What type of energy is stored in a battery?
pls give all the possible answer and pls if you can give an explanation

thx I'm really stuck​

Answer:

Explanation:

1 Object C has an acceleration that is greater than the acceleration for D.

2 B

3 17M

4 The velocity is zero.

5 a straight line with negative slope

just took it

Answer:

B. the Big Bang

Explanation:

Answer:

When the early universe cooled enough for atoms to form, Nucleosynthesis began.

hope it helps!

Answer:

Approximately \(1.69 \times 10^{30}\; \rm kg\).

Explanation:

Let \(M\) and \(m\) denote the mass of the star and the planet, respectively.

Let \(G\) denote the constant of universal gravitation (\(G \approx 6.67408 \times 10^{-11}\; \rm m^{3} \cdot kg^{-1}\cdot s^{-2}\).)

Let \(r\) denote the orbital radius of this planet (assuming that \(r\!\) is constant.) The question states that \(r = 1.65 \times 10^{10}\; \rm m\).

The size of gravitational attraction of the star on this planet would be:\(\displaystyle \frac{G \cdot M \cdot m}{r^{2}}\).

If attraction from the star is the only force on this planet, the net force on this planet would be \(\displaystyle \frac{G \cdot M \cdot m}{r^{2}}\).

Let \(\omega\) denote the angular velocity of this planet as it travels along its circular orbit around the star. The size of \(\omega\!\) could be found from the period \(T\) of each orbit: \(\omega = (2\, \pi) / T\).

In other words, this planet of mass \(m\) is in a circular motion with radius \(r\) and angular velocity \(\omega\). Therefore, the net force on this planet should be equal to \(m \cdot \omega^2 \cdot r\).

Hence, there are two expressions for the net force on this planet:

Equate the right-hand side of these two equations:

\(\displaystyle \frac{G \cdot M \cdot m}{r^2} = {\left(\frac{2\pi}{T}\right)}^{2}\, m \cdot r\).

Simplify this equation and solve for \(M\), the mass of the star:

\(\displaystyle M = \frac{{(2\pi / T)}^2 \cdot r^3}{G}\).

Notice that \(m\), the mass of the planet, was eliminated from the equation. That explains why this question could be solved without knowing the exact mass of the observed planet.

Convert the orbital period of this star to standard units:

\(\begin{aligned}T &= 14.5\; \text{day} \times \frac{24\; \text{hour}}{1\; \text{day}} \times \frac{3600\; \text{second}}{1\; \text{hour}} \\ & = 1.2528 \times 10^{6}\; \rm \text{second}\end{aligned}\).

Calculate the mass of the star:

\(\begin{aligned} M &= \frac{{(2\pi / T)}^2 \cdot r^3}{G} \\ &\approx \frac{\displaystyle {\left(\frac{2\pi}{1.2528 \times 10^{6}\; \rm s}\right)}^{2} \times \left(1.65 \times 10^{10}\; \rm m\right)^{3}}{6.67408 \times 10^{-11}\; \rm m^{3}\cdot kg^{-1} \cdot s^{-2}}\\ &\approx 1.69 \times 10^{30}\; \rm kg\end{aligned}\).

The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The resultant force of both forces is 15.62 N.

The Resultant of forces is a single force obtained when two or more forces are combined.

To calculate the resultant of the force, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the resultant force of both forces is 15.62 N.

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Using the parallelogram law of vectors to obtain the resultant, we have the value 16 N.

The resultant force is that force that has the same effect in magnitude and direction as two forces acting together. In this case, we have two forces , 8 N and 10 N inclined at an angle of 120 degrees

Using the parallelogram law of vectors to obtain the resultant;

R = √([8²+10²)-2×8×10cos120°]

R = √164 +80

R = 16 N

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The time takes the kid to remain in the air is 0.735 s.

Time is the duration of an events. The s.i unit of time is seconds.

To calculate how long the kid will be in the air, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the time is 0.735 s.

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The total quantity of an economy's final goods and services demanded at different inflation rates is the aggregate demand curve.

The total amount spent in an economy on domestic goods and services is known as aggregate demand, or AD. AD is technically what economists refer to as total planned expenditure. Consider aggregate demand to be total spending for the time being; we'll go into more detail about it in later articles.

All four elements of demand are included in aggregate demand:

The price level is one of several variables that affect this desire. The entire amount spent on domestic products and services at each price level is displayed on an aggregate demand curve.

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The time it would take it to reach Earth if the Sun remained at its current position is 978,349.5 years.

The time of motion of the giant molecular cloud is the time take for the giant molecular cloud to reach the earth.

Mathematically, the time taken for the giant molecular cloud to reach the earth is given as;

time = distance / speed

where;

time of motion = (6.48 x 10¹⁴ km) / (21 km/s)

time of motion = 3.086 x 10¹³ seconds = 978,349.5 years.

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The significant figure of a value or measurement is the number of important digits that it contains

The main purpose for learning about significant figures in science and/or technology courses is precision of measurements.

In science and technology experiments and reseaches, we always want to ensure that measured values are as close to the true values as possible. This is because any deviation from the true value can invalidate the result of the experiment. Also, errors due to repeated approximations can have cummulative effects on the experimental results.

Therefore, the knowledge of significant figures is useful in science and technology to be able to record values of experimental measurements as close as possible to the actual value.

Answer:

Sedentary lifestyle is the lifestyle by which most physical activity is abandoned, performing activities that do not require energy consumption or large muscle movements on a large scale, such as using a computer, driving a car or playing video games.

Today, most young people have gradually turned towards sedentary lifestyles, mainly motivated by the increase in technological availability, and the extensive dependence generated on technology both to communicate with their peers (cell phones, social networks, etc. .) and for leisure time (video games, etc.).

Some ways to promote physical activity in young people and prevent sedentary lifestyle can be to create sports groups, where young people can establish social relationships without depending on networks or technological devices, or establish tasks of physical activity during study or work hours.

The unit of the potential energy is the same as the kinetic enrgy and it is kg·m²/s².

And the SI unit of the potential energy is Joule. It is represented by the symbol J.

Thus, Joules (J) is the SI unit of the measurement of the potential energy.

Answer:

Electron emitted by nucleus.

Answer: Electron emitted by nucleus

Answer:  

t = 1.27 x 10⁹ s  

Explanation:  

First, we will find the volume of the wire:

Volume = V = AL  

where,  

A = Cross-sectional area of wire = πr² = π(1 cm)² = π(0.01 m)² = 3.14 x 10⁻⁴ m²  

L = Length of wire = 150 km = 150000 m  

Therefore,    

V = 47.12 m³

Now, we will find the number of electrons in the wire:  

No. of electrons = n = (Electrons per unit Volume)(V)  

n = (8.43 x 10²⁸ electrons/m³)(47.12 m³)  

n = 3.97 x 10³⁰ electrons  

Now, we will use the formula of current to find out the time taken by each electron to cross the wire:

\(I =\frac{q}{t}\)  

where,  

t = time = ?  

I = current = 500 A  

q = total charge = (n)(chareg on one electron)  

q = (3.97 x 10³⁰ electrons)(1.6 x 10⁻¹⁹ C/electron)  

q = 6.36 x 10¹¹ C  

\(500\ A = \frac{6.36\ x\ 10^{11}\ C}{t}\\\\t = \frac{6.36\ x\ 10^{11}\ C}{500\ A}\)

Therefore,

t = 1.27 x 10⁹ s

The vertical distance covered by the eagle can be given as,

Plug in the known values,

The above equation can be further solved as,

Therefore, the time taken by eagle to reach at food is 10.4 s or 4.91 s.

Answer:

wd = F * D

wd = 100 * 5

wd = 500

The work done on the box is 500 Joules.

When an object is moved over a distance by an external force, at least a portion of which is applied in the direction of the displacement, it is said to have done "work" in physics. By multiplying the length of the path by the component of the force acting along the path, work can be calculated if the force is constant.

As work is a scalar quantity, it can be defined only by magnitude, it has no direction. SI unit of work is Joule and CGS unit of work is erg.

Given parameters:

Mass of the box: m = 4 kg.

Force applied on the box: F = 100 N.

Displacement of the box: d = 5 meters.

Hence, the work done on the box is = applied force × displacement

= 100 N × 5 meters

= 500 Joules.

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Answer: e. P/2

Explanation:

For ideal gases, we have the relation:

P*V = n*R*T

where:

n =  number of mols

R = Gas constant

T = temperature

V = volume

P = pressure.

We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:

Pa = (n*R*T)/V.

For sample B, we have:

n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:

Pb = (n/2)*R*(T/2)*(2/V) = (n*R*T/V)*(2/4)

and:

(n*R*T/V) = Pa

Then we can replace it and we get:

Pb = (n*R*T/V)*(2/4) = Pa*(2/4) = Pa*(1/2) = Pa/2.

Then the correct option is e.

The radius of curvature for each surface of the thin convex lenses is 4 times the focal length (f).

Two spherical surfaces often make up an optical lens. The lens is referred to as a biconvex lens or just a convex lens if those surfaces are curved outwards. These lenses have the ability to focus an outside light beam to a spot on the opposite side by converging it.

The radius of curvature is always positive for convex lenses and always negative for concave lenses.

The relationship between the focal length (f), radius of curvature (R), and index of refraction (n) for a thin convex lens is,

1/f = (n - 1) * (1/R1 - 1/R2)

where R1 and R2 are the radii of curvature of the two surfaces of the lens.

