when red, green, and blue light are combined in equal proportions the result is? group of answer choices white light ultraviolet radiation green light yellow light black light

The existence of black holes is supported by a significant body of scientific evidence and observations like, stellar observations, gravitational waves, accretion disks, galactic centers, and general relativity.

1. Stellar observations: Astronomers have observed the behavior of stars within galaxies, particularly in binary star systems. They have noticed anomalies in the orbital motion and energy output of these systems that can be best explained by the presence of a black hole.

2. Gravitational waves: In 2015, the Laser Interferometer Gravitational-Wave Observatory (LIGO) made the first direct detection of gravitational waves, which are ripples in the fabric of spacetime caused by the acceleration of massive objects. LIGO has detected gravitational waves originating from the merger of black holes, providing strong evidence for their existence.

3. Accretion disks: When matter falls into a black hole, it forms an accretion disk, which is a swirling disk of superheated gas and dust. The intense X-ray emissions detected from these accretion disks provide further evidence for the presence of black holes.

4. Galactic centers: Observations of galactic centers, including our own Milky Way galaxy, have revealed the presence of extremely massive and compact objects. These objects, known as supermassive black holes, can explain the observed gravitational effects and energy emissions from these regions.

5. General relativity: The theory of general relativity, proposed by Albert Einstein, provides a mathematical framework for understanding the behavior of gravity and the existence of black holes. General relativity has been extensively tested and has successfully predicted various phenomena related to black holes.

While the direct observation of black holes remains challenging due to their nature as objects that trap all light, the evidence from these various lines of inquiry strongly supports their existence. Scientists continue to study and explore black holes to deepen our understanding of the universe.

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The pressure of 76 cm of mercury column is 10132.5 Pa.

Pressure, in the physical sciences, the perpendicular force per unit area, or the stress at a point within a confined fluid.

The pressure of 76 cm of mercury column can be converted to Pascals (Pa) using the following conversion factor:

1 atm = 101325 Pa

760 mmHg = 1 atm

Therefore,

76 cm Hg = (76/760) atm = 0.1 atm

Now, we can convert this pressure in atm to Pascals using the following conversion factor:

1 atm = 101325 Pa

Therefore,

0.1 atm = 0.1 * 101325 Pa = 10132.5 Pa

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--The complete question is, Pressure of 76cm of mercury column is ______ pa.--

Answer: d boiling water

Explanation: the water is boiling and bubbling cause the molecules are so fast and they hit off each other

Answer:

21.76J

Explanation:

F=ma

where:

m=mass

a=acceleration

Kamaria's mother should pull her with a force of  21.76 Newton if she (Kamaria) wants her acceleration to be 0.80 m/s².

In order to accelerate a body of mass 'm kg' with an acceleration of 'a m/s²', a force of magnitude equal to the product of mass and required acceleration is required. Mathematically -

F = m x a

Given is a girl learning how to ice skate. She wants to move with an acceleration of 0.80 m/s² and her mass is 27.2 kg.

From the definition of force, we can write -

F = m x a

F = 27.2 x 0.8

F = 21.76 Newton

Therefore, Kamaria's mother should pull her with a force of  21.76 Newton if she (Kamaria) wants her acceleration to be 0.80 m/s²

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The moment of inertia of the skater when their arms are extended is 2.724 kg·m².

In the given question, the mass of the skater is 68.5 kg. The radius of cylinder, r = 0.115 m. The length of arm, l = 0.875 m. The percentage of mass in each arm is 5%.

The moment of inertia of a skater when the arms are pulled inward is given as: I_b = 0.453 kg.m²

Let's calculate the moment of inertia of the skater when the arms are extended. The skater is considered to be composed of two parts, body and arms.

The moment of inertia of the body can be calculated as:

I_b = (1/2) M_b R_b² ... (1)

Here, M_b is the mass of the body, and R_b is the radius of the body. The given radius, r = 0.115 m is the radius of the body. Therefore, R_b = 2r = 0.23 m. The mass of the body can be calculated as:

M_b = (1 - 0.05) M = 0.95 (68.5 kg) = 65.075 kg.

Substituting these values in equation (1), we get:

I_b = (1/2) × 65.075 × (0.23)²= 1.106 kg.m²

The moment of inertia of each arm can be calculated as:

I_a = (1/3) M_a L_a² ... (2)

Here, M_a is the mass of each arm, and L_a is the length of each arm. The percentage of mass in each arm is 5%. Therefore, the mass of each arm can be calculated as:

M_a = 0.05 M = 0.05 (68.5 kg) = 3.425 kg.

Substituting the given values in equation (2), we get:

I_a = (1/3) × 3.425 × (0.875)²= 0.809 kg.m²

The total moment of inertia of the skater is given by: I = I_b + 2I_a (since there are two arms) = 1.106 + 2(0.809) = 2.724 kg.m²

Therefore, the moment of inertia of the skater when their arms are extended is 2.724 kg·m².

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Here work done by the car against the force of air in each second denotes the power needed to overcome air resistance at that particular speed. The power of engine is 28 kW.

The power of an object denotes the rate of performing the work. It is defined as the work done in unit time. The SI unit of power is Watt (W) which is also called joules per second.

Power = Resistance × Speed of vehicle

Here the air resistance is found to be 700 N. Then,

Power = 700 × 40 = 28000 N m/s = 28 kW

Thus the engine power is 28 kW.

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When light travels from one medium to another, its speed, direction, and wavelength can change, while its frequency remains constant. These changes are due to differences in the refractive indices of the two media.

As light travels from one medium to another, several of its properties change, including its speed, direction, and wavelength. The speed of light changes because the refractive index of each medium is different, which alters the velocity of the wave. The direction of the light may also change, a phenomenon known as refraction, as it enters a medium with a different refractive index. The amount of refraction depends on the angle of incidence, the angle between the incoming light and the normal line to the surface of the medium. Finally, the wavelength of the light may also change due to the refractive index of the medium, a phenomenon known as dispersion. This results in the separation of white light into its component colors when it passes through a prism or other refracting medium.

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The final volume of the balloon is 197,083 L.

They are proportional to each other if the pressure does not change. However, there are pitfalls. To perform calculations we have to use the so-called absolute temperature. Increased external air pressure compresses the balloon.

Using equation;

PV =nRT

here constants are P,n, R

so the relation between P and T is

V₁ /T₁= V₂/T₂

V₂ = (V₁ /T₁)×T₂

    = (125,000/300)×473

     = 197,083 L.

As the volume of the balloon decreases the pressure inside the balloon increases. After all external air pressure can compensate. It becomes a balloon filled with dense cold air. According to Boyle's law, the volume of a gas of constant mass at constant temperature is inversely proportional to its pressure. The air around you has weight and pushes away everything it touches. This pressure is called atmospheric pressure or barometric pressure. This is the force exerted on a surface by the air above as gravity pulls the surface toward the Earth.

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Yes, the information that the sprinter's mass is 60.0 kg is needed to find the normal force and to determine the maximum acceleration.

To determine the maximum acceleration that the sprinter can achieve, we need to know the coefficient of static friction between the soles of her shoes and the track surface, as well as her weight (force of gravity acting on her).

The coefficient of static friction can be used to calculate the maximum force of friction (friction force = coefficient of static friction x normal force).

The normal force is equal to the weight of the object, which is given as 60.0 kg. So the normal force is : 60.0 kg x 9.8 m/s^2 = 588 N.

The maximum force of friction is: friction force = coefficient of static friction x normal force

= 0.754 x 588 N

= 445.5 N

The maximum acceleration can be determined by dividing the force acting on an object by its mass.

a = F / m

= 445.5 N / 60.0 kg

= 7.4 m/s^2

So the maximum acceleration the sprinter can achieve is 7.4 m/s^2

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(i) The length of wire X is determined as 7.14 m.

(ii) The current in the wire is determined as 0.06 A.

(iii) The charge passing through the wire in 5 minutes is 18 C.

The length of wire X is calculated by applying the following formula as shown below;

ρ = RA / L

where;

Since the wires are made of the same material, resistivity of wire X = resistivity of wire Y

let wire X = 1

let wire Y = 2

R₁A₁ / L₁ = R₂A₂ / L₂

L₁ = ( R₁A₁L₂ ) / ( R₂A₂ )

L₁ = ( 200Ω x A₁ x 2.5 m ) / ( 35Ω x 2A₁ )

L₁ = 7.14 m

The current flowing in wire X is calculated as follows;

V = IR

I = V / R

where;

I = ( 12 V ) / (  200Ω )

I = 0.06 A

The charge passing through the wire in 5 minutes is calculated as follows;

Q = It

Q = 0.06 A x ( 5 x 60 s )

Q = 18 C

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The mass of the object is obtained as 130 g.

The triple beam balance is the kind of balance that could be used to measure the mass of a substance. There are so many kinds of balance that could be used in science and these include;

1) beam balance

2) Spring balance
3) unequal arm balance

We read the mass of the object by looking at all the points that we have set on the triple beam balance to achieve the balance point. In the case of the substances that we have seen in the image of the question, the mass of the object is obtained as 130 g.

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D, the oceanic crust

Explanation: The crust is the outermost layer of Earth's lithosphere, and since the question is talking about the ocean, D is the most likely choice.

happy to help, have a great day! :)

Answer:

Yeah  I think you're right

Explanation:

Because every obj is in motion till acted upon by a force(the branch)

The magnetic field at a distance r from the center of a long wire with radius a and uniform current per unit area j in the positive z direction can be found using Ampere's law and is equal to B = { μ0jr/2 (for r<a)

μ0ja²/2r (for r>a) }

For a point inside the wire (r<a), we can choose an imaginary Amperian loop in the shape of a circle with radius r centered on the wire.

The current passing through this loop is equal to the current density times the area of the loop, so I = jπr^2. By Ampere's law, the line integral of the magnetic field around this loop is equal to μ0 times the enclosed current, where μ0 is the permeability of free space.

Since the current is uniform, the magnetic field is also uniform and directed in the azimuthal direction. Therefore, the line integral reduces to B times the circumference of the loop, or 2πrB. Thus, we have:

2πrB = μ0 jπr²

B = μ0jr/2

For a point outside the wire (r>a), we can again choose an imaginary Amperian loop in the shape of a circle with radius r centered on the wire. However, in this case, the current passing through the loop is equal to the total current flowing in the wire, which is equal to the current density times the cross-sectional area of the wire, or I = jπa^2. Thus, we have:

2πrB = μ0 jπa²

B = μ0ja²/2r

Therefore, the magnetic field at a distance r from the center of a long wire with radius a and uniform current per unit area j in the positive z direction is given by:

B = { μ0jr/2 (for r<a)

μ0ja²/2r (for r>a) }

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The work-energy theorem states that a force acting on a particle as it moves over a distance changes the kinetic energy of the particle if the force has a component parallel to the motion.

The work-energy theorem is a fundamental principle in physics that relates the work done on an object to its change in energy. According to the theorem, when a force acts on a particle and causes it to move over a certain distance, the work done by the force changes the energy of the particle. Specifically, if the force has a component parallel to the motion of the particle, it can change the particle's kinetic energy.

Kinetic energy is the energy associated with the motion of an object, and it depends on its mass and velocity. When a force acts parallel to the motion of the particle, it can either increase or decrease the particle's speed, thus altering its kinetic energy. If the force is in the same direction as the particle's velocity, it adds energy to the particle and increases its kinetic energy. Conversely, if the force is in the opposite direction to the particle's velocity, it subtracts energy from the particle and decreases its kinetic energy.

In summary, the work-energy theorem states that a force acting on a particle over a distance changes the kinetic energy of the particle if the force has a component parallel to the motion. It highlights the connection between work, force, distance, and energy, providing a useful tool for analyzing the behavior of objects in various physical systems.

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Ignoring the malformed character, it looks like you're saying you have particle initially located at (1, 1, 3) that travels in a straight line to (5, 9, 4) with initial speed 6 and constant acceleration vector 4i + 8j + k.

Use the fundamental theorem of calculus to determine the velocity function for the particle:

\(\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u) \, du\)

The particle moves in the same direction as the vector

(5i + 9j + 4k) - (i + j + 3k) = 4i + 8j + k

which has magnitude

√(4² + 8² + 1²) = √81 = 9

Normalize the direction vector by dividing it by its magnitude:

(4i + 8j + k)/9 = 4/9 i + 8/9 j + 1/9 k

The particle has initial speed 6, so we must scale this unit vector by a factor of 1/6 to get the initial velocity vector:

6 (4/9 i + 8/9 j + 1/9 k) = 8/3 i + 16/3 j + 2/3 k

Solve for v(t) :

\(\vec v(t) = \dfrac83\vec\imath + \dfrac{16}3\vec\jmath + \dfrac23\vec k + \displaystyle \int_0^t \left(4\vec\imath + 8\vec\jmath+\vec k\right) \, du\)

\(\vec v(t) = \dfrac83\vec\imath + \dfrac{16}3\vec\jmath + \dfrac23\vec k + \left(4t\,\vec\imath + 8t\,\vec\jmath+t\,\vec k\right)\)

\(\vec v(t) = \left(\dfrac83+4t\right)\vec\imath + \left(\dfrac{16}3+8t\right)\vec\jmath + \left(\dfrac23+t\right)\vec k\)

Use the fundamental theorem again to find the position vector r(t) :

\(\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u) \, du\)

\(\vec r(t) = \vec\imath+\vec\jmath+3\vec k + \displaystyle \int_0^t \left(\left(\dfrac83+4u\right)\vec\imath + \left(\dfrac{16}3+8u\right)\vec\jmath + \left(\dfrac23+u\right)\vec k\right) \, du\)

\(\vec r(t) = \vec\imath+\vec\jmath+3\vec k + \left(\left(\dfrac83 t+2t^2\right)\vec\imath + \left(\dfrac{16}3t+4t^2\right)\vec\jmath + \left(\dfrac23t+\dfrac12t^2\right)\vec k\right)\)

\(\vec r(t) = \left(1+\dfrac83 t+2t^2\right)\vec\imath + \left(1+\dfrac{16}3t+4t^2\right)\vec\jmath + \left(3+\dfrac23t+\dfrac12t^2\right)\vec k\)

Answer:

options?!?

Explanation:

give us some options

Answer:

Im sorry but i really need these points. FORGIVE ME

Explanation:

Answer:

Valence Electrons

Explanation:

The electrons of an atom that can participate in the formation of chemical bonds with other atoms. they are the furthest electrons from nucleus

The correct match of the change in mass or distance and the effect of change on the gravitational force between two objects are given below:

d → 2d and m in unchanged ----> Fg → (1/4) Fg

m → 2m and d is unchanged --->  Fg → (2) Fg

d → 2d and m → 2m   ---> Fg →  Fg

d → (1.2) d and m is unchanged --->  Fg → (4) Fg

m → (1/2) m and d is unchanged ---> Fg → (1/2) Fg

Gravitational force is the force that pushes mass-containing objects toward one another. We frequently consider the pull of gravity from the Earth. Your body is kept on the ground by this force. However, all mass-bearing objects are pulled toward one another by gravity.

The gravitational force depends on the magnitude of the masses and the distance between the masses.

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Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

\(K.E = \frac{1}{2}mv^2\\\)   ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

\(K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\\)

using equation (1):

K.Eₓ = 4 K.E

For thrice speed:

vₓ = 3v

then,

\(K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\\)

using equation (1):

K.Eₓ = 9 K.E

A. The kinetic energy of automobile when it moves at twice the speed is 8000 J

B. The kinetic energy of automobile when it moves at three times the speed is 18000 J

Let the mass of the automobile be constant.

Let the initial velocity be v

A. Determination of the kinetic energy of the automobile when it moves at twice the speed.

KE₁ /v₁² = KE₂ / v₂²

2000 / v² = KE₂ / (2v)²

2000 / v² = KE₂ / 4v²

Cancel out v²

2000  = KE₂ / 4

Cross multiply

KE₂ = 2000 × 4

KE₂ = 8000 J

B. Determination of the kinetic energy of the automobile when it moves at three times the speed.

KE₁ /v₁² = KE₂ / v₂²

2000 / v² = KE₂ / (3v)²

2000 / v² = KE₂ / 9v²

Cancel out v²

2000  = KE₂ / 9

Cross multiply

KE₂ = 2000 × 9

KE₂ = 18000 J

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A remains constant, the tension in cable B can be calculated using the formula T = W/sin(θ), where T is the tension, W is the weight of the sign, and θ is the angle formed by cable A. the tension in cable B is 750N/sin(30°) = 1333.38N.

what is cable ?

Cable is a type of wiring system used to transmit electrical signals. It consists of insulated conductors, usually copper, twisted together in a pattern that reduces interference from external sources. Cables are often used to connect components within a system, such as computers, televisions, and audio systems.

They can also be used to connect systems to each other, such as connecting a laptop to a router or connecting a router to a modem. Cables can be used to carry data as well as power. Depending on the type of cable, it can support various types of data transfer speeds and resolutions. For example, HDMI cables are used to transmit audio and video signals in high-definition.

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The Tip Speed Ratio (TSR) is the ratio of the speed of the wind turbine blade to the wind speed. It is defined as the speed of the blade tips divided by the wind speed and is represented by λ.

The Tip speed ratio is defined as the ratio of the wind speed at the tips of the turbine blades to the wind speed. The ratio is used to compare the performance of various wind turbines. The performance of the wind turbine is directly related to the tip speed ratio. This ratio is important as it helps in determining the amount of energy that can be harvested from the wind.

It is also important because it is used to measure the efficiency of a wind turbine. The higher the tip speed ratio, the more efficient the turbine is in capturing the energy from the wind.b) The operation of the wind turbine is optimized when the tip speed ratio changes. The tip speed ratio can be changed by altering the rotational speed of the blades, the length of the blades, or the wind speed. When the tip speed ratio is optimized, the wind turbine can operate at its maximum efficiency.

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True

The helium-neon lasers most commonly used in student physics laboratories have average power outputs of 0. 250 mw

Intensity of laser beam is 72.3W/m²

Given:

average power output = 0. 250 mw

To Find: intensity of laser beam

First of all, we need to find the area of the circular spot, which is given by:

A = πr^2

where r is the radius of the spot, which is half the diameter, therefore

r = d/2 = 2.10mm/2 = 1.05mm = 1.05 x 10^-3m

So, the area of the spot is

A = π(1.05 10^-3m)^2 = 3.46 10^-6m²

We know that the power output of the laser is

P = 0.250mW = 2.5.10^-4W

So the intensity of the laser beam is

I = P/A = 2.5^-10 W/3.46-10^-6m^2 = 72.3W/m²

So, intensity of laser beam is 72.3W/m²

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A lorenz curve represents the cumulative percentage of total income received along the horizontal axis and the cumulative share of population along the vertical axis.

The distribution of the cumulative percent of occurrences by the cumulative percent of population is shown graphically by the Lorenz Curve. By expanding the neighbourhood income quintile group, the horizontal axis (x-axis) of the curve shows the cumulative percent of persons in the population, and the vertical axis (y-axis) shows the cumulative percent of events in the population.

The Lorenz curve can be described as the proportion of the population that the neighbourhood income quintile represents holding the proportion of population events.

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Answer:

The lifeguard should run approximately 17.752 meters along the shore, before, jumping in the water

Explanation:

The given parameters are;

The rate at which the lifeguard runs = 5 m/s

The rate at which the lifeguard swims = 1 m/s

The horizontal distance of the child from the lifeguard = 30 meters along the shore

The vertical distance of the child from the lifeguard = 60 meters along the shore

Let x represent the distance the lifeguard runs

We have;

The distance the lifeguard swims = √((30 - x)² + 60²)

Time = Distance/Speed  

The time the lifeguard runs = x/5

The time the lifeguard swims = √((30 - x)² + 60²)/1

The total time = √((30 - x)² + 60²) + x/5

The minimum time is given by finding the derivative and equating the result to zero, as follows;

Using an online application, we have;

d(√((30 - x)² + 60²) + x/5)/dx = 1/5 - (30 - x)/(√((30 - x)² + 60²)) = 0

Which gives;

1/5 - (30 - x)/(√(x² - 60·x + 4500) = 0

(30 - x)/(√(x² - 60·x + 4500)) = 1/5

5×(30 - x) = √(x² - 60·x + 4500)

We square both sides to get;

(5×(30 - x))² = (x² - 60·x + 4500)

(5×(30 - x))² - (x² - 60·x + 4500) = 0

25·x² - 1500·x + 22500 - x² + 60·x - 4500 = 0

24·x² - 1440·x + 18000 = 0

Dividing n=by 24 gives;

24/24·x² - 1440/24·x + 18000/24 = 0

x² - 60·x + 750 = 0

By the quadratic formula, we have;

x = (60 ± √((-60)² - 4×1×750))/(2 × 1) =

Using an online application, we have;

x = (60 ± 10·√6)/(2)

x = 30 + 5·√6 or x = 30 - 5·√6

x ≈ 42.25 m and x ≈ 17.752 m

At x = 42.25

Time = √((30 - 42.247)² + 60²) + 42.247/5 ≈ 69.69 seconds

At x = 17.75

Time = √((30 - 17.752)² + 60²) + 17.752/5 ≈ 64.79 seconds

Therefore, the route with the shortest time is when the lifeguard runs approximately 17.752 meters (rounded to three decimal places) along the shore, before, diving in the water