When it comes to our place in the solar system today, which model do we accept?

a) heliocentric
b) Ptolemaic
c) geocentric
d) Aristotelean

Answer:

0

Explanation:

Potential energy of the body is converted to kinectic enery as it falls thus the formula massx gravity x height at the instant it hits the ground the height is 0 putting this into the equation the potential energy is 0 since the potential energy is converted to kinectic energy potential energy is equal to kinectic energy then the kinectic energy at the instant it hits the ground is 0

As the ball falls, its potential energy starts to change into kinetic energy. When the ball hits the floor, its kinetic energy will be 200J.

A body's capacity for work is measured in terms of energy. It cannot be produced or eliminated. There are numerous types of energy, including thermal, electrical, fusion, electrical, and nuclear. Energy has the ability to change its forms.

Given parameters:

Potential energy of the ball when it is on a shelf, V = 200 J.

When the ball starts to fall, its potential energy due to gravity starts converting into kinetic energy. And as much the ball goes down, its kinetic energy will increase and potential energy will decrease.

At the instant the ball hits the floor, its potential energy due to gravity becomes zero and totally converted to kinetic energy.

Hence, the amount of kinetic energy the ball has at the instant it hits the floor is 200 J.

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The take-off speed of the plane as it accelerate from rest is 36.65 m/s.

Speed can be defined as the ratio of distance to time.

To calculate the the take-off speed of the plane, we use the formula below.

Formula:

Make v the subject of the equation

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the take off speed of the plane is 36.65 m/s.

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Answer:

      ΔU = - 9,179 10-11 J

Explanation:

For this exercise the two basketballs are linked by gravitational interaction, so we can use gravitational energy

               U = - G m₁m₂ / R

In this case the mass is equal and the initial distance is r₁ = 19 cm = 0.19 m

               U₁ = - G m² / r₁

let's calculate

              U₁ = - 6.67 10⁻¹¹ 0.55² / 0.19

              U₁ = - 10,619 10⁻¹¹ J

when its centers are separated it is at r₂ = 1.4 m

              U₂ = - 6.67 10⁻¹¹ 0.55² / 1.4

              U₂ = - 1.44 10-11 J

the energy between these two points is

          ΔU = U₂ - U₁

          ΔU = (-1.44 +10.619) 10-11

          ΔU = - 9,179 10-11 J

Answer:

The correct option is D

Explanation:

This question can be better understood when discussed using the Newton's first law of motion which states that an object would continue to move with a uniform speed (in a straight line) unless acted upon by an external force. What happens here (in the question) is that the bike rider would have continued moving at a constant speed (to the right) if not for the opposing force of the wind that acted against her (to the left). This wind/force would cause her speed to reduce or slow down (as posited by the law).

The soil loss in  \(Mg ha^{-1}\) (Ton/ha) if the bulk density of the soil is 1.01  \(Mg m^{-3}\)  is option a. 0.202 Mg/ha.

For expressing the soil loss in \(Mg ha^{-1}\), need to convert the units appropriately. First, convert the soil loss from millimetres (mm) to meters (m) by dividing it by 1,000 (1 mm = 0.001 m). Thus, the soil loss is 0.0002 m.

Next, calculate the volume of soil lost per unit area (ha). The volume can be obtained by multiplying the soil loss (0.0002 m) by the area (ha). Since the bulk density of the soil is given as 1.01 \(Mg m^{-3}\), can convert the volume to mass by multiplying it by the bulk density.

Using the formula:

Soil loss (Mg ha-1) = Soil loss (m) × Bulk density (\(Mg m^{-3}\)) × Area (ha)

Substituting the values:

Soil loss (\(Mg ha-1\)) = 0.0002 m × 1.01 \(Mg m^{-3}\) × 1 ha

Calculating the result:

Soil loss (\(Mg ha-1\)) = 0.0002 × 1.01 = 0.000202 \(Mg ha-1\)

Therefore, the correct answer is option a. 0.202 Mg/ha.

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Answer:

Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.

Answer:

Wegener was a German meteorologist, geophysicist and polar researcher. In 1915 he published 'The Origin of Continents and Oceans', which outlined his theory of Continental Drift. Wegener was a member of four expeditions to Greenland.

Explanation:

hope it helps

Alfred Wegner is a German weather scientist. His claim about the continental drift was that the continents were moving. He had 4 evidence to support his claim

Answer:

Xe

Explanation:

At low temperatures or high pressures, real gases deviate significantly from ideal gas behavior. It is also good to know that ideal gas law assumes that the gas molecules have negligible/no size.

Keeping that in mind, Xe is the largest of the bunch, and therefore is expected to have the greatest deviation of the ideal gas when under high pressure or low temperature.

Hope this helped

When a volleyball is tossed over a net, starting from a height of 1.5 meters above the ground, where  after reaching the top of its trajectory it returns to its original height as it falls, the ball's speed is the same as when it was tossed, but its velocity is different.

As ball 1 gets to the top of its trajectory, its velocity becomes zero.

since not stated otherwise, we assume that both balls have the same properties

If ball 2 is released at this instance, then they both will travel down at the same time interval and have initial velocity as zero.

since vertical travel is downwards, then acceleration due to gravity g is positive for both balls.

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Answer:

To solve this problem, we need to use the coefficient of thermal expansion for gasoline, which tells us how much the volume of gasoline will increase as its temperature increases. The coefficient of thermal expansion for gasoline is approximately 950 x 10^-6 /°C.

Using this information, we can calculate the increase in volume of gasoline as it warms up from 15°C to 35°C:

ΔV = V * α * ΔT

where V is the initial volume of gasoline (60 L), α is the coefficient of thermal expansion for gasoline (950 x 10^-6 /°C), and ΔT is the change in temperature (20°C).

ΔV = 60 * 950 x 10^-6 * 20

ΔV = 0.114 L

Therefore, the amount of gasoline spilled as it warms up from 15°C to 35°C is:

60 L - 0.114 L = 59.886 L

Explanation:

So the answer is (A) 50.2 litre.

Answer:

588 J

Explanation:

P.E = mgh

      = 6 * 9.8 * 10

     = 588 J

if g value is rounded and taken as 10 then answer is 600 J.

Answer:

"Faster" is most likely the answer, I'm not 100% sure though

Exaggerated feelings of self-importance are most closely linked with narcissism. Narcissism is a personality trait characterized by an inflated sense of self-worth, an excessive need for admiration, and a lack of empathy towards others.

Individuals with narcissistic traits often believe they are superior to others, crave attention and validation, and have a grandiose self-image.

They may engage in self-promotion, seek constant admiration, and exploit others for personal gain. Narcissism is associated with a sense of entitlement, a tendency to manipulate and exploit others, and a lack of empathy or concern for the well-being of others.

While a certain level of self-confidence and self-esteem is healthy, excessive narcissism can negatively impact relationships, lead to interpersonal conflicts, and hinder personal growth and development.

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Explanation:

The given data is as follows.

      Length (l) = 2.4 m

      Frequency (f) = 567 Hz

Formula to calculate the speed of a transverse wave is as follows.

                 f =

Putting the gicven values into the above formula as follows.

                 f =

                567 Hz =

                     v = 544.32 m/s

Thus, we can conclude that the speed (in m/s) of a transverse wave on this string is 544.32 m/s.

An electric-powered dipole positioned on the foundation exhibits radiation fields alongside its axis and is regular to the dipole. The radiation pattern follows a sinusoidal shape and shows most radiation alongside the axis and minimum radiation perpendicular to the dipole.

(a) Along the axis of the dipole, the electrical field E and magnetic area B can be decided using the ways-field approximation. The electric field is given via:

E = (\(k0\) * ℘0 * ω² * sinθ) / (4πε0 * r * c²)

in which \(k0\) is the vacuum wave range, ℘0 is the dipole second, ω is the angular frequency, θ is the attitude between the axis and the direction of the statement, ε0 is the permittivity of unfastened area, r is the space from the dipole, and c is the speed of mild.

The magnetic area is given through:

B = (\(k0\) * ℘0 * ω² * sinθ) / (4πr * c²)

(b) For the route regular to the dipole, the electric field and magnetic area can be determined as follows:

E = (\(k0\) * ℘zero * ω² * cosθ) / (4πε0 * r² * c²)

B = 0

In this example, the magnetic area is 0 because the field lines are parallel to the route of observation.

(c) The sketch of the radiation sample as a function of Θ could have a maximum value at Θ = 0 (alongside the axis of the dipole) and minimal values at Θ = ±90° (regular to the dipole).

The radiation sample will follow a sinusoidal shape, with the most and minimal values repeating periodically as Θ changes. The pattern can be symmetric with an appreciation of the axis of the dipole.

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Explanation:

Find a force is F=mv^2/r, so F=50*5^2/5 = 250N

True, it is possible for a fault to have a north-south (N-S) strike and an eastward dip.

Faults can have various orientations and dips depending on the tectonic forces and geological conditions in a particular region. The strike refers to the direction of the fault line on the Earth's surface, while the dip indicates the angle at which the fault plane is inclined from the horizontal. Therefore, a fault can have any combination of strike and dip, including an N-S strike and an eastward dip.

Faults are geological fractures where movement has occurred, and their orientations can vary. A fault with a north-south (N-S) strike means it extends in that direction horizontally. The dip refers to the angle of the fault plane from the horizontal. So, it is possible for a fault to have an N-S strike and an eastward dip.

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We know that

• The initial speed is 5.8 m/s.

• The time elapsed is 1.1 seconds.

• The final speed is zero because it will stop.

Let's find the acceleration. We have to use a formula that involves the initial speed, the time spent, the final speed, and acceleration.

Now we use the given magnitudes to solve for a.

(a) The magnitude of the chicken's acceleration is -5.3 m/s^2.

Now, to find how far the chicken slid, we have to use a formula that includes distance.

Let's use the magnitudes we know to find d.

(b) The chicken slid 3.2 meters.

As you can observe, the positive direction of the movement is towards the home plate. So, the acceleration is towards the third base because it's negative, that is, the chicken is slowing down to get to home plate.

Therefore, the direction of the acceleration is towards the third base.

The astronaut's weight on Earth is approximately 1177.2 Newtons.

To calculate the astronaut's weight on Earth, we need to use the formula:
Weight = Mass x Gravity
The mass of the astronaut is given as 120kg, and we know that the gravity on Earth is approximately 9.81 m/s^2. So, we can calculate the weight as follows:
Weight = 120kg x 9.81 m/s^2
Weight = 1177.2 N
It's important to note the difference between weight and mass. Mass refers to the amount of matter in an object, while weight is a measure of the force exerted on an object due to gravity. The mass of the astronaut remains constant on both the moon and Earth, but their weight changes due to the different gravitational pull of each celestial body. Answering this question required an understanding of both weight and mass, and the relationship between them.

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Answer:

The type of pressure that prevents a white dwarf from collapsing is the electron degeneracy pressure.

A white dwarf is a stellar remnant of a low or medium-mass star that has died, formed by a white dwarf supernova.

How does a white dwarf stay stable?

The white dwarf's stability is maintained by electron degeneracy pressure, which is the result of electrons being packed so tightly in the star's core that they are forced to behave like a gas, rather than a collection of individual particles.

The quantum mechanical Pauli exclusion principle governs the behavior of these electrons, which prohibits two fermions from occupying the same quantum state at the same time.

As a result, each electron is forced into a higher-energy state, resulting in a pressure that resists gravitational compression.

Therefore, the type of pressure that prevents a white dwarf from collapsing is the electron degeneracy pressure.

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Simple machines increase mechanical advantage.

Simple machines are devices that can make work easier by amplifying or changing the direction of the applied force. Mechanical advantage refers to the factor by which a simple machine multiplies the force applied to it. In other words, it is the ratio of the output force to the input force. By increasing the mechanical advantage, simple machines allow us to apply a smaller input force to achieve a larger output force, making it easier to perform tasks.

Simple machines do not increase the force itself; rather, they enhance the effectiveness of the force applied, making it more efficient. The mechanical advantage gained from using a simple machine enables us to overcome resistance or move objects with less effort.

Therefore, simple machines increase mechanical advantage, which allows us to achieve greater output force compared to the input force.

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Answer:

B: Pure Substance

Explanation:

Answer:

Moonlight; phases; eight; 29 days; sunlit; earth; sun; moon.

Explanation:

A moon generally do not have or possess light but rather it reflects the light from the sun.

The moon is lit by light bouncing off of it. That light reaches Earth as moonlight. The different shapes that the moon appears to have are called phases. The moon goes through eight (8) phases as it revolves around the earth every 29 days. The phase that we see depends on how much of the sunlit part of the moon we can see. This depends on the positions of the earth, sun, and moon.

The eight (8) phases of the moon include the following;

1. Last quarter half moon.

2. Waning crescent moon.

3. New moon.

4. Waxing crescent moon.

5. First quarter half moon.

6. Waxing Gibbous moon.

7. Full moon.

8. Waning Gibbous moon.

(A)The principle of wave propagation and resonance is used.(B)The equation used for the fundamental frequency of a closed tube is: f = (v/2L) × n. (C) For the lowest  frequencies (n = 1, 2, 3), we can calculate the frequencies using the formula: f₁ = (v/2L) × 1. Important that  the values of these frequencies may vary depending on the exact length and characteristics of the ear canal.

These frequencies may vary depending on the exact length and characteristics of the ear canal.

A) The physics concepts and equation being used in this question are related to standing waves in a closed tube. The equation used is the formula for the fundamental frequency of a closed tube, which is derived from the principles of wave propagation and resonance.

B) The equation used for the fundamental frequency of a closed tube is:

f = (v/2L) × n,

where f is the frequency, v is the speed of sound, L is the length of the tube, and n is the harmonic number.

C) Plugging in the numbers:

Given:

Length of the ear canal (L) = 2.7 cm = 0.027 m

Speed of sound (v) = 343 m/s

For the lowest three frequencies (n = 1, 2, 3), we can calculate the frequencies using the formula:

f₁ = (v/2L) × 1,

f₂ = (v/2L) × 2,

f₃ = (v/2L) × 3.

