What some sort of number do I need to times 32 by each time to equal 104?

Answer:

P=130

Step-by-step explanation:

The integral ∫4t dt from 0 to e will calculate the probability that you will have a customer visit within the time interval [0, e] given an average of 4 customers per minute.


The integral represents the cumulative distribution function (CDF) of the exponential distribution, which is commonly used to model the time between events in a Poisson process. In this case, the Poisson process represents the arrival of customers to your website. The parameter λ of the exponential distribution is equal to the average rate of arrivals per unit time. Here, the average rate is 4 customers per minute. Thus, the parameter λ = 4.

The integral ∫4t dt represents the CDF of the exponential distribution with parameter λ = 4. Evaluating this integral from 0 to e gives the probability that a customer will arrive within the time interval [0, e].

The result of the integral is 4e - 0 = 4e. Therefore, the probability that you will have a customer visit within the time interval [0, e] is 4e.

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The number of cups of trail mix, x that Shoshana will make for the week as required is; x ≥ 2½.

As evident from the task content; Shoshana wants to make enough to bring ½ cup to school for Monday - Friday.

Hence, the number of days is 5 in which case ½ cups is used for each day.

On this note, the minimum number of cups she needs to prepare is; 5 × ½ = 2½.

On this note, the required inequality is; x ≥ 2½.

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First, let's check if the sequence is geometric or arithmetric.

If arithmetric, the sequence will have common difference.

Arithmetric

\( \displaystyle \large{a_{n + 1} - a_n = d}\)

d stands for a common difference. Common Difference means that sequences must have same difference after subtracting.

Geometric

\( \displaystyle \large{ \frac{a_{n + 1}}{a_n} = r}\)

r stands for a common ratio.

To find the value of y, you can check the sequence. If we try subtracting the sequences, the differences are different. That means the sequences are not arithmetric. That only leaves the geometric sequence.

Let's check by dividing sequences.

We have:

Let's check by divide -54 by 18 and 162 by -54. We need to divide more than one so we can prove that the sequence is geometric.

\( \displaystyle \large{ \frac{ - 54}{18} = - 3 } \\ \displaystyle \large{ \frac{ 162}{ - 54} = - 3} \)

Hence, the sequence is geometric.

Because the common ratio is -3. Let these be the following:

\( \displaystyle \large{ a_{n + 1} = y } \\ \displaystyle \large{ a_n = 2 } \\ \displaystyle \large{ r = - 3 }\)

From the:

\( \displaystyle \large{ \frac{a_{n + 1}}{a_n} = r}\)

Substitute the values in.

\( \displaystyle \large{ \frac{y}{2} = - 3}\)

Multiply the whole equation by 2 to isolate y.

\( \displaystyle \large{ \frac{y}{2} \times 2 = - 3 \times 2} \\ \displaystyle \large{ y = - 6}\)

Therefore, the value of y is -6.

well, for the piece-wise function, we know that hmmm x = -1, -1 is less 1, so the subfunction that'd apply to that will be -2x + 1, because on that section "x is less than or equals to 1".

so f(-1) => -2(-1) + 1 => 3.

Answer:3

Step-by-step explanation:

In this case x=-1 so you will use the top equation because x<1

so f(-1) = -2(-1) + 1

          = 2+1

           =3

The height of the monument is 201 ft

The angle of elevation is 63.6

Sine of B is equal to

The height of the monument is solved using trigonometry, The angle of elevation is first calculated using cosine

cos (angle of elevation) = 100 / 225

angle of elevation = arc cos (100 / 225)

angle of elevation =  63.612 degrees

The height, h

tan 63.6 = h / 100

h = 100 * tan 63.6

h = 201.449

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The factors are therefore;  (4x – 3), (x + 3) and (x – 1)

A polynomial is is a function that contains an algebraic term which is raised to a particular power.

Now we have;

4x³ + 5x² – 18x + 9

Thus we can write;

4x³ – 3x² + 8x² – 6x – 12x + 9

Using the factors;

x²(4x – 3) + 2x(4x² – 3) – 3(4x – 3)

Therefore;

(4x – 3)(x² + 2x– 3)

(4x – 3)(x² + 3x – x – 3)

(4x – 3)(x + 3)(x – 1)

The factors are therefore;  (4x – 3), (x + 3) and (x – 1)

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A. The probability that one selected subcomponent is longer than 122 cm can be found by calculating the area under the normal distribution curve to the right of 122 cm. We can use the z-score formula to standardize the value and then look up the corresponding probability in the standard normal distribution table.

z = (122 - μ) / σ = (122 - 100) / 5.6 = 3.93 (approx.)

Looking up the corresponding probability for a z-score of 3.93 in the standard normal distribution table, we find that it is approximately 0.9999. Therefore, the probability that one selected subcomponent is longer than 122 cm is approximately 0.9999 or 99.99%.

B. To find the probability that the mean length of three randomly selected subcomponents exceeds 122 cm, we need to consider the distribution of the sample mean. Since the sample size is 3 and the subcomponent lengths are normally distributed, the distribution of the sample mean will also be normal.

The mean of the sample mean will still be the same as the population mean, which is 100 cm. However, the standard deviation of the sample mean (also known as the standard error) will be the population standard deviation divided by the square root of the sample size.

Standard error = σ / √n = 5.6 / √3 ≈ 3.24 cm

Now we can calculate the z-score for a mean length of 122 cm:

z = (122 - μ) / standard error = (122 - 100) / 3.24 ≈ 6.79 (approx.)

Again, looking up the corresponding probability for a z-score of 6.79 in the standard normal distribution table, we find that it is extremely close to 1. Therefore, the probability that the mean length of three randomly selected subcomponents exceeds 122 cm is very close to 1 or 100%.

C. If we want to find the probability that all three randomly selected subcomponents have lengths exceeding 122 cm, we can use the probability from Part A and raise it to the power of the sample size since we need all three subcomponents to satisfy the condition.

Probability = (0.9999)^3 ≈ 0.9997

Therefore, the probability that if three subcomponents are randomly selected, all three of them have lengths that exceed 122 cm is approximately 0.9997 or 99.97%.

Based on the given information about the normal distribution of subcomponent lengths, we calculated the probabilities for different scenarios. We found that the probability of selecting a subcomponent longer than 122 cm is very high at 99.99%. Similarly, the probability of the mean length of three subcomponents exceeding 122 cm is also very high at 100%. Finally, the probability that all three randomly selected subcomponents have lengths exceeding 122 cm is approximately 99.97%. These probabilities provide insights into the performance of the automatic machine in terms of producing longer subcomponents.

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Answer:

\(y-1=\frac{3}{2} (x+3)\)

Step-by-step explanation:

Slope of the line drawn is -6 ÷ -4 = \(\frac{3}{2}\)

Point slope is y - y1 = m(x - x1)

y1 = 1, x1 = -3

\(y-1=\frac{3}{2} (x+3)\)

Answer:

25 cm

Step-by-step explanation:

hope it helps.....

Answer:

25 cm

Step-by-step explanation:

Use Algebra:

Area of a triangle is  \(A = \frac{1}{2} bh\)  

\(\frac{1}{2}b\) × 32 = 400

\(\frac{1}{2}b\) = 12.5

\(b = 25 cm\)

Answer: Perimeter → 15.07964474

Area→ 18.09557368

The error is made because two or more shapes are said to be similar if they have common corresponding properties of sides and/ angles. The Option D is correct.

All similar shapes are two or more given shapes that share some properties in terms of their corresponding sides or angles. As a result, if the corresponding sides or angles are related, they are similar. It is important to note that similarity does not imply congruency.

When the sides and angles of the given triangles LMN and QRS are compared, it is clear that: angle Side Angle (ASA) similarity implies that the included side between two pairs of congruent angles is similar. As a result, the Option D explains the error in the diagram.

Missing options "a.Your​ friend's paper does not name the triangles correctly for them to be congruent. b. Your​ friend's paper shows that the SAS Postulate should be used to show congruence because a pair of congruent angles is included between two pairs of congruent sides. c. The ASA Postulate cannot be used to prove the congruence of the two triangles as shown because the triangles do not have two pairs of congruent angles. d. The ASA Postulate cannot be used to prove the congruence of the two triangles as shown because the included sides between the two pairs of congruent angles are not marked as congruent in both triangles.

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answer is  y ≤ \(\frac{1}{3}x (-4)\)

Given that,

Area of shaded inequality below solid line is positive

and  y-intercept of the solid line is equal to  - 4

therefore,

The inequality must be

y ≤ \(\frac{1}{3}x (-4)\)

In Mathematics, inequality represents the mathematical expression in which both sides are not equal. If the relationship makes the non-equal comparison between two expressions or two numbers, then it is known as inequality in Maths. In this case, the equal sign “=” in the expression is replaced by any of the inequality symbols such as greater than symbol (>), less than symbol (<), greater than or equal to symbol (≥), less than or equal to symbol (≤) or not equal to symbol (≠). The different types of inequalities in Maths are polynomial inequality, rational inequality, absolute value inequality.

A system of linear inequalities in two variables includes at least two linear inequalities in the identical variables. When we solve linear inequality then we get an ordered pair. So basically, in a system, the solution to all inequalities and the graph of the linear inequality is the graph displaying all solutions of the system. Let us see an example to understand it.

the Linear inequality: 2x – y >1, x – 2y < – 1

The symbols ‘<‘ and ‘>’ express the strict inequalities and the symbols ‘≤’ and ‘≥’ denote slack inequalities. A linear inequality seems exactly like a linear equation but there is a change in the symbol that relates two expressions.

here is given step to easily find the value of inequality:

Step 1: The inequality is already in the form that we want. That is, the variable y y is isolated on the left side of the inequality.

Step 2: Change inequality to equality. Therefore, y > x + 1y>x+1 becomes y = x + 1y=x+1.

Step 3: Now graph the y = x + 1y=x+1. Use the method that you prefer when graphing a line. In addition, since the original inequality is strictly greater than symbol, \Large{>}>, we will graph the boundary line as a dotted line.

Step 4: The original inequality is y > x + 1y>x+1. The greater than symbol implies that we are going to shade the top area or region.

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The value of the expression "true && !false" can be determined by evaluating each part separately and then combining the results.

1. The "!" symbol represents the logical NOT operator, which negates the value of the following expression. In this case, "false" is negated to "true".

2. The "&&" symbol represents the logical AND operator, which returns true only if both operands are true. Since the first operand is "true" and the second operand is "true" (as a result of the negation), the overall expression evaluates to "true".

Therefore, the value of the expression "true && !false" is "true".

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Applying one of the properties of a parallelogram, the value of x is 10°, then 6x=60° and 12x=120°.

There are different quadrilaterals, for example square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. For example, a parallelogram presents some properties that are presented below.

The figure of the exercise shows two adjacent angles. From the property: the adjacent angles are supplementary, you have:

6x+12x=180

18x=180

x=10°

Therefore, 6x= 6*10=60° and 12x=12*10=120°.

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Answer:

Step-by-step explanation:

Answer:

  3

Step-by-step explanation:

The quadratic formula is used to solve a quadratic equation in standard form, based on the values of the coefficients.

The standard-form quadratic ax² +bx +c = 0 has solutions given by the quadratic formula:

  \(x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)

For the quadratic 3x² +4x -2 = 0, we have a=3, b=4, c=-2 and the formula gives ...

  \(x=\dfrac{-4\pm\sqrt{4^2-4(3)(-2)}}{2(3)}=\dfrac{-4\pm\sqrt{16+24}}{6}\\\\x=\dfrac{-4\pm 2\sqrt{10}}{6}=\dfrac{-2\pm\sqrt{10}}{3}\)

The denominator in the solution is 3.

Answer:

The answer is x=(-2±√10)/3

Step-by-step explanation:

The for the values of the variables x = 7 and y = 10, the given must be a parallelogram.

A quadrilateral having two sets of parallel sides is referred to as a parallelogram. In a parallelogram, the opposing sides are of equal length, and the opposing angles are of equal size. Also, the interior angles that are additional to the transversal on the same side. 360 degrees is the sum of all interior angles.

A parallelepiped is a three-dimensional shape with parallelogram-shaped faces. The base and height of the parallelogram determine its area.

For the given quadrilateral to be parallelogram the opposite sides need to be parallel and equal.

For the given quadrilateral we have:

2y - 16 = y - 6

2y - y = -6 + 16

y = 10

Also,

2x + 2 = y + 6

Substitute the value of y = 10:

2x + 2 = 10 + 6

2x = 16- 2

2x = 14

x = 7

Hence, the for the values of the variables x = 7 and y = 10, the given must be a parallelogram.

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Answer:

Step-by-step explanation:

We got two equations.

First modeling the total money using x for nickels and y for quarters.

0.05x + 0.25y = $8.80

Our second equation is modeling the total coins.

x + y = 68

Which we can change to substitute for x.

x = 68 - y

Substitute for x to find the answer.

0.05(68 - y) + 0.25y = 8.80

3.4 - 0.05y + 0.25y = 8.80

3.4 + 0.20y = 8.80

0.20y = 5.4

y = 27.

So, there is 27 quarters and 41 nickels.

Repeated measures study is a technique used in statistics that involves taking multiple measures from the same individual or group. The major concern with a repeated-measures study is the possibility of carry-over effects.

What is a repeated-measures study?A repeated-measures study is a design used in statistics, where all the members of a given sample group are evaluated on two or more occasions. In other words, the repeated-measures study can be viewed as a test-retest design.In this type of study, participants undergo a specific treatment or intervention, and then their responses or measurements are evaluated at various intervals to examine any effects of the intervention. The repeated measures are then compared, and statistical tests are used to determine whether there are any significant differences in the results.

The possibility of carry-over effects: When conducting a repeated-measures study, the possibility of carry-over effects is a major concern. This occurs when the effects of the first treatment are still present when the second treatment is applied, resulting in an unintended impact on the second set of results. For example, if an experimental group is treated with a medication and then evaluated, and the same group is treated with a different medication and then evaluated, the results may be influenced by the residual effects of the first medication.

A carry-over effect can result in an inaccurate representation of the study's effect and can decrease the validity of the results. As a result, researchers must establish an appropriate washout period to reduce the impact of the carry-over effects before conducting a repeated-measures study.

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Answer:

x = 80

Step-by-step explanation:

x + 30 = 110 (Opposite angles are equal)

x = 110 - 30

x = 80

We have the table for the relative frequency below: Class Relative Frequency; Football 0.133 ; Basketball 0.267 ; Soccer 0.233 ; Baseball 0.133 ; Hockey 0.233

An array has a subscript zero for its first element. When using built-in array types, array bounds are not checked.

soccer and hockey is the correct answer because in both of these games there is a possibility of a match to be tied if both teams score equal no of goals in the given time. Both games have two halves of play,  and the team scoring more goal in the given time wins but sometimes both teams score an equal number of goals then the match is  tied

Class Frequency

Football 4

Basketball 8

Soccer 7

Baseball 4

Hockey 7

Total frequency = 4 + 8 + 7 + 4 + 7 = 30

Let's find the relative frequency.

To find the relative frequency, we have:

Relative frequency = frequency/total frequency

We have:

Football = \(\frac{4}{30}\) = 0.133

Basketball = 8/30 = 0.267

Soccer = 7/30 = 0.233

Baseball = 4/30 = 0.133

Hockey = 7/30 = 0.233

Therefore,

We have the table for the relative frequency below: Class Relative Frequency; Football 0.133 ; Basketball 0.267 ; Soccer 0.233 ; Baseball 0.133 ; Hockey 0.233

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We have the table for the relative frequency below: Class Relative Frequency; Football 0.133 ; Basketball 0.267 ; Soccer 0.233 ; Baseball 0.133 ; Hockey 0.233

An array has a subscript zero for its first element. When using built-in array types, array bounds are not checked.

soccer and hockey is the correct answer because in both of these games there is a possibility of a match to be tied if both teams score equal no of goals in the given time. Both games have two halves of play,  and the team scoring more goal in the given time wins but sometimes both teams score an equal number of goals then the match is  tied

Class Frequency

Football 4

Basketball 8

Soccer 7

Baseball 4

Hockey 7

Total frequency = 4 + 8 + 7 + 4 + 7 = 30

Let's find the relative frequency.

To find the relative frequency, we have:

Relative frequency = frequency/total frequency

We have:

Football =4/30  = 0.133

Basketball = 8/30 = 0.267

Soccer = 7/30 = 0.233

Baseball = 4/30 = 0.133

Hockey = 7/30 = 0.233

Therefore,

We have the table for the relative frequency below: Class Relative Frequency; Football 0.133 ; Basketball 0.267 ; Soccer 0.233 ; Baseball 0.133 ; Hockey 0.233

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Answer:

42.86

Step-by-step explanation:

Answer:

42.86%

Step-by-step explanation:

First, we turn it into a fraction:

18/42

Simplify:

3/7 = 42.86 (rounded)

So 18 is 42.86% of 42

The probability that the number in a sample of 127 who do so differs from the expected value is 0.6198.

How to calculate probability?

The critical value, according to the data, is 84. the following will be the mean:

= np = 127 × 2/3 = 84.6

The standard deviation is also 5.3748. The corresponding z score will be:

= (84 - 86.67)/5.3748

= -0.50.

Therefore, the left tailed area will be:

P(z < -0.50) = 0.3099

Since, it's two tailed, we'll multiply by 2. This will be:

= 2 × 0.3099

= 0.6198

In conclusion, the probability is 0.6198.

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The statement that is NOT correct about hypothesis testing is: "We cannot eliminate both type l error and type II error at the same time."

In hypothesis testing, we aim to make a decision about a population parameter based on sample data. Type I error refers to rejecting a true null hypothesis, while Type II error refers to failing to reject a false null hypothesis. While it is not possible to completely eliminate both types of errors simultaneously, we can minimize the chances of committing either of them by choosing an appropriate significance level and conducting a power analysis.

Therefore, the statement that we cannot eliminate both Type I and Type II errors at the same time is incorrect.

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x= 8 , -3

Given:

x² - 5x -24 =0

x² - 8x  + 3x -24=0

x(x-8) + 3(x- 8)=0

(x-8)(x+3)=0

x= 8 , -3

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Answer:

45$

Step-by-step explanation:

If it's $3 for lunch, and she charges it everyday for 15 days, then $3 * 15 = $45

Answer:

(-3,4) for the second problem

Step-by-step explanation:

This is a system of equations.  We can solve the first for y and use that in the second.

Solve first one for y:

3x + y = -5

y = (-3x - 5)

Use this value for y in the second equation:

8x + 7(-3x - 5) = 4

8x - 21x -35 = 4

-13x = 39 (divide both sides by -13 here)

x = -3

Now put this value for x into one of the original equations to get y:

3(-3) + y = -5

-9 + y = -5

y = 4

You can put these x and y values into the original equations to check your work.

Answer: h(3)= -4 h(-3)=-16

Step-by-step explanation:

Plug in 3 and -3 for x and solve

h(3)= 2(3)-10

h(-3)= 2(-3)-10

The dimensions of the corral that will minimize the cost of the fencing are x = 4 yards (width) and y = 325 yards (length).

To begin solving this problem, we need to use the given information to set up an equation that represents the cost of the fencing. Let's start by defining the dimensions of the rectangular corral. We can use x to represent the width and y to represent the length.

Since the area of the corral is 1300 square yards, we know that:

xy = 1300

Now, let's think about the fencing. We need to divide the corral in half with a fence down the middle, which means we have two equal sections with a width of x/2. The length of each section is still y.

To find the perimeter of each section, we add up all the sides. For the top and bottom, we have two lengths of y and two widths of x/2. For the sides, we have two lengths of x/2 and two widths of y. This gives us a perimeter of:

2y + x + 2x + 2y = 4y + 2x

Since we have two sections, the total perimeter is:

2(4y + 2x) = 8y + 4x

We can now set up an equation for the cost of the fencing:

Cost = (8y + 4x)($5) + (x)($3)

The first part of the equation represents the cost of the perimeter fence, while the second part represents the cost of the fence down the middle.

Now, we want to find the dimensions of the corral that will minimize the cost of the fencing. To do this, we can use calculus. We take the derivative of the cost equation with respect to x and set it equal to zero:

dCost/dx = 20y + 3 = 0

Solving for y, we get:

y = -3/20

Since we can't have a negative length, this solution is not valid. However, we can find the minimum cost by plugging in the value of y that makes the derivative equal to zero into the original equation for the cost of the fencing. This gives us:

Cost = (8y + 4x)($5) + (x)($3)
Cost = (8(-3/20) + 4x)($5) + (x)($3)
Cost = (-(12/5) + 4x)($5) + (x)($3)
Cost = -24x + 3x^2 + 3900

To minimize the cost, we take the derivative with respect to x and set it equal to zero:

dCost/dx = -24 + 6x = 0
x = 4

Plugging this value of x back into the equation for the cost of the fencing gives us:

Cost = -24(4) + 3(4^2) + 3900
Cost = $3892

Therefore, the dimensions of the corral that will minimize the cost of the fencing are x = 4 yards (width) and y = 325 yards (length).

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