When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 10 kg, the acceleration of the object is 4m/s^2 . If the same force acts upon another object whose mass is 8kg , what is this object's acceleration?

owing equations, determine whether y is a function of x . x+4y=8

Answer:

x = -5

Step-by-step explanation:

6(x+2) = (5x+7)

6x + 12 = 5x + 7

x = -5

Answer:

< A = 148°

Step-by-step explanation:

<A = <B → 6x - 2° = 4x + 48° → 2x = 50° → x = 25°

<A = 6(25°) - 2° = 150° - 2° = 148°

The end-points of the line segment will be negative 1.25 and 0.25.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

The length of the line segment is 1.50 units and the midpoint of the line segment is negative 0.50. Then the end-points of the line segment are given as,

⇒ - 0.50 ± (1.50) / 2

Simplify the expression, then we have

⇒ - 0.50 ± (1.50) / 2

⇒ - 0.50 - (1.50) / 2, - 0.50 + (1.50) / 2

⇒ - 0.50 - 0.75, - 0.50 + 0.75

⇒ - 1.25, 0.25

The end-points of the line fragment will be negative 1.25 and 0.25.

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The value of q is 0.35.

The value of p is 0.16.

The value of r is 0.27.

The value of P(A given NOT B) is approximately 0.4211.

To calculate the values of p, q, and r, we can use the information provided in the Venn diagram and the probabilities of events A and B.

Given:

P(A) = 0.43

P(B) = 0.62

P(A∩B) = 0.27

Calculating the value of p:

The value of p represents the probability of event A occurring without event B. In the Venn diagram, p corresponds to the region inside A but outside B.

We can calculate p by subtracting the probability of the intersection of A and B from the probability of A:

p = P(A) - P(A∩B)

= 0.43 - 0.27

= 0.16

Therefore, the value of p is 0.16.

Calculating the value of q:

The value of q represents the probability of event B occurring without event A. In the Venn diagram, q corresponds to the region inside B but outside A.

We can calculate q by subtracting the probability of the intersection of A and B from the probability of B:

q = P(B) - P(A∩B)

= 0.62 - 0.27

= 0.35

Therefore, the value of q is 0.35.

Calculating the value of r:

The value of r represents the probability of both event A and event B occurring. In the Venn diagram, r corresponds to the intersection of A and B.

We are given that P(A∩B) = 0.27, so the value of r is 0.27.

Therefore, the value of r is 0.27.

Finding the value of P(A given NOT B):

P(A given NOT B) represents the probability of event A occurring given that event B does not occur. In other words, it represents the probability of A happening when B is not happening.

To calculate this, we need to find the probability of A without B and divide it by the probability of NOT B.

P(A given NOT B) = P(A∩(NOT B)) / P(NOT B)

We can calculate the value of P(A given NOT B) using the provided probabilities:

P(A given NOT B) = P(A) - P(A∩B) / (1 - P(B))

= 0.43 - 0.27 / (1 - 0.62)

= 0.16 / 0.38

≈ 0.4211

Therefore, the value of P(A given NOT B) is approximately 0.4211.

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1. The percentage of maize flour is given as 16.7 %

2. The common ratio of the GP is r = 1.5.

1. We have to set up equation

60x + 90(1 - x) = 85

60x + 90 - 90x = 85

now we have to solve for the value of x

-30x = -5

x = 5 / 30

x = 0.167

Hence percentage of maize flour is given as 16.7 %

2. a + ar = 20 (1)

ar + ar^2 = 30 (2)

We can rearrange equation (1) to get an expression for a:

a = 20 / (1 + r)

Now, we can substitute a into equation (2) to get an equation only in terms of r:

\(20r / (1 + r) + 20r^2 / (1 + r) = 30\\20r + 20r^2 = 30(1 + r)\\20r + 20r^2 = 30 + 30r\\20r^2 - 10r - 30 = 0\\2r^2 - r - 3 = 0\)

Solving this quadratic equation, we get:

We have two solutions, r = 1.5 and r = -1. But since the GP is increasing, we discard the negative solution. Therefore, the common ratio of the GP is r = 1.5.

