When converted to a household measurement, 9 kilograms is approximately equal to a

Answers

Answer 1

Answer:

D) 19.8 lbs

Explanation:

1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.

1kg is also equal to 2.205 lbs. 9*2.205=19.8416

9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system

a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.

This leaves us with 19.8 lbs


Related Questions

A sample of an unknown material appears to weigh 300N in air and 200N when immersed in alcohol of density 700kg/m^3 . What is the volume and density of the material

Answers

Answer:

the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.

Explanation:

To solve the problem, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

Let's first find the weight of the unknown material in air:

W_air = 300 N

Next, let's find the weight of the unknown material in alcohol:

W_alcohol = 200 N

We can find the buoyant force acting on the material by subtracting the weight in alcohol from the weight in air:

F_buoyant = W_air - W_alcohol = 300 N - 200 N = 100 N

According to Archimedes' principle, this buoyant force is equal to the weight of the alcohol displaced by the material:

F_buoyant = ρ_alcohol * V * g

where ρ_alcohol is the density of the alcohol, V is the volume of the material, and g is the acceleration due to gravity.

Substituting the values we know:

100 N = 700 kg/m^3 * V * 9.81 m/s^2

Solving for V:

V = 0.0145 m^3

Finally, we can find the density of the material by dividing its weight in air by its volume:

ρ_material = W_air / V = 300 N / 0.0145 m^3 = 20690.3 kg/m^3

Therefore, the volume of the material is 0.0145 m^3 and its density is 20690.3 kg/m^3.

Identify the energy levels from which the 410.2 nm emission line of the Balmer series of the
hydrogen atom originates, i.e., state the values of ninitial and nfinal. What is the frequency of the
radiation involved in the transition between these levels?

Answers

The energy level from which is emitted is n = 6

The frequency is\(7.3 * 10^14\) Hz

What is the energy level?

The Rydberg equation is a mathematical formula that relates the wavelengths of light emitted by an atom to the energy levels of its electrons.

Using the Rydberg equation;

1/λ= RH (1/\(n_{2}^2\) - 1/\(n_{1} ^2\))

1/\(410.2 * 10^-9\) = \(1.097 * 10^7\)(1/\(2^2\) - 1/  /\(n_{1} ^2\))

1/\(4.102 * 10^-7\) = \(1.097 * 10^7\)(1/4 - 1/\(n_{1} ^2\))

1/\(4.102 * 10^-7\) * 1/ \(1.097 * 10^7\) = (1/4 - 1/\(n_{1} ^2\))

0.22 = 0.25 -  1/\(n_{1} ^2\)

0.22 - 0.25 = -  1/\(n_{1} ^2\)

-0.03 = -  1//\(n_{1} ^2\)

\(n_{1}\) = 6

Using;

f = c/λ

\(3 * 10^8/4.102 * 10^-7 \\f = 7.3 * 10^14 Hz\)

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The SST’s initial operating temperature was 5.5 K. At what wavelength (in micrometers) does the telescope’s own blackbody emission peak? How does this wavelength compare with the wavelength range in which the telescope is designed to operate?

Answers

We can calculate the wavelength of the peak as follows:

λmax = 2.898 x 10^-3 μm K / 5.5 K = 0.526 μm

So, the wavelength of the peak is 0.526 μm.

What type of wavelength is this?

The above wavelength is in the far-infrared range, which is different from the wavelength range in which the SST is designed to operate. The SST operates in the submillimeter range, which is significantly longer than the wavelength of the blackbody emission peak.

How does this wavelength compare with the wavelength range in which the telescope is prepared to work?

The wavelength of the blackbody emission peak does not compare favourably with the wavelength range in which the telescope is designed to operate. The telescope must be cooled to reduce its blackbody emission to operate effectively in the submillimeter range.

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Substitute the value 26.7 (or the exact value of 80/3) for x in the first of the original equation (x + y = 40) to find the value of y. Once you have found the value of y using the first of the original equation, you can substitute this value of y and the value of x (26.7) into the second of the original equation (0.75x + 1.5y = 40) to check your work. If the values that you find on the two sides of the equal sign are not equal, then you must recheck your work.

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

the value of  \(y = 13.3\)

Explanation:

From the question we are told that

       The equation is  (x + y = 40)

        The first value of x is  \(x_1 = 26.7\)

        The second equation is  (0.75x + 1.5y = 40)

So  substituting \(x_1\)

     \(26.7 + y = 40\)

=>   \(y = 13.3\)

Now substituting y and  \(x_1\) into second equation

       \(0.75(26.7) + (1.5* 13.3) = 40\)

 =>  \(40 = 40\)

So  \(y = 13.3\)

         

Substitute the value 26.7 (or the exact value of 80/3) for x in the first of the original equation (x

Equipotential Surfaces: A region of space contains a uniform electric field directed in the positive x direction as shown. Among the following the correct statements about the electric potential is: Select one: VYYc b. V₁ V₂ Ve d. We can't judge ​

Equipotential Surfaces: A region of space contains a uniform electric field directed in the positive

Answers

The true statement about the electric potential for the equipotential surface is  \(V_A = V_B = V_C\)

What is equipotential surface?

A surface with an equipotential potential is one where all points on the surface have the same electric potential. .

That is an equipotential surface is that surface at every point of which, the electric potential is the same.

The formula for the potential across every point on the surface is given as;

V = F/Q x R

V = ER

where;

E is the electric field across the surfaceR is the distance or position of the charge

Since the surface is equipotential with uniform electric across the surface, the electric potential at any point across the surface will be the same.

So \(V_A = V_B = V_C\)

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A 74.0-kg man stands on a bathroom scale inside an elevator.(a) The elevator accelerates upward from rest at a rate of 1.10 m/s2 for t1 seconds. What does the scale read during this time interval

Answers

Answer:

806.6 N

Explanation:

Given that :

Mass (m) = 74 kg

Acceleration due to gravity (g) = 9.8 m/s²

Acceleration during interval t1 = 1.10 m/s²

Using the relation :

Normal reaction = Mass (g + acceleration at interval t1)

Normal reaction = 74(9.8 + 1.10)

Normal reaction = 74(10.9)

Normal reaction = 806.6 N

a certain amount of work is required to push a heavy crate 2m across the floor. How much work is required to push the same crate 8m across the floor.

Answers

Answer:

Explanation:

If the velocity during motion is constant, moving the crate four times as far will require four times the work

W = Fd

4W = F(4d)

Determine the radius of the round strut so that the round and square struts have the same cross-sectional area and compute the critical load of each strut. Use E = 200 GPa.

Answers

The radius of strut so that the round and struts have same cross-sectional area = 2.764 mm and the critical load of a strut =  3.95*\(10^{-3}\).

Let Radius for a round strut = 'r'

Now, Square Strut:

As, method Cross Section is 24 X 1 (\(mm^{2}\))

So, Area, A' of cross-section = 24*1 = 24 \(m^{2}\)

>> As, Area of round cross-section, A = pi*\(r^{2}\)

Now, Given that, Both have same cross-section area

=> pi*\(r^{2}\)  = 24

Solving,

=> r = radius of round cross-section = 2.764 mm

>> Now, According to Buckling Criteria,

Critical Load for a Stru, Pcr = (pi*\(r^{2}\)*E*I)/Le\(q^{2}\)

>> Now, as both Struts or columns are simple supported at both ends

So, Leq = L = 1 m

Also, E = 200 GPa = 200*\(10^{9}\) N/m2

Now, I = Moment of Inertia

As, For Round Strut,

I = pi*\(r^{4}\)/4 = pi*2.7644/4 = 45.837 = 45.837*\(10^{-12}\)

=> Pcr = pi*\(r^{2}\)*200*109*45.837*10-12/12

Solving,

=> Pcr = 0.0905 kN  (CRITICAL LOAD FOR ROUND)

>> Now, For Strut,

As, Buckling places about axis with minimum Moment of Inertia

So, Imin = a*\(b^{3}\)/12 = 24*1*1*1/12 = 2   = 2*  \(10^{-12}\)

So, Putting every values in Critical Equation:

Pcr = p\(i^{2}\)*200*\(10^{-9}\)*2*\(10^{-12}\)/12

=> Pcr = 3.95*\(10^{-3}\) kN (REQUIRED CRITICAL LOAD STRUT)

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Question 24 1 pts Find the voltage in an extension cord having a 0.0600 22 resistance and through which a 5.00A current is flowing: 500 V 30V O5V O 126V O 60V​

Answers

The voltage in the extension cord is 30 V.

