What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s^−1?
Answers
The minimum work required to get the cylinder rolling without slipping at a rotational speed of 20 s-1 is 1.04 kg-m2/s2.
The torque required to rotate a solid cylinder without slipping is given by:
τ = Iα
Where I is the moment of inertia of the cylinder, and α is its angular acceleration.
The moment of inertia of a solid cylinder is given by:
I = mr2
Where m is the mass of the cylinder, and r is its radius.
Plugging in the values, we get:
I = (52 kg)(0.1 m)2 = 0.052 kg-m2
The angular acceleration is given by:
α = ω/t
Where ω is the angular velocity and t is the time taken to reach the desired angular velocity.
Plugging in the values, we get:
α = (20 s-1)/t
Since we do not know the time taken to reach the desired angular velocity, we will assume that it is 1 second.
Plugging in the values, we get:
α = (20 s-1)/1 s = 20 rad/s2
Now, we can calculate the torque required to rotate the cylinder without slipping:
τ = Iα = (0.052 kg-m2)(20 rad/s2) = 1.04 kg-m2/s2
Finally, we can calculate the minimum work required to get the cylinder rolling without slipping:
W = τθ
Where θ is the angular displacement. Since we do not know the angular displacement, we will assume it to be 1 radian.
Plugging in the values, we get:
W = (1.04 kg-m2/s2)(1 rad) = 1.04 kg-m2/s2
Hence, the minimum work required to get the cylinder rolling without slipping at a rotational speed of 20 s-1 is 1.04 kg-m2/s2.'
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Complete question:
A solid 52-kg cylinder has a radius of 0.10 m.What minimum work is required to get the cylinder rolling without slipping at a rotational speed of 20 s^−1?
Related Questions
The gravitational force between the Sun (mass = 1.99 × 1030 kg) and Mercury (mass = 3.30 × 1023 kg) is 8.99 × 1021 N. How far is Mercury from the Sun? 6.98 × 1010 km 6.98 × 107 km 4.87 × 1013 km 4.87 × 1024 km
Answers
Answer:
B. 6.98 × 10^7 km
Explanation:
Just did this on Edge
Answer:
B
Explanation:
YOU'RE WELCOME
I need help pls. Will mark brainliest.
Answers
Ek=kinetic energy (J)
m=mass of object (Kg)
v=speed of object (m/s)
We have the following formula:
Ek=(1/2)mv² ⇒ m=2(Ek)/v²
In this case:
m= mass of the child + mass of the bike
m=30 kg + m₁ (m₁=mass of the bike).
We would have to modify our formula like this:
m=2(Ek)/v²
m=30 kg + m₁
30 kg +m₁=2(Ek)/v²
m₁=2(Ek)/v²-30 kg
We have the following data:
v=0.6 m/s
Ek=12.4J
m=30 Kg + m₁
Therefore:
m₁=2(Ek)/v² - 30 kg
m₁=2(12.4 J)/(0.6 m/s)² - 30 kg
m₁=24.8 J/(0.36 m²/s²) -30 kg
m₁=68.89 Kg - 30 kg
m₁=38.89 Kg
Answer: the mass of the bike is 38.89 Kg.
a football player runs from his own goal line to the opposing team's goal line, returning to his twenty-yard line, all in 22.5 s. calculate his average speed and the magnitude of his average velocity. (enter your answers in yards/s.)
Answers
1)Average speed = 8y/s
2)Average velocity= 0.88y/s
Average speed depends on the distance whereas average velocity depends on the displacement . Speed is a scalar quantity while average velocity is a vector quantity.
Let us assume, L=100 yards as the length of the football field.
1)We know that average speed is the total distance covered by the player divided by the time taken.
Total distance covered to go from one goal line to the other and then back to the 20-yards line is:
s= 100y + (100-20)y
= 100y+ 80y
=180y
Given, time t=22.5 s,
Now, the average speed of the player is:
v= s/t
= 180y/22.5
= 8 y/s
2)To calculate the magnitude of average velocity, we have to consider the direction and sign of the velocity.
In the beginning, the player goes from one goal line to the other one, so he covers 100 y. But, in the second part of the motion he goes back by 80 y. Hence, the net displacement of the player is:
s= 100y-80y= 20y
now, the average velocity is:
v= s/t
=20/22.5
= 0.88 y/s.
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George rides his bike to his friend’s house that is 5 kilometers from his house. If he rides his bike at an average speed of 15 km/h, how long will it take him to get to his friend’s house?
Answers
Answer:
The answer is 0.33 H!
Explanation:
What is the purpose of using the string to tie the forelegs and hind legs during dissection?
Answers
Answer:
To holds the legs apart without rupturing any vein
Explanation:
The purpose of using string to tie the forelegs and hind legs during dissection is to hold the legs apart without rupturing ant vein or artillery for easy dissection procedure( the dismembering of the body of a deceased animal or plant to study its anatomical structure)
when tieing the forelegs and the hind legs the same string is used to tie them and the string is then passed/looped under the dissecting table/tray this way the legs will be held apart and the dissection can commence.
An aircraft has a liftoff speed of 33 m/s. What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240 m
Answers
Answer:
2.27 m/s²
Explanation:
Recall that one of the equations of motion can be expressed as
v² = u² + 2as
where
v = final velocity = takeoff speed = 33m/s
u = initial velocity = rest = 0 m/s
a = acceleration ( we are asked to find this)
s = distance traveled = length of takeoff run = 240m
substituting the known values into the equation above,
v² = u² + 2as
33² = 0² + 2a(240)
1089= 480a
a = 1089/480
a = 2.27 m/s²
ANSWER
2.27 m/s^2
EXPLANATION
We can use the general relationship from kinematics:
vf^2 = vi^2 + 2as
where:
s = distance;
a = acceleration;
vi = 0m/s is the initial velocity;
vf=33ms is the final velocity.
So:
33^2 = 0^2 + 2 ⋅ a ⋅ 240
a= 1089/480
= 2.27m/s^2
2. A 10kg block of wood is pulled across a level ground by fore of 15N applied at
an angle of 30 degree from the horizontal. How much work is done, if it is moved
to a distance of 3m?
(Note: F applied = 15N x cos 30 degree, cos 30 degree = 0.5)
Answers
Answer:
about 19.49J
Explanation:
Work = F × D × Cosine(θ)
Substitute values :D:
Work= 15N x cos 30 degree x 3m x cos 30
Work= 7.5 x 3 x cos 30
Work= about 19.49 joules
please help me
sub -physics, topic-laws of motion
Answers
The maximum angular speed of the turntable to avoid slipping is option (2), √(µg/x).
How to determine angular speed?The maximum angular speed of the turntable can be found by equating the centrifugal force with the frictional force acting on the block.
At maximum angular speed, the centrifugal force acting on the block is given by F = mRω², where R = x is the distance of the block from the center and ω is the angular speed of the turntable.
The frictional force acting on the block is f = µN, where N is the normal force on the block.
At maximum angular speed, the normal force N is equal to the weight of the block, N = mg.
Equating the centrifugal force and the frictional force:
mRω² = µN
mRω² = µmg
ω² = µg/R
ω = √(µg/R)
Substituting R = x:
ω = √(µg/x)
Therefore, the maximum angular speed of the turntable so that the block does not slip is given by √(µg/x).
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A crate is pulled by a force (parallel to the incline) up a rough incline. The crate has an initial spped shown in the figure below. The crate is pulled a distance of 8.24m on the incline by a force of 150N force. b) What is the speed of the crate after it is pulled the 8.24M? Answer in units of m/s.
Answers
Answer:
(a) Kinetic energy of the cart is 648.32 J.
(b) Speed of the cart is 11.44 m/s.
Explanation:
From the attached below figure we came to know that,
Mass of the crate is 10 kg (m)
Initial speed of the crate is 1.2 m/s (v)
Coefficient of friction on a rough plane is 0.286 (µ)
Force on the cart is 150 N (F)
The distance which crate is moved (d) is 8.05 m.
Calculation of kinetic energy:
Acceleration of the cart:
We know that,
F = F – m × g × sinθ - µ × m × g × cosθ (F = ma)
m × a = F – m × g × sinθ - µ × m × g × cosθ
10 × a = 150 – (10 × 9.8 × sin 27) – (0.286 × 10 × 9.8 × cos 27)
10 × a = 150 – 44.49 – 24.97
10 × a = 80.54
Calculation of speed:
Change in kinetic energy = m × a × d
Change in kinetic energy = 10 × 8.054 × 8.05
Change in kinetic energy = 648.32 J
Explanation:
Which type of binary can have their sizes measured directly by photometry? - eclipsing -virtual astrometric -visual spectroscopic
Answers
In an eclipsing binary system, the two stars orbit each other in such a way that they periodically pass in front of each other from the perspective of an observer on Earth. As one star eclipses the other, the combined brightness of the system changes, resulting in a characteristic light curve.
Eclipsing binaries can have their sizes measured directly by photometry. This is because an eclipsing binary is a system where the two stars orbit each other in such a way that one star passes in front of the other from our line of sight on Earth. By measuring the decrease in brightness as the star passes in front of each other, we can determine the size of the stars and their relative distance from each other using photometry. On the other hand, virtual astrometric and visual spectroscopic binaries require more complex methods to determine their sizes and distances.
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What are some changes that can be caused by electromagnetic energy?
Answers
Answer:
cause the changes is the interaction with something. ... So the electromagnetic energy will have increased it's ...
Wavelength and frequency. Explanation: Electromagnetic energy is determined by wavelength and frequency. These are dependent on each other, so anything ... More
How do astronomers explain the energetic jets that come out of quasars and active galactic nuclei in opposite directions
Answers
Astronomers explain the energetic jets that come out of quasars and active galactic nuclei(AGN) in opposite directions in a way that the supermassive black holes' chaotic accretion discs "spit out" jets in directions perpendicular to the disc.
Quasar : A supermassive black hole with a mass between millions and tens of billions of solar masses that is fueled by an extraordinarily bright active galactic nucleus (AGN) and encircled by a gaseous accretion disc is known as a quasar.
An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum.
Hence, astronomers propose that the chaotic accretion discs of supermassive black holes "spit out" jets in directions perpendicular to the disc, explaining the intense jets that emerge from quasars and active galactic nuclei in different directions.
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The radius of a small ball is around 3.79747 cm. The radius of a basketball is about 3.16 times larger. What is the ratio of the surface areas of the small ball and a basketball? 2. What is the ratio of their volumes?
Answers
Explanation:
The ratio of the areas is the square of the ratio of the radii.
A/A = 3.16² = 9.99
The ratio of the volumes is the cube of the ratio of the radii.
V/V = 3.16³ = 31.6
The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. What is the approximate mass of the vehicle in kg? Round your answer to the nearest kilogram
Answers
Given,
Force(F)= 2100N
Acceleration (a)=1.8m/s^2
Mass(m)= ?
Wo know that ,
Force = mass*acceleration
or, F= m*a
or, 2100= m*1.8
or , 2100/1.8 = m
:. m = 1166.67N
The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.
What is force ?The word "force" has a clear definition. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.
The vector sum of the forces exerted on a particle or object is known as the net force. The original forces' impact on the motion of the particle is replaced by the net force, which is a single force.
Force ( F ) is 2100N
Acceleration ( a ) is 1.8m/s²
Mass(m)= ?
According to formula;
Force = mass × acceleration
F= m × a
2100 = m × 1.8
2100 / 1.8 = m
Therefore, m = 1166.6kg.
Thus, The net force on a vehicle that is accelerating at a rate of 1.8 m/s2 is 2100 N. The approximate mass of the vehicle in kg is 1166.67kg.
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A 6.8 kg cannon ball leaves a canon with a speed of 188 m/s. Find the average net force applied to the ball if the cannon muzzle is 4.2 m long.
i want the answer with the steps
Answers
Answer:
its not long dummy, its your imagination
Explanation:
Bio is a root word that means
O heart.
O life.
O cell.
O sugar.
Answers
☆*:.｡. o(≧▽≦)o .｡.:*☆
You push a 10 n object 10 meters. How much work was done on the object
Answers
Work= 10N * 10m
Work= 100J
star cluster a has o and b main sequence stars, while cluster b only has g spectral type and cooler main sequence stars. which cluster is younger?
Answers
Cluster B has younger lifetime.
Because energy imparted from transition of energy from one shell to other.This transition gives the imparting colours. This is an outcome of crystal field theory. Clusters have more dark energy and have more power to hang out the particulates of atmosphere. Atmosphere is cluttered market of gases imparting forces and collision on each other and thereby the life time of reactants have more half life. The slowing of the reaction is responsible due to some addition of catalysts. Clusters impart only one third of the total radiation and spans the opposite force towards gravity sphere. So it has less power consumption for more time.Reaction of cluster-
\(\\\\n+m---------- > \beta \\\\\pi ------------ > \alpha^- +x^+\)
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How much force is required to move a electron through an electric field with strength of 1.375 x 10^19 N/C?
Answers
Answer:
The magnitude of the force required to move the electron through the given field is 2.203 N
Explanation:
Given;
The field strength of the electron, E = 1.375 x 10¹⁹ N/C
charge of electron, q = 1.602 x 10⁻¹⁹ C
The magnitude of the force required to move the electron through the given field is calculated as follows;
F = Eq
F = (1.375 x 10¹⁹ N/C) (1.602 x 10⁻¹⁹ C)
F = 2.203 N
Therefore, the magnitude of the force required to move the electron through the given field is 2.203 N
If the velocity is 50 and the time is 5 seconds what is the acceleration?
Answers
Just divide the both, you will get the answer!
does it sound rude?
im sorry for that!
Answer:
10
Explanation:
Consider the beam in (Figure 1). Take that w = 10 kN/m and P = 12 kN. Determine the normal force, shear force, and moment at point C. Follow the sign convention.
Answers
The normal force at point C is the force exerted perpendicular to the beam. Since the beam is in equilibrium, the sum of all forces in the vertical direction is equal to zero. Therefore, the normal force at point C will be equal in magnitude and opposite in direction to the total vertical force acting on the beam.
2. Shear force: The shear force at point C is the force acting parallel to the beam, causing it to shear or slide. To determine the shear force at point C, we need to consider the forces acting on either side of point C and take the sign convention into account. If we take the left side of point C, the shear force will be positive if it acts in the upward direction and negative if it acts in the downward direction. Similarly, if we take the right side of point C, the shear force will be positive if it acts in the downward direction and negative if it acts in the upward direction. We need to sum up the vertical forces on either side of point C and determine the difference to find the shear force at point C.
3. Moment: The moment at point C is the turning effect caused by the forces acting on either side of point C. To determine the moment at point C, we need to consider the forces acting on either side of point C and their perpendicular distances from point C. Again, we need to take the sign convention into account. Clockwise moments are considered positive, while counterclockwise moments are considered negative. We need to calculate the moments caused by the forces on either side of point C and determine the algebraic sum to find the moment at point C.
By applying these steps, we can determine the normal force, shear force, and moment at point C.
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The airport has a new plane that can go from 0 miles per hour to 100 miles per hour in 10 seconds. What is being described about the new plane?
Answers
Acceleration is a vector quantity that is defined as ❝ rate of change in velocity ❞
And as per the question, the plane can go from 0 miles to 100 miles/hour in 10 seconds that shows rate of change in its velocity. that is :
from 0 miles/hour to 100 miles/hour. hence Acceleration is the quantity being described about the new plane.
\(\qquad \sf \dashrightarrow \: a = \dfrac{v - u}{t} \)[ v = final velocity, u = initial velocity, t = time ]
\(\qquad \sf \dashrightarrow \: a = \dfrac{100 - 0}{10} \)\(\qquad \sf \dashrightarrow \: a = \dfrac{100}{10} \)\(\qquad \sf \dashrightarrow \: a = 10 \: \)So, the Acceleration of the new plane is 10 miles/hour²
#12
A man and a forklift truck lift equal masses 10 feet vertically. Of the following statements, the correct one is:
the man does more work than the forklift
W = F xd
the forklift does more work than the man
they do the same amount of work
insufficient information is given to compare the work done by the man and the forklift
Answers
In the situation of a man and a forklift truck lift equal masses 10 feet vertically, the correct answer is they do the same amount of work.
Based on the relation between work and force, we know their formula is -
W = F × s × cos theta, where W represents work, F represents force and s represents displacement. Theta indicates the angle between displacement and force applied. Now the masses are lifted vertically which means only gravitational force will act on it. The movement of both man and forklift will be horizontally parallel to ground.
The theta angle will be 90°. Cos 90 is 0. So, keep the values in formula to find the work done.
W = F × s × 0. We know multiplication of any number with zero is zero. Hence, they both do same amount of work, which is zero.
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A 2 kg hammer is 0.4m above the ground. What is the gravitational potential energy?
Answers
Answer:
(P.E)=mgh
=2*0.4*10
=8joule
answer
Explanation:
use formula (P.E)=mgh
g=10m/s^2 or 9.8m/s
Do two magnets create magnetic force fields that allow them to interact without touching? Did the investigation answer the question? Explain whether the investigation gave enough evidence to support the idea that invisible magnetic force fields exist.
Answers
Answer:
Magnetic forces are non contact forces; they pull or push on objects without touching them. Magnets are only attracted to a few 'magnetic' metals and not all matter.
Answer:
the person above me is correct i think respectlfully he
not correct
Explanation:
lots of time spent wondering
An airplane is heading south at a speed of 600km/h. If a wind begins blowing from the southwest at a speed of 100km/h, calculate: a) The velocity (magnitude and direction) of the plane relative to the ground. b) How far away from its intended position will it be after 10min if the pilot takes no corrective action? c) In what direction should the pilot aim in order to fly due south?
Answers
Answer:
Here's what I got:
Let's assume that N and E are + directions while S and W are - directions.
Wind is blowing from SW; thus, it is blowing towards NE (or at 45 deg N of E).
Dividing the wind's speed into components:y-component: +70.71 km/h; x-component: +70.71 km/h
Dividing the airplane's speed into components:y-component: -600 km/h; x-component: 0 km/h
Adding the components to get the resulting components:y-component: -529.29 km/h; x-component: +70.71
Using the Pythagorean Theorem to find the resulting speed:v^2 = y^2 + x^2 so v = 533.99 km/h
To find the angle of direction, use arctan (y/x):arctan (529.29/70.71) = 82.39 deg
ANSWER: velocity = 533.99 km/h at 82.39 deg S of E
Explanation:
a testable prediction about a possible to a problem is called a,
a: exercise
b: variable
c: hypothesis
d: experiment
Answers
Answer: C
A hypothesis is a testable explanation with some research behind it. An Hypothesis can be right or wrong.
The answer is C.
Hope it helps!
Answer:
c. is the answer but I'm not 100% sure
hypothesis
(a) What is its kinetic energy at this moment? (b) Find the net work done on the object if its velocity changes to (8.00i + 4.00 j) m/s.
Answers
Please provide the mass and initial velocity of the object to calculate the kinetic energy and the net work done.
To answer your questions, let's first define the terms you mentioned:
1. Kinetic Energy: The energy an object possesses due to its motion.
2. Net Work Done: The total work done on an object, which is equal to the change in its kinetic energy.
3. Velocity Changes: The difference in an object's initial and final velocities.
(a) To find the kinetic energy at a given moment, we need to know the mass of the object and its velocity at that moment. Please provide the mass and velocity of the object.
(b) To find the net work done on the object when its velocity changes to (8.00i + 4.00j) m/s, we can use the following steps:
Step 1: Calculate the initial kinetic energy (KE_initial) using the formula KE_initial = 0.5 * mass * (initial velocity)^2.
Step 2: Calculate the final kinetic energy (KE_final) using the formula KE_final = 0.5 * mass * (final velocity)^2.
Step 3: Calculate the net work done (W_net) using the formula W_net = KE_final - KE_initial.
Please provide the mass and initial velocity of the object to calculate the kinetic energy and the net work done.
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PLS help really confused will mark brainiest to the right answer.
Answers
The base ball would have more acceleration than the bowling ball. Option C.
What is the acceleration?We know that from the Newton second law of motion, force is the product of the mass and the acceleration of an object. We can write that; F = ma
F = force
m= mass
a= acceleration
It is clear from the equation that we have shown above that the accaleration of the object does not only depend on the force but also on mass of the object. We can now write;
a = F/m
The higher the mass the lesser the acceleration of the object as we saw above.
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ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answers
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.