What principle is responsible for alternating light and dark bands when light passes through two or more narrow slits a refraction c diffraction B polarization D interference?

The mechanical energy of the system 0.150 s after the ball was released is  0.920J.

The sum of potential and kinetic energy is referred to as mechanical energy. It is the force responsible for an object's motion and positioning. There are several types of mechanical energy, including kinetic energy, which is present in moving objects, and potential energy, which is present in compressed springs.

Equation of motion of harmonic oscillator

X = a\(e^{-rt}\) cos(wt)

X = A(t) cos(wt)

Total mechanical energy,

E = 1/2KA²t

E = 1/2Ka²\(e^{-2rt}\)

r = b/2m

E (0.150) = 0.250 J exp(-2x (2.0/2×0.300) ×150)

E (0.150) =  0.250 exp(-1)J

E (0.150) = 0.250/eJ

E = 0.920J.

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"Bernoulli's principle indicates that increasing the velocity of a fluid will cause its pressure to increase." According to the Bernoulli's principle this statement is incorrect or false.

According to Bernoulli, when he research about flow of the liquid, he finds out that when the speed of liquid is increasing then the pressure on the liquid is decreasing. In other words the potential energy of the liquid will become less.

According to the Bernoulli's principle, when the speed of liquid is increasing then the pressure on the liquid is decreasing. In other words the potential energy of the liquid will become less.

That means when there is less pressure on a tube that gives less pressure in the water and gives a lot of area to flow. Then the flow of the liquid increases.

Not only pressure many other forces that acting on the liquid, if its become less efficient on the liquid. Like gravitational potential energy and many more. Then the liquid flows verry frequently.

But the statement tells opposite to the Bernoulli's principle, So from the discussion we can easily conclude that this statement is incorrect or false.

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Answer:

space is the answerrrerreer

Answer:

22236 mi

Explanation:

The maximum height which it has to reach after their upward swing is:

4.1m.

Maximum Height refers to the highest vertical position which an object can reach starting from a rest point along an axis.

From the given set of data, we have

Mass of the actor, m₁ = 75.5 kg

Cable length, h₁ = 4.10 m

Mass of the costar, m₂ = 55 kg

We are using the conversion of energy:

Potential energy at start = kinetic energy at end

Therefore, v =√2gh

v = √ 2 x 9.8 x 4.10

v= 8.96 m/s

Then to calculate for the maximum height, we would get:

1/2mv2= mgh2

make h subject formula

h2= v²/2g

h2= (8.96)²/2 x 9.8

h2= 4.1m  is the maximum height.

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Answer:

Question 7 is "Weight force down is greater than the air drag"

Question 8 is "600 N"

Explanation:

Question 7: When looking at the forces acting on the skydiver it's important to look at what force is larger, in this case, it's the weight. If two forces are acting in opposite directions, then the body will move in the direction of the force that has a larger value, 735 N.

Question 8: When the question tells you that the forces should be balanced, it means that they should turn out to equal zero if you were to subtract the forces, or you can think of it as trying to get the side that has a smaller number to be equal to the number that is greater. Since the question specifically says the parachute will ADD drag to the equation, you solve this one by asking yourself "What number + 135 will equal 735?" This ends up being 600 N.

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Answer:

A. wind blows from the land toward the sea.

B. that this happens because the land cools faster than the sea, and, as a result, the air over land cools faster, which creates an area of higher pressure on land and lower pressure over the sea.

Explanation:

bc I am smrt

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The threshold frequency is 6.2∗10^14 Hz that causes electrons to be ejected.

What is the electron's threshold frequency?

The lowest frequency of light that, when it strikes a metal surface, triggers the emission of electrons is known as the threshold frequency.

How many electrons are emitted from the surface depends on what.

As a result, the quantity of photons, or the brightness of the light, determines how many electrons are ejected. A portion of the packet's energy is used to defeat the metal's electron's binding energy. The work function, or, is the name given to this tying energy.

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Answer:

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Explanation:

El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:

\(v = v_{o}+g\cdot t\) (1)

Donde:

\(v_{o}\) - Velocidad inicial, en metros por segundo.

\(v\) - Velocidad final, en metros por segundo.

\(g\) - Aceleración gravitacional, en metros por segundo al cuadrado.

\(t\) - Tiempo, en segundos.

Si sabemos que \(v_{o} = -75\,\frac{m}{s}\), \(g = -9.807\,\frac{m}{s^{2}}\) y \(t = 26\,s\), entonces la velocidad final del mango es:

\(v = v_{o}+g\cdot t\)

\(v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)\)

\(v = -329.982\,\frac{m}{s}\)

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Answer:

Elements in a family have the same

Ans C. number of valence electrons

The horizontal distance travelled by the football is 3.1 m.

The angle of projection of the football is calculated as follows;

tan ( θ ) = Vy / Vx

where;

tan ( θ ) = 5 / 3

tan ( θ ) = 1.667

θ = arc tan (1.667)

θ = 59⁰

The resultant velocity of the ball is calculated as follows;

v = √ (Vx² + Vy²)

v = √ (3² + 5²)

v = 5.83 m/s

The horizontal distance travelled by the football is calculated as follows;

x = v² sin(2θ) /g

where;

x = [ (5.83)² sin(2 x 59) /9.8 ]

x = 3.1 m

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Answer:

Force = -10 Newton.

Explanation:

Given the following data;

Initial velocity = 8.5m/s

Final velocity = 7.5m/s

Time = 0.25 seconds

Mass = 2.5kg

To find the force exerted;

First of all, we would determine the acceleration of the ball;

Acceleration = (v - u)/t

Acceleration =(7.5 - 8.5)/0.25

Acceleration = -1/0.25

Acceleration = -4 m/s²

Now, to find the force exerted;

Force = mass * acceleration

Force = 2.5 * -4

Force = -10 Newton

Note: The force is negative because it is an opposite reaction.

The light will continue to travel at 34.8° with the normal. The result is obtained by using the Snell's Law.

The Snell's Law is a formula to describe the relationship between the angles of incidence and refraction when a light passes through two medias. It can be expressed as

ni / nr = sin θr / sin θi

Where

Note that the angles are measured from the normal line.

The critical angle can be expressed as

sin θc = ni / nr

If the critical angle is 53.7° and the light enters the substance from air at 45.0° with the normal, what angle with the normal will it continue to travel?

We can combine the above two formulas to find the refracted angle.

ni / nr = sin θr / sin θi

sin θc = sin θr / sin θi

sin 53.7° = sin θr / sin 45°

0.806 = sin θr / 0.707

sin θr = 0.707 × 0.806

sin θr = 0.570

θr = 34.8°

Hence, the light will continue to travel at 34.8° with the normal.

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Answer:

Kinetic theory is based on the kinetic energy of moving particles.  In Boyle's Law the temperature is helped constant, so the kinetic energy of the molecules is a constant. The pressure and the volume are inversely related in Boyle's Law. In Kinetic theory pressure is created by the collision of particles.

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Explanation:

Answer:

Therefore, the required ratio of the radius of the aluminum sphere to the radius of the lead sphere is 1.6.

Explanation:

A higher pitch siren is audible to this person. The sound waves become less frequent as they get more spaced apart as the police car moves off.

The distance between identical points (adjacent crests) in adjacent cycles determines how far a waveform signal has traveled in space or over a wire. In wireless systems, this length is frequently specified in meters (m), centimeters (cm), or millimeters (mm) (mm).

The wavelength, which is also the distance between two wave crests and troughs, is the measurement of wave length. In cycles per second (Hz), the term "frequency" refers to the number of vibrations that cross a specific area in a second (Hertz).

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Answer:

The magnitude of a gravity is always 9.8 which is later approximated to 10m/s.

Answer:

a. 9.8

Explanation:

The magnitude of acceleration due to gravity is 9.8

Answer:

The time required to come to a stop will increase by a factor of four. This is because the acceleration is constant, and the stopping distance is proportional to the square of the speed, so doubling the speed quadruples the stopping distance.

The integral of 1/(1 + x²) is (1/2)ln|1 + x²| + C where C is the constant of integration.

Integration is a mathematical process of finding the antiderivative of a function. To integrate the given expression 1/(1 + x²), we will use the substitution method.

Let u = 1 + x², du/dx = 2x dx, then dx = du/2x and the integral becomes:

∫1/(1 + x²) dx = ∫1/u * (1/2x) du= (1/2)∫1/u du

The antiderivative of 1/u is ln|u| + C, where C is the constant of integration.

Therefore, the final solution of the integral is (1/2)ln|1 + x²| + C.

Let us work through the steps:

Step 1:Let u = 1 + x² and then differentiate both sides with respect to x to obtain du/dx. du/dx = 2x

Substitute 2x dx = du into the integral ∫1/(1 + x²) dx to get the integral in terms of u:∫1/u * (1/2x) du = (1/2) ∫1/u du

Step 2:Calculate the antiderivative of 1/u, which is ln|u|. Thus, the final solution is (1/2)ln|1 + x²| + C, where C is the constant of integration. The constant C will vary depending on the initial conditions of the problem.

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Rain cell 1: 2 mm/hr, 3 km wide, absorption = 0.02 dB/km, Rain cell 2: 4 mm/hr, 3 km wide, absorption = 0.05 dB/km. The total propagation factor seen by the radar for a target at 12 km is 0.048 dB.

To calculate the total propagation factor (F2) at a range of 12 km, we need to consider the clear air absorption and the absorption due to the rain cells at different ranges.

Given information:

Clear air absorption at X-Band: 0.004 dB/km

Rain cell 1: 2 mm/hr, 3 km wide, absorption = 0.02 dB/km

Rain cell 2: 4 mm/hr, 3 km wide, absorption = 0.05 dB/km

To plot the propagation factor as a function of range, we'll calculate the contributions from each component and sum them up.

Clear Air Absorption:

At 12 km range, the clear air absorption factor is:

Clear air absorption = Clear air absorption coefficient * Range

= 0.004 dB/km × 12 km

= 0.048 dB

Rain Cell 1:

The rain cell 1 is located between 5 km to 8 km. Within this range, the absorption factor is constant at 0.02 dB/km.

We need to calculate the fraction of the rain cell coverage within the range of interest.

Fraction of rain cell 1 coverage = (Coverage within range of interest) / (Total rain cell width)

= (min(8 km, 12 km) - max(5 km, 12 km)) / 3 km

Since the range of interest is 12 km, the coverage within the range is:

Coverage within range of interest = min(8 km, 12 km) - max(5 km, 12 km)

= min(8 km, 12 km) - 12 km

= min(8 km, 12 km) - 12 km

= 8 km - 12 km

= -4 km (No coverage within the range)

Since there is no rain cell coverage within the range of interest, the propagation factor due to rain cell 1 is 0 dB.

Rain Cell 2:

The rain cell 2 is located between 8 km to 11 km. Similar to rain cell 1, we calculate the fraction of rain cell coverage within the range of interest.

Fraction of rain cell 2 coverage = (Coverage within range of interest) / (Total rain cell width)

= \(\frac{ (min(11 km, 12 km) - max(8 km, 12 km))}{3 km}\)

Within the range of interest, the coverage is:

Coverage within range of interest = min(11 km, 12 km) - max(8 km, 12 km)

= min(11 km, 12 km) - 12 km

= 11 km - 12 km

= -1 km (No coverage within the range)

Since there is no rain cell coverage within the range of interest, the propagation factor due to rain cell 2 is 0 dB.

Now, we can calculate the total propagation factor (F2) at 12 km by summing up the contributions:

F2 = Clear air absorption + Rain Cell 1 + Rain Cell 2

= 0.048 dB + 0 dB + 0 dB

= 0.048 dB

Therefore, the total propagation factor seen by the radar for a target at 12 km is 0.048 dB.

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Why is the moon’s force of gravity less than that of the earth?

Since the moon has a smaller mass than the earth, the moon has less gravity than the earth. Gravity is related to mass.

Larger mass = larger gravity

Smaller mass = lesser gravity

Moon has small mass, therefore less gravity.

Answer:

2.66 m/s to the right

Explanation:

Applying,

The Law of conservation of momentum,

For elastic collision,

mu+m'u' = mv+m'v'................. Equation 1

Where m = mass of Car A, m' = mass of car B, u = initial velocity of car A, u' = Initial velocity of car B, v = Final velocity of car A, v' = Final velocity of car B

make v the subject of the equation

v = (mu+m'u'-m'v')/m.................. Euqation 2

Note: Assuming Left direction is positive and right direction is negative.

Given: m = 67.3 kg, m' = 65.2 kg, u = 5.65 m/s, u' = -3.2 m/s, v' = 5.38 m/s

Substitute these values into equation 2

v = [(67.3×5.65)+(65.2×[-3.2])-(65.2×5.38)]/67.3

v = (380.245-208.64-350.776)/67.3

v = -179.17/67.3

v = -2.66

Hence v = 2.66 m/s to the right

Answer:

A human

Explanation:

An elephant weighs more, therefore it's gravitational pull by Earth impacts it more than a human.

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Answer:

Explanation:

Think of it this way: An elephant has more inertia than a human. It is much harder to push an elephant across a floor than it is a human, and much harder to stop the elephant once it is moving. Therefore, by definition, an elephant has more mass than a human.

The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

Electrical power is the rate at which electrical work is done.

The unit of electrical power is Watts.

The experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.

The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.

The ammeter reading is taken as well.

When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.

Calculating, the power of the lamp:

Power = 24 × 4.2 = 100 W

Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

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First, we need to do a type conversion. Because the types of the two given quantities are different. One is in minutes. The other is in hours. A vehicle that travels \(45\) kilometers in an hour travels how many meters in a second?

A vehicle that travels \(12.5\) meters in a second travels how many meters in \(20\) minutes?

Newton's second law allows to find the result for the friction coefficient of the street is:

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.

           ∑ F = m a

Where bold indicates vectors, m is to mass and acceleration.

In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight.

        Sin θ = \(\frac{W_x}{W}\)  

        cos θ = \(\frac{W_y}{W}\) / W

        Wₓ = W sin θ

         \(W_y\)  = W cos θ

We write Newton's second law for each axis.

y-axis

         N- \(W_y\)  = 0

         N = mg cos θ

x-axis

        Wₓ - fr = ma

Since they indicate that the body goes down at a constant speed, the acceleration is zero.

         W sin θ = fr

The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.

         fr = μ N

we substitute.

          fr = μ mg cos θ

         mg sin θ = μ cos θ  

        μ = tan θ

Let's calculate.

         μ = tan 38.0

         μ = 0.78

In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:

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Answer:

F = 108.5 [N]

Explanation:

To solve this type of problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

ΣF = m*a

where:

ΣF = sum of forces [N]

m = mass = 35 [kg]

a = acceleration = 0.5 [m/s²]

f = friction force [N]

F - f = m*a

F - 91 = (35*.5)

F = 91 + 17.5

F = 108.5 [N]

Answer:

1.127,56,000m

2. 347,600,000

3. 384,000

4. 200000000

5.  16,000,000cm

6. 36,000,000cm

7. 125,000m long, 400m deep, 1,500m wide

8. 11.18km/sec

9. 5,400,000

10.  2g

11. 1,200 mg to 2700 mg

12.   158000 kg

13. 450000000 mg

14.    23,000g to 90,000g

15.   40,000 ML

16.  1,000 ML

17.  26,600 KL

18. 1,558,000 L

19. 60 ML

20. 0.947

Answer:

El trabajo realizado por la niña es 25.9 J.

Explanation:

El trabajo ue hace la niña viene dado por:

\( W = |F|*|d|*cos(\theta) \)    

En donde:

F: es la fuerza realizada = 10 N

d: es el desplazamiento = 300 cm

θ: es el ángulo entre la fuerza y el desplazamiento = 30°

Entonces, el trabajo es:

\( W = |F|*|d|*cos(\theta) = 10 N*3 m*cos(30) = 25.9 J \)    

Por lo tanto, el trabajo realizado por la niña es 25.9 J.

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