What will happen to an object whose tangential velocity at closest approach about the earth is less than the circular velocity?

The equilibrium constant for the reaction at 25°C is 6.50.

What is Equilibrium?

In a broad sense, equilibrium refers to a state of stability or balance in a system where opposing forces or elements are in proportionately equal or balanced amounts, resulting in a state of rest or unchanging conditions. It is a notion that is frequently applied in a number of disciplines, such as physics, chemistry, economics, and social sciences.

The relationship between the standard free-energy change and the equilibrium constant is given by the following equation:

ΔG° = -RT ln K

where ΔG° is the standard free-energy change, R is the gas constant (8.314 J K⁻¹ mol⁻¹ or 1.987 cal K⁻¹ mol⁻¹), T is the temperature in kelvin, and K is the equilibrium constant.

First, we need to convert the standard free-energy change from kilojoules per mole to joules per mole:

ΔG° = -12.50 kJ mol⁻¹ = -12,500 J mol⁻¹

Next, we need to convert the temperature from Celsius to kelvin:

T = 25°C + 273.15 = 298.15 K

Now we can plug these values into the equation and solve for K:

ΔG° = -RT ln K

-12,500 J mol⁻¹ = -(8.314 J K⁻¹ mol⁻¹)(298.15 K) ln K

ln K = (-12,500 J mol⁻¹) / [-(8.314 J K⁻¹ mol⁻¹)(298.15 K)]

ln K = 1.871

\(K = e^{(ln K)} = e^{(1.871)} = 6.50\)

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Answer:

False you dont repaint your hamster.

Explanation:

LOL

The planetary temperature energy balance is obtained by radiating back the absorbed radiation energy from outer-space, by the planet and thus acquiring thermal equilibrium.

What is the process of attaining thermal equilibrium by Earth?

The Stefan-Boltzmann law states that the more the temperature a planet has, the more it will radiate out to reach thermal equilibrium.

We know that outer space contains large masses of radiative energy freely distributed in its vast expanse. A small fraction of this energy is absorbed by the Earth through the atmosphere, surface land, clouds etc.

Now, radiative balance is achieved when a planet's surface continuously warms up until it reaches its peak at which point the same amount of absorbed energy can then be radiated back to space. The relative amount of energy radiated back by a planet is dependent upon the size of the planet.

A colder planet relatively absorbs lower amount of radiation energy from space. In some time, as the planet heats up enough, the energy is radiated back to the space attaining thermal equilibrium.

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Answer:

The speed is 1.35 m/s

Explanation:

(m1+m2) vi= m1+m2v2

(50+1.5) (3.5)=50 (5+v2) +1.5 v2

180.25= 250+ 51.5 v2

180.25- 250+ 51.5 v2

-69.75= 51.5 v2

v2= -1.35 m

Answer:

Explanation:

I dont understand what its saying .....?

Answer:

The answer for this question is B water vapor

Explanation:

just trust me bro

Answer:

Visible light lies at the center of the electromagnetic spectrum

(infrared has longer wavelength than visible light and ultraviolet has shorter wavelengths than visible light)

Of the last three only infrared light with long wavelengths and low photon energy can be true. (Along with the first two)

(Radio waves are of the order of meters with low photon energies)

When the Earth is at point C, Equinox happens.

In Equinox, the Sun is directly above the equitor making day and night equal in both hemispheres.

Answer:

frequency is equal to the wavelength multiply by the speed of light

Explanation:

wavelength multiply by the speed of light Will give you the frequency

Answer:

current must flow and chemical energy must take place

Answer:

Explanation: 6 m / s , with the center of the ball leaving the racquet horizontally 2 . 37 m above the court surface. The net is 12 m away and 0 . 90 m high.

Answer:

C. 29.21 m³

Explanation:

Given the following data;

To find the final volume, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

\( P_{1}V_{1} = P_{2}V_{2} \)

Making V2 the subject of formula, we have;

\( V_{2} = \frac {P_{1}V_{1}}{P_{2}} \)

Substituting the values into the formula, we have;

\( V_{2} = \frac {18.9 * 3.4}{2.2} \)

\( V_{2} = \frac {64.26}{2.2} \)

Final volume, V2 = 29.21 m³

Answer:

The momentum of the steel ball is 0.28 kg m/sec.

Explanation:

The momentum of an object can be calculated using the formula: momentum = mass x velocity. In this case, the mass of the steel ball is 100 g, which is equivalent to 0.1 kg. The velocity of the ball is 2.8 m/sec. Plugging in the values into the formula, we get:

momentum = 0.1 kg x 2.8 m/sec

momentum = 0.28 kg m/sec

So the momentum of the steel ball is 0.28 kg m/sec.

One and a half miles of distance  is required for a train to stop when traveling 50 miles per hour.

Rate of change in position, or speed, is equal to distance traveled divided by time. To solve for time, divide the distance traveled by the rate.

Rearranging the formula,

Speed = distance / time.

Distance = speed × time.

Time = distance / speed.

Hence,

Distance = Speed × Time

⇒ Distance = 50 × 60 / 2000

⇒ Distance = 1.5 miles

⇒ Thus, the distance which is required to stop a train is 1.5 miles, which is, One and a half miles.

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Largest-size vehicle (kg) it can lift if the diameter of the output and maximum gauge pressure is given is 0.455 * 10³ kg.

Pressure that is measured relative to ambient atmospheric pressure is called gauge pressure. Gauge pressure can be measured using a diaphragm sensor in which one side of the diaphragm is exposed to the pressure media that is to be measured and the other side gets exposed to ambient atmospheric pressure.

Given the diameter of the piston = 25.5 cm,

radius = 12.75 cm= 0.1275 m

Area of the piston is;

A=  πr²

= 3.14 * (0.1275)²

=0.051 m²

Given maximum pressure of the lift= 17 atm

p =1.72 * 10⁶ Pa

Maximum force that piston can lift:

F= p * A

=  1.72 * 10⁶ *( 0.051 )²

= 4.47 * 10³ N

Size of the vehicle :

m = F/g

=  4.47* 10³/ 9.81

mass = 0.455 * 10³ kg

Largest-size vehicle that it can lift is 0.455 * 10³ kg.

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True. The active elements of fractal computation are indeed the pixels, which are the individual units that make up a digital image.

Fractal computation involves performing complex calculations and iterations on these pixels to generate the intricate patterns and structures that characterize fractals.

True. In the context of fractal computation, the active elements are the pixels, as they represent the individual data points that are calculated and displayed to form the fractal image.

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A. Electrical energy  B. Elastic energy  are the forms of potential energy.

Potential energy is the energy possess by an object because due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

Types of Potential energy:

Therefore,

Electrical energy , Elastic energy are the forms of potential energy.

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Distance be s

\(\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2\)

\(\\ \sf\longmapsto s=0(38.5)+\dfrac{1}{2}(2.9)(38.5)^2\)

\(\\ \sf\longmapsto s=1.45(1482.25)\)

\(\\ \sf\longmapsto s=2149.26m\)

Answer:

The rotational kinetic energy of the system is 448.6276 kg * m^2/s^2.

Rotational kinetic energy is the energy that an object possesses due to its rotation about an axis. It is a form of mechanical energy that is associated with the motion of a rotating body.

The moment of inertia of the system about the x axis can be calculated using the formula for the moment of inertia of a system of particles:

I = Σ (mi * ri^2)

where

mi = mass of particle i

ri = distance from particle i to the axis of rotation (in this case, the x axis)

Substituting the values for the masses and distances, we get:

I = (4.60 kg * (3.45 m)^2) + (2.30 kg * (-2.30 m)^2) + (3.45 kg * (-4.60 m)^2)

= (4.60 kg * 11.9225 m^2) + (2.30 kg * 5.29 m^2) + (3.45 kg * 21.16 m^2)

= 55.7927 kg * m^2

So, the moment of inertia of the system about the x axis is 55.7927 kg * m^2.

The rotational kinetic energy of the system can be calculated using the formula:

K = 0.5 * I * ω^2

where

ω = angular speed (4.00 rad/s)

Substituting the values for I and ω, we get:

K = 0.5 * (55.7927 kg * m^2) * (4.00 rad/s)^2

= 0.5 * 55.7927 kg * m^2 * 16.00 (rad/s)^2

= 448.6276 kg * m^2/s^2

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Chandragupta Maurya was an emperor of the Indian subcontinent who stood out for unifying much of the territory and establishing a strong and stable government.

Chandragupta Maurya (340 BC-293BC), was a leader who stands out as the founder of the Maurya Empire where he unified most of the territory of the Indian subcontinent. Therefore, he is considered the first authentic emperor of India.

In general, Chandragupta Maurya's rule was noted for he conquered the Nanda dynasty's territory in the north of the Indian subcontinent and continued to join new territories to his empire.

This empire also annexed the Pandya and Cheras kingdoms in South India. However, they thus preserved their independence and accepted the supremacy of the Mauryan emperor.

Additionally, this empire was characterized by having a very strong central government that ruled from the capital city of Pataliputra (now near Patna).

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Answer:

9.1 mph

Explanation:

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The astronaut's height, as measured from the space station, will appear contracted due to relativistic effects. Due to relativistic length contraction, the astronaut's height, as measured from the space station, appears to be approximately 3.52 meters.

According to the theory of special relativity, objects in motion relative to an observer will experience length contraction along the direction of motion. In this case, the spaceship is moving at a speed of 0.9 times the speed of light (0.9 c) relative to the space station.

The length contraction factor, denoted by γ, can be calculated using the Lorentz factor:

γ = 1 / √(1 - v²/c²)

Where v is the velocity of the spaceship and c is the speed of light. Plugging in the values, we have:

γ = 1 / √(1 - 0.9²)

γ ≈ 1.92

To determine the astronaut's height as measured from the space station, we multiply her actual height by the length contraction factor:

Height (as measured from the space station) = Actual height × γ

Height (as measured from the space station) = 1.83 m × 1.92

Height (as measured from the space station) ≈ 3.52 m

Therefore, due to relativistic length contraction, the astronaut's height, as measured from the space station, appears to be approximately 3.52 meters.

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To calculate the total heat required to change the state of beryllium from a solid at 914°C to a liquid at 1285°C, we need to consider the heat required for two processes.

Given data:

Molar mass of beryllium, B = 9.01 g/mol

Density, d = 1820 kg/m³

Melting point of beryllium, T1 = 1285 °C (Correction: The given melting point should be 1285°C, not 914°C)

Specific heat capacity of beryllium, c = 1.82 J/g°C

Boiling point of beryllium, T2 = 2469 °C

Heat of fusion of beryllium, L = 135 x 10³ J/kg

Mass of beryllium, m = 1.073 kg

Melting point of beryllium, T1 = 1285 °C (Correction: The given melting point should be 1285°C, not 914°C)

Boiling point of beryllium, T2 = 2469 °C

Specific heat capacity of beryllium, c = 1.82 J/g°C

Heat of fusion of beryllium, L = 135 x 10³ J/kg

1. Heat required for the phase change from solid to liquid at the melting point (Q1):

Q1 = mL

Q1 = 1.073 kg × (135 × 10³ J/kg)

Q1 = 144,855 J

2. Heat required to raise the temperature of the liquid beryllium from its melting point to the boiling point (Q2):

Q2 = mcΔT

Q2 = 1.073 kg × 1000 g/kg × 1.82 J/g°C × (2469 - 1285) °C

Q2 = 1,747,586.4 J

The total heat required is the sum of Q1 and Q2:

Total heat = Q1 + Q2

Total heat = 144,855 J + 1,747,586.4 J

Total heat = 1,892,441.4 J

Therefore, the amount of heat in joules that must be added to 1.073 kg of beryllium to change it from a solid at 914°C to a liquid at 1285°C is approximately 1,892,441.4 J.

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Answer:

Notice that for all substances, the heat of vaporization is substantially higher than the heat of fusion. Much more energy is required to change the state from a liquid to a gas than from a solid to a liquid.

Gaseous water would require the most heat to produce a temperature change.

Intermolecular force is defined as the force of attraction existing between the neighboring molecules in a container that holds the together.

Here,

Evaporation is the process of conversion of liquid water into gaseous water vapor.

Condensation is the process of conversion of gaseous water vapor into liquid water.

Condensation occurs under higher temperature than that of evaporation. Condensation requires more temperature because the energy for separating the molecules in the gaseous state is comparatively higher. In order to convert the gaseous state into liquid state, it requires a greater intermolecular forces so that the gaseous molecules are brought more closer. The intermolecular force needed for the process of evaporation is lesser when compared to condensation. So, the heat required in evaporation is comparatively less.

Hence,

Gaseous water would require the most heat to produce a temperature change.

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The Pythagorean Theorem states that the squares on the hypotenuse (the side across from the right angle) of a right triangle, or, in standard algebraic notation, a2 + b2, are equal to the squares on the legs.

The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a fundamental relationship between a right triangle's three sides in Euclidean geometry. According to this rule, the areas of the squares on the other two sides add up to the area of the square whose side is the hypotenuse, or the side across from the right angle. The Pythagorean equation, which is typically used to express this theorem, can be expressed as an equation linking the lengths of the legs (a, b), and the hypotenuse (c):

There are several ways to generalize the theorem, including to higher-dimensional spaces, non-Euclidean spaces, objects other than right triangles, and even things that are not triangles at all but n-dimensional solids. The Pythagorean theorem has garnered interest outside of mathematics as a representation of mathematical mystique, power, or obscurity; there are numerous references to it in popular works of fiction, dramas, musicals, songs, stamps, and cartoons.

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