When the normality is violated and the sample size is too small to ensure the normality of the sampling distributions, one option is to try to transform the dependent variable using the Box-Cox methodology using the suggested Lambda value. True O False

Answer:

(-2, -10)

Step-by-step explanation:

x=-2 y=-10

y=5*x

- 10=5*(-2) -10=-10

Answer:

3x+15+10

3x + 25

Step-by-step explanation:

Answer:

3x + 25

Step-by-step explanation:

Answer:

4.21x+2.72

Step-by-step explanation:

(-1.41x - 0.01) + (5.62x + 2.73)

Combine like terms

-1.41x+5.62x     -0.01+2.73

4.21x+2.72

Answer:

4.21x + 2.72

Step by step explanation:

( - 1.41x - 0.01 ) + ( 5.62x + 2.73 )

First solve the brackets.

- 1.41x - 0.01 + 5.62x + 2.73

Combine like terms.

-1.41x + 5.62x - 0.01 + 2.73

4.21x + 2.72

Answer:

       \(\frac{2}{7}\)

Step-by-step explanation:

3.5 = \(\frac{7}{2}\)

swap the numerator and denominator (flip the fraction):

reciprocal of \(\frac{7}{2}\) is \(\frac{2}{7}\)

Answer:

90

Step-by-step explanation:

90 has 0 ones so it is already rounded.

Answer:

90

Step-by-step explanation:

Hey there!

Well 90.000 to the nearest tenth is just 90 because there is decimal places to round.

Hope this helps :)

Answer:

2st

Step-by-step explanation:

because only 34 can be divided by 17 and there arent enough of s and ts

If ƒ is entire, then it has an nth order primitive for all n = N.

Given that UC C is open and ƒ: U → C is entire.

For n = N, we define an nth order primitive for f on U to be any function F: U → C such that

= f. dnF dzn

To prove that if f is entire, then ƒ has an nth order primitive for all n = N, we need to make use of Cauchy's theorem and integral formulas.

Let us define an operator Pn: A → A of nth order as:

Pn(g(z)) = 1 / (n − 1) ! ∫γ (g(w)/ (w - z)^n ) dw

where A is an open subset of C, γ is any closed curve in A and n is a positive integer.

Now let F be any antiderivative of ƒ. We can easily show that:

dn-1F dzdzn = (n - 1)!∫γ ƒ (w)/ (w-z)^n dw

We observe that if Pn(ƒ)(z) is the nth order operator applied to ƒ(z), then we have

Pn(ƒ) (z) = dn-1F dzdzn

Hence Pn(F) is the nth order primitive of ƒ on U. Therefore if ƒ is entire, then it has an nth order primitive for all n = N.

Conclusion: If ƒ is entire, then it has an nth order primitive for all n = N.

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Answer:

A

jk its D hope this helps

Answer:

Linear equations are an important tool in science and many everyday applications. They allow scientist to describe relationships between two variables in the physical world, make predictions, calculate rates, and make conversions, among other things. Graphing linear equations helps make trends visible.

Answer: Linear equations are an important tool in science and many everyday applications. They allow scientist to describe relationships between two variables in the physical world, make predictions, calculate rates, and make conversions, among other things. Graphing linear equations helps make trends visible.

Step-by-step explanation:

Answer:

1. y= 2/5x+11

2. y=3x-15

2y-5x=9

Step-by-step explanation:

I did this already

For the transformation at -78 °C, appropriate reagents include lithium aluminum hydride (LiAlH4) and diethyl ether.

At -78 °C, certain chemical reactions require the use of specific reagents to achieve the desired transformation. One commonly used reagent is lithium aluminum hydride (LiAlH4), which acts as a strong reducing agent. It is capable of reducing various functional groups, such as carbonyl compounds, to their corresponding alcohols.

Diethyl ether is typically employed as a solvent to facilitate the reaction and ensure efficient mixing of the reactants. Researchers often utilize this low temperature for reactions involving sensitive or reactive intermediates, as it helps control the reaction and prevent unwanted side reactions.

The use of LiAlH4 and diethyl ether provides a reliable combination for achieving the desired transformation at this temperature, enabling chemists to manipulate and modify compounds in a controlled manner.

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The mean for the given grouped data given for the stated frequency distribution is found as 20.68.