D) Unit check and explanation:

Let's check the units:

The units of the speed of sound (v) are m/s.

The units of the length (L) are meters (m).

The units of frequency (f) are cycles per second or Hertz (Hz).

Plugging in the numbers and evaluating the expressions, we can find the values of the lowest three frequencies:

f₁ = (343 m/s / 2 × 0.027 m) × 1,

f₂ = (343 m/s / 2 × 0.027 m) × 2,

f₃ = (343 m/s / 2 × 0.027 m) × 3.

By calculating these expressions, we will obtain the numerical values of the lowest three frequencies of the standing waves in the ear canal.

It is important to note that the values of these frequencies may vary depending on the exact length and characteristics of the ear canal.

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Answer:

0.96  N

Explanation:

Explanation:

Using Equations of Motion :

(1) v = u + at

24 = 6.5 + a * 210

a (Acceleration) = 0.083 m/s^2

(2) v^2 = u^2 + 2aS

S = 576 - 42.25 / 0.166

S (Distance travelled) = 3215.3 m

(Option A seems a typo since the answer is 3215.3 m)

Answer:

002 bc eause iy is

Answer:

512.5 mJ

Explanation:

Let the two identical charges be q = +35 µC and distance between them be r₁ = 46 cm. A charge q' = +0.50 µC located mid-point between them is at r₂ = 46 cm/2 = 23 cm = 0.23 m.

The electric potential at this point due to the two charges q is thus

V = kq/r₂ + kq/r₂

= 2kq/r₂

= 2 × 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C/0.23 m

= 630/0.23  × 10³ V

= 2739.13 × 10³ V

= 2.739 MV

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

So, the new electric potential at this point is

V' = kq/r₃ + kq/r₄

= kq(1/r₃ + 1/r₄)

= 9 × 10⁹ Nm²/C² × 35 × 10⁻⁶ C(1/0.35 m + 1/0.11 m)

= 315 × 10³(2.857 + 9.091) V

= 315 × 10³ (11.948) V

= 3763.62 × 10³ V

= 3.764 MV

Now, the work done in moving the charge q' to the point 12 cm from either charge is

W = q'(V' - V)

= 0.5 × 10⁻⁶ C(3.764 MV - 2.739 MV)

= 0.5 × 10⁻⁶ C(1.025 × 10⁶) V

= 0.5125 J

= 512.5 mJ

Work done will be:  \(512.5 \mu J\).

Given:

q = +35 µC

q' = +0.50 µC

r₁ = 46 cm

r₂ = 46 cm/2 = 23 cm = 0.23 m

The electric potential at this point due to the two charges q is thus

\(V = \frac{kq}{r_2}+\frac{kq}{r_2}\\\\ V= \frac{2kq}{r_2}\\\\V= \frac{2 * 9 * 10^9Nm^2/C^2 * 35 * 10^{-6} C}{0.23 m}\\\\V= \frac{630}{0.23*10^3}V\\\\V= 2739.13 * 10^3 V\\\\V= 2.739 \mu V\)

When the charge q' is moved 12 cm closer to either of the two charges, its distance from each charge is now;

r₃ = r₂ + 12 cm = 23 cm + 12 = 35 cm = 0.35 m and

r₄ = r₂ - 12 cm = 23 cm - 12 cm = 11 cm = 0.11 cm.

Thus, the new electric potential at this point is

\(V' = \frac{kq}{r_3} + \frac{kq}{r_4}\\\\V= kq(\frac{1}{r_3}+\frac{1}{r_4})\\\\V= 9 * 10^9 Nm^2/C^2 * 35 * 10^{-6} C (\frac{1}{0.35m}+\frac{1}{0.11m})\\\\V= 315 * 10^3(2.857 + 9.091) V\\\\V= 315 * 10^3 (11.948) V\\\\V= 3763.62 * 10^3 V\\\\V= 3.764 \mu V\)

Now, the work done in moving the charge q' to the point 12 cm from either charge is:

\(W = q'(V' - V)\\\\W= 0.5 * 10^{-6} C(3.764 MV - 2.739 MV)\\\\W= 0.5 *10^{-6} C(1.025 * 10^6) V\\\\W= 0.5125 J\\\\W= 512.5 \mu J\)

Thus, the work done will be: \(512.5 \mu J\).

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Answer: Kinetic energy is the energy an object has because of its motion

(if it needs to be a one worded answer than just type motion)

The potential energy of an object depends on its mass and its height.

The law of conservation of energy states that energy can be neither created nor destroyed, but it can change its form.

Answer:Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work.

As expressed by the equation, potential energy depends upon the mass and the height of the object. Any increase in these two quantities will lead to an increase in the amount of potential energy possessed by the object.

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside.