where the dot needa go ?

Answer:

20 times

Step-by-step explanation:

40 / 2 = 20?? sorry if im wrong

Answer: 23 spools of thread

Step-by-step explanation:

0.2 times 9 = 1.8 spools of thread

25 - 1.8 = 23.2 spools of thread

Answer:

4

Step-by-step explanation:

g=4

that means

16/g= 16/4

16/4=4

The equation of the circle that passes through the point (-4,-3) and has a center at (-8, -6) is \((x + 8)^2 + (y + 6)^2 = 25\). The equation is in standard form, where the center and radius of the circle is (-8, -6), 5 units.

The equation of a circle with center (a, b) and radius r is given by:

\((x - a)^2 + (y - b)^2 = r^2\)

In this problem, we are given that the center of the circle is (-8, -6), so we can substitute these values for a and b in the equation:

\((x - (-8))^2 + (y - (-6))^2 = r^2\)

\((x + 8)^2 + (y + 6)^2 = r^2\)

The distance between two points (x1, y1) and (x2, y2) is given by the distance formula:

\(d = sqrt((x2 - x1)^2 + (y2 - y1)^2)\)

\(d = sqrt((x2 - x1)^2 + (y2 - y1)^2)\)

\(d = sqrt((4)^2 + (3)^2)\)

d = 5

Therefore, the radius of the circle is 5.

\((x + 8)^2 + (y + 6)^2 = 5^2\)

\((x + 8)^2 + (y + 6)^2 = 25\)

So the equation of the circle that passes through the point (-4, -3) and has a center at (-8, -6) is: \((x + 8)^2 + (y + 6)^2 = 25\)

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Area of triangle:

A= 1/2*b*h

=  1/2 *(29)* (19)

= 1/2 *(551)

= 275.5 in^2

Area of rectangle:

A= l * w

= (29) * (10)

= 290 in^2

Total Area:

275.5 + 290 = 565.5 in^2

Hope this helps! Have a great day :)

Answer:

565.5 in

Step-by-step explanation:

The area for a rectangle is A = lw

So A = (29)(10)

A = 290

The area for a triangle is A = 1/2bh

So A = 1/2(29)(19)

A = 1/2(551)

A = 275.5

You combine the two numbers to get a total area of 565.5 in

the answer is 120 just do 10*12

Answer:

The answer is 60.

Step-by-step explanation:

We are doing a triangle not a square, so divide 10*12 in half. What do you get? 60. That's your answer.

55/24 will be the simplified form of the expression 43/8 + 25/12 -31/6.

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a correct fraction is smaller than the denominator.

given an expression 43/8 + 25/12 -31/6

Simplify given data

=> 43/8 + 25/12 -31/6

=> 5 + 3/8 + 2 + 1/12 - 5 - 1/6

=> 2 + 3/8 + 1/12 - 2/12

=> 2 + 3/8 -1/12

=> 2 + 9/24 -2/24

=> 2 + 7/24

=> 55/24

therefore, The simplified form of the given equation will be 55/24.

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The number of bacteria in the colony after 16 hours = 992

The bacteria doubles every 4 hours and we are considering 16 hours

The number of times that the bacteria doubles is 16/4 = 4 times

Note that there is a first term and four other terms when the bacteria were doubled

There are 5 terms in total

Number of terms, n = 5

The initial amount of bacteria, a = 32

The bacteria doubles every 4 hours

That is, the common ratio, r = 2

Since there is a common ratio, this is a geometric progression.

The sum of n terms of a geometric progression is given as:

Substitute a = 32, r = 2, and n = 5 into the formula above to get the number of bacteria in the colony after 16 hours

The number of bacteria = 992

Answer:

the answer is 3

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

3=48/16

48/16 + 3/8 (6/16) = 54/16

54÷3=18

answer is 18 students

Big boxes have 1/4 of 20 gigabytes of ram will be 5 gigabytes.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Big boxes have 1/4 of 20 gigabytes of ram.

Then the multiplication of the numbers 1/4 and 20 will be given by putting a cross sign between them. Then we have

⇒ (1/4) x 20

⇒ 20 / 4

⇒ 5 gigabytes

Big boxes have 1/4 of 20 gigabytes of ram will be 5 gigabytes.

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The maximum volume of an open cylinder with surface area equal to 16π and a radius between 1 and 8 feet is 16π cubic feet, and it is achieved when the radius is equal to 2 feet and the height is equal to 4 feet.

The surface area of an open cylinder is given by the formula 2πrh + 2πr^2, where r is the radius and h is the height. We are given that the surface area is equal to 16π, so we have the equation:

2πrh + 2πr^2 = 16π

Simplifying this equation, we get:

r(h + r) = 8

We want to maximize the volume of the cylinder, which is given by the formula V = πr^2h. Using the equation we derived above, we can express the height in terms of the radius:

h = (8 - r^2)/r

Substituting this expression for h into the formula for the volume, we get:

V = πr^2((8 - r^2)/r)

Simplifying this expression, we get:

V = 8πr - πr^3

To find the maximum volume, we need to find the value of r that maximizes this expression. To do this, we take the derivative of the expression with respect to r:

dV/dr = 8π - 3πr^2

Setting this equal to zero, we get:

8π - 3πr^2 = 0

Solving for r, we get:

r = 2

We can verify at this is a maximum by taking the second derivative of the expression with respect to r:

d^2V/dr^2 = -6πr

At r = 2, this is negative, indicating that we have a maximum.

Therefore, the maximum volume is achieved when the radius is equal to 2 feet. Substituting this into the equation we derived for h, we get:

h = (8 - 2^2)/2 = 4

So the maximum volume is:

V = π(2)^2(4) = 16π cubic feet.

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Answer: QN = 12

Step-by-step explanation: This quadrilateral is a paralelogram because its 2 opposite sides (NP and MQ) are parallel and the other 2 (MN and PQ) are congruent.

In paralelogram, diagonals bisect each other, which means QR = RN.

If QR = RN:

QR = 6

Then,

QN = QR + RN

QN = 6 + 6

QN = 12

The diagonal QN of quadrilateral MNPQ is QN = 12.

Answer:

Value of An if n is 17 = -834

Step-by-step explanation:

Given:

A100 = 245

d = 13

n = 17

Find:

Value of An if n = 17

Computation:

An = a + (n-1)d

A100 = a + (100-1)13

245 = a + (99)17

245 = a + 1,287

a = 245 - 1,287

a = -1,042

So,

Value of An if n = 17

An = a + (n-1)d

A17 = -1,042 + (17-1)(13)

A17 = -1,042 + (16)(13)

A17 = -1,042 + 208

A17 = -834

Value of An if n is 17 = -834

If Lisa spends her income on veggie burgers and pints of soy milk and the price of veggie burgers is three times the price of a pint of soy milk, then when Lisa maximizes her utility she will buy both goods until the marginal utility of veggie burgers is three times the marginal utility of soy milk.

Therefore, if Lisa spends her income on veggie burgers and pints of soy milk and the price of veggie burgers is three times the price of a pint of soy milk, then when Lisa maximizes her utility she will buy both goods until the marginal utility of veggie burgers is three times the marginal utility of soy milk.

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The effective interest on £2000 at a 3% interest rate compounded quarterly over a period of 4 years is approximately £245.15.

To calculate the effective interest, we need to use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the future value of the investment (including interest)

P = the principal amount (initial investment)

r = the annual interest rate (as a decimal)

n = the number of compounding periods per year

t = the number of years

In this case, the principal amount (P) is £2000, the annual interest rate (r) is 3% (or 0.03 as a decimal), the compounding is done quarterly (n = 4), and the investment period (t) is 4 years.

Plugging the values into the formula:

A = £2000(1 + 0.03/4)^(4*4)

= £2000(1 + 0.0075)^16

= £2000(1.0075)^16

≈ £2000(1.126825)

Calculating the future value:

A ≈ £2253.65

To find the effective interest, we subtract the principal amount from the future value:

Effective Interest = £2253.65 - £2000

≈ £253.65

Therefore, the effective interest on £2000 at a 3% interest rate compounded quarterly after 4 years is approximately £253.65.

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Answer:

10, 0, 2.

Step-by-step explanation:

It means that the number is greater than -3.

So, 10, 0, 2, are all greater than -3, and all the other numbers are smaller. So 10, 0, 2 are the numbers that are part of the solution for x>-3.

Answer:

10(a), 0(c), 2(d)

Given:

\(\begin{aligned}&x^2+y^2=16 \\&z=x y\end{aligned}\)

Express 16 as \(4^{2}\): \(x^2+y^2=16\)

\(x^2+y^2=4^2\\x^2+y^2=4^2 \times 1\)

Trignometry,

\(\cos ^2(t)+\sin ^2(t)=1\)

Now, substitute \(\cos ^2(t)+\sin ^2(t)\) for 1:

\(\begin{aligned}&x^2+y^2=4^2 \times 1 \\&x^2+y^2=4^2 \times\left[\cos ^2(t)+\sin ^2(t)\right]\end{aligned}\\x^2+y^2=4^2 \times \cos ^2(t)+4^2 \times \sin ^2(t)\)

Law of indicates:
\(\begin{aligned}&x^2+y^2=[4 \times \cos (t)]^2+[4 \times \sin (t)]^2 \\&x^2+y^2=[4 \cos (t)]^2+[4 \sin (t)]^2\end{aligned}\\x^2=[4 \cos (t)]^2 \text { and } y^2=[4 \sin (t)]^2\)

Taking positive square roots as follows:

\(x=4 \cos (t), y=4 \sin (t)\)

Recall that, z = xy.

Now, we have:

\(\begin{aligned}&z=4 \cos (t) \times 4 \sin (t) \\&z=16 \cos (t) \cdot \sin (t)\end{aligned}\)

Now, substitute the values:
\(r(t)=x_t i+y_t j+z_t k\)

So, the vector r(t) is: \(r(t)=(4 \cos (t)) i+(4 \sin (t)) i+(16 \cos (t) \cdot \sin (t)) i\)

Therefore, the vector function r(t) is written as: \(r(t)=x_t i+y_t j+z_t k\)

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The return value of the given linear regression model with weights containing an input vector < 3, 1, 5 > is 85

To find the output of the given linear regression model with weights w0=6, w1=9, w2=2, and w3=10 for the input vector <3, 1, 5>,

follow these steps:

1. Multiply each input value by its corresponding weight: (3 * w1) + (1 * w2) + (5 * w3)

2. Add the result from step 1 to the bias term, w0.

Let's calculate:

Step 1: (3 * 9) + (1 * 2) + (5 * 10) = 27 + 2 + 50 = 79

Step 2: 79 + 6 = 85

So, the linear regression model will return a value of 85 for the given input vector <3, 1, 5>.

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Answer:

c≤−26

hope that helped <3

f(x) is concave down on the interval -5 ≤ x ≤ -6 and 0 ≤ x ≤ 6.

f(x) is concave up on the interval -6 ≤ x ≤ 0.

To determine where f(x) is concave up or concave down, we need to calculate the second derivative of f(x):

f(x) = x √(\(x^2\) + 36)

f'(x) = √\(x^2\) + 36) + \(x^2\) √(\(x^2\) + 36)

f''(x) = (x (\(x^2\) +72) )/((\(x^2\)+36)\(^(3\)/2))

To find where f(x) is concave up or concave down, we need to find where f''(x) > 0 (concave up) or f''(x) < 0 (concave down).

f''(x) = 0 when x = 0 or x = +/-6.

Thus, f(x) is concave down on the interval -5 ≤ x ≤ -6 and 0 ≤ x ≤ 6, and concave up on the interval -6 ≤ x ≤ 0.

The inflection point for this function is at x = 0.

To find the minimum and maximum for this function, we need to look at the endpoints and critical points of the interval -5 ≤ x ≤ 6.

f(-5) = -5√61 and f(6) = 6√72, so the minimum occurs at x = -5 and the maximum occurs at x = 6.

Therefore:

f(x) is concave down on the interval -5 ≤ x ≤ -6 and 0 ≤ x ≤ 6.

f(x) is concave up on the interval -6 ≤ x ≤ 0.

The inflection point for this function is at x = 0.

The minimum for this function occurs at x = -5.

The maximum for this function occurs at x = 6.

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The total savings at the end of the third year will be approximately \(\$417,060.15\).

To calculate the total amount saved at the end of the third year, we need to determine the savings accumulated during each period and then sum them.

In the first 15 years, with a monthly savings of \(\$300\)and an annual interest rate of \(3.5\%\), we can use the future value of an ordinary annuity formula:

\(\[A = P \times \left(\frac{(1 + r)^n - 1}{r}\right)\]\)

where:

- \(A\)is the accumulated savings

- \(P\) is the monthly savings amount

- \(r\) is the monthly interest rate (\(3.5\% / 12\))

- \(n\) is the total number of months (15 years x 12 months/year)

Calculating the first 15-year savings:

\(\[A_1 = 300 \times \left(\frac{(1 + \frac{0.035}{12})^{15 \times 12} - 1}{\frac{0.035}{12}}\right)\]\)

In the next 15 years, with a monthly savings of \(\$650\) and an annual interest rate of \(6.5\%\), we can use the same formula:

Calculating the next 15-year savings:

\(\[A_2 = 650 \times \left(\frac{(1 + \frac{0.065}{12})^{15 \times 12} - 1}{\frac{0.065}{12}}\right)\]\)

Finally, to find the total savings at the end of the third year, we sum the accumulated savings from the first and second periods:

\(\[A_{\text{total}} = A_1 + A_2\]\)

To calculate the total savings at the end of the third year, we first need to find the accumulated savings for the two periods.

Calculating the accumulated savings for the first 15 years:

\(\(A_1 = 300 \times \left(\frac{{(1 + \frac{{0.035}}{{12}})^{{15 \times 12}} - 1}}{{\frac{{0.035}}{{12}}}}\right) \approx 68,081.80\)\)

Calculating the accumulated savings for the next 15 years:

\(\(A_2 = 650 \times \left(\frac{{(1 + \frac{{0.065}}{{12}})^{{15 \times 12}} - 1}}{{\frac{{0.065}}{{12}}}}\right) \approx 348,978.35\)\)

Now, we can find the total savings at the end of the third year:

\(\(A_{\text{{total}}} = A_1 + A_2 \approx 68,081.80 + 348,978.35 = 417,060.15\)\)

Therefore, the total savings at the end of the third year will be approximately \(\$417,060.15\).

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If you Saving $300/month for 15 years at 3.5%, then $650/month for another 15 years at 6.5%, will yield approximately $21,628.59 after three years.

To calculate the total amount you will have at the end of the third year, we can follow these steps:

1. Calculate the future value of the first saving period:

Using the formula for compound interest:

\(\[ \text{Future Value} = P \times \frac{{(1 + r)^t - 1}}{r} \]\)

Where:

\(\( P \)\) = Monthly savings amount

\(\( r \)\) = Annual interest rate (as a decimal)

\(\( t \)\) = Time period in years

For the first saving period:

\(\( P = \$300.00 \)\)

\(\( r = 0.035 \)\) (3.5% annual interest rate)

\(\( t = 15 \)\) (years)

Future Value of the first saving period:

\(\[ \text{Future Value} = \$300.00 \times \frac{{(1 + 0.035)^{15} - 1}}{0.035} \]\)

2. Calculate the future value of the second saving period:

For the second saving period:

\(\( P = \$650.00 \)\)

\(\( r = 0.065 \)\) (6.5% annual interest rate)

\(\( t = 15 - 3 = 12 \)\) (remaining years after the first saving period)

Future Value of the second saving period:

\(\[ \text{Future Value} = \$650.00 \times \frac{{(1 + 0.065)^{12} - 1}}{0.065} \]\)

3. Calculate the total future value at the end of the third year:

Total Future Value = Future Value of the first saving period + Future Value of the second saving period

The calculations for the total amount you will have at the end of the third year are as follows:

Future Value of the first saving period:

\(\[ \text{Future Value of the first saving period}\) = \(\$300.00 \times \frac{{(1 + 0.035)^{15} - 1}}{{0.035}} \approx \$7,648.63\)

Future Value of the second saving period:

\(\[ \text{Future Value of the second saving period}\) = \(\$650.00 \times \frac{{(1 + 0.065)^{12} - 1}}{{0.065}} \approx \$13,979.96\)

Total Future Value at the end of the third year:

\(\[ \text{Total Future Value}\) = \(\text{Future Value of the first saving period} + \text{Future Value of the second saving period}\)

\(\[ \approx \$7,648.63 + \$13,979.96 \approx \$21,628.59 \]\)

Therefore, If you Saving $300/month for 15 years at 3.5%, then $650/month for another 15 years at 6.5%, will yield approximately $21,628.59 after three years.

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Answer:don’t worry u not dum and also im sorry that’s not a function.

Step-by-step explanation:

Give me brainliest!

Answer:

Shannon run 1.5 km more on Friday than on Saturday.

Step-by-step explanation:

From the given table

i.e.

Friday run - Saturday run =  2 - 0.5

                                          = 1.5 km

Thus, Shannon run 1.5 km more on Friday than on Saturday.

By solving a simple product we will see that 12% of 45 is equal to 5.4

If we have a number N and we want to take a percentage P of that number, the operation we need to do is:

new number = N*(P/100%)

Here the original number is N = 45 and the percentage is 12%, then we need to solve:

new number = 45*(12%/100%) = 5.4

Then the 12% of 45 is equal to 5.4

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Answer:$51.08

Step-by-step explanation:

Angle-Angle-Side (AAS) Theorem has two sides and a non-included angle.

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Answer:

C (-1/2, -4 1/2)

Step-by-step explanation:

x = -2/(2·2)

x = -2/4 or -1/2

y = 2(-1/2)² + 2(-1/2) - 4

y = 2(1/4) - 1 - 4

y =  1/2 - 1 - 4 or -1/2 - 4 which equals -4 1/2