When comparing the successive ionization energies of an element, an unusually big increase in ionization energy is seen when the core electrons of the element are removed. In general, the ionization energy of an element rises as you remove electrons from it.
Each time you remove an electron, the atom becomes increasingly more positively charged, and the remaining electrons become more firmly bound to the nucleus. As a result, it takes more energy to remove each successive electron. The first ionization energy is always the lowest.
It takes the least amount of energy to remove the outermost electron, which is also the least tightly bound to the nucleus. The second ionization energy is the energy required to remove the second electron from a neutral atom that has already had one electron removed.
The second ionization energy is always higher than the first because removing an electron from a positively charged ion requires more energy than removing one from a neutral atom.
There is an unexpectedly high increase in ionization energy when the core electrons of an element are removed, causing an unusually big increase in ionization energy.
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air with a density of 10 g/m^3 is 100% saturated at 12 c. at what temperature will it reach its dew point?
The dew point is the temperature at which air becomes saturated and water vapor starts to condense.
Assuming a constant pressure, the dew point temperature of the air can be found using the formula:
dew point temperature = (237.7 * ln(RH/100) + (17.27 * T)/(237.7 + T))
where RH is the relative humidity and T is the temperature in degrees Celsius. Since the air is 100% saturated, RH = 100. Plugging in the given values, we get:
dew point temperature = (237.7 * ln(1) + (17.27 * 12)/(237.7 + 12))
Solving this equation, we get the dew point temperature to be approximately 12°C. This means that at a temperature of 12°C, the air will become fully saturated and reach its dew point, causing water vapor to condense into liquid droplets.
The dew point is the temperature at which air becomes saturated and water vapor starts to condense. To find the dew point temperature, we consider that the air's density is 10 g/m^3 and it's 100% saturated at 12°C. In this case, we need to find the temperature at which the air's relative humidity reaches 100%. Using the Clausius-Clapeyron equation or psychrometric charts, one can determine the dew point temperature based on the given conditions. Unfortunately, without knowing the air's actual water vapor content, we cannot provide an exact dew point temperature.
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during photosynthesis, the cell forms c6h12o6 (glucose) and o2 (oxygen gas) by combining co2 (carbon dioxide) and h2o (water). classify the molecules as reactants or products in the chemical reaction.
Reactants: CO₂ (carbon dioxide) and H₂O (water)
Products: C₆H₁₂O₆ (glucose) and O₂ (oxygen gas)
In the chemical reaction of photosynthesis, carbon dioxide (CO₂) and water (H₂O) are the reactants. These are the substances that undergo a chemical change and are consumed during the reaction. They are necessary for the production of glucose (C₆H₁₂O₆) and oxygen gas (O₂), which are the products of photosynthesis. The reactants, CO₂ and H₂O, are converted into glucose and oxygen through the process of photosynthesis, which occurs in the chloroplasts of plant cells.
Glucose serves as an energy source for the cell and is used in various metabolic processes, while oxygen is released as a byproduct and plays a crucial role in supporting respiration in organisms that consume it. The classification of the molecules as reactants and products helps to understand the flow and transformation of matter during photosynthesis.
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Why is it necessary to maintain excess bromine in the reaction mixture with trans-cinnamic acid and bromine
Answer:
It is necessary because Trans-cinnamic is a limiting reagent in the mixture reaction while Bromine is the excess reagent
Explanation:
It is necessary to maintain excess bromine in the reaction mixture because Bromine is the excess reagent in the reaction mixture and if it's quantity is less it would consume the limiting reagent ( Trans-cinnamic ) completely . hence Bromine should maintain excess quantity in the reaction mixture
A sample of hydrogen gas has a volume of 145 mL when measured at 44
degrees C and 1.47 atm. What volume would the hydrogen sample occupy
at STP?
Answer:
\(186.01\ \text{mL}\)
Explanation:
\(P_1\) = Initial pressure = 1.47 atm
\(P_2\) = Final pressure = \(10^5\ \text{Pa}\)
\(T_1\) = Initial temperature = \(44^{\circ}\text{C}\)
\(T_2\) = Final temperature = \(273.15\ \text{K}\)
\(V_1\) = Initial volume = 145 mL
\(V_2\) = Final volume
We have the relation
\(\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow V_2=\dfrac{P_1V_1T_2}{T_1P_2}\\\Rightarrow V_2=\dfrac{1.47\times 101325\times 145\times 273.15}{(44+273.15)\times 10^5}\\\Rightarrow V_2=186.01\ \text{mL}\)
Final volume of the sample is \(186.01\ \text{mL}\).
biography of the person who discovered o2
Answer:
Oxygen was discovered independently by two chemists in the late 18th century: Carl Wilhelm Scheele and Joseph Priestley.
Carl Wilhelm Scheele was a Swedish chemist who is credited with the discovery of several elements, including oxygen, chlorine, and molybdenum. He was born on December 9, 1742, in Stralsund, Sweden, and showed an early interest in chemistry. In the 1770s, he made several important discoveries related to oxygen, including the fact that it is a gas and that it is necessary for combustion. However, he did not publish his findings until after Priestley had published his own work on oxygen. Scheele died on May 21, 1786, at the age of 43.
Joseph Priestley was an English scientist, philosopher, and theologian who is best known for his discovery of oxygen. He was born on March 13, 1733, in Birstall, England, and studied theology and science at the University of Leeds. In the 1770s, he conducted a series of experiments in which he isolated and described oxygen. He published his findings in 1774, in a book called "Experiments and Observations on Different Kinds of Air." Priestley's work on oxygen helped to lay the foundations for modern chemistry and the understanding of combustion and respiration. He died on February 6, 1804, at the age of 70.
When ions are tightly surrounded by solvent molecules they are said to be _____.
When ions are tightly attached to solvent molecules they are called as solvated ions.
When separation occurs, the solute is divided into ions or molecules, and every ion or molecule is surrounded by a solvent. The bonding between the solute particles and solvent molecules is called solvation. A solvated ion or molecule is surrounded by solvent molecules. For example, when we add NaCl to water, the NaCl molecules split into Na⁺ and Cl⁻ ions. These ions of sodium and chlorine then get surrounded by water molecules. We can call the ion water mixture a solution and the surrounded ions of sodium and chlorine as solvated ions.
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Write each chemical bond or elements of the chemical formula:2Mg + O2 -> 2MgO As a Lewis dot structure (while still in the formatting of the chemical formula).
1) Chemical formula
\(2Mg+O_2\rightarrow2MgO\)2) Mg Lewis structure
3) O2 Lewis structure
4) MgO Lewis structure
5) Chemical formula written as Lewis dot structure
.
Convert the following Kelvin temperatures to degree Celsius.
631 K=
Answer:
358 \( {}^{o} c\)
Answer:
the correct answer to the question is i 358°C
name this compound
please helppp thank you!!!
Answer:
Sodium sulfide is the chemical compound with the formula Na 2 S, or more commonly its hydrate Na 2 S·9H 2 O. Both are colorless water-soluble salts that give strongly alkaline solutions. When exposed to moist air, Na 2 S and its hydrates emit hydrogen sulfide , which smells like rotten eggs.
I'm not sure if it's right but it's a guess because of the 2Na.
That is sodium carbonate, Na₂CO₃.
what is 585119what is 9 +
if you dissolve 93.1g of k2CO3(s) (molar mass=136.21 g/mol) in enough water to produce a solution with a volume of 1.09 L. what is the molarity
Answer: The molarity of the K2CO3 solution is 0.625 M.
Explanation: To find the molarity of a solution, you need to know the moles of solute and the volume of the solution in liters. Here's how to solve the problem:
Calculate the moles of K2CO3 using its given mass and molar mass:
moles = mass / molar mass = 93.1 g / 136.21 g/mol = 0.682 mol
Calculate the volume of the solution in liters:
volume = 1.09 L
Calculate the molarity of the solution using the moles and volume:
molarity = moles / volume = 0.682 mol / 1.09 L = 0.625 M
What are the units for specific gravity?
Answer:
Specific gravity is a dimensionless quantity; that is, it is not expressed in units. To find the sp gr of a solid or liquid, you must know its density in kilograms per meter cubed (kg/m3) or in grams per centimeter cubed (g/cm3). Then, divide this density by the density of pure water in the same units.
Explanation:
PLEASE HELP CHEMISTRY QUESTION
When two solutions are mixed in a beaker, a reaction occurs, and the temperature drop is the reaction of……..
A) exothermic and -ve enthalpy
B) endothermic and -ve enthalpy
C) exothermic and +ve enthalpy
D) endothermic and +ve enthalpy
Answer:
B
Explanation:
the reaction is endothermic because of the temperature drop and the enthralpy is negative because its an endothermic reaction.
I did some research so I believe this to be correct but if its no I'm sorry
This chemical equation represents a chemical reaction.
NaCN + HBr + NaBr + HCN
Which two chemicals are reactants in the chemical reaction?
A.NaCN
B.NaBr
C.HCN
D.HBr
Answer: NaCN and HBr
Explanation:
3. Which of the following is not an example of acceleration?
a. A car coming to a stop at a stoplight.
b. An avalanche increasing speed down the side of a mountain.
c. A cheetah running at a constant speed on a hunt.
d. A jet making a sharp turn in an air show.
Answer:
C: The Cheetah running at a constant speed.
Explanation:
Acceleration can be defined as:
1: A decrease in speed
2: An increase in speed
3: A change in direction.
The cheetah is the only object that does not meet any criteria for acceleration.
The example that is not an example of acceleration is a cheetah running at a constant speed on a hunt. The correct option is option (c).
Acceleration refers to a change in velocity, either in magnitude or direction. In the case of the cheetah running at a constant speed, there is no change in velocity, so there is no acceleration.
The cheetah maintains a steady speed, there is no change in velocity hence, it is not accelerating.
Therefore, a cheetah runs at a constant speed on a hunt. The correct option is option (c).
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Carbon disulfide and carbon monoxide are produced when carbon is heated with sulfur dioxide.
5C(s)+2SO2(g)→CS2(l)+4CO(g)
How many moles of C are needed to react with 0.460 mole SO2?
How many moles of CO are produced when 2.0 moles C reacts?
How many moles of SO2 are required to produce 0.35 mole CS2?
How many moles of CS2 are produced when 2.4 moles C reacts?
1) To react with 0.460 mole of SO₂, 1.15 moles of C are needed.
2) When 2.0 moles of C reacts, 1.6 moles of CO are produced.
3) To produce 0.35 mole of CS₂, 0.70 moles of SO₂ are required.
4) When 2.4 moles of C reacts, 0.48 moles of CS₂ are produced.
1.
From the balanced equation, the stoichiometric ratio between C and SO₂ is 5:2. Therefore, to calculate the moles of C required, we can set up a proportion:
(5 moles C / 2 moles SO₂) = (x moles C / 0.460 moles SO₂)
Solving for x, we find:
x = (5/2) × 0.460 = 1.15 moles C
2.
From the balanced equation, the stoichiometric ratio between C and CO is 5:4. Therefore, to calculate the moles of CO produced, we can set up a proportion:
(5 moles C / 4 moles CO) = (2.0 moles C / x moles CO)
Solving for x, we find:
x = (4/5) × 2.0 = 1.6 moles CO
3.
From the balanced equation, the stoichiometric ratio between SO₂ and CS₂ is 2:1. Therefore, to calculate the moles of SO₂ required, we can set up a proportion:
(2 moles SO₂ / 1 mole CS₂) = (x moles SO₂ / 0.35 moles CS₂)
Solving for x, we find:
x = (2/1) × 0.35 = 0.70 moles SO₂
4.
From the balanced equation, the stoichiometric ratio between C and CS₂ is 5:1. Therefore, to calculate the moles of CS₂ produced, we can set up a proportion:
(5 moles C / 1 mole CS₂) = (2.4 moles C / x moles CS₂)
Solving for x, we find:
x = (1/5) × 2.4 = 0.48 moles CS₂
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Differentiate liquid crystals from pure liquids and crystalline solids.
(Answer this question correctly and I will give the first correct answer brainliest)
Answer:
the difference between pure liquids and crystallines solids is pure liquids have optically active molecules forming twisted shapes whereas solids do not
Explanation:
Milk of magnesia helps to neutralize stomach acid because it is a _____. strong acid strong base good indicator salt
Milk of magnesia helps to neutralize stomach acid because it is a strong base.
Acid: Acids have a sour taste and turn certain dyes red.
It gives off hydrogen ions in water and forms salts by combining with certain metals.
Acids are substances that has pH greater less than 7.
Base: Base turn certain dyes blue.
It takes off hydrogen ions in water and forms salts by combining with certain metals.
It has pH greater than 7.
When acid and base combine, salt is formed.
Milk of magnesia is a laxative that is thought to work by drawing water into the intestines, an effect that helps to cause movement of the intestines.
It is an antacid.
Hence, Milk of magnesia helps to neutralize stomach acid because it is a strong base.
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A gas sample that has a pressure of 4.23 atm, a volume of 1,870 mL, and a temperature of 293 K is allowed to expand to a volume of 6.01 L with a final temperature of 373 K. What is the final pressure of the gas in atmospheres?
Answer:
1.68 atm.
Explanation:
Given:
P1 = 4.23atm
V1 = 1870 mL
T1 = 293K
P2 = ?
V2 = 6.01 L = 6010 mL
T2 = 373 K
Assuming number of moles and R is constant:
\(\frac{P1V1}{T1} = \frac{P2V2}{T2}\)
⇒ P2 = \(\frac{P1V1T2}{T1V2}\) = \(\frac{2,950,467.3}{1,760,930}\)
= 1.68 atm.
Required: a. Compute the acid-test ratio for each of the separate cases above. b. Which company is in the best position to meet short-term obligations? Complete this question by entering your answers
Among the three companies, Company A has the highest acid-test ratio (2.67), followed by Company B (2.00), and then Company C (1.75). The higher the acid-test ratio, the better the company's ability to meet short-term obligations without relying on inventory sales. Therefore, Company A is in the best position to meet short-term obligations.
To compute the acid-test ratio (also known as the quick ratio) for each company, we'll use the formula:
Acid-Test Ratio = (Current Assets - Inventory) / Current Liabilities
a. Compute the acid-test ratio for each company:
Company A:
Current Assets = $250,000
Inventory = $50,000
Current Liabilities = $75,000
Acid-Test Ratio for Company A = ($250,000 - $50,000) / $75,000
Acid-Test Ratio for Company A = $200,000 / $75,000
Acid-Test Ratio for Company A ≈ 2.67
Company B:
Current Assets = $150,000
Inventory = $30,000
Current Liabilities = $60,000
Acid-Test Ratio for Company B = ($150,000 - $30,000) / $60,000
Acid-Test Ratio for Company B = $120,000 / $60,000
Acid-Test Ratio for Company B = 2.00
Company C:
Current Assets = $300,000
Inventory = $90,000
Current Liabilities = $120,000
Acid-Test Ratio for Company C = ($300,000 - $90,000) / $120,000
Acid-Test Ratio for Company C = $210,000 / $120,000
Acid-Test Ratio for Company C = 1.75
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Barium-122 has a half-life of 2 minutes. Suppose you obtained a sample weighing 10. 0 g and it takes 10 minutes to set up an experiment in which the barium-122 is to be used. How many grams of barium- 122 will remain at the point when you start the experiment?.
The mass of Barium-122 left is 0.313 g. All nuclear reactions are of first order reactions.
A first-order reaction is one in which the rate of reaction is proportional to the concentration of the reactant. For a first order reaction rate constant,
k = ( 2.303 /t )x log ( Mo / M)
Where
Mo = initial mass= 10.0 g
M= Mass left after time t = ?
t = time = 10 min
k= rate constant= 0.693/half life
= 0.693/2 min
= 0.3465 min^-1
Plug the values we get log(Mo/M) = (kt)/2.303
= (0.3465*10)/2.303
= 1.504
Mo/M=10^1.504 = 31.9
M= 10.0g/31.9
= 0.313 g
So, mass of Barium-122 left is 0.313g.
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1. explain the purpose of each step of the extraction procedure used to obtain the concentrated extract? why are things done the way they are?
Extraction procedure is the method of separating substances that are useful or needed from a complex mixture.
The process can be done using various methods such as distillation, chromatography, and solvent extraction.The extraction procedure is used to obtain a concentrated extract from a complex mixture.
The following are the steps involved in the extraction procedure:
1. Collection of the material - This is the first step in the extraction process. It involves the collection of the sample that contains the desired compound.
2. Grinding the material - This step is essential for the extraction process since it increases the surface area of the sample, which makes it easier for the solvent to penetrate.
3. Mixing the sample with the solvent - This is done to extract the compound of interest. The solvent dissolves the compound, making it easier to extract.
4. Separation of the extract - After the compound has been dissolved in the solvent, the next step is to separate the extract from the mixture.
5. Concentration of the extract - This is the last step of the extraction procedure. The purpose of this step is to obtain a concentrated extract. The extract is concentrated to increase the concentration of the compound of interest.
The reason for following these steps is to make sure that the compound of interest is extracted efficiently. Each step has a particular purpose that contributes to the efficiency of the process.
