What kind of instrument, developed by Leon Foucault, provides physical evidence that Earth is rotating on its axis?
pendulum
sundial
drum
flashlight
Answers
The kind of instrument that provides physical evidence that Earth is rotating on its axis is a pendulum. A pendulum is a device that swings back and forth under the influence of gravity.
It is composed of a weight suspended from a pivot point that is free to oscillate back and forth. The most fundamental application of the pendulum is to determine the value of gravity. Pendulums and the Earth's rotation A Foucault pendulum is a pendulum that hangs from a long cable and swings back and forth. The cable is affixed to a support, and the pendulum is free to oscillate in a vertical plane that is not confined to the support's plane. The reason for this is due to the Earth's rotation. The Foucault pendulum is a good example of a simple physical phenomenon that illustrates one of the essential characteristics of the Earth. The Foucault pendulum's ability to keep swinging in the same direction despite the Earth's rotation demonstrates the Earth's rotation. In summary, the instrument developed by Leon Foucault that provides physical evidence that Earth is rotating on its axis is a pendulum. The pendulum is a simple physical phenomenon that demonstrates the Earth's rotation.
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Related Questions
An atom of an element X has one more shell of electrons than an atom of berylium but it has one less valence electron thatn berylium which element is X
Answers
Answer:
Sodium
Explanation:
Sodium in period 3 has three electron shells. Recall that the period to which an element belongs shows the number of electron shells present in each atom of the element.
Beryllium is in period two, hence it possesses only two electron shells. However, beryllium is a member of group two hence it has two valence electrons in its outermost shell.
Sodium on the other hand has only one electron in its outermