what's make oil boil?
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Related Questions
A Contractor Has A Job Which Should Be Completed In 100 Days. At Present, He Has 80 Men On The Job And It Is Estimated That They Will Finish The Work In 130 Days. Of The 80 Men, 50 Are Each Paid ₱120.00 A Day, 25 At ₱180.00 A Day, And 5 At ₱250.00 A Day. For Each Day Beyond The Original 100 Days, A Contractor Has To Pay ₱500.00 Liquidated Damages.A) How Many
A contractor has a job which should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00 liquidated damages.
a) How many more men should the contactor add so that he would complete the work on time?
b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine?
Answers
A contractor has a job that should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00.
liquidated damages.(a) How many more men should the contractor add so that he would complete the work on time?In the first case, we see that the contractor already has 80 men and they are working for 130 days to complete the job. So, we can use the following formula to determine the additional number of workers required to finish the work in 100 days.
b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine Let’s assume that the contractor adds 440 workers, of which 2 are paid ₱180.00 a day and the rest are paid ₱120.00 a day.
The total cost of the new workers is, therefore, ₱9600.00 + ₱4500.00 + ₱49800.00 = ₱63,900.00.The cost of liquidated damages would be calculated as follows: $$LD = (130-100) \cdot 500 = ₱15,000.00$$.
Therefore, the contractor would save money if he employs more men and not pays the fine. The contractor’s savings would be:$$Savings = LD - Additional cost$$$$= 15000.00 - 63900.00 $$$$= -48900.00$$
Thus, we can see that the contractor would save ₱48,900.00 by employing more men and not paying the fine.
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According to astm d2487, a piece of stone with a 1.5-inch diameter is considered:______.
Answers
Answer: Your answer friend is Boulder. Good luck man
Explanation:
Assuming you determine the required section modulus of a wide flange beam is 200 in3, determine the lightest beam possible that will satisfy this condition.
Answers
Answer:
W18 * 106
Explanation:
Given that the section modulus of the wide flange beam is 200 in^3 the lightest beam possible that can satisfy the section modulus must have a section modulus ≥ 200 in^3. also the value of the section modulus must be approximately closest to 200in^3
From wide flange Beam table ( showing the section modulus )
The beam that can satisfy the condition is W18 × 106 because its section modulus ( s ) = 204 in^3
name two problems the refrigeration system may have if the condensing unit is exposed to a low ambient condition when not equipped with a low ambient head pressure controlled valve.
Answers
Insufficient refrigerant flow rates through metering devices and starved evaporator coils in condensers can result from low temperatures.
What is the refrigeration principle?A substance that moves heat from one place to another during a heat cycle is called a refrigerant. When a refrigerant is applied to the food that is kept in the refrigerator, it absorbs heat and transfers the heat to the surrounding area at a lower temperature. The refrigeration cycle is made up of four main parts: evaporator, compressor, condenser, and thermal expansion valve (TXV) metering device The refrigeration cycle's primary function is to transfer heat from indoor air to outdoor air.
The first law of thermodynamics is the underlying physics principle of mechanical refrigeration. According to this law, energy—or heat in this instance—cannot be produced or destroyed; rather, it can only be transferred from one location to another, and work is required to initiate the transfer of energy.
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given a file a that is 21 bytes in length, how many other 21-byte files will produce the same sha-1 hash as a
Answers
Answer:
255
Explanation:
You want to know the number of other 21-byte files that can have the same sha-1 hash code as a given file.
SHA-1 hashThe SHA-1 hash algorithm produces a 20-byte message digest for its input. That is, there can be 2^160 possible different digests.
There can be 2^(21·8) = 2^168 possible different 21-byte files, so any given hash code may be repeated for (2^168)/(2^160) = 2^8 different files.
2^8 -1 = 255 other files may have the same SHA-1 hash.
__
Additional comment
If there is some regularity in the file structure that prevents the hash codes from being uniformly distributed, then the number of files with the same digest may well exceed 256.
Given a file a that is 21 bytes in length, SHA-1 or SHA256 other 21-byte files will produce the same sha-1 hash.
What is Hash Function?
Any function that may be used to map data of any size to fixed-size values is referred to be a hash function, while some haveh functions also enable variable length output. Hash values, hash codes, digests, or just hashes are the names given to the results of a hash function.
The SHA-1 hash function generates a 160-bit hash value from an input. Since the number of possible inputs is significantly larger than the number of possible 160-bit hash values, there can be multiple inputs that produce the same hash value, known as a hash collision.
The exact number of 21-byte files that will produce the same SHA-1 hash as a is unknown and depends on the specific input and the properties of the SHA-1 hash function. However, it is widely believed that collisions can be found for SHA-1 with a practical effort, so it is generally not considered secure for cryptographic purposes.
In short, if MD5 isn't strong enough to prevent collisions, use a stronger hash. If the stronger hashes are too slow, use a fast hash with a low chance of collisions, like MD5. Then, to further lower the likelihood of a collision, use a slower hash, like SHA-1 or SHA256. However, if SHA256 is quick enough and the doubled space isn't an issue, you should probably use SHA256.
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A wastewater treatment plant treats 20 MGD of wastewater containing 950 mg/L of suspended solids in a primary clarifier that has a 20% suspended solids removal efficiency. The rate of sludge collection, the flow rate out the bottom of the clarifier, is 0.08 MGD.
a) What is the solids concentration (in mg/L) in the sludge leaving the clarifier?
b) What mass of solids (in kg/y) is removed annually by the primary clarifier?
Answers
Answer:
a) 47500 mg/L
b) 5250366.444 kg/year
Explanation:
Given data:
suspended solids removal efficiency = 20%
Flowrate in the primary clarifier ( Q ) = 20 MGD ( change to Liters/day
Q = 20* 10^6 * 3.785412 Liters /day
settled concentration ( St ) = 950mg/L * 0.2 = 190 mg/L
amount of settled solid = Q * St
= ( 20* 10^6 * 3.785412 ) * 190 = 14384.5656 kg/day
∴ Amount going into sludge with a flowrate of 0.08 MGD = 14384.5656 kg/day
a) concentration of solid in sludge ( leaving the clarifier )
= amount of settled solid / flow rate out of the clarifier in liters/day
= 14384.5656 / ( 0.08 * 10^6 * 3.785412 )
= 0.0475 kg/L
= 47500 mg/L
b) Determine mass of solids that is removed annually
= 14384.5656 kg/day * 365 days
= 5250366.444 kg/year
Sadie is the props manager for a small community theater. Because she does not have a part onstage, Sadie is not part of the Performing Arts pathway of the Arts, AV Technology and Communication cluster.
True
False
Answers
Answer:
I think it is false!
Explanation:
Answer: I think it's true
Explanation:
Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.
using the what-if function in excel to make a decision is considered a type of __________.
Answers
A forecast as well as scenario model is a form of decision-making tool that uses the what-if Excel function.
What purposes does Excel serve?Users of Microsoft Excel may format, arrange, and compute data together in spreadsheet. Data analysts or other customers can make data simpler to examine when data is added as well as altered by arranging the data using tools like Excel. The boxes in Excel are referred to as cells, and they are arranged in columns or rows.
What is a formula in Excel?In Microsoft Excel, an formula seems to be an expression that changes the values of a group of cells. These equations nevertheless provide a result, even if it's erroneous. Using Excel formulas, you may do operations like addition, subtraction, multiplication, as well as division.
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Nested for loops. C++
Integer inVal is read from input. For each number from 0 to inVal, output the number followed by the number's value of plus sign characters, '+'. End each output with a newline.
Ex: If the input is 5, then the output is:
0
1+
2++
3+++
4++++
5+++++
------------------------------------------------
#include
using namespace std;
int main() {
int inVal;
int i;
int j;
cin >> inVal;
//Code goes here
return 0;
}
Answers
Here's the code to accomplish the task using nested for loops in C++:
#include <iostream>
using namespace std;
int main() {
int inVal;
int i;
int j;
cin >> inVal;
for (i = 0; i <= inVal; i++) {
for (j = 0; j < i; j++) {
cout << "+";
}
cout << i << endl;
}
return 0;
}
Define the term nested.
Nested refers to a situation where one construct, such as a loop or conditional statement, is placed inside another construct of the same type. For example, a nested for loop is a loop within another loop, where the inner loop is executed multiple times for each iteration of the outer loop. Similarly, a nested if statement is an if statement within another if statement, where the inner if statement is only executed if the outer if statement evaluates to true. Nesting is a common programming technique used to solve complex problems by breaking them down into smaller, more manageable parts.
This program reads an integer inVal from input and then uses nested for loops to output each number from 0 to inVal, followed by a corresponding number of plus sign characters. The output for each number is ended with a newline character.
The outer for loop iterates from 0 to inVal, while the inner loop iterates from 0 to i - 1. For each iteration of the inner loop, a plus sign character is output, and after the inner loop, the current value of i is output on a new line. The number of plus sign characters output is determined by the current value of i, since the inner loop runs i times.
Therefore, the program outputs a sequence of numbers followed by a corresponding number of plus sign characters, where the number of plus sign characters for each number increases as the number increases.
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A Generalised Extreme Value distribution with parameters below has been selected for flood design at a location in northern NSW having flood data in units ML/day. scale=14 shape=-0.5 location=21 estimate the following (a) The AEP (as %) for a design flood equivalent to 100 ML/day: (b)the design flood estimate in (ML/day) for AEP=1%:
Answers
a) AEP for 100 ML/day: 8.34%
b) Design flood for AEP=1%: 56.91 ML/day.
How to calculate the AEP for a design flood(a) To gauge the Annual exceedance probability (AEP) as a rate for a planned surge proportionates to 100 ML/day, able to utilize the Generalised extreme value (GEV) conveyance with the given parameters.
The scale parameter is 14, the shape parameter is -0.5, and the location parameter is 21.
Utilizing these parameters, able to calculate the AEP by deciding the probability of the design flood (100 ML/day) or the next flood size happening.
By applying the GEV dissemination, we discover that the AEP for a design flood of 100 ML/day is roughly 8.34%.
(b) To estimate the design flood size in ML/day for an AEP of 1%, we once more utilize the GEV dissemination with the given parameters. We got to discover the flooded value that compares to a 1% exceedance probability.
By applying the converse GEV dissemination, we appraise that the design flood greatness for an AEP of 1% is around 56.91 ML/day.
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.Tech A says that unitized hubs have a wheel nut with a higher installation torque than
serviceable wheel bearings. Tech B says that unitized hubs have the proper bearing end
play designed into the assembly once they are torqued properly. Who is correct?
a. Tech A
b.
Tech B
C
Both a and b
D
Neither a and d
Answers
Tech A says that unitized hubs have a wheel nut with a higher installation torque than serviceable wheel bearings. Tech B says that unitized hubs have the proper bearing end play designed into the assembly once they are torqued properly is Option C: Both a and b
Describe a wheel bearing?When compared to manually adjusted, PreSet, or LMS hub assemblies, unitized hub assemblies often require a lot more assembly torque and special spindle nut systems.
Therefore, An essential component of the wheel assembly that connects the wheel to the axle is a wheel bearing. A metal ring is used to hold a group of steel balls (also known as ball bearings) or taper (also known as tapered bearings) together. It permits the wheel to spin easily and with little resistance.
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With an example, describe the scaling issues and data volatility in IoT systems.
Answers
Answer:
What are some of the scalability issues in large IoT systems?
IoT Scalability Issues: 5 Essential Considerations
Large Wireless System Capacity. ...
Simplified Network Planning and Setup. ...
Interoperable Architecture. ...
Remote Network and Device Management. ...
Flexible and Scalable Software Infrastructure. ...
5 Common Myths about LPWAN for IoT Debunked.
Explanation:
which of the following is true for the depletion region capacitance of a pn junction? select one: a. all of these b. the capacitance depends on the square root of the reverse bias for an abrupt step junction c. the capacitance depends on the cube root of the reverse bias for a linearly graded junction d. the capacitance decreases as the reverse bias increases e. the amount of charge stored increases as the reverse bias increases
Answers
All of these statements are true.
The depletion region functions as an insulating or dielectric substance. P-n junction diodes can therefore be compared to parallel plate capacitors.
What is PN junction?A P-N junction is the boundary or interface between the p-type and n-type semiconductor material types inside of a semiconductor.The process of doping produces the P-N junction in a semiconductor.In an electrical circuit, a diode (PN junction) makes it easier for current to flow in one way than the other.While reverse biasing is applying a voltage across a diode in the opposite direction, forward biasing refers to applying a voltage across a diode that facilitates easy current passage. High resistance is present in the p-n junction diode's depletion zone.As a result, the depletion region functions as an insulating or dielectric substance.P-n junction diodes can therefore be compared to parallel plate capacitors.Transition capacitance is the measurement of how much capacitance changes as voltage increases.
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A soil sample, taken from a borrow pit has a specific gravity of soil solids of 2.66. The sample was taken to a materials laboratory and tested. The results of a standard Proctor test are tabulated below.
Weight of Soil (lb) Moisture Content (%)
3.20 12.8
3.78 13.9
4.40 15.0
4.10 15.7
3.70 16.6
3.30 18.1
The maximum dry density in lb/ft3 is most nearly:_______
Answers
Answer:
115 Ib/ft^3
Explanation:
To determine the maximum dry density in Ib/ft3 we have to calculate :
Bulk unit weight ( yb ) ; W / v
Dry unit weight ( yd. ) : yb / ( 1 + w )
For every set of data given
assuming v = 1/30 ft^3
calculating for the 3 data set ( maximum dry density )
weight of soil (W) = 4.40
moisture content (%) (w) = 15.0 = 0.15
Bulk unit weight (yb) = 4.40 / (1/30) = 132 Ib/ft^3
Dry unit weight ( yd. ) = 132 / ( 1 + 0.15 ) = 114.702 Ib/ft^3
therefore after calculations the maximum dry density in Ib/ft^3 ≈ 115 Ib/ft^3
A car travels from A, due north to a town B 4 km away. It then travels due east until it arrives town C 5 km from B. determine the distance of town C from A
Answers
Answer:
A to C = 6.4 km
Explanation:
A to B = 4 km
B to C = 5 km
A to C = using pythagorean theorem
a² + b² = c²
a = A to B = 4
b = B to C = 5
c = A to C
c² = 4² + 5²
c = 6.4 km (A to C)
According to the scenario, the distance between town C from town A is found to be 6.40 Km.
Which background does this question depend on?The background that this question depends on is known as the direction-based question. These types of questions completely depend on the distance of moving bodies like cars, persons, or any other objects as well with respect to the initial position.
According to the question,
The distance between town A to town B = 4 km.
The distance between town B to town C = 5 km.
Now, according to the Pythagoras theorem, the distance between town C to town A is as follows:
\(AC^2\) = \(AB^2 +BC^2\).
\(AC^2\) = \(4^2+5^2\)
\(AC^2\) = 16 + 25 = 41.
AC = √41 = 6.40 km.
Therefore, the distance between town C from town A is found to be 6.40 Km.
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* Question 1: Design alarm system as shown below. The alarm turns on when one of the following
conditions happened:
A. Motion IR sensor & window sensor
activated.
B. Motion IR sensor & door sensor
activated.
C. Otherwise the buzzer off.
(A)
Warning
Motion
Sensors
Buzzer
Suppose that: Warning buzzer on pin 8
Motion sensor on pin 5
Window sensor on pin 6
Door sensor on pin 7
The buzzer works on beating mode.
(C)
Door
sensor
TE
(B)
Window
Sensors
Answers
Answer:
A
Explanation:
Since most architects have at least a bachelor's degree, they do not require on-the-job training.
O True
O False
Answers
Answer:
The answer is false, I hope this helps. :3
Answer:
False
Explanation:
I took the quiz and it was correct
In lighting system, why it is important to consider maintenance factor?
Answers
Answer: The maintenance factor of a lighting system reflects how much of the initial luminous flux is still available at the end of its useful life. The planned lighting engineer must compute the maintenance factor and multiply the new value of the light output by it.
Explanation:
Answer:
Explanation: A lighting system's maintenance factor indicates how much of the initial luminous flux remains available at the end of its service life. The maintenance factor must be determined by the planning lighting engineer and the new value of the luminous flux multiplied by it.
TRUE/FALSE. The standard library version of sqrt(-2) throws a runtime exception because there is no possible answer
Answers
The given statement "The standard library version of sqrt(-2) throws a runtime exception because there is no possible answer" is TRUE because square roots of negative numbers do not have real number solutions.
The standard library version of the sqrt() function throws a runtime exception when given a negative number like -2 as its argument.
Instead, they have complex number solutions involving imaginary numbers. In many standard libraries, the sqrt() function is designed to handle real numbers only, so it cannot provide a complex number answer.
When it encounters a negative input, it raises a runtime exception to indicate that the input is invalid for this function, and no possible real number solution exists.
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Calculate the internal energy and enthalpy changes that occur when air is changed from an initial state of 277 K and 10 bars, where its molar volume is 2.28 m²/kmol to a final state of 333 K and 1 atm. Assume for air PV/T is constant (i.e it is an ideal gas) and Cv = 21 and Cp = 29.3 kg/kmol-¹
Answers
Answer:
PV/T is constant and that CV=21 kJ/kmolK and CP=29.3 kJ/kmol.K
Explanation:
To calculate the internal energy and enthalpy change for the given air system, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done
A 36-mph wind blows against an outdoor movie screen that is 70 ft wide and 20 ft tall. Estimate the wind force on the screen. Use drag coefficient Cd = 1.15.
Answers
Answer:
The wind force on the screen is approximately 5,341.5936 \(lb_f\)
Explanation:
The speed of the wind, v = 36 mph
The width of the outdoor movie, w = 70 ft. wide
The height of the outdoor movie, h = 20 ft. tall
The drag coefficient, Cd = 1.15
We have;
\(C_d = \dfrac{F}{\dfrac{\rho \cdot v^2 \cdot A}{2} }\)
From which we have;
The wind force, F = 0.00256·\(C_d\)·v²·A
Where;
A = The cross sectional area of the rectangular outdoor movie screen, A = w × h
∴ A = 70 ft. × 20 ft. = 1,400 ft.²
The wind force, F = 0.00256 × 1.15 × (36 mph)² × 1,400 ft.² = 5,341.5936 \(lb_f\)
The wind force on the screen, F = 5,341.5936 \(lb_f\).
The wind force on the outdoor movie screen is;
F = 23437.26 N
We are given;
Wind speed; v = 36 mph = 16.0934 m/s
Width of screen; w = 70 ft = 21.336 m
Height of screen; h = 20 ft = 6.096 m
Drag coefficient; Cd = 1.15
Now formula for the drag force is;
F = ½•C_d•ρ•A•v²
Where;
F is drag force
C_d is drag coefficient
ρ is density of object
v is speed of object
A is area
Let us use density as 1.21 kg/m³
Area; A = wh = (21.336 × 6.096)
Thus;
F = ½ × 1.15 × 1.21 × (21.336 × 6.096) × 16.0934²
F = 23437.26 N
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Heat air rises, cools then falls. Air near heat is replaced by cooler air and the cycle repeats
Answers
In order to be a Mechanical Engineer, you need to:
1. Have a Bachelor's Degree
2. Have a Master's Degree
3. Have a Ph.D.
Answers
Answer:
3
Explanation:
it is compulsory to have a bachelor's degree
Below are listed parameters for different direct-mapped cache designs: Cache Data Size: 32 KiB Cache Block Size: 2 words Cache Access Time: 1 cycle Generate a series of read requests that have a lower miss rate on a 2 KiB 2-way set associative cache than the cache listed above. Identify one possible solution that would make the cache listed have an equal or lower miss rate than the 2 KiB cache. Discuss the advantages and disadvantages of such a solution.
Answers
To generate a series of read requests that have a lower miss rate on a 2 KiB 2-way set associative cache, we need to consider the cache parameters and access patterns. Let's analyze the cache listed above first:
Cache Data Size: 32 KiB
Cache Block Size: 2 words
Cache Access Time: 1 cycle
To reduce the miss rate on a 2 KiB 2-way set associative cache, we can consider the following factors:
Cache Size: The size of the cache affects its capacity to store data. Since the 2 KiB cache is smaller than the 32 KiB cache listed above, it may result in a higher miss rate. To generate read requests with a lower miss rate, we can focus on utilizing the available cache space efficiently.
Cache Block Size: The block size determines the amount of data fetched from memory into the cache on a cache miss. A larger block size can improve spatial locality and reduce miss rates. However, it can also lead to more capacity misses if the cache is not large enough to hold multiple blocks from the same memory region.
Access Patterns: The pattern of memory accesses can greatly impact cache performance. Sequential and localized access patterns tend to have lower miss rates compared to random or scattered access patterns. By designing read requests that exhibit good spatial and temporal locality, we can improve the cache's hit rate.
One possible solution to make the listed cache have an equal or lower miss rate than the 2 KiB 2-way set associative cache is to increase its associativity. The given cache is direct-mapped, meaning each memory block can only map to one specific cache block. By making the cache set associative (e.g., 2-way set associative), each memory block can map to two cache blocks instead. This allows for more flexibility in caching data and reduces the likelihood of capacity misses.
Advantages of increasing cache associativity:
Reduced miss rate: The cache can accommodate more data with increased associativity, improving the hit rate and reducing cache misses.
Improved spatial locality: Higher associativity allows for better utilization of cache space, increasing the likelihood of neighboring memory blocks being present in the cache.
Disadvantages of increasing cache associativity:
Increased complexity and cost: Higher associativity requires additional hardware, such as additional cache lines and comparators, which increases the complexity and cost of the cache design.
Increased access latency: The cache access time may increase due to the additional hardware and the need for more complex cache indexing and replacement policies.
It's important to note that the actual impact on the miss rate and cache performance depends on the specific access patterns and characteristics of the workload. Analyzing the workload and considering factors such as cache size, block size, and associativity can help in designing an optimized cache system with a lower miss rate.
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You are using a Jupyter Notebook to explore data in a DataFrame named productDF. You want to write some inline SQL by using the following code, and visualize the results as a scatter plot: %%sql SELECT cost, price FROM product What should you do before running a cell with the %%sql magic? a. Create a new DataFrame named product from productDF.select("cost", "price") b. Persist the productDF DataFrame using productDF.createOrReplaceTempView("product") c. Filter the productDF dataframe using productDF.filter("cost == price") d. Rename the columns in the productDF DataFrame using productDF.withColumnRenamed("cost", "price")
Answers
rosbel or Janette lol baakkaaa
Answers
Answer:
t5g5gtttttttttttttttttttttttttttttttttttttttttttt
Explanation:gt555555555555555555555555555555555555555555555555
Answer:
dawbkjbjwwjhjfbfjewfaekfhawkjndwkja
Explanation: dum*as*
Please answer the questions !
Answers
Answer:
120
Explanation:
A spherical tank for storing gas under pressure is 25 m in diameter and is made of steel 15 mm thick. The yield point of the material is 240 MPa. A factor of safety of 2.5 is desired. The maximum permissible internal pressure is most nearly: 90 kPa 230 kPa 430 kPa D. 570 kPa csauteol psotolem here Pcr 8. A structural steel tube with a 203 mm x 203 mm square cross section has an average wall thickness of 6.35 mm. The tube resists a torque of 8 N m. The average shear flow is most nearly
A. 100 N/m
B. 200 N/m
C. 400 N/m
D. 800 N/m
Answers
Answer:
1) 2304 kPa
2) B. 200 N/m
Explanation:
The internal pressure of the of the tank can be found from the following relations;
Resisting wall force F = p×(1/4·π·D²)
σ×A = p×(1/4·π·D²)
Where:
σ = Allowable stress of the tank
A = Area of the wall of the tank = π·D·t
t = Thickness of the tank = 15 mm. = 0.015 m
D = Diameter of the tank = 25 m
p = Maximum permissible internal pressure pressure
∴ σ×π·D·t = p×(1/4·π·D²)
p = 4×σ×t/D = 4 × 240 ×0.015/2.5 = 5.76 MPa
With a desired safety factor of 2.5, the permissible internal pressure = 5.76/2.5 = 2.304 MPa
2) The formula for average shear flow is given as follows;
\(q = \dfrac{T}{2 \times A_m}\)
Where:
q = Average shear flow
T = Torque = 8 N·m
\(A_m\) = Average area enclosed within tube
t = Thickness of tube = 6.35 mm = 0.00635 m
Side length of the square cross sectioned tube, s = 203 mm = 0.203 m
Average area enclosed within tube, \(A_m\) = (s - t)² = (0.203 - 0.00635)² = 0.039 m²
\(\therefore q = \dfrac{8}{2 \times 0.039} = 206.9 \, N/m\)
Hence the average shear flow is most nearly 200 N/m.
Following are the solution to the given question:
Calculating the allowable stress:
\(\to \sigma_{allow} = \frac{\sigma_y}{FS} \\\\\)
\(= \frac{240}{2.5} \\\\= 96\\\\\)
Calculating the Thickness:
\(\to t =15\ mm = \frac{15\ }{1000}= 0.015\ m\\\\\)
The stress in a spherical tank is defined as
\(\to \sigma = \frac{pD}{4t}\\\\\to 96 = \frac{p(25)}{4(0.015)}\\\\\to p = 0.2304\;\;MPa\\\\\to p = 230.4\;\;kPa\\\\\to p \approx 230\;\;kPa\\\\\)
\(\bold{\to A= 203^2= 41209\ mm^2} \\\\\)
Calculating the shear flow:
\(\to q=\frac{T}{2A}\)
\(=\frac{8}{2 \times 41209 \times 10^{-6}}\\\\=\frac{8}{0.082418}\\\\=97.066\\\\\)
\(\to q=97 \approx 100 \ \frac{N}{m}\\\)
Therefore, the final answer is "".
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To measure an object accurately, what point on the ruler would you align with the object edge
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Answer:
Along the zero to measure an object on a ruler
Calculate the rms value.
Answers
Answer:
(√6)/3 ≈ 0.8165
Explanation:
The RMS value is the square root of the mean of the square of the waveform over one period. It will be ...
\(\displaystyle\sqrt{\frac{1}{T}\left(\int_{\frac{T}{4}}^{\frac{3T}{4}}{1^2}\,dt+\int_{\frac{3t}{4}}^{\frac{5t}{4}}{(\frac{-4}{T}}(t-T))^2\,dt\right)}=\sqrt{\frac{1}{T}\left(\frac{T}{2}+\left.\frac{16}{T^2}\cdot\frac{1}{3}(t-T)^3\right|_{\frac{3t}{4}}^{\frac{5t}{4}}\right)}\\\\=\sqrt{\frac{1}{T}\left(\frac{T}{2}+\frac{T}{6}\right)}=\sqrt{\frac{2}{3}}=\boxed{\frac{\sqrt{6}}{3}\approx0.8165}\)
