what would you want individuals and communities to understand to help them avoid negatively affecting climate

The force that acts on a projectile in the horizontal direction is Gravitational force.

A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.

Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.

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Answer:

Aluminum

Explanation:

promise

give  me brainlest plleaseee

Answer:aluminum

Explanation:

Answer: Fitness assessments are designed to screen for risk of heart disease.

Explanation:

Fitness assessments are medical examinations that are designed to measure a person's physical fitness and identify any health risks they may have. These assessments may include tests of strength, endurance, flexibility, and cardiovascular fitness. One of the primary objectives of a fitness assessment is to screen for the risk of heart disease, which is a major health concern that can be prevented or treated through exercise and other lifestyle changes. While fitness assessments may identify specific injuries or medical conditions, their primary focus is on evaluating a person's overall health and fitness.

Answer:

CaO, CaMg, or CaF2

Ca2Cl, CaNa, or CaP

CaF, CaMg, or CaNa

CaO, CaF2, or CaCl2

Explanation: i think

Answer:

I’m pretty sure it’s B. It is harmful to the person and beneficial to the bacteria.

Explanation:

I’m taking the test right now. But if you think about it the bacteria is fighting off the medicine to which means the bacteria will just keep growing. So I’m 97% sure it’s B. Good luck you can do it don’t stop believing in yourself!!!!!! Hope I helped. And remember at the end of the day all that matters is love and happiness not grades!!!!!!!

Answer:

Answer is B!

Explanation:

I took the cumulative exam and got 100%

The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Answer:

4°C

Explanation:

Water is densest at 4°C.  Since dense water sinks, the bottom of the lake will be 4°C.

Answer:

Tell me why you cried, and why you lied to me

Tell me why you cried, and why you lied to me

Well I gave you everything I had

But you left me sitting on my own

Did you have to treat me, oh, so bad

All I do is hang my head and moan

Tell me why you cried, and why

Explanation:

Answer:

An object is called a horizontal projectile if it is launched from a certain height with some initial horizontal velocity only. The initial vertical velocity of such an object is zero. But as the object falls through the atmosphere the horizontal component of velocity remains constant but vertical component increases due to gravitational acceleration.

Explanation:

Answer:

i believe its 3

Explanation:

Answer:

（3x - 4）（x - 1）

Explanation:

Your question is wrong

Answer:

  -0.011176 m/s²

Explanation:

You want the acceleration in m/s² of a train that comes to rest from 30 mi/h after 20 minutes.

The acceleration is the change in velocity divided by the change in time.

  \(-\dfrac{\dfrac{30\text{ mi}}{\text{h}}}{20\text{ min}}=\dfrac{30\text{ mi}}{20\text{ h$\cdot$min}}\times\dfrac{1609.344\text{ m}}{1\text{ mi}}\times\dfrac{1\text{ h}}{60\text{ min}}\times\left(\dfrac{1\text{ min}}{60\text{ s}}\right)^2\\\\=-\dfrac{30\cdot1609.344\text{ m}}{20\cdot60^3\text{ s}^2}=\boxed{-0.011176\text{ m/s}^2}\)

Answer:

\(u=14.48m/s\)

Explanation:

From the question we are told that:

Height of window \(h=2m\)

Height of window off the ground \(h_g=7.5m\)

Time to fall and drop \(t=1.3s\)

Generally the Newton's equation motion  is mathematically given by

 \(s=ut+\frac{1}{2}at^2\)

Where

\(h=ut+\frac{1}{2}at^2\)

\(2=u1.3-\frac{1}{2}*9.8*1.3^2\)

\(2=u1.3-8.281\)

\(u=7.91m/s^2\)  

Generally the Newton's equation motion  is mathematically given by

\(2as=v^2-u^2\)

Where

\(-2gh_g=v^2-u^2\)

\(-2*9.8*7.5=(7.91)^2-u^2\)

\(-147=62.5681-u^2\)

\(u=\sqrt{209.5681}\)

\(u=14.48m/s\)

Therefore the  ball’s initial speed

\(u=14.48m/s\)

Answer:

B. Northern Canada

Explanation:

A continental polar air mass can form over the land during the winter months. In the Northern Hemisphere, it originates in northern Canada or Alaska. As it moves southward, it brings dry weather conditions to the United States. Temperature and humidity levels are both low. Hope this helps :)

The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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1. Ramp 2. He gains the maximum kinetic energy from the steepest ramp.

2. Ramp 3 which is the flattest ramp should give him the least.

3. The greater his speed, the more kinetic energy he generates.

The simplest way to explain how kinetic energy is produced is; Motion produces kinetic energy. When there is some sort of movement, there is a likelihood of kinetic energy being produced.

Mechanical, thermal, electrical, and chemical energies can all produce kinetic energy.

For example, when Mechanical labor is done,  a force acts on an item and causes it to move. This action then turns into kinetic energy.

Also, When an item is heated, the particles in it gain kinetic energy, raising its temperature.

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Answer:

The steepest ramp gives the greatest amount of kinetic energy. The flattest ramp gives the least amount of kinetic energy. The middle ramp is in between. As the skateboarder’s speed increases, so does his kinetic energy.

Explanation:

pluto

Explanation:

The range R of a projectile is given by

\(R = \frac{v_0^2}{g} \sin 2\theta\)

The maximum range \(R_{max}\) occurs when \(\sin 2\theta = 1\:\text{or}\:\theta = 45°\). Let \(\alpha\) be the angle above or below 45°. Now let's look at the ranges brought about by these angle differences.

Case 1: Angle above 45°

We can write the range as

\(R_+ = \dfrac{v_0^2}{g} \sin 2(45° + \alpha)= \dfrac{v_0^2}{g} \sin (90° + 2\alpha)\)

\(\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha + \cos 90° \sin 2\alpha)\)

\(\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(1)\)

Case 2: Angle below 45°

We can write the range as

\(R_- = \dfrac{v_0^2}{g} \sin 2(45° - \alpha)= \dfrac{v_0^2}{g} \sin (90° - 2\alpha)\)

\(\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha - \cos 90° \sin 2\alpha)\)

\(\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(2)\)

Note that the equations (1) and (2) are identical. Therefore, the ranges are equal if they differ from 45° by the same amount.

Answer:

here

Explanation:

Equilibrium is a state of a system which does not change. ... An equilibrium is considered stable (for simplicity we will consider asymptotic stability only) if the system always returns to it after small disturbances. If the system moves away from the equilibrium after small disturbances, then the equilibrium is unstable.

Answer:

iam not sure but I think its NaNO3

Answer:

Explanation:

It depends on the substance's weight/capacity.

Answer:

v = 1.098 m/s

Explanation:

Given that,

A person walks 750m due north then 250 m due east of the entire walk takes 12 min.

We need to find the average velocity of the person.

Displacement,

\(d=\sqrt{750^2+250^2} \\\\d=790.56\ m\)

Average velocity = displacement/time

\(v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s\)

So, the average velocity of the person is 1.098 m/s.

Due to light refraction, any fish in the water can see a fisherman on the bank a little more clearly than one might anticipate. When the light hits the water's surface, it “bends” down by around 13 degrees, leaving the image. Thus option A is correct.

When it reaches the surface, light emanating from the fish refracts (changes direction). When viewed from above the water, a fish appears to be closer to the surface than it actually is.

Therefore, Fred the fisherman has been told that, because of refraction, a fish in water will appear.

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Option D is correct. Frequency is the property describes the rate at which waves pass by.

Wave frequency is the number of waves that travel through a specified location in a given amount of time.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

Frequency is the property describes the rate at which waves pass by.

Hence,frequency is the right answer.

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Answer:

Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3.07 x 10^3 m/s.

Explanation:

A geosynchronous circular orbit is an orbit in which a satellite revolves around the Earth once every 24 hours so that it appears to be stationary in the sky relative to an observer on the ground. The radius of such an orbit is known as the geostationary radius and is approximately 42,164 km or 3.58 x 10^7 m above the surface of the Earth.

To find the orbital speed of a satellite in a geosynchronous circular orbit, we can use the formula:

v = (GM / r)^0.5

Where v is the orbital speed, G is the gravitational constant (6.674 x 10^-11 N m^2/kg^2), M is the mass of the Earth (5.97 x 10^24 kg), and r is the distance from the center of the Earth to the satellite (in this case, r = 3.58 x 10^7 m + radius of the Earth).

The radius of the Earth is approximately 6,371 km or 6.371 x 10^6 m. Therefore, the distance from the center of the Earth to the satellite is:

r = 3.58 x 10^7 m + 6.371 x 10^6 m

r = 4.217 x 10^7 m

Now we can plug in the values for G, M, and r into the formula and solve for v:

v = (GM / r)^0.5

v = [(6.674 x 10^-11 N m^2/kg^2) x (5.97 x 10^24 kg) / (4.217 x 10^7 m)]^0.5

v = 3.07 x 10^3 m/s

Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3.07 x 10^3 m/s.

Explanation:

The orbital speed of a satellite in a circular orbit around the Earth can be found using the following formula:

v = sqrt(G*M/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the distance from the center of the Earth to the satellite's orbit.

For a geosynchronous orbit, the satellite has a period of 24 hours, which means it completes one orbit in 24 hours. This corresponds to an orbital radius of:

R = 3.58 x 10^7 m + 6.38 x 10^6 m = 4.22 x 10^7 m

where 6.38 x 10^6 m is the radius of the Earth.

The mass of the Earth is approximately 5.97 x 10^24 kg, and the gravitational constant is approximately 6.6743 x 10^-11 N*(m/kg)^2. Substituting these values into the equation above, we get:

v = sqrt(GM/R) = sqrt(6.6743 x 10^-11 N(m/kg)^2 * 5.97 x 10^24 kg / 4.22 x 10^7 m) = 3074 m/s

Therefore, the orbital speed of a satellite in a geosynchronous circular orbit 3.58 x 10^7 m above the surface of the Earth is approximately 3074 m/s.

Answer:

the particle is at coordinates (18,15/2)

Explanation:

To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:

a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j

So the acceleration of the particle is a = 2i + 3j m/s².

To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:

r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j

We can use the kinematic equations of motion to solve this problem.

Let the acceleration of the particle be a = axî + ayj.

(a) Using the equation of motion v = u + at, where u is the initial velocity:

f = v = u + at

Substituting the given values, we get:

(91+7j) = (3î-2j) + a(3î + 3j)

Equating the real and imaginary parts, we get:

91 = 3a + 3a (coefficients of î are equated)

7 = -2a + 3a (coefficients of j are equated)

Solving these equations simultaneously, we get:

a = î(23/6) + j(1/2)

So the acceleration of the particle is a = (23/6)î + (1/2)j.

(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:

At t = 3s, the displacement of the particle is:

s = ut + (1/2)at^2

Substituting the given values, we get:

s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2

Simplifying, we get:

s = 9î + (17/2)j

So the coordinates of the particle at t=3s are (9, 17/2).

Explanation:

To determine the velocity and pressure head at position B in a horizontally converging pipe, we can use the principle of conservation of mass and Bernoulli's equation.

According to the principle of conservation of mass, the mass flow rate remains constant throughout the pipe. Therefore, we can write:

A₁V₁ = A₂V₂

where A₁ and A₂ are the cross-sectional areas at positions A and B, respectively, and V₁ and V₂ are the velocities at positions A and B, respectively.

Given:

A₁ = (π/4)(d₁)² = (π/4)(200 cm)² = 31416 cm²

A₂ = (π/4)(d₂)² = (π/4)(150 cm)² = 17671 cm²

V₁ = 2 m/s

We can calculate V₂ using the equation:

V₂ = (A₁V₁) / A₂

Substituting the values:

V₂ = (31416 cm² * 2 m/s) / 17671 cm² ≈ 3.54 m/s

Therefore, the velocity at position B is approximately 3.54 m/s.

Next, to determine the pressure head at position B, we can use Bernoulli's equation:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂² + ρgh₂

Assuming the datum is at position B, where the pressure head (h₂) is zero, the equation simplifies to:

P₁ + (1/2)ρV₁² + ρgh₁ = P₂ + (1/2)ρV₂²

Given:

g = 10 m/s² (acceleration due to gravity)

Z = 0 m (datum)

ρ = density of the liquid (not given)

Since the density (ρ) of the liquid is not provided, we cannot determine the absolute pressure at position B or calculate the pressure head. The information given is insufficient to determine the pressure head at position B.

In summary:

- The velocity at position B is approximately 3.54 m/s.

- The pressure head at position B cannot be determined with the given information.

The resultant velocity of the boat is 7.5 km/h.

The resultant displacement of the boat is calculated as follows;

Sum of the vertical displacement of the boat is calculated as;

∑Fy = -24 km sin(50)  + 8 km sin(60)

∑Fy = -11.5 km

Sum of the horizontal displacement of the boat is calculated as;

∑Fx = -24 km cos(50)  - 8 km cos(60)

∑Fx = -19.4 km

The resultant displacement is calculated as follows;

d = √ (-11.5² + 19.4²)

d = 22.55 km

The resultant velocity of the boat is calculated as follows;

v = ( 22.55 km ) / ( 3 hrs )

v = 7.5 km/h

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Answer:

62

Explanation:

it doesn't need explanation

In situations where wind speeds are over the turbine's design limit, controlling the blade pitch can help prevent overload.

The region of the circle the blades' sweeping motion through the air creates is referred to as the swept area.

The area that the propeller covers is equal to the sum of the blades' average surfaces times the number of blades.

In situations where wind speeds are over the turbine's design limit, controlling the blade pitch can help prevent overload. Once the load torque has been maintained, pitch control is utilised to adjust the rotor speed [16]. The Morten et al.

Blade velocity coefficient, also known as the coefficient of velocity or friction factor represented by K, is the ratio of vr2 to vr1 when there is friction, where vr2 will be less than vr1 when there is friction.

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