When powdered zinc is heated with sulfur, a violent reaction occurs, and zinc sulfide forms:
Zn(s) + S₈(s) → ZnS(s)
[unbalanced]
Some of the reactants also combine with oxygen in air to form zinc oxide and sulfur dioxide. When 83.2 g of Zn reacts with 52.4 g of S₈, 104.4 g of ZnS forms.
(b) If all the remaining reactants combine with oxygen, how many grams of each of the two oxides form?

Answer:

91.49 grams

Explanation:

No of molecules = no of moles × Avogadro's number

No of moles = No of molecules / Avogadro's number

Number of moles = 5.4×10^23/6.02×10^23

Number of moles = 0.897 moles of Al2O3

Number of moles = mass in gram / molar mass

Mass in gram = number of moles× molar mass

Mass in gram = 0.897× 102

91.49 grams

Answer:

uhh its gallon

Explanation:

A 14-year-old adolescent girl, Alice, has been diagnosed with anorexia nervosa. In the assessment of Alice, the findings that are more commonly associated with anorexia nervosa are Dysmenorrhea, decreased body temperature, and Heat intolerance.

Dysmenorrhea: Anorexia nervosa can lead to hormonal imbalances and disruptions in the menstrual cycle, which can cause irregular or absent periods (amenorrhea) and sometimes dysmenorrhea (painful periods).

Decreased body temperature: Anorexia nervosa can lead to lower body weight and reduced body fat, which can result in a lower body temperature. This is a physiological response to conserve energy and maintain the body's functions.

Heat intolerance: Anorexia nervosa can affect the body's ability to regulate temperature properly, leading to increased sensitivity to heat or cold. Individuals with anorexia may feel more discomfort or intolerance in extreme temperatures.

Hence,  the findings that are more commonly associated with anorexia nervosa are explained above.

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Severe diarrhea can diminish potassium ion absorption, this statement is true.

Severe diarrhea can lead to significant losses of fluid and electrolytes, including potassium ions. This can result in decreased absorption of potassium ions by the body. It is important to replace lost fluids and electrolytes during bouts of severe diarrhea to prevent potential health complications. True, severe diarrhea can diminish potassium ion absorption. This occurs because diarrhea causes the loss of fluids and electrolytes, including potassium, which can lead to decreased absorption and potential imbalances in the body.

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Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below.

Explanation:

To determine the number of grams of S used:

1. Calculate the molar mass of Al2S3: 2(Al) + 3(S) = 2(26.98 g/mol) + 3(32.07 g/mol) = 150.18 g/mol.

2. Use the molar ratio from the balanced equation: 3 moles of S correspond to 1 mole of Al2S3.

3. Convert grams of Al2S3 to moles: 5.53 g / 150.18 g/mol = 0.0368 mol.

4. Calculate grams of S: 0.0368 mol × 3 mol S / 1 mol Al2S3 = 0.1104 g.

To determine the number of grams of Al used:

1. Use the molar ratio from the balanced equation: 2 moles of Al correspond to 3 moles of S.

2. Convert grams of S to moles: 59.33 g / 32.07 g/mol = 1.848 mol.

3. Calculate grams of Al: 1.848 mol × 2 mol Al / 3 mol S = 1.232 g.

According to the balanced chemical equation 2Al + 3S → Al2S3, we can determine the amount of sulfur (S) and aluminum (Al) used or produced. To find the grams of S used, we first calculate the molar mass of Al2S3 and then use the molar ratio to convert grams of Al2S3 to moles of S. Multiplying the moles of S by its molar mass gives us the mass of S used, which is 0.1104 g. For the grams of Al used, we use the molar ratio between Al and S to convert the grams of S to moles of Al. Finally, multiplying the moles of Al by its molar mass gives us the mass of Al used, which is 1.232 g.

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The stereochemical relationship between the salts formed by (+)-tartaric acid with racemic 1-phenylethanamine is diastereomeric.

This is because (+)-tartaric acid is a chiral molecule, meaning it has a non-superimposable mirror image, while the racemic 1-phenylethanamine is a mixture of both enantiomers (mirror-image isomers) in equal amounts.

When (+)-tartaric acid reacts with the racemic 1-phenylethanamine, it forms two different diastereomeric salts. These salts have distinct physical properties and can be separated, allowing for the resolution of the racemic mixture.

These diastereoisomers can be separated using the techniques such as chromatography, and their stereochemical relationship can be determined using methods such as NMR spectroscopy.

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0.070 moles of water are needed to produce 0.070 mol of oxygen.

To calculate the moles of water needed to produce 0.070 mol of oxygen, we should first determine the balanced equation for photosynthesis. The balanced equation is:-

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

From this equation, we can see that 6 moles of water are required to produce 6 moles of oxygen. Therefore, we can set up a proportion to find the moles of water needed for 0.070 mol of oxygen:-

(6 moles H₂O / 6 moles O₂) = (x moles H₂O / 0.070 moles O₂)

Now, we can solve for x:-

x moles H₂O = (6 moles H₂O / 6 moles O₂) * 0.070 moles O₂

x moles H₂O = (1) * 0.070 moles O₂

x moles H₂O = 0.070 moles

Therefore, 0.070 moles of water are needed to produce 0.070 mol of oxygen.

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The mass of oxygen that reacted with butane to give 2.2 kg of carbon dioxide and 1.125kg of water  is  5.2kg

A chemical equation is a symbol-and-formula-based symbolic representation of a chemical reaction, with the reactant entities supplied on the left and the product entities are given on the right.

Simply divide the substance's stated weight by its molar mass to get how many moles of any particular substance is present in the sample.

According to the given question,

Molar mass of CO₂ = 12+(16×2)

                               =44 g/ mol

Weight of CO₂ = 2.2 kg= 2200 g

Therefore,

The number of moles of CO₂ formed

= 2200/44= 50 moles

From the given chemical equation we can deduce that 8 moles of CO₂ is given by 13 moles of oxygen.

By using the unitary method of calculation,

8 moles of CO₂ given by 13 moles of O₂

50 moles of CO₂ given by = (13×50)/8

                                         = 81.25 moles

Similarly for H₂O,

Molar mass = 18 g/mol

Number of moles= 1125/18

                          = 62.5 moles

10 moles of H₂O given by 13 moles of O2

62.5 moles of  H₂O given by

= (13×62.5)/10

 = 81.25 moles

Therefore the total moles of Oxygen that reacted with butane is 162.5

Thus the mass of oxygen that reacted with butane is (162.5×32)= 5.2kg

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The percent by mass of acetic acid in the vinegar is 2.33%.

Below are the steps to solve the given problem using the data table given below:

Step 1: Calculate the mass of the vinegar. Given,Mass of flask and vinegar solution- 25.17gMass of flask- 15.12gMass of vinegar solution = Mass of flask and vinegar solution - Mass of flask= 25.17 g - 15.12 g= 10.05 g

Step 2: Calculate the moles of NaOH used in the titration.Molarity of NaOH solution is 0.1 M.Moles of NaOH = Molarity × Volume of NaOH usedMoles of NaOH = 0.1 M × 39.00 mL (since the initial volume of NaOH is 0.00 mL)Moles of NaOH = 0.0039 moles

Step 3: Determine the moles of acetic acid used in the reaction.The balanced chemical equation for the reaction between NaOH and acetic acid (the main component of vinegar) is given below:CH3COOH + NaOH → CH3COONa + H2OMoles of NaOH = Moles of CH3COOH (since they react in a 1:1 ratio)Moles of CH3COOH = 0.0039 moles

Step 4: Calculate the mass of acetic acid used in the reaction.Molar mass of acetic acid is 60.05 g/mol.Mass of CH3COOH = Moles of CH3COOH × Molar mass of CH3COOH= 0.0039 moles × 60.05 g/mol= 0.234 gStep 5: Calculate the percent by mass of acetic acid in the vinegar.Percent by mass of acetic acid = (Mass of CH3COOH / Mass of vinegar solution) × 100%= (0.234 g / 10.05 g) × 100%= 2.33%.

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Answer:

I cannot give you all the answer but I can help you to solve those.

Explanation:

The first question:

How many grams are there in 7.5×\(10^{23}\) molecules of \(H_{2} SO_{4}\)?

So we need to find the molecular mass first, use your periodic table,

And then we can find out 2+32+16×4=98 g/mol

Then, we need to find how many moles, by using Avogadro's constant:

Avogadro's constant: 1 mole = 6.02×\(10^{23}\)

∴\(\frac{7.5*10^{23} }{6.02*10^{23}}\)=1.25 mol(2d.p.)

Lastly, find the grams using the formula \(M= \frac{m}{n}\)

m=Mn

m=1.25*98

m=122.5g

-------------------------------------------------------------------------------------------------------------

In conclusion, use those formula to help you:

\(M= \frac{m}{n}\) (which M = molecular mass(atomic mass) m=mass of the substance and n = moles)

Avogadro's constant: \(\frac {molecular mass} {6.02*10^{23}} = moles\)

The cultures of prehistoric humans are primarily known through the excavation of stone tools and other durable artifacts, such as the Oldowan and Acheulian tool traditions.

