Answer: 1 2 and 4 hope this helps
Step-by-step explanation:
Answer:
yes, the correct answers are:
A) 1 = 2(x2 + 2x)
B) 1 = 2x2 + 4x
D) 3 = 2(x + 1)2
Step-by-step explanation:
got it correct in edg 2020 hope this is of help :)
Cooper obtains an experimental functions of the stream function and the velocity potential for a particular flow type which are given by ψ=2xy and φ=x
2
−y
2
. Show that the conditions for continuity and irrotational flow are satisfied.
The given functions ψ = 2xy and φ = x^2 - y^2 satisfy the conditions for continuity and irrotational flow.
To show continuity, we need to verify that the partial derivatives of ψ and φ with respect to x and y are equal. Let's calculate these partial derivatives:
∂ψ/∂x = 2y
∂ψ/∂y = 2x
∂φ/∂x = 2x
∂φ/∂y = -2y
From the above calculations, we can see that the partial derivatives of ψ and φ with respect to x and y are equal. Therefore, the condition for continuity, which requires the equality of partial derivatives, is satisfied.
To show irrotational flow, we need to verify that the curl of the velocity vector is zero. The velocity vector can be obtained from the stream function ψ and velocity potential φ as follows:
V = ∇φ x ∇ψ
Taking the curl of V:
∇ x V = ∇ x (∇φ x ∇ψ)
Using vector calculus identities and simplifying the expression, we find:
∇ x V = 0
Since the curl of the velocity vector is zero, the condition for irrotational flow is satisfied.
Therefore, based on the calculations and verifications, we can conclude that the given functions ψ = 2xy and φ = x^2 - y^2 satisfy the conditions for continuity and irrotational flow.
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Solve the equation.
p−3=−4
p=
The value of p in the given equation is -1.
Given is an equation p-3 = -4, we need to find the value of p,
So,
p-3 = -4
p = -4+3
p = -1
Hence, the value of p in the given equation is -1.
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The grass in Jamie's yard grew 161616 centimeters in 101010 days. It was growing at a constant rate.
How many days did it take the grass to grow 111 centimeter?
days
How many centimeters did the grass grow in 111 day?
centimeters
Days it took the grass to grow 1 centimeter and centimeters the grass grew in 1 day
0.625 days to grow 1 cm.
16/10 = 1.6 cm in 1 day.
How many centimeters did the grass grow in 111 days?According to the law of proportion, any two ratios or fractions must be equal.
In only a week and a half, the grass in Jamie's backyard grew by 16 cm. it is expanding at an unchanging pace.
We need to determine how many days have passed since the grass has grown one centimeter.
Let's say that x represents the number of days that the grass grew one centimeter.
Given the following definition of proportion:
16/10=1/x
16x = 10
x = 0.625 days
As a result, one centimeter of grass growth occurred after 0.625 days had passed.
b)
Change x into 1. Because x is the number of days.
16/10=1/1
16/10
1.6
'In conclusion, in 1 day, 1.6 cm will grow.
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A car traveled 180 miles at a constant rate.
Part 1. Complete the table to show the rate at which the car was traveling if it completed the same distance in each number of hours.
travel time (hours) rate of travel (miles per hour)
(5:
1040)
(4.5:
520)
(3:
360)
(2.25:
180)
Answer 1:
1040
Answer 2:
520
Answer 3:
360
Answer 4:
180
the lengths of songs on the radio are normally distributed with a mean length of 210 seconds. if 38.2% of all songs have lengths between 194 and 226 seconds, then the standard deviation of this distribution is
Answer:
Step-by-step explanation:
in a multiple regression problem involving two independent variables, if b1 is computed to be 2.0, it means that
In a multiple regression problem involving two independent variables, if b1 is computed to be 2.0, it means that For every unit increase in x1, the predicted mean of Y rises by 2 units holding \(x_{2}\) constant.
Given data,
Slope b1 = +2
Mutiple regression which means,
Use multiple linear regression to determine the relationship between two or more independent variables and one dependent variable.
The value of the dependent variable at a specific level of the independent variables (For instance, the crop's anticipated yield at specific levels of temperature, rainfall, and fertilizer application).
\(y = b_{0} +b_{1}x_{1}+b_{2}x_{2}+b_{3}x_{3}+....\)
\(b_{1}\)=2 means
The estimated mean of Y increases by 2 units for each increase of 1 unit of \(x_{1}\), holding \(x_{2}\) constant.
Hence, the expected mean of Y increases by two units for every unit increase in x1.
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Implicit Function Theorem. Suppose f(x, y) is a continuously differentiable R"- valued function near a point (a, b) = Rm x R", f(a,b) = 0, and det dyfl(a,b) #0. Then {(x, y) W f(x,y)=0} {(x, g(x)) xEX} for some open neighborhood W of (a, b) in Rm x R and some continuously differentiable function g mapping some Rm neighborhood X of a into R". Moreover, (dxg)x= -(dyf)-¹(x,g(x)) dx f(x,g(x)), and g is smooth in case f is smooth. = : Application Discuss how in general Implicit Function Theorem can be used to solve an optimization problem with two constraints. The objective function should have k ≥ 3 variables. Give a specific example with k at least 4. -
Eliminate the constraints g1 and g2 from the optimization problem, effectively reducing it to a problem with k - 2 variables.
The Implicit Function Theorem provides a powerful tool for solving optimization problems with constraints. In general, if we have an objective function with k ≥ 3 variables and two constraints, we can apply the Implicit Function Theorem to transform the constrained optimization problem into an unconstrained one. Consider an example with k ≥ 4 variables.
Let's say we have an objective function f(x1, x2, x3, x4) and two constraints g1(x1, x2, x3, x4) = 0 and g2(x1, x2, x3, x4) = 0.
We can define a new function:
F(x1, x2, x3, x4, y1, y2) = (f(x1, x2, x3, x4), g1(x1, x2, x3, x4), g2(x1, x2, x3, x4)) and apply the Implicit Function Theorem.
If det(dyF) ≠ 0, then we can solve the system F(x, y) = 0 to obtain a function y = g(x1, x2, x3, x4).
This allows us to eliminate the constraints g1 and g2 from the optimization problem, effectively reducing it to a problem with k - 2 variables.
The optimization problem can then be solved using standard unconstrained optimization techniques applied to the reduced objective function f(x1, x2, x3, x4) with variables x1, x2, x3, and x4.
The solutions obtained will satisfy the original constraints g1(x1, x2, x3, x4) = 0 and g2(x1, x2, x3, x4) = 0.
By using the Implicit Function Theorem, we are able to transform the optimization problem with constraints into an unconstrained problem with a reduced number of variables, simplifying the solution process.For example, the equation x 2 – y 2 = 1 is an implicit equation while the equation y = 4 x + 6 represents an explicit function.
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A parabola can be drawn given a focus of (8,10) and a directrix of y=6. write the equation of the parabola in any form
pls help its due in 5 min
The equation of the parabola is h²-16h+8k+32=0 when parabola can be drawn with a focus of (8,10) and a directrix of y=6.
Given that,
A parabola can be drawn with a focus of (8,10) and a directrix of y=6.
We have to find the equation of the parabola in any form.
We know that,
The distance of any point P is (h,k) on a parabola form a focus is equal to its perpendicular distance from the directrix.
So,
√((h-8)²+(k-2)²) = | (k-6)/√0²+1² |
Squaring on both sides
(h-8)²+(k-2)² = (k-6)²
From th formula (a-b)² = a²-2ab+b²
We get,
h²-16h+64+k²-4k+4 = k²-12k+36
h²-16h+64+k²-4k+4 - k²+12k-36 =0
h²-16h+64-4k+4+12k-36=0
h²-16h+8k+32=0
Therefore, The equation of the parabola is h²-16h+8k+32=0 when parabola can be drawn with a focus of (8,10) and a directrix of y=6.
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Test the exactness of ODE, if not, use an integrating factor to make exact and then find general solution: (2xy-2y^2 e^3x)dx + (x^2 - 2 ye^2x)dy = 0.
It is requred to test the exactness of the given ODE and then find its general solution. Then, if the given ODE is not exact, an integrating factor must be used to make it exact.
This given ODE is:(2xy - 2y²e^(3x))dx + (x² - 2ye^(2x))dy = 0.To verify the exactness of the given ODE, we determine whether or not ∂Q/∂x = ∂P/∂y, where P and Q are the coefficients of dx and dy respectively, as follows: P = 2xy - 2y²e^(3x) and Q = x² - 2ye^(2x).Then, we have ∂P/∂y = 2x - 4ye^(3x) and ∂Q/∂x = 2x - 4ye^(2x).Thus, since ∂Q/∂x = ∂P/∂y, the given ODE is exact.To solve the given ODE, we have to find a function F(x,y) that satisfies the equation Mdx + Ndy = 0, where M and N are the coefficients of dx and dy respectively. This is accomplished by integrating both P and Q with respect to their respective variables. We have:∫Pdx = ∫(2xy - 2y²e^(3x))dx = x²y - y²e^(3x) + g(y), where g(y) is a function of y. We differentiate both sides of this equation with respect to y, set it equal to Q, and then solve for g(y). We have:(d/dy)(x²y - y²e^(3x) + g(y)) = x² - 2ye^(2x)Thus, g'(y) = 0 and g(y) = C, where C is a constant.Substituting the value of g(y) in the equation above, we get:x²y - y²e^(3x) + C = 0, as the general solution.The given ODE is exact, so we can solve it by finding a function that satisfies the equation Mdx + Ndy = 0. After integrating both P and Q with respect to their respective variables, we find that the general solution of the given ODE is x²y - y²e^(3x) + C = 0.
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Let g(x) = ⌊ x ⌋. Find
a) g−1({0}).
b) g−1({−1, 0, 1}).
c) g−1({x | 0 < x < 1}).
a) g^(-1)({0}) = [0, 1)
b) g^(-1)({-1, 0, 1}) = (-1, 0) ∪ [0, 1) ∪ [1, 2)
c) g^(-1)({x | 0 < x < 1}) = (0, 1).
the inverse of g(x) = ⌊x⌋ for the set {x | 0 < x < 1} is g^(-1)({x | 0 < x < 1}) = (0, 1).
a) The inverse of g(x) = ⌊x⌋ is the set of values x for which ⌊x⌋ = 0. Since the greatest integer less than or equal to 0 is 0 itself, the inverse of g(x) = ⌊x⌋ for the set {0} is g^(-1)({0}) = [0, 1).
b) To find the inverse of g(x) = ⌊x⌋ for the set {-1, 0, 1}, we need to determine the values of x for which ⌊x⌋ takes on these values. For ⌊x⌋ = -1, x must be in the range (-1, 0). For ⌊x⌋ = 0, x must be in the range [0, 1). For ⌊x⌋ = 1, x must be in the range [1, 2). Therefore, the inverse of g(x) = ⌊x⌋ for the set {-1, 0, 1} is g^(-1)({-1, 0, 1}) = (-1, 0) ∪ [0, 1) ∪ [1, 2).
c) The inverse of g(x) = ⌊x⌋ for the set {x | 0 < x < 1} can be found by determining the values of x that satisfy this condition. Since g(x) rounds down to the nearest integer, the values of x for which 0 < x < 1 are in the interval (0, 1). Therefore, the inverse of g(x) = ⌊x⌋ for the set {x | 0 < x < 1} is g^(-1)({x | 0 < x < 1}) = (0, 1).
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a security camera at andover bank is mounted on a wall 9 feet above the floor. what angle of depression should be used if the camera is to be directed to a spot 6 feet above the floor and 12 feet from the wall?
The angle of depression should be 26.57 degrees so the security camera should be directed downwards from the wall.
To find the angle of depression, we can use the tangent function. Let's call the angle of depression "θ". The tangent of an angle is equal to the opposite side (the difference in height between the camera and the spot) divided by the adjacent side (the horizontal distance between the camera and the spot). So, in this case:
tan(θ) = 6/12 = 1/2
Now that we have the tangent value, we can use the inverse tangent function (arctan) to find the actual angle:
θ = arctan(1/2)
Using a calculator, we can find that the angle of depression is approximately 26.57 degrees. So the security camera should be directed downward at an angle of 26.57 degrees to be directed at the spot 6 feet above the floor and 12 feet from the wall.
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I don't get my question for my homework. Here is the questions, "You have 46 gold coins, 115 diamonds, and 184 rubies. You need to put them in treasure chests, and each chest must contain the same number of each individual item. What is the greatest number of treasure chests you can fill? How many gold coins in each chest? How many diamonds in each chest? How many rubies in each chest? " This is the type of question. There is also one more problem I'm stuck on. "You and some friends took a metal detector to the beach every day for a week to search for coins. You managed to find 246 nickels, 312 dimes, and 204 quarters. When you divided them up, you realized that each person got the same exact amount of each coin with no coins remaining. How many are in your group? How many nickels did each person receive? How many dimes did each person receive? How many quarters did each person receive?" Please help me out! Thanks
Answer:
Question 1
The greatest number of treasure chest you can fill = 23
Step-by-step explanation:
Gold coins = 46
Diamonds = 115
Rubies = 184
To determine the greatest number of treasure chests you can fill, find the highest common factors of 46, 115 and 184
46 = 1, 2, 23, 46.
125 = 1, 5, 23, 115
184 = 1,2,4,8,23,46,92,184
The highest common factors of 46, 115 and 184 is 23
The greatest number of treasure chest you can fill = 23
Number of gold coins in each chest = 46/23
= 2
Number of diamonds in each chest = 115 / 23
= 5
Number of rubies in each chest = 184 /23
= 8
Question 2
Nickels = 246
Dimes = 312
Quarters = 204
Find the highest common factor of 246, 312, 204
246 = 1, 2, 3, 6, 41, 82, 123, 246
312 = 1, 2, 3, 4, 6, 8, 12, 13, 24, 26, 39, 52, 78, 104, 156, 312.
204 = 1, 2, 3, 4, 6, 12, 17, 34, 51, 68, 102, 204
The highest common factor of 246, 312, 204 is 6
How many are in your group?
6 members
There are 6 members in your group that each person got the same exact amount of each coin with no coins remaining.
Number of nickels each person receive = 246 / 6
= 41
Number of dimes each person receive = 312 / 6
= 52
Number of quarters each person receive = 204 / 6
= 34
The variance of a distribution of means of samples of more than one is
A) smaller than the original population variance.
B) the same as the original population variance.
C) greater than the original population variance.
D) unrelated to the original population variance.
The variance of a distribution of means of samples of more than one is A) smaller than the original population variance.
When considering the distribution of means of samples, the central limit theorem states that as the sample size increases, the sampling distribution approaches a normal distribution regardless of the shape of the population distribution. Additionally, the standard error of the mean decreases as the sample size increases.
The variance of a population is denoted by σ^2.
The variance of the distribution of sample means, also known as the sampling distribution, is denoted by σ^2/N, where N is the sample size.
As the sample size (N) increases, the denominator increases, leading to a smaller value for the variance of the distribution of sample means (σ^2/N). Thus, the variance of the distribution of means of samples is smaller than the original population variance.
The variance of a distribution of means of samples of more than one is smaller than the original population variance. This is due to the central limit theorem and the decrease in standard error as the sample size increases.
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Why
is the use and interpretation of an R or s chart so critical when
examining an X-bar chart?
The use and interpretation of an R or s chart are critical when examining an X-bar chart because they provide additional information about the variation within the subgroups. This allows for a more comprehensive analysis of the process and helps identify any issues or sources of variability.
When using an X-bar chart, the focus is on monitoring the process mean or average. However, the X-bar chart alone does not provide information about the variation within the subgroups. This is where the R or s chart comes into play. The R chart measures the range of values within each subgroup, while the s chart measures the standard deviation.
By using an R or s chart alongside the X-bar chart, we can assess the variability within the subgroups and determine if it is stable over time. If the variation within the subgroups is high and unpredictable, it may indicate that the process is out of control or that there are sources of variation that need to be addressed. The R or s chart provides additional insights into the process performance and helps in identifying the presence of special causes of variation.
In summary, the use and interpretation of an R or s chart in conjunction with an X-bar chart allow for a more comprehensive analysis of process variation. This helps in understanding the stability and capability of the process and enables appropriate actions to be taken to improve quality and performance.
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Need help with this.
Answer:
a=6, b=59, c=28
Step-by-step explanation:
48/a+9=17 b-10/7=7 0.25c-5=2
48/a+9-9=17-9 7 (b-10/7) =7(7) 0.25c-5+5=2+5
48/a=8 10+ b-10=49+10 0.25c=7
a(48/a) = a (8) b=59 0.25c/0.25=7/0.25
48=8a c=28
a=6
Please help I’m confused. Image attached, thanks it’s number 3
Answer:
B
Step-by-step explanation:
The independent variable is t (time) because no matter what happens the weeks will still pass. The dependent variable is b (balance) because it depends on the amount of time passed. You can see that after every week the balance decreases by 50. So when the independent variable increases by 1, the dependent variable decreases by 50.
3
4
2
1280
Find the measure of Angle 1 in the parallelogram above.
Angle 1 = type your answer...
The value of angle 1 in the parallelogram is given as 26 degrees
How to solve for the value of the anglesLet us call the vertices of the angles as ∠A, ∠B, ∠C and ∠D
we have ∠ A represented as 1 and 2
∠B as 128
∠C as 3 and 4
∠D is unnamed
Using the property of parallelogram, we can see that
∠ A is opp ∠C hence they are equal
∠B = ∠D = 128 because they are opposite
Another property says that the sum of adjacent angles in a parallelogram are = 180 degrees they are supplementary
such that
∠ A + 128 = 180
∠ A = 180 - 128
∠ A = 52 degrees
∠ A is made up of two angles 1 and 2 that are equal
hence 52 / 2
= 26
Proof: the sum of internal angle in a parallelogram is 360 degrees
∠ A = ∠ C = 56 degrees because they are opposite
56 + 56 + 128 + 128
= 360 degrees
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7. Find the perimeter of the rectangle with length 51 feet and width 77 feet.179 ft128 ft3,927 ft256 ft
The perimeter of a rectangle is given by:
\(P=2(W+L)\)Where W= width = 77 ft and L=lenght = 51 ft:
\(\begin{gathered} P=2(77ft+51ft) \\ P=2(128ft) \\ P=256ftft \end{gathered}\)Hence, the correct answer is the last option.
10 Dakarai thought of a number. He subtracted 11 from the number then divided the result by 4.
a Use a mapping to write this as a function.
Dakarai's answer was -1.2.
b Use inverse functions to work out the number Dakarai thought of. Show all your working.
a) The function that represents the given situation is (x - 11) ÷ 4 = -1.2 and the number thought by Dakari is 6.2
b) The inverse function (y - 11) ÷ 4 = -1.2
Function:
The function that is from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.
Given,
Dakarai thought of a number. He subtracted 11 from the number then divided the result by 4.
Here we need to find the following
a) function that map the function and the number though by Dakarai
b) inverse of the function
Let us consider the number thought by Dakarai as "x"
First, he subtracted 11 from the number,
So it can be written as,
=> x - 11
After that, he divided it by 4
So, the it can be written as,
=> (x - 11) ÷ 4
Now, the result was -1.2
So the function is
=> (x - 11) ÷ 4 = -1.2
Now we have to solve this equation, in order to find the value of x,
=> (x - 11) ÷ 4 = -1.2
=> x - 11 = -1.2 × 4
=> x - 11 = -4.8
=> x = -4.8 + 11
Therefore, the value of x is 6.2
And the inverse of the function can be written as by change the x as y,
Then we get,
=> (y - 11) ÷ 4 = -1.2
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A park ranger counted the number of squirrels he saw while giving tours in three sections of a national park that have different areas.
Determine the unit rate in terms of the number of squirrels per square mile in the park, and complete the sentences below. Assume the relationship of squirrels to square miles shown in the table can be extended to the entire park.
Fill in the Blank.
The park ranger counted ___ squirrels for every mile in the park.
For every 128 square miles in the park, the park ranger would count ___ squirrels.
For every ___ square miles in the park, the park ranger would count 324 squirrels.
Area is a measure of the size of a two-dimensional surface or region. It is typically measured in square units, such as square meters or square feet. The area of a shape is found by multiplying the length and width of the shape in most cases, although the formula for finding the area may vary depending on the shape.
In the given question,
To find the unit rate in terms of the number of squirrels per square mile, we need to divide the total number of squirrels by the total area of the park.
Total number of squirrels = 20 + 32 + 128 = 180
Total area of the park = 5 + 8 + 32 = 45
Unit rate of squirrels per square mile = 180/45 = 4 squirrels per square mileFor every 128 square miles in the park, the park ranger would count 512 squirrels. (4 squirrels per square mile x 128 square miles = 512 squirrels)For every 40 square miles in the park, the park ranger would count 324 squirrels. (4 squirrels per square mile x 40 square miles = 160 squirrels)Note: The last blank can be filled with 40, as shown above.
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Answer:
1. 4
2. 512
3. 81
Step-by-step explanation:
Camden invested $680 in an account paying an interest rate of 2 1/4% compounded daily. Jayden invested $680 in an account paying an interest rate of 2 5/8% compounded continuously. After 19 years, how much more money would Jayden have in his account than Camden, to the nearest dollar?
Answer:690
Step-by-step explanation:
690
Answer: $3,261.
Step-by-step explanation:
The answer is $3,261. Jayden would have more money in his account than Camden because his account pays a higher interest rate and is compounded continuously, which allows more frequent compounding of interest. This means that Jayden's account accumulates more interest than Camden's account over time.
1 + 2a + 3 + 4a + 5 + 6a + ...... + 97 + 98a + 99 + 100a = 0 What does a equal?
Answer:
a = -50/51
Step-by-step explanation:
1 + 2a + 3 + 4a + 5 + 6a + ...... + 97 + 98a + 99 + 100a = 0
1 + 3 + 5 + ... + 99 + 2a + 4a + ... + 98a + 100a = 0 Eq. 1
99 + 97 + 95 + ... + 1 + 98a + 96a + ... + 4a + 2a = 0 Eq. 2
Add Eq. 1 and Eq. 2
100 + 100 + ... + 100 + 102a + 102a + ... 102a = 0
50(100)/2 + 50(102a)/2 = 0
2500 + 2550a = 0
2550a = -2500
a = -2500/2550
a = -250/255
a = -50/51
Suppose a sale price is $18 and the discount is 25%. Explain how to find the regular price.
Answer:
Step-by-step explanation:
x - 0.25x = 18
3/4x = 18
x = 24
when the points on a unit hypersphere, we know the projection on any unit vectors has mean 0 and variance 1. then, is this condition sufficient to say that the original points are uniformly distributed on the unit hypersphere?
No, the condition of having a mean of 0 and variance of 1 for projections on any unit vector is not sufficient to say that the original points are uniformly distributed on the unit hypersphere.
This is because it only guarantees that the projections have a specific statistical distribution, but it doesn't provide information about the distribution of the original points in the hypersphere. In fact, there are many non-uniform distributions that satisfy this condition, such as Gaussian or Laplace distributions.
To determine if the original points are uniformly distributed on the unit hypersphere, additional information about their distribution is needed, such as their density function or probability measure. One common way to test for uniformity is to use statistical tests such as the Kolmogorov-Smirnov test or the Anderson-Darling test, which compare the observed distribution to the expected distribution under uniformity.
In summary, having a mean of 0 and variance of 1 for projections on any unit vector is a necessary but not sufficient condition for uniform distribution on the unit hypersphere, and additional information and testing is needed to confirm uniformity.
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WILL GIVE BRAINLIEST!!
A line has a slope of 1/3 and passes through the point (–9, –3). What is its equation in slope-intercept form?
Answer:
y = \(\frac{1}{3}\) x
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
here slope m = \(\frac{1}{3}\) , then
y = \(\frac{1}{3}\) x + c ← is the partial equation
to find c substitute (- 9, - 3) , that is x = - 9, y = - 3 into the partial equation
- 3 = \(\frac{1}{3}\) (- 9) + c = - 3 + c ( add 3 to both sides )
0 = c
y = \(\frac{1}{3}\) x + 0 , that is
y = \(\frac{1}{3}\) x
is this correct ? if not what’s the correct answer?
Answer:
correct
Step-by-step explanation:
Corresponding vertices are listed in the same order. In BCDE, segment DE is listed last. In OPQR, the segment listed last is QR. If the figures are congruent, then ...
DE ≅ QR
graph below.
Plumbing Jobs
Total Charge
(in dollars)
225
200
175
150
125
100
75
50
25
5
0 31 2 3 4
Number of Hours
4.
What is the slope of the line graphed
above?
PLEASE HELP!!!
Write the factored form of the least common denominator needed to simplify this expression
Answer:
(g+5)x(g-3)
Step-by-step explanation:
A gardener already has 4 1/2 ft of fencing in his garden. He wants to fence in a square garden for his flowers. The length of one side of the garden will be 2 3/4 ft. How much more fencing will the gardener need to purchase?
The gardener will need to purchase an additional 6 1/2 ft of fencing to complete his square garden for his flowers.
You want to know how much more fencing the gardener will need to purchase if he already has 4 1/2 ft of fencing and
the length of one side of the square garden is 2 3/4 ft.
Since the garden is square, all sides have the same length. We know one side is 2 3/4 ft.
Multiply the length of one side (2 3/4 ft) by 4 to find the total amount of fencing needed for the entire garden:
2 3/4 × 4 = 11 ft.
Now, subtract the amount of fencing the gardener already has (4 1/2 ft) from the total amount needed (11 ft):
11 - 4 1/2 = 6 1/2 ft.
So, the gardener will need to purchase an additional 6 1/2 ft of fencing to complete his square garden for his flowers.
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Are vertical lines negative?
Vertical lines do not have positive slopes or negative slopes. They have undefined slopes.
Now, According to the question :
What is Vertical line?
A vertical line is a line, parallel to y-axis and goes straight, up and down, in a coordinate plane. Whereas the horizontal line is parallel to x-axis and goes straight, left and right.
Is a vertical line positive or negative?
The slope of a line can be positive, negative, zero, or undefined. A horizontal line has slope zero since it does not rise vertically (i.e. y1 − y2 = 0), while a vertical line has undefined slope since it does not run horizontally (i.e. x1 − x2 = 0).
Hence, Vertical lines do not have positive slopes or negative slopes. They have undefined slopes.
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