When dolphin swims close to its prey, it transmits sound waves to figure out details (like direction where the fish is moving) of its prey. Now, if the frequency of the reflected waves has increased, would the dolphin catch up its prey or fall behind? Explain your answer.

The pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

To determine the speed of the pendulum when it passes through the lowest point of its swing, we can use the principle of conservation of mechanical energy.

At the highest point (2.9 cm above the resting position), the pendulum has gravitational potential energy. As it swings down, this potential energy is converted into kinetic energy, given by the equation:

Potential Energy (PE) = Kinetic Energy (KE)

The highest point's potential energy is given by:

PE = mgh

Where:

m = pendulum mass (4.0 kg).

g = acceleration due to gravity (9.8 m/s^2)

h = height above the resting position (2.9 cm = 0.029 m)

Substituting the values, we have:

PE = 4.0 kg * 9.8 m/s^2 * 0.029 m = 1.1356 J

Since energy is conserved, this potential energy will be completely converted into kinetic energy at the lowest point. Thus, the kinetic energy is also 1.1356 J:

KE = 1.1356 J

The following equation gives the kinetic energy:

KE = (1/2)mv^2

Where:

m = pendulum mass (4.0 kg).

v = velocity of the pendulum at the lowest point

Rearranging the equation to solve for v:

v^2 = (2KE) / m

v^2 = (2 * 1.1356 J) / 4.0 kg

v^2 = 0.5678 m^2/s^2

Taking the square root of both sides results in the following:

v ≈ 0.754 m/s

Therefore, the pendulum will be moving at approximately 0.754 m/s when it passes through the lowest point of its swing.

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Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

Answer: 140.625

Explanation: Because energy gained due to damped motion and needs to be absorbed

Answer:

For 1, it's 784

For 2, it's 10,000

For 3, it's 178,000

Explanation:

I have taken the K12 quiz :)

Happy Spooky Month Everyone!! Stay safe!

(1) The Gravitational Potential Energy of the ball is 784 J.

(2) The Kinetic Energy of the dog is 10,000 J.

(3) The total Mechanical Energy of the Skydiver is 78,000 J.

(1)

The Gravitational Potential Energy of the ball is the energy possessed by the ball due to its height above the ground.

P.E = mgh

P.E = 8 x 9.8 x 10

P.E = 784 J

(2)

The Kinetic Energy of the dog is possessed by the dog due to its motion.

K.E = ¹/₂mv²

K.E = 0.5 x 50 x 20²

K.E = 10,000 J

(3)

The total Mechanical Energy of the Skydiver is the sum of the potential energy and the kinetic energy.

M.A = P.E + K.E

M.A = 78,000 J  +  100,000 J

M.A = 178,000 J

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Answer:

3q

Explanation:

The strength of the electric field is 1.10×10^4 N/C.

The data is sent to us.

r = d/2 = 0.1/2 = 0.05 m, d = 10 cm = 0.1 m, and z = 17 cm = 0.17 m

Q = 40 nC = 40×10^-9 C

A) in the middle of the two circles

Since the electric fields created by the two rings are directed in opposite directions, there is no electric strength.

B) midway down the left ring

Electric strength is equal to the sum of the electric fields created by the left and right rings.

Electric strength is equal to E leftring + E rightring, which equals 0 plus kQz/(r2 + z2).

Electric strength = k×Q×z/(r^2 + z^2)^

Electric strength = 9×10^9×40×10^-9×0.17/(0.05^2 + 0.17^2)

Electric strength= 1.10×10^4 N/C

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The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The best way of presenting the information on density graphically would be to use a D, bar graph.

A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.

A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.

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Two natural sources of light: the sun and the stars

Two artificial sources of light: light bulb and torches

Answer:

Natural lights: Sunlight, Moonlight, or Lightning

Artificial: Light bulb, Candles, or a lighter/matches

Explanation:

Answer:

Explanation:

70.0(5.00)(9.81) = 3,433.5 = 3430 N

To solve this we must be knowing each and every concept related to  centripetal force and its calculations. Therefore, the centripetal force acting on her is 3430 N.

The term centripetal relates to a propensity to gravitate toward the center. Centripetal refers to moving in the direction of the center. The force that maintains an item moving in a circular direction and helps it stay on the path is referred to as centripetal force.

Furthermore, centrifugal force is indeed the tendency of things to deviate from a circular route and fly in a straight line. People frequently confuse centripetal force with centrifugal force.

Mathematically,

F = m a

  = 70 acceleration

  = 70 × 5 × 9.81

 = 3430 N

Therefore, the centripetal force acting on her is 3430 N.

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The equation to obtain the final speed of car is,

Substitute the known values,

The negative sign of acceleration indicates that the car is deaccelerating.

The force required to stop the car is,

Substitute the magnitude of known values,

Thus, the force required to stop the car is 4970 N.

Answer:

The frequency of light can be calculated using the formula:

`c = λv`

Where `c` is the speed of light in a vacuum, `λ` is the wavelength of light, and `v` is the frequency of light.

The speed of light in a vacuum is `3.00 × 10^8 m/s`.

To convert the wavelength from nanometers to meters, we need to divide by `1 × 10^9`.

Thus, the frequency of light with a wavelength of 655 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(655 × 10^-9 m)`

`v = 4.58 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`.

Similarly, the frequency of light with a wavelength of 515 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(515 × 10^-9 m)`

`v = 5.83 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz`.

Finally, the frequency of light with a wavelength of 475 nm is:

`v = c/λ`

`v = (3.00 × 10^8 m/s)/(475 × 10^-9 m)`

`v = 6.32 × 10^14 Hz`

Therefore, the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

So, the frequency of light with a wavelength of 655 nm is `4.58 × 10^14 Hz`, the frequency of light with a wavelength of 515 nm is `5.83 × 10^14 Hz` and the frequency of light with a wavelength of 475 nm is `6.32 × 10^14 Hz`.

Answer:

Explanation:

A) The output force required to lift a 15 kg object would be equal to the weight of the object, which is given by:

Output force = Weight of object = m * g

where m is the mass of the object and g is the acceleration due to gravity. Assuming that g is equal to 9.81 m/s^2, we have:

Output force = 15 kg * 9.81 m/s^2 = 147.15 N

Therefore, the output force required to lift a 15 kg object would be 147.15 N.

B) In this case, the input force is the force that you are pushing down with the lever, which is given as 20 N.

C) The mechanical advantage of the ramp is given by the ratio of the output force to the input force. In this case, the output force is the weight of the object (40 N) and the input force is the force that you are pushing with (10 N). Therefore, the mechanical advantage of the ramp would be:

Mechanical advantage = Output force / Input force = 40 N / 10 N = 4

So, the ramp multiplies your force by a factor of 4.

Note that in all of these calculations, we have assumed that the system is ideal and that there are no losses due to friction or other factors. In practice, these losses will reduce the mechanical advantage of the system and make it more difficult to lift or move objects.

Disaster recovery and cooperation are both benefited by cloud storage. It makes file sharing simple and guarantees that data is backed up and retrievable in the event of loss or damage.

Your documents and data are kept in a safe data centre off-site by a cloud provider. You are no longer required to update software, maintain the servers, or make sure the hardware is working properly.

To store data, including files, business data, videos, or photographs, cloud storage uses remote servers. Users use an internet connection to upload data to servers, where it is stored on a virtual machine on a physical server.

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The magnitude of the average force exerted by the floor on the ball during the collision is 215 N, and the direction is upward.

What is Potential Energy?

Potential energy is the energy that an object possesses due to its position or configuration relative to other objects, or due to the configuration of its internal components. It is a form of energy that is associated with the forces that act on an object, such as gravity, electric forces, and magnetic forces.

(a) To determine the impulse delivered to the ball by the floor, we can use the principle of conservation of energy to relate the ball's potential energy at the initial height to its potential energy at the rebound height, taking into account the loss of energy due to the collision with the floor. We can then use the impulse-momentum theorem to relate the impulse to the change in momentum of the ball during the collision.

The initial potential energy of the ball is given by:

PEi = mgh = (0.215 kg)(9.81 m/s^2)(19.5 m) = 41.6 J

At the rebound height, the potential energy is:

PEf = mgh = (0.215 kg)(9.81 m/s^2)(15.0 m) = 31.7 J

The loss of energy due to the collision is:

ΔPE = PEi - PEf = 9.9 J

This energy loss is due to both the work done by the force of gravity during the downward motion and the work done by the force of the floor during the upward motion. However, since the ball rebounds to a height that is less than its initial height, we know that the impulse delivered by the floor must be in the downward direction, opposite to the direction of the ball's motion during the collision.

Using the impulse-momentum theorem, we can write:

J = Δp = mΔv

where J is the impulse delivered by the floor, Δp is the change in momentum of the ball during the collision, and Δv is the change in velocity of the ball during the collision. Since the ball is moving downward before the collision and upward after the collision, we can write:

Δv = vf - vi = (15.0 m/s) - (-15.0 m/s) = 30.0 m/s

where vi is the initial velocity of the ball (before the collision) and vf is the final velocity of the ball (after the collision).

Thus, the impulse delivered to the ball by the floor is:

J = mΔv = (0.215 kg)(30.0 m/s) = 6.45 kg · m/s (downward)

So, the magnitude of the impulse delivered to the ball by the floor is 6.45 kg · m/s, and the direction is downward.

(b) To determine the average force exerted by the floor on the ball during the collision, we can use the definition of impulse as the product of force and time, and the fact that the ball is in contact with the floor for a known amount of time.

We know that the ball is in contact with the floor for 0.0300 seconds. Therefore, the average force exerted by the floor on the ball during the collision is:

Favg = J / Δt

where Δt is the time interval during which the impulse is delivered. In this case, Δt is equal to the contact time, which is 0.0300 seconds.

Thus, the average force exerted by the floor on the ball is:

Favg = J / Δt = (6.45 kg · m/s) / (0.0300 s) = 215 N (upward)

So, the magnitude of the average force exerted by the floor on the ball during the collision is 215 N, and the direction is upward.

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After reaching a certain velocity and the belt continues to move at the constant velocity(to the right).

Let's select the correct free body diagram for the box.

When the belt was at rest and the belt was placed, the horizontal velocity was zero.

When the belt started moving with some acceleration, the force of friction will try moving the box to the opposite direction.

But in this case, the belt has attained a certain velocity which makes it to start moving at a constant velocity. At constant velocity acceleration iz zero.

Since it is moving at a constant velocity, the net force is zero since there is no acceleration.

Therefore, there will be no acceleration, there is zero net force.

The free body diagram will be:

Therefore, the correct free body diagram is option b.

ANSWER:

B.

Answer:

С . Molecules are made up of two or more  atoms.

Explanation:

The relationship between molecules and atoms is that molecules are made up of two or more atoms.

Molecules are made up of atoms.

A molecule is the smallest particle of a substance element or compound capable of independent existence.

A molecule could be monoatomic, diatomic or polyatomic.

Monoatomic molecules are made up of one atom

Diatomic are made up of two different atoms

Polyatomic substances are made up of more than two kinds of atoms.

The coefficient of friction between the two blocks is 0.194.

The problem involves finding the coefficient of friction between two blocks of equal mass attached by a string that moves over a sloped ramp with an angle of 30 degrees. The blocks start from rest and are allowed to move freely. The distance traveled by the blocks is 0.50 m, and the time taken to travel this distance is 0.935 s. To solve the problem, we need to consider the forces acting on the system of blocks. The forces acting on the blocks are the gravitational force, the tension in the string, and the frictional force. As the blocks are moving up the ramp, the force of gravity is pulling them down. The tension in the string is pulling the blocks up the ramp. The frictional force is opposing the motion of the blocks and is acting in the opposite direction to the tension in the string.

To determine the coefficient of friction, we can use the equations of motion to find the acceleration of the blocks. Once we have the acceleration, we can use Newton's Second Law to find the net force acting on the blocks. We can then use the force of friction to find the coefficient of friction. Using the equations of motion, we can find the acceleration of the blocks:

a = 2d/t^2

where d is the distance traveled by the blocks and t is the time taken to travel the distance. Plugging in the given values, we get:

a = 2(0.50 m)/(0.935 s)^2 = 1.15 m/s^2

Next, we can use Newton's Second Law to find the net force acting on the blocks:

ΣF = ma

where ΣF is the sum of the forces acting on the blocks. Plugging in the known forces, we get:

T - mg sin θ - μmg cos θ = ma

where T is the tension in the string, m is the mass of the blocks, g is the acceleration due to gravity, θ is the angle of the ramp, and μ is the coefficient of friction.

We can simplify this equation by substituting mg sin θ for the component of the weight of the blocks that is acting down the ramp and mg cos θ for the component of the weight that is acting perpendicular to the ramp:

T - mg sin θ - μmg cos θ = ma

T - mg(1/2) - μmg(√3/2) = ma

We can also use the equation for the tension in the string:

T = 2mg sin θ

Substituting this into the equation for net force, we get:

2mg sin θ - mg(1/2) - μmg(√3/2) = ma

Simplifying and solving for μ, we get:

μ = (2gsinθ - a)/(2gcosθ)

Substituting the given values, we get:

μ = (2(9.81 m/s^2)sin 30° - 1.15 m/s^2)/(2(9.81 m/s^2)cos 30°) = 0.194

Therefore, the coefficient of friction between the two blocks is 0.194.

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Answer:70 watts

Explanation: I took the test and got it correct

Mountain is the land feature is marked on the map as x.

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Answer:

sorry but I don't know what exactly I'm supposed to calculate.you never actually stated it

Answer: if weight affects how fast they go?

Explanation:

Answer:

How can we change the speed of a toy car on a racetrack to describe the car’s motion?

Explanation:

thats the sample respond

The dependent, independent, and controlled variables​ are as follows:

1. Dependent - The effect of lime urea table salt and compost on the soil

2. Independent - The soil on which the elements are incorporated.

3. Controlled variable - The height of the plants.

The dependent variable is that which is tested in the experiment and in this experiment, Chandani is testing the effect of lime, urea, table salt, and compost on the soil.

The independent variable is the altered element in the experiment and for this experiment, this is the soil that receives different additives. Finally, the controlled variable is that which remains constant and that is the height of each plant that the researcher checks.

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Treating the box as a particle, there are two forces acting on it in opposite directions: the box's weight mg pulling it downward and the resistive force of the air pointing upward.

The box is falling at a constant speed, so by Newton's second law we have

mg - r = 0

where mg = (75.0 kg) (9.80 m/s²) = 735 N is the weight of the box and r is the magnitude of air resistance. So we have

r = mg = 735 N

We can find the components as:

Answer:

false

Explanation:

Answer:

false

Explanation:

edge

The student's path traces out a rectangle and she ends up at the same spot, so her displacement is 0 m.

On the other hand, she travels a total distance equal to the perimeter of that rectangle,

4.0 m + 8.0 m + 4.0 m + 8.0 m = 24 m

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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Answer:

Explanation:

Your body weighs more at the pole for two important reasons. Both have to do to the spin of the earth on its axis.

Because of its spin the earth is thicker around the equator than it is through the poles. This means that when you stand on the equator, you are farther away from the center of earth than you would be at the poles. As gravity decreases with the inverse of the square of distance, gravity will be weaker at the equator.

As you are also spinning with the earth, you will have a required centripetal acceleration and force to keep you attached to the ground, This force decreases the effect of gravity so again, you would weigh less at the equator.

Answer:

TRUE

Explanation:

Answer:

True

Explanation: