What’s the correct answer I need help!!!!

The approximate area of the trapezoid is determined as  13.95 unit².

The approximate area of the trapezoid is calculated as follows;

Area = ¹/₂(b₁ + b₂)h

Where;

The y-coordinates of the points on the curve at x=3/2 and x=4 is calculated as follows;

y(3/2) = - (3/2)²/2 + 3/2 + 5

y(3/2) = -9/8 + 3/2 + 5

y(3/2) = 5.375

y(4) = -4²/2 + 4 + 5

y(4) = -8 + 9

y(4) = 1

h = 5.375 - 1 = 4.375

The approximate area of the trapezoid is calculated as;

Area = ¹/₂(5.375 + 1) x 4.375

Area = 13.95 unit²

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Answer:

how tu understand what?

Answer:

To determine a cylinder's volume, you'll need to know its height and the radius of the circular base (the distance between the circle's center and its edge) at both the top and bottom. V = r 2 h is the formula, with V denoting volume, r denoting the radius of the circular base, h denoting height, and pi denoting the constant.

Step-by-step explanation:

Hope this helps! :)

a) No, you should not guess the point (-3,5) because it is not within the given domain of the function.

b) Yes, you should guess the point (2,5) because it lies within the given domain and range of the function.

a) The given domain of the function is (-3,5]. This means that the function includes all values greater than -3 and less than or equal to 5. However, the point (-3,5) has an x-coordinate of -3, which is not included in the domain. Therefore, you should not guess this point. It is important to consider the domain restrictions when guessing points for the function.

b) The given domain of the function is (-3,5], and the given range is [-4,7]. The point (2,5) has an x-coordinate of 2, which falls within the given domain. Additionally, the y-coordinate of the point, 5, falls within the given range. Therefore, you should guess the point (2,5) because it satisfies both the domain and range restrictions of the function. When guessing points, it is crucial to ensure that they lie within the specified domain and range to accurately represent the function.

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Consider the general term,

Substitute 0, 1, 2, 3 to get the first 4 terms of the series,

Consider that the difference between any two successive terms is constant at 6.

So this series will definitely form an arithmetic sequence.

So, it is a YES for the first box.

As already calculated the terms corresponding to n=0 is 2.

So the first term is 2.

Also the common difference is calculated by subtracting any term from its succeeding term,

Thus the common difference is 6.

Answer:

4.72222222222

Step-by-step explanation:

I just calculate

can I have brainliest

Answer:

4 2/11

Step-by-step explanation:

The absolute value is the distance between a number and zero. This means that absolute value cannot be negative because you cannot travel a negative distance. The distance between - 4 2/11 is 4 2/11.

Hope This Helps :)

The absolute value of -4(2/11) is 46/11.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

-4(2/11)

= -46/11

Now,

The absolute value.

= |-46/11|

= 46/11

Thus,

The value is 46/11.

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Answer:

aye bro i hate doing homework at night

Step-by-step explanation:

ye

Answer:

Experimental units, factors & treatments in experiment.

Step-by-step explanation:

Experimental Units are the 60 restaurants.

Factors are the : Menu description & price

Treatments in experimental design : Healthy Low Price, Healthy Medium Price, Healthy High price & Value low price, Value medium price, Value high price.

Answer:c= the price will be of $9, 492

Step-by-step explanation:

Hope this helps

Answer: c no solution

Step-by-step explanation:

Variables (like x) do not have a actual number, so you can never truly answer the equation. Without a key, like a= 24. Number c.

Answer:

w = 2.5

Step-by-step explanation:

do minus 8 on both sides making the formula

2w =5

then divide both sides by two so the 2w is now just w making it

w = 5÷2

w = 2.5

Answer:

15.3 oz

Step-by-step explanation:

Here, we want to get the value of the new size after reduction

We start with reduction amount

That will be;

15/100 * 18 = 2.7 oz

So we now get what it can hold

That’s;

18-2.7 = 15.3 oz

Answer:

180°

Step-by-step explanation:

Answer:

a. KJ

b. GF

c. HFG

d. FIJ

e. parallel lines will never intersect, skew lines are crooked and not in line with another specified line.

Step-by-step explanation:

hope this helps :)

The Miller-Rabin test's algorithm will be used to show that the Fermat number F₁ is not a prime. So, we now have to establish that F is a probable prime.

Fermat's test:Let's recall Fermat's test, which is based on Fermat's Little Theorem. For a prime number p and an integer a that is coprime to p, Fermat's Little Theorem states that a^(p−1) ≡ 1 (mod p).

Therefore, if for a given integer n, a^(n−1) ≡ 1 (mod n) is false for any a coprime to n, then n is not a prime. By Fermat's test, the Fermat number F = 2^(2^k) + 1 is not a prime if and only if 2^((2^k)(n−1)) ≢ 1 (mod F) for some integer n and gcd(2, F) = 1. Now, we'll use Fermat's test to show that the Fermat number F₁ is not a prime.Miller-Rabin test:Miller-Rabin is a randomized primality test that is widely utilized. It is an iterative probabilistic algorithm for determining whether or not a number is prime.

The algorithm performs k tests to determine whether a number is prime with a certain probability of error. Miller-Rabin's test is utilized to see if a number is composite or a strong probable prime with high probability (which is not less than (1/4)^k for k rounds).

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Answer:

50 min 5 hours

Step-by-step explanation:

Answer: 6 hours and 50mins

Step-by-step explanation:

Graphing calculators provide a variety of advantages to students. They are powerful tools that allow students to graph equations, visualize data, and explore mathematical concepts.

Graphing calculators also provide students with a comprehensive set of math functions, including trigonometric, exponential, and logarithmic functions. This means that students can use them to solve complex equations, or to develop and graph mathematical models.

With a graphing calculator, students can easily manipulate the graph to explore the effect of changing variables on the equation. This is particularly useful for understanding calculus concepts, and for visualizing the effects of different mathematical operations.

Overall, graphing calculators provide a variety of advantages and are an invaluable tool for students studying mathematics.

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Answer:

Equivalent Fractions for 8/3: There are infinity equivalent fractions to 83. See some examples: 83, 166, 249, 3212, 4015, 4818, 5621, 6424, 7227, 8030, 8833, 9636, 10439, 11242, 12045, 12848, 13651, 14454, 15257, 16060...

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

180 - 45 - 98 = 37

Answer:

37. ...... yeah.......

Answer:

\( \rightarrow \sf \: −31\)

Step-by-step explanation:

\( \rightarrow \sf \frac{1}{4} (4)-5(6)-2\)

\( \rightarrow \sf \: \frac{1}{4} \times \frac{4}{1} - 30 - 2\)

\( \rightarrow \sf \: 1 - 30 - 2\)

\( \rightarrow \sf \: - 31\)

Answer:

kzkakkalqlqoqowowpwowppw

The molecular weight of this molecule is 31 amu.

Angle is a shape formed when two lines or line segments meet at a point. It is usually measured in degrees, with the most common angles being 0°, 90°, 180°, and 360°. Angles are used to measure the orientation of objects and can be used to calculate the area of a shape. Angles are also used in a variety of engineering, architectural, and construction applications.

Molecular weight (m) is a measure of the mass of a given molecule or a compound. It is defined as the sum of the atomic masses of all the atoms present in the molecule. It is typically expressed in atomic mass units (amu).

The molecular weight of a substance can be determined by using the following equations:

m/1 = The atomic mass of the first element in the molecule
m/2 = The atomic mass of the second element in the molecule
m/3 = The atomic mass of the third element in the molecule
m/4 = The atomic mass of the fourth element in the molecule
m/5 = The atomic mass of the fifth element in the molecule

For example, if the molecule is composed of oxygen (O), hydrogen (H), and nitrogen (N), the molecular weight can be determined by adding the atomic masses of each element:
m/1 = 16 amu (for oxygen)
m/2 = 1 amu (for hydrogen)
m/3 = 14 amu (for nitrogen)

Therefore, the molecular weight of this molecule is 31 amu.

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Step-by-step explanation:

\(y^{2} = 36 - {x}^{2} \\ {x}^{2} + {y}^{2} = 36 \\ ( x - 0)^{2} + (y - 0)^{2} = {(6)}^{2} \\ \)

The standard equation of a circle is (x - h)² + (y - k)² = r²

where (h,k) is the center and r is the radius.

Therefore, (0,0) is the center and 6 is the radius.

The chi-square goodness-of-fit test can provide information on categorical data match an expected distribution and which categories are contributing to any deviation from that distribution.

The chi-square goodness-of-fit test is a statistical test used to determine whether a set of observed categorical data matches an expected distribution. Specifically, the test compares the observed frequencies of each category to the expected frequencies based on a hypothesized distribution, and calculates a chi-square statistic. This statistic measures the degree of difference between the observed and expected frequencies, with larger values indicating greater deviation from the expected distribution. If the chi-square statistic is large enough to reject the null hypothesis (i.e., the observed data do not match the expected distribution), the test can provide information on which categories are contributing the most to the discrepancy. This can help identify which categories are over-represented or under-represented in the observed data, and can inform further investigation into potential causes of the deviation. In summary, the chi-square goodness-of-fit test can provide information on whether observed categorical data match an expected distribution and which categories are contributing to any deviation from that distribution.

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Answer: 0.48

Step-by-step explanation:

× 0.1 = ÷10

÷ 0.1 = ×10

× 0.01 = ÷100

÷ 0.01 = ×100

So, we do=

4.8 x 0.1 = 4.8 ÷ 10

= 0.48

So our answer is 0.48

For the situation where the null hypothesis (H0) is p=0.7 and the alternative hypothesis (HA) is p≠0.7 at α=0.01, we need to find the critical value(s) for z.

a)Since the alternative hypothesis is two-tailed (p≠0.7), we will divide the significance level (α) equally between the two tails. Thus, α/2 = 0.01/2 = 0.005. By looking up the corresponding value in the z-table, we can find the critical value. The critical value for a two-tailed test at α=0.005 is approximately ±2.58.

b) In the scenario where H0: p=0.5 and HA: p>0.5 at α=0.01, we are dealing with a one-tailed test because the alternative hypothesis is p>0.5. To find the critical value for t, we need to determine the value in the t-distribution with (n-1) degrees of freedom that corresponds to an area of α in the upper tail. Since α=0.01 and the degrees of freedom are not given, we cannot provide an exact value. However, if we assume a large sample size (which is often the case with hypothesis testing), we can use the normal distribution approximation and the critical value can be obtained from the z-table. At α=0.01, the critical value for a one-tailed test is approximately 2.33.

c) When H0: μ=20 and HA: μ≠20 at α=0.01, we are conducting a two-tailed test for the population mean. To find the critical value for z, we need to divide the significance level equally between the two tails: α/2 = 0.01/2 = 0.005. By looking up the corresponding value in the z-table, we find that the critical value for a two-tailed test at α=0.005 is approximately ±2.58.

d) In the situation where H0: p=0.7 and HA: p>0.7 at α=0.10 with n=340, we are performing a one-tailed test for the population proportion. To find the critical value for z, we need to determine the value in the standard normal distribution that corresponds to an area of (1-α) in the upper tail. At α=0.10, the critical value is approximately 1.28.

e) For H0: μ=30 and HA: μ<30 at α=0.01 with n=1000, we have a one-tailed test for the population mean. Similar to situation (b), assuming a large sample size, we can approximate the critical value using the z-table. At α=0.01, the critical value for a one-tailed test is approximately -2.33.

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Answer:

I think 1500 but u may need some else to be sure

Answer:

X=6 and y=-7

Step-by-step explanation:

Answer:

15/50

Step-by-step explanation:

5*3=15

5*10=50

so 15/50.

Answer:

can you expand on your question?

Step-by-step explanation: