Answer:
it is -1x2
Step-by-step explanation:
by the ex variable u will get it
Answer asap :) pls will mark brainliest
FAST ANSWER PLEEEAAAAASE Verify that (sinx-cosx)^1=1-2sinxcosx is an identity.
Answer:
yes i jist looked it up lljljlj
That equation is very similar to the Pythagorean Identity. I might be, but I don’t know.
I don’t know what the answer Is
Answer:
Exact Form: x = 10/7
______
Decimal Form: x = 1.428571
Mixed Number Form: x = 1 3/7
Hope this helps, have a nice day/night! :D
If this helped please mark this as brainliest!
Answer:
In the picture
Step-by-step explanation:
Good luck!
help me find the answer please need help asap
Evaluate x-y = -11 and y =26
x= 15
Step-by-step explanation:Hi there !
x - y = - 11
replace y = 26
x - 26 = - 11
x = 26 - 11
x = 15
Good luck !
Consider the problem: Mai has $36 to spend on movie tickets. Each movie ticket costs $4.50. How many tickets can she buy? Part 1: Select BOTH a multiplication equation AND a division equation to represent this situation. Group of answer choices 4.50 ÷ 36 = ? ? · 4.50 = 36 4.50 · 36 = ? 36 ÷ 4.50 = ?
Answer:
Multiplication:
4.5x = 36 or ? · 4.50 = 36
Division:
Total cost / cost per ticket = number of tickets or 36 ÷ 4.50 = ?
Points 1 to 6To present y=-x^3+3x^2, 9 points must be selected, point 1: Domain, 2: zeros of the function, 3: period and symmetry, 4: sign of the function, 5: going to the edge of the function, 6: asymptotes, 7: monotony and extreme values, 8: concavity and convexity, 9: to present the function graphically.
ANSWERS
1. Domain: all real values
2. Zeros: 0 (with multiplicity 2) and 3
3. Not periodic. Symmetric about the point (1, 2)
4. Positive for x < 3; negative for x > 3
5. f → ∞ as x → -∞; f → -∞ as x → ∞
6. none
EXPLANATION
1. The domain of a function is the set of all the x-values for which the function exists. In this case, we have a polynomial function and, therefore, the domain is all real values.
2. To find the zeros of the function, we have to solve,
\(-x^3+3x^2=0\)First, factor x² and -1 out. To do so, we have to divide each term by x² and by -1 - or, in other words, divide by -x²,
\(\begin{gathered} -x^2\left(\frac{-x^3}{-x^2}+\frac{3x^2}{-x^2}\right)=0 \\ \\ -x^2(x^{3-2}-3x^{2-2})=0 \end{gathered}\)So, we have,
\(-x^2(x-3)=0\)In this equation, we can see that if x = 0, then the equation is true. Also, if x = 3 the equation is true. So, these are the two zeros, with the particularity that x = 0 has multiplicity 2. This is because the factor related to that zero is x squared.
Hence, the zeros are 0 and 3. 0 has multiplicity 2.
3. As mentioned before, this is a polynomial function, which means that it is not a periodic function. A cubic function is an odd function, and it is symmetric about the origin. However, this function is not the parent function, x³, but it is symmetric about the point (1, 2).
4. We know that the function is zero at x = 0 and at x = 3. For x < 0, the function is positive,
\(with\text{ }x=-1:\text{ }y=-(-1)^3+3(-1)^2=-(-1)+3\cdot1=1+3=4\)For 0 < x < 3, the function is also positive. This is because x = 0 with multiplicity 2.
Then, since the function crosses the x-axis at x = 3 and that zero has multiplicity 1, we can conclude that the function is negative for x > 3.
Hence, is the function is positive for x < 3 and negative for x > 3.
5. As mentioned in part 4, the function is positive for all values of x less than 3, which means that the function goes to infinity as x goes to negative infinity.
Since for x > 3 the function is always negative, it goes to negative infinity as x goes to infinity.
6. A polynomial function has no restrictions in the domain and, therefore, has no asymptotes.
PLEASE HELP THIS IS ALL IT GIVES ME I HOPE YOU COULD DK THE ANSWER WITH JUST THIS BUT PLEASE I NEED HELP
Answer:
f (3) = 21
Step-by-step explanation:
To answer, we know that x in f (x) equals 3, so in f (x) = 7x, we simply substitute x with 3:
f (3) = 7 (3)
Now multiply:
f (3) = 21
21 is your answer
Hope this helps :)
Show that {(x, y) | x − y ∈ Q} is an equivalence relation on the set of real numbers, where Q denotes the set of rational numbers. What are [1], [1/2], and [π]?
In summary the equivalence relation on the set of real numbers is:
- [1] = {x ∈ R | x = 1 + q, q ∈ Q}
- [1/2] = {x ∈ R | x = 1/2 + q, q ∈ Q}
- [π] = {x ∈ R | x = π + q, q ∈ Q}
What are real numbers?The union of both rational and irrational numbers is known as a real number. They are represented by the letter "R" and can be either positive or negative.
To show that the relation {(x, y) | x − y ∈ Q} is an equivalence relation on the set of real numbers, we need to verify three properties: reflexivity, symmetry, and transitivity.
1. Reflexivity: For any real number x, we have x - x = 0, which is a rational number (0 ∈ Q). Therefore, (x, x) ∈ {(x, y) | x − y ∈ Q} for all x, and the relation is reflexive.
2. Symmetry: If (x, y) ∈ {(x, y) | x − y ∈ Q}, then x - y is a rational number. Since the negation of a rational number is still a rational number, -(x - y) = y - x is also a rational number. Therefore, (y, x) ∈ {(x, y) | x − y ∈ Q}, and the relation is symmetric.
3. Transitivity: If (x, y) ∈ {(x, y) | x − y ∈ Q} and (y, z) ∈ {(x, y) | x − y ∈ Q}, then x - y and y - z are both rational numbers. The sum of two rational numbers is also a rational number, so (x - y) + (y - z) = x - z is a rational number. Therefore, (x, z) ∈ {(x, y) | x − y ∈ Q}, and the relation is transitive.
Since the relation satisfies all three properties (reflexivity, symmetry, and transitivity), it is an equivalence relation on the set of real numbers.
Now, let's determine the equivalence classes [1], [1/2], and [π].
The equivalence class [1] consists of all real numbers x such that x - 1 ∈ Q. In other words, [1] = {x ∈ R | x - 1 ∈ Q}. This means that any real number x in the form x = 1 + q, where q is a rational number, belongs to [1].
Similarly, the equivalence class [1/2] consists of all real numbers x such that x - 1/2 ∈ Q. Therefore, [1/2] = {x ∈ R | x - 1/2 ∈ Q}, which means that any real number x in the form x = 1/2 + q, where q is a rational number, belongs to [1/2].
Finally, the equivalence class [π] consists of all real numbers x such that x - π ∈ Q. Thus, [π] = {x ∈ R | x - π ∈ Q}. This means that any real number x in the form x = π + q, where q is a rational number, belongs to [π].
In summary:
- [1] = {x ∈ R | x = 1 + q, q ∈ Q}
- [1/2] = {x ∈ R | x = 1/2 + q, q ∈ Q}
- [π] = {x ∈ R | x = π + q, q ∈ Q}
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The number of hours a lightbulb burns before failing varies from bulb to bulb. The population distribution of burnout times is strongly skewed to the right. The central limit theorem says that
The average burnout time of a large number of bulbs has a sampling distribution that is close to the normal is known as central limit theorem states.
What is Population Distribution?The Population Distribution is a form of a probability distribution that measures the frequency with which the items or variables that make up the population are drawn or expected to be drawn for a given research study.
In statistics, the frequency (or absolute frequency) of an event can be said as the number of times the observation has occurred/recorded in an experiment or study.
Probability in statistics denotes the possibility of the outcome of any random event. The term means to check the extent to which any event is likely to happen.
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help me.........................
Answer:
86°solution,
Draw a line RM parallel to line PQ and ST .And the line RM divides the angle W in two part .i.e x° and y°
<w=X+y
If RM is parallel to ST then,
<MRT=<SRT (being alternate angles)
<X=34°
If RM is parallel to PQ then,
<PQR=<MQR( being alternate angles)
52°=y
y=52°
now,
w=X+y
=34° +52°
=86°
Hope this helps...
Good luck on your assignment..
Solve the differential equation: dy - 10xy = dx such that y = 70 when x = 0. Show all work.
The solution to the given differential equation with the initial condition y = 70 when x = 0 is y - 10xy² - 10xC₁ = x + 70
To solve the given differential equation:
dy - 10xy = dx
We can rearrange it as:
dy = 10xy dx + dx
Now, let's separate the variables by moving all terms involving y to the left side and all terms involving x to the right side:
dy - 10xy dx = dx
To integrate both sides, we will treat y as the variable to integrate with respect to and x as a constant:
∫dy - 10x∫y dx = ∫dx
Integrating both sides, we get:
y - 10x * ∫y dx = x + C
Now, let's evaluate the integral of y with respect to x:
∫y dx = xy + C₁
Substituting this back into the equation:
y - 10x(xy + C₁) = x + C
y - 10xy² - 10xC₁ = x + C
Next, let's apply the initial condition y = 70 when x = 0:
70 - 10(0)(70²) - 10(0)C₁ = 0 + C
Simplifying:
70 - 0 - 0 = C
C = 70
Substituting this value of C back into the equation:
y - 10xy² - 10xC₁ = x + 70
Thus, the solution to the given differential equation with the initial condition y = 70 when x = 0 is y - 10xy² - 10xC₁ = x + 70
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Is 39/7 rational number
Answer: yes
Explanation: All fractions, positive or negative, are rational numbers.
So 39/7 must be rational.
PLS HELP... 10 POINTS ASAP
Coach Jackson has a ratio of 1 girls to 3 boys in his classroom. If there are 6 girls in his class, what is the total number of students in Coach Jackson's class?
a. 18
b. 24
c. 12
d. 2
Answer:
b, 24
Step-by-step explanation:
b
1:3
6:18
6+18=24
I GOTCHU HOMIE
Answer:
The answer is 18.
Step-by-step explanation:
6 x 3 x 1 = 18
TIME REMAINING
59:54
Fatima evaluated the expression StartFraction 4 m Superscript negative 3 Baseline n Superscript negative 2 Baseline Over m Superscript negative 1 Baseline n EndFraction, when m = negative 2 and n = 4. Her work is shown below.
StartFraction 4 m Superscript negative 3 Baseline n Superscript negative 2 Baseline Over m Superscript negative 1 Baseline n EndFraction = 4 m Superscript negative 2 Baseline n Superscript negative 3 Baseline = 4 (negative 2) Superscript negative 2 Baseline (4) Superscript negative 3 Baseline = StartFraction 1 Over 64 EndFraction times StartFraction 1 Over 64 EndFraction = StartFraction 1 Over 4,096 EndFraction
What was Fatima’s error?
She subtracted the exponents incorrectly when simplifying the expression.
She substituted the wrong values for the variables.
She applied the exponent Negative 2 to 4 (negative 2) instead of applying the exponent to just Negative 2.
She found an incorrect value for (Negative 8) Superscript negative 2 since the value should be negative.
Answer:
It c
Step-by-step explanation:
She applied the exponent Negative 2 to 4 (negative 2) instead of applying the exponent to just Negative 2.
an = 10. Which statement is true for the sequence defined as 12 + 22 + 32 + ... + (n + 2)2 ? 2n2 + 11n + 15 (a) Monotonic, bounded and convergent. (b) Not monotonic, bounded and convergent. (c) Monotonic, bounded and divergent. (d) Monotonic, unbounded and divergent. (e) Not monotonic, unbounded and divergent.
For the sequence the correct statement is Monotonic, bounded, and divergent. So the correct answer is option (c).
To determine which statement is true for the sequence defined as 12 + 22 + 32 + ... + (n + 2)2, let's examine the pattern of the sequence.
The given sequence represents the sum of squares of consecutive natural numbers starting from 1. In other words, it can be written as:
12 + 22 + 32 + ... + n2 + (n + 1)2 + (n + 2)2
Expanding the squares, we have:
1 + 4 + 9 + ... + n2 + n2 + 2n + 1 + n2 + 4n + 4
Combining like terms, we get:
3n2 + 6n + 6
Now, let's substitute n = 10 into the expression:
3(10)2 + 6(10) + 6
= 300 + 60 + 6
= 366
Therefore, when n = 10, the sum of the sequence is 366.
Now, let's analyze the given statements:
(a) Monotonic, bounded, and convergent.
(b) Not monotonic, bounded, and convergent.
(c) Monotonic, bounded, and divergent.
(d) Monotonic, unbounded, and divergent.
(e) Not monotonic, unbounded, and divergent.
To determine whether the sequence is monotonic, we need to check if the terms of the sequence consistently increase or decrease.
If we observe the given sequence, we can see that the terms are increasing, as we are adding squares of consecutive natural numbers. So, the sequence is indeed monotonic.
Regarding boundedness, as the sequence is increasing, it is not bounded above. Therefore, it is not bounded.
Lastly, since the sequence is not bounded, it cannot be convergent. Instead, it is divergent.
Based on these analyses, the correct statement for the given sequence is:
Monotonic, bounded, and divergent. So option c is the correct answer.
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Find the angle measure. Round to the nearest tenth.
tan x = 1.16
degrees
(Enter your answer as a number with one decimal place.)
X =
Answer:
The answer is 49.2° to 1d.p
Step-by-step explanation:
tanx=1.16
x=tan‐¹(29/25)
x=49.2° to 1 d.p
can someone find a limit at a location where there is a hole in a graph, such as where a point has been removed or where a graph abruptly stops? why or why not? give an explanation that includes the consideration of (in) the limit from the left, (ii) the limit from the right, and (iii) the general limit.
Yes, it is possible to find a limit at a location where there is a hole in a graph , such as where a point has been removed or where a graph abruptly stops.
This is because the limit of a function is defined as the value that the function approaches as x approaches a given value. In the case of a hole in the graph, the limit is found by looking at the limit from the left, the limit from the right, and the general limit.
The limit from the left is the limit of the function as x approaches the hole from the left. The limit from the right is the limit of the function as x approaches the hole from the right. The general limit is the overall limit of the function at the point where the hole appears. By considering all of these limits, it is possible to determine the overall limit of the function at the point where the hole is present.
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Please help me with this Geometry Question
The value of x from the given figure is 12 units.
What are similar triangles?Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.
From the given figure,
Consider ΔADC and ΔABC,
∠C=∠C (Reflex property)
AC=AC (Reflex property)
∠BAC=∠CDA=90°
By AA similarity, ΔADC ~ ΔABC
So, AC/BC = DC/AC
x/36 = 4/x
x²=36×4
x²=144
x=12 units
Therefore, the value of x from the given figure is 12 units.
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If k is a negative integer, which of these is DEFINITELY NEGATIVE? A. k* (k-1) * (k - 2) B. k* (k+1) C. k* (-50) D. (50-k)
Answer:
only A ans bellow
Step-by-step explanation:
let k= -4
A. k * (k - 1) * ( k - 2)
= -4 * (-4 -1) * ( -4 -2)
= -4* (-5) * (-6)
= 20*-6
= -120
B. k * ( k+1)
= -4 * ( -4+1)
= -4 * (-3)
= + 12
C. k * (-50)
= -4 * (-50)
= + 200
D . (50 - k)
= 50 - (-4)
= 50 + 4
= + 54
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if k is negative then k(k-1)(k - 2) will be definitely negative.
What is Number system?A number system is defined as a system of writing to express numbers.
Given that k is a negative integer.
We need to find which of the given options are defnitely negative.
Let us consider k as -3.
k(k-1)(k - 2)
-3(-3-1)(-3-2)
-3(-4)(-5)=-60
Which is negative.
k(k+1)=-3(-3+1)=6 +ve
k (-50)=-3(-50)=150 +ve
(50-k)=50-(-3)=53 +ve.
Hence, if k is negative then k(k-1)(k - 2) will be definitely negative.
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A carton of grapefruit juice displays the nutritional information shown below. How many grams of sugar are there in a 200 ml glass of juice? Grapefruit juice 250 ml contains Carbohydrate Sugar Protein 19.5 g | 16.5 g | 1.5 g
Answer:
13.2 g
Step-by-step explanation:
let x = grams sugar in a 200 ml glass
16.5 g sugar / 250 ml = x g sugar / 200 ml
x(250) = (16.5)(200)
x = (16.5)(200) / (250) = 3300 / 250 = 13.2
Answer: there are 13.2 g sugar in a 200 ml glass of juice
A baseball team wins 45% of its games. What fraction of games does it win?
A. eight over twenty
B. nine over twenty five
C. nine over twenty
D. eight over twenty five
Answer:
c
Step-by-step explanation:
nine over twenty i think i dont remember i did this last year
Answer:
C. nine over twenty
Step-by-step explanation:
First we should do all of the dividing of the fractions
8/20 = .4 = 40%
9/25 = .36 = 36%
9/20 = .45 = 45%
8/25 = .32 = 32%
then turn them into percentages
Use the Distributive Property to rewrite each expression. Then evaluate.
7(6-4)
Answer:
14
Step-by-step explanation:
PEMDAS:
P: Parentheses
E: Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction
Step 1:
7 ( 6 - 4 ) Equation
Step 2:
7 ( 2 ) Subtract
Answer:
14
Hope This Helps :)
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John Carter, it shows Carter leaping about 100 feet up on Mars. John Carter is an Earth man who has been transported to Mars so his leg muscles have been built to handle Earth's gravity while Mars' gravity is a lot less. On Earth, Michael Jordan had a vertical jump velocity of 16 ft/sec. Suppose John Carter could triple that initial jump velocity due to being on Mars, so his initial velocity would be v0= 48 ft/sec. a.) How high could he jump on Mars? b.) How long could he stay in the air before he hit the ground? c.) The movie shows Carter jumping about 100 ft high. Is that about right by the calculus? d.) What would his speed be when he hit the ground?
Solution :
Given initial velocity, v= 48 ft/s
Acceleration due to gravity, g = \($12\ ft/s^2$\)
a). Therefore the maximum height he can jump on Mars is
\($H_{max}=\frac{v^2}{2g}$\)
\($H_{max} = \frac{(48)^2}{2 \times 12}$\)
= 96 ft
b). Time he can stay in the air before hitting the ground is
\($T=\frac{2v}{g}$\)
\($T=\frac{2 \times 48}{12}$\)
= 8 seconds
c). Considering upward motion as positive direction.
v = u + at
We find the time taken to reach the maximum height by taking v = 0.
v = u + at
0 = 16 + (12) t
\($t=\frac{16}{12}$\)
\($=\frac{4}{3} \ s$\)
We know that, \($S=ut + \frac{1}{2}at^2$\)
Taking t = \($=\frac{4}{3} \ s$\) , we get
\($S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$\)
\($S=\frac{32}{3}$\) feet
Thus he can't reach to 100 ft as it is shown in the movie.
d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.
Therefore final velocity is = -16 ft/s
Carl gauss and his fellow classmates were asked to find the sum of the first 100 natural numbers. the teacher expected this to take some time, but gauss was done almost immediately. how might he have done it?
Carl Gauss uses the pairing method to solve it and the sum of first 100 natural number is 5050.
Sum of the number:
Sum is the way of putting things together.
If the sum two or more numbers together, make a new total by adding it.
Given,
Carl gauss and his fellow classmates were asked to find the sum of the first 100 natural numbers.
The teacher expected this to take some time, but gauss was done almost immediately.
Gauss used this same method to sum all the numbers from 1 to 100.
But he realized that, adding them will take some amount of time.
So, he will pair the numbers, like
=> 1 + 100 = 101
=> 2 + 99 = 101
=> 3 + 98 = 101
.
.
.
.
=> 50 + 51 = 101
That meant he had 50 pairs, each with a sum of 101.
He could then multiply
=> 50 x 101 = 5050
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Can someone explain to me how to solve 5-(3-2)+2
I've looked it up and the answer is 6 but I don't understand how to get there. Plus we need to show our work so please help! I will give 22 points
Answer:
Step-by-step explanation:
brackets first
5 - (3-2) + 2
5 - (1) + 2
5 - 1 + 2
4 + 2
6
Answer:
5-(3-2)+2
5-1+2
4+2
6
Step-by-step explanation:
Follow PEMDAS
P ()
E: Exponent
M: Multiplication
D: Division
A: Addition
S: Subtraction
And you answer each equation going from Left to Right
there are 13 boys and 10 girls in the classroom.what is the ratio of boys and girls
Answer:Step-by-step explanation: 13:10
please help asap for the area. i got homework to submit in 5 minutes
Answer:
area = 228 m^2
Step-by-step explanation:
here's your solution
=> length = 20 m. , width = 12 m
=> Area of rectangle = length*width
=> Area of rectangle = 12*20
=> Area of rectangle = 240 m^2
now we need to find area of traingle
=> base = 4 m. , height = 6 m
=> area of traingle = 1/2*base*height
=> area of traingle = 1/2*4*6
=> area of traingle = 12 m^2
=> now , area of figure = 240 m^2 - 12 m^2
=> 228 m^2
hope it helps
Answer:
p= 66.32 m
a= 228 m squared
Step-by-step explanation:
sol
2.18 Show that the equation \[ 4 x^{2} u^{n}+\left(1-x^{2}\right) u=0 \]
has two solutions of the form \[ \begin{array}{l} u_{1}=x^{\frac{1}{2}}\left[1+\frac{x^{2}}{16}+\frac{x^{4}}{1024}+\cdots\righ
The equation \(4x^2u^n + (1-x^2)u = 0\) has two solutions. One solution is given by \(u_1 = x^{1/2}\left(1 + \frac{x^2}{16} + \frac{x^4}{1024} + \dots\right)\). The other solution is not provided in the given question.
To find the solutions, we can rewrite the equation as \(u^n = -\frac{1-x^2}{4x^2}u\). Taking the square root of both sides gives us \(u = \pm\left(-\frac{1-x^2}{4x^2}\right)^{1/n}\). Now, let's focus on finding the positive solution.
Expanding the expression inside the square root using the binomial series, we have:
\[\left(-\frac{1-x^2}{4x^2}\right)^{1/n} = -\frac{1}{4^{1/n}x^{2/n}}\left(1 + \frac{(1-x^2)}{4x^2}\right)^{1/n}\]
Since \(|x| < 1\) (as \(x\) is a fraction), we can use the binomial series expansion for \((1+y)^{1/n}\), where \(|y| < 1\):
\[(1+y)^{1/n} = 1 + \frac{1}{n}y + \frac{1-n}{2n^2}y^2 + \dots\]
Substituting \(y = \frac{1-x^2}{4x^2}\), we get:
\[\left(-\frac{1-x^2}{4x^2}\right)^{1/n} = -\frac{1}{4^{1/n}x^{2/n}}\left(1 + \frac{1}{n}\cdot\frac{1-x^2}{4x^2} + \frac{1-n}{2n^2}\cdot\left(\frac{1-x^2}{4x^2}\right)^2 + \dots\right)\]
Simplifying and rearranging terms, we find the positive solution as:
\[u_1 = x^{1/2}\left(1 + \frac{x^2}{16} + \frac{x^4}{1024} + \dots\right)\]
The second solution is not provided in the given question, but it can be obtained by considering the negative sign in front of the square root.
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Is there only 1 prime number?
Since, a prime number is whole number higher than one that cannot be divided exactly by any other whole number than itself and one. No, there are many prime numbers.
What is a prime number?A whole number higher than one that cannot be divided exactly by any other whole number than itself and one is a prime number.
What is whole number?Complete numbers the range of numbers that includes zero and natural numbers. not a decimal or fraction.
Prime number 2,5,7,13, ......
so there are multiple prime numbers.
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