What’s g - 62 = 14
And what’s 243 = M + 108?

As average animal has four legs, there were ten pigs and ten chickens, giving a total of 54 legs: 10 x 4 = 40 legs, 10 x 2 = 20 legs.

10 pigs and 10 chickens were present. 10 pigs have 4 legs each, for a total of 40 legs. 10 chickens have 2 legs each, for a total of 20 legs. 40 + 20 = 54 legs. Jill counted the animals in the farmyard and found twenty. The 20 animals had a total of 54 legs, according to Jack. We can perform a straightforward step-by-step computation to determine the number of pigs and chicks present. Since each pig has four legs, we may generate 40 legs by multiplying the number of pigs, 10, by 4. Similar to humans, chickens have two legs each, so multiplying 10 by 2 results in 20 legs. The sum of the two figures gives us 54 legs, which is the same as Jack's estimate. Hence, the farmyard contained 10 pigs and 10 hens.

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Answer: 5x + 3y = -15

Step-by-step explanation:

First with the given points, we will write the slope in slope intercept form and convert it to standard form.

We need to find the slope. The slope is the diffrence between the y coordinates divided by the difference between the x coordinate.

0- (-5) = 5

-3-0 = -3      

5/ -3 = -5/3    

The slope is -5/3.

We need to now find the y-intercept using the formula y=mx + b  

where  m is the slope and b is the  y intercept.

Use one of the points coordinates and input them into the formula to solve for b.

We will use the coordinates of the point (-3,0)

0 = -5/3(-3) + b

0 = 5 + b

-5  -5

b= - 5

y= -5/3x - 5    

Now we have the equation and we will have to convert it into the form

 Ax + By = C  where C is always constant .  

     y = -5/3x - 5      Add -5/3x to both sides

+5/3x  + 5/3x

5/3x + 1y= -5       This is now in standard form   but we will convert it into integers by multiplying both sides by 3.

3(5/3x + 1y) = 3(-5)

5x + 3y = -15

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−5−5(6x−8)=−5x+19

−5+(−5)(6x)+(−5)(−8)=−5x+19(Distribute)

−5+−30x+40=−5x+19

(−30x)+(−5+40)=−5x+19(Combine Like Terms)

−30x+35=−5x+19

−30x+35=−5x+19

Step 2: Add 5x to both sides.

−30x+35+5x=−5x+19+5x

−25x+35=19

Step 3: Subtract 35 from both sides.

−25x+35−35=19−35

−25x=−16

Step 4: Divide both sides by -25.

−25x

−25

=

−16

−25

x=

16

25

The value of x is 16/25.

Algebra, a discipline of mathematics where abstract symbols rather than concrete numbers are subjected to arithmetic operations

As per the given data:

We are given an expression, and we have to find out the value of x by solving the given expression.

-5 - 5(6x-8) = -5x + 19

In LHS, multiplying by 5 in the whole bracket.

-5 - [5 × 6x - 5 × 8] = -5x + 19

-5 - [30x - 40] = -5x + 19

In LHS, multiplying by -ve in the bracket.

-5 - 30x + 40 = -5x + 19

Adding 5x both the sides.

-5 - 25x + 40 = 19

Taking all the constants to the RHS after switching signs.

-25x = 19 - 40 + 5

-25x = -16

Multiplying by -ve both the sides.

25x = 16

x = 16/25

The value of x is 16/25.

Hence, The value of x is 16/25.

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The area decreases by 7.75% each year. After 9 years, the area will be 4700km^2 multiplied by (1 - 0.0775) raised to the power of 9. This equals approximately 2892.31 km^2.

1. Calculate the annual decrease:

4700km^2 * 7.75% = 363.25 km^2
2. Calculate the percentage of the original area remaining after each year:

(100% - 7.75%) = 92.25%
3. Calculate the area after 9 years:

4700km^2 * (92.25%)^9 = approximately 2892.31 km^2.

The area will be approximately 2892.31 km^2 after 9 years.

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Answer:

\(\begin{matrix}8&2&7\\ 4&&1\\ 5&3&9\end{matrix}\)

Step-by-step explanation:

\(\begin{matrix}a&e&b\\ f&&g\\ c&h&d\end{matrix}\)

From the table,we can extract these equations:

a + e + b = a + c + f = b + g + d = c + h + d

a + e + b = a + c + f ⇒ e + b = c + f

b + g + d = c + h + d ⇒ b + g = c + h

\(\begin{Bmatrix}e+b=c+f\\ b+g=c+h\end{Bmatrix} \Longrightarrow g-e=h-f\Longrightarrow g+f=h+e\)

2 + 3 = 4 + 1 then let’s consider :

e = 2 ; h = 3 ; f = 4 ; g = 1 ,which satisfies g + f = h + e

The table becomes:

\(\begin{matrix}a&2&b\\ 4&&1\\ c&3&d\end{matrix}\)

From the equation b + e = c + f we get b + 2 = c + 4 then b = c + 2

If we consider c = 5 ⇒ b = c + 2 = 5 + 2 = 7

Then the table becomes

\(\begin{matrix}a&2&7\\ 4&&1\\ 5&3&d\end{matrix}\)

Then a + 9 = d + 8 ⇒ d = a + 1

If we consider a = 8 ⇒ d = 9

\(\begin{matrix}8&2&7\\ 4&&1\\ 5&3&9\end{matrix}\)

I know it’s not perfect reasoning ,but it may help.

Under some circumstances, notably when the sample size is high enough and the population from which the samples are drawn has a normal distribution, the distribution of sample means will be roughly normal. The Central Limit Theorem refers to this.

Regardless of the population distribution's form and provided that the population has a finite standard deviation, the Central Limit Theorem states that as sample size grows, the distribution of sample means tends to resemble a normal distribution.

Additionally, even if the population distribution is not perfectly normal, if the sample size is high enough (often thought to be 30 or more), the combined effects of the Centrbal Limit Theorem and the Law cause the sample means to generally follow a normal distribution.

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The pair of the line together that could be perpendicular to RS and should be considered will be EA and FG.

It should be noted that in terms of elementary geometry, two geometric objects should be considered as perpendicular when they intersect at a right angle.

In such a case, a line is treated to be perpendicular to another line in the case when the two lines intersect at a right angle.

Therefore, based on the information, the pair of the line together that could be perpendicular to RS and should be EA and FG.

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Using the sample space, the probability of rolling an even number with a six-sided dice is 3/6 or 1/2.

In the given question we have to find the probability of rolling an even number with a six-sided dice.

The sample space of dice through the experiment is

{1,2,3,4,5,6}

The even numbers is {2,4,6}.

The probability of rolling an even number with a six-sided dice is

P(E)=Total number of even outcome/Total number of outcome

P(E)=3/6

P(E)=1/2

Hence, the probability of rolling an even number with a six-sided dice is 3/6 or 1/2.

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Explanation:

x = number of coins Karen has

4x = four times the number of coins she has

4x-4 = number of coins Bill has, four fewer than 4x

Add up the first and third expressions to get

(x) + (4x-4) = (x+4x) - 4 = 5x-4

The two of them have a combined 5x-4 coins

Answer:

78.4% probability at least one does not have a job

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they have a job, or they do not have a job. The probability of a student having a job is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

In which \(C_{n,x}\) is the number of different combinations of x objects from a set of n elements, given by the following formula.

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

And p is the probability of X happening.

60% of the students at a large university have a job

This means that \(p = 0.6\)

Three of these students are randomly selected

This means that \(n = 3\)

What is the probability at least one does not have a job?

Either all of them have a job, or at least one does not. The sum of the probabilities of these events is decimal 1. So

\(P(X < 3) + P(X = 3) = 1\)

We want P(X < 3). Then

\(P(X < 3) = 1 - P(X = 3)\)

In which

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 3) = C_{3,3}.(0.6)^{3}.(0.4)^{0} = 0.216\)

\(P(X < 3) = 1 - P(X = 3) = 1 - 0.216 = 0.784\)

78.4% probability at least one does not have a job

Answer:

14

Step-by-step explanation:

Answer:

t + 4/10 >1

t + 4>1*10

t >10 - 4

t > 6

Answer:

I think they will match if they have a relationship so A. But, i also think it could be different it's like humans they aren't all the same. :)

Step-by-step explanation:

Those were my reasons and thats pretty much what you think or make it is what it is so best idea is to work it out. :)

Answer:

-x²-2

Step-by-step explanation:

The percentage of the students who wore a silly hat is 64 %.

The percentage is defined as a ratio expressed as a fraction of 100.

We have been given that Last Tuesday was a silly hat day at Aaron's school. 64 students wore a silly hats and 36 students did not.

We have to determine the percentage of the students who wore a silly hat

The total number of students = 64 students wore silly hats and 36 students did not.

The total number of students = 64 + 36 = 100

We have to determine the percentage of the students who wore a silly hat

The percentage of the students wore a silly hat = (64/ 100) × 100

The percentage of the students wore a silly hat = 0.64 × 100

The percentage of the students wore a silly hat = 64 %

Thus, the percentage of students who wore silly hats is 64 %.

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The required proof that KLMN is a trapezoid is below in the solution part.

A trapezoid is a quadrilateral having two parallel bases and one set of other sides called as legs.

To prove that KLMN is a trapezoid, we need to show that it has exactly one pair of parallel sides.

First, let's find the slopes of each side of the quadrilateral:

The slope of KL is (b-0)/(a-0) = b/a.

The slope of LM is (b-b)/(3a-a) = undefined.

The slope of MN is (0-b)/(4a-3a) = -b/a.

The slope of KN is (0-0)/(4a-0) = 0.

Since KL and MN have slopes that are negative reciprocals of each other, they are parallel. Therefore, KLMN has a pair of parallel sides and meets the definition of a trapezoid. Thus, the statement "KLMN is a trapezoid" is proven.

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The question seems incomplete, the correct question has been attached below.

The Cartesian equation of the curve is y = -4x + 9 for -1 ≤ x ≤ 4.

To eliminate the parameter t, we can isolate t in the equation x = t^2 - 2 and substitute it into the equation for y. This gives us:

y = t + 1

t = x + 2

y = x + 3

So the Cartesian equation of the curve is y = x + 3 for -2 ≤ y ≤ 4.

We can eliminate t by taking the natural logarithm of both x and y. This gives us:

ln x = t - 8

ln y = 2t

Solving for t in the first equation and substituting it into the second equation, we get:

t = ln(x) + 8

y = e^(2ln(x)+16) = x^2e^16

So the Cartesian equation of the curve is y = x^2e^16.

To eliminate t, we can again isolate it in the equation for x and substitute it into the equation for y. This gives us:

x = t + 1

t = x - 1

y = 5 - 4(x - 1) = -4x + 9

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The Cartesian equation of the curve is y = 1 - 4x, for -1 ≤ x ≤ 4.

To eliminate the parameter t, we can solve for t in terms of x and substitute it into the equation for y:

t = ±√(x + 2)

y = t + 1 = ±√(x + 2) + 1

Squaring both sides and simplifying, we get:

(x + 2) = (y - 1)²

So the Cartesian equation of the curve is:

x = (y - 1)² - 2, for -2 ≤ y ≤ 4.

To eliminate the parameter t, we can take the natural logarithm of both sides of the equation for y:

ln y = 2 ln e + t ln e = 2 ln e + ln x

ln y = ln (xe²)

y = xe²

So the Cartesian equation of the curve is:

y = x^2e^2.

To eliminate the parameter t, we can solve for t in terms of x and substitute it into the equation for y:

t = 1 + x

y = 5 - 4t = 1 - 4x

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Two different ways to write f dA as an iterated integral for the shaded region R. 1 + R 1, in the order dy dx and dx dy.

To write f dA as an iterated integral in two different ways for the shaded region R. 1 + R 1, we need to first determine the limits of integration for each variable.

If we start with the order dy dx, we can see that the shaded region is bounded by y = 0, y = 2, x = 1 and x = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dy dx
= ∫1^2 ∫0²-x f(x,y) dy dx + ∫2³ ∫0 f(x,y) dy dx
= ∫1^2 [∫0²-x f(x,y) dy] dx + ∫2³ [∫0 f(x,y) dy] dx
(Note: We split the integral into two parts based on the two different regions.)

Alternatively, if we switch the order to dx dy, we can see that the shaded region is bounded by x = 1, x = 2, y = x-1 and y = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dx dy
= ∫0 ∫x+1² f(x,y) dy dx + ∫1² ∫1 f(x,y) dx dy
= ∫0 [∫x+1² f(x,y) dy] dx + ∫1² [∫1 f(x,y) dx] dy
(Note: We split the integral into two parts based on the two different regions.)

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Two different ways to write f dA as an iterated integral for the shaded region R. 1 + R 1, in the order dy dx and dx dy.

To write f dA as an iterated integral in two different ways for the shaded region R. 1 + R 1, we need to first determine the limits of integration for each variable.

If we start with the order dy dx, we can see that the shaded region is bounded by y = 0, y = 2, x = 1 and x = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dy dx
= ∫1^2 ∫0²-x f(x,y) dy dx + ∫2³ ∫0 f(x,y) dy dx
= ∫1^2 [∫0²-x f(x,y) dy] dx + ∫2³ [∫0 f(x,y) dy] dx
(Note: We split the integral into two parts based on the two different regions.)

Alternatively, if we switch the order to dx dy, we can see that the shaded region is bounded by x = 1, x = 2, y = x-1 and y = 2. Therefore, we can write the integral as follows:

f dA = ∫∫R f(x,y) dx dy
= ∫0 ∫x+1² f(x,y) dy dx + ∫1² ∫1 f(x,y) dx dy
= ∫0 [∫x+1² f(x,y) dy] dx + ∫1² [∫1 f(x,y) dx] dy
(Note: We split the integral into two parts based on the two different regions.)

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The question that is a statistical question is: "which brand of ice cream is preferred by the people shopping at a grocery store?" (Option D)

A statistical question is one that can be addressed by gathering varying amounts of data.

This is a statistical issue since it entails gathering and evaluating data from a group of individuals to discover which brand of ice cream the majority prefers.

The other alternatives are not statistical inquiries since they solicit personal opinions or preferences rather than group facts.

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Answer:

D

Step-by-step explanation:

Answer:

Completing the square is useful because it gives us alternatives to the quadratic formula and can solve problems that the quadratic formula can't.

The solution for the system of equations of three variables is:

x = 4

y = -1

z = -3

Or (4, -1, -3) written as a point.

Here we have a system of equations on 3 variables, the system is:

3x + 2y + z = 7

5x + 5y +4z = 3

3x + 2y + 3z = 1

Notice that the "x" and "y" coefficients in the first and last equation are the same ones, so we can take the difference between these to get:

(3x + 2y + 3z ) - (3x + 2y + z ) = 1 - 7

2z = -6

z = -6/2 = -3

So the value of z is -3.

Replacing that in the first and second equation we get:

3x + 2y - 3 = 7

5x + 5y + 4*(-3) = 3

Now we can simplify these:

3x + 2y = 10

5x + 5y = 15

We can divide the second one by 5 to get:

(5x + 5y)/5 = 15/5

x + y = 3

Isolating x, we get:

x = 3 - y

Now we replace that in the other equation:

3*(3 - y) + 2y = 10

9 - y = 10

9 - 10 = y

-1 = y

Now we know the value of y, finally with:

x = 3 - y

We can get the value of x:

x = 3 - (-1) = 4

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Answer:

4

Step-by-step explanation:

36 =9w

w =36 :9

w =4

Answer:

$196 for twenty-four months. $130 for twelve months  

$80 for one month. $100 dollars for five months.

Step-by-step explanation:

y=mx+b solved is y=5x+75

note- X is the amount of months

y=5(24)+75       y=5(11)+75      y=5(1)+75         y=5(5)+75

y=120+75          Y=55+75        y=5+75            y=25+75

y=195                 y=130             y= 80               y=190

PESTLE framework is a tool used for analyzing an organization's macro-environment. The six main types of environmental factors are Political, Economic, Sociocultural, Technological, Legal, and Environmental.

True Economic forces are one of the types of influences analyzed in the PESTLE framework. False An organization's strength is not part of the types studied in the PESTLE framework. True The PESTLE framework is designed to provide a comprehensive list of influences on the possible success or failure of strategies. It is a useful tool for identifying opportunities and threats in the external environment of a company.

PESTLE framework is a tool used for analyzing an organization's macro-environment. It categorizes environmental influences into six main types that include Political, Economic, Sociocultural, Technological, Legal, and Environmental. The PESTLE framework is designed to provide a comprehensive list of influences on the possible success or failure of strategies. It is a useful tool for identifying opportunities and threats in the external environment of a company. The PESTLE framework can be used in conjunction with other tools, such as SWOT analysis, to gain a deeper understanding of an organization's position in the market.

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Answer: 2/13

Step-by-step explanation:

To solve this word problem expression, we can first convert the mixed number to an improper fraction so it's easier to work with.

1 1/3 = 4/3

Adding 4/3 to 0.4, we get 5.2/3.

4/15 divided by 5.2/3 is 4/26, or 2/13

After subtracting the cost of parking from the total budget, a group of 6 people can go to the amusement park with the remaining budget of $132.00, considering that each ticket costs $19.47 without tax.

Let's first subtract the cost of parking from the total budget:

$143.25 - $11.25 = $132.00

Now we need to find out how many people can go to the amusement park with the remaining budget of $132.00.

We can start by finding out how much one ticket costs without tax:

$22 / 1.13 = $19.47

So each ticket costs $19.47 without tax. We can now calculate how many tickets can be bought with the remaining budget:

$132.00 / $19.47 = 6.78

Since we cannot buy a fraction of a ticket, we need to round down to the nearest whole number. Therefore, a group of 6 people can go to the amusement park with the given budget.

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Answer:

X=1

Step-by-step explanation:

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