Prepare the frequency distribution table for the given data:

Interval         Frequency{f}      Midpoint of frequency{x}          f×x

1-7                    16                        4                                            64

8-10                  4                        9                                            36

11-15                 4                        13                                           52

16-20               17                       18                                           306

21-35               13                       28                                          364

36-50              13                       43                                          559

Sum                67                                                                     1381

The mean  of grouped data = Sum (Interval Midpoint * Frequency) / Sum of all frequency

Mean =  1386 / 67

Mean = 20.68

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Answer: s/12 = v

Step-by-step explanation:

Answer:

x = 7 x (9 + 2)

Step-by-step explanation:

Sum of 9 and 2 is ( 9 + 2)

7 times that is 7 x (9 + 2)

If my answer is incorrect, pls correct me!

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-Chetan K

A connected graph can be disconnected by removing vertices if and only if it is not a complete graph.

A connected graph is one where there exists a path between any pair of vertices. Removing any vertex from a complete graph will result in a disconnected graph since there will be at least one pair of vertices that are no longer connected. Therefore, a complete graph cannot be disconnected by removing vertices.

On the other hand, if a graph is not a complete graph, it means that there exist at least two vertices that are not connected by an edge. By removing these vertices, we effectively disconnect the graph since there is no longer a path between them.

Thus, it is possible to remove vertices to disconnect a graph that is not a complete graph.

A complete graph cannot be disconnected by removing vertices, while a non-complete graph can be disconnected by removing appropriate vertices.

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Answer:

y=3x+14

Step-by-step explanation:

We can use point-slope intercept form to find the equation of the line.

Equation: y-y₁=m(x-x₁)

**For a line to be perpendicular to another, its slopes must be negative reciprocals of each other. So, in our example, the slope of the new line must be \(\frac{1}{3}\).

1. Plug in provided info into the equation listed above (the coords are the values that we will put for x₁ and y₁:

    y-5=\(\frac{1}{3}\)(x-(-3))

2. Simplify:

    y-5=\(\frac{1}{3}\)(x+3)

3. Distribute & Simplify

    y-5=\(\frac{1}{3}\)x+1

3. Add 5 to both sides of the equation:

    y=\(\frac{1}{3}\)+6

The equation of the line that passes through (-3, 5) and is perpendicular to the line y=-3x-1 is y = x/3 + 20/3.

For the given question;

The equation of the perpendicular line is given as;

y=-3x-1

Compare with the standard slope intercept form.

y = mx + c

m is the slope and c is the y intercept.

Say slope m1 = -3

Then, the relation for the slopes of two perpendicular lines are-

m1 x m2 = -1

m2 = -1/m1

m2 = -1/-3 = 1/3

This, line with the slope 1/3 passes through the points;

(x1, y1) = (-3, 5)

The equation of the line is obtained as;

y - y1 = m2(x - x1)

y - 5 = (1/3)(x + 5)

y = x/3 + 20/3

Thus, the equation of the line that passes through (-3, 5) and is perpendicular to the line y=-3x-1 is y = x/3 + 20/3.

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The smaller number is approximately 89.09, and the larger number is approximately 1.2 times that, or approximately 106.91.

We have,

Let's call the smaller number "x".

Since the other number is 20% more than the smaller number, the larger number can be represented as:

x + 0.2x = 1.2x

We know that the sum of the two numbers is 196, so we can set up the equation:

x + 1.2x = 196

Simplifying the left side of the equation, we get:

2.2x = 196

Dividing both sides by 2.2, we get:

x = 89.09 (rounded to two decimal places)

Therefore,

The smaller number is approximately 89.09, and the larger number is approximately 1.2 times that, or approximately 106.91.

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The shapes of the curves in the AS/AD (Aggregate Supply/Aggregate Demand) model are based upon the relationship between the price level and the output level in an economy.

The AD curve shows the relationship between the overall price level and the quantity of goods and services demanded by all buyers in an economy. It has a negative slope, indicating that as the price level increases, the quantity of goods and services demanded decreases.

The AS curve shows the relationship between the overall price level and the quantity of goods and services that firms are willing and able to supply. In the short run, the AS curve is upward sloping, indicating that as the price level increases, firms are willing to supply more output due to higher profits. In the long run, the AS curve becomes vertical, indicating that the level of output is determined by the factors of production and technology, not the price level.

Thus, the shapes of the curves in the AS/AD model are based on the behavior of buyers and sellers in an economy and their response to changes in the overall price level.

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There will be 5 units on side DF. There's no need to hunt for more details because they've already been given.

Triangles that are exactly the same in terms of size and shape are said to be congruent. Congruent is symbolized by the symbol when the measurements of one triangle's three sides and three angles match those of another triangle's three sides and three angles.

The ratio of the sides of the two triangles is equal since they are congruent.

BC / EF = AC / EF

Assume that side DF is x in length.

20 / DF = 24 /6

20 / x = 24 / 6

x = 20 / 4

x = 5

Therefore, DF = 5 units

As a result, side DF will be 5 units long. There is no need to look for any more information because it has already been provided.

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Answer:

3 . 2

4. 3

Step-by-step explanation:

Differentiate the given functions using the product rule so we get , dy/dx = 2xIn x + 3x

For y = x²(x² + 3), let's differentiate using the product rule.

Using the notation f(x) = x² and g(x) = x² + 3, we have:

y = f(x) * g(x)

To differentiate, we apply the product rule:

dy/dx = f'(x) * g(x) + f(x) * g'(x)

Differentiating f(x) = x², we have f'(x) = 2x.

Differentiating g(x) = x² + 3, we have g'(x) = 2x.

Substituting these values into the product rule, we get:

dy/dx = (2x)(x² + 3) + (x²)(2x)

Simplifying further, we have:

dy/dx = 2x³ + 6x + 2x³

Combining like terms, we obtain:

dy/dx = 4x³ + 6x

For y = x²(In x + 1), let's differentiate using the product rule.

Using the notation f(x) = x² and g(x) = In x + 1, we have:

y = f(x) * g(x)

Applying the product rule:

dy/dx = f'(x) * g(x) + f(x) * g'(x)

Differentiating f(x) = x², we have f'(x) = 2x.

Differentiating g(x) = In x + 1, we have g'(x) = 1/x.

Substituting these values into the product rule, we get:

dy/dx = (2x)(In x + 1) + (x²)(1/x)

Simplifying further, we have:

dy/dx = 2x(In x + 1) + x

Expanding the brackets and combining like terms, we obtain:

dy/dx = 2xIn x + 2x + x

Simplifying further, we have:

dy/dx = 2xIn x + 3x

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The vertex form of the equation is y = (x - 3)² - 4, which corresponds to option OD.

To convert the given equation from standard form to vertex form, we need to complete the square.

The vertex form of a parabola's equation is y = a(x-h)² + k, where (h, k) represents the vertex of the parabola.

Given equation: y = x² - 6x + 14

Move the constant term to the right side:

y - 14 = x² - 6x

Complete the square by adding and subtracting the square of half the coefficient of x:

y - 14 + 9 = x² - 6x + 9 - 9

Group the terms and factor the quadratic:

(y - 5) = (x² - 6x + 9) - 9

Rewrite the quadratic as a perfect square:

(y - 5) = (x - 3)² - 9

Simplify the equation:

y - 5 = (x - 3)² - 9

Move the constant term to the right side:

y = (x - 3)² - 9 + 5

Combine the constants:

y = (x - 3)² - 4

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The probability of rolling two dice and getting a sum of 7 is 1/6.

The probability is the ratio of the number of favorable outcomes to the total outcomes in that sample space. Probability of an event P(E) = (Number of favorable outcomes) ÷ (Sample space).

Sample space for rolling a pair of dice we have:

=> S {(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6) (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}

n(S) = 36

Let A = sum of numbers is 7 = { (1, 6)(2, 5)(3, 4) (4, 3) (5, 2) (6, 1)}

n(A) = 6

P (Sum of numbers is 7) = n(A) / n(S)

= 6/36 = 1/6

Therefore, the probability of rolling two dice and getting a sum of 7 is 1/6.

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Hi ;-)

\(\text{x}=-1 \ \text{and} \ \text{y}=-4\\\\\dfrac{5x^2-y^2+3}{2x-4y}=\dfrac{5\cdot(-1)^2-(-4)^2+3}{2\cdot(-1)-4\cdot(-4)}=\dfrac{5\cdot1-16+3}{-2+16}=\boxed{-\frac{8}{14}}\)

The area of the composite figures are as follows;

10. Area of the trapezoids are; 96 cm², 80 cm², 96 cm², 80 cm²

Area of the rectangle at the center =  320 cm²

11. Area of the field on the left is 18,600 m²

Area of the field on the right is 11,000 m²

A composite figure is a figure that consists of two or more regular shapes.

10. The width of each trapezoid are;

(28 - 20)/2 = 4

(24 - 16)/2 = 4

The area of each trapezoid are;

The area of each of the left and right trapezoid = 4 × (20 cm + 28 cm)/2 = 96 cm²

Area of the top and bottom trapezoid = 4 × (16 cm + 24 cm)/2 = 80 cm²

Area of the rectangle at the center = 16 cm × 20 cm = 320 cm²

11. Area of ΔDEI = 0.5 × 80 m × 60 m = 2400 m²

Area of trapezoid EIGF = 0.5 × (60 m + 50 m) × (60 m + 20 m) = 4400 m²

Area of the triangle ΔAGF = 0.5 × 50 m × 80 m = 2000 m²

Area of ΔAHC = 0.5 × 40 m × (20 m + 80 m) = 2000 m²

Area of ΔABC = 0.5 × 30 m × (20 m + 80 m) = 1500 m²

Area of quadrilateral AHCB =  2000 m² + 1500 m² = 3500 m²

Area of triangle ΔCDH = 0.5 × 40 m × (80 m + 60 m) = 2800 m²

Adding together, we get;

2400 + 4400 + 2000 + 2000 + 1500 + 3500 + 2800 = 18,600

The area of composite figure is 18,600 m²\

Area of ΔEFH = 0.5 × 20 m × 40 m = 400 m²

Area of trapezoid GFHJ = 0.5 × (20 m + 40 m) (40 m  + 40 m) = 2400 m²

Area of triangle ΔAGJ = 0.5 × 40 m ×(20 m + 60 m) = 1600 m²

Area of triangle ΔABK = 0.5 × 30 m × 60 m = 900 m²

Area of trapezoid BCF_K = 0.5 × (40 m + 30 m) × (40 m + 20 m) = 2100 m²

Area of triangle ΔCIE = 0.5 × 40 m × (40 m + 40 m) =  1600 m²

Area of triangle ΔCDE = 0.5 × 50 m × (40 m × 40 m) = 2000 m²

Adding the areas together, we get;

400 + 2400 + 1600 + 900 + 2100 + 1600 + 2000 = 11000

The area of the field is 11,000 m²

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According to the given conditions the value of \(x$ is $\frac{9\sqrt{2}}{2}$.\)

A triangle is a closed two-dimensional geometric shape with three sides and three angles. It is one of the basic shapes in geometry and has many applications in mathematics, science, and engineering.

We can use the trigonometric ratio for the angle \($45^\circ$\) (which is also known as the angle of the isosceles right triangle) to find the value of \(x$.\)

In a right-angled triangle, the sine of an acute angle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse. Therefore, we have:

\($$\sin(45^\circ) = \frac{\text{opposite}}{\text{hypotenuse}}$$\)

Substituting the given values, we get:

\($$\sin(45^\circ) = \frac{x}{9}$$\)

Since the sine of \(45^\circ$ is equal to $1/\sqrt{2}$\), we can simplify the equation as follows:

\($\frac{1}{\sqrt{2}} = \frac{x}{9}$$\)

Multiplying both sides by 9, we get:

\(x = \frac{9}{\sqrt{2}}$$\)

To simplify this expression, we can multiply the numerator and denominator by \(\sqrt{2}$:\)

\($x = \frac{9\sqrt{2}}{2}$$\)

Therefore, according to the given conditions the value of \(x$ is $\frac{9\sqrt{2}}{2}$.\)

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Answer:

3(3a-6b+7c)

Step-by-step explanation:

9a-18b+21c=3(3a-6b+7c)

Answer:

Tag me as Brilliant

Step-by-step explanation:

Herevis your answer.

Answer:

x=85

Step-by-step explanation:

35+60 = 95

180 minus 95 = 85