A physics student running 2.8 m/s increases her velocity to 4.7 m/s in 3.4 seconds. What is the magnitude of acceleration of the student?
Answer:
The magnitude of acceleration of the student is 0.6 m/s²
Explanation:
Given that,
Initial velocity = 2.8 m/s
Final velocity = 4.7 m/s
Time = 3.4 sec
We need to calculate the magnitude of acceleration of the student
Using formula of acceleration
\(a=\dfrac{v_{f}-v_{i}}{t}\)
Where, \(v_{f}\) = final velocity
\(v_{f}\) = final velocity
t = time
Put the value into the formula
\(a=\dfrac{4.7-2.8}{3.4}\)
\(a=0.6\ m/s^2\)
Hence, The magnitude of acceleration of the student is 0.6 m/s²
What volume of o2 is needed to react completely with 39.4 g of mos2 (molar mass = 160.06 g/mol) at stp?
The volume of O2 needed to react completely with 39.4 g of MoS2 at STP is approximately 18.4 liters.
To determine the volume of oxygen (O2) required to react completely with 39.4 g of MoS2 at STP (Standard Temperature and Pressure), we need to use stoichiometry. The balanced chemical equation for the reaction between MoS2 and O2 is 2 MoS2 + 7 O2 → 2 MoO3 + 4 SO2. From the equation, we can determine the molar ratio between MoS2 and O2. By converting the given mass of MoS2 to moles, we can then calculate the moles of O2 needed. Finally, using the ideal gas law and STP conditions, we can find the volume of O2.
The balanced chemical equation for the reaction between MoS2 and O2 is 2 MoS2 + 7 O2 → 2 MoO3 + 4 SO2. From the equation, we can determine the molar ratio between MoS2 and O2, which is 2:7. This means that for every 2 moles of MoS2, we need 7 moles of O2 for complete reaction.
First, we calculate the number of moles of MoS2 using its molar mass. The molar mass of MoS2 is given as 160.06 g/mol. Therefore, the number of moles of MoS2 is:
moles of MoS2 = mass of MoS2 / molar mass of MoS2
= 39.4 g / 160.06 g/mol
≈ 0.246 mol
Next, we use the molar ratio to determine the moles of O2 required:
moles of O2 = (moles of MoS2) × (7 moles of O2 / 2 moles of MoS2)
≈ 0.246 mol × (7/2)
≈ 0.861 mol
Finally, we can calculate the volume of O2 at STP using the ideal gas law, which states that PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
At STP, the pressure (P) is 1 atmosphere (atm) and the temperature (T) is 273.15 Kelvin (K). The ideal gas constant (R) is approximately 0.0821 L·atm/(mol·K). Plugging in the values, we have:
V = (nRT) / P
= (0.861 mol) × (0.0821 L·atm/(mol·K)) × (273.15 K) / 1 atm
≈ 18.4 L
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what are the heaviest elements not apprecitly larger than the lightest elements
The heaviest elements not appreciably larger than the lightest elements are the transition metals. These metals include elements like iron, copper, and gold. Although they are heavier than the lightest elements like hydrogen and helium, their size is not significantly larger.
This is because the size of an atom is determined by the number of protons in its nucleus and the number of electrons in its outermost shell. While the transition metals have more protons than the lightest elements, their outermost shells are also more tightly bound to the nucleus, making their size relatively small.
The size of an atom is also affected by the electron configuration, which determines the size of the electron cloud. The transition metals have a relatively stable electron configuration, which contributes to their small size. Additionally, the presence of multiple energy levels in the electron cloud of the transition metals means that they can have a range of sizes, with some being slightly larger than others.
In summary, the heaviest elements not appreciably larger than the lightest elements are the transition metals, which have a relatively small size due to the number of protons in their nucleus, the stability of their electron configuration, and the presence of multiple energy levels in their electron cloud.
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Two wires are identical, except that one is aluminum and one is copper. The aluminum wire has a resistance of 0.263Ω. What is the resistance of the copper wire? Take the resistivity of copper to be 1.72 x 10^-8 Ω·m, and that of aluminum to be 2.82 x 10^-8 Ω·m.
The resistance of the copper wire is 0.161 Ω. The resistance of a material depends on various factors, including its length, cross-sectional area, and temperature.
