what mass NaNO3 is needed to make 400mL of a 0.3M solution? ( molar mass = 84.99g)

Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li

To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.

Let's analyze the given representations:

36Li:

This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.

613C:

This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.

3063Cu:

This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.

1530P:

This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.

Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.

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The mass of the precipitate formed when 50mL of 16.9% (w/v) solution of AgNO 3 is mixed with 50mL of 5.8% (w/v) NaCl solution is 7.19 g.

Let's calculate the number of moles of NaCl:

Number of moles = Mass(g)/Molecular mass

Number of moles of NaCl = 50×5.8/100/58.5

= 50×5.8/100×58.5

= 0.05 mole

The mass of AgCl can be calculated by referring to Equation 1.

By applying POAC on Ag

Number of moles Ag in AgNO3 = Number of moles Ag in AgCl

Number of moles of AgCl = 0.05mole…(ii)

Molecular mass of AgCl = 143.5………..(iii)

Mass of AgCl = Number of moles × Molecular mass of AgCl ………(iv)

Substitute (ii) and (iii) in (iv)

= 0.05 × 143.5

= 7.16g

The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.

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There are three possible values for the l and there are nine possible values for ml.

The term quantum numbers has to do with the description that shows the most probable position of the electron in an atom. We know that the orbital is a region in space, where there is a high probability of finding the electrons.

Given that the values of l must be in the range of 0 to n - l and the values of ml must be in the rang of -l to + l. we then can use this to know the  number of the possible combinations of  l and ml when n = 3.

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Explanation:

To calculate the heat gained by nickel, we can use the formula:

q = m * c * ΔT

where q is the heat gained, m is the mass of the nickel, c is the specific heat of nickel, and ΔT is the change in temperature.

Given:

- Mass of nickel, m = 31.4 g

- Specific heat of nickel, c = 0.443 J/g · °C

- Change in temperature, ΔT = 64.2 °C - 27.2 °C = 37.0 °C

Substituting the values into the formula, we get:

q = (31.4 g) * (0.443 J/g · °C) * (37.0 °C)

Simplifying the calculation, we get:

q = 584 J

Therefore, the heat gained by nickel when 31.4 g of nickel is warmed from 27.2 °C to 64.2 °C is 584 J.

The non-metal elements in Group 7 – known as the halogens – get less reactive as you go down the group

Answer & Explanation:

The reactivity of elements in Group VII, also known as Group 17, decreases with increasing atomic radius. This is because halogens have high electronegativities and a proclivity to gain electrons in noble gas configurations. Myths are traditional stories or beliefs that explain cultural or societal beliefs, customs, or natural phenomena. They can be passed down through generations and can be based on true or fictitious events. Mythology, on the other hand, is the collection of myths associated with a specific culture or religion. Mythology can be amplified through retelling, incorporation into religious practices; association with significant events or figures, and adaptation into other media forms such as literature, film, or art.

Answer:

because those are the only thermometers that are truly accurate for kelvins

Explanation:

The Kelvin temperature in thermometers is used by scientists because it provides a temperature where zero indicates the complete absence of thermal energy.

All thermometers have a scale on them that we use to find the temperature, known as a temperature scale. Kelvin proposed that the temperature interval from the ice point to the steam point be defined as 100° containing earlier centigrade scales.

Lord Kelvin had given an absolute temperature scale based on the Carnot cycle.  The zero point is 273.15 on Kelvin’s scale below that of the Celsius scale.

On the kelvin scale, Each division is called a Kelvin (K) and is equal to a degree on the Celsius scale. On the Celsius scale, zero degrees is the freezing point of water while on the Kelvin scale the zero point is at absolute zero temperature.

Therefore, 0 K is equal to - 273.15°C, and 0°C is equal to 273.15 kelvins. A mathematical expression that gives the relation between the Celsius and Kelvin scales:

Temperature (K) = Temperature (°C) + 273

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Answer:

1) increase concentration

2) decrease the amount

3) decrease the concentration

4) it would increase

Explanation: edge 2021

Answer:

1) increase concentration

2) decrease the amount

3) decrease the concentration

4) it would increase

Explanation:

The evidence in figure 2 and table 1 which describes the changes in the rock after a year is the presence of a round edge.

This is referred to as the breaking down or dissolving of rocks and minerals on Earths surface through elements such as wind, water etc.

In the diagram given, the rock previously had a sharp edge but as time went on there was breakdown of the edges which resulted in it becoming round and is therefore the evidence that weathering most likely occurred in the rock.

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Based on the periodic trends in the periodic table, the most reactive element is oxygen; option C

Periodic trends in the periodic table refers to the periodic variation in the properties of the elements which is observed in the periodic table as one moves across the periodic table from left to right across a period or down a group in the periodic table.

This regular variation is also known as periodicity in the properties of elements.

Some of the periodic trends observed in the periodic table include:

Considering the most reactive element based on the periodic trends:

Titanium, Ti is a transition metal whose reactivity is intermediate as it is found in between group 2 and 3 of the periodic table

Silicon is metalloid which is not very reactive

Oxygen, O is a very reactive non-metal found in group 6A

Argon, is a noble gas which is almost inert.

Therefore, the most reactive element is oxygen.

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690 g AgCl

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[RxN - Unbalanced] AgNO₃ + ZnCl₂ → AgCl + Zn(NO₃)₂

↓

[RxN - Balanced] 2AgNO₃ + ZnCl₂ → 2AgCl + Zn(NO₃)₂

[Given] 2.4 mol ZnCl₂

[Solve] x g AgCl

Step 2: Identify Conversions

[RxN] 1 mol ZnCl₂ → 2 mol AgCl

[PT] Molar Mass of Ag - 107.87 g/mol

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol

Step 3: Stoich

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

687.936 g AgCl ≈ 690 g AgCl

Answer:

The percentage yield of sodium carbonate is 91.47%

Explanation:

we start by writing the reaction equation:

2NaCl + CaCO3 ——-> Na2CO3 + CaCl2

From the reaction we can see that 2 moles of sodium chloride produced 1 mole of sodium carbonate

Let us calculate the actual number of moles of sodium chloride produced from 112 g of it

Mathematically,

number of moles = mass/molar mass

Molar mass of sodium chloride is 23 + 35.5 = 58.5 g/mole

So the number of moles of sodium chloride produced will be 112/58.5 = 1.91 moles

The number of moles of sodium carbonate produced is half of this = 1.91/2 = 0.955

The mass of sodium carbonate produced from 0.955 moles of it will be;

number of moles * molar mass

The molar mass of sodium carbonate is 106 g/mol

So the number of moles is = 0.955 * 106 = 101.23 g

Mathematically;

percentage yield = actual yield/theoretical yield * 100%

Percentage yield = 92.6/101.23 * 100% = 91.47%

Answer: trial b

Explanation:

(I leave off the x10^23 because they both will divide out)    Use your per

Answer:

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Explanation:

The concentration of CO2 in club soda is approximately 1.1964 g/L.

To find the concentration of CO2 in club soda, we need to use the stoichiometry of the reaction and the volume and concentration of the NaOH solution used.

The balanced equation for the reaction is:

CO2(aq) + 2NaOH(aq) → Na2CO3(aq)

From the stoichiometry of the equation, we can see that 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated using the volume and concentration of NaOH solution used.

Given that 32.14 mL of 0.04202 M NaOH solution was used, we can calculate the moles of NaOH:

moles of NaOH = volume (L) × concentration (M)

moles of NaOH = 32.14 mL × 0.04202 mol/L

moles of NaOH = 0.001351 mol

According to the stoichiometry of the equation, 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated as:

moles of CO2 = (moles of NaOH) / 2

moles of CO2 = 0.001351 mol / 2

moles of CO2 = 0.0006755 mol

Now, we need to convert the moles of CO2 to grams. The molar mass of CO2 is approximately 44.01 g/mol.

mass of CO2 = moles of CO2 × molar mass of CO2

mass of CO2 = 0.0006755 mol × 44.01 g/mol

mass of CO2 = 0.02979 g

Finally, we need to express the concentration of CO2 in club soda in g/L. We are given that the sample of club soda used is 25.00 mL.

concentration of CO2 = (mass of CO2) / (volume of club soda in L)

concentration of CO2 = 0.02979 g / (25.00 mL × 0.001 L/mL)

concentration of CO2 = 1.1964 g/L

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The mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay.

The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

The number of half lives in 27 days;

n = 27 days/14 days

n = 1.929

The mass of P-32 remaining after 27 days, if the initial mass is 40g;

mass remaining = 40 g / (2^1.929)

mass remaining = 40 g / 3.808

mass remaining = 10.5 g

Thus, the mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

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The balance that can be used to measure a mass reading of 0.90 g will be a balance with ±0.01 g tolerance.

The mass reading       balance used for measurement

1.230 g                      ±0.001 g tolerance

5.43g                         ±0.01 g tolerance

4.0000g                    ±0.0001 g tolerance

6.539g                       ±0.001 g tolerance

The tolerance of a balance is the number of decimal place values shown on the balance and it is the permissible limitations measured in grams, that a balance can tolerate.

From the given parameters:

The mass reading       balance used for measurement

0.90 g                        ±0.01 g tolerance

1.230 g                      ±0.001 g tolerance

5.43g                         ±0.01 g tolerance

4.0000g                    ±0.0001 g tolerance

6.539g                       ±0.001 g tolerance

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The value of Kc for the given reaction is 0.0579 (rounded to four decimal places).

The formula for the equilibrium constant, Kc, of a reaction is given by the ratio of the product of the concentrations of the products raised to their respective stoichiometric coefficients to the product of the concentrations of the reactants raised to their respective stoichiometric coefficients.

The stoichiometric coefficients are the coefficients in the balanced chemical equation.

To determine the value of Kc for the reaction given by the following chemical equation:N2(g) + 3 H2(g) ⇌ 2 NH3(g)

we first need to write the expression for Kc.

The expression for Kc is given by the following formula:Kc = [NH3]² / [N2][H2]³.

We are given the equilibrium concentrations as follows:[N2]eq = 2.66 M[H2]eq = 0.64 M[NH3]eq = 3.34 M

We can substitute these values into the expression for Kc and obtain the following:Kc = (3.34)² / (2.66)(0.64)³ = 0.0579 (rounded to four decimal places).

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Answer:

Model C has more double the oxygen than A. I think it is B

Explanation:

Al atoms: 6, S atoms: 9, O atoms: 36, The total number of atoms is 51.

what is 3Al2(SO4)3 ?

3Al2(SO4)3 is a chemical formula that represents the compound aluminum sulfate. It is also sometimes written as Al2(SO4)3.

Aluminum sulfate is a white crystalline solid that is commonly used in water treatment, as a coagulating agent to remove impurities and suspended solids from water. It is also used in the paper industry, in the production of dyes and pigments, and as a food additive. Aluminum sulfate has a variety of other applications as well, such as in the production of aluminum and in the tanning of leather.

The formula 3Al2(SO4)3 indicates that the compound contains three molecules of aluminum sulfate, with a total of six aluminum atoms and nine sulfate ions. Each aluminum sulfate molecule consists of two aluminum atoms and three sulfate ions.

Al atoms: 6, S atoms: 9, O atoms: 36, The total number of atoms is 51.

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NaCl because it is ionic.

According to the question, solute are spread on ice in order to make it melt. The substance that would lower the freezing point of water the most is salt (NaCl) due to its ionic nature.

The more the ions that dissociate in the water, the lower the freezing point becomes.

When a cylinder is filled to a volume of 3.50 L at 760 mmHg with chlorine gas. The volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

Boyle's law is generally a gas law which states that "a gas's pressure and volume are inversely proportional when the temperature is kept constant, as volume increases, pressure falls and vice versa".

Mathematically,

P₁V₁ = P₂V₂

P₁ = 760 mmHg = 101.32 kPa

V₁ = 3.50 L

P₂ = 50 kPa

V₂ = ?

Substituting the values we get,

101.32 × 3.50 = 50 × V₂

⇒ V₂ = (101.32 × 3.50)/50

⇒ V₂ = 7.0924 L

Hence, the volume of the gas if the pressure is changed to 50.0 kPa is 7.0924 L.

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Answer:

is an assumption , in an idea that is proposed for the sake of argument so that it can be tested to see if it might be true.

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Answer:

Option B. Heptane

Explanation:

To obtain the parent name of the above compound, all we need to do is to locate the longest continuous carbon chain.

The longest continuous carbon chain of the above compound is 7.

Next, we shall also consider the chain if there is any double or triple bond.

From the diagram given above, no double or triple bond is present.

Finally, the parent name of the compound is heptane since the longest continuous carbon chain is 7 and no double or triple bond is present in the compound.

Ionic radii are a measure of the size of ions, which are atoms or molecules that have gained or lost electrons and therefore have a net electric charge. The ionic radii of elements within a group or a period can show certain trends due to the properties of the elements and the way in which their electron configurations change.

Within a group:

Within a group, ionic radii tend to increase as you go down the group. This is because elements in the same group have the same number of valence electrons (the electrons in the outermost energy level of an atom), but as you go down the group, the number of energy levels (shells) increases. This means that the outermost electrons are farther away from the nucleus, which leads to a larger atomic radius. When an atom loses or gains an electron to become an ion, the ionic radius will be similar to the atomic radius, so the ionic radii of elements within a group will also increase as you go down the group.

Across a period:

Across a period, ionic radii tend to decrease as you go from left to right. This is because elements in the same period have the same number of shells, but as you go from left to right, the number of protons (and therefore the atomic number) increases. This increases the positive charge of the nucleus, which attracts the electrons more strongly. As a result, the electrons are held closer to the nucleus, leading to a smaller atomic radius. When an atom loses or gains an electron to become an ion, the ionic radius will be similar to the atomic radius, so the ionic radii of elements across a period will also decrease as you go from left to right.

It is important to note that these trends are not always absolute and there can be some exceptions due to other factors such as electron shielding and the electron configurations of the elements.

There are several explanations for the trends in ionic radii within groups and across periods in the periodic table:

Overall, these trends in ionic radii can be explained by the interplay between the atomic size, effective nuclear charge, and the number of valence electrons of the elements.