Where would we find yellow bone marrow?​

Answer:

No

Explanation:

Droplets or aerosols. When an infected person coughs, sneezes, or talks, droplets or tiny particles called aerosols carry the virus into the air from their nose or mouth. Anyone who is within 6 feet of that person can breathe it into their lungs.

Airborne transmission. Research shows that the virus can live in the air for up to 3 hours. It can get into your lungs if someone who has it breathes out and you breathe that air in.

Surface transmission. Another way to catch the new coronavirus is when you touch surfaces that someone who has the virus has coughed or sneezed on. You may touch a countertop or doorknob that's contaminated and then touch your nose, mouth, or eyes. The virus can live on surfaces like plastic and stainless steel for 2 to 3 days. To stop it, clean and disinfect all counters, knobs, and other surfaces you and your family touch several times a day.

Fecal-oral. Studies also suggest that virus particles can be found in infected people's poop. But experts aren't sure whether the infection can spread through contact with an infected person's stool. If that person uses the bathroom and doesn't wash their hands, they could infect things and people that they touch.

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\(\%C_E = \frac{E}{T} * 100\%\)

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In \((Ca(OH)_2)\)

The amount of all elements is: (i.e formula mass of \((Ca(OH)_2)\))

\(T = 1 * Ca + 2 * H + 2 * O\)

\(T = 1 * 40 + 2 * 1 + 2 * 16\)

\(T = 74\)

The amount of calcium is: (i.e formula mass of calcium)

\(E = 1 * Ca\)

\(E = 1 * 40\)

\(E = 40\)

So, the percentage component of calcium is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{40}{74} * 100\%\)

\(\%C_E = \frac{4000}{74}\%\)

\(\%C_E = 54.05\%\)

The amount of hydrogen is:

\(E = 2 * H\)

\(E = 2 * 1\)

\(E = 2\)

So, the percentage component of hydrogen is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{2}{74} * 100\%\)

\(\%C_E = \frac{200}{74}\%\)

\(\%C_E = 2.70\%\)

Similarly, for oxygen:

The amount of oxygen is:

\(E = 2 * O\)

\(E = 2 * 16\)

\(E = 32\)

So, the percentage component of oxygen is:

\(\%C_E = \frac{E}{T} * 100\%\)

\(\%C_E = \frac{32}{74} * 100\%\)

\(\%C_E = \frac{3200}{74}\%\)

\(\%C_E = 43.24\%\)

Answer:

Water moves through the hydrosphere in a cycle. Water collects in clouds, then falls to Earth in the form of rain or snow.

Answer:

Water moves through the hydrosphere in a cycle.

Explanation:

Hope it helps.

The most stable contributor's structure is the genuine structure of the resonance hybrid. The delocalization of electrons is what stabilizes the resonance hybrid. The potential resonance forms are quickly interconverted by a resonance hybrid.

Equivalent resonance types equally contribute to the hybrid's overall structure. Consider the resonance hybrid structure of a carboxylate group as an example. Different resonance contributors do not always contribute equally to the hybrid structure until they are equivalent to one another in terms of stability, as is the case for the carboxylate group, which has equivalent contributions from A and B as shown in the given figure. One resonance structure will more closely resemble the “actual” (hybrid) structure than another if it is more stable (lower in energy) than the other.

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Answer:

created when two objects rub together

Explanation:

when you rub two objects together, it creates friction and friction is energy.

Answer:

C

Explanation:

It was the first to show that the atom had no net charge.

Answer:

no ,its not necessary tht two objects have same volume have the same mass because the density of the material they are made up of can be different. mass and volume areindependent, two objects with thesame volume can have differentmasses. Therefore, the objects can have different densities.

During the oxidative phosphorylation, the electrons move is the correct option is a) Through electron transport chain.

In the oxidative phosphorylation the electrons will flow through the electron transport chain. The electrons will passes to the oxygen, which will combines with the protons to form the water. The electrons will move through the electron transport chain from the higher energy to the lower energy state. The energy that is release will moves the protons through the channels in  membrane proteins, and moving it into the inner space of membrane .

Thus, the electrons move through the electron transport chain during the oxidative phosphorylation.

This question is incomplete, the complete question is :

During oxidative phosphorylation, which answer choice best describes how electrons move?

a) Through electron transport chain

b) Through electron carrier

c) Both a and b

d) None of the above

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When this new mixture is then filtered, the salt in the salty water solution passes through the filter paper to form the filtrate and the sand remains as the residue.

The process of mixtures

A mixture is composed of two or more types of matter that can be present in varying amounts and can be physically separated by using methods that use physical properties to separate the components of the mixture, such as evaporation, distillation, filtration and chromatography.

When water mixes with carbon dioxide, a substance called carbonic acid is formed. Carbonic acid is a weak acid that plays an important role in the carbon cycle. The carbon cycle is the process through which carbon moves from the atmosphere, to plants, then to animals, to the soil, and and back into the atmosphere.

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Answer:

100 percent  heterozygous and 0 percent of white rabbits

Explanation:

it would be 100%

hope that helped :)

The purpose of cracking in the production of ethene is to convert large molecules into small molecules.

Ethene can be produced from the thermal cracking of ethane and propene.

In thermal cracking, high temperature of about 750-850°C and pressure of up to about 70 atm is used to break carbon-carbon bonds. Free radicals are formed in the process.

More about petroleum refining processes:

Petroleum refinery can be classified into two broad categories, namely the main refining processes and conversion processes. Main refining processes includes distillation, absorption and adsorption, while conversion processes involves thermal cracking, catalytic cracking and hydrocracking.

As the name implies, cracking is generally the breaking up of larger molecules into smaller, more useful molecules, such as those with 5 to 12 carbons.

To better comprehend cracking processes, we can use the analogy of dropping a ceramic mug.

When this ceramic mug is dropped, it breaks into smaller ceramic pieces. This represents smaller molecules being formed from a larger molecule. The force used to break them into smaller molecules would differ in the various types of cracking processes. For example, thermal cracking mainly uses heat while catalytic cracking mainly uses a zeolite catalyst.

Note that for these cracking processes to occur, there are other conditions involved.

Additional:

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Forces can cause objects to accelerate , decelerate , stop , start moving , change direction , change shape , or even turn

Agarose gel electrophoresis differs from SDS-PAGE in all of the following ways except  loading buffer which generally gives the sample a uniform negative charge. As a result, choice A is the best one.

By determining their size and charge, small molecules (DNA, RNA, protein, etc.) or their fragments can be separated and analysed using the gel electrophoresis technique. Biochemistry as well as molecular biology use it to distinguish between a mixture of fragments of DNA and RNA by length, to determine the size of DNA as well as RNA fragments, or to separate amino acids by charge. Clinical chemistry uses it to separate amino acids by charge and size (IEF agarose, basically size independent). Its loading buffer typically imparts a homogeneous negative charge to the sample.

Therefore, the correct option is option A.

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Answer:

1. A. 9 eggs

2. B. 5:3

3. C. Exactly 44 g

4. C. Mass and atoms only

5. D. 6.81 g of PH₃

6. C. 88.4%

7. B. O₂

8. D. 30.8 g CO₂

9. B.

10. B.

11. C. 99 g

12. D. mole ratio

13. C. Theoretical

14. A. 6.0 mol H₂O

15. D. 39.7 g CH₃OH

16. A. 650 g HgO

17. D. 8.8 mol H₂

18. B. 82.6%

Explanation:

1. The number of eggs it takes to make 1 cake = 3 eggs

The number of eggs it takes to make 3 × 1 = 3 cake = 3 × 3 = 9 eggs

Therefore, the correct option is;

A. 9 eggs

2. The given reaction is presented as follows;

C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)

In the above reaction, we have;

Moles of , O₂, reacted = 5 moles

Moles of , CO₂, produced = 3 moles

The ratio of the of O₂ reacted to moles of CO₂ produced = 5 moles:3 moles

∴ The ratio of the of O₂ reacted to moles of CO₂ produced = 5:3

The correct option is;

B. 5:3

3. The reaction is presented as follows;

O₂ (g) + C(s) → CO₂ (g)

From the reaction, 1 mole (12 g) of carbon produces 1 mole of CO₂

The molar mass of CO₂ = The mass of 1 mole of CO₂ = 44.01 g/mol

Given that the reaction is completed, the mass of CO₂ produced = The mass of 1 mole of CO₂ ≈ 44 g

The correct option is;

C. Exactly 44 g

4. The given reaction is presented as follows;

N₂ + 3 F₂ → 2NF₃

The initial number of atom = 2 + 6 = 8

The final number of atom = 2 × 4   = 8

∴ The initial number of atom = The final number of atom

Therefore, the number of atoms is conserved;

The mass of the reactants ≈ 28 g/mol + 3 × 37.996806 g/mol ≈ 141.993612 g/mol ≈ 142 g/mol

The mass of the product ≈ 2 × 71 g.mol = 142 g/mol

∴ The mass is conserved

Moles of reactants = 1 + 3 = 4

Moles of products = 2

∴ The number of moles is not conserved

The correct option is

C. Mass and atoms only

5. The molar mass of P₄ = 123.895048 g/mol

One mole of P₄ (123.895048 g) produces four moles (4 × 34.00) of PH₃

6.20 g of P₄. will produce (4 × 34.00)/(123.895048) × 6.20 g ≈ 6.80576 g ≈ 6.81 g

The correct option is D. 6.81 g of PH₃

6. The percentage yield = ((The actual yield)/(The ideal yield)) × 100

The actual yield of silver = 38.1 g

The ideal yield of silver = 43.1 g

∴ The percentage yield = ((38.1 g)/(43.1 g)) × 100 = 88.3990719258% ≈ 88.4%

The percentage yield = 88.4%

The correct option is C. 88.4%

7. The given chemical equation is presented as follows;

CS₂ (g) + 3 O₂ (g) → CO₂ (g) + 2 SO₂ (g)

The number of moles in 192 g of O₂ = 192 g/(32 g/mol) = 6 moles

Given that 3 moles of O₂ reacts with 1 mole of CS₂ to produce 1 mole of CO₂ and 2 moles SO₂,  therefore 2 × 3 = 6 moles of O₂ will reacts with 2 × 1 = 2 moles of CS₂ to produce 2 moles of CO₂ and 4 moles SO₂

∴ The limiting reactant is;

B. O₂

8. The given chemical equation is presented as follows;

2 C₈H₁₈ (g) + 25 O₂ (g) → 16 CO₂ (g) + 18 H₂O (l)

The number of moles in 10 g of C₈H₁₈, n₁ = (10 g)/(114.26 g/mol)

The number of moles of CO₂ produced, n₂ = (10 g)/(114.26 g/mol) × 16/2 ≈ 0.7 moles

The mass of CO₂ produced, m ≈ 44.01 × n₂ ≈ 44.01 g/mol × 0.7 moles ≈ 30.807 grams ≈ 30.8 grams

The theoretical yield of CO₂ from completely burning 10.0 g of C₈H₁₈ ≈ 30.8 grams of CO₂

The correct option is D. 30.8 g CO₂

9. The correct option is B. The limiting reactants determine the maximum amount of product that can be formed

10. Option B, which has 3 atoms of each element combining to form a product with 1 atom of one element and 2 atoms of the other element

The correct option is B.

11. By the conservation of mass, we have;

The mass of the reactants = The mass of the products

Let 'x' represent the mass of zinc in the products of the reaction

Therefore, we have;

61 g of calcium + 207 g of zinc chloride = 169 g of calcium chloride + x g of Zinc

∴  x g = 61 g + 207 g - 169 g = 99 g

The mass of zinc in the products of the reaction, x g = 99 g

The correct option is;

C. 99 g

12. The quantity that must be used to convert from one chemical substance to another is the mole ratio

The correct option is D. mole ratio

13. The maximum mass of the product that could form in a reaction is called the theoretical yield, which is option C.

The correct option is C. Theoretical

14. 1 mole of O₂ produces 2 moles of water (H₂O), therefore;

3 × 1 = 3.0 moles of O₂ will produce 3 × 2 = 6 moles of H₂O

The correct option is

A. 6.0 mol H₂O

15. 2 mole × 2.02 g/mol = 4.04 g of H₂ (g) produces 32.05 g CH₃OH (l)

∴ 5 g of H₂ (g) will produce 32.05 g × 5/4.04 ≈ 39.6658416 g ≈ 39.7 g of CH₃OH

The correct option is;

D. 39.7 g CH₃OH

16. 2 (2 × 216.59 g = 433.18 g) moles of HgO produces 1 mole of O₂

1.5 mole of O₂ will be produced by 1.5 × 2 = 3 moles (3 × 216.59 g = 649.77 g ≈ 650 g) of HgO

The correct option is A 650 g HgO

17. 3 moles of H₂ produces 2 moles of NH₃

The number of moles of NH₃ in 100 g of NH₃, n = 100 g/(17.04 g/mol) = 5.868544 moles

The number of moles of H₂ that will produce 5.868544 moles of NH₃ = 3/2 × 5.868544 moles = 8.802816 moles ≈ 8.8 moles

Therefore, the correct option is;

D. 8.8 mol H₂

18. The theoretical yield of PbO = (223.2/331.2) × 9.90 g = 6.67173913 g

The percentage yield = (5.51 g)/(6.67173913 g) × 100 ≈ 82.6%

The correct option is option B 82.6%.

The daughter element is produced from the beta decay of ¹⁴⁵₅₆Ba is ¹⁴⁵₅₇La.

A beta particle is emitted from the nucleus of an atom during radioactive decay. The electron, however, occupies regions outside the nucleus of an atom.

Beta particle has no mass and minus charge on itself.

Radioactive decay equation for the Barium is shown as follow:

¹⁴⁵₅₆Ba → ¹⁴⁵₅₇La + °₋₁β

The daughter element which is produced from the from reaction is Lanthanum.

Hence, ¹⁴⁵₅₇La is the daughter element.

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Answer:

host

Explanation:

the virus exploits your cells

Answer:

parasite is worse than throwing up

Explanation:

throwing up tells you that you can't have an infection in every way possoble

Answer:

C should be your answer

Explanation:

I have notes with that question

By raising the pressure to 1.89 atm and keeping the temperature constant, 2.86 L volume of gas was consumed.

The initial pressure is 758 torr, and the question specifies a temperature of 21. The initial volume is 5.42 L. 1.89 atm has been given as the final pressure.

Atm units have been used to convert the original pressure.

1 atm Equals 760 torr so,

0.997 atm = 758 torr

In line with Boyle's law: \(P1*V1=P2*V2\)

Where, P1 and V1 stand for, respectively, the starting pressure and volume. The final pressure and volume are P2 and V2, respectively.

so,

0.997 atm *  5.42 L = 1.89 atm  * Final volume

Final volume: 2.86 L

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A 25.0-ml sample of 0.10 M HCl is titrated with the 0.10 M NaOH. The pH of the solution after the 12.7 ml of NaOH have been added to the acid is 1.4.

The moles of the HCl = molarity × volume

The moles of the HCl = 0.10  × 0.025

The moles of the HCl = 0.0025 mol

The moles of the NaOH = molarity × volume

The moles of the NaOH = 0.10  × 0.0127

The moles of NaOH = 0.00127 mol

HCl  +  NaOH ----> NaCl  +  H₂O

0.0025 mol of the HCl  react with the 0.0025 mol

Remaining moles =  0.0025 - 0.00127

                             = 0.00123 mol

[H⁺] = 0.00123 / ( 0.025 + 0.0127)

       = 0.033 M

pH = - log [H⁺]

pH = 1.4

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Answer:

option 3) They have no freedom to move

Answer:

C

Explanation:

The mass of AgBr produced from 22.5 L of AgNO₃ is 50.01 gram

Mass is a measure of the amount of matter in a substance or an object.

Here given reaction is stoichiometric

From the balanced equation for the reaction si

2AgNO₃ + MgBr₂ → 2AgBr + Mg(NO₃)₂

The mole ratio of AgNO₃ and AgBr is 2 : 1

Mole of 22.5 g AgNO₃ = 22.5/169.87

Mole of 22.5 g AgNO₃ = 0.1325 mole

Equivalent mole of AgBr = 0.265 mole

Mass of 0.265 mole AgBr = 0.265×188.77

Mass of 0.265 mole AgBr = 50.01 gram

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Answer:

es she from 20.cto 75.c?es así es la

To carry out the bromination of benzene via an electrophilic aromatic substitution reaction, the following reagents are necessary: Bromine Br2, Lewis acid catalyst (Iron Bromide), organic solvent (tetrachloride).

1. Bromine (Br2) as the electrophile
2. Lewis acid catalyst such as iron (III) bromide (FeBr3) or aluminum bromide (AlBr3) to activate the bromine and enhance the electrophilicity of the system.
3. An organic solvent such as carbon tetrachloride (CCl4) or chloroform (CHCl3) to dissolve the reactants and provide a medium for the reaction to occur.
Bromine (Br2): This provides the bromine atom for substitution on the benzene ring. A Lewis acid catalyst, such as Iron(III) bromide (FeBr3) or Aluminum bromide (AlBr3): This helps generate the electrophilic bromine species and activates the benzene ring for the substitution reaction.
With these reagents, you can perform the bromination of benzene successfully.

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The reagents necessary for the bromination of benzene via an electrophilic aromatic substitution reaction are bromine (Br2) and a Lewis acid catalyst such as iron (III) bromide (FeBr3) or aluminum bromide (AlBr3). Additionally, a solvent such as nitrobenzene or carbon tetrachloride may be used to facilitate the reaction.

1. Bromine (Br2): This is the halogen that will be introduced to the benzene ring during the reaction.
2. A Lewis acid catalyst, typically either Aluminum Bromide (AlBr3) or Iron(III) Bromide (FeBr3): This catalyst is required to generate the electrophilic bromine species that will react with the benzene ring.

Your answer: The reagents necessary for the bromination of benzene via an electrophilic aromatic substitution reaction are Bromine (Br2) and a Lewis acid catalyst, such as Aluminum Bromide (AlBr3) or Iron(III) Bromide (FeBr3).

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The balanced equation for the given reaction is:

16MnO4^- + 3Cr(OH)3 → 3CrO42- + 8MnO42- + 24OH^-

From the balanced equation, we can see that 24 hydroxide ions (OH^-) are produced on the product side.

Therefore, the balanced equation contains 24 hydroxide ions.

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Codominance is a type of inheritance pattern in which both alleles of a gene are expressed equally in the phenotype of the individual. This means that if a baby inherits two different alleles for a particular trait, both will be expressed in the baby's physical appearance.

In the case of the missing identification bracelets, the nurse could use the principle of codominance to help identify the babies and return them to their correct parents. For example, if one baby has a parent with blood type A and the other has a parent with blood type B, and both babies have blood type AB due to codominance, then the nurse could match the babies with their correct parents based on their blood type.

Similarly, if there are other observable traits that exhibit codominance, such as eye color or skin tone, the nurse could use these to help identify the babies and return them to their correct parents. By understanding and applying the principles of codominance inheritance, the nurse could help ensure that each baby is reunited with their rightful family.

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Answer:

Float a few ping pong balls in your water tub. The slightest breeze will create waves in the water and keep a solid layer of ice from forming for a lot longer.

a) Na, K, K+:The species in the appropriate order of the series (Increasing radius) is Na < K < K+.Na (sodium) has an atomic radius of 186 pm.K (potassium) has an atomic radius of 227 pm.K+ (potassium ion) has an ionic radius of 138 pm.

b) S, Cl, Cl-:The species in the appropriate order of the series (decreasing size) is S > Cl > Cl-.S (sulfur) has an atomic radius of 104 pm.

Cl (chlorine) has an atomic radius of 99 pm.Cl- (chloride ion) has an ionic radius of 181 pm.

c) Mg, Ca, Ba: The species in the appropriate order of the series (most negative to least negative electron affinity) (highest to lowest Electron Affinity) is Ba > Ca > Mg. Electronegativity decreases down a group, which means as we go down the group, the atoms have less attraction for electrons, making electron affinity less negative.Ba (barium) has the highest electron affinity among the given species.Ca (calcium) has the second-highest electron affinity among the given species.Mg (magnesium) has the lowest electron affinity among the given species.

d) Mg, Si, Cl: The species in the appropriate order of the series (increasing First ionization energy) is Mg < Si < Cl. The ionization energy increases as we move across a period from left to right.Mg (magnesium) has the lowest first ionization energy among the given species.Si (silicon) has a higher first ionization energy than magnesium.Cl (chlorine) has the highest first ionization energy among the given species.

e) Be, F, O: The species in the appropriate order of the series (least negative to most negative electron affinity) is O < F < Be. The electron affinity increases as we move across a period from left to right.O (oxygen) has the least negative electron affinity among the given species.F (fluorine) has a higher electron affinity than oxygen.Be (beryllium) has the most negative electron affinity among the given species.

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The number of hamburgers sold on Wednesday is 275.

Let's assume the number of hamburgers sold is x.

According to the given information, the number of cheeseburgers sold is 70 more than the number of hamburgers. So, the number of cheeseburgers sold can be expressed as x + 70.

The total number of hamburgers and cheeseburgers sold is given as 620, so we can set up the following equation:

x + (x + 70) = 620

Combining like terms, we get:

2x + 70 = 620

Subtracting 70 from both sides of the equation:

2x = 550

Dividing both sides by 2:

x = 275

Therefore, the number of hamburgers sold on Wednesday is 275.

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A characteristic that all members of the same species have (for example eyes) is called a species trait.

Species traits are characteristics shared by all members of a species, such as body size, length, or height.

Several creatures within a species may have distinct attribute values due to intraspecific variation, such as differing body weights, yet when combined, they produce a distribution that is unique to each species.

The biggest collection of creatures in which any two individuals of the right sexes or mating types may conceive a viable child, usually by sexual reproduction, is referred to as a species.

A species can also be identified by its karyotype, DNA sequence, anatomy, behaviour, or ecological niche.

Thus, A characteristic that all members of the same species have (for example eyes) is called a species trait.

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