What is Resistance?
Resistance is a measure of how much a material opposes the flow of electric current. It is defined as the ratio of the voltage applied to a conductor to the current flowing through it, and is measured in ohms (Ω). Materials with high resistance are poor conductors of electricity, while materials with low resistance are good conductors.
We can use the formula for resistance of a wire:
R = (ρ * L) / A
where R is resistance, ρ is resistivity, L is length of the wire, and A is its cross-sectional area.
We know that the wires are identical, so they have the same length and cross-sectional area. Therefore, their resistances are proportional to their resistivities:
R_aluminum / R_copper = ρ_aluminum / ρ_copper
We can rearrange this to solve for the resistance of the copper wire:
R_copper = R_aluminum * ρ_copper / ρ_aluminum
Plugging in the given values, we get:
R_copper = 0.263 Ω * (1.72 x 10^-8 Ω·m) / (2.82 x 10^-8 Ω·m) = 0.161 Ω
Therefore, the resistance of the copper wire is 0.161 Ω.
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As shown in the figure, two blocks are connected by a very light string, and the upper block is pulled upward by a different string. The masses of the upper and lower blocks are 300 g and 240 g, respectively. The string between the blocks will break if its tension exceeds 3.6 N, and the string that pulls the combination upward will break if its tension exceeds 7.8 N.
(a) What is the largest upward acceleration that the blocks can be given without either string breaking?
(b) If the upward acceleration is slightly higher than this, which string breaks, the upper one or the lower one?
For strings between blocks:
(a) The largest upward acceleration is 0.014 m/s²
(b) The string between the two blocks break.
How to calculate tension?To find the largest upward acceleration, the tension in the string between the blocks is equal to the gravitational force acting on the lower block. The tension in the string pulling the combination upward is equal to the gravitational force acting on the combination.
a) The gravitational force acting on the lower block is the weight of the lower block (mass x acceleration due to gravity) = (240g x 9.8m/s²) = 2352 N.
The gravitational force acting on the combination is the weight of the combination (mass x acceleration due to gravity) = (540g x 9.8m/s²) = 5292 N.
Since the tension in the string between the blocks must not exceed 3.6 N, and the tension in the string pulling the combination upward must not exceed 7.8 N, the largest acceleration on the blocks without breaking either string is:
a = (3.6 N + 7.8 N) / 540 g = 0.014 m/s²
b) If the acceleration is slightly higher than this, the string that breaks is the one between the two blocks, as it is already under a lower tension than the string pulling the combination upward.
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Physics
1. A car travels north on the highway for 125 kilometers, then turns west for 75 kilometers, then makes a u-turn and travels south for 125 kilometers.
A. Determine the displacement of the car.
2. Anthony has 25 kilograms of sand, while Juan has 60 pounds of sand. Determine which of the two boys has the most amount of sand.
3. 4. A horse runs with a velocity of 15 km/hr towards the north for 90 minutes. Determine the displacement of the horse.
Explanation:
A car travels north on the highway for 125 kilometers, then turns west for 75 kilometers, then makes a u-turn and travels south for 125 kilometers.
A. To determine the displacement of the car, you would need to calculate the final position of the car relative to its initial position. In this case, the car traveled north for 125 km, then west for 75 km, and then south for 125 km. This means the car ends up in the same place it started (125 km south of its starting point), so the displacement would be 0 km.
Anthony has 25 kilograms of sand, while Juan has 60 pounds of sand. To determine which of the two boys has the most amount of sand, we need to convert the weight of the sand from pounds to kilograms. 60 pounds is approximately 27.2 kilograms. So Juan has 27.2 kilograms of sand and Anthony has 25 kilograms of sand. Anthony has more sand.
A horse runs with a velocity of 15 km/hr towards the north for 90 minutes. To determine the displacement of the horse, you would need to calculate the distance traveled by the horse. You can use the formula: Displacement = velocity x time. In this case, the velocity is 15 km/hr and the time is 90 minutes (converted to hours). So, Displacement = 15 x (90/60) = 22.5 km towards the North.
Ms. Reitman's scooter starts from rest and accelerates at 2.0 m/s2
What is the scooter's velocity after 2 s?
Answer: 4 m/s
Explanation:
The scooter's velocity after 2 seconds of its start will be 4 m/s.
