what might be some effective strategies to prevent the various misuses of evaluations?

Answer:

(- 0.5, 5.5 )

Step-by-step explanation:

Using the midpoint formula

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \(\frac{x_{1}+x_{2} }{2}\) , \(\frac{y_{1}+y_{2} }{2}\) )

Here (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (1, 7) , then

midpoint = ( \(\frac{-2+1}{2}\), \(\frac{4+7}{2}\) ) = ( \(\frac{-1}{2}\), \(\frac{11}{2}\) ) = ( - 0.5, 5.5 )

Answer:

10.125 hours

Step-by-step explanation:

We can convert 6 3/4 hours into minutes by multiplying it by 60

this equals 405. Jill spent 405 minutes doing homework.

Jack spent 1 1/2 times as long on his homework as Jill (1 1/2 is equivalent to 1.5)

We can multiply 1.5 x 405 and get 607.5 which means Jack spent 607.5 minutes doing homework

607.5 minutes is equivalent to 10.125 hours.

Step-by-step explanation:

draw a triangle then label corners a and b. spread them 120 degrees apart and there you have it.

DOL = ($76,000 / $38,000) = 2 , This means that for every 1% increase in sales, operating income will increase by 2%.

The degree of operating leverage (DOL) measures the percentage change in operating income resulting from a percentage change in sales. To calculate DOL for Bristo Corporation, we need to first calculate the contribution margin per unit. Contribution margin is the difference between the selling price and variable expenses. In this case, the contribution margin per unit is $40 (i.e., $50 - 20% of $50).
Next, we can calculate the total contribution margin by multiplying the contribution margin per unit by the number of units sold:
Total contribution margin = 1900 units x $40 per unit = $76,000
Finally, we can calculate the DOL using the following formula:
DOL = (contribution margin / operating income)
Operating income is the difference between total revenue and total expenses (fixed and variable):
Operating income = total revenue - total expenses
Operating income = (1900 units x $50 per unit) - (20% x 1900 units x $50 per unit + $66000)
Operating income = $38,000
Therefore, DOL = ($76,000 / $38,000) = 2
This means that for every 1% increase in sales, operating income will increase by 2%.

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Answer:

a=5

Step-by-step explanation:

8+a=13

subtract 8 from each side:

8-8+a=13-8

Simplify:

a=13-8

a=5

Answer:

Clockwise : going the way the clock hand goes (going right)

Counterclockwise : opposite of clock hand (going left)

Answer:

E

Step-by-step explanation:

Here, we want to find the area of the shaded portion on the graph.

That would be P(-1.2<z<0.85)

we complete this by checking these values on the standard score table as follows;

P( z< 0.85) - P(z<-1.2) = 0.68727

The measure of the angles are: K, L, C, N, O G = -3/4, 65, 8 40.4, 89 and 44 respectively

To determine K

9x + 2 = 23 + 5x -1

9x -5x = -1 +2

4x = -3Making x the subject we have

x= -3/4

To find the value of L

Let angle L be x

x + 65 = 130

x=130-65

That is x = 65

To find the m<C

4x + 7 = 3x + 15

Collecting like terms

4x - 3x = 15-7

Making x the subject of the relation we have

x=8

To find the m<N

7x + 6x - 1 = 90

13x = 89

x=89/13

x= 6.9

Substitute x = 6.9 in 6x -1

6(6.9) -1

m<L = 40.4

To find the m<O

5x - 11 = 4x +9

5x-4x = 9 +11

x=20

By substitution in 4x +9 we have

4(20) +9

80+9

m<S = 89

To find the value of the angle G

6x - 4 = 5x +4

6x - 5x = 4+4

x = 8

Therefore the m<G is

5x +4

5(8) +4

40+4 = 44 digress

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Answer:

That's must be really cold!

Answer:

dang where do you live. its like 60 here

Step-by-step explanation:

Answer:

I think this should be C.

Step-by-step explanation:

You can download answer here

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Answer: Its B and C

Which equations shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation 3 x minus 5 = negative 2 x + 10? Select two options.

x = 5

–15 = –5x

5x = 15

–15 = 5x

x = -5

Answer:

The vertices of the quadrilateral after a dilation with scale factor \(\frac{2}{3}\) are \(J'(x,y) = (0,0)\), \(K'(x,y) = (0,4)\), \(L'(x,y) = (6, 8)\) and \(M'(x,y) = (8,0)\).

Step-by-step explanation:

Let suppose that center of dilation is located at origin, that is \(O(x,y) = (0,0)\). Vectorially speaking, dilation is described by following expression:

\(D'(x,y) = O(x,y) + r\cdot [D(x,y)-O(x,y)]\) (1)

Where:

\(O(x,y)\) - Center of dilation.

\(D(x,y)\) - Original point.

\(D'(x,y)\) - Dilated point.

\(r\) - Dilation factor.

If we know that \(O(x,y) = (0,0)\), \(r = \frac{2}{3}\), \(J(x,y) = (0,0)\), \(K(x,y) = (0,6)\), \(L(x,y) = (9,12)\) and \(M(x,y) = (12,0)\), then the dilated points are, respectively:

\(J'(x,y) = O(x,y) + r\cdot [J(x,y)-O(x,y)]\)

\(J'(x,y) = (0,0) +\frac{2}{3}\cdot [(0,0)-(0,0)]\)

\(J'(x,y) = (0,0)\)

\(K'(x,y) = O(x,y) + r\cdot [K(x,y)-O(x,y)]\)

\(K'(x,y) = (0,0)+\frac{2}{3}\cdot [(0,6)-(0,0)]\)

\(K'(x,y) = (0,4)\)

\(L'(x,y) = O(x,y) +r\cdot [L(x,y)-O(x,y)]\)

\(L'(x,y) = (0,0) + \frac{2}{3}\cdot [(9,12)-(0,0)]\)

\(L'(x,y) = (6, 8)\)

\(M'(x,y) = O(x,y) +r\cdot [M(x,y)-O(x,y)]\)

\(M'(x,y) = (0,0) +\frac{2}{3}\cdot [(12,0)-(0,0)]\)

\(M'(x,y) = (8,0)\)

The vertices of the quadrilateral after a dilation with scale factor \(\frac{2}{3}\) are \(J'(x,y) = (0,0)\), \(K'(x,y) = (0,4)\), \(L'(x,y) = (6, 8)\) and \(M'(x,y) = (8,0)\).

  Option B will be the correct option.

        (a, b) → (ka, kb)

Following the rule for dilation,

If a quadrilateral J(0, 0), K(0, 6), L(9, 12) and M(12, 0) is dilated by a scale factor \(\frac{2}{3}\), coordinates of the image points will be,

\(J(0,0)\rightarrow J'(0, 0)\)

\(K(0,4)\rightarrow K'(0, 4)\)

\(L(9,12)\rightarrow L'(6,8)\)

\(M(12,0)\rightarrow M'(8,0)\)

     Therefore, Option B will be the correct option.

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Answer:

3×3(3-8)+2

9 (-5)+2

-45+2

= -43

The product of \(\(3A^2 - A + 5I\)\) is \(\[\begin{bmatrix}308 & -78 & -126 \\-90 & 282 & -39 \\-50 & -42 & 99\end{bmatrix}\]\)

To find the product 3A² - A + 5I, where A is the given matrix:

\(\[A = \begin{bmatrix} -4 & 2 & 3 \\ 1 & -5 & 0 \\ 2 & 3 & -1 \end{bmatrix}\]\)

1. A² (A squared):

A² = A.A

\(\[A \cdot A = \begin{bmatrix} -4 & 2 & 3 \\ 1 & -5 & 0 \\ 2 & 3 & -1 \end{bmatrix} \cdot \begin{bmatrix} -4 & 2 & 3 \\ 1 & -5 & 0 \\ 2 & 3 & -1 \end{bmatrix}\]\)

Multiplying the matrices, we get,

\(\[A \cdot A = \begin{bmatrix} (-4)(-4) + 2(1) + 3(2) & (-4)(2) + 2(-5) + 3(3) & (-4)(3) + 2(0) + 3(-1) \\ (1)(-4) + (-5)(1) + (0)(2) & (1)(2) + (-5)(-5) + (0)(3) & (1)(3) + (-5)(2) + (0)(-1) \\ (2)(-4) + 3(1) + (-1)(2) & (2)(2) + 3(-5) + (-1)(3) & (2)(3) + 3(2) + (-1)(-1) \end{bmatrix}\]\)

Simplifying, we have,

\(\[A \cdot A = \begin{bmatrix} 31 & -8 & -13 \\ -9 & 29 & -4 \\ -5 & -4 & 11 \end{bmatrix}\]\)

2. 3A²,

Multiply the matrix A² by 3,

\(\[3A^2 = 3 \cdot \begin{bmatrix} 31 & -8 & -13 \\ -9 & 29 & -4 \\ -5 & -4 & 11 \end{bmatrix}\]3A^2 = \begin{bmatrix} 3(31) & 3(-8) & 3(-13) \\ 3(-9) & 3(29) & 3(-4) \\ 3(-5) & 3(-4) & 3(11) \end{bmatrix}\]3A^2 = \begin{bmatrix} 93 & -24 & -39 \\ -27 & 87 & -12 \\ -15 & -12 & 33 \end{bmatrix}\]\)

3. -A,

Multiply the matrix A by -1,

\(\[-A = -1 \cdot \begin{bmatrix} -4 & 2 & 3 \\ 1 & -5 & 0 \\ 2 & 3 & -1 \end{bmatrix}\]-A = \begin{bmatrix} 4 & -2 & -3 \\ -1 & -5 & 0 \\ -2 & -3 & 1 \end{bmatrix}\]\)

4. 5I,

\(5I = \left[\begin{array}{ccc}5&0&0\\0&5&0\\0&0&5\end{array}\right]\)

The product becomes,

The product 3A² - A + 5I is equal to,

\(= \[\begin{bmatrix} 93 & -24 & -39 \\ -27 & 87 & -12 \\ -15 & -12 & 33 \end{bmatrix} - \begin{bmatrix} -4 & 2 & 3 \\ 1 & -5 & 0 \\ 2 & 3 & -1 \end{bmatrix} + \begin{bmatrix} 5 & 0 & 0 \\ 0 & 5 & 0 \\ 0 & 0 & 5 \end{bmatrix}\]\)

\(= \[\begin{bmatrix}308 & -78 & -126 \\-90 & 282 & -39 \\-50 & -42 & 99\end{bmatrix}\]\)

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Complete question -  If

A = \(\left[\begin{array}{ccc}-4&2&3\\1&-5&0\\2&3&-1\end{array}\right]\)

find the product 3A² − A + 5I

Answer:

(4)

Step-by-step explanation:

you times the thing by the thing and then go boom because 3 x 4 - 2 = 10 ez ez gg

Answer: Check out the diagram below

The reflected image is shown in red.

=================================================

Explanation:

Draw a vertical line through -2 on the x axis. This is the mirror line.

Now focus on the upper right corner of the figure, which is at (-3, -1). Notice how the horizontal distance from this corner point to the mirror line is exactly 1 unit. If we move another 1 unit to the right, then we'll arrive at (-1,-1) which is where the reflected point lands or ends up.

In short, the upper right corner point (-3,-1) reflects over x = -2 to land on (-1,-1)

----------------------

As another example, the upper left corner point (-5, -1) will move exactly 4 spaces to the right to get to the mirror line. Then we move another 4 spaces to the right to get to (2,-1).

So the upper left corner (-5,-1) will ultimately move to (2,-1) after the reflection over x = -2.

Apply these steps to the other corner points and you'll end up with what is shown below.

Take note that a point like A(-5,-1) moves to A'(1,-1), and similar to the other points as well. Also, notice that when going from A to B to C, etc we are moving clockwise. We move counterclockwise when going from A' to B' to C' etc. Reflections always swap the orientation.

Transformation involves changing the position of a shape.

The coordinates of the image are:

\(\mathbf{A '= (1,1)}\)      \(\mathbf{B' = (-1,-1)}\)     \(\mathbf{C' = (-1,-4)}\)     \(\mathbf{D' = (0,-4)}\)

\(\mathbf{E' = (0,-3)}\)      \(\mathbf{F = (1,-3)}\)

The vertices of the shape are:

\(\mathbf{A = (-5,-1)}\)

\(\mathbf{B = (-3,-1)}\)

\(\mathbf{C = (-3,-4)}\)

\(\mathbf{D = (-4,-4)}\)

\(\mathbf{E = (-4,-3)}\)

\(\mathbf{F = (-5,-3)}\)

The rule of reflection across line x =-2 is:

\(\mathbf{(x,y)=(-x -4,y)}\)

So, we have:

\(\mathbf{A '= (5 - 4,-1) = (1,-1)}\)

\(\mathbf{B' = (3-4,-1) = (-1,-1)}\)

\(\mathbf{C' = (3-4,-4) = (-1,-4)}\)

\(\mathbf{D' = (4-4,-4) = (0,-4)}\)

\(\mathbf{E' = (4-4,-3) = (0,-3)}\)

\(\mathbf{F = (5-4,-3) = (1,-3)}\)

So, the coordinates of the image are:

\(\mathbf{A '= (1,-1)}\)

\(\mathbf{B' = (-1,-1)}\)

\(\mathbf{C' = (-1,-4)}\)

\(\mathbf{D' = (0,-4)}\)

\(\mathbf{E' = (0,-3)}\)

\(\mathbf{F = (1,-3)}\)

See attachment for the image of the transformations

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Answer:

0 = 208 - 12x

Step-by-step explanation:

Since after 5 days the tree only had 208 leaves remaining, assuming that the rate of decay is constant, we can use the following equation to calculate the total number of days (starting at the 5-day mark as 0) until the tree loses all of its leaves. In this equation, the total number of days is represented by the variable x.

0 = 208 - 12x

Now that we have the equation we can solve it...

0 = 208 - 12x ... subtract 208 on both sides

-208 =  -12x   ... divide both sides by -12

17.33 = x

Finally, we can see that after 18 days (not 17.33 because we are counting full days) the tree will have lost all of its leaves.

Answer:

C (C and D)

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

3 to the 3rd power is 3x3x3=27, (-5x-2)=10 because two negatives cancel each other out and make a positive, add 27 and 10 and that equals 37. Hope this helps :)

Answer:

Infinitely many

Brainliest?

Answer:

Valid

Step-by-step explanation:

Area of the pond is 86.625 m²

Given data :

Diameter of the pond = 14m

Radius of the inner circle (pond), r = 7 m

Width of the concrete path = 1.75m

Radius of outer circle (Including pond + Path), R = 7 + 1.75 = 8.75 m

Area of the path = Area of the outer circle − Area of the inner circle.

= πR² - πr²

= 22 / 7 x ( 8.75 + 7) ( 8.75 − 7 )

= 86.625 m²

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Answer:

x8

Step-by-step explanation: bacause if you see and look really close

The translations of the graph of the parent function \(f(x) = x^2\)  that result in the graph of \(g(x) = (x + 2)^2 + 6\) will be that the parabola moved  \(2\)  units to the left and  \(6\) units up.

Translation is the act or process of changing completely. In this also the graph changes or transform. i.e. in the graph values of the expression are changing and forming new shape.

We have,

Parent Quadratic equation   \(f(x) = x^2\)

And,

Translation of graph  \(g(x) = (x + 2)^2 + 6\)

So,

Parent quadratic function works in the form of  \(f(x) = a(x-h)^2 + k\)

Here,

"h" tells if the vertex of the parabola is going left or right.

"k" determines if the vertex of the parabola is going up or down.

So, According to the question;

We have,

Translation of graph  \(g(x) = (x + 2)^2 + 6\)

So,

From equation we find out that the vertex of the parabola moved  \(2\)  units to the left and  \(6\) units up.

(Always remember if moving left means  sign would be of plus because in parent quadratic function is in the form of  \(f(x) = a(x-h)^2 + k\)  we have minus sign in it.)

Hence, we can say that the Translation of the graph of the parent function \(f(x) = x^2\)  that result in the graph of \(g(x) = (x + 2)^2 + 6\) will be that the parabola moved  \(2\)  units to the left and  \(6\) units up.

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Thus,  the higher the test statistic, the stronger the evidence against the "null hypothesis" (i.e., no relationship between Alcohol and Calories).

To calculate the test statistic for the relationship between Alcohol (X) and Calories (Y) in the Beer Large data set, you'll need to perform a linear regression analysis.

1. Access the Beer Large data set in StatCrunch and load it into the platform.
2. Select 'Stat' > 'Regression' > 'Simple Linear' from the menu.
3. Choose 'Alcohol' as the explanatory variable (X) and 'Calories' as the response variable (Y).
4. Click 'Compute' to run the linear regression analysis.

The output will provide you with the test statistic value (rounded to 1 decimal place) for the relationship between Alcohol and Calories.

This value is important when assessing the significance of the relationship between the two variables, as it helps you determine if the relationship is statistically significant or not.

Remember, the higher the test statistic, the stronger the evidence against the null hypothesis (i.e., no relationship between Alcohol and Calories).

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If the sequence of statements is executed within a loop where `j` ranges from 0 to `n`, the overall time complexity is O(n).

To compute the complexity function for a sequence of statements where the variable `j` ranges from 0 to `n`, we need to analyze the complexity of each individual statement and then sum them up.

Let's assume the time complexity of each statement is as follows:

Statement 1: O(1)

Statement 2: O(1)

...

Statement `n`: O(1)

Since all the statements have a time complexity of O(1), we can say that each statement takes constant time regardless of the input size.

Now, we need to consider the loop where `j` ranges from 0 to `n`. In each iteration of the loop, the sequence of statements is executed. Therefore, the time complexity of the loop will depend on the number of iterations.

The loop `for j in range(n)` runs `n` times. In each iteration, the sequence of statements is executed. Since each statement has a time complexity of O(1), the total complexity of the sequence of statements executed in each iteration is O(1).

Therefore, the time complexity of the loop is given by:

O(1) * n = O(n)

Finally, since the loop is the only part that depends on the input size `n`, the overall time complexity of the sequence of statements is O(n).

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Complete Question

For a sequence of statements, compute their complexity functions individually and add them up for (j=0; j < n; j++). Write the complete question.

Extend the triangle's size by -1/3 with the center point (-1,2).

The triangle's vertices of new location point are (-2,1),(0,1) and (-3,4).

The triangle's vertices' coordinates are not specified. Assume that the triangle's vertices are located at points A(2, 5), B(-4, 5) and C. (5, -4).

A point is transformed when it is moved from its original location to a new one. Reflection, rotation, translation, and dilation are examples of Dilation is the growth or contraction of an object's size. A point A(x, y) is displaced from a point (a, b) by a factor k as follows:

\(A^{'}= (k(x-a)+a,k(y-b)+b)\)

Where, (a,b)=(-1,2) and k=\(\frac{-1}{3}\).

The triangle's vertices are located at points A(2, 5), B(-4, 5), and C. (5, -4). The new address is:

\(A^{'}= (\frac{-1}{3} (2-(-1))-1,\frac{-1}{3}(5-2)+2)=(-2,1)\\B^{'}= (\frac{-1}{3} (-4-(-1))-1,\frac{-1}{3}(5-2)+2)=(0,1)\\C^{'}= (\frac{-1}{3} (5-(-1))-1,\frac{-1}{3}(-4-2)+2)=(-3,4).\)

Therefore, The triangle's vertices of new location points are (-2,1),(0,1) and (-3,4).

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Answer:

so if PT=TQ and TQ=7x-9

PT=5x+3=TQ=7x-9

5x+3=7x-9

minus 5x both sides

3=2x-9

add 9 both sides

12=2x

divide 2

6=x

PT=5x+3

PT=5(6)+3

PT=30+3

PT=33

PT=QT=33

x=6

Step-by-step explanation:

Answer:

97 / 60 is what 2/3 + 3/4 + 1/5 comes

They also come to 1 37/60

Step-by-step explanation:

1 37/60 = 97/60           Does it?

Result = 2/3 + 3/4 + 1/5

The common denominator is 3 * 4 * 5 = 60, so that much is true.

2/3 = 40/60

3/4 = 45/60

1/5 = 12 / 60

When you add these three together, the numerator is 40 + 45 + 12 = 97

So the answer is correct.

Answer:

61500m

Step-by-step explanation:

To convert km into m, multiply by 1000

Answer:

61500metres.

hope it helps.