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please help there is a pic and marking brain list
Answer:
3
Explanation:
the orbitals that are usually the next highest in energy after the 6s orbitals are the:
The orbitals that are usually the next highest in energy after the 6s orbitals are the 4f and 5d orbitals. This is a long answer, but it provides a thorough explanation.
The electronic configuration of elements is determined by the Aufbau principle, which states that electrons fill orbitals in order of increasing energy. In the case of transition metals, the 6s orbital is usually filled before the 4f and 5d orbitals. However, as we move across the transition series.
the energy levels of the orbitals change. The 4f and 5d orbitals become increasingly closer in energy to the 6s orbital, and at a certain point, they become higher in energy. Therefore, after the 6s orbital is filled, the next highest energy orbitals are typically the 4f and 5d orbitals. the orbitals that are usually the next highest in energy after the 6s orbitals are the 4f orbitals.
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If a solution contains 20g of glycerol and 5g of coeine, what is the codeine percentage strength of the solution?
20%
The codeine percentage strength of the solution is 20%
The term "percent strength" describes the proportion of a material that has dissolved in a given volume of liquid. Knowing how parts relate to wholes is the secret of % strength: A percent is equal to x parts out of 100 overall.Meaning of percentage strengthThe amount of a liquid is often measured, and the % strength tells you how many parts by volume of the active ingredient are present. 100 parts by volume are included in the total volume of the solution or liquid preparation.How do you determine a solution's strength?Mass of solute times strength of solution(g) Amount of the solution(L)
The amount of solute dissolved in grams per liter of the solution is used to determine the solution's strength.It stands for the solution's potency or concentration.It uses grams per liter to express.To learn more about percentage strength visit:
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Which two circumstances had to be true in order for no prefix to be used to indicate the number of atoms in covalent compounds?
In order for no prefix to be used to indicate the number of atoms in covalent compounds, the compound must consist of only two elements or involve hydrogen. These rules help simplify the naming and representation of covalent compounds.
In order for no prefix to be used to indicate the number of atoms in covalent compounds, two circumstances must be true:
1. The first circumstance is when the compound consists of only two elements. In this case, the prefix "mono-" is not used to indicate the number of atoms of the first element. For example, in the compound CO2, the prefix "mono-" is not used before the carbon atom.
2. The second circumstance is when the compound contains hydrogen. In covalent compounds involving hydrogen, the prefix "mono-" is not used to indicate the number of hydrogen atoms. For example, in the compound NH3, the prefix "mono-" is not used before the hydrogen atoms.
It's important to note that these circumstances apply to covalent compounds specifically. Covalent compounds are formed by the sharing of electrons between atoms. In contrast, ionic compounds involve the transfer of electrons, and prefixes are not used to indicate the number of atoms in ionic compounds.
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What is the name of the compound Si₉Br₃?
‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️
Is this right? If not which is it pls
Answer:
i believe it is b as well
Explanation:
Write a balanced half-reaction for the reduction of permanganate ions in acidic solution. What are the oxidation states of manganese in this reaction?.
The oxidation state of manganese in the reaction is +2 and a balanced half-reaction for the reduction of permanganate ions in an acidic solution can be given as; \(MnO_{4}^{-} + 8H^{+} + 5e^{-} ---- > Mn^{2+} + 4H_{2}O\)
Permanganate in chemistry is a general name for the chemical compound which consists of manganate (VII) ion. Permanganate(VII) ion is a strong oxidizing agent because manganese is in a +7 oxidation state and it can be easily reduced and oxidized by other agents.
An acidic solution is a solution that has a high concentration of hydrogen ions therefore the balanced half-reaction for the reduction of permanganate ions in such a solution can be given as;
\(MnO_{4}^{-} + 8H^{+} + 5e^{-} ---- > Mn^{2+} + 4H_{2}O\)
Therefore the oxidation state of manganese from this balanced half-reaction is determined to be +2 and water is produced as a by-product
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Find the amount concentration of the anion in a 0.100 mol/L solution of Al(CIO3)3.
Answer:
0.3M
Explanation:
Find the amount concentration of the anion in a 0.100 mol/L solution of Al(CIO3)3.
FOR EVERY MOLE OF Al(CIO3)3., THERE ARE 3 MOLES OF CIO3.
SO IN A 0.00m SOLUTION, THE CONCENTRATION OF THE ANION
ClO3 IS 3X0.1M = 0.3M
.