = \frac{1}{2} \times 3 \times {8}^{2} \)

\(d = 96\)

Compared to a main-sequence star with a short lifetime, a main-sequence star with a long lifetime is less luminous, cooler, smaller, and less massive. This is because the length of a star's lifetime is largely determined by its mass.

More massive stars have a shorter lifespan because they burn through their fuel more quickly, while less massive stars have a longer lifespan because they burn their fuel more slowly. As a result, main-sequence stars with longer lifetimes tend to be smaller, cooler, and less luminous than those with shorter lifetimes.

This is because they are burning their fuel at a slower rate, producing less energy and heat. Additionally, less massive stars have lower surface temperatures, which also contributes to their lower luminosity and cooler temperature.

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In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.

Rules for naming Ionic compounds

The oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.

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Hi there!

We can use the rotational equivalent of Newton's Second Law:

\(\huge\boxed{\Sigma \tau = I \alpha}\)

Στ = Net Torque (Nm)

I = Moment of inertia (kgm²)

α = Angular acceleration (rad/sec²)

We can plug in the given values to solve.

\(\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}\)

Answer:

By opening the door, Elijah is using the chemical energy, which he obtained from eating food to do work. Thus, he is converting chemical energy to mechanical energy.

Stretching the spring by opening the screen door convert the potential energy which is stored in the spring to kinetic energy.

Overall there is conversion of chemical energy to potential energy.

By letting the door go, Elijah is using chemical energy. By snapping shut, the door is converting potential energy to kinetic energy. The overall energy change is conversion of chemical energy to kinetic energy.

Explanation:

Answer:

no :)

Explanation:

ezzzzzzzzzzzzzzzzzzzz

Liquid water is not itself wet, but can make other solid materials wet. Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.

According to Wien's law, the color of the sun should be a bright white or slightly bluish-white. This is because Wien's law states that the peak wavelength of the sun's radiation is in the ultraviolet region, which corresponds to a color on the blue end of the visible spectrum.

However, since the sun emits radiation across a broad range of wavelengths, it appears as a bright white ball in the sky to the human eye.

Based on Wien's Law, the Sun's color is primarily white. Wien's Law helps determine the peak wavelength of radiation emitted by a black body, such as the Sun, based on its temperature. The Sun's surface temperature is around 5,500°C (9,932°F), which corresponds to a peak wavelength in the visible light spectrum, causing it to appear white to the human eye.

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The angle of refraction for the light ray with the wavelength of 589nm traveling through air strikes a crown glass at 30.0° incidence is 19.2°.

Refraction is the quantity used to measure the amount of refraction taking place at any boundary when light passes between the two mediums.

Refractive index can be calculated using Snell's law, the formula for calculating angle of refraction is as follows:

n₁/n₂ = sinФ₁/sinФ₂

n₁. sin(i) = n₂. sin(r)

where, n₁ = refractive index of medium 1

n₂ = refractive index of medium 2

i = angle of incidence in air

r = angle of refraction in glass

Therefore, by putting the values in this formula we can get the angle of refraction.

(1) × sin(30°)=(1.52) × sin(r)

sin(r)= 1/2 × 1.52

sin(r) = 1/ 3.04

r = sin⁻¹(0.328)

r = 19.2°

Therefore, Angle of refraction = 19.2°

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Your question is incomplete, most probably the complete question is:

A light ray of wavelength 589 nm (produced by a sodium lamp) traveling through air strikes a smooth, flat slab of crown glass at an angle of 30.0 to the normal. If the index of refraction of the crown glass is 1.52 and the index of refraction of air is 1. Find the angle of refraction.

Answer:

A or People who sell coffee with caffeine

Explanation:

Edge 2021, Have a great day/night

Answer:

people who sell coffee with caffeine

Explanation: got it right

Magellan could not use Polaris for navigation in the Southern Hemisphere because it is not visible from that region.

Polaris, also known as the North Star, has been used for navigation by explorers in the Northern Hemisphere. However, when Magellan sailed to the Southern Hemisphere, he could not use Polaris for navigation.

Polaris is located very close to the North Celestial Pole, which means it appears to be almost directly above the Earth's North Pole. As a result, when navigating in the Northern Hemisphere, Polaris remains relatively fixed in the night sky, providing a reliable point of reference for determining north.

In the Southern Hemisphere, however, Polaris is not visible. This is because it is located close to the Earth's North Pole, and the South Celestial Pole does not have a bright star comparable to Polaris. Navigators in the Southern Hemisphere must rely on other celestial objects, such as the Southern Cross or specific constellations, to determine their direction.

Therefore, Magellan could not use Polaris for navigation in the Southern Hemisphere because it is not visible from that region.

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Answer:

Her linear velocity (speed) is approximately 2.2 m/sec

Her angular velocity is approximately 1.26 rad/second

Explanation:

The given parameters are;

The diameter of the merry-go-round, d = 3.5 m

The number of revolutions she travels per minute = 12 revolutions per minute

Therefore, we have;

The distance she travels in one revolution =  π·d = π × 3.5 m

The distance of the twelve revolutions  = 12 × π × 3.5 m

The time she takes for the 12 revolutions = 1 minute = 60 seconds

Therefore, her speed = 12 × π × 3.5 m/(60 seconds)  ≈ 2.2 m/sec

Her angular velocity = Angle covered/Time = 12 × 2 × π/60 ≈ 1.26 rad/second.

The converted unit from mile per hour to feet per second is 71.87 ft/s.

We need to know about unit conversion to solve this problem. The unit conversion can be used to convert a unit to another unit. It can be defined as

a = xb

where a is unit a, b is unit b and x is the constant of conversion.

From the question above, we know that

v = 49 miles/hour

1 mile = 5280 ft

By substituting the given parameters, the converted unit is

v = 49 miles/hour

v = 49 x (5280 ft) / (3600 s)

v = 49 x 1.47 ft/s

v = 71.87 ft/s

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Explanation:

initial velocity U = 20m/s

Final velocity V = 35m/s

time = 15.0 secs

change in velocity = 35 - 15

= 20m/s

acceleration a = change in velocity/time V/t

a = (35-20)/15

a= 15/15

Hence, your acceleration is 1m/s^2

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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