State first equation of motion?
The first equation of motion is -
v = u + at
Given is Ms. Reitman's scooter that starts from rest and accelerates at
2 m/s².
We can write -
[a] = 2 m/s²
[t] = 2 s
Using the first equation of motion, we can write -
v = u + at
v = 0 + 2 x 2
v = 4 m/s
Therefore, the scooter's velocity after 2 seconds of its start will be 4 m/s.
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Which of the following does not accurately describe what we observe toward the Galactic center?
A) at radio wavelengths, we see giant gas clouds threaded by powerful magnetic fields
B) at infrared wavelengths, we see a massive stellar cluster
C) at optical wavelengths, we see a cluster of old, red stars
D) at X rays, we see faint emission from an accretion disk around a black hole
The option that does not accurately describe what we observe toward the Galactic center is, at optical wavelengths, we see a cluster of old, red stars. Option C.
This is because at optical wavelengths, the light is blocked by dust and gas in the Galactic center, and hence, we are not able to observe the old, red stars. However, at radio wavelengths, we see giant gas clouds threaded by powerful magnetic fields, which are responsible for the formation of stars in the center. At infrared wavelengths, we see a massive stellar cluster, which includes young, massive stars that emit a lot of infrared radiation.
At X rays, we see faint emission from an accretion disk around a black hole, which is the result of material being pulled into the black hole and emitting X-rays. Thus, all the other options accurately describe what we observe toward the Galactic center, except for option C.
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two identical waves of amplitude 5cm meet alarge ripple tank what will be amplitude of combined wave at apoint were they interference contructive and were they interfere destrucgivelythis is
The combined amplitude of two identical waves of amplitude 5 cm depends on whether the interference is constructive or destructive.
Constructive Interference: When two waves interfere constructively, their amplitude increases. In this scenario the combined waveform will have an amplitude equal to the sum of the individual amplitudes if the two waveforms are in phase (crest aligns with crest and trough aligns with trough). Consequently, in constructive interference, the amplitude of the combined wave will be 5 cm + 5 cm = 10 cm.
Destructive Interference : Interference that is destructive occurs when two waves interact in a way that cancels out each other's amplitudes. The amplitude of the combined waveform will be equal to the difference between the individual amplitudes in this case if the two waveforms are out of phase (peak aligned with trough). In destructive interference, the amplitude of the combined wave will be 5 cm – 5 cm = 0 cm.
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For a projectile's Vertical Motion: the total hang time is twice the time it takes the projectile to reach Vtop.
O True
O False
Answer:
false, because the two are the exact same, at least in time
The density of gold is 19.3 g cm³. What is the mass of a bar of gold in Kg that measures 6 cm x 4 cmx to 2 cm ?
solve
Answer: 0.9264 kg
Explanation: [I'll use "cc" for cubic centimeter, instead of cm^3.
The volume is 6cm*4cm*2cm = 48 cm^3 (cc).
Density of Au is 19.3 g/cc
Mass of gold = (48 cc)*(9.3 g/cc) = 926.4 grams Au
1 kg = 1,000 g
(926.4 grams Au)*(1 kg/1,000 g) = 0.9264 kg, 0.93 kg to 2 sig figs
At gold's current price of $57,500/kg, this bar is worth $53,268. Keep it hidden from your lab partner (and instructor).
Flossie blew a tire 5 minutes into the second leg, up to that point she had traveled 10 km making her speed 2 km/m. It took 2 minutes to fix her tire. Flossie had to finish within 2 minutes in order to stay even with the evil Mabel. If Flossie had 8 km left what speed will she need to win?
Answer:
4km/m
Explanation:
She was going at 2km/m, so 2 kilometers per minute. She has 2 minutes therefore she needs to double her rate to 4 kilometers per minute.
6.1 6.2 5 x 10-5 t (s) 1 x 10-4 State the Doppler effect in words. The average frequency of the social vocalisations of these dolphins is 38 kHz. Show by calculation that the frequency recorded is 2 kHz higher than the actual frequency. (2) (2)
The calculated frequency recorded is 2 kHz higher than the actual frequency of 38 kHz.
It occurs when there is a relative motion between the source and the observer along the line of sight. When the source of the sound is moving towards the observer, the frequency of the sound waves appears to increase, resulting in a higher frequency than the actual frequency of the source.
Similarly, when the source is moving away from the observer, the frequency appears to decrease, resulting in a lower frequency than the actual frequency of the source.
The average frequency of the social vocalizations of the dolphins is 38 kHz. However, due to the Doppler effect, the frequency recorded is 2 kHz higher than the actual frequency.
Using the formula:
Δf/f = v/c
where,
Δf = change in frequency
f = actual frequency
v = velocity of the source
c is the speed of sound
From the given terms, we know that the time interval (t) is 6.1 to 6.2 seconds, which gives us a duration of 0.1 seconds. We also know that the velocity (v) is 5 x 10-5 meters per second, and the wavelength (λ) is 1 x 10-4 meters (since the speed of sound in water is 1500 meters per second).
Using the formula:
v = λ/t
we can calculate the frequency (f') recorded by the observer as:
f' = (c + v)/λ * f
where c is the speed of sound in water, which is approximately 1500 meters per second.
Substituting the given values, we get:
f' = (1500 + 5 x 10-5)/1 x 10-4 * 38 kHz
f' = 38.01 kHz
Therefore, the frequency recorded by the observer is 2 kHz higher than the actual frequency of the dolphins. This difference in frequency due to the Doppler effect is important to consider when studying animal vocalizations, as it can affect our understanding of their communication patterns and behaviors.
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Describe how the properties of sound waves change as they spread out in a spherical pattern.
To solve this we must be knowing each and every concept related to sound waves. Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.
What is sound waves?A sound is a type of energy or a vibration that moves through a material such as air or water. Sound may pass through with a gaseous medium as well. It is anything that is audible. The speed that sound varies depending on the medium.
A wave is a medium that transmits energy from one location to another. Waves are classified into three types: transverse waves, longitudinal waves, or surface waves. A sound waves change as they spread out in a spherical pattern, they go up and down.
Therefore, a sound waves change as they spread out in a spherical pattern, they go up and down.
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thermal energy is the _____ of the kinetic and potential energies of all particles in an object.
2. conductivity in an electrical circuit is analogous to in a magneticcircuita) retentivity c) resistivityb) permeability d) inductance
Conductivity in an electrical circuit is analogous to in a magnetic circuit resistivity. The correct option is (c).
Conductivity in an electrical circuit refers to the ability of a material to conduct electric current. Similarly, in a magnetic circuit, resistivity is analogous to conductivity.
Resistivity is a measure of how well a material opposes the flow of magnetic flux. It is denoted by the symbol ρ and is the reciprocal of permeability (μ) which relates to how easily a material can establish a magnetic field in response to an applied magnetic field.
Permeability (b) is a property that characterizes how easily a material can be magnetized in the presence of a magnetic field. It is the analog of permittivity in electrical circuits.
Retentivity (a) refers to the ability of a magnetic material to retain its magnetization after the removal of an external magnetic field.
Inductance (d) is a property of an electrical circuit related to the ability to store energy in a magnetic field when current flows through a conductor.
Therefore, the correct answer is (c) resistivity, as it represents the opposition to the flow of magnetic flux in a magnetic circuit, analogous to conductivity in an electrical circuit.
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a man of mass 60 60 kg, runs up the stairs of total height 5 5 meters in 4 4 seconds. how much power is exerted by the man?
The power exerted by the man is 735 watts.
To find the power exerted by the man, we need to use the formula for power, which is:
Power = Work / Time
Work is the product of force and displacement, so we can write the formula as:
Power = (Force × Displacement) / Time
We know that the displacement is 5 meters and the time is 4 seconds. To find the force, we need to use the formula for weight, which is:
Weight = Mass × Acceleration
The acceleration in this case is the acceleration due to gravity, which is 9.8 m/s². So the weight of the man is:
Weight = 60 kg × 9.8 m/s² = 588 N
Now we can plug in the values into the formula for power:
Power = (588 N × 5 m) / 4 s = 735 Nm/s = 735 W
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Three engines operate between reservoirs separated in temperature by 300 K. The reservoir temperatures are as follows:Engine A: Th = 1000 K, Tc = 700 K;Engine B: Th = 800 K, Tc = 500 K;Engine C: Th = 600 K, Tc = 300 K.Rank the engines in order of theoretically possible efficiency, from highest to lowest.
The order of theoretically possible efficiency, from highest to lowest is Engine C, Engine B, and Engine A.
The theoretical efficiency of a Carnot engine is given by the formula:
Efficiency = 1 - T_{c} / Th
where Th and T_{c} are the temperatures of the hot and cold reservoirs, respectively.
Using this formula, we can calculate the efficiency of each engine.
For engine A, we have:
Efficiency = 1 - T_{c} / Th = 1 - 700 K / 1000 K = 0.3 or 30%
For engine B, we have:
Efficiency = 1 - T_{c} / Th = 1 - 500 K / 800 K = 0.375 or 37.5%
For engine C, we have:
Efficiency = 1 - T_{c} / Th = 1 - 300 K / 600 K = 0.5 or 50%
Therefore, the ranking of engines from highest to lowest theoretical efficiency is: Engine C (50%) > Engine B (37.5%) > Engine A (30%)
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A light bulb has a resistance of 360 . What is the current in the bulb when it has a potential difference of 120 V across it?
0.33 A
3 A
480 A
43,200 A
Answer:
333 mAmps .33 A
Explanation:
v = ir
v/r = i
120 v / 360 ohm = .3333 A
Answer:
A). 0.33A
Explanation:
A ball is projected horizontally from the top of a hill with a velocity of 30m/s if it reaches the ground 5sec later the height of the hill is???
Answer:
The hill is a total of 150 meters tall
Explanation:
30×5=150
the best way to protect yourself from excessive exposure to radiation is to . question 33 options: not get x-rays wear a film badge limit the length of your exposure increase your distance from the source
One of the best ways to protect yourself from excessive exposure to radiation is to avoid unnecessary exposure. If possible, avoid getting X-rays or other types of radiation when they are not medically necessary. However, if you do need to get an X-ray, make sure it is done by a licensed professional who will take the necessary precautions to limit your exposure.
Radiation can be harmful to the human body, and exposure to excessive radiation can lead to serious health problems such as cancer and radiation sickness. Therefore, it is essential to protect yourself from excessive exposure to radiation.
Finally, increasing your distance from the source of radiation can also help protect you from excessive exposure. The further away you are from the source of radiation, the less exposure you will receive. Therefore, if you work in an environment where you are exposed to radiation, try to keep as much distance between yourself and the source as possible.
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You have decided to select a new car by using the scientific method, how might you proceed
Answer: hypothesize that a certain ageof car will give you a disired level of preformance
Explanation:
test the car, if it does not preform well consider a new model
what are the first 20 elements and their chemical symbols
Question is attached. Show Workings.
a) The time of revolution is 97.57 minute.
b) The acceleration of gravity at the orbit is 8.10 m/s².
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Orbital speed of the satellite is = 425 km/min.
a) The time of revolution = perimeter of the orbit ÷ orbital speed of the satellite
= 2π × 6600 km/425 km/min
= 97.57 minute.
b) The acceleration of gravity at the orbit is = g (R/r)²
= 9.8 × (6000/6600)² m/s²
= 8.10 m/s²
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How far must I compress a spring with spring constant 573N/m to produce a force of 184N? Express your answer to the nearest hundredth
compressed0.32 meters
Explanation
Step 1
The force exerted by a spring on objects attached to its ends is proportional to the spring's change in length away from its equilibrium length and is always directed towards its equilibrium position.
\(F=-kx.\)so
let
\(\begin{gathered} k=573\text{ }\frac{\text{N}}{m} \\ F=184\text{ N} \end{gathered}\)replace and solve for x
\(\begin{gathered} F=-kx \\ 184=-573\frac{N}{m}\cdot x \\ divide\text{ both sides by 573 N/m} \\ \frac{184}{-573\frac{N}{m}}=\frac{-573\frac{N}{m}\cdot x}{-573\frac{N}{m}} \\ -0.32\text{ m=x} \end{gathered}\)the negative symbol indicates the spring is compresed
so, the answer is
0.32 meters
I hope this helps you
. ___________ The heat and light move from the core into this layer.
\(\huge{ \star \fcolorbox{magenta}{purple}{ \fcolorbox{magenta}{blue}{ \fcolorbox{magenta}{pink}{ \fcolorbox{magenta}{red}{ \sf{photosphere}}}}}} \star\)
Answer:
PHOTOSPHERE
Explanation:
HOPE IT HELPS YOU
A concave mirror has a focal length of 20 cm. What is the position (in cm) of the resulting image if the image is inverted and four times smaller than the object? a. 15 b. 25 c.50 d. 100
The position of the resulting image is 25 cm (option b). To determine the position of the resulting image formed by a concave mirror, we can use the mirror equation.
Here is the mirror equation
1/f = 1/di + 1/do
Where:
f is the focal length of the mirror
di is the distance of the image from the mirror
do is the distance of the object from the mirror
focal length (f) = 20 cm
image is inverted and four times smaller than the object
Let's assume the distance of the object from the mirror (do) is positive. Since the image is inverted, the distance of the image from the mirror (di) will be negative.
Now, we can solve for di using the mirror equation:
1/20 = 1/di + 1/do
Since the image is four times smaller than the object, the magnification (m) can be expressed as:
m = -di/do = -1/4
Substituting the value of m in terms of di and do, we have:
-1/4 = -di/do
Simplifying, we get:
di = (do)/4
Now, let's substitute di = (do)/4 into the mirror equation:
1/20 = 1/[(do)/4] + 1/do
Simplifying further, we have:
1/20 = (1 + 4)/(4*do)
1/20 = 5/(4*do)
Cross-multiplying, we get:
4do = 520
4*do = 100
do = 100/4
do = 25 cm
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. explain what would cause this difference in theoretical mass of soap vs. recovered mass of soap if the mass is higher than expected, in addition, if the mass is lower than expected.
The difference between the theoretical mass of soap and the recovered mass can be caused by factors such as contamination, incomplete reaction, loss during handling, or side reactions. It's important to carefully consider these possibilities when analyzing differences in mass.
Theoretical mass of soap refers to the expected mass of soap that should be obtained during a chemical reaction, based on the balanced equation and stoichiometry. However, sometimes the actual mass of soap recovered may differ from the theoretical mass.
If the recovered mass of soap is higher than expected, it could be due to several reasons:
1. Contamination: There may be impurities or other substances mixed with the soap, leading to an increase in the overall mass. For example, if the soap was not properly dried before weighing, it might retain some water molecules, causing the mass to be higher.
2. Incomplete reaction: The reaction may not have gone to completion, meaning that not all the reactants were converted into soap. This could occur if the reaction conditions were not optimal or if the reactants were not mixed properly. In such cases, the actual mass of soap recovered would be lower than the theoretical mass, resulting in a higher overall mass.
If the recovered mass of soap is lower than expected, it could be due to the following reasons:
1. Loss during handling: Some soap may have been lost during the transfer or handling process, leading to a lower overall mass. For example, if the soap was spilled or left behind on the apparatus, it would not be included in the recovered mass.
2. Side reactions: During the soap-making process, there could be unintended side reactions that consume some of the reactants and result in the formation of other products. These side reactions reduce the amount of soap formed, leading to a lower recovered mass compared to the theoretical mass.
To summarize, the difference between the theoretical mass of soap and the recovered mass can be caused by factors such as contamination, incomplete reaction, loss during handling, or side reactions. It's important to carefully consider these possibilities when analyzing differences in mass.
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suppose a woman does 500 j of work and 9500 j of heat transfer occurs into the environment in the process. what is the change in her internal energy, assuming no change in temperature or consumption of food? (that is, there is no other energy transfer.)
The change in internal energy is 10,000 J.
Given that, Work = 500 J
Heat Transfer = 9500 J
Internal energy can be altered by the temperature difference between a system and its surroundings.
We need to calculate the change in internal energy.
Let us use the equation of internal energy of a system,
ΔU = Q - W
where, Q is heat
W is work done
Let us put the values in the formula,
ΔU = -9500 - 500 = -10,000 J
Negative sign of heat is taken as the heat is lost in the process.
Thus, the change in internal energy is 10,000 J.
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what metal can you melt using 1000 degress celcius
If you'll looking for a metal that melts at exactly 1000 degrees celcius, then Red Brass melts at exactly 1000 degrees celcius