what would be the force (in n) exerted by a spring with a stiffness of 100 n/m that was compressed 0.02 m?

When an obstacle is less than a specific distance away, the sonar system's beeping becomes a continuous tone.

This distance depends on the specific sonar system being used and its settings. In general, the continuous tone indicates that the obstacle is close enough to require immediate attention or action to avoid potential hazards.When an obstacle is less than a certain distance away, typically around 2-3 feet, the sonar system's beeping becomes a continuous tone. This indicates that the obstacle is very close and immediate action is required to avoid a collision.

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Answer:

6.78 m/s

Explanation:

We can use the law of conservation of momentum to solve this problem. According to this law, the total momentum of a system is conserved in the absence of external forces. In this case, the system consists of the truck and the parked car.

Before the collision, the momentum of the truck is given by:

p1 = m1 * v1 = 130 kg * 12 m/s = 1560 kg*m/s

The momentum of the parked car is zero since it is not moving.

The total momentum of the system before the collision is therefore:

p1_total = p1 + p2 = 1560 kg*m/s

After the collision, the two objects stick together and move with a common velocity, which we will call v_final. The total mass of the system is:

m_total = m1 + m2 = 130 kg + 100 kg = 230 kg

The total momentum of the system after the collision is:

p2_total = m_total * v_final

According to the law of conservation of momentum, p1_total = p2_total. Therefore:

1560 kg*m/s = 230 kg * v_final

Solving for v_final, we get:

v_final = 1560 kg*m/s / 230 kg = 6.78 m/s

Therefore, the final velocity of the two objects after the collision is 6.78 m/s.

Explanation:

m1 of the truck: 130 kg

m2 of the car: 100 kg

v1 of the truck: 12 m/s

vf?

use the formula:

(m1×v1) + (m2×v2) = (m1+m2)vf

so

\(vf = \frac{(m1 \times v1) + (m2 \times v2)}{(m1 + m2)} \)

\(vf = \frac{(130 \times 12) + (100 \times 0)}{(130 + 100)} \)

vf = 1560 ÷ 230 = 6,7 m/s

Answer:

2000J

Explanation:

The formula for work is W=Force x Distance

W=FxD

W=500N x 4m

W=2,000 Joules

Answer:

Planets that are farther from the sun than the earth (all but Mercury and Venus) will exhibit retrograde motion.

If the position of the planet is observed relative to the background stars, the planet will appear to move backward relative to the stars when the earth is moving in an Eastward direction faster than the planet, and the planet appears to move backwards relative to the stars

(The planet will be on the side of the earth that is opposite that of the sun)

The statement "The government (FCC) regulates the frequencies in the electromagnetic spectrum that can be used for wireless communication" is true.

The government, specifically the Federal Communications Commission (FCC) in the United States, regulates the frequencies in the electromagnetic spectrum that can be used for wireless communication.

The electromagnetic spectrum encompasses a wide range of frequencies, from radio waves to microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. The FCC allocates and manages these frequencies to ensure efficient and coordinated use of the spectrum by various wireless communication devices, including cell phones, Wi-Fi routers, radios, and other wireless technologies.

By regulating the spectrum, the FCC aims to prevent interference between different wireless devices and ensure reliable and secure communication. These regulations help in maintaining order, maximizing spectrum utilization, and promoting fair access to wireless communication resources.

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Complete question :

The government (FCC) regulates the frequencies in the electromagnetic spectrum that can be used for wireless communication. T/F

Stopping drug use before it starts (Priority I) as set by the White House Office of National Drug Control Policy would be considered in the category of Prevention strategies.

Stopping drug use before it starts is a primary focus of prevention strategies aimed at reducing drug abuse and addiction. The White House Office of National Drug Control Policy categorizes this objective as Priority I, emphasizing its significance in addressing drug-related issues. Prevention efforts prioritize educating individuals, particularly young people, about the risks and consequences of drug use, promoting healthy behaviors, and providing resources and support to prevent initiation of drug use. By targeting prevention as a top priority, policymakers and organizations aim to reduce the demand for drugs and ultimately mitigate the harms associated with substance abuse.

