wheel and axle is also called a continuous lever​

Answers

Answer 1

Explanation:

When load is connected to axle and effort is on the wheel it acts as first class lever with in fulcrum in the middle ..So wheel and axle is continuous lever

Answer 2
Wheel and axle is called continuous lever, why? When load is connected to axle and effort is on the wheel, it acts as a first class lever with fulcrum in the middle. ... So, it is called a continuous lever. Hopes that helped.

Related Questions

What is the answer to this question number 2?

What is the answer to this question number 2?

Answers

Answer:

1⁺ ion

Explanation:

Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.

Most metals are electropositive and would prefer to lose electrons than to gain it.

Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.

On losing an electron the number of protons is then greater than the number of electrons. This leaves a net positive charge.

How much kinetic energy does Usain Bolt (m=94kg) have when he hits his top
speed of 12 m/s?

Answers

Answer:

6768 Joules (J)

Explanation:

kinetic energy = 1/2mv^2

1/2 (94x12^2) = 6768

A Jogger runs 2.0km due east, then 10km at 45° north of east and finally 0.5km due north- Determine the displacement using graphical method Using Scale of 5ocm =2 km​

Answers

Answer:

Explanation:

To determine the displacement of the jogger using a graphical method, we can create a vector diagram to represent the individual components of the jogger's motion. We can then find the resulting displacement by adding the vectors end to end.

Assuming that "50cm = 2km" is the scale, we can convert the distances to represent them on the diagram:

2.0 km due east = 100 cm

10 km at 45° north of east = 70.71 cm (using Pythagorean theorem)

0.5 km due north = 25 cm

Next, we can plot the vectors on a coordinate grid, with east as the x-axis and north as the y-axis.

The jogger's first move, 2 km due east, can be represented by a vector starting from the origin and extending 100 cm to the right.

The second move, 10 km at 45° north of east, can be represented by a vector starting from the end of the first vector and extending 70.71 cm up and to the right.

The third move, 0.5 km due north, can be represented by a vector starting from the end of the second vector and extending 25 cm straight up.

Finally, to find the displacement, we add the vectors end to end. The displacement is the vector that starts at the origin and extends to the endpoint of the final vector. The magnitude of the displacement can be found using the Pythagorean theorem.

Using this method, we can determine the displacement of the jogger using a graphical method and the given scale.

Give three examples where an object's average speed is the same as its average velocity, and three where the two are different.

Answers

Velocity is a vector quantity and speed is a scalar quatity. This means that velocity changes with direction and speed does not.

What is speed and velocity?

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

Three examples were velocity and speed are same:

A car moving in a straight line with constant speed will also have same velocity. A runner running in the straight track with constant speed will also have same velocity. A truck on a straight highway will have same average velocity and speed.

Three examples were velocity and speed are different:

A car moving in a round road with constant speed will not have same velocity. A runner running in one round track with constant speed will not have same velocity. A truck going on a mountain will not have same average velocity and speed.

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The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?

Answers

The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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how will you use the information you've learned from dan ariely's talk to inform your future decisions?

Answers

One important takeaway from Dan Ariely's talk is that our decision-making processes are frequently irrational and influenced by variables outside of our conscious consciousness.

Social norms, emotional states, and cognitive biases, for example, can all influence our choices. As a result, one method to put this knowledge to use is to become more aware of these influences and actively consider them when making decisions.

This may entail devoting more time to decision-making, seeking out diverse views, and being aware of our own biases and tendencies.

Another key takeaway from the talk is the significance of considering the long-term consequences of our choices rather than focusing solely on short-term gains or losses.

This may entail weighing the risks and benefits of various options, as well as considering the effect of decisions on others as well as ourselves.

Overall, the information presented by Dan Ariely can be used to make more thoughtful and informed decisions by becoming more aware of our own biases and tendencies, considering diverse viewpoints, and thinking critically about the potential repercussions of our decisions.

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Which of the following is NOT a form of Potential Energy? Check all that
apply.
Energy stored in the bonds of molecules.
Energy associated with motion.
Electrons flowing from one end of a circuit to another in an electrical system,
A snowball on the edge of a 100 meter cliff.

Which of the following is NOT a form of Potential Energy? Check all thatapply.Energy stored in the bonds

Answers

I think it’s gonna snow ball is on the edge of a 100 m cliff
Easy., did this in science last year DONT worry! It is he snowball because that is a different type of energy I forget what it's called but it's the snowball in a cliff.

A 10,000J battery is depleted in 2h. What power consumption is this? *

A) 5000W
B) 3W
C) 1.4W
D) 20000W

show your work please

Answers

Answer:

P = 1.4 W

Explanation:

Given that,

The work done or the energy of the battery, E = 10,000 J

Time, t = 2 h

We need to find the power consumption. Let it is P. Power is the rate of doing work. So,

\(P=\dfrac{W}{t}\\\\P=\dfrac{10,000}{2\times 3600}\\\\P=1.38\ W\)

or

P = 1.4 W

So, the power of the battery is 1.4 W.

if a wave has a period of 30 seconds and then the frequency is cut to a quarter what is the new period?

Answers

If a wave has a period of 30 seconds and the frequency is cut to a quarter, then the new period can be calculated using the formula:

New Period = 1 / New Frequency

The original frequency can be calculated using the formula:

Frequency = 1 / Period

So, for the original wave:

Frequency = 1 / 30 seconds = 0.0333 Hz

When the frequency is cut to a quarter, the new frequency is:

New Frequency = 0.0333 Hz / 4 = 0.00833 Hz

Using the formula for the new period:

New Period = 1 / 0.00833 Hz = 120 seconds

Therefore, the new period is 120 seconds.

Which of the following is not a vector? O Torque O Linear momentum O Moment of inertia O Angular momentum

Answers

A vector is not a moment of inertia. A body's inertia is a quality that makes it resist attempts to set it in movement or, if it is already moving, then change the speed or direction of it.

Describe inertia using an example.

The resistance the body offers to remain in constant motion in the absence of an external force is known as the inertia of motion. For instance, the inertia of motion causes people to slide backward when a speeding bus suddenly stops.

What are inertia and the SI unit of it?

The quality of inertia is the incapacity of an object to alter its position or the conformation of a particular body. Kilo grammes are the SI unit of inertia because mass is a measurement of inertia. Kg m2 is the unit of inertia moment if you require one.

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A well-coated structure is defined as A) 95% or better B) 90% or better C) 99% or better D) 93% or better

Answers

Answer and Explanation:

A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing. Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body.

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A well-coated structure is defined as having a coating that meets a certain standard of quality. The answer to this particular question depends on the specific criteria being used to evaluate the coating. This would typically require a coating coverage of 90% or better, if not higher.

However, in general, a well-coated structure would typically refer to a surface that has been thoroughly and evenly covered with a coating material such as paint or varnish. This ensures that the underlying material is protected from environmental factors such as moisture and UV radiation. In addition, a well-coated structure can also improve the overall appearance of the surface, making it more aesthetically pleasing.

Regarding the options provided in the question, the answer would depend on the specific criteria being used to evaluate the coating. However, it is safe to say that a well-coated structure would require a high level of coating coverage, with minimal areas left uncovered or with an uneven application. This would typically require a coating coverage of 90% or better, if not higher. Ultimately, the specific answer would depend on the standards and expectations set by the evaluating body

A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2
. Calculate
the length of this wire required to make a 10 Ω coil.

Answers

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

\(R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m\)

Therefore, the length of the wire is 134.62 m.

A 40 g racquetball bounces off of the back wall (theta=39°) of a racquetball court as shown with the same initial and final speed v. if the magnitude of the impulse on the racquetball is 2.4Ns. find the followingA.the speed V B. if the racquetball was in contact with the wall for 5.5 ms find the average force that the wall exered on the racquetball?

A 40 g racquetball bounces off of the back wall (theta=39) of a racquetball court as shown with the same

Answers

The impulse exerted on an object is equal to the change in the linear momentum of the object:

\(I=\Delta p\)

On the other hand, the linear momentum of an object is equal to the product of its mass and its velocity:

\(p=mv\)

In the given problem, the magnitude of the velocity does not change but its direction does. Initially, the vertical component of the vleocity is equal to v*sinθ towards the wall and after the collision, the vertical component of its velocity is equal to v*sinθ away from the wall.

Then, the total change in the velocity of the ball is equal to 2v*sinθ. Then, the change in the linear momentum of the wall is:

\(\Delta p=m\cdot\Delta v=m\cdot2v\sin \theta=2mv\sin \theta\)

Since the change in linear momentum is equal to the impulse, then:

\(2mv\sin \theta=I\)

Isolate the speed v from the equation:

\(\Rightarrow v=\frac{I}{2m\sin \theta}\)

Replace I=2.4Ns, m=40.0g, θ=39º to find the magnitude of the speed v (remember to write all the quantities using SI units before plugging in the values on a calculator):

\(\begin{gathered} v=\frac{2.4Ns}{2(40.0g)\sin(39º)} \\ =\frac{2.4Ns}{2(40.0\times10^{-3}kg)\sin(39º)} \\ =47.67\frac{m}{s} \end{gathered}\)

On the other hand, the average force exerted over an object is equal to the impulse per unit time:

\(F=\frac{I}{\Delta t}\)

Replace I=2.4Ns and Δt=5.5ms to find the average force exerted over the racquetball:

\(F=\frac{2.4Ns}{5.5\times10^{-3}s}=436.36N\)

Therefore, the answers are:

A)

The speed of the ball is approximately 46.7 meters per second.

B)

The average force exerted on the ball is approximately 436 Newtons.

What is the kinetic energy of the ball as it is halfway through the fall from a forty foot building? What is the potential energy?

Answers

We must apply the kinetic energy and potential energy formulae to provide a solution to this query. For sake of simplicity, let's say that the ball weighs 1 kg and that the gravitational acceleration is approximately 9.81 m/s2.

KE is calculated as (1/2) x (1 kilogram) x (10.94 m/s)2 59.8 J.

At the halfway point, the ball has a kinetic energy of roughly 59.8 joules.

As a result, the ball's potential energy and kinetic energy are both approximately 59.8 J at the halfway point.

What happens to an object's kinetic energy during a fall?

An object's potential energy declines and its kinetic energy rises as it descends freely toward the ground. as the hard object makes contact

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Maria read on an internet blog that infrared light is dangerous to humans. According to the blog, infrared light exposure is responsivle for a number of detrimental effects in humans. Which of these can actually be caused by exposure to infrared light?
a-overheating
b-skin cancer
c-radiation sickness
d-memory less

Answers

Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).

Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.

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an electron and a proton are initially very far apart. They are thenbrjought together to form a hydrogen atom, in which the electron orbits the proton at an average distance of 5.29x10^-11 m. What is the change in electric potential energy?

Answers

Answer:

\(E=4.35\times 10^{-18}\ J\)

Explanation:

Given that,

The distance between the electron and proton, \(r=5.29\times 10^{-11}\ m\)

We need to find the change in electric potential energy. It can be calculated as follows :

\(E=\dfrac{kq_1q_2}{r^2}\)

Where

k is the electrostatic constant

Change,

\(\Delta E=\dfrac{kq_1q_2}{r}-0\)

Put all the values.

\(\Delta E=\dfrac{9\times 10^9\times (-1.6\times 10^{-19})^2}{5.29\times 10^{-11}}\\\\=-4.35\times 10^{-18}\ J\)

So, the required change in electric potential energy is \(4.35\times 10^{-18}\ J\).

how does acceleration relate to velocity?

Answers

Acceleration is the increase or decrease in velocity.

The equation is:

Acceleration= Change in velocity / Change in time

Someone Please HELP QUICK

Someone Please HELP QUICK

Answers

The total distance traveled by the skier is  160 m.

option C.

What is distance?

Distance is a measure of how far apart two objects or points are. It can be defined as the numerical value of the physical space between two objects or points.

Distance can be measured in a variety of units, such as meters, feet, miles, or kilometers, depending on the system of measurement used.

Distance can also refer to the length of a path between two points, which can be a straight line or a curved line.

The total distance traveled by the skier is calculated as follows;

total distance = distance ( 0 min) + distance (1 min) + distance (2 min) + distance ( 3 mins)

total distance = 0 m + (120 m - 0 m) + ( 160 m - 120 m )

total distance = 0 m + 120 m + 40 m = 160 m

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Why are rocks important to geologists? Check all that apply.
They give clues about Earth's past environments.
They present opportunities for future use in technology.
They contain valuable resources used for building.
Many people like to collect different types of rocks.
Rocks are important to modern transportation.

Answers

Answer:

a, b and c or They give clues about Earth's past environments.

They contain valuable resources used for building.

They present opportunities for future use in technology.

Explanation:

The Reasons why Rocks are important to geologists are ; ( A, B, C )

They give clues about Earth's past environments ( A ) They present opportunities for future use in technology ( B ) They contain valuable resources used for building ( C )

Rocks are the basic elements for the formation of the earth crust, they contain important geological materials like  mineral crystals such as  limestone,  non-mineral like glass,  pieces from other rocks, and fossils.

The study of rocks by geologists provide geologists with important information regarding the presence of mineral resources and the soil composition of the past and present environments.  

Rocks contains important resources such as quartz , glass and limestone which are used as Raw materials for the production of building materials.

Hence we can conclude that The Reasons why Rocks are important to geologists are ; ( A, B, C ).

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Why are rocks important to geologists? Check all that apply.They give clues about Earth's past environments.They

when the direction of acceleration is opposite to the direction of velocity

Answers

Answer:

If acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.

Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron. What should be the accelerating potential that need to be applied on an electron so that it has a de Broglie wavelength equal to that of the proton calculated above?

Answers

mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.

What is the energy of an electron that has undergone a 100 kV potential difference?

An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.

What is the relationship between kinetic energy and the de Broglie wavelength?

De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.

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Fossil clues are one of the _____________ clues that support the theory of continental drift.
A. crust B. resource C. climate D. rock

Answers

Answer:

a

Explanation:

I think don't get mad if I'm wrong

Solve the gaussian integration with polar coordinates

Solve the gaussian integration with polar coordinates

Answers

Solving Gaussian integration with polar coordinates involves converting the integral into polar coordinates, finding the mean and standard deviation of the function, substituting them into the Gaussian distribution formula, and integrating it over the range of the function in polar coordinates.

Gaussian integration with polar coordinates is the process of finding the integral of a function using polar coordinates and the Gaussian distribution. The polar coordinate system is a two-dimensional coordinate system that uses the radius and angle to locate a point in a plane. The Gaussian distribution is a probability distribution that is often used to describe random variables in statistics.
To solve the Gaussian integration with polar coordinates, we need to convert the integral into polar coordinates. The conversion is done using the following equations:
x = r cos(θ)
y = r sin(θ)
r² = x² + y²
θ = tan⁻¹(y/x)
Once the integral is converted into polar coordinates, we can use the Gaussian distribution to solve it. The Gaussian distribution is given by the following formula:
f(x) = (1/σ√(2π))e^(-(x-μ)²/2σ²)
where μ is the mean of the distribution and σ is the standard deviation. To use this formula, we need to first find the mean and standard deviation of the function we are integrating.
After finding the mean and standard deviation, we can substitute them into the Gaussian distribution formula and integrate it over the range of the function in polar coordinates. The result of the integration will be the value of the integral.
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QUESTIONS An athlete, during his race in the 100 m sprint in the 2008 Beijing Olympics, exerted #force of 850 s on the race track using his show on the right foot at an angle of 50/' to the horizontal, 850 N 3.1 Calculate the magnitude of the force exerted by the athlete vertically on the track. 3.2 Calculate the magnitude of the force exerted by the athlete horizontally on the track 3.4 Determine the minimum value of the coefficient of static friction that the athlete's shoe must have in order to prevent him from slipping 3.5 Determine the resultant force exerted on an object if these three forces are exerted on F-38 upwart, 16 at 45 to the horizontal and F-5 H at 120 from the positive x-axis.​

Answers

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

The Hertzsprung-Russell diagram shown is divided into four sections.
C Section 3
n
Luminosity (Lsun)
Cortion A
10%
10⁰
10²
10-2
104
Hertzsprung-Russell Diagram
400 200 100
55
Temperature (x10² K)
Which section of the diagram includes the coolest, brightest stars?
A Section 1
B
Section 2
75
45

30

Answers

The section of the diagram that includes the coolest, brightest stars is A, Section 1.

How is the Hertzsprung-Russell diagram described?

On the Hertzsprung-Russell diagram, the vertical axis represents luminosity, which is the total amount of energy emitted by a star per unit time. The luminosity is measured in units of solar luminosity, which is the amount of energy emitted by the Sun per unit time.

The section that includes the coolest, brightest stars is Section 1. This is because in this section, the stars have a low temperature (around 3,000-4,000 K) and a high luminosity (around 1,000-10,000 times that of the Sun). These stars are called red giants, and they are nearing the end of their lives. As they run out of fuel, their outer layers expand and cool, making them appear red and bright.

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The Hertzsprung-Russell diagram shown is divided into four sections.C Section 3nLuminosity (Lsun)Cortion

In order to go in a circle at a constant speed an object needs

Answers

Answer:

So for an object moving in a circle, there must be an inward force acting upon it in order to cause its inward acceleration. This is sometimes referred to as the centripetal force requirement. The word centripetal (not to be confused with the F-word centrifugal) means center seeking.

Explanation:

hope this helps

A metallic ring of mass 1 kg has moment of inertia 1 kg m² when rotating about one of its diameters. It is molten and
remoulded into a thin uniform disc of the same radius. How much will its moment of inertia be, when rotated about its own
axis.​

Answers

Answer:

The moment of inertia of disc about own axis is 1 kg-m².

Explanation:

Given that,

Mass of ring m= 1 kg

Moment of inertia of ring at diameter \((I_{r})_{d}=1\ kg\ m^{2}\)

The radius of metallic ring and uniform disc both are equal.

