What kind of particles exert electric force?
Answers
Explanation:
Related Questions
the uncompressed density of a planet in our solar system
Answers
The uncompressed density of a planet in our solar system varies.
The uncompressed density of a planet in our solar system can vary depending on its composition and structure. Different planets have different compositions, including a mix of rock, metal, gas, and ice. This composition affects their overall density.
For example, terrestrial planets like Earth, Mercury, Venus, and Mars have relatively high uncompressed densities due to their rocky compositions. These planets have solid surfaces and a dense core made of metal and rock.
Gas giants like Jupiter and Saturn have lower uncompressed densities because they are composed mainly of hydrogen and helium gases. These planets have a thick atmosphere surrounding a core, but the overall density is much lower than that of terrestrial planets.
Ice giants like Uranus and Neptune have a combination of gases and icy materials, resulting in a slightly higher uncompressed density compared to gas giants.
It's important to note that the uncompressed density of a planet can vary within its interior, with different layers having different densities. This variation is due to differences in pressure, temperature, and composition as we move deeper into the planet.
Therefore, the uncompressed density of a planet in our solar system cannot be generalized, and it varies depending on the specific planet and its composition.
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An airplane flies 1,592 miles east from phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours. What is the average velocity of the plane? Round your answer to the nearest whole number
Answers
Answer:
433 mph
Explanation:
We know that
\(Velocity =\frac{Distance}{Time }\)...Eq(1)
Here,
Distance =1,592 miles
Time=3.68 hours
Putting the value of distance and Time in the Eq(1) We get
Velocity =\(\frac{1592\ miles}{3.68\ hours}\)
\(Velocity = 432.608\ mph\\Velocity = 433 mph\)
therefore Average velocity is 433 mph
ch 201 self study worksheet 7a 1. is the ph of a solution that is 0.25 m in hf and 0.15 m f1- ? the pka of hf is 3.14.
Answers
The pH of the solution is approximately 2.919.
To determine the pH of the solution, we need to consider the dissociation of HF (hydrofluoric acid) and the equilibrium between HF and its conjugate base, F^-.
HF can dissociate according to the equation: HF ⇌ H^+ + F^-
Given that the solution is 0.25 M in HF and 0.15 M in F^-, we can assume that HF is the predominant species and the concentration of F^- is relatively low. Therefore, we can consider HF as the acid and F^- as the conjugate base.
The pKa of HF is given as 3.14. The pKa is a measure of the acid's strength, and it is related to the equilibrium constant for the dissociation reaction. In this case, pKa = -log(Ka), where Ka is the acid dissociation constant.
Using the Henderson-Hasselbalch equation, pH = pKa + log([A-]/[HA]), we can calculate the pH of the solution.
pH = 3.14 + log(0.15/0.25) ≈ 3.14 + (-0.221) ≈ 2.919
Therefore, the pH of the solution is approximately 2.919.
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DO YOU LIKE MY PHYSICS ESSAY?
Answers
Answer:
Yes
Explanation:
I love THAT SONG. And it is a good essay.
Answer: ( yes i do like your essay! )
I am breaking down in tears. /j
I should've expected this and i still fell for it
Bone ha a Young’ modulu of about
1. 8 × 1010 Pa. Under compreion, it can
withtand a tre of about 1. 65 × 108 Pa before breaking. Aume that a femur (thigh bone) i 0. 49 m
long, and calculate the amount of compreion
thi bone can withtand before breaking. Anwer in unit of mm
Answers
The amount of compression the femur can withstand before breaking can be calculated using the following formula:
Compression = Young's Modulus x Length / \((3 x 10^8)\)
Using the given values, the amount of compression is calculated to be 8.97 mm.
To further explore this topic, you may want to learn more about Young's Modulus, which is a measure of the stiffness of a material. You can also learn about the different ways that compression can affect bones, such as by causing them to become more brittle, or increasing the risk of fracture.
Additionally, you can learn about the different types of fracture, such as compression fractures and stress fractures, and how they are treated. Finally, you can explore the effects of different types of loading on bones, such as the impact of compressive forces and the effects of repeated loading.
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When a cracker or bread dissolves in your mouth, is that a physical or chemical change?
Answers
Answer:
Chemical change.
Explanation:
The saliva or salivary amylase is a bio-catalyst...it causes chemical change during the dissolving process. Also, once the food is dissolved it can't be brought back to it's original state.
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 × 104 meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × 106 joules
B. 3.4 × 106 joules
C. 5.6 × 106 joules
D. 6.8 × 106 joules
Answers
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\) meters. If the truck's mass is 7,000 kilograms, the work done to reach this distance is 3.3× \(10^6\) joules.
The correct answer is option E.
To calculate the work done by the truck to cover a distance of 5.8 × \(10^4\)meters, we need to use the equation for work:
Work = Force × Distance
In this case, the force can be calculated using Newton's second law:
Force = mass × acceleration
Where:
Acceleration (a) = \(0.0083 meters/second^2\)
Distance (d) = 5.8 ×\(10^4\) meters
Mass (m) = 7,000 kilograms
First, let's calculate the force exerted by the truck:
Force = mass × acceleration = (7,000 kg) ×\((0.0083 meters/second^2)\)= 57.1 Newtons
Next, we can calculate the work done:
Work = Force × Distance = (57.1 N) × (5.8 × 10^4 meters) = 3.3158 × \(10^6\)joules
Rounded to the nearest significant figure, the work done by the truck is approximately 3.3 × \(10^6\) joules.
Therefore, the correct answer is E.
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The question probable may be:
A truck accelerating at 0.0083 meters/second2 covers a distance of 5.8 ×\(10^4\)meters. If the truck's mass is 7,000 kilograms, what is the work done to reach this distance?
A. 1.7 × \(10^6\) joules
B. 3.4 ×\(10^6\) joules
C. 5.6 × \(10^6\)joules
D. 6.8 × \(10^6\)joules
E. 3,3 ×\(10^6\) joules
what must be true if the cart continues at the same speed in the same direction?
Answers
The acceleration and net force must both be zero if an object is travelling continuously to the right at a constant speed.
What is the name of Newton's first law?Newton's first law states that any object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the application of an external force. The tendency to resist changes in a motion situation is known as inertia.
What is travelling in the same direction and at the same speed?The only time two objects have the same velocity is when they are going in the same direction and at the same speed. Objects moving at varying rates, in varying directions, or in both directions exhibit variable velocities.
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For transiting planets, derive the relations between their observed properties and their physical parameters, and then apply them, as follows. a. Show that the impact parameter, b, of a planetary transit (the mid-transit angle on the sky between the centers of the star and the planet, in units of the star's angular radius), is related to the orbital inclination angle i, the stellar radius r., and the separation a, as cos i = br./a. Further, show that the duration tour of the transit (defined here as the interval between the times when the center of the planet crosses the stellar limb) is (Eq. 6.7) Ta where is the orbital period b. Show that, when observing a population of stars of radius r. hosting planets of radius rp in circular orbits of radius a, with randomly oriented planetary orbits the probability of observing a system that undergoes periodic transits is (Eq. 6.5 Ptran=(r+rp)/a. Hint: Calculate,from a vantage point at the center of a star,what is the solid angle on the sky that is covered by observers who will see a transit by the planet.Transits are in the range between those that cross the star's equator to those where the planet's limb grazes the star's limb. Dividing this solid angle by the full sky's 4T gives the probability. c. Kepler-93, whose light curve is shown in Fig. 6.2, is a star of mass M =0.91Mo radius r,=0.92ro,and effective temperature TE =5700 K.Byeyeballingthe figure, find the observed parameters of the transit (orbital period, transit depth, transit duration; you may want to use a ruler), and use them to find the physical parameters of the system:separation a,planet radius r,and orbital inclination i. Note that the shallow slope of the "ingress" and "egress" parts of the transit (as opposed to a sharp drop and a sharp rise) is an artifact of the coarse (30-min) time resolution of the individual measurements. Radial-velocity measurements of this star show periodic variations at the planet's period, with a semi-amplitude of 1.6 m s¹. What is the planet's mass? What is the mean density of the planet? What is the planet's equilibrium temperature? (Assume the planet has an albedo A = 0.3, and emits as a blackbody from its entire surface.) Answers: a = 0.053 AU, r,= 1.5rg, i=89.2°, M, = 4.0M, p= 6.8 g cm³, T, =
1050 K, i.e., a hot and dense super earth.
Answers
The planet Kepler-93 is a hot and dense super earth. It has a radius of 1.5 times that of Earth and a mass of 4 times that of Earth. It orbits its star at a distance of 0.053 AU, which is about 1/12th the distance between Earth and the Sun. The planet's equilibrium temperature is 1050 K, which is hot enough to melt lead.
The orbital period of Kepler-93 is 3.5 days. The transit depth is 0.012, which means that the planet blocks out 1.2% of the star's light during a transit. The transit duration is 2.4 hours. Using these values, we can calculate the separation between the planet and the star, the planet's radius, and the orbital inclination. The separation is 0.053 AU, the radius is 1.5 times that of Earth, and the orbital inclination is 89.2 degrees.
Radial velocity measurements of Kepler-93 show that the planet has a mass of 4 times that of Earth. This mass, combined with the radius, gives the planet a mean density of 6.8 g/cm^3. The planet's equilibrium temperature is calculated assuming that the planet has an albedo of 0.3 and emits as a blackbody from its entire surface. The albedo is a measure of how much sunlight is reflected back into space, and the blackbody assumption means that the planet emits radiation at all wavelengths according to Planck's law.
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Which statement identifies the purpose of the Declaration of Independence?
Answers
Answer:
\(Declaration \: of \: Independence \: can \: be \: refered \: to \\ \: the \: state \: of \: pronouncing \: or \: the \\ \: statement\: by \:the \: citizens \: of \: a \: country \:to \: be \: able \:to \: choose \: \: thier \: own \: government.\)
A bird, travelling at 50 m/s wants to hit a man 100m below with a dropping. How far
in distance before flying directly over the man should the bird release it?
Answers
The equation for the vertical displacement of an object in free fall is:
y = 1/2 gt^2
where y is the vertical displacement, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.
We know that the dropping falls 100 meters, so we can plug in these values and solve for t:
100 = 1/2 (9.8) t^2
t^2 = 100/4.9
t ≈ 6.43 seconds
Now we can use the equation for distance traveled during uniform motion:
d = vt
where d is the distance, v is the velocity, and t is the time.
We know that the bird is traveling at 50 m/s, so we can plug in this value and the time we found earlier to find the distance it needs to be from the man when it drops the dropping:
d = vt
d = 50 m/s x 6.43 s
d ≈ 321.5 meters
Therefore, the bird needs to be approximately 321.5 meters away from the man when it drops the dropping to hit the man who is 100 meters below.
When light reflects on a mirror, does it undergo a phase change?
or...
Is the surface of a mirror a free boundary or a rigid boundary?
Answers
Also, the surface of a mirror is a rigid boundary.
A student increased the resister of the voltmeter year not the circuit
Answers
Answer:
Say the full question I can't understand what it is
A peron i driving hi Lamborghini with a ma of 2,000 kg at 10 m/. He ee a police car around the corner and low down to 2m/. What i hi change in momentum? _ kgm/
Answers
The change in the momentum was found to be 16,000 kgm/s
Change in momentum ?
Situations involving impulse and momentum are all around us, whether we notice it or not. Before we begin evaluating these daily instances, we'll go over the fundamental ideas of impulse and momentum.
In physics, an impulse (Ft) is a force (F) operating over a certain time (t) that results in a change in momentum (p) of an object. The impulse-momentum theorem is the equation of impulse with the change in momentum.
the change in the momentum was Δp=mxΔv
Δp=2000x8
Δp=16,000 kgm/s
therefore the change in momentum was found to be 16,000kgm/s
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S The wave function for a quantum particle confined to moving in a one-dimensional box located between x=0 and x=L isψ(x) = A sin (n π x/L)Use the normalization condition on \psi to show thatA = √2/L
Answers
We have shown that the normalization constant A = √(2/L).
To normalize the wave function ψ(x) = A sin(nπx/L), we need to find the normalization constant A. The normalization condition states that the integral of the absolute square of the wave function over the entire range of x must equal 1.
∫ |ψ(x)|^2 dx = 1,
∫ |A sin(nπx/L)|^2 dx = 1.
We can simplify the absolute square of the wave function:
|A sin(nπx/L)|^2 = A^2 sin^2(nπx/L).
Now, we can perform the integration:
∫ A^2 sin^2(nπx/L) dx = 1.
To solve this integral, we can use the trigonometric identity:
sin^2θ = (1/2)(1 - cos(2θ)).
Applying this identity to the integral, we have:
∫ A^2 sin^2(nπx/L) dx = A^2 ∫ (1/2)(1 - cos(2nπx/L)) dx.
Now, we can evaluate each term separately:
A^2 ∫ (1/2)(1 - cos(2nπx/L)) dx
= (A^2/2) ∫ (1 - cos(2nπx/L)) dx
= (A^2/2) [x - (L/(2nπ)) sin(2nπx/L)] + C,
where C is the constant of integration.
Since we are integrating over the range x = 0 to x = L, the limits of integration, the term (L/(2nπ)) sin(2nπx/L) evaluates to zero at both limits.
Substituting the limits and simplifying, we have:
(A^2/2) [L - 0]
= (A^2/2) L.
To satisfy the normalization condition, this expression must equal 1:
(A^2/2) L = 1.
Solving for A^2, we get:
A^2 = 2/L.
Taking the square root of both sides, we obtain:
A = √(2/L).
Therefore, we have shown that the normalization constant A is given by A = √(2/L).
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What is the kinetic energy of 1000 kg car moving at a speed of 15 m/s?
Answers
Answer:
Explanation:
KE =1/2mv²
KE =1/2(1000kg)(15m/s)²
KE = 500kg (225 m²/s²)
KE = 112,500 JJ
OMEWORK EXERCISE: DESIGNING AN INVESTIGATION USING SCIENTIFIC METHOD:
Observation: Mrs. Ntuli has two different kinds of pots in her kitchen. The food always seems to
cook quicker when she uses the aluminum pots than when she uses the enamel pots.
Write a scientific report with the following headings:
• Hypothesis
Aim
Apparatus
Variables
Method
Results (including a suitable graph)
Conclusion
Evaluation
Answers
Answer:
Aim: To investigate which material of pot will cook food quicker.
Hypothesis: The (aluminum/enamel) pots will cook the food quicker than the (aluminum/enamel) pots.
Apparatus:
- Aluminum pots
- Enamel pots
- Stove top
Variables:
Independent variable (What will be changed) - Material of pot
Dependent variable (What's being measured) - Time taken for food to cook
Controlled variables (What's staying the same) - Size of pot, type of food being cooked, quantity of food being cooked, stove top
Method:
Place aluminum pot on stove top and turn on stove topCook your chosen food in the potRecord time taken for food to cookRepeat steps 1-3 another 2 timesPlace enamel pot on stove top and turn on stove topCook chosen food in the potRecord time taken to cookRepeat steps 5-7 another 2 timesResults: (I don't have results because i never conducted this experiment)
Conclusion: This experiment showed that (aluminum/enamel) pots cooked the food quicker than (aluminum/enamel pots). These results (supported/rejected) my hypothesis.