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\({\sf{12 \times ( - 4) = -48}}\)

Answer: I think it’s 647.96

Step-by-step explanation:

warning: this is not the exact value (it’s rounded)

First you find the height of the traingle

To do that, do pythagoras theorem

square root 36 squared minus 25.5 squared

then use formula for area of a triangle

If you start at (0,-4) and you move left 1 unit and right 4 units, you end at (3, -4)

From the question, we have the following parameters that can be used in our computation:

Start = (0, -4)

Also, we have

You move left 1 unit and right 4 units

Mathematically, this can be expressed as

(x, y) = (x - 1 + 4, y)

Substitute the known values in the above equation, so, we have the following representation

Endpoint = (0 - 1 + 4, -4)

Evaluate the expression

Endpoint = (3, -4)

Hence, the endpoint is (3, -4)

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Matching of the functions domain and range are as follows:

f(x)   = 4-4x ;

Domain:{0,1,3,5,6}

Range;{-20,-16,-8,0,4}

f(x) = 5x - 3

Domain:{-2,-1,0,3,4}

Range:{-13,-8,-3,12,4}

f(x) = -10x

Domain:{-4,-2,0,2,4}

Range:{-40,-20,0,20,40}

f(x) = (3/x) + 1.5

Domain:{-3,-2,-1,2,6}

Range:{0.5,0,-1.5,3,2}.

1) The function f(x) = 4 - 4x

Take Domain:{0,1,3,5,6}

If, we take x=0 and put in the function then we get

f(x)=4-0

f(x)=4

put x=1

f(x) = 4 - 4 =0

put x=3 then we get

f(x)=4-12=--8

put x=5 them we get

f(x)=4-20=-16

put x=6 then we get

f(x)=4-24=-20

Therefore ,range:[-20,-16,-8,0,4}

2) The function f(x)=5x-3

Take domain{-2,-1,0,3,4}

Now, put x=-2 in the function then we get

f(x) = -13

now put x=-1 then we get

f(x)=-5-3=-8

Put x=0 then we get

f(x)=0-3=-3

Put x=3 then we get

f(x)=15-3=12

Put x=4 then we get

f(x)=20-3=17

Therefore , range:{-13,-8,-3,12,17}

3) The function f(x)=-10x

Take domain:{-4,-2,0,2,4}

Put x=-4 in the function then we get

f(x)=40

Put x= -2 then we get

f(x)=20

Put x=0 then we get

f(x)=0

Put x=2 then we get

f(x)=-20

Put x=4 then we get

f(x)=-40

Therefore , range :{-40,-20,0,20,40}

4) The function f(x)= (3/x) + 1.5

Take domain:{-3,-2,-1,2,6}

Put x= -3 in the taken function then we get

f(x)=-1+1.5=0.5

put x=-2 then  we get

f(x)= -1.5+1.5=0

Put x=-1 then we get

f(x)=-3+1.5=-1.5

Put x= 2 then we get

f(x)=1.5+1.5=3

Put x= 6 then we get

f(x)=0.5+1.5=2

Therefore, range : {0.5,0,-1.5,3,2}.

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Mean: 34.125, Median: 31.5, Mode: 38

Mean: 19.222, Median: 18, No mode

Mean: 8.611, Median: 8, Mode: 8

Let's find the mean, median, and mode for each set of numbers:

Set: 40, 38, 29, 34, 37, 22, 15, 38

Mean: To find the mean, we sum up all the numbers and divide by the total count:

Mean = (40 + 38 + 29 + 34 + 37 + 22 + 15 + 38) / 8 = 273 / 8 = 34.125

Median: To find the median, we arrange the numbers in ascending order and find the middle value:

Arranged set: 15, 22, 29, 34, 37, 38, 38, 40

Median = (29 + 34) / 2 = 63 / 2 = 31.5

Mode: The mode is the number(s) that appear(s) most frequently in the set:

Mode = 38 (appears twice)

Set: 26, 32, 12, 18, 11, 14, 21, 12, 27

Mean: Mean = (26 + 32 + 12 + 18 + 11 + 14 + 21 + 12 + 27) / 9 = 173 / 9 ≈ 19.222

Median: Arranged set: 11, 12, 12, 14, 18, 21, 26, 27, 32

Median = 18

Mode: No mode (all numbers appear only once)

Set: 3, 3, 4, 7, 5, 7, 6, 7, 8, 8, 8, 9, 8, 10, 12, 9, 15, 15

Mean: Mean = (3 + 3 + 4 + 7 + 5 + 7 + 6 + 7 + 8 + 8 + 8 + 9 + 8 + 10 + 12 + 9 + 15 + 15) / 18 ≈ 8.611

Median: Arranged set: 3, 3, 4, 5, 6, 7, 7, 7, 8, 8, 8, 8, 9, 9, 10, 12, 15, 15

Median = 8

Mode: Mode = 8 (appears 4 times)

Mean: 34.125, Median: 31.5, Mode: 38

Mean: 19.222, Median: 18, No mode

Mean: 8.611, Median: 8, Mode: 8

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Answer:

Step-by-step explanation:

Well Coefficent means its by it self with is called a constant. A coffecient is a number used to mulitpy a varable

Answer:

x = -2 and y = -21

Step-by-step explanation:

Given equations are :

\(y=15x+9\ .....(1)\\\\y=\dfrac{x}{2}-20\ ....(2)\)

From equation (1) and (2)

\(15x+9=\dfrac{x}{2}-20\\\\15x-\dfrac{x}{2}=-20-9\\\\\dfrac{29x}{2}=-29\\\\x=-2\)

Put the value of x in equation (1)

y = 15(-2) + 9

= -30 + 9

y = -21

So, the solution of the equations are (-2,-21).

You have the next data:

GH=x+6

HI=x+5

GI=3x+8

If the point G is on the line GI you have:

Then you can see that the segment GI is equal to the add of the segment GH and HI:

Then:

To find the value of the x you:

1. Make the opperations (additions) knowing that you can only add numbers with the same variable or numbers without variable, as follow:

You get:

Now you can clear the x, as follow:

Now you know the value of the x=3

You find the numerical length of GH, substituting x for its value:

The sum of the functions is option B. (f + g)(x) = 2x³ + 3x² - 5x - 3.

A function is defined as a relation from a set to another set  such that the elements in the first set maps to one and only one element in the second set.

Or in other words, no elements in the first set has more than one image in the second set.

Given the two functions,

f(x) = 2x³ + 3x² - 7x + 2 and g(x) = 2x - 5.

We have to find (f + g) (x).

Sum of the functions is,

(f + g)(x) = f(x) + g(x)

             = (2x³ + 3x² - 7x + 2) + (2x - 5)

             = 2x³ + 3x² - 7x + 2x + 2 - 5

             = 2x³ + 3x² - 5x - 3

Hence the sum of the given function is 2x³ + 3x² - 5x - 3.

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a. Assuming no additional restrictions, there are  800 possible three-digit area codes.

b. Considering ERCs, there are  80 ERCs.

c. For the seven digits after the area code, there are \(8 \times 10^6 = 8,000,000\)  possible seven-digit phone numbers.

d. Assuming only the 0 and 1 restrictions from parts a and c, the number of possible ten-digit phone numbers is 800 \(\times\) 8,000,000 = 6,400,000,000.

a. For three-digit area codes, the first digit cannot be 0 or 1.

Assuming no additional restrictions, there are 8 possibilities for the first digit (2-9) and 10 possibilities for each of the remaining two digits (0-9). Therefore, the total number of three-digit area codes possible under this plan is \(8 \times 10 \times 10 = 800.\)

b. For an ERC (Easily Recognizable Code), the second and third digits of the area code must be the same, and the first digit cannot be 0 or 1. There are 8 possibilities for the first digit (2-9) and 10 possibilities for the third digit (0-9).

Since the second digit must be the same as the third digit, there is only 1 possibility.

Therefore, the total number of ERCs is \(8 \times 1 \times 10 = 80.\)

c. For the seven digits after the area code, the first digit of the three-digit local prefix cannot be 0 or 1.

There are 8 possibilities for the first digit (2-9) and 10 possibilities for each of the remaining six digits (0-9).

Therefore, the total number of seven-digit phone numbers possible is 8 * \(10\times 10 \times 10 \times 10 \times 10 \times 10 = 8,000,000.\)

d. Assuming only the 0 and 1 restrictions from parts a and c, the number of possible ten-digit phone numbers can be calculated by multiplying the number of possibilities for each digit position.

For the area code (part a), there are 800 possibilities.

For the seven digits after the area code (part c), there are 8,000,000 possibilities.

Therefore, the total number of ten-digit phone numbers possible is 800 * 8,000,000 = 6,400,000,000.

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Answer:

2

Step-by-step explanation:

24*w = 288

w = 288 /24

w = 12

24 ÷ w = 24 ÷ 12 = 2

9514 1404 393

Answer:

Step-by-step explanation:

Let n represent the number of necklaces Rosaria ordered. Then the total cost of the order is ...

  10(120 -n) +11(n) = 1270

  n = 70 . . . . . . . . . . . . . simplify, subtract 1200

  120 -70 = 50 . . . . . . . the number of bracelets

Rosaria purchased 70 necklaces and 50 bracelets.

It should be noted that to determine the values of a and b from a description of an exponential function of the form f(x) = ab^x, one can use two points on the graph.

Use two points on the graph: If you have two points on the graph of the exponential function, you can use them to solve for a and b. Let (x1, y1) and (x2, y2) be two points on the graph. Then, you can set up two equations:

y1 = ab^(x1)

y2 = ab^(x2)

Divide the second equation by the first equation to get:

y2/y1 = (ab^(x2))/(ab^(x1)) = b^(x2 - x1)

Take the logarithm of both sides to get:

log(y2/y1) = (x2 - x1) log(b)

Solve for log(b) and substitute back into the first equation to get:

a = y1 / b^(x1)

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Answer:

15% of 25

Step-by-step explanation:

Given the following questions:

25% of 15
15% of 25

We find the answer by using the formula to calculate percentage for both questions.

Question one:
\(\frac{p\times n}{100}\)
\(\frac{25\times15}{100} =25\times15=375\div100=3.75\)
\(=3.75\)

25% of 15 is 3.75

Question two:
\(\frac{p\times n}{100}\)
\(\frac{15\times 25}{100}=15\times25=375\div100=3.75\)
\(=3.75\)

15% of 25 is 3.75

Finally:
\(3.75=3.75\)

\(15-3.75=11.25\)
\(25-3.75=21.25\)
\(11.25 < 21.25\)

Which means 15% of 25 is "greater than" 25% of 15.

Hope this helps.

Answer:

C

Step-by-step explanation:

First you need to convert the fractions into decimal form.

Joe-12 1/2 becomes 12.5

Ellen-12.09

Steve-12.4

Patty-12.8

Now put these in order from fastest to slowest

12.09,12.4,12.5,12.8

Answer:

12.8

12 1/2

12 2/5

12.09

is least from greatest

By SAS congruence triangle MLN and triangle OLN are congruent.

Triangle congruence theorem or triangle congruence criteria help in proving if a triangle is congruent or not. The word congruent means exactly equal in shape and size no matter if we turn it, flip it or rotate it.

Given that, LM≅LO, ∠MLN≅∠OLN.

LM≅LO (Given)

∠MLN≅∠OLN (Given)

LN≅LN (Reflexive property of congruence)

ΔMLN≅ΔOLN (SAS congruence)

∠M≅∠O (CPTC)

MN≅ON (CPTC)

Therefore, by SAS congruence triangle MLN and triangle OLN are congruent.

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1) y = 3x+2, where slope is 3 and point is(3, -5).

2) y+6 = 4(x-5) is the equation for the given slope and point.

                      y = mx + b

                       Slope = m = tan θ = (y2 - y1)/(x2 - x1)

1) y + 5 = 3(x-1)x-x

Compare this equation to y - y₁ = m(x - x₁)

y = 3x - 3 + 5

y = 3x + 2

2) Given:

Slope = 4; point (5, -6)

y - y₁ = m(x - x₁)

y + 6 = 4(x -5 )

Option A

Hence, i) y = 3x+2, where slope is 3 and point is(3, -5) and ii) y+6 = 4(x-5) is the equation for the given slope and point.

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The percentage of drivers who are at least 45 is 62%

From the question, we have the following parameters that can be used in our computation:

The table of values

From the table, we have

Age 45 = 62 percentile

When represented properly

So, we have

Age 45 = 62%

This means that the percentage of drivers who are at least 45 is 62%

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Answer:

Step-by-step explanation:

Year 1: $850 * 0.91 = $773.50

Year 2: $773.50 * 0.91 = $704.69

Year 3: $704.69 * 0.91 = $641.95

...

Year 34: (continue the pattern)

We can continue this calculation for each year, but to save time, we can use an exponential decay formula:

Remaining Amount = Initial Amount * (1 - rate)^years

Substituting the values:

Remaining Amount = $850 * (1 - 0.09)^34

Calculating this expression:

Remaining Amount ≈ $850 * (0.91)^34 ≈ $255.88

After 34 years, approximately $255.88 will be left with Sally.

Answer:

86

Step-by-step explanation:

the square is 7×8 = 56

the triangles: (3,5×8)/2 = 28/2 = 15

56+15+15 = 86

Answer: 0

Step-by-step explanation: I am going by the words , there WERE 3 ponies. So Sarah couldn’t take any rides.

Answer:

the answer is 1.2 or 1 1/5

Step-by-step explanation:

Answer:

.50 = 1/2 so its 1/2 plus 1/2 plus 1/5 which you turn 1/5 and 1/2 in ten and it now 5/10 plus 5/10 plus 2/10 with equals 1 and 2/10 or otherwise 1 and 1/5

Step-by-step explanation:

The additive identity is z = 0 + 0i

We know that the additive identity is a number that when we add it to our number, it does not change.

So the additive identity X is defined, for any number A, as:

A + X = A

So we want a complex number z = a + bi

such that:

19 + 5i + z = 19 + 5i

It is trivial to notice that:

z = 0 + 0i = 0

So the additive identity is 0 (just like for the case of real numbers).

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