When converted to a household measurement, 9 kilograms is approximately equal to a

This paragraph can provide more details and clarify why option C is the correct answer.  When a ball bearing moves in a circular path, it experiences a force called centripetal force that acts towards the center of the circle.

This force is responsible for keeping the object in a curved path instead of moving in a straight line. The centripetal force acts perpendicular to the velocity vector at any given point on the circular path. As a result, the direction of motion of the ball bearing constantly changes, but the speed remains constant. In the first paragraph, we can explain the concept of centripetal force and its effect on the motion of the ball bearing. We can mention that the centripetal force acts towards the center of the circle, causing the ball bearing to move in a circular path. This paragraph can be shorter since it only introduces the basic idea. In the second paragraph, we can expand on the explanation and emphasize that the speed of the ball bearing remains constant. We can mention that even though the direction of motion changes, the magnitude of the velocity remains the same. This paragraph can provide more details and clarify why option C is the correct answer.

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Answer:

D: keeping voltage constant and increasing resistance.

Explanation:

The current in an electrical circuit is determined by Ohm's law, which states that the current is directly proportional to the voltage and inversely proportional to the resistance.

Mathematically, Ohm's law can be expressed as:

I = V/R

where I is the current, V is the voltage, and R is the resistance.

We need to make sure that the right-hand side of the equation remains constant to keep the current in the circuit the same. Therefore, we can look at each set of changes and see how they affect the right-hand side of the equation.

A. Decreasing voltage and keeping resistance constant:

B. Increasing voltage and increasing resistance:

C. Increasing voltage and keeping resistance constant:

D. Keeping voltage constant and increasing resistance:

So, the correct answer is D: keeping voltage constant and increasing resistance.

The weight of the Mars Rover Curiosity on Earth and on Mars is 8820 N and 3330 N respectively.

The weight of an object is given by the product of its mass and the gravitational field strength at its location.

On Earth:

On Mars:

Therefore, the weight of the Mars Rover Curiosity on Earth and on Mars are 8820 N and 3330 N respectively.

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Answer: 2134

Explanation:

I just had this question on my exam

Answer:

F = 1071.08 N

Explanation:

Given that,

The radius of the circular track, r = 3.23 m

Speed of the car, v = 3.72 m/s

The mass of the car, m = 250 kg

We need to find the net force acting on it. The centripetal force will act on it and it is given by the relation as follows :

\(F=\dfrac{mv^2}{r}\\\\F=\dfrac{250\times (3.72)^2}{3.23}\\\\F=1071.08\ N\)

So, the net force acting on the car is 1071.08 N.

Given data,

Distance, d = 240 m

Time in seconds, t = 0.2 seconds

Formula to calculate the velocity.

Substitute the given values in the above formula.

The Title of the interviews Questionnaire is : Community Members' Right to Safe and Healthy Living Questionnaire. The Questionnaire is attached.

A tool for research known as a questionnaire comprises a series of questions formulated to extract data from individuals or a collective of individuals. A systematic approach in acquiring data, which permits researchers to obtain uniform feedback and perspectives from respondents, is termed as structured data collection.

Questionnaires have multiple applications such as conducting surveys, holding interviews, performing assessments, and carrying out evaluations.

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The change in momentum of the object will be 20 kg m/s

change in momentum = final momentum - initial momentum

                                     = mass* velocity (final) - mass* velocity (initial)

                                     = m ( v (final)  - v (initial) )

                                     = 1 ( 10 - ( -10 ))

                                     = 20 kg m/s

The change in momentum of the object will be 20 kg m/s

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Explanation:

simple machine can multiplayer of speed and force

Answer:

ur mom

Explanation:

ur mom

Answer:

0.03

Explanation:

The distance of the blackboard from the student's eyes is approximately 1.7208 meters.

To determine the distance of the blackboard from the student's eyes, we can use the thin lens equation:

1/f = 1/di + 1/do

where f is the focal length of the lens, di is the image distance (the distance between the lens and the image of the blackboard on the retina), and do is the object distance (the distance between the lens and the blackboard).

We can first find the image distance using the formula:

1/f = 1/di + 1/do

where f is the refractive power of the lens in diopters, and di is the distance between the lens and the image on the retina in meters.

Thus, we have:

1/f = 1/di + 1/do

1/57.5 = 1/1.75 + 1/di

Solving for di, we get:

di = 0.0292 meters

Now, to find the object distance, we can subtract the image distance from the distance between the lens and the retina:

do = 1.75 - di

do = 1.7208 meters

The distance of the blackboard from the student's eyes is approximately 1.7208 meters.

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Answer:

B. 8,437.5 J

Explanation:

Given the following data;

Height = 400m

Mass = 75kg

Velocity = 15m/s

Time = 10 secs

To find the kinetic energy of the skier?

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

Substituting into the equation, we have;

\( K.E = \frac{1}{2}*75*15^{2}\)

\( K.E = 37.5*225\)

K.E = 8,437.5 Joules.

Answer:

Explanation:

The only thing that decreases the gravitational pull between 2 objects is if you increase the distance.

The formula is F = G*m*m/r^2

As r^2 gets larger and G and m1 and m2 remain the same, F has to get smaller because r^2 divides into G*m1*m2

Answer:

F = 160.0 N

Explanation:

Given: Soccer payer with a mass = 80 kg, force = 20 N

To find: force

Formula: \(F=ma\)

Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

F = m × a

F = 20 kg - 10 = 2  

F = 80 × 2 = 160

F = 160.0 N

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

The acceleration of a 50 g object pushed with a force of 0.5 N is 10 m/s².

To find the acceleration of the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:

F = m * a

Given:

Force (F) = 0.5 N

Mass (m) = 50 g = 0.05 kg

Substituting the given values into the equation, we have:

0.5 N = 0.05 kg * a

To find the acceleration (a), we rearrange the equation:

a = F / m

a = 0.5 N / 0.05 kg

a = 10 N/kg

Since acceleration is measured in meters per second squared (m/s²), we convert the unit of N/kg to m/s²:

1 N/kg = 1 m/s²

Therefore, the acceleration of the 50 g object pushed with a force of 0.5 N is 10 m/s².

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Answer:

Explanation:

force = f, mass = m, acceleration = a

f = m a

m = 200 kg

f = 800 N

f = m a

800 = 200a

a = 800 / 200

a = 4

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Answer:

F = M v^2 / R = M w^2 R      where w represents the angular frequency

Only 1 / R causes a reduction in centripetal force when increased

(B)   is the answer

Option B. The radius of curvature causes a reduction in centripetal force with an increase in the magnitude.

Centripetal force is a force that acts on the object that moves in a circular motion and is directed towards the center of the circular moving path. The mathematical representation of centripetal force is -

Where Fc = the centripetal force,

m = mass of the object,

v = velocity

and r = radius.

From the given explanation above, The centripetal force and radius of curvature are inversely proportional to each other,

that is, Fc = 1/r.

Therefore, an increase in the radius of curvature leads to a reduction in the centripetal force.

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The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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Answer:

36111 kg

Explanation:

Given

Force = 65000N

Acceleration = 1.8m/s²

Required

Determine the mass of the elevator

This question will be answered using the following Force formula.

Force = Mass * Acceleration

Substitute values for Force and Acceleration

65000N = Mass * 1.8m/s²

Make Mass the subject

Mass = 65000N/1.8m/s²

Mass = 36111.11 kg

From the list of given options, option E answers the question.

Answer:206.3

Explanation:

The quantity of heat energy that must be transferred to 2.25 kg of brass to raise its temperature from 20 °C to 240 °C is 195030 J

First, we shall list out the given parameters from the question. This is shown below:

The quantity of heat energy that must be transferred can be obtained as follow:

Q = MCΔT

= 2.25 × 394 × 220

= 195030 J

Thus, we can conclude quantity of heat energy that must be transferred is 195030 J

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Answer:

6

Explanation:

just add

A representative element is an element whose properties can be used to discuss the chemistry of the group into which the element falls.

A representative element is an element whose properties can be used to discuss the chemistry of the group into which the element falls. Now we will try to answer each of the questions.

1) The atoms of arsenic and nitrogen have five valence electrons

2) The statement that correctly describes the two representative elements are in the same period of the periodic table is that they belong to the same period and have the same number of shells.

3) Helium is different from the other members of group 18 because it has 2 and not eight valence electrons

4) The element that has  atoms with valence electrons in a higher energy level than those of calcium (Ca) is barium

5) The statements that best describes the arrangement of electrons in fluorine is that the the electronic configuration is [He] 2s2 2p5.

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The correct answer isThe astronaut's b) mass remains the same.

The mass of an object remains constant regardless of its position or distance from the center of the Earth. Mass is a measure of the amount of matter in an object and is an intrinsic property. It does not change with the position or location of the object.

On the other hand, the weight of an object can vary depending on its distance from the center of the Earth. Weight is the force experienced by an object due to gravity and is dependent on the mass of the object and the gravitational acceleration at its location.

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As an astronaunt travels from the surface of the earth to a postion that is four times

as far away from the center of the earth, the astronaut's

a) mass decreases

b)

mass remains the same

c) weight increases

d) weight remains the same

The reactive force when a fish swims through water is the force of the water on the fish. This is an example of Newton’s third law of motion which states that for every action, there is an equal and opposite reaction. The active force is the fish pushing against the water, so the reactive force would be the reverse, the equal force of the water pushing back on the fish.

Answer:

\(v = u + at \\ 25 = 12 + a6 \\ 13 = 6a \\ a = 2.16 \\ \)

a=2.16ms^-2

Answer:

a) maximum mass of the Mars lander to ensure it can land safely is 200 kg

b) area of the parachute required is 480 m² which is larger than 400 m²

c) area of the parachute should be 12.68 m²

Explanation:

Given the data in the question;

V = 20 m/s

A = 200 m²

drag co-efficient CD = 1.855

g = 3.71 m/s²

density of the atmospheric pressure β = 0.01 kg/m³

a. Calculate the maximum mass of the Mars lander to ensure it can land safely?

Drag force FD = 1/2 × CD × β × A × V²

we substitute

FD = 1/2 × 1.855 × 0.01 kg/m × 200 m² × ( 20 m/s )²

FD = 742 N

we know that;

FD = Fg

Fg = gravity force

Fg = mg

so

FD = mg

m = FD/g

we substitute

m = 742 N / 3.71 m/s²

m = 200 kg

Therefore, the maximum mass of the Mars lander to ensure it can land safely is 200 kg

b. The mission designers consider a larger lander with a mass of 480 kg. Show that the parachute required would be larger than 400 m²;

Given that;

M = 480 kg

Show that the parachute required would be larger than 400 m²

we know that;

FD = Fg = Mg = 480 kg × 3.71 m/s²

FD = 1780.8 N

Now, FD = 1/2 × CD × β × A × V², we solve for A

A = FD / 0.5 × CD × β × V²

we substitute

A = 1780.8  / 0.5 × 1.855 × 0.1 × (20)²

A = 1780.8 / 3.71

A = 480 m²

Therefore, area of the parachute required 480 m² which is larger than 400 m²

c. To test the lander before launching it to Mars, it is tested on Earth where g = 9.8 m/s^2 and the atmospheric density is 1.0 kg m-3. How big should the parachute be for the terminal speed to be 20 m/s, if the mass of the lander is 480 kg?

Given that;

g = 9.8 m/s²,

β" = 1 kg/m³

v" = 20 m/s

M" = 480 kg

we know that;

FD = Fg = M"g

FD = 480 kg × 9.8 m/s² = 4704 N

from the expression; FD = 1/2 × CD × β × A × V²

A = FD / 0.5 × CD × β" × V"²

we substitute

A = 4704 / 0.5 × 1.855 × 1 × (20)²

A = 4704 / 371

A = 12.68 m²

Therefore area of the parachute should be 12.68 m²