What phase of a low mass stars life has a core with active helium fusion and a shell of hydrogen fusion

Answer:

1.constant acceleration.

2.0 ms

3. 0 ms

Explanation:

1. (D) uniformly accelerated motion

2. (A) zero

3. (B) -10 m/s

4. (C) -9.8 m/s^2

5. (B) projectile motion

If you add a vector with a magnitude of 1 to a vector of magnitude 2, the possible magnitudes for the vector sum range from 1 to 3.

This is because of the triangle inequality theorem.The triangle inequality theorem states that the magnitude of the sum of two vectors is less than or equal to the sum of their magnitudes. In other words, if we have two vectors A and B, then the magnitude of their sum C is given by:

|C| ≤ |A| + |B|

If we have a vector of magnitude 1, we can call it vector A. If we have a vector of magnitude 2, we can call it vector B.

Then the magnitude of their sum, vector C, is given by:|C| = |A| + |B|.

Since |A| = 1 and |B| = 2, we can substitute those values into the equation: |C| = 1 + 2

|C| = 3

Therefore, the maximum magnitude of the vector sum is 3.

However, the minimum magnitude of the vector sum is found when the vectors are pointing in opposite directions.

In this case, the magnitude of the sum would be:

|C| = |B| - |A|

|C| = 2 - 1

|C| = 1.

Therefore, the possible magnitudes for the vector sum range from 1 to 3.

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Same time = 0.61 s

It falls from the same height, and the vertical component of the object's velocity is affected in the same way by the gravity independent of the horizontal component.

Given,

The length is r=5.70 m

The tangential speed is r=9.10 m/s

The centripetal acceleration is:

The acceleration is:

The range of the physical address if CS = 2B95 is from 2B950 to 2B95F. This corresponds to a range of addresses from 2B9500 to 2B95FF.

In the hexadecimal system, the digits range from 0 to F, where each digit represents a value from 0 to 15. The CS value of 2B95 is composed of four hexadecimal digits: 2, B, 9, and 5. To determine the range of the physical address, we consider the CS value as the most significant part of the address.

The physical address range begins with the CS value (2B95) followed by three digits ranging from 0 to F. This allows for a total of 16^3 = 4096 possible addresses. Therefore, the range of the physical address is from 2B9500 to 2B95FF, covering all possible combinations of the three digits following the CS value.

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Answer: Force = mass x acceleration

Explanation: Here, the plane is standing still so acceleration here is

acceleration due to gravity ( 9.8 m/\(s^{2}\))  So,

 Force = mass x 9.8

 230000 = mass x 9.8

 Mass = \(\frac{230000}{9.8}\) = 23,469.39 kgs

Here force is negative because it is acting against gravity. Also, since the unit of force is Newton so the unit of mass is in kgs

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Answer:

oooh thats hard

Explanation:

well i would probaly search the page number or anthing on the page that   should help

Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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Answer:

1 Inch and 20 F

Explanation:

Answer:

5

Explanation:

electrons can be more than det

Daniela had a 5-meter head start and Leonard caught up to her at 25 meters best describes the runners. Option A is correct.

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

The graph shows that Daniela had a 5-meter head start and Leonard caught up to her at 25 meters

Hence option A is correct.

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Answer:

Daniela had a 5 meter head start, and Leonard caught up to her at 25 meters.

Explanation: took the unit test

Elastic cartilage is a type of cartilage composed of a network of branching elastic fibers.

Elastic cartilage is a specialized type of cartilage found in certain parts of the body that require flexibility and resilience. It is composed of a network of branching elastic fibers, which give it its characteristic properties. Elastic cartilage contains a mixture of cells called chondrocytes, along with abundant elastic fibers embedded within the extracellular matrix. These elastic fibers allow the cartilage to stretch and recoil, providing both strength and flexibility to the tissues it supports.

One of the key components of elastic cartilage is type II collagen, which provides a framework for the cartilage matrix. However, unlike hyaline cartilage, elastic cartilage also contains an abundance of elastic fibers, primarily composed of a protein called elastin. These elastic fibers are responsible for the cartilage's unique properties, allowing it to deform and return to its original shape. Elastic cartilage is found in various parts of the body, such as the external ear (pinna), the epiglottis (a flap of tissue in the throat), and the auditory (Eustachian) tube. Its elastic nature enables it to withstand repeated bending and stretching without permanent deformation.

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Answer:

The room will appear to be twice as big because the object distance is equal to the image distance. The mirror takes into account the distance between the mirror and how big the room is.

Test 4 illustrates a balanced net force as both the forces acting in opposite directions are equal in magnitude.

Net force is zero in image depicted by test 4. Thus, the forces acting in opposite direction, upward and downward, can be considered as balance forces. Equal in size and directed oppositely, balanced forces are those. One definition of equilibrium is a state of balanced forces. When the forces are in balance, there is no change in direction.

While balanced forces can keep an object at rest or moving at a constant speed, unequal forces can cause objects to accelerate. We are brought back to remember the condition of weight in order to comprehend this as :

F = ma,

where the magnitude of Force is equal to the product of the mass and the acceleration due to gravity.

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Answer:

expands

Explanation:

The required torque at the axle, is given by the difference between the

moments of the applied forces.

The torque required is 19.62 N·m counterclockwise

Reasons:

The given parameters are;

Mass of the disk, m = 5.0 kg

Location of the axle = Half the radius of the disk

Diameter of the disk, D = 40 cm = 0.4 m

Applied mass, 0.1 m from the axle = 15 kg

Applied mass, 0.3 m from the axle = 10 kg

Required:

Magnitude of torque at the axle that prevent the disk from rotating

Solution:

Torque needed = Clockwise moment - Counterclockwise moment

Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m

Counterclockwise moment = 15 kg × 0.1 m  × 9.81 m/s² = 14.715 N·m

τ + Counterclockwise moment = Clockwise moment

τ + 14.715 N·m = 34.335 N·m

Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m

Torque required, τ = 19.62 N·m counterclockwise

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The probable question drawing obtained from a similar question online is attached

Takumi hope to reduce through his actions is, the severity of stochastic effects, such as cancer.

To find the answer, we need to know more about the stochastic effects.

Thus, we can conclude that, Takumi hope to reduce through his actions is, the severity of stochastic effects, such as cancer.

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Answer:

    m v ´- MV = (m + M) v ’

Explanation:

If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved

initial instant. Before the crash

          p₀ = m v - MV

final instatne. After the crash, we have two cases

1) inelastic shock

          m_f = (m + M) v '

          p₀ = p_f

         m v ´- MV = (m + M) v ’

2) elastic collision with the astronaut's velocity, zero in this case the moment remains

        m v - MV = mv ’+ Mv’

also the kinetic energy is conserved

       mv'2 + M V2 = mv'2 + m v'2

with these two equations we can find the speed of the cars

\(\quad \quad\quad \huge \underline{\tt{ANSWER᭄}}\)

\( \quad\quad\quad\quad\)

\( \blue{ \star}\)Magnetic Energy :

\( \blue{ \star}\)Gravitational Energy :

\( \blue{ \star}\)Nuclear Energy :

\( \blue{ \star}\)Thermal energy :

The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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Answer:

Explanation:

When the mass

m

is being accelerated with an acceleration of

a

,we can say the net force acting in the direction of acceleration is

F

=

m

a

here,it is given that only one force

F

was applied to cause this acceleration, and also given,

m

=

2

K

g

,

a

=

2

m

s

−

2

So,

F

=

2

⋅

2

=

4

N

Answer:

4N

Explanation:

given formula solution

m=2kg F=ma F=2kg×2m/s^2

a=2m/s^2 =4N

The tension force in the string is 3.84 N.

To find the tension force in the string, we can use the centripetal force equation:

F = (m * v²) / r

Where:

F is the centripetal force (tension force in this case)

m is the mass of the ball

v is the velocity of the ball

r is the radius of the circular path

In this scenario, the ball is moving in a circular path with a period of 0.90s. The period is the time it takes for the ball to complete one full revolution. The velocity (v) can be calculated by dividing the circumference of the circle by the period:

v = 2πr / T

Where:

T is the period

r is the radius of the circular path

Given that the radius (r) is 0.30m and the period (T) is 0.90s, we can calculate the velocity:

v = (2π * 0.30) / 0.90

Once we have the velocity, we can substitute the values into the centripetal force equation:

F = (0.06 * ([(2π * 0.30) / 0.90])²) / 0.30

By solving this equation, we find that the tension force in the string is approximately 3.84 N.

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Answer:

Explanation:

brash this so hard

Explanation:

It is given that,

Length of the poster, l = 0.95 m

Breadth of the poster, b = 1 m

The poster is in the shape of rectangle. For a rectangular shape, perimeter is equal to :

P = 2(l+b)

P=2(0.95+1)

P=3.9 m

(b) One digits, P = 4 m

(c) Two digits, P = 3.9 m

(d) Three digits, P = 3.90 m

For the first question, we can use the formula distance = speed × time. Since we want to find the time it takes for the echo to travel to us, we can rearrange the formula to solve for time: time = distance ÷ speed. Plugging in the given values, we get.

time = 1262 ÷ 340 = 3.71 seconds
Therefore, it would take approximately 3.71 seconds to hear the echo of your voice off a cliff wall that is 1,262 meters away. For the second question, we know that the period of a pendulum is the time it takes to complete one full swing. We can use the formula period = time ÷ a number of swings. Plugging in the given values, we get:
To calculate the time it takes to hear the echo of your voice off a cliff wall, we first need to consider that the sound travels to the wall and then back to you. So, the total distance the sound travels is 2 * 1,262 meters.

1. Calculate the total distance the sound travels: 2 * 1,262 m = 2,524 m
2. Use the formula time = distance/speed to find the time it takes to hear the echo.
3. Plug in the values: time = 2,524 m / 340 m/s
4. Calculate the time: time ≈ 7.42 seconds

So, the period of the pendulum is approximately 4.25 seconds.

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Explanation:

Let thermal capacity of the vessel be C' J K-1

Heat energy given by hot water = 40 x 4.2 x (60 - 30) = 5040 J

Heat energy taken by cold water = 50 x 4.2 x (30 - 20) = 2100 J

Heat energy taken by vessel = C' x (30 - 20) = 10 C' J

If there is no loss of heat energy,

Heat energy given by hot water = Heat energy taken by cold water and vessel

or 5040 = 2100 + 10 C'

or 10 C' = 2940

or C'= 294 J K-1

Thus, thermal capacity of vessel = 294 J K-1.

Answer:

32v

Explanation:

edge 2023

The 60 degrees is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is given that axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

It is required to find the angle between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-fifth of its initial value.

Suppose the angle between the polarizer and the axis of filter is θ.

The intensity of light that is passing after the filter is 0.2 l₀.

From the law of Malus, we have

I = I₀ \(cos^{2}\)θ

0.2I₀= I₀ \(cos^{2}\)θ

0.2 =  \(cos^{2}\)θ

\(cos\\\)θ = 0.447

θ = 60°

Thus the angle between the direction of polarized light and the axis of a polarizing filter is 60 degree.

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Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Mass of the car is 2000 kg . The Acceleration is given as 3.0 m/s² . And, we have been asked to calculate the Force acting on the Car .

For calculating the Force , we will use the Formula :-

\( \bigstar \: \: \: \boxed{ \sf{ \: Force \: = \: Mass \: \times \: Acceleration \: }} \)

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf {Force \: = \: Mass \: \times \: Acceleration } \)

\( \longmapsto \: \: \: \sf {Force \: = \: 2000 \: \times \: 3.0 } \)

\( \longmapsto \: \: \: \textbf {\textsf {Force \: = \: 6000 }} \)

Hence :-

\( \underline {\rule {180pt} {4pt}} \)