When a substance goes through a chemical change, it forms a new substance that has different physical and chemical properties. Often, chemical changes are caused by changes in temperature. Which of the following is a chemical change caused by a change in temperature? A. freezing a popsicle B. cooking an egg C. melting ice cream D. boiling water

Answer:

c

Explanation:

kw=h+bls

Answer:

C

Explanation:

Took the test

In her book A Vindication of the Rights of Women, British author Mary Wollstonecraft advocated that women should be treated with the same respect and decency as men, particularly when it comes to education. Thus, option C is correct.

A Vindication of the Rights of Woman (1792), a groundbreaking feminist text, asserts that girls should be given the same privileges as males.

So that they might become outstanding husbands, mothers, and laborers in addition to being educated to be frivolous and inept by the educational system.

Women should be given the same opportunities as men, and women share the same capacity for reasoning at birth. Women should have the same rights to influence, expertise, and power in society as men do.

Therefore, Men have failed in their attempts to safeguard women because they have not given them the means to do so.

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#1

Heterogenous mixture mean unsimilar substances .

#2

An element is a substance made of only one type of atoms

In the given redox reaction, Ni2+(aq) + NH4+(aq) → Ni(s) + NO3-(aq), the element being oxidized is nitrogen (N) .                      

In the given redox reaction, nickel (Ni) is being oxidized. This can be identified by the fact that the oxidation state of Ni changes from +2 in the Ni2+ ion to 0 in the solid Ni.                                                                                                                         This means that Ni is losing electrons and becoming more positive, which is characteristic of oxidation in a redox reaction. The ammonium ion (NH4+) is being reduced because it is gaining electrons and its oxidation state is changing from +1 to 0 in the formation of solid Ni. Overall, this reaction is a combination of oxidation and reduction processes, which is why it is called a redox reaction.

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1.0 mole of C must completely react to produce 2.0 moles of C2H6.

The balanced chemical equation provided is:

2 C + 3 H2 → C2H6

In the given chemical equation 2 C + 3 H2 → C2H6, the coefficients represent the stoichiometric ratios of the reactants and products. These coefficients indicate the relative number of moles of each substance involved in the reaction. According to the equation, 2 moles of C are required to produce 1 mole of C2H6. This means that for every 2 moles of C2H6 produced, there must be 2 moles of C involved. If we want to determine the number of moles of C required to produce 2.0 moles of C2H6, we can use the stoichiometric ratio. Since the ratio of C to C2H6 is 2:1, we divide the given number of moles of C2H6 by 2 to find the corresponding number of moles of C. By dividing 2.0 moles of C2H6 by 2, we get 1.0 mole of C. This means that in order to produce 2.0 moles of C2H6, we need 1.0 mole of C to completely react.

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Answer:

64g of \(\bold{CH_{3}OH}\dashrightarrow\)44.8L

vapour density of \(CH_{3}3OH=\frac{mass}{volume}\) of \(\bold{CH_{3}OH}\)

=64/44.8=10/7=1.43 g/l

Vapour density of \(\bold{CH_{3}OH}\)=1.43g/l

64g of \(\bold{CH_{3}OH => 44.8L }\)

vapour density of \(\small{\sf{CH_{3}3OH=\frac{mass}{volume} of } \bold{CH_{3}OH}}\)

=64/44.8=10/7=1.43 g/l

Vapour density of \(\bold{CH_{3}OH = 1.43 g/L}\)

The answer is (A) -200 J.

The first law of thermodynamics states that the change in the internal energy of a system, ΔU, is equal to the heat added to the system, Q, minus the work done by the system, W:

ΔU = Q - W

In this case, we know that ΔU = -300 J (decrease in internal energy) and W = 100 J (work done on the system). Therefore, we can rearrange the equation to solve for Q:

Q = ΔU + W = -300 J + 100 J = -200 J

This means that the system lost 200 J of heat. However, the question asks for the change in heat, which means we need to take the negative sign into an account. Therefore, the answer is (A) -200 J.

The first law of thermodynamics is a fundamental principle of physics that states that energy can only be moved or changed from one form to another. This theory holds true for all types of energy, including mechanical, thermal, and electromagnetic energy.

The first law of thermodynamics is concerned with the conservation of energy in a system. It says that the total energy of a closed system remains constant, which includes both the system's internal energy and the work done on or by the system.

In other words, any change in a system's energy must be balanced by a change in the work or heat entering or exiting the system.

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The oxidation number of vanadium in different molecule

VO2 + (light yellow) = V -2 x 2 = +1  so, V= +5

V2+ (violet) = +2  so, V= +2

VO2+ (blue) = V-2 = 2+ so, V= +4

V3+ (green) = 3+ so, V= 3+

The total number of electrons that an atom acquires or loses to establish a chemical bond with another atom is known as the oxidation number, also known as the oxidation state. Among them is vanadium. It can be in the +2, +3, +4, and +5 oxidation states. These states are purple (II), green (III), blue (IV), and yellow (IV), each of which has a different colour (V).

Hence, vanadium has different oxidation state.

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Answer:

Liquid to Gas

Explanation:

The drink in the soda is a liquid and when you open the can, the CO2 leaves the container.

Hope this helped! :)

Answer:

883g

Explanation:

The mass of 0.327 liters of Aluminum is 0.8829g.

Mass is an intrinsic property of a body which is related to the amount of matter in a physical body until the discovery of atomic and particle physics.

It is described as the amount of matter present in an object or body. Everything we see around us has mass like table, chair, your bed, football, glass and even air has mass.

Mass can be expressed as

Density= Mass/ Volume

so,

mass= Density * volume

where, mass is in grams

density is in \(g/cm^3\)

volume is in \(cm^3\) or Litres

For above given information, Density is 2.72 \(g/cm^3\) for Aluminum

Volume is 0.327 Lt.

so, mass= 2.72 * 0.327

mass = 0.8829g

Thus, the mass of 0.327 liters of Aluminum is 0.8829g.

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Answer:

pcl3 is the empirical formula of the compound

Explanation:

1. First, let's rewrite the equation:

FeO + H2O --> Fe(OH)2

1 mole of FeO react with one mole of H2O producing 1 mole of Fe(OH)2.

Let's transform 1000g of FeO and 800 g of H2O into moles using: n = m/MM

MM of FeO = 72 g/mol

MM of H2O = 18 g/mol

n FeO = 1000/72

n FeO = 13.89 moles

n H2O = 800/18

n H2O = 44.4 moles

We can see that we have less moles of FeO than of water. The ratio between them is 1:1, so FeO is our limiting reactant.

Answer 1: FeO is the limiting reactant.

2. To calculate the theoretical yield, we need to use the number of moles of the limiting reactant, which is 13.89.

So it will be produced 13.89 moles of Fe(OH)2, since the ratio between FeO and Fe(OH)2 is 1:1.

So let's transform 13.89 moles of Fe(OH)2 into grams:

m = n*MM

MM of Fe(OH)2 = 90 g/mol

m = 13.89*90 = 1250.1 g of Fe(OH)2

Answer 2: Theoretical yield = 1250 g of Fe(OH)2

4. The excess reactant is H2O.

After the reaction, it will left 44.4 - 13.89 = 30.51 moles of H2O.

It is in grams:

m = n*MM

m = 30.51*18

m = 549 g

Answer: 549 g

The percent composition by mass of oxygen in magnesium sulfate (MgSO₄)  is 53.33%.

The percent composition of mass of oxygen in magnesium sulfate can be calculate as follows

we know that Molar mass of magnesium sulfate = 120 g/mol

Magnesium sulfate has four oxygen atoms, so multiply the molar mass of oxygen by four. So 16 × 4 = 64 g/mol.

To calculate the percent oxygen composition,

% oxygen composition = mass molar oxygen / mass molar

% oxygen composition = 64/120 × 100

% oxygen composition = 53.33 %

Therefore, the percent composition by mass of oxygen in magnesium sulfate (MgSO₄)  is 53.33%.

The mass fraction of every element found in a compound is referred to as the percentage composition of the solution.

Three techniques can be used to determine the percentage composition of matter:

The first method is good if both ingredients are solid and can be measured in grams.

A second approach can be used when both components are liquids.

A third approach is used when one substance is solid and the other is liquid. Divide the two quantities and multiply by 100 to calculate the composition ratio. By convention, both quantities must have the same units.

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The concentration of the unknown sulfuric acid sample is 0.0909M.

The first step in solving this problem is to calculate the molarity of the sodium hydroxide solution used in the titrations. This can be done using the balanced chemical equation for the reaction between oxalic acid dihydrate and sodium hydroxide:

\(H_{2} C_{2} O_{4}.2H_{2} O + 2NaOH\) → \(Na_{2} C_{2} O_{4}. 2H_{2}O\)  + \(2H_{2} O\)

From the equation, we can see that 2 moles of NaOH react with 1 mole of   \(H_{2} C_{2} O_{4}.2H_{2}O\) . Therefore, the number of moles of NaOH used in the titration can be calculated as follows:

moles NaOH = (volume of NaOH solution) x (molarity of NaOH solution)

moles NaOH = 25.30 mL x (1 L / 1000 mL) x (1 mol \(H_{2} C_{2} O_{4}.2H_{2}O\) / 126.07 g) x (2 mol NaOH / 1 mol \(H_{2} C_{2} O_{4} .2H_{2}O\)) x (1 L / 20.00 mol NaOH)

moles NaOH  = 0.002012 mol

Using the volume and moles of NaOH used in the first titration, we can calculate the molarity of the NaOH solution:

Molarity of NaOH = moles NaOH / volume of NaOH solution

Molarity of NaOH = 0.002012 mol / (25.30 mL x (1 L / 1000 mL))

Molarity of NaOH = 0.0796 M

Now we can use the volume and molarity of NaOH from the second titration to calculate the number of moles of sulfuric acid in the unknown sample:

moles \(H_{2} SO_{4}\) = (volume of NaOH solution) x (molarity of NaOH solution)

moles \(H_{2} SO_{4}\) = 22.85 mL x (1 L / 1000 mL) x (0.0796 mol NaOH / 1 L)

moles \(H_{2} SO_{4}\) = 0.001818 mol

Finally, we can calculate the concentration of the sulfuric acid:

Molarity of \(H_{2} SO_{4}\) = moles H2SO4 / volume of sulfuric acid

Molarity of \(H_{2} SO_{4}\) = 0.001818 mol / (20.00 mL x (1 L / 1000 mL))

Molarity of \(H_{2} SO_{4}\) = 0.0909 M

Therefore, the concentration of the unknown sulfuric acid sample is 0.0909 M.

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The BEST advice that Li may give Riviera is 'she should pay her bills on time'. It is a good practice to maintain finances in good order.

Personal finance refers to how a person manages his/her money as well as saving and investing.

Paying bills on time is a fundamental issue for taking control of your money and thus controlling your financial life.

Some key tips to maintain finances in order include:

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Answer: The answers are A, B, and E.

Explanation: Got it wrong on Edge and that's what it showed.

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the correct option are option A,B,D,E.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

The compound that is ionic in nature can be dissociated very easily in water. Since ionic compounds are polar in nature, they readily dissolve in water. among given option Ba(NO\(_3\))\(_2\), CaSO\(_4\), H\(_2\)CO\(_3\) and Mg\(_3\)(PO\(_4\))\(_2\) will dissociate in water.

Therefore, the correct option are option A,B,D,E.

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Answer:

 Not too large and not too small. 

Explanation:

Answer:

The catalytic mechanism of glucokinase (GK) is still not fully understood, but it is thought to involve the following steps:

Glucose binds to GK in a specific pocket.

ATP binds to GK in a different pocket.

The two substrates are brought close together by GK.

A general acid-base catalyst in GK deprotonates the C6 hydroxyl group of glucose.

A nucleophilic attack by the C6-hydroxyl group of glucose on the α-phosphate of ATP takes place.

The reaction is completed by the release of ADP and glucose-6-phosphate.

GK is a very efficient catalyst, and it is thought that its efficiency is due to the following factors:

The specific binding of the substrates to GK creates a favorable orientation for the reaction to take place.

The presence of a general acid-base catalyst in GK speeds up the reaction by providing a proton to protonate the C6 hydroxyl group of glucose and a base to abstract a proton from the α-phosphate of ATP.

The close proximity of the substrates in GK allows the reaction to take place more easily.

GK is an important enzyme in the regulation of glucose homeostasis. It is the rate-limiting enzyme in the hepatic phosphorylation of glucose, and it plays a role in the regulation of insulin secretion.

Explanation:

Aluminum, carbon, and calcium are examples of chemical elements type of matter.

Chemical elements are the fundamental substances that cannot be broken down into simpler substances by ordinary chemical means. They are considered pure substances and are the building blocks of all matter.

Each element is characterized by its unique atomic number and is represented by a specific symbol, such as Al for aluminum, C for carbon, and Ca for calcium.

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The metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

The amount of heat Q = mcΔT where

Making ΔT subject of the formula, we have

ΔT = Q/mc

Given that Q and m are the same for each metal,

ΔT ∝ 1/c

We see that the temperature change is inversely proportional to the specific heat capacity.

Since the metals are at the same temperature, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

So, the metal which will reach the highest temperature is the metal with the lowest specific heat capacity.

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 Three significant figures in 2.31 and three in 0.790 2.31/0.790 = 2.92

  .  

2.) (2.08 × 10³) × (3.11 × 10²) = 6.468 800 000 × 10⁵  

      Three significant figures in 2.08 and three in 3.11.

Significant figures are the variety of digits in a value, frequently a dimension, that contribute to the degree of accuracy of the value. We begin counting widespread figures at the primary non-0 digit.

If a number expressing the end result of a dimension (e.g., duration, pressure, volume, or mass) has more digits than the quantity of digits allowed by way of the measurement decision, then most effective as many digits as allowed by means of the measurement decision are dependable, and so best those can be massive figures.

5 rules for significant figures include:-

* All non-zero numbers ARE substantial.

* Zeros among two non-0 digits ARE great.

* Leading zeros are not giant.

* Trailing zeros to the proper of the decimal are widespread.

* Trailing zeros in an entire quantity with the decimal proven are enormous.

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Answer:

Explanation:

A. Tabular form of the formation of the compound formed between X and Y (carbon and oxygen):

| Element | Electronic Configuration |

|---------|-------------------------|

| X       | 1s² 2s² 2p⁶ 3s²        |

| Y       | 1s² 2s² 2p⁶ 3s² 3p⁵   |

B. Formation of the compound:

The compound formed between X and Y is carbon dioxide (CO2). Carbon (X) has an electronic configuration of 1s² 2s² 2p⁶ 3s², and oxygen (Y) has an electronic configuration of 1s² 2s² 2p⁶ 3s² 3p⁵.

Carbon has 4 valence electrons in its outermost energy level, while oxygen has 6 valence electrons in its outermost energy level. In order to achieve stability, carbon needs to gain 4 electrons, while oxygen needs to gain 2 electrons.

To form the compound CO2, carbon will share electrons with two oxygen atoms. Carbon will share 2 electrons with each oxygen atom, resulting in a double bond between carbon and each oxygen atom.

The formation of the compound can be represented as follows:

O = C = O

2. Drawing the formation of the compound:

In text format, the formation of the compound CO2 can be represented as:

     O

    //

   C

    \\

     O

Here, the central carbon atom (C) is bonded to two oxygen atoms (O) through double bonds. The structure of carbon dioxide is linear, with the carbon atom in the center and the oxygen atoms on either side.

Answer:

the answer of rhe question is B

Answer:

6.7 to 7 let's just say neutral

Explanation:

considering the amount of water added to the acid..

it's very diluted

The pH of the solution if 5 ml of 6M HCL is added to 95 ml of pure water is 0.52.

To find the pH of the solution, we need to use the formula: pH = -log[H+].

First, we need to calculate the concentration of H+ ions in the solution.

We know that 5 ml of 6M HCL is added to 95 ml of pure water, so we can calculate the moles of HCl added:

5 ml x 6 mol/L = 30 mmol HCl

Since we added 30 mmol HCl to a total volume of 100 mL, the concentration of H+ ions in the solution is:

[H+] = 30 mmol / 100 mL = 0.3 mol/L

Now, we can plug this concentration into the pH formula:

pH = -log(0.3) = 0.52

Therefore, the pH of the solution is 0.52.

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n=2 to n=5

An atom of the chemical element hydrogen is known as a hydrogen atom.

An atom of the chemical element hydrogen is known as a hydrogen atom. The Coulomb force holds a single positively charged proton and a single negatively charged electron to the nucleus of the electrically neutral atom. About 75% of the universe's total baryonic mass is made up of atomic hydrogen.

A hydrogen atom is an atom belonging to the chemical element hydrogen. There are two other hydrogen isotopes, deuterium and tritium, in addition to protium, which is the most prevalent form of the atom.

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The specific heat of the metal is 0.113 J/(g℃).

To solve this problem, use

Q = mcΔT

where Q is the heat transferred, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Let's first find the heat absorbed by the metal,

Q1 = mcΔT = 100.0 g x c x (25.7℃ - 100.0℃)

Since the metal was heated in boiling water until it reached 100.0℃, we can assume that its initial temperature was 100.0℃, so ΔT = 25.7℃ - 100.0℃ = -74.3℃.

The specific heat of the metal is not given, so we can't solve for Q1 at this point. However, we can use the fact that the heat absorbed by the metal is equal to the heat released by the metal when it is dropped into the water,

Q1 = Q2

where Q2 is the heat released by the metal when it is dropped into the water.

Using the same equation for Q2,

Q2 = mcΔT = (100.0 g + 125 g) x 4.184 J/(g℃) x (25.7℃ - 20.1℃)

where 4.184 J/(g℃) is the specific heat of water.

Simplifying and solving for Q1,

Q1 = Q2 = 8396.7 J

Now, we can use the equation for Q1 to solve for the specific heat of the metal,

Q1 = mcΔT

8396.7 J = 100.0 g x c x (-74.3℃)

Simplifying and solving for c,

c = 0.113 J/(g℃)

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