Since the two radii of curvature for each of the two convex lenses are equal, we can simplify the equation to:

1/f = (n - 1) * (2/R)

R = radius of curvature for each surface of the lens.

We can rearrange this equation

R = 2 * f / (n - 1)

Substituting the given values of n = 1.5

R = 2 * f / 0.5

R = 4 * f

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Answer:

Yes I think... But the joke is it is a walk then.

Answer:

no

Explanation:

because if the fly get its wings cut off its obviously not going to be able to fly

Answer:

If I say the correct answer is B.280

Answer:

ε = 2 V/cm

Explanation:

To calculate the mobility inside this bar, we just need to apply the expression that let us determine the mobility. This expression is the following:

ε = ΔV / L

Where:

ε: Hole mobility inside the bar

ΔV: voltage applied in the bar

L: Length of the bar

We already have the voltage and the length so replacing in the above expression we have:

ε = 2 V / 1 cm

The data of the speed can be used for further calculations, but in this part its not necessary.

Hope this helps

Answer:

It's A, B, and D

A. The city integrated its school

B. Atlanta became a leader in aviation

D. The population increased to one million

Explanation:

Jonathan needs to maintain a separation of 0.543 mm between the plates to get the desired charge, and a dielectric constant of 92.6 to achieve a separation of 5 mm with a dielectric.

(a) Using the equation Q = CV, where Q is the charge, C is the capacitance, and V is the voltage, we can solve for the capacitance: C = Q/V =\((8.15 x 10^-9 C) / (50 V) = 1.63 x 10^-10 F.\)

Then, using the formula for capacitance of parallel plate capacitors: C = ε0A/d, where ε0 is the permittivity of free space, A is the area of the plates, and d is the separation distance, we can solve for the separation distance: d =\(_{3}OA/C = (8.85 x 10^-12 F/m) x (0.01 m^2) / (1.63 x 10^-10 F) = 0.543 mm.\)

(b) To find the dielectric constant, we can use the formula for capacitance of a parallel plate capacitor with a dielectric: C = εrε0A/d, where εr is the relative permittivity or dielectric constant of the material. Solving for εr, we get: εr = Cd / ε0A = \((1.63 x 10^-10 F)\) x (0.005 m) / \((8.85 x 10^-12 F/m)\) x \((0.01 m^2)\) = 92.6.

Therefore, Jonathan should use a dielectric with a relative permittivity of 92.6 to achieve a separation of 5 mm.

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The GPE (Gravitational potential energy) of the balloon of mass 250 kg is 367500 J.

To calculate the GPE of the balloon, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the GPE of the balloon is 367500 J.

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Answer:

Positive charge is attracted to the neutral object.

Explanation:

Recall ; Like charges repel, unlike charges attract. This phrase simply means (positive (+) is attracted to negative (-ve) and vuc versa while both positive, positive and negative, negative charge repel.

For a neutral object. The quantity of positive charge equals the quantity of negative charges. This simply means a neutral object contains charges as well, which are usually scattered or randomly aligned.

Therefore, when a positive charge is brought near a neutral body, the order of alignment of the charges change, with the negative charge all moving towards the direction of the positively charged body and the positive charges in the neutral body aligning in the opposite direction.

The charge will be attracted.

As you may know, opposite charges attract (and equal charges repel).

So, when you put a positive charge near a neutral material, all the negative charges in the material will move towards the surface of the material closer to the positive charge (and the positive charges in the material will move away).

Now the charge in the material is not homogeneous, so the positive charge will see a negatively charged surface near it, and it will be attracted to that surface.

Thus we can conclude that as a positive charge is brought near a neutral, insulating piece of material, the charge will be attracted towards it.

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Answer: 430297.6828056 light milliseconds

Explanation: the distance between  earth and venus is

184835061.608992 kilometers based on the model. the spacecraft would be at the halfway point which would be 92417530.804496 kilometers from earth. then, you find the midpoint of the 2 planets if they were aligned in a straight path. that would be 129000000 kilometers. then you find how fast it would take light to travel that distance. therefore you would get 430297.6828056 light milliseconds as the answer. Hope the answer was helpful. -Stephen

This question involves the concepts of kinetic energy, potential energy, and the law of conservation of energy.

The watermelon is "1.02 m" above the ground.

The total energy of the watermelon can be found by its potential energy at the highest point:

Total Energy = mgh

where,

Therefore,

Total Energy = (118 kg)(9.81 m/s²)(5 m)

Total Energy = 5787.9 J

Now, according to the law of conservation of energy, at the given point:

Total Energy = Kinetic Energy + Potential Energy

5787.9 J = 4610 J + mgh'

\(h'=\frac{5787.9\ J-4610\ J}{(118\ kg)(9.81\ m/s^2)}\)

h' = 1.02 m

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Answer:

yes

Explanation:

because it will help find who did the crime and it can also open jobs and opportunities for the people who likes sicnenae

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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