When the outliers are removed, how does the mean change? dot plot with 1 on 18, 2 on 38, 1 on 40, 3 on 44, 1 on 46, 1 on 48 The mean decreases by 2. 75. The mean increases by 2. 75. The mean increases by 3. 25. There are no outliers.

The future receipt is discounted at an interest rate of 12% and its present value is $210,018 in 7 years is the $520,000 received.

The formula for calculating present value is:

PV = FV / (1 + r)^n

Where:

PV = Present Value

FV = Future Value

r = Interest Rate

n = Number of years

Rearranging the formula to solve for 'n' (number of years):

n = log(FV / PV) / log(1 + r)

Plugging in the given values:

PV = $210,018

FV = $520,000

r = 12% or 0.12

n = log(520,000 / 210,018) / log(1 + 0.12)

Using a calculator, we can find the approximate value of 'n':

n ≈ 7.2 years

Therefore, in approximately 7.2 years, the $520,000 will be received. Rounding to the nearest whole number, the answer is (c) 7 years.

learn more about year from given link

https://brainly.com/question/10196617

#SPJ11

Respuesta:

720 cm³

Explicación paso a paso:

El volumen de un prisma rectangular viene dado por:

V = largo * ancho * alto

Dimensión de la caja de arte = 12 por 20 por 5

Dimensión del borrador = largo * ancho * alto

Volumen del borrador = 2 por 4 por 0,5

Dimensión del estuche de arte que no contiene borrador:

(12 por 20 por 5) - (2 por 4 por 0,5)

(10 por 16 por 4,5)

Volumen de la caja que no contiene borrador:

10 * 16 * 4,5 = 720 cm³

The identified parameters are:

ta = 6 minutes

tθ = 11 minutes

∂a = 4 minutes

∂θ = 20 minutes

ra = 1/6 minutes^(-1)

rθ = 1/11 minutes^(-1)

ta: Mean time between calls to the center

tθ: Effective response time

∂a: Standard deviation of the time between calls to the center

∂θ: Standard deviation of the effective response time

ra: Rate of calls to the center (inverse of ta, i.e., ra = 1/ta)

rθ: Rate of effective response (inverse of tθ, i.e., rθ = 1/tθ)

Given information:

Mean time between calls to the center (ta) = 6 minutes

Standard deviation of time between calls (∂a) = 4 minutes

Effective response time (tθ) = 11 minutes

Standard deviation of effective response time (∂θ) = 20 minutes

Using this information, we can determine the values of the parameters:

ta = 6 minutes

tθ = 11 minutes

∂a = 4 minutes

∂θ = 20 minutes

ra = 1/ta = 1/6 minutes^(-1)

rθ = 1/tθ = 1/11 minutes^(-1)

So, the identified parameters are:

ta = 6 minutes

tθ = 11 minutes

∂a = 4 minutes

∂θ = 20 minutes

ra = 1/6 minutes^(-1)

rθ = 1/11 minutes^(-1)

Learn more about Standard Deviation here:

https://brainly.in/question/50665860

#SPJ11

Answer:

23

Step-by-step explanation:

Every triangle adds up to 180 so we would add all of these expressions up and set them equal to 180. 13x-11+8x-9+30x-4=180. Simplify to 51x-24=180. Opposite operation with negative 24. 51x=204. Yet, again do the opposite operation to isolate x, 204/54, which leaves the answer of 4. But that is not the question. It is asking for angle W, well since we know what x is, we are able to plug in x to the expression used in angle W, 8(4)-9 which brings tha answer of 23 :)

The minimized SOP expression for the given logic function is ABCDE + ABCDE.

To find the minimized Sum of Products (SOP) expression using a five-variable Karnaugh map, follow these steps:

Step 1: Create the Karnaugh map with five variables (A, B, C, D, and E) and label the rows and columns with the corresponding binary values.

```

    C D

A B  00 01 11 10

0 0 |  -  -  -  -

 1 |  -  -  -  -

1 0 |  -  -  -  -

 1 |  -  -  -  -

```

Step 2: Fill in the map with '1' values for the minterms given in the logic function, and '0' for the remaining cells.

```

    C D

A B  00 01 11 10

0 0 |  0  0  0  0

 1 |  1  1  0  1

1 0 |  0  1  1  0

 1 |  0  0  0  1

```

Step 3: Group adjacent '1' cells in powers of 2 (1, 2, 4, 8, etc.).

```

    C D

A B  00 01 11 10

0 0 |  0  0  0  0

 1 |  1  1  0  1

1 0 |  0  1  1  0

 1 |  0  0  0  1

```

Step 4: Identify the largest possible groups and mark them. In this case, we have two groups: one with 8 cells and one with 4 cells.

```

    C D

A B  00 01 11 10

0 0 |  0  0  0  0

 1 |  1  1  0  1

1 0 |  0  1  1  0

 1 |  0  0  0  1

```

Step 5: Determine the simplified SOP expression by writing down the product terms corresponding to the marked groups.

For the group of 8 cells: ABCDE

For the group of 4 cells: ABCDE

Step 6: Combine the product terms to obtain the minimized SOP expression.

F(A,B,C,D,E) = ABCDE + ABCDE

So, the minimized SOP expression for the given logic function is ABCDE+ ABCDE.

Learn more about Sum of Products: https://brainly.com/question/30386797

#SPJ11

The minimized SOP expression for the given logic function is ABCDE + ABCDE.

We start by creating the Karnaugh map with five variables (A, B, C, D, and E) and label the rows and columns with the corresponding binary values.

A B   C D

00 01 11 10

0 0 |  -  -  -  -

1 |  -  -  -  -

1 0 |  -  -  -  -

1 |  -  -  -  -

We then fill in the map with '1' values for the minterms given in the logic function, and '0' for the remaining cells.

  A B  C D

00 01 11 10

 0 0 |  0  0  0  0

1 |  1  1  0  1

1 0 |  0  1  1  0

1 |  0  0  0  1

we then group adjacent '1' cells in powers of 2:

A B    C D

00 01 11 10

0 0 |  0  0  0  0

1 |  1  1  0  1

1 0 |  0  1  1  0

1 |  0  0  0  1

For the group of 8 cells: ABCDE

For the group of 4 cells: ABCDE

F(A,B,C,D,E) = ABCDE + ABCDE

In conclusion, the minimized SOP expression for the logic function is ABCDE+ ABCDE.

Learn more about Sum of Products at:

brainly.com/question/30386797

#SPJ4

64.77% of a given amount remains after 900 years.

To determine the percentage of radioactive radium remaining after 900 years, we'll use the half-life formula:

Final Amount = Initial Amount * \(1/2^{(time elapsed / half-life)}\)

In this case, the half-life is 1599 years and the time elapsed is 900 years. We want to find the percentage remaining, so let's assume the initial amount is 100%.

Final Amount = 100 * \((1/2)^{(900 / 1599)}\)

Now, we'll calculate the exponent:

Exponent = 900 / 1599 ≈ 0.5635

Then, we'll compute the final amount:

Final Amount ≈ 100 * \((1/2)^{0.5635}\) ≈ 100 * 0.6477 ≈ 64.77%

After 900 years, approximately 64.77% of the initial radioactive radium remains. This percentage was found using the half-life formula, which accounts for the exponential decay of radioactive substances over time.

The formula shows how the remaining amount of a substance decreases as time progresses based on its half-life, which is the time it takes for half of the substance to decay. In this scenario, radium's half-life of 1599 years and the 900-year time frame were used to determine that roughly 64.77% of the initial radium remains.

Know more about Radioactive radium here:

https://brainly.com/question/31436084

#SPJ11

Answer:

2x-1/5=9

We move all terms to the left:

2x-1/5-(9)=0

determiningTheFunctionDomain

2x-9-1/5=0

We multiply all the terms by the denominator

2x*5-1-9*5=0

We add all the numbers together, and all the variables

2x*5-46=0

Wy multiply elements

10x-46=0

We move all terms containing x to the left, all other terms to the right

10x=46

x=46/10

Answer:

102

Step-by-step explanation:

100 plus 2 equals 102

Hopefully this helps you :)

pls mark brainlest ;)

(b+1)/2b

quotient = divided by

we're dividing a number that is 1 more than b (b + 1), with a number twice as large as b (2b).

Answer:

The cube root for 216 is 6

Step-by-step explanation:

Answer:

the cube root of 216 is 6

Step-by-step explanation:

False. In a Two-Way 2 x 2 Between Subjects ANOVA, there are typically two independent variables, each with two levels, resulting in a total of four groups.

A Two-Way 2 x 2 Between Subjects ANOVA involves the analysis of variance with two independent variables, each having two levels. The independent variables can be thought of as factors, and their combinations create different groups for comparison.

In this design, there are two factors, each with two levels. When you multiply the number of levels for each factor (2 x 2), you get four possible combinations or groups. Each group represents a specific combination of the two levels of the independent variables.

For example, if the first independent variable is "A" with levels A1 and A2, and the second independent variable is "B" with levels B1 and B2, the four groups in the ANOVA would be: A1B1, A1B2, A2B1, and A2B2.

Learn more about ANOVA

brainly.com/question/29537928

#SPJ11

The percentage of Measurements that are 124.4 or higher is approximately 0.99%.

In order to determine the percentage of measurements that are 124.4 or higher in a population of measurements that is approximately normal with a mean of 95 and a standard deviation of 15, we need to use the z-score formula.

The z-score formula is used to standardize a distribution so that it can be compared to a normal distribution with a mean of 0 and a standard deviation of 1.

The formula for calculating the z-score is: z = (x - μ) / σWhere:x is the measurement we want to standardize.μ is the population mean.σ is the population standard deviation.

The first step is to calculate the z-score for the measurement of 124.4:z = (124.4 - 95) / 15z = 2.2933The second step is to find the percentage of measurements that are 124.4 or higher using a standard normal distribution table. We look up the area to the right of the z-score of 2.2933 in the table.

The closest value in the table is 0.9901, which corresponds to a z-score of 2.33. We know that the area to the left of a z-score of 2.33 is 0.9901, so the area to the right of a z-score of 2.33 is:1 - 0.9901 = 0.0099

This means that approximately 0.99% of the measurements are 124.4 or higher.

Therefore, the percentage of measurements that are 124.4 or higher is approximately 0.99%.

For more quesions on Measurements .

https://brainly.com/question/27233632

#SPJ8

The motion from point A to point D indicated in the figure can be analyzed to find the speed and velocity as follows;

4. 12 kilometers

5. The displacement is zero

6. The average speed is 3 km/hour

7. The velocity is 6 km/hour

8. The average speed includes times at which the individual is at rest

9. An horizontal line means constant speed

Velocity is the ratio of displacement to the duration of motion, while speed is the ratio of the distance to the duration of the motion. Velocity is a vector quantity, while speed is a scaler quantity.

4. The distance traveled = AB + BC + CD

Therefore;

Distance travelled = 3 km + 4 km + (3 km + 2 km) = 12 km

5. The displacement while at the same location is zero, therefore, the displacement when at the friends house is zero displacement.

6. The location of home = A

The location of the final destination = C

The distance from A to C = 12 km

The time it takes from point A to C, t = 5:00 - 1:00 = 4

It takes 4 hours to travel from A to C

7. The displacement from A to B = 3 km

The duration of the journey from A to B = 0.5 hours

Velocity = Displacement/Time

8. The reason why the speed and the velocity are different is due to the time spent at the stops along the way to point D are added to the time used for calculating the speed.

9. The horizontal line on a speed time graph, where speed is on the vertical axis and time is measured on the horizontal axis, indicates that the object is moving with a constant speed.

Learn more on speed time graph here: https://brainly.com/question/14346950

#SPJ1

The Python script generates 1000 random numbers from a normal distribution, counts the numbers in different categories, saves them in variables A, B, and C, and creates corresponding text files.

Here's a Python script that fulfills the requirements:

import numpy as np

# Step 1: Generate 1000 random numbers with a normal distribution

random_numbers = np.random.randn(1000)

# Step 2: Count the numbers in each category

count_A = np.sum(random_numbers < -0.25)

count_B = np.sum((random_numbers >= -0.25) & (random_numbers <= 0.25))

count_C = np.sum(random_numbers > 0.25)

# Step 3: Save numbers in variables A, B, and C

A = random_numbers[random_numbers < -0.25]

B = random_numbers[(random_numbers >= -0.25) & (random_numbers <= 0.25)]

C = random_numbers[random_numbers > 0.25]

# Step 4: Generate text files for A, B, and C

np.savetxt('numbers_A.txt', A)

np.savetxt('numbers_B.txt', B)

np.savetxt('numbers_C.txt', C)

# Display the counts

print("Count of numbers less than -0.25:", count_A)

print("Count of numbers between -0.25 and 0.25:", count_B)

print("Count of numbers larger than 0.25:", count_C)

Make sure to have NumPy library installed in your Python environment to run this script successfully. After executing the script, it will generate three text files named "numbers_A.txt", "numbers_B.txt", and "numbers_C.txt" containing the numbers falling into each respective category. The script will also display the count of numbers in each category.

To learn more about Python visit : https://brainly.com/question/26497128

#SPJ11

Answer:

Step-by-step explanation: potatoes

Answer:

The ratio of the circumference of any circle to the diameter of that circle.

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

3 equals 10% of what? ​

10% = 0.1

3 = 0.1x

divide both sides by 0.1

3/0.1 = 0.1x/0.1

x = 30

Answer:

x =10

Step-by-step explanation:

10/100 = 3/x

cross multiply and you get 300 = 10x

divide by 10 on both sides 10x/10 get canceled out you want to get the varaible on one side of the equation then divide 300/10 and you get 30 so your final answer is x=30  hope this helped you sorry if incorrect

Answer:

x = 150 degree

x = 210 degree

Step-by-step explanation:

cos(x) = -cos(30) = -√3/2

x = 150 degree

x = 210 degree

Answer:

θ = 150°, 210°

Step-by-step explanation:

Given:

\(\cos \theta=- \cos 30^{\circ}, \quad 0 < \theta < 360^{\circ}\)

We know from trigonometric values of special angles that :

\(\cos 30^{\circ}=\dfrac{\sqrt{3}}{2}\)

and that 30° is in Quadrant I.

Therefore:

\(-\cos 30^{\circ}=-\dfrac{\sqrt{3}}{2}\)

\(\begin{array} {|c|c|}\cline{1-2} \sf Quadrant & \sf Reference \: Angle\\\cline{1-2} \rm I & \theta\\\cline{1-2} \rm II & 180^{\circ}-\theta \\\cline{1-2} \rm III & \theta - 180^{\circ} \\\cline{1-2} \rm IV & 360^{\circ} - \theta \\\cline{1-2} \end{array}\)

Cosine is negative In Quadrants II and III.  Therefore, use the above table to find the reference angles of 30° that make the cosine of the angle negative:

\(\cos (180-30)^{\circ}=-\dfrac{\sqrt{3}}{2} \implies \cos 150^{\circ}=-\dfrac{\sqrt{3}}{2}\)

and:

\(\cos (30-180)^{\circ}=-\dfrac{\sqrt{3}}{2} \implies \cos (-150^{\circ})=-\dfrac{\sqrt{3}}{2}\)

Therefore, θ = 150° ± 360°n, -150° ± 360°n.

So the measure of θ in the given interval is 150° and 210°.

a) the dimension of its column space is also 2. b) the rank of A is 2. c) the nullity of matrix A is 1. d) the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

(a) The dimension of the row space of a matrix is equal to the dimension of its column space. So, if the dimension of the row space of matrix A is 2, then the dimension of its column space is also 2.

(b) The rank of a matrix is defined as the maximum number of linearly independent rows or columns in the matrix. Since the dimension of the row space of matrix A is 2, the rank of A is also 2.

(c) The nullity of a matrix is defined as the dimension of the null space, which is the set of all solutions to the homogeneous equation Ax = 0. In this case, the matrix A is a 3 x 3 matrix, so the nullity can be calculated using the formula:

nullity = number of columns - rank

nullity = 3 - 2 = 1

Therefore, the nullity of matrix A is 1.

(d) The dimension of the solution space of the homogeneous system Ax = 0 is equal to the nullity of the matrix A. In this case, we have already determined that the nullity of matrix A is 1. Therefore, the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

Know more about matrix here:

brainly.com/question/24079385

#SPJ4

The standard deviation of returns is 0.0665 when a person is holding stock and there are three possible outcomes.

To calculate the expected return, we multiply the probability of each state by its corresponding return and sum them up:

Expected return = (20% * 18%) + (55% * 9%) + (25% * -5%)

Expected return = 0.20 * 0.18 + 0.55 * 0.09 + 0.25 * (-0.05)

Expected return = 0.036 + 0.0495 - 0.0125

Expected return = 0.073

The expected return is 7.30%.

To calculate the standard deviation of returns, we need to find the variance first. The variance is calculated as the weighted sum of squared deviations from the expected return:

Variance = (20% * (18% - 7.30%)^2) + (55% * (9% - 7.30%)^2) + (25% * (-5% - 7.30%)^2)

Variance = 0.20 * (0.1077)^2 + 0.55 * (0.0177)^2 + 0.25 * (-0.123)^2

Variance = 0.00232 + 0.000173 + 0.001903

Variance = 0.004423

The standard deviation is the square root of the variance:

Standard deviation = √(0.004423)

Standard deviation = 0.0665

Therefore, the value obtained is 0.0665.

To know more about standard deviation refer here:

https://brainly.com/question/29115611#

#SPJ11

The total electric force on the 7.00−μC charge is 0.872 N at an angle of 330°.

The force exerted on the 7.00−μC charge by the 2.00−μC charge is

F₁​ ​= \(k_{e}\)q₁q₂​​/r₂ r^

= [(8.99×10⁹N.m²/C²)(7.00×10^−6C)(2.00×10^−6C) ×(cos60°i^+sin60°j^​)]/ (0.500m)²

F₁ ​= (0.252i^+0.436j^​)N

Similarly, the force on the 7.00μC charge by the −4.00−μC charge is

F₂​ ​= \(k_{e}\)q₁​q₃/​r² ​​r^

= [(8.99×10⁹N.m²/C²)(7.00×10^−6C)(−4.00×10^−6C)​×(cos60°i^−sin60°j^​)]/(0.500m)²

F₂​ ​=(0.503i^−0.872j^​)N

Hence, the total force on the charge 7.00−μC  is

F = F₁​​+F₂​

​=(0.755i^−0.436j^​)N

We can also note the total force as:

F = (0.755N)i^−(0.436N)j^​ = 0.872N

To know more about electric force, here

https://brainly.com/question/29141236

#SPJ4

--This question is incomplete; the complete question is

"Three charged particles are located at the corners of an equilateral triangle, as shown in Figure. Calculate the total electric force on the 7.00−μC charge."--

Any constructed vertical line that can only ever cross a graph once is considered to be a function. It is not a function if any points on the graph allow a vertical line to pass through them more than once.

To find the average rate of change per year for each loan over a certain interval, we can use the formula:

average rate of change = (change in amount owed) / (change in time)

We can calculate the change in amount owed by subtracting the initial amount from the final amount. For each loan, we'll consider the following time intervals:

Loan A: from t = 0 to t = 1

Loan B: from t = 1 to t = 2

Loan C: from t = 2 to t = 3

We can then calculate the average rate of change per year for each loan as follows:

Loan A:

average rate of change = (a(1) - a(0)) / (1 - 0)

= (1.12a(0) - a(0)) / 1

= 0.12a(0)

Therefore, the average rate of change per year for Loan A over the interval from t = 0 to t = 1 is 0.12 times the initial amount owed.

Loan B:

average rate of change = (b(2) - b(1)) / (2 - 1)

= (1.24b(1) - b(1)) / 1

= 0.24b(1)

Therefore, the average rate of change per year for Loan B over the interval from t = 1 to t = 2 is 0.24 times the amount owed at t = 1.

Loan C:

average rate of change = (c(3) - c(2)) / (3 - 2)

= (1.306c(2) - c(2)) / 1

= 0.306c(2)

Therefore, the average rate of change per year for Loan C over the interval from t = 2 to t = 3 is 0.306 times the amount owed at t = 2.

To know more about function visit:

https://brainly.com/question/12431044

#SPJ1

Therefore, the average rate of change per year for Loan A over the interval from t = 0 to t = 1 is 0.12 times the initial amount owed.

Therefore, the average rate of change per year for Loan B over the interval from t = 1 to t = 2 is 0.24 times the amount owed at t = 1.

Therefore, the average rate of change per year for Loan C over the interval from t = 2 to t = 3 is 0.306 times the amount owed at t = 2.

Every vertical line that has been drawn but cannot cross a graph more than once is referred to as a function. It is not considered to be a function for any graph points to allow a vertical line to pass through them more than once.

To find the average rate of change per year for each loan over a certain interval, we can use the formula:

average rate of change = (change in amount owed) / (change in time)

We can calculate the change in amount owed by subtracting the initial amount from the final amount. For each loan, we'll consider the following time intervals:

Loan A: from t = 0 to t = 1

Loan B: from t = 1 to t = 2

Loan C: from t = 2 to t = 3

We can then calculate the average rate of change per year for each loan as follows:

Loan A:

average rate of change = (a(1) - a(0)) / (1 - 0)

= (1.12a(0) - a(0)) / 1

= 0.12a(0)

Therefore, the average rate of change per year for Loan A over the interval from t = 0 to t = 1 is 0.12 times the initial amount owed.

Loan B:

average rate of change = (b(2) - b(1)) / (2 - 1)

= (1.24b(1) - b(1)) / 1

= 0.24b(1)

Therefore, the average rate of change per year for Loan B over the interval from t = 1 to t = 2 is 0.24 times the amount owed at t = 1.

Loan C:

average rate of change = (c(3) - c(2)) / (3 - 2)

= (1.306c(2) - c(2)) / 1

= 0.306c(2)

Therefore, the average rate of change per year for Loan C over the interval from t = 2 to t = 3 is 0.306 times the amount owed at t = 2.

To know more about function visit:

https://brainly.com/question/30721594

#SPJ1

Answer:

do what?? there nothing showing

Answer:

\(x > 4\)

Step-by-step explanation:

X is greater than 4

Answer:

1,900

Step-by-step explanation:

Answer:

1900 is my pick

Step-by-step explanation:

Looking through the options, the answer is option D.