The problem above can be solved using ohm's law

⇒ Formula:

V = IR.................. Equation 1

⇒ Where:

V = Voltage in the extension cordI = Current flowing through the extension cordR = Resistance of the extension cord.

From the question, I think there was a slight error in the value of the current given it suppose to be 500 A, and not 5.00 A

⇒ Given:

I = 500 AR = 0.06 ohms

⇒ Substitute these values into equation 1

V = 500(0.06)V = 30 V

Hence the voltage in the extension cord is 30 V

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Sounds are vibrations transmitted through the air or another medium. There are three
physical characteristics of a sound, each giving rise to a perceptual characteristic of
the sound. For example, one of these physical characteristics is frequency, which
gives rise to pitch perception. Define and describe all three characteristics of the
sound stimulus and the perceptions to which they give rise. Detail how each physical
characteristic relates to the associated perception.

Answers

Answer:

Explanation:

The three physical characteristics of a sound stimulus and their corresponding perceptual characteristics are as follows:

1. Frequency: Frequency refers to the number of vibrations or cycles per second that occur in a sound wave. It is measured in hertz (Hz). Frequency gives rise to the perception of pitch. Pitch is the subjective perception of how high or low a sound is. Higher frequencies are perceived as higher pitches, while lower frequencies are perceived as lower pitches. For example, a sound wave with a higher frequency would be perceived as a higher-pitched sound, like a whistle, whereas a sound wave with a lower frequency would be perceived as a lower-pitched sound, like a deep bass note.

2. Amplitude: Amplitude is the magnitude or intensity of a sound wave and is usually measured in decibels (dB). It represents the amount of energy carried by the sound wave. Amplitude gives rise to the perception of loudness. Loudness is the subjective perception of the strength or intensity of a sound. Greater amplitudes are perceived as louder sounds, while smaller amplitudes are perceived as quieter sounds. For instance, a sound wave with a higher amplitude would be perceived as a louder sound, like a thunderclap, whereas a sound wave with a lower amplitude would be perceived as a softer sound, like a whisper.

3. Timbre: Timbre refers to the quality or tone color of a sound. It is the characteristic that allows us to distinguish between sounds with the same pitch and loudness. Timbre is influenced by the complex combination of different frequencies, amplitudes, and waveforms present in a sound wave. It gives rise to the perception of the unique "sound signature" of an instrument or voice. For example, a guitar and a piano playing the same note at the same loudness would still sound different due to their distinct timbres. Timbre enables us to identify and differentiate between various musical instruments and voices.

In summary, frequency determines the pitch perception of a sound, amplitude influences the perception of loudness, and timbre defines the unique quality or tone color of a sound. These physical characteristics directly relate to the corresponding perceptual characteristics, providing us with a rich and diverse soundscape in our auditory experience.

The planet Mars approached closest at a distance of 15.3 * 10 ^ 7 km from the earth on May 30, 2016. If the mass of the earth and mass of the Mars are 6×10^24 kg and 6×10^23 kg respectively, what will be the gravitational force between these two planets.​

The planet Mars approached closest at a distance of 15.3 * 10 ^ 7 km from the earth on May 30, 2016.

Answers

The gravitational force between Earth and Mars can be calculated using the formula:

F = G * ((M1 * M2) / d^2)

where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N m^2 / kg^2), M1 and M2 are the masses of the two planets, and d is the distance between their centers.

Plugging in the values, we get:

F = (6.67 x 10^-11 N m^2 / kg^2) * ((6×10^24 kg) * (6×10^23 kg)) / (15.3 x 10^7 m)^2

Solving this equation gives us the gravitational force between Earth and Mars as 2.7 x 10^22 N.

So, the gravitational force between Earth and Mars on May 30, 2016 was approximately 2.7 x 10^22 Newtons.

The gravitational force between Earth and Mars is approximately 2.3 x \(10^{17}\) Newtons.

The gravitational force between two objects can be calculated using the formula:

F = (G * m1 * m2) / \(r^{2}\)

Where F is the gravitational force, G is the gravitational constant (approximately 6.67 x \(10^{-11}\) N.\(m^{2}\)/\(Kg^{2}\)), m1 and m2 are the masses of the two objects, and r is the distance between their centers.

In this case, the mass of Earth (m1) is 6 x \(10^{24}\) kg, the mass of Mars (m2) is 6 x \(10^{23}\) kg, and the distance between them (r) is 15.3 x \(10^{7}\) km or 15.3 x \(10^{10}\) m.

Plugging these values into the formula, we have:

F = (6.67 x \(10^{-11}\)N.\(m^{2}\)/\(kg^{2}\)) * (6 x \(10^{24}\) kg) * (6 x \(10^{23}\) kg) / (15.3 x \(10^{10}\) m)^2

Simplifying the equation, we get:

F ≈ 2.3 x \(10^{17}\) N

Therefore, the gravitational force between Earth and Mars is approximately 2.3 x \(10^{17}\) Newtons. This force represents the attraction between the two planets due to gravity.

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A point object moves from point A to point B along a circular path with a radius. What is the size of the angle ?

Answers

The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

How to solve size of an angle?

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

plz help I will mark as brainlest plz help me

(c) One lorry travels from your town to another town. The lorry reaches a top speed of 90 km/h, but its average speed between the towns is only 66 km/h.

(ii) The journey between the towns takes 20 minutes. Calculate the distance between the towns.​

Answers

Please make me brainliest also the answer is b
Using the average speed between the towns:

D
S* T = equation triangle

Average Speed: 66km/h
Time taken: 20minutes

20 minutes into hours = 0.33…

Distance=Speed*Time
D=S*T
x=66*0.33=

22km

Hope this helps! :)

As rotational speed increases, thrust____?

increases exponentially.

increases at the same rate.

decreases exponentially.

decreases at the same rate

Answers

Increases exponentially is your correct answer

Match the elements with the number of neutrons. (4 points)
1.
88 38 Sr
2.
39 19 Ka
3.
14 6 Carbon
4.
234 90 Thorium plus 4 2 Helium
a.
20
b.
50
c.
8
d.
74

Answers

The following elements are matched with their number of neutrons

1. 88 38 Sr - b. 50

2. 39 19 Ka - a. 20

3. 14 6 Carbon - c. 8

4. 234 90 Thorium plus 4 2 Helium - d. 74

To determine the number of neutrons for each element, we need to subtract the atomic number (which represents the number of protons) from the mass number (which represents the total number of protons and neutrons).

1. 88 38 Sr:

The atomic number of strontium (Sr) is 38, which means it has 38 protons. The mass number is 88. Subtracting the atomic number from the mass number: 88 - 38 = 50. Therefore, the number of neutrons in strontium is 50.

2. 39 19 Ka:

The atomic number of potassium (K) is 19, indicating 19 protons. The mass number is 39. Subtracting the atomic number from the mass number: 39 - 19 = 20. Hence, the number of neutrons in potassium is 20.

3. 14 6 Carbon:

The atomic number of carbon (C) is 6, representing 6 protons. The mass number is 14. Subtracting the atomic number from the mass number: 14 - 6 = 8. Thus, the number of neutrons in carbon is 8.

4. 234 90 Thorium plus 4 2 Helium:

The atomic number of thorium (Th) is 90, which means it has 90 protons. The mass number is 234. Subtracting the atomic number from the mass number: 234 - 90 = 144. However, there is also an additional helium (He) isotope mentioned with a mass number of 4 and atomic number of 2. Adding the number of neutrons from thorium and helium: 144 + 2 = 146. Hence, the number of neutrons in thorium plus helium is 146.

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What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?

Answers

The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².

What is the moment of inertia?

This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².

From the question:

Mass,M =4.2kg

Radius, R=32Cm

The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:

moment of inertia, I =1/2MR²

I =\(\frac{1}{2}\) * 4.2 * 32²

  =2,150.4 kgm²

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A bus is moving at a speed of 20 m/s, when it begins to slow at a constant rate of 5 m/s2 in order to stop at a bus stop. If it comes to rest at the bus stop, how far away was the bus from the stop?

Answers

Answer:

u=20m/sec

v=0

a=5m/sec^2

v^2=u^2-2as[ here acceleration is negative]

0=400-2x5xs

-400= -10s

s= 40 metre.

The bus stop is 40 m away from the point at which it starts to slow down at -5 m/s².

State third equation of motion?

The third equation of motion is -

v² - u² = 2aS

Given is a bus moving at a speed of 20 m/s. It begins to slow at a constant rate of 5 m/s² in order to stop at a bus stop.

We can write -

[u] = 20 m/s

[a] = - 5 m/s²

[v] = 0 m/s

Using the third equation of motion -

v² - u² = 2aS

- (20)² = 2 x - 5 x S

- 400 = - 10 S

S = 400/10

S = 40 m

Therefore, the bus stop is 40 m away from the point at which it starts to slow down at -5 m/s²

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A person standing on a scale feels a normal force of 655 N pushing up on him. What is his mass?

Answers

i’m pretty sure the answer would be 66.79141 kilogram force

Answer: 66.8 kilograms

Taigas, tundra and tropical rainforests share what common abiotic component?

Answers

Answer:

water

Explanation:

hope this helps

Taigas, tundra and tropical rainforests share what common abiotic component?

The total capacitance of two 15uF capacitors
connected in parallel is

Answers

The total capacitance of two 15uF capacitors  connected in parallel is 30 μF .

The total capacitance of two 15  microfarads capacitors connected in parallel is 30 microfarads.

Given:

The two capacitors of 15 microfarads each in a parallel combination.

To find:

The total capacitance

Solution:

The capacitance of one capacitor = \(C_1= 15 \mu F\)

The capacitance of another capacitor =\(C_2= 15 \mu F\)

The total capacitance in parallel combination is given by:

\(C_T=C-1+C_2\\\\=15 \mu F+15 \mu F= 30 \mu F\)

The total capacitance of two 15uF capacitors connected in parallel is 30 microfarads.

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F=3i+2j+4k N and D= 2i-3j+5k m what will be workdone ?

Answers

Answer:

The work done is 20 Joules (J).

Explanation:

To calculate the work done, we can use the formula:

Work = Force dot Displacement

Given the force vector F = 3i + 2j + 4k N and the displacement vector D = 2i - 3j + 5k m, we can calculate the dot product between these vectors.

The dot product of two vectors A and B is given by:

A dot B = (Ax * Bx) + (Ay * By) + (Az * Bz)

Calculating the dot product between F and D:

F dot D = (3 * 2) + (2 * -3) + (4 * 5)

      = 6 - 6 + 20

      = 20

A cylinder of gas is at room temperature (20°C). The air conditioner breaks down, and the temperature rises
to 46°C. What is the new pressure of the gas relative to its initial pressure (Pi)?

Answers

Answer: we divide this equation by pV and use {C}_{p}={C}_{V}+ . ... The temperature, pressure, and volume of the resulting gas-air mixture

Explanation:

The new pressure of the gas relative to its initial pressure P₁ is P₁ × 1.09

From the question given above, the following data were obtained:

Initial temperature (T₁) = 20 °C = 20 + 273 = 293 K

Initial pressure (P₁) = P₁

New temperature (T₂) = 46 °C = 46 + 273 = 319 K

New pressure (P₂) =?

The new pressure of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

P₁ / 293 = P₂ / 319

Cross multiply

293 × P₂ = P₁ × 319

Divide both side by 293

P₂ = (P₁ × 319) / 293

P₂ = P₁ × 1.09

Thus, the new pressure relative to it's initial pressure is P₁ × 1.09

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4. A hot air balloon of mass 250.00 kg at a height of 150.0 m descends slowly into a field. What is the
GPE of the balloon before the descent, in kilojoules?

Answers

The GPE (Gravitational potential energy) of the balloon of mass 250 kg is 367500 J.

What is Gravitational Potential Energy (GPE)?

To calculate the GPE of the balloon, we use the formula below.

Formula:

GPE = mgh........... Equation 1

Where:

m = Mass of the balloong = acceleration due to gravityh = HeightGPE = Gravitational potential energy.

From the question,

Given:

m = 250 kgh = 150 mg = 9.8 m/s²

Substitute these values into equation 1

GPE = 250×150×9.8GPE = 367500 J

Hence, the GPE of the balloon is 367500 J.

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How smart is Albert Einstein?​

Answers

Albert Einstein was one of the greatest physicists of all time and is widely considered a genius. He made groundbreaking contributions to our understanding of the universe, including the theory of relativity and the famous equation E=mc².

Einstein's intelligence can be seen in his early academic achievements. He excelled in math and physics, and by the age of 16, he was already doing advanced physics research on his own. He went on to earn a PhD and made significant contributions to physics, publishing numerous papers and developing revolutionary theories.

Moreover, his ability to think creatively and critically is evidenced by his approach to problem-solving. He was known for his thought experiments, which allowed him to explore complex concepts and theories without the need for expensive equipment or experiments. He was also skilled at developing intuitive and elegant solutions to complex problems.

Therefore Einstein's intelligence is widely recognized and respected by scientists, scholars, and the general public alike. He is considered one of the most brilliant minds in history and has made a lasting impact on our understanding of the universe.

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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)

Answers

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Suppose a 3000 cm3 container holds 7.0 g of nitrogen gas at a pressure of 200 kPa. The gas can be heated at constant pressure if a piston moves outward to let the gas expand as it's heated. Alternatively, the gas can be heated at constant volume if the piston is locked in place to prevent expansion. How does the heat required for one of these processes compare to the heat required for the other process?

1. What is the starting temperature of the gas?
2. With the piston locked in place, the gas is heated until the pressure doubles. What is the final temperature?

Answers

1) The starting temperature of the gas is 288 K

b) When the pressure is doubled, the temperature is 576 K

What is the temperature?

We know that we have to use the ideal gas equation so as to be able to obtain the temperature of the starting of the gas and we know that;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Number of moles = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Then we have;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

If the pressure doubles and we have;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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Un autocar que circula a 81 km/h frena uniformemente con una aceleración de -4,5 m/s2.


a) Determina cuántos metros recorre hasta detenerse.


b) Representa las gráficas v-t y s-t.

Answers

Answer:

a) \(\Delta x=56.25 m\)

b) imagen adjunta

Explanation:

a) Primero debemos hacer la conversión de 81 km/h a m/s, esto es 22.5 m/s.

Ahora, usando la ecuacion cinemática, en un movimiento acelerado tenemos:

\(v_{f}^{2}=v_{0}^{2}+2a \Delta x \)

Queremos encontrar la posición hasta detenerse, osea vf = 0.

\(\Delta x=\frac{-v_{0}^{2}}{2a}\)

\(\Delta x=\frac{-22.5^{2}}{-2*4.5}\)

\(\Delta x=56.25 m\)

b) Para este caso el gráfico se encuentra adjunto.                                      

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A siren emits a sound at 1700 Hz. Assume a speed of sound of 332 m/s. What frequency would a stationary observer hear if the car with the siren is travelling at:A. 25 m/s towards the observerB. 25 m/s away from the observerC. 140 km/h towards the observer

Answers

F source = 1700 HZ

v= source

S sound =332 m/s

Doppler equation:

F listener = F source ( speed of sound / speed of sound - v source)

A) v source 25 m/s

F = 1700 hz ( 332 m/s / 332m/s - 25m/s) = 1,838 HZ

B) v = - 25 m/s

F = 1700 hz ( 332 m/s / 332m/s + 25m/s) = 1581 HZ

C) 140 km/h = 39 m/s

F = 1700 hz ( 332 m/s / 332m/s - 39m/s) = 1,926 HZ

A cup of coffee with a lid is enclosed in an insulated cup 0.5cm thick in the shape of a cube 7.3cm on a side. The thermal conductivity is 0.02w/m the temperature of the coffee is 90 and the temperature of the surrounding is 22

Answers

\(\begin{align}Q &= \frac{kA\Delta T}{d} \ &= \frac{(0.02)(0.0315)(90 - 22)}{0.005} \ &= 237.6\ \text{W}\end{align}\)

This is the rate of heat transfer through the insulated cup. Note that this assumes that the heat transfer is steady and one-dimensional, which may not be strictly accurate in reality.

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Jose was out drinking with his friends for nearly the whole night. The next morning he was confused and vomiting, and had a low body temperature.

Answers

Answer:

He has a hangover.

Explanation:

Just something I know.

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