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Answer:

ΔT = 28.667°C is the answer.

Explanation:

Given,

Mass of water = 4.0 kg

Water is heated by = 8 × 10² W = 800 W

Time = 10 min = 10 × 60 = 600 s

Now,

using the equation of specific heat,

Q = mcΔT

where c is the specific heat capacity of water = 4186 J/kg°C

Q = Pt

Substituting,

Pt = mcΔT

800 × 600 = 4 × 4186 × ΔT

480000 = 16744 × ΔT

ΔT = 28.667

∴Temperature increased, ΔT = 28.667°C

Answer:

Divide the number of times an event occurs by the duration of time to calculate frequency. For instance, Anna divides the number of webpage clicks (236) by the time spent on the site (one hour, or 60 minutes). She discovers that she gets 3.9 clicks every minute.

Explanation:

does this help?

Answer:

1. 571.43m/s

2. 142.9m and 342.9m

Explanation:

1.Take the difference in time.

1.2-0.7=0.7 seconds

Take the distance between them and divide with differnce in time.

400÷0.7=571.43 seconds.

2.Take the time of the two men and divide by two.

0.5÷2= 0.25 secs

1.2÷2= 0.6 secs

multiply each with the velocity.

0.25×571.43=142.9m

0.6×571.43=342.9m

Graph A, because distance-time graph is a straight line parallel to the time-axis because the position of the object does not change when it is at rest.

Distance is the length between two points or items, and it is directionless. Since distance is a scalar attribute, it only takes into account the overall magnitude and ignores the start and end locations. Being a scalar attribute, distance may only be positive or zero; it cannot be the opposite.

Although kilometers (km) and centimeters (cm) or millimeters (mm) can also be used to express shorter distances, the meter (m) is the most used unit of measurement for distance (mm). When calculating distance, the letter D is usually used to denote the distance traveled.

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Answer:

1. 4

2.0.625HZ

3.500

4. 428274940000000 or 4.2*10^14

5. 2

Explanation:

omnicalculator.com/physics/wavelength

The ball's initial velocity is 25.9m/s

A table's top is horizontally rolled off by a ball. The ball hits the ground at a final velocity of -3.5 m/s after 3 seconds. (Presume that a=-9.8 m/s2)

from above statement we got

final velocity= -3.5 m/s.

acc= -9.8 m/s²

t=3 seconds

now:

we will use kinematic equation

v=u+at, in this v is final velocity, u is initial velocity,t is time and a is acc

now put all the given values in  kinematic equation

-3.5 = u+( -9.8)(3 )

-3.5=u-29.4

u=25.9m/s

so the  initial velocity is  25.9m/s

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With the use of vertical motion formula, the shirt will take 3 s to reach the top of its arc. And the maximum height reached is 44.7 m

The motion of an object under is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a cheerleader launches a t-shirt from an air gun. The shirt leaves the gun with a speed of 29 m/s.

A. Ignoring air resistance, the time it will take the shirt to reach the top of its arc can be found by using the equation

v = u - gt

Where

Substitute all the parameters into the equation

0 = 29 - 9.8t

9.8t = 29

t = 29/9.8

t = 2.96 s

t = 3 s approximately

B. Ignoring air resistance, if the cheerleader launches with an initial height of 1.75m, let us first calculate the maximum height reached by the shirt by using the formula

v² = u² - 2gH

At maximum height, v = 0

0 = 29² - 2 × 9.8 × H

0 = 841 - 19.6H

19.6H = 841

H = 841/19.6

H = 841/19.6

H = 42.9 m

The maximum height reached = 42.9 + 1.75 = 44.7 m

Therefore, the time taken for the shirt to reach the top of its arc is 3 s  and the maximum height reached is 44.7 m

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Answer:

a total of four nodes and three antinodes

Explanation:

please tell me if im incorrect i will fix it asap.

In the given scenario, when a body of mass m rests on a horizontal plane with the static and kinetic friction coefficients both equal to y, the maximum force of static friction that can act on the body is equal to y times the normal force.

The static friction coefficient represents the maximum frictional force that can be exerted on an object at rest, while the kinetic friction coefficient represents the frictional force acting on an object in motion. In this case, since the body is at rest, the static friction force is relevant.

The maximum force of static friction can be calculated by multiplying the static friction coefficient (y) by the normal force. The normal force is equal to the weight of the body (m multiplied by the acceleration due to gravity). Therefore, the maximum force of static friction is given by y times the weight of the body.

This maximum force of static friction acts in the opposite direction to the applied force or the force attempting to move the body. As long as the applied force does not exceed the maximum force of static friction, the body will remain at rest. However, if the applied force exceeds this maximum force, the body will start to move and the frictional force will transition to the kinetic friction force.

It is important to note that in this scenario, the static and kinetic friction coefficients are equal (both y). This assumption simplifies the calculations and implies that the magnitude of the frictional force remains constant regardless of the motion of the body.

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A parallel-plate capacitor has capacitance Co = 8.50 pf when there is air between the plates. The separation between the plates is 1.30 mm Part A What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 104 .(a)the maximum magnitude of charge that can be placed on each plate is approximately 3.32 x 10^(-10) C.(b) 9.28 x 10^(-10) C.

Part A:

The maximum magnitude of charge that can be placed on each plate of a parallel-plate capacitor can be determined using the formula:

Q = C * V

where Q is the charge, C is the capacitance, and V is the voltage across the capacitor.

Given:

Capacitance (Co) = 8.50 pF = 8.50 x 10^(-12) F

Separation between the plates (d) = 1.30 mm = 1.30 x 10^(-3) m

Maximum electric field (E) = 3.00 x 10^4 V/m

We can calculate the maximum voltage (V) using the formula:

E = V/d

Substituting the given values:

V = E * d

= (3.00 x 10^4 V/m) * (1.30 x 10^(-3) m)

= 3.90 x 10^1 V

Now, we can calculate the maximum magnitude of charge (Q) using the formula:

Q = C * V

= (8.50 x 10^(-12) F) * (3.90 x 10^1 V)

≈ 3.32 x 10^(-10) C

Therefore, the maximum magnitude of charge that can be placed on each plate is approximately 3.32 x 10^(-10) C.

Part B:

When a dielectric is inserted between the plates of the capacitor, the capacitance increases according to the formula:

C' = K * Co

where C' is the new capacitance, K is the dielectric constant, and Co is the original capacitance.

Given:

Dielectric constant (K) = 2.80

The new capacitance (C') can be calculated as:

C' = K * Co

= (2.80) * (8.50 x 10^(-12) F)

= 2.38 x 10^(-11) F

Using the same maximum electric field (E) as before, we can calculate the maximum voltage (V') using the formula:

E = V'/d

V' = E * d

= (3.00 x 10^4 V/m) * (1.30 x 10^(-3) m)

= 3.90 x 10^1 V

Finally, we can calculate the new maximum magnitude of charge (Q') using the formula:

Q' = C' * V'

= (2.38 x 10^(-11) F) * (3.90 x 10^1 V)

≈ 9.28 x 10^(-10) C

Therefore, the new maximum magnitude of charge that can be placed on each plate, when a dielectric with K = 2.80 is inserted, is approximately 9.28 x 10^(-10) C.

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Answer:

\(\boxed {\boxed {\sf D. \ 6.02*10^{23} \ atoms}}\)

Explanation:

One mole of a substance contains the same amount of representative particles. These particles can be atoms, molecules, ions, or formula units. In this case, the particles are atoms of titanium.

Regardless of the particles, there will always be 6.02*10²³ (also known as Avogadro's Number) particles in one mole of a substance.

Therefore, the best answer for 1 mole of titanium is D. 6.02*10²³ atoms.

Answer:

D) 6.02 x 1023

Explanation:

A.P.E.X

(a) The inductive reactance in the circuit is 65.94 Ω.

(b) The capacitive reactance in the circuit is 539.51 Ω.

(c) The impedance of the circuit is in kiloohms.

(d) The resistance in the circuit is 2.23 kiloohms.

(e) The phase angle between the current and the source voltage is 21.2°.

(a) The inductive reactance (XL) can be calculated using the formula XL = 2πfL, where f is the frequency (50.0 Hz) and L is the inductance (210 mH = 0.210 H). Substituting the values, we find XL = 65.94 Ω.

(b) The capacitive reactance (XC) can be calculated using the formula XC = 1/(2πfC), where C is the capacitance (5.90 pF = 5.90 x 10^(-12) F). Substituting the values, we find XC = 539.51 Ω.

(c) The impedance (Z) of the circuit is the total opposition to the flow of current and is given by the formula Z = √(R^2 + (XL - XC)^2), where R is the resistance. Since the impedance is in kiloohms, we need to convert the resistance to kiloohms (110 mA = 0.110 A). Substituting the values, we find the impedance of the circuit.

(d) The resistance in the circuit is given as the maximum current (110 mA = 0.110 A) divided by the maximum voltage (AVmax = 240 V), resulting in a resistance of 2.23 kiloohms.

(e) The phase angle (θ) between the current and the source voltage can be calculated using the formula θ = arctan((XL - XC)/R). Substituting the values, we find the phase angle to be 21.2°.

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Answer:

The correct option is;

How loud or soft the sound is

Explanation:

The loudness of a sound wave is given by the amount of energy that the pressure wave carries and it is measured in decibels (dB) which is the relative intensity of the pressure wave of a sound to the standard pressure

A loud sound has a high amplitude and a soft sound has a low amplitude, such that as the amplitude of the sound is increased, due to increased energy input, the sound becomes louder, and as the amplitude of the sound is decreased due to reduced energy input, the sound becomes softer.

The approximate TOD of the victim is Maybe around 4:30 pm.

The liver temperature can provide a more accurate representation of the genuine core body temperature, hence it is ideal to take the temperature either rectally or by monitoring the liver temperature.To do this, a tiny incision must be made in the right upper belly, and the thermometer must be inserted into the liver tissue.

This stiffening process, known as rigor mortis, occurs at a fairly known time, making it possible to predict when someone will pass away.In overall: If the body is warm and there is no rigidity, the time of death was less than three hours ago.If the body is stiff and warm, death happened 3 to 8 hours earlier.

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The ratio of the mass of an electron to its rest mass when it is moving with a kinetic energy of 20 MeV can be calculated using the equation of special relativity and assuming that the speed of the electron is much less than the speed of light. The result is that the mass of the electron is 39.22 times its rest mass.

The ratio of the mass of an electron to its rest mass can be calculated from its kinetic energy using the equation of special relativity, which states that the total energy of an object is equal to its rest mass multiplied by the square of the speed of light, plus its kinetic energy.

The rest mass of an electron is 0.51 MeV, so its total energy is given by:

\(E\) = \(0.51 MeV*c^{2} + KE\)

Where c is the speed of light, and KE is its kinetic energy.

Since the kinetic energy of the electron is 20 MeV, we have:

\(E = (0.51 MeV) * (c²) + 20 MeV\)

And the total energy can be divided by the rest mass of the electron and the square of the speed of light to obtain the ratio of its mass to its rest mass:

 \(m/m0\) = \(\frac{E}{0.51 MeV * c^{2} }\)

\(m/m0\) = \(\frac{0.51 MeV*c^{2} + 20 MeV}{0.51 MeV }\)

We can simplify the calculation by assuming that the speed of the electron is much less than the speed of light, so that we can ignore the term (0.51 MeV * c^2).

In that case, we have:

\(m/m0\) = \(\frac{20MeV}{0.51MeV}\)

\(m/m0 = 39.22\)

So the ratio of the mass of an electron to its rest mass when it is moving with a kinetic energy of 20 MeV is 39.22.

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Answer:

η = 0.882 = 88.2 %

Explanation:

The efficiency of the pulley system can be given as follows:

\(\eta = \frac{W_{out}}{W_{In}}\\\\\)

where,

η = efficiency of pulley system = ?

W_out = Output Work = (600 N)(0.6 m) = 360 J

W_in = Input Work = (35.7 N)(11.43 m) = 408.051 J

Therefore,

\(\eta = \frac{360\ J}{408.051\ J}\)

η = 0.882 = 88.2 %

The weight of the log is 980N

The force of gravity acting on an object is its weight, which is equal to its mass times the acceleration of gravity, or w = mg. The newton is the SI unit for weight since it is a force.

The weight of a 100 kg log can be calculated using the equation w = mg,

where m is the mass of the log (100 kg) and g is the acceleration due to gravity (9.8 m/s^2).

So, w = (100 kg)(9.8 m/s^2) = 980 N.

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The net force on particle q3 is -3.49 x 10^-3 N.

The net force on particle q3 can be calculated by considering the electric forces between q3 and each of the other particles, and then adding them vectorially. The electric force between two charged particles can be calculated using Coulomb's law:

\(F = k * |q1 * q2| / r^2\)

where k is Coulomb's constant (8.9875 x 10^9 N * m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the separation between the charges.

First, let's calculate the electric force between q3 and q2:

\(F12 = k * |-84.2 uC * 90.6 uC| / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 uC^2) / (0.432 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (7583.792 x 10^-6 C^2) / (0.432 m)^2\\= 3.05 x 10^-3 N\)

Next, let's calculate the electric force between q3 and q1:

\(F13 = k * |-84.2 uC * -75.8 uC| / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 uC^2) / (0.876 m)^2\\= 8.9875 x 10^9 N * m^2/C^2 * (6399.756 x 10^-6 C^2) / (0.876 m)^2\\= -6.54 x 10^-3 N\)

Finally, the net force on particle q3 is given by the vector sum of the individual forces:

Fnet = \(F12 + F13 = 3.05 x 10^-3 N - 6.54 x 10^-3 N = -3.49 x 10^-3 N\)

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The acceleration of the plane is 8 m/s² while covering a distance of 1.20 km in 5 seconds.

To find the acceleration of the plane, we can use the following equation:

Acceleration (a) = (Final velocity (v) - Initial velocity (u)) / Time (t)

First, we need to convert the distance from kilometers to meters:

1.20 km = 1.20 × 10³ m

Given:

Initial velocity (u) = 2.00 × 10² m/s

Final velocity (v) = 2.40 × 10² m/s

Distance (s) = 1.20 × 10³ m

Using the formula for acceleration, we can rearrange it to solve for acceleration:

a = (v - u) / t

Since the airplane is flying level, we assume a constant velocity, so the time (t) can be calculated as:

t = s / v

Plugging in the values:

t = (1.20 × 10³ m) / (2.40 × 10² m/s) = 5 seconds

Now we can calculate the acceleration:

a = (2.40 × 10² m/s - 2.00 × 10² m/s) / 5 s = 8 m/s²

Therefore, the acceleration of the plane must be 8 m/s².

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For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.

The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.

When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.

\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)

Substituting the known values:

\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)

Solving for m₂:

\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)

The mass of the right block must be 7.9 kg for the two blocks to remain stationary.

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The question is -

Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg

The first situation that the bird is giving force to its wings to fly , it is related to the first law. The second one the coffee cup stay on rest until any force acts on it is related to the first law.

Newton's first law of motion states, every objects tends to stay in its current  state until an external force acts on it. The second law states that, the force is the product of mass and acceleration. Thus, greater is the mass greater force is needed to accelerate an object.

Third law of motion states that, for every action there is an equal and opposite reaction.

The sailor when pushing the boat, the boat is exerting a force in turn and the man can slide to the land and boat moves away. This is third law of motion.

As the force by the wind increases, its acceleration increases . This is second law. The team with greater mass in tug of war game will  have greater force that is just the second law.

The skater board tends to move again even after the hitting, its is first law of Newton.

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Answer:

it is b on edge not d, well atleast for me it was b

Explanation:

Answer:

B) one battery, two switches, and three light bulbs

Explanation: