when they go swimming in their favorite water hole, jeb and dixie like to swing over the water on an old tire attached to a tree branch with a 3.0-m nylon rope. if the diameter of the rope is 2.00 cm, by how much does the rope stretch when 60.0- kg dixie swings from it? (ynylon

Therefore, the answer is: a. 1, c. 4. are the electrons contained in the main energy levels

When n = 1, there can only be two electrons in the first energy level.

When n = 2, there can be a maximum of eight electrons in the second energy level.

When n = 3, there can be a maximum of 18 electrons in the third energy level.

When n = 4, there can be a maximum of 32 electrons in the fourth energy level.

a. 1: Since n = 1, there can only be two electrons in the first energy level.

b. 3: Since n = 2, there can be a maximum of eight electrons in the second energy level, but it is impossible to have only three electrons in the second energy level.

c. 4: Since n = 3, there can be a maximum of 18 electrons in the third energy level. Therefore, it is possible to have four electrons in the third energy level.

d. 6: Since n = 3, there can be a maximum of 18 electrons in the third energy level, but it is impossible to have only six electrons in the third energy level.

e. 7: Since n = 4, there can be a maximum of 32 electrons in the fourth energy level, but it is impossible to have only seven electrons in the fourth energy level.

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In stating his paradox, olber expected the night sky to be bright and not dark as we see it because he thought that every line of sight should intersect a star in an infinite universe.

A paradox is a situation when a statement seems or opposed to common sense but is true.

Night sky must be bright and not dark is said by Olber.  There are randomly scattered stars in the universe. He assumed that each and every light ray must cross the star to brighten it more and sky will look brighter at night.

His paradox is just a common sense but perhaps true.

Thus, in stating his paradox, olber expected the night sky to be bright and not dark as we see it because he thought that every line of sight should intersect a star in an infinite universe.

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Answer:

A and B

Explanation:

They contain Chlorophyll

They are relatively tall

Answer:

I believe it is D

Explanation:

Answer:

inhibitor

Explanation:

Inhibitors slow down chemical reactions. Inhibitors slow down or stop the activity of an enzyme.

Suppose 10¹⁸ electrons start at rest and move along a wire brough a + 12 V potential difference.

(a) The change in electrical potential energy of all the electrons is -1.92 x 10⁻¹ Joules.

(b) The final speed of the electrons is 0.10 m/s is 4.55 x 10⁻³³ Joules.

(a) To calculate the change in electrical potential energy of all the electrons, we can use the formula:

ΔPE = q * ΔV

where ΔPE is the change in electrical potential energy, q is the charge, and ΔV is the change in potential difference.

Given:

Number of electrons (n) = 10¹⁸

Charge of one electron (q) = -1.6 x 10⁻¹⁹ C

Change in potential difference (ΔV) = +12 V (positive because the electrons move from a higher potential to a lower potential)

Substituting the values into the formula:

ΔPE = (10¹⁸) * (-1.6 x 10⁻¹⁹ C) * (+12 V)

= -1.92 x 10⁻¹ J

The change in electrical potential energy of all the electrons is approximately -1.92 x 10⁻¹ Joules.

(b) The final speed of the electrons is given as 0.10 m/s. To calculate the change in kinetic energy, we need to know the mass of the electrons. The mass of one electron is approximately 9.1 x 10⁻³¹ kg.

Change in kinetic energy (ΔKE) = (1/2) * m * (v²)

where m is the mass of one electron and v is the final speed of the electrons.

Substituting the values into the formula:

ΔKE = (1/2) * (9.1 x 10⁻³¹ kg) * (0.10 m/s)²

= 4.55 x 10⁻³³ J

The change in kinetic energy of all the electrons is approximately 4.55 x 10⁻³³ Joules.

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(a) The change in electrical potential energy of all the electrons is 1.92 x 10^-18 J.

(b) The final speed of the electrons is 0.10 m/s.

(a) To calculate the change in electrical potential energy of all the electrons, we use the formula ΔPE = qΔV, where q is the charge on an electron and ΔV is the change in potential difference.

Given:

q = 1.6 x 10^-19 C (charge on an electron)

ΔV = 12 V (change in potential difference)

Using the formula, we have:

ΔPE = qΔV

ΔPE = (1.6 x 10^-19 C) x (12 V)

ΔPE = 1.92 x 10^-18 J

Therefore, the change in electrical potential energy of all the electrons is 1.92 x 10^-18 J.

(b) The final speed of the electrons is given as 0.10 m/s.

The question does not explicitly ask for the current flowing through the wire, but it can be determined using the formula I = neAv, where n is the number of electrons, e is the charge on one electron, and A is the area of the cross-section of the wire. However, the area of the wire is not provided, so we cannot calculate the current accurately.

If we assume the area of the cross-section of the wire to be 1 mm^2 (0.000001 m^2), then we can calculate the current as follows:

Given:

n = 1.01 x 10^18 (number of electrons)

e = 1.6 x 10^-19 C (charge on one electron)

A = 0.000001 m^2 (assumed area of the cross-section of the wire)

Using the formula, we have:

I = neAv

I = (1.01 x 10^18) x (1.6 x 10^-19 C) x (0.000001 m^2)

I = 1.6224 A

Therefore, the current flowing through the wire is 1.6224 A.

Please note that the resistance of the wire is not provided in the question, so we cannot calculate it accurately without that information.

Additionally, the time taken by the electrons to travel through the wire is not explicitly asked in the question, but if we assume the length of the wire to be 1 m and the final velocity of the electrons to be 0.10 m/s, we can calculate the time as follows:

Given:

l = 1 m (length of the wire)

v = 0.10 m/s (final velocity of the electrons)

Using the formula, we have:

t = l / v

t = 1 m / 0.10 m/s

t = 10 s

Therefore, the time taken by the electrons to travel through the wire is 10 seconds.

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Answer:

B.rate of convection

Explanation:

Answer:

Density is the only thing affecting whether something floats or sinks . If an object has a higher density than the fluid it is in ( fluid can mean liquid or gas ) , it will sink . If it has a lower density , it will float . Density is determined by an object's mass and volume .

Hope this helps

Answer:

a)   A´= A  

b)   θ₁´ = 29º,  θ₂´ = - 169º ,  θ₃´ = -49º

Explanation:

In this exercise you are asked to give the magnitudes and angles of the vectors from another system of

reference

a) The magnitudes

The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector

          A = \(x_{f}\)- x₀

if the vectors are measured in another reference frame

         x_{f}´ = xx_{f}- U

         x₀´ = x₀ -U

where U is the distance between the two reference frames

         A´ = x_{f}´ - x₀´

we substitute

         A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀

         A´ = A

 it does not change

b) Angles

The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis

     θ₁ = 29º

     does not change

     θ₁´ = 29º

    θ₂ = 191º

   we measure clockwise

     θ₂´ = θ₂ - 360

     θ₂´ = 191 - 360

     θ₂´ = - 169º

     θ₃ =311º

    we measure clockwise

     θ₃´ = 311 -360

     θ₃´ = -49º

Answer:

6amp

Explanation:

From Ohm's Law

V = IR

Where V = 12volts, R = 2ohms

12volts = I × 2ohms

I = 12/2

I = 6amp

The current flowing through the light bulb is 6amp

The energy needed to heat the water and the copper tank to 55°C is 25,083,080 J.

Q = mCΔT

m = 150 kg (mass of water)

C = 4.18 J/g°C (specific heat capacity of water)

ΔT = 55°C - 15°C = 40°C (change in temperature)

Using the formula, we get:

\(Q_{water}\) = mCΔT

\(Q_{water}\) = (150 kg) x (4.18 J/g°C) x (40°C)

\(Q_{water}\) = 25,080,000 J

m = 20 kg (mass of tank)

C = 0.385 J/g°C (specific heat capacity of copper)

ΔT = 55°C - 15°C = 40°C (change in temperature)

Using the formula, we get:

\(Q_{tank}\) = mCΔT

\(Q_{tank}\) = (20 kg) x (0.385 J/g°C) x (40°C)

\(Q_{tank}\)= 3080 J

Finally, we can add the two energies together to get the total energy needed:

\(Q_{total}\) = \(Q_{water}\) \(+\) \(Q_{tank}\)

\(Q_{total}\) \(= 25,080,000 J + 3080 J\)

\(Q_{total}\) \(= 25,083,080 J\)

Energy is a fundamental concept that refers to the ability of a physical system to do work or cause a change. It is a scalar quantity that is measured in units of joules (J) in the International System of Units (SI). According to the law of conservation of energy, energy cannot be created or destroyed, but it can be transformed from one form to another. This means that the total amount of energy in a closed system remains constant.

Energy is a crucial concept in many areas of physics, including mechanics, thermodynamics, and electromagnetism. Understanding energy is essential for understanding how the physical world works, and it has numerous applications in technology and everyday life, from powering our homes and vehicles to the production of food and the functioning of our bodies.

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Answer:

It indicates that a force has 2 directions at the point at which they cross

Answer:

A. A field pointing in two directions

Problem 2

Answer: Choice D only

Explanation:

Let's go through the list of possible answers

Ionic bonds include the transfer of electrons between atoms, the formation of ions with opposite charges, the attraction between positively and negatively charged ions, and the formation of a lattice structure in ionic compounds

Ionic bonds are a type of chemical bond that involves the transfer of electrons from one atom to another, resulting in the formation of ions with opposite charges. These ions are then attracted to each other due to their opposite charges, forming an ionic bond. Ionic compounds typically have a lattice structure, in which the ions are arranged in a repeating pattern. Example: NaCl, MgO, CaF2, Li2O, AlF3,

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For the 100 litre open-topped tank:

a) To find an equation that gives the amount of salt remaining in the tank after t seconds, consider the rate at which salt enters and leaves the tank.

The initial amount of salt in the tank is 100 L × 80 g/L = 8000 g.

Rate of salt entering the tank:

The fresh water entering the tank at 10 L/sec has a salt concentration of 0 g/L. Therefore, the rate of salt entering the tank is 0 g/sec.

Rate of salt leaving the tank:

The excess water running out over the top at 10 L/sec carries away salt with a concentration of 80 g/L. Therefore, the rate of salt leaving the tank is 80 g/sec.

Rate of change of salt in the tank:

The rate of change of salt in the tank is given by the difference between the rate of salt entering and leaving the tank:

dS/dt = 0 - 80 = -80 g/sec

b) To find how much salt is left in the tank after one minute (60 seconds), integrate the rate equation from t = 0 to t = 60:

∫dS = ∫(-80) dt

ΔS = -80t + C

Since the initial amount of salt is 8000 g (at t = 0), solve for the constant C:

8000 = -80(0) + C

C = 8000

Therefore, the equation for the amount of salt remaining in the tank after t seconds is:

S(t) = -80t + 8000

Substituting t = 60 seconds:

S(60) = -80(60) + 8000

S(60) = 3200 g

c) After 100 L of brine has flowed out over the top of the tank, the remaining volume of salt water in the tank is 100 L (initial volume) - 100 L (flowed out) = 0 L. Therefore, there is no salt left in the tank.

d) To find when half of the salt in the tank has flowed out over the top,  set S(t) = 0.5 × initial amount of salt:

0.5 × 8000 = -80t + 8000

-80t = 8000 - 4000

-80t = 4000

t = -4000 / -80

t = 50 seconds

Therefore, half of the salt in the tank will have flowed out over the top after 50 seconds.

e) To find when the tank contains salt water at a concentration of 5 g/L, set S(t) = V(t) × 5, where V(t) is the volume of water in the tank at time t:

V(t) × 5 = -80t + 8000

V(t) = (-80t + 8000) / 5

V(t) = 100 L (initial volume) - 10 L/sec × t (rate of water leaving the tank):

100 - 10t = (-80t + 8000) / 5

Multiplying both sides by 5:

500 - 50t = -80t + 8000

30t = 7500

t = 250 seconds

Therefore, the tank will contain salt water at a concentration of 5 g/L after 250 seconds.

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Answer:

Option A

Explanation:

An electric force is a charged reaction that causes an attraction or a repulsion between two charged objects. In this case rubbing a glass rod with wool charges up the rod which then turns it into magnetic, which attracts the paper scraps from the ground to the rod where it sticks. The best answer is option A or "Pam rubs a glass rod with wool, then moves the rod over a pile of small paper scraps. The scraps leap into the air and stick to the rod."

Hope this helps.

Answer:

KE = 250 kg/m/s

Explanation:

use the formula: KE = 1/2 m (v^2)

KE = 1/2 (5) (10^2)

KE = (2.5) (100)

KE = 250 kg/m/s

Answer:

1 joule per second.

Explanation:

The watt (symbol: W) is a unit of power or radiant flux. In the International System of Units (SI), it is defined as a derived unit of (in SI base units) 1 kg⋅m2⋅s−3 or, equivalently, 1 joule per second.

An industrial load consumes 100 kw at 0.8 pf lagging. if an ammeter in the transmission line indicates that the load current is 200 a rms, the load voltage is 625 volts.

We are provided with information about an industrial load, specifically its power consumption, power factor, and current. Our goal is to determine the load voltage. First, we calculate the apparent power (S) using the formula S = P / PF, where P is the power and PF is the power factor. The power is given as 100 kW (kilowatts), and the power factor is stated as 0.8 (lagging). Dividing 100 kW by 0.8 gives us an apparent power of 125 kVA (kilovolt-amperes). Next, we utilize the relationship between apparent power, voltage, and current. The apparent power (S) is given by the formula S = V * I, where V represents voltage and I represents current. Rearranging the formula, we find V = S / I.

Plugging in the values we have, we substitute 125 kVA for S and 200 A (amperes) for I. Dividing 125 kVA by 200 A, we calculate the load voltage to be 625 V (volts). Therefore, based on the given power consumption of 100 kW at a power factor of 0.8 lagging and an ammeter reading of 200 A rms, we conclude that the load voltage is 625 volts.

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Violet light (410 nm) and red light (685 nm) pass through a diffraction grating with d=3. 33x10^-6.  the angular separation between the violet light and red light for m = 2 is approximately 0.276 radians.

The angular separation between two wavelengths passing through a diffraction grating can be determined using the formula:

Sin(θ) = mλ / d

Where θ is the angle of diffraction, m is the order of the diffraction pattern, λ is the wavelength of light, and d is the spacing between the lines on the grating.

In this case, we have two wavelengths, violet light with a wavelength of 410 nm (4.1x10^-7 m) and red light with a wavelength of 685 nm (6.85x10^-7 m). We are interested in the angular separation for m = 2.

For violet light:

Sin(θ_violet) = (2 * 4.1x10^-7 m) / (3.33x10^-6 m)

Sin(θ_violet) ≈ 0.245

For red light:

Sin(θ_red) = (2 * 6.85x10^-7 m) / (3.33x10^-6 m)

Sin(θ_red) ≈ 0.411

The angular separation between the two wavelengths can be calculated as the difference between their respective angles of diffraction:

Θ_separation = sin^(-1)(sin(θ_red) – sin(θ_violet))

Θ_separation ≈ sin^(-1)(0.411 – 0.245)

Θ_separation ≈ 0.276 radians

Therefore, the angular separation between the violet light and red light for m = 2 is approximately 0.276 radians.

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A) 42.7% is the energy efficiency of the device.

Energy efficiency is a measure of how much energy is wasted. There are several ways to save energy, especially thermal energy, and the rate at which it is lost needs to be slowed down. Energy efficiency is defined as requiring less energy to complete an activity or reach a goal. Homes, structures, and production facilities that use less energy to create their products also consume less energy to heat, cool, and run gadgets and appliances.

Energy efficiency is one of the most straightforward and cost-effective ways to halt global warming, reduce consumer energy costs, and increase the competitiveness of American businesses. Energy efficiency is also a key component in the decarbonization process to attain net-zero emissions of carbon dioxide.

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Answer:

The scale would exert a force of approximately 519.4 Newtons on the 53 kg person standing on it while the elevator is in motion at a constant speed of 2.0 m/s.

Explanation:

The gravitational force acting on the person can be calculated using the formula: force = mass * acceleration due to gravity.

Given that the mass of the person is 53 kg, and the acceleration due to gravity on Earth is approximately 9.8 m/s², we can calculate the force:

force = 53 kg * 9.8 m/s² = 519.4 N.

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The carbon-14 can be used to date the hammer suspected to be used in 3400 BC.

Half life is the time taken for a radioactive element to decay to half of its original value.

Thus, we can conclude that the carbon-14 can be used to date the hammer suspected to be used in 3400 BC.

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In an IR spectrum, Alkyl C-H Stretch 2950 - 2850 cm-1 of the circled c-h bonds exhibits a stretching absorption at the highest wave number.

The IR spectrum is a plot percentage of transmittance (or absorbance) of the radiation through the molecule versus wave number of the radiation. An IR diapason is basically a graph colluded with the infrared light absorbed on the Y- axis against frequency or wavelength on the X-axis. An illustration pressing the different regions that light can be classified into is given below.

IR Spectroscopy detects frequentness of infrared light that are absorbed by a patch. motes tend to absorb these specific frequentness of light since they correspond to the frequency of the vibration of bonds in the patch.

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Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

force = 20 N

distance = 6 m

work done = 20 × 6 = 120

We have the final answer as

Hope this helps you

Answer:

Explanation:

As a seismologist studying earthquakes in a particular region, you might expect to find certain features of the earth's crust in that region that are indicative of tectonic activity. Some examples of these features include:

Fault lines: These are fractures in the earth's crust where two tectonic plates have moved relative to each other, often resulting in earthquakes when the movement is sudden and violent.

Folded mountain ranges: When tectonic plates collide, the resulting pressure can cause the earth's crust to fold and form mountain ranges.

Volcanoes: Many earthquakes occur in regions with volcanic activity, as the movement of magma beneath the earth's surface can cause the ground to shake.

Plate boundaries: The boundary between two tectonic plates is often a zone of high seismic activity, as the plates grind against each other and cause earthquakes.

Seismic gaps: Some areas along a fault line may have experienced few or no earthquakes in recent history, and are therefore considered "seismic gaps." These areas may be more prone to earthquakes in the future as the pressure builds up.

By studying these and other features of the earth's crust, you can gain a better understanding of the underlying tectonic processes that contribute to earthquakes in the region.

Answer:

c. earth's shadow covering the moon

Explanation:

One thing that produces an eclipse is when Earth's shadow covers the moon and the moon and Sun's gravitational pull on each other. Option C is correct.

When the moon passes in front of Earth and the sun, it creates a solar eclipse and casts a shadow across the globe.

A solar eclipse can occur only during the new moon phase when the moon travels squarely between the sun and Earth and casts shadows on its surface.

Earth’s shadow covers the moon the gravity from the moon and Sun describes one event that causes an eclipse.

Hence option C is correct.

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A 200 watt to decibels is option (b) 53 dBm.

To convert 200 watts to decibels referenced to 1 milliwatt, we can use the formula:

dB = 10 * log10(P/Pref)

where P is the power being measured (in this case, 200 watts) and Pref is the reference power (1 milliwatt).

First, we need to convert 200 watts to milliwatts. Since 1 watt is equal to 1000 milliwatts, we have:

200 watts = 200 * 1000 = 200,000 milliwatts.

Now we can calculate the decibel value:

dB = 10 * log10(200,000/1)

dB = 10 * log10(200,000)

Using a calculator, the result is approximately 53 dB.

The decibel (dB) is a logarithmic unit used to express the ratio of two power levels. In this case, we are comparing the power of 200 watts to the reference power of 1 milliwatt. By converting the power to decibels, we can more easily express and compare power levels on a logarithmic scale. In telecommunications and electronics, dBm is often used, which is a decibel measurement referenced to 1 milliwatt. In this context, 53 dBm indicates that the power of 200 watts is 53 decibels higher than 1 milliwatt.

Therefore, the answer is option (b) 53 dBm.

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