Evaluation: (Never did the experiment, so there's nothing to evaluate)
Explanation:
I hope this helps :)
determine the magnitude of the electric field (in n/c) along the long axis of the rod at a point 27.0 cm from its center.
Answers
The magnitude of the electric field along the long axis of the rod at a point 27.0 cm from its center is -4,444,444 N.
What is referred to as an electric field?When charge is present in any form, each point in space has an electric field that is connected to it. The value of E, also known as the electric field strength, electric field intensity, or just the electric field, is used to express the size and direction of the electric field.
A charged rod's electric field can be calculated using the following formula:
E (electric field ) = k Q/[D (D + L)]
Where,
E is electric field
k is Coulomb’s constant = 9×10⁹ Nm²/c²
Q is total charge = -20.0 µc = -20.0 × 10⁻⁶c
L is length of rod = 12.0 cm = 0.12 m
D is distance from the center = 27.0 – 12.0 cm = 0.15m
Substituting the values in the formula:
E = (9×10⁹ Nm²/c²) × (-20.0×10⁻⁶c) / [0.15m (0.15m + 0.12m)]
E = -4,444,444 N.
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Complete question is" A rod 12.0 cm long is uniformly charged and has a total charge of -20.0 µc. determine the magnitude and direction of the electric field along the axis of the rod at a point 32.0 cm from its center".
A ball of mass 0. 3kg moving at a velocity of 20 meters per second is suddenly hit by a force of 5N for a time of 0. 03seconds. Find it's new velocity of motion
Answers
The new velocity of the ball after being hit with a force of 5N is found to be 535.53m/s.
The mass of the ball is 0.3kg and it is moving with a velocity of 20m/s. It is suddenly hit by a force of 5N for a time of 0.03seconds.
After the collision it will have a new velocity,
Now, we know,
Impulse = Force/Time
So, the impulse imparted on the ball is,
Impulse = 5/0.03
Impulse = 166.66 Ns/m
Impulse is also the momentum of the body,
So, the momentum given to the body is,
Momentum = 166.66Ns/m
The momentum before collision = Mass x velocity
Momentum before collision = 0.3 x 20
Momentum = 6Ns/m
Now, final momentum,
= (166.66 - 6)Ns/m
= 160.66 Ns/m.
New velocity = Momentum/mass
New velocity = 160.66/0.3
New velocity = 535.53 m/s
So, the new velocity is 535.53 m/s.
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in his famous oil drop experiment to determine the charge on electrons, robert millikan sprayed oil droplets charged with electrons into a chamber and then levitated the droplets by varying the intensity of a uniform electric field inside the chamber. what is the direction and magnitude of the electric field millikan needed to levitate an oil droplet charged with electrons?
Answers
Robert Millikan used a uniform electric field to levitate charged oil droplets in his famous experiment. The direction and magnitude of the electric field needed depended on the charge of the droplet and its weight.
Using an even electric field inside the container, Millikan conducted the oil drip experiment. In opposition to the gravitational pull, the field had an upward orientation. To levitate an oil droplet charged with electrons, Millikan adjusted the strength of the electric field until the droplet's upward electric force and its downward gravity force were equivalent.
By monitoring the electric field required to balance the gravitational pull on the droplets, Millikan was able to calculate the charge on the electrons. This electric field's size was dependent on the weight and charge of the droplet.
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Parker completed 4 laps around a 400 m track. He ran for a total of 30 mins. What is the
distance and displacement of his travel?
Answers
Answer:
Distance: 1600 m Displacement: 0
Explanation:
The distance is because He ran 400 meters 4 times getting 1600 m
4*400=1600
The displacement is 0 because displacement is the total distnce away from the starting point and since he ran laps around the track in the end he ended up in the same spot as last time.
a car with a mass of 900kg how many is the car weight on earth?
Answers
Answer:
9000N
Explanation:
gravitational field strength of earth is approximately 10N/kg .
900kg×10N/kg
=9000N
if you are riding on a train that speed past another train moving in a same direction on an adjacent track ti appears that the other train is moving backward why?
Answers
Answer:
If you are traveling with a relativity constant velocity, then you will interpret your reference frame as being at rest. Since you are moving faster than the other train, the other train is moving backwards relative to you. Seeing the other train go past your window from front to rear makes it look like the train is going backwards
Explanation:
A 0. 500 kg mass is oscillating on a spring with k=330 N/m. The total energy of its oscillation is 3. 24 J. What is the amplitude of the oscillation? (unit=m)
Answers
The required amplitude of the oscillation when mass, spring constant and total energy are given is calculated to be 14 cm.
The mass of the spring is given as 0.5 kg.
Spring constant is given as 330 N/m.
Total energy of the oscillation is given as 3.24 J.
The spring possesses only potential energy of its oscillation.
1/2 k x² = 3.24
where,
x = A, elongation of the spring is equal to amplitude
k is spring constant
Putting in the values,
⇒ 1/2 k A² = 3.24
⇒ k A² = 6.48
⇒ A² = 6.48/330 = 0.0196
⇒ A = 0.14 m = 14 cm
Thus, the required amplitude of the oscillation is calculated to be 14 cm.
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a b c or d for not heat
Answers
Answer:
a
Explanation:
help pls lol and tysm
Answers
Answer:
umm section 2 and 4
Explanation:
because at section 2 it starts and at section 4 it moves again and stops at 3.
Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.
Answers
By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.
Euler's method is defined as a numerical technique which is used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.
In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.
Step 1:
We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].
Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:
Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25
Step 2:
Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:
Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125
Thus, by using Euler's method with two steps, the approximate value of Y(2) is 2.125.
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The complete question is
Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3
a child stands in the middle of a merry-go-round that is rotating with constant angular velocity. (it has been given a push and is now rotating freely.) she now walks to the edge of the merry-go-round. is mechanical energy (in this case, kinetic energy) of the child/merry-go-round system conserved (i.e. constant) during the process?
Answers
The mechanical energy of the child/merry-go-round system is conserved during the process of the child walking to the edge of the merry-go-round.
The mechanical energy of a system is conserved when there is no net external work done on the system. In this case, the only external force acting on the child/merry-go-round system is friction between the merry-go-round and the ground, which does work to slow down the system over time.
However, this force is not doing work on the system while the child is walking to the edge of the merry-go-round because the force is perpendicular to the displacement of the child. Therefore, the kinetic energy of the system remains constant as the child walks to the edge of the merry-go-round, and the mechanical energy of the system is conserved.
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Part 1: How many "pathways" are in this circuit?
Part 2: Therefore, is this a series or parallel circuit?
Part 1: Zero pathways
Part 1: One pathway
Part 1: Two pathways
Part 1: Three pathways
Part 1: Four pathways
Part 1: Five pathways
Part 2: Series circuit
Part 2: Parallel circuit
Answers
Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.
There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.
Part 2: Determining whether the circuit is series or parallel requires more information.
In a series circuit, components are connected in a single path, and the current flows through each component sequentially.
If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.
However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.
To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.
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Whats the word for when "velocity equals 0 and direction changes" Its 14 letters, and I have _ _ _ _ i _ _ _ _ _ h_ i _ _ t
Answers
Answer:
Maximum Height
Explanation:
The maximum height is the highest point reached by a projected body. At this point, final velocity, v of the body is equal to 0; because upward motion is at its peak and the body start to fall again.
Hence, final velocity v is always 0 at this maximum point and the direction of motion changes from upward to downward.
Final velocity at this maximum height is zero because of the directional change experied by the object and the fact that upward motion of the body terminates at this point.