Answer:
0.25 or 1/4
Step-by-step explanation:
hope this helps
Answer:
Step-by-step explanation:
Half of half a mile is one quarter mile: (1/2)(1/2) = 1/4
George claims that a music school in his hometown, the average child takes less than 5 years of piano lessons. We have a random sample of 20 children from the city, with a mean of 4.6 years of piano lessons and a standard deviation of 2.2 years.
Required:
a. Evaluate Georgianna's claim using a hypothesis test.
b. Construct a 95% condence interval for the number of years students in this city take piano lessons, and interpret it in context of the data.
c. Do your results from the hypothesis test and the condence interval agree? Explain your reasoning.
Evaluating Georgianna's claim using a hypothesis test.The claim is that the average child takes less than 5 years of piano lessons. Therefore, we use a one-tailed hypothesis test with a null hypothesis asH0: µ ≥ 5 versus the alternative hypothesis Ha: µ < 5.
Level of significance is not given, hence we can assume it to be 0.05. Calculating the test statistic as follows:$$t=\frac{\overline{x}-\mu }{s/\sqrt{n}}$$Substituting the given values in the above equation, we get$$t=\frac{4.6-5}{2.2/\sqrt{20}}$$So, t = -1.69, for a one-tailed test (left-tailed) and the degrees of freedom are n-1 = 19. Using the t-distribution table with α = 0.05 and 19 degrees of freedom, the critical value is -1.73, hence, -1.69 falls within the non-rejection region. Therefore, we cannot reject the null hypothesis. There is not enough evidence to support Georgianna's claim.b. Constructing a 95% confidence interval for the number of years students in this city take piano lessons, and interpret it in the context of the data.
The formula for confidence interval for a population mean is Interpretation: We can be 95% confident that the average number of years students in this city take piano lessons falls between 4.01 and 5.19 years.c. Explaining if the results from the hypothesis test and the confidence interval agreeYes, the results from the hypothesis test and the confidence interval agree because we cannot reject the null hypothesis in the hypothesis test. This means that the null hypothesis, H0: µ ≥ 5 is plausible. Further, the 95% confidence interval for the mean number of years students take piano lessons lies completely above the value of 5 years, which is Georgianna's claim. This is in line with the hypothesis test result. Thus, we can conclude that there is no sufficient evidence to support Georgianna's claim.
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Y = 2x/a + 2b solve for b
Answer:
b = Y/2 - x/a
Step-by-step explanation:
Find the measure of angle x in the figure.
Note: Angles not drawn to scale.
Angle x measures=
Answer:
x = 125°
Step-by-step explanation:
There are 7 angles in this shape. The sum of the angles in a shape like this is calculated using a formula.
Total of angles
= (n - 2)•180°
Put in 7, because there are 7 angles.
= (7 - 2)•180°
= 5•180°
= 900°
So the total of the angles should be 900°. We know all of the angles except one.
900° = 123°+129°+128°+128°+132°+135°+ x
900° = 775° + x
Subtract 775.
125° = x
The missing angle is 125°.
Helene wrote a report. It took her 4 hours to write 24 pages. What was her unit rate in pages per hour
Helpppppppppppppppppppppppppppppppppppppppppppppppp
Answer:
60 grams brudda
Step-by-step explanation:
if there is a very weak correlation between two variables, then the coefficient of determination must be group of answer choices
Answer:
If there is a very weak correlation between two variables, then the coefficient of determination (R-squared) must be low as well.
This is because the coefficient of determination measures the proportion of variance in the dependent variable that can be explained by the independent variable(s).
When the correlation between the variables is weak, there is less variance in the dependent variable that can be explained by the independent variable(s), resulting in a lower R-squared value. So, the answer is "low".
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Asia is a chef in a restaurant. To prepare for dinner service, she chops 7 1/2 onions in 1/6 of an hour. What is Asia's rate of chopping in onions per hour?
Asia is a chef in a restaurant. To prepare for dinner service, she chops 7 1/2 onions in 1/6 of an hour. Asia's rate of chopping onions is 30 onions per hour.
From the information given;
Asia chops \(\mathbf{7 \dfrac{1}{2} \ onions }\) in \(\mathbf{\dfrac{1}{6} \ hours}\)So, the onion is given in mixed fraction which can be converted to an improper fraction as: \(\mathbf{\dfrac{15}{2}\ onions}\)
Now,
if Asia chops \(\mathbf{\dfrac{15}{2}\ onions}\) in \(\mathbf{\dfrac{1}{6} \ hours}\) Then Asia will chop (x) onions in 1 hour.We can cross multiply the above two equations to determine the number of onions Asia will chop per hour as follows:
\(\mathbf{(x) \times \dfrac{1}{6} \ hours = \dfrac{15}{2} \ onions \times 1 \ hour}}\)
Making (x) the subject of the formula:
\(\mathbf{(x)=\dfrac{ \dfrac{15}{2} \ onions \times 1 \ hour}{ \dfrac{1}{6} \ hours }}}\)
\(\mathbf{(x)={ \dfrac{15}{2} \ onions } \times { \dfrac{6}{1} }}}\)
(x) = 15 onions × 3
(x) = 30 onions per hour.
Therefore, Asia's rate of chopping onion is 30 onions per hour.
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If Asia chops 7 1/2 onions in 1/6 hour, therefore, using proportion, the rate of chopping onions per hour is: 45 onions per hour.
Applying the knowledge of proportion and fractions, we can determine Asia's chopping rate of onions per hour.
Given:
Number of onions chopped in 16 hour = 7 1/2 onionsLet number of onions chopped in 1 hour be xUsing proportion, we have the following:
\(7\frac{1}{2} = \frac{1}{6} \\\\x = 1\)
Cross multiply\(\frac{1}{6} \times x = 7\frac{1}{2} \times 1\\\\\frac{x}{6} = \frac{15}{2}\)
Multiply both sides by 6\(\frac{x}{6} = \frac{15}{2}\\\\x = \frac{15}{2} \times 6\\\\x = 45\)
Therefore, if Asia chops 7 1/2 onions in 1/6 hour, therefore, using proportion, the rate of chopping onions per hour is: 45 onions per hour.
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At a middle school, 30% of students buy lunch in the cafeteria and the remaining students bring lunch from home. A spinner with 10 equal-sized sections numbered 0-9 will be used to simulate the lunch trend. How can you design a simulation to guess whether the next 20 students buy lunch or bring lunch from home?
A:Assign the numbers 0–3 to represent students who buy lunch and the numbers 4–9 to represent students who bring lunch from home. Spin the spinner 20 times and count how many spins are between 0–3 and how many are between 4–9.
B:Assign the numbers 0–2 to represent students who buy lunch and the numbers 3–9 to represent students who bring lunch from home. Spin the spinner 10 times and count how many spins are between 0–1 and how many are between 4–6, then multiply the counts by 2.
C:Assign the numbers 0–2 to represent students who buy lunch and the numbers 3–9 to represent students who bring lunch from home. Spin the spinner 20 times and count how many spins are between 0–2 and how many are between 4–9.
D:Assign the numbers 0–3 to represent students who buy lunch and the numbers 4–9 to represent students who bring lunch from home. Spin the spinner 10 times and count how many spins are between 0–3 and how many are between 4–9.
Answer:
B
Step-by-step explanation:
I'm pretty confident that it is B
Solve 5.7 − 14.
43
19.7
−8.3
−19.7
Solve |x| +7<4.
(x1x < -11 or x>-3)
{x | < - 11 or x > 4.
There is ''No solution'' of the expression |x| + 7 < 4.
What is Mathematical expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
We have to given that;
The expression is,
⇒ |x| + 7 < 4
Now, We can solve the expression as;
The expression is,
⇒ |x| + 7 < 4
Subtract 7 both side;
⇒ |x| + 7 - 7 < 4 - 7
⇒ |x| < - 3
Hence, The expression has no solution.
Thus, There is ''No solution'' of the expression |x| + 7 < 4.
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Assume that there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents. Scientists later investigate whether or not this bivariate relationship is moderated by age.
Age 16-20: r = 0.6 p = 0.01
Age 21+: r = 0.2 p = 0.05
T or F: Based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
It is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
In the given scenario, it is not completely true that based only on the r and p values listed above, you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
Let's first understand what is meant by the term "moderator.
"Moderator: A moderator variable is a variable that changes the strength of a connection between two variables. If there is a statistically significant bivariate relationship between the amount of texting during driving and the number of accidents, scientists investigate whether this bivariate relationship is moderated by age.
Therefore, based on the values of r and p, it is difficult to determine if age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
As we have to analyze other factors also to determine whether the age is a moderator or not, such as the sample size, the effect size, and other aspects to draw a meaningful conclusion.
So, it is False that based only on the r and p values listed above you can come to the conclusion that age is a moderator of the bivariate relationship between the amount of texting and the number of accidents.
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Explain why the confidence intervals you constructed using the percentile method and the standard error method are not exactly the same.
The confidence intervals created using the percentile method and the standard error method are not exactly the same for two reasons:
First, the two methods are based on different assumptions about the population distribution of the sample. Second, the percentile method and the standard error method use different formulas to compute the confidence intervals. The standard error method assumes that the population is normally distributed, while the percentile method does not make any assumptions about the distribution of the population. As a result, the percentile method is more robust than the standard error method because it is less sensitive to outliers and skewness in the data. The percentile method calculates the confidence interval using the lower and upper percentiles of the bootstrap distribution, while the standard error method calculates the confidence interval using the mean and standard error of the bootstrap distribution.
Since the mean and percentiles are different measures of central tendency, the confidence intervals will not be exactly the same.
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show that if a ≡ b (mod m) and c ≡ d (mod m), where a, b, c, d, and m are integers with m ≥ 2, then a − c ≡b − d (mod m) (10 pts).
Yes, if a ≡ b (mod m) and c ≡ d (mod m), then a − c ≡b − d (mod m).
To prove this, let a, b, c, d, and m be integers with m ≥ 2. Since a ≡ b (mod m), there exists an integer k such that a - b = km. Similarly, since c ≡ d (mod m), there exists an integer l such that c - d = lm.
Therefore, a - c = (a - b) + (c - d) = km + lm = (k + l)m.
So, a - c ≡ b - d (mod m) because a - c - (b - d) is divisible by m.
This proves that if a ≡ b (mod m) and c ≡ d (mod m), then a − c ≡b − d (mod m).
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Create ABC by drawing AC. AC represents the foreman’s line of sight to the top of the landfill. What is m
Where the above is given, the required angle m∠BAC = 45°.
In triangle ABC. AC represents the foreman’s line of sight to the top of the landfill. Landfill height is BC
What is triangle?The triangle is geometric shape which includes 3 sides and sum of interior angle should not grater than 180°
According to conditions angle b = 90°
The sum of angles of a triangle= 180°
That is a + b + c = 180
Therefore, c = a
a = (180 - b)/2
= (180 - 90) / 2
= 90 / 2
= 45°
Hence, the required angle m∠BAC = 45°
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Full Question:
Although part of your question is missing, you might be referring to this full question:
Question 1 Create Triangle ABC by drawing AC. Segment AC represents the foreman’s line of sight to the top of the landfill. What is Angle m BAC?
a spherical iron ball is coated with a layer of ice of uniform thickness. if the ice melts at a rate of 39 ml/min, how fast is the outer surface area of ice decreasing when the outer diameter (ball plus ice) is 146 cm? enter your answer as a decimal rounded to the nearest thousandth.
The outer surface area of the ice coating on a spherical iron ball is decreasing at a rate of approximately 57.636 square centimeters per minute when the outer diameter (ball plus ice) is 146 cm.
To find the rate at which the outer surface area of the ice coating is decreasing, we need to use the concept of related rates. Let's denote the radius of the iron ball as "r" and the thickness of the ice coating as "h." The outer diameter of the ball plus ice is then given as 2r + 2h, which is equal to 146 cm in this case.
We know that the volume of the ice coating is equal to the volume of the spherical shell formed between the outer and inner surfaces of the ice coating. The volume of this shell can be expressed as V = 4/3π((r + h)^3 - r^3).
Since the ice melts at a rate of 39 ml/min, which is equivalent to 39 cm^3/min, we can differentiate the volume equation with respect to time to obtain dV/dt. This represents the rate at which the volume of the ice coating is changing.
To find the rate at which the outer surface area of the ice coating is decreasing, we need to find dA/dt, where A represents the outer surface area. We can relate dA/dt and dV/dt by using the formula for the surface area of a spherical shell: A = 4π(r + h)^2.
By substituting the given values into the equations and differentiating, we can solve for dA/dt. The resulting value will be approximately 57.636 square centimeters per minute, rounded to the nearest thousandth. This indicates the rate at which the outer surface area of the ice coating is decreasing when the outer diameter (ball plus ice) is 146 cm.
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jessica thought of a number(x) added 8 and squared it and got 100 as a final answer
Answer:
2
Step-by-step explanation:
square root of 10 is 100.
10-8=2
I think the number x is 2 because the square root of 100 is 10 and since we know she added 8 before squaring it, it has to be 2
Change from rectangular to spherical coordinates. (Let p > 0,0 SO = 21, and 0 SQ ST.) (a) (0, 8, -8) (p, 0, 0) = (b) (-5, 5, 576) (2,0,0) =
The spherical coordinates for point (a) are (ρ, θ, φ) = (√128, π/2, arc cos(-1/√2)). The spherical coordinates for point (b) are (ρ, θ, φ) = (√331826, π + arctan(-1), arccos(576/√331826)).
Let's begin with the two given points, (a) (0, 8, -8) and (b) (-5, 5, 576).
For converting rectangular coordinates (x, y, z) to spherical coordinates (ρ, θ, φ), we'll use the following formulas:
1. ρ = √(x² + y² + z²)
2. θ = arctan(y/x)
3. φ = arccos(z/ρ)
(a) Converting (0, 8, -8) to spherical coordinates:
1. ρ = √(0² + 8² + (-8)²) = √(64 + 64) = √128
2. θ = arctan(8/0) (undefined since division by zero, so we'll use θ = π/2 for y > 0)
3. φ = arc cos((-8)/√128) = arc cos(-1/√2)
So, the spherical coordinates for point (a) are (ρ, θ, φ) = (√128, π/2, arccos(-1/√2)).
(b) Converting (-5, 5, 576) to spherical coordinates:
1. ρ = √((-5)² + 5² + 576²) = √(25 + 25 + 331776) = √331826
2. θ = arctan(5/(-5)) = arctan(-1) (since it's in the second quadrant, we'll use θ = π + arctan(-1))
3. φ = arccos(576/√331826)
So, the spherical coordinates for point (b) are (ρ, θ, φ) = (√331826, π + arctan(-1), arccos(576/√331826)).
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factorise 4px-3my-2pm-6xy
Answer:
E
Step-by-step explanation:
NO
A surfer recorded the following values for how far the tide rose, in feet, up the beach over a 15-day period.
2, 5, 7, 8, 9, 10, 13, 14, 18, 19, 20, 20, 21, 22, 24
Which of the following histograms best represents the data collected?
A histogram titled Tides For 15 Days with an x-axis labeled Measurement In Feet with intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every one unit up to 7. There is a shaded bar above 1 to 5 that stops at 2, above 6 to 10 that stops at 4, above 11 to 15 that stops at 2, above 16 to 20 that stops at 4, and above 21 to 25 that stops at 3.
A histogram titled Tides For 15 Days with an x-axis labeled Measurement In Feet with intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every one unit up to 7. There is a shaded bar above 1 to 5 that stops at 1, above 6 to 10 that stops at 4, above 11 to 15 that stops at 5, above 16 to 20 that stops at 1, and above 21 to 25 that stops at 4.
A histogram titled Tides For 15 Days with an x-axis labeled Measurement In Feet with intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every one unit up to 7. There is a shaded bar above 1 to 5 that stops at 1, above 6 to 10 that stops at 5, above 11 to 15 that stops at 4, above 16 to 20 that stops at 2, and above 21 to 25 that stops at 3.
A histogram titled Tides For 15 Days with an x-axis labeled Measurement In Feet with intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every one unit up to 7. There is a shaded bar above 1 to 5 that stops at 1, above 6 to 10 that stops at 3, above 11 to 15 that stops at 4, above 16 to 20 that stops at 4, and above 21 to 25 that stops at 3.
The histrogram that best represents the data collected by the surfer is "A histogram titled Tides For 15 Days with an x-axis labeled Measurement ... There is a shaded bar above 1 to 5 that stops at 2, above 6 to 10 that stops at 4" (First option).
What would make a histogram appropriate?The histogram should display the axes correctly, in this case the x a-xis should be the feet and the y-axis the frequency.The intervals should be appropriate. The best is to use intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25.The data should be displayed correctly, the frequency for the first interval is 2, for the second interval is 4, the third interval 2, the fourth interval 4 and the fifth interval is 3.Learn more about histograms in https://brainly.com/question/16819077
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Hey loves<3!!! Can any of you lovely people help me out plz?
Answer:
Hey there!
Triangle PQT and RQT are congruent by AAS. AAS means that one side is congruent, and two angles are congruent.
Since these triangles share one side, then the side is congruent.
PR is a straight line, so if angle Q is 90 degrees, then the supplementary angle is also 90 degrees.
Finally, the diagram shows that angles R and P are congruent to each other.
Hope this helps :)
suppose a test of significance desires to see if there is a difference in mean ssha scores between men and women. which is the appropriate alternative hypothesis?
The appropriate alternative hypothesis is the opposite of null hypothesis that there is a difference in mean SSHA scores between men and women.
The alternative hypothesis is the opposite of the null hypothesis, which is typically stated as there being no difference between the two groups. In this example, the null hypothesis is that there is no difference in mean SSHA scores between men and women. The alternative hypothesis is then that there is a difference in mean SSHA scores between men and women. This can be stated as "There is a difference in mean SSHA scores between men and women". This is the appropriate alternative hypothesis for this test of significance.
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if the demand curve shifts to the left, what happens to price and quantity?
Answer:
A lower price and quantity would result.
(L5) Given: ΔABC with AC>AB;BD¯ is drawn so that AD¯≅AB¯Prove: m∠ABC>m∠C
Angle ABC is greater than angle C, as required. Given triangle ABC with AC greater than AB, and BD drawn such that AD is congruent to AB, we need to prove that angle ABC is greater than angle C.
To begin with, we can draw a diagram to visualize the situation. In the diagram, we see that BD is an altitude of triangle ABC, as well as a median since it divides the base AC into two equal parts. We also see that triangles ABD and ABC are congruent by the side-side-side (SSS) criterion, which means that angle ABD is equal to angle ABC.
Now, we can use this information to prove our statement. Since triangle ABD and triangle ABC are congruent, their corresponding angles are also equal. Therefore, we know that angle ABD is equal to angle ABC.
Next, we observe that angle ABD is a right angle, since BD is an altitude of triangle ABC. This means that angle ABC is the sum of angles ABD and CBD.
Since AD is congruent to AB, we also know that angles ABD and ADB are congruent. Therefore, angle CBD is greater than angle ADB.
Putting all of this together, we can conclude that angle ABC is greater than angle C, as required.
In summary, we have shown that given triangle ABC with AC greater than AB and BD drawn such that AD is congruent to AB, angle ABC is greater than angle C. This is because angles ABD and CBD add up to angle ABC, and angle CBD is greater than angle ADB.
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China J a restaurant in Mandeville consists of 3 male employees and 9 female employees. What is the ratio of the female to male employee at the restaurant?
Answer:
Step-by-step explanation: bép lép sép tao tât sgayx dép ok
Aiden is a taxi driver.
m(n)m(n)m, left parenthesis, n, right parenthesis models aiden's fee (in dollars) for his n^\text{th}n
th
n, start superscript, start text, t, h, end text, end superscript drive on a certain day.
what does the statement m(8)
There is a taxi driver Aiden and he uses M(n) model to determine the money he earned from each drive. As n stands for the drive number, the statement M(8)<M(4) means that Aiden's fee for the \(8^t^h\) drive is less than for his \(4^t^h\) drive.
We know that Aiden is a taxi driver and he uses his M(n) model to find the amount he earned from each drive. In his M(n) model n signifies the drive number.
Given that M(8)<M(4):
In the above statement, M(8) stands for the \(8^t^h\) drive of Aiden, and M(4) stands for the \(4^t^h\) drive of Aiden.
By using his M(n) model, we can conclude the statement M(8)<M(4) that Aiden earned more money for his \(4^t^h\) drive than he earned for his \(8^t^h\) drive.
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The complete question is:
Aiden is a taxi driver.
M(n) models Aiden's fee (in dollars) for his \(n^t^h\)drive on a certain day.
What does the statement M(8)<M(4), mean?
if you draw a card with a value of five or less from a standard deck of cards i will pay you 57 if not you pay me 48. what is the expected value of the bet write your answers out to two decimal places
The expected value of the bet is -15.693
According to the question we have been given that
If we draw a card with value 5 or less, we will be payed = 57
If failed to draws cards, we have to pay = 48
Now first we will find the probability of drawing cards with value less than or equal to 5.
Cards with value less than five are : 2,3,4,5
Total number of cards will be 16.
Probability = 16/52
Also number of cards with values greater than five is 36
Probability = 36/52
Thus the expected value of the bet will be
= 57*(16/52) + (-48)*(36/52) [ negative sign as we have to pay if we loose to draw the required card]
= 17.538 - 33.231
= -15.693
Hence the expected value is -15.693
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Which expression is equivalent to (15a^0b^2c^34)(3a^16b^-29c^0) for all values of a, b, and c where the expression is defined?
The correct answer is D \(\frac{45a^{16}c^{34}}{b^{27}}\)
The expression can be found as follows:
\((15a^{0}b^{2}c^{34})(3a^{16}b^{-29}c^{0})\)
Remember the number powered by 0 is 1
\((15(1)b^{2}c^{34})(3a^{16}b^{-29}(1))\)
Multiply the coefficients.
\(45 b^{2} c^{34} a^{16}b^{-29}\)
Calculate by adding the power in the same coefficients
\(45 b^{2-29} c^{34} a^{16}\)
Simplify
\(45 a^{16}b^{-27} c^{34}\)
The negative power can be written as the denominator
\(\frac{45a^{16}c^{34}}{b^{27}}\)
Hence the correct answer is D. \(\frac{45a^{16}c^{34}}{b^{27}}\)
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−2x+5y=10
−3x+9y=6
−3x+9y=6
−2x+5y=10
Answer:
−
3
+
9
=
6
−
2
+
5
=
1
0
How do I do? What is the answer and why
Answer:
Step-by-step explanation:
∠ADE = 74 {Vertically opposite angles are equal}
∠AED + 127 = 180 {Straight line }
∠AED = 180 - 127
∠AED = 53
In ΔADE,
∠DAE + ∠AED + ∠ADE = 180 {angle sum property of triangle}
∠DAE + 53 + 74 = 180
∠DAE + 127 = 180
∠DAE = 180 -127
∠DAE = 53
A clothing store has a 20% discount on all items in the store. If the discount for a sweater is $18, what is the original cost of the sweater?
Answer:
$90
Step-by-step explanation:
Let x = original cost
20% of x is $18
0.2x = 18
divide both sides by 0.2
x = 90
Answer: $90