So, \(R_{r}=R_{d}\)

We need to calculate the value of radius of ring and disc

Using theorem of perpendicular axes

\((I_{r})_{c}=2\times (I_{r})_{d}\)

Put the value into the formula

\((I_{r})_{c}=2\times1\)

\((I_{r})_{c}=2\ kg\ m^2\)

Put the value of moment of inertia

\(MR_{r}^2=2\)

\(R_{r}^2=\dfrac{2}{M}\)

Put the value of M

\(R_{r}^2=\dfrac{2}{1}\)

So, \(R_{r}^2=R_{d}^2=2\ m\)

We need to calculate the moment of inertia of disc about own axis

Using formula of moment of inertia

\(I_{d}=\dfrac{1}{2}MR_{d}^2\)

Put the value into the formula

\(I_{d}=\dfrac{1}{2}\times1\times2\)

\(I_{d}=1\ kg\ m^2\)

Hence, The moment of inertia of disc about own axis is 1 kg-m².

A hazard sign has 3 identical

parallelogram-shaped stripes as shown.

Charles must outline each stripe with

reflective tape. Is one roll of 144 inches

of tape enough to finish the job?

Answers

Answer and Explanation: To know how much tape he will need, we have to calculate the perimeter of each parallelogram-shaped stripe.

Perimeter is the sum of all the sides of a figure.

For a parallelogram:

P = 2*length + 2*width

So, we need to determine width and length of the stripe.

Width is 3 inches. Length is the hypotenuse of the right triangle, whose sides are 6 and 18 inches. Then, length is

\(h=\sqrt{18^{2}+6^{2}}\)

\(h=\sqrt{360}\)

h = 19 in

Perimeter of the first stripe is

P = (2*19) + (2*3)

P = 44 inches

The hazard sign has 3 stripes. So total perimeter is

\(P_{t}=\) 44 + 44 + 44

\(P_{t}=\) 132 inches

To outline the parallelogram-shaped stripes, Charles need a total of 132 inches of tape. Since one roll has 144 inches, he will have enough tape to finish the job.

A hazard sign has 3 identicalparallelogram-shaped stripes as shown.Charles must outline each stripe withreflective

27. The number of coils of wire through which a bar magnet is moved is increased. The
amount the needle on the meter is deflected

A. increases
B. decreases
C. shows no change
D. does not move at all

Answers

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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A 75.0 kg astronaut is training for accelerations that he will experience upon reentry. He is placed in a centrifuge (r = 20.0 m) and spun at a constant angular velocity of 15.0 rpm (revolutions per minute). He is then slowed and brought to a stop in 2.0 minutes.
Find the magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity.

How many g’s is the astronaut experiencing when moving at constant angular velocity?


Find the torque that is needed to bring the centrifuge to a stop knowing the centrifuge has a mass of 5500.0 kg (ignore all other forces) and the force is applied at the edge of the centrifuge (20.0 m radius). Hint: torque is based on the change of linear velocity.

Answers

a. The magnitude and direction of the centripetal acceleration and force when he is spinning at constant angular velocity is 8.72 m/s^2 and 654.0 N respectively.

b.  The astronaut is experiencing 0.89 g when moving at constant angular velocity.

c. The torque that is needed to bring the centrifuge to a stop 6875 Nm.

What is angular velocity?

Angular velocity is described as a pseudovector representation of how fast the angular position or orientation of an object changes with time.

The magnitude of the centripetal acceleration and force, we will use the formula: a = v^2 / r, where v is the tangential velocity and r is the radius of the centrifuge.

a = (2pi20m15.02pi/60)^2 / 20m = 8.72 m/s^2

To calculate the force, we will use the formula

F_ = ma, where m is the mass of the astronaut, 75.0 k

F_ = 75.0 kg * 8.72 m/s^2 = 654.0 N

b. To calculate  the number of g's the astronaut is experiencing when moving at constant angular velocity, we will divide the centripetal acceleration by the acceleration due to gravity, 9.8 m/s^2

8.72 m/s^2 / 9.8 m/s^2 = 0.89 g

c.

Torque = I * alpha, where I is the moment of inertia and alpha is the angular acceleration.

I = (1/2) * 5500.0 kg * 20.0m^2 = 55000 kgm^2

The angular acceleration can be found using the formula

Alpha = (change in angular velocity) / (change in time)

The change in angular velocity is 15.0 rpm - 0 rpm = 15.0 rpm and the change in time is 2.0 minutes = 120 seconds

alpha = 15.0 rpm / 120 s = 0.125 rad/s^2

Torque = 55000 kgm^2 * 0.125 rad/s^2 = 6875 Nm

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