Stone tools and imperishable artifacts serve as key archaeological evidence for understanding prehistoric cultures. Through meticulous excavation and analysis, archaeologists have been able to piece together the lifestyles, technological advancements, and social behaviors of early human societies. The term "paleolithic" refers to the Old Stone Age, a time when humans relied on stone tools as their primary implements.

The Oldowan tool tradition is considered the earliest stone tool industry, dating back around 2.6 million years ago. It is characterized by simple tools, such as choppers and scrapers, which were crafted by flaking off pieces from larger stones. These tools were primarily used for basic activities like butchering and processing animal carcasses.

Later, the Acheulian tool tradition emerged around 1.76 million years ago, representing an advancement in stone tool technology. Acheulian tools, such as handaxes and cleavers, were more refined and standardized, showcasing an increased level of sophistication in tool-making techniques. These tools served a wide range of purposes, including hunting, woodworking, and shaping raw materials.

By studying the Oldowan and Acheulian tool traditions, researchers gain valuable insights into the cognitive abilities, cultural development, and technological progress of early humans. The examination of these artifacts provides evidence of their adaptability, problem-solving skills, and the gradual refinement of their tool-making techniques over time.

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In the preceding equation, 6.67 moles of boric acid (\(H_3BO_3\)) will react to generate 10 moles of water (\(H_2O\)).

To determine the number of moles of boric acid that react in the equation to produce 10 moles of water, we need to examine the balanced chemical equation and use stoichiometry.

1. Begin by examining the balanced chemical equation for the reaction involving boric acid and water. Let's assume the equation is:

  \(3H_2O\) + \(3H_2O\) -> \(B_2O_3\) + \(6H_2O\)

2. From the balanced equation, we can see that 2 moles of boric acid (H3BO3) react with 3 moles of water (\(H_2O\)) to produce 6 moles of water (\(H_2O\)).

3. Use the given information that 10 moles of water (\(H_2O\)) are produced. Since the stoichiometric ratio between boric acid and water is 2:3, we can set up a proportion to find the number of moles of boric acid:

  2 moles \(H_3BO_3\) / 3 moles \(H_2O\) = x moles \(H_3BO_3\) / 10 moles \(H_2O\)

4. Cross-multiply and solve for x:

  (2 moles \(H_3BO_3\))(10 moles \(H_2O\)) = (3 moles \(H_2O\))(x moles \(H_3BO_3\))

  20 moles \(H_2O\) = 3x moles \(H_3BO_3\)

5. Divide both sides of the equation by 3 to isolate x:

  x moles \(H_3BO_3\) = (20 moles \(H_2O\)) / 3

6. Calculate the value of x:

  x moles \(H_3BO_3\) ≈ 6.67 moles \(H_3BO_3\)

Therefore, approximately 6.67 moles of boric acid (\(H_3BO_3\)) will react to produce 10 moles of water (\(H_2O\)) in the given equation.

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A first-order reaction is a chemical process in which the rate of the reaction is proportional to the concentration of the reactant. In other words, if the concentration doubles, so does the pace of the reaction. Like the decomposition reaction, a first-order reaction can include just one reactant or up to two.

Explanation :

To find out after how many seconds the concentration of the reactant in a first-order reaction will be halved, given the rate constant is 1.155x10^(-3) sec^(-1), we can use the first-order rate equation:

t(1/2) = ln(2) / k

where t(1/2) is the half-life of the reaction, ln(2) is the natural logarithm of 2, and k is the rate constant.

Step 1: Plug in the values.
t(1/2) = ln(2) / (1.155x10^(-3) sec^(-1))

Step 2: Calculate the natural logarithm of 2.
ln(2) ≈ 0.693

Step 3: Divide the natural logarithm of 2 by the rate constant.
t(1/2) ≈ 0.693 / (1.155x10^(-3) sec^(-1))

Step 4: Solve for t(1/2).
t(1/2) ≈ 599.65 seconds

After approximately 599.65 seconds, the concentration of the reactant in the first-order reaction will be halved.

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The concentration of the unknown KOH solution is approximately 0.0792 M.

To calculate the concentration of the unknown potassium hydroxide (KOH) solution, we can use the concept of stoichiometry and the balanced chemical equation of the reaction between KOH and H₂SO₄. The balanced equation is as follows:

2 KOH + H₂SO₄ → K₂SO₄ + 2 H₂O

From the balanced equation, we can see that two moles of KOH react with one mole of H₂SO₄ to form two moles of water. This means that the ratio of KOH to H₂SO₄ is 2:1.

Given:

Volume of KOH solution used = 25.22 mL

Volume of H₂SO₄ solution = 20.00 mL

Concentration of H₂SO₄ solution = 0.100 M (moles per liter)

First, we need to calculate the number of moles of H₂SO₄ used in the reaction. We can use the formula:

Moles = Concentration × Volume (in liters)

Moles of H₂SO₄ = 0.100 M × 0.02000 L = 0.002 moles

Since the stoichiometric ratio of KOH to H₂SO₄ is 2:1, the number of moles of KOH used in the reaction is also 0.002 moles.

Now, we can calculate the concentration of the KOH solution using the formula:

Concentration = Moles / Volume (in liters)

Concentration of KOH = 0.002 moles / 0.02522 L ≈ 0.0792 M

It's important to note that in titration calculations, we assume that the reaction between the two solutions is stoichiometric and complete. However, in reality, there might be some experimental errors or side reactions that can affect the accuracy of the calculated concentration. To improve accuracy, multiple titrations can be performed and the average value can be taken. Additionally, proper handling and measurement techniques should be employed to minimize errors and ensure accurate results.

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The de Broglie connection between both the momentum p or the wavelength of an electron (=h/p, h is Hubble constant) is used to calculate the wavelength of the an electron for a given power.

The following equation gives the kinetic energy of the an electron accelerated thru a voltage differential of V volts: where e is indeed the electron charge and 1/2 mv2 = eV (1.6x10-19 C) If you want to respond to this question, you'll need to know the electron charge as well as the Planck constant.

Yet, a speeding electron creates a shifting magnetic field, which in turn causes a changing electromagnetic current, which in turn causes a shifting magnetic field, etc. Or to put it another way, it produces an electromagnetic wave.

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Volume of Cl₂ = 9.34 L

Reaction

2NaI + Cl₂ ⇒ 2NaCl + I₂

mol NaI (MW=149,89 g/mol) :

\(\tt \dfrac{125}{149,89}=0.834\)

mol Cl₂ : mol NaI = 1 : 2

mol Cl₂ :

\(\tt \dfrac{1}{2}\times 0.834=0.417\)

Assumptions at STP(1 mol=22.4 L) :

\(\tt 0.417\times 22.4~L=9.34~L\)

            Precipitate definition (Entry 2 of 3) 1: a substance that has been physically or chemically isolated from a solution or suspension, typically in the form of an insoluble crystalline or amorphous solid. 2: a byproduct, outcome, or result of a procedure or action. adjective. precipitate.

Precipitation Illustration

        Silver chloride will solidify out of solution when silver nitrate and sodium chloride are combined in water. Silver chloride is the precipitate in this instance.

       Solids are created by the process of precipitation after two chemicals react. The downword () arrow symbol is used to represent the production of precipitate in this type of reaction.

      It happens between the reactant ions in the aqueous solutions that give rise to the material. Complete response: Precipitation includes the following: snow, sleet, hail, and rain.

       An excess of the light blue precipitate dissolves to create an inky transparent solution. A little amount of sodium hydroxide solution and subsequently an excessive amount are added to solution W. There develops an insoluble white precipitate.

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LDA (Lithium Diisopropylamide) is a better base than butyllithium for the deprotonation of a ketone because it is a more selective and less reactive base.

LDA's bulky structure reduces the chance of unwanted side reactions, such as nucleophilic attack on the carbonyl group.

This selectivity allows for the controlled formation of an enolate ion, which can participate in various organic reactions.

On the other hand, butyllithium is a strong and more reactive base that can lead to multiple unwanted reactions and less control over the deprotonation process. Thus, LDA is preferred for the deprotonation of ketones.

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Density of solution = 1.06 g/mL

Therefore, mass of 875 mL of solution = 875 * 1.06 = 927.5 g

Given mass of NaCl in the solution = 98.6 g

Therefore, the percentage by mass of the solution = (mass of NaCl / mass of solution) × 100= 98.6 / 927.5 × 100 = 10.63 % ≈ 10.6 %

Hence, option d is the correct answer.

An amount of 98.6 g of NaCl is dissolved in enough water to form 875 mL of solution. The mass of the solution is 927.5 g. The percentage by mass of the solution is 10.6 %. Therefore, the correct option is d.

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(a) The water bottle trail would wrap around the globe 15,993,256 times. (b)  the water bottle trail would wrap around the globe 19,991,570 times if the bottles were laid side-by-side.

(a) To find out how many times the water bottle trail would wrap around the globe if the bottles were laid end-to-end, we need to divide the circumference of the earth (in the same units as the bottle height) by the height of the bottle.

First, we need to convert the circumference of the Earth from miles to cm.

24,860 miles * 1.609 km/mile * 100 cm/m = 399,831,400 cm

Then, we divide the circumference of the earth by the height of the bottle:

399,831,400 cm / 25 cm/bottle = 15,993,256 bottles.

So, the water bottle trail would wrap around the globe 15,993,256 times.

(b) To find out how many times the water bottle trail would wrap around the globe if the bottles were laid side-by-side, we need to divide the circumference of the earth by the width of the bottle.

Let's assume that 5cm of the bottle space is covered when placed side by side

So the width of the bottle is 25cm-5cm = 20cm

we divide the circumference of the earth by the width of the bottle:

399,831,400 cm / 20 cm/bottle = 19,991,570 bottles.

So, the water bottle trail would wrap around the globe 19,991,570 times if the bottles were laid side-by-side.

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Question- The height of an Evian bottle is approximately 25 cm. If 31.2 x 109 empty water bottles were laid end-to-end around the equator, how many times would the water bottle trail wrap around the globe. The circumference of the earth at the equator is 24,860 miles (1 mile = 1.609 km).(b) How many times would the water bottle trail wrap around the globe if the Evian bottles were laid side-by-side. Assume that 5 cm of the bottle space is covered when placed side by side.

Answer:

B

Explanation:

Answer:

Hope this helps :D

Explanation:

Metal: Aluminum and Copper

Non-Metal: Hydrogen and Flourine

Acid: Sulfuric Acid and Phosphoric Acid

Alkali Metals: Hydrogen and Lithium

Compounds: Water and Carbon Dioxide

Elements: Carbon and Oxygen

We can calculate the mole ratio of acetic acid to water by dividing the number of moles of acetic acid by the number of moles of water, mole ratio of acetic acid to water = (Number of moles of acetic acid) / (Number of moles of water).

In order to determine the mole ratio of acetic acid (CH3COOH) to water (H2O) in vinegar, we first need to calculate the number of moles of acetic acid and water in 100 g of vinegar.                                                                                                                       Given that vinegar is 5% acetic acid and 95% water, we can calculate the masses of acetic acid and water in 100 g of vinegar: Mass of acetic acid = 5% of 100 g = 5 g.                                                                                                                                          Mass of water = 95% of 100 g = 95 g.                                                                                                                                                                Next, we'll calculate the number of moles for each component using their respective molar masses.                                                    Molar mass of acetic acid (CH3COOH) = 60.052 g/mol.                                                                                                                            Molar mass of water (H2O) = 18.015 g/mol.                                                                                                                                               Number of moles of acetic acid = mass of acetic acid / molar mass of acetic acid = 5 g / 60.052 g/mol.                                                Number of moles of water = mass of water / molar mass of water = 95 g / 18.015 g/mol.                                                                     Now, we can calculate the mole ratio of acetic acid to water by dividing the number of moles of acetic acid by the number of moles of water.                                                                                                                                                                             Therefore, mole ratio of acetic acid to water = (Number of moles of acetic acid) / (Number of moles of water).

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Answer:

56.64°c

Explanation:

its obtained from facts that heat gained by water=heat lost by calorimeter

Answer:

than what can i do lol

Answer:

i know right answer

Explanation:

let me explain

Answer:

Strength

Explanation:

Lattice energy is the energy needed to remove one mole of ionic substance to its gaseous ion.

The lattice energy is used to determine the strength of a substance.

Answer: Correct, the answer to the first question is Strength.

Explanation:

The answer to the second question is A, B, and D.

Edg:)

There are several illicit drugs that are produced in dangerous clandestine labs across the country. One notable example is methamphetamine, commonly known as meth.

The production of methamphetamine typically involves the synthesis of pseudoephedrine or ephedrine, which are found in certain over-the-counter medications. These precursor chemicals are then combined with a mixture of other toxic substances, such as solvents, acids, and reagents, in makeshift labs often located in residential areas or remote locations.

The clandestine production of methamphetamine poses significant risks not only to those involved in its manufacture but also to the surrounding communities. The process involves handling hazardous chemicals, which can lead to fires, explosions, and toxic fumes. The byproducts and waste generated during the manufacturing process are also highly toxic and pose environmental and health hazards.

Law enforcement agencies and regulatory bodies are actively involved in combating the production and distribution of illicit drugs like methamphetamine to protect public safety and health. It is important to note that the production, possession, and distribution of illicit drugs are illegal and carry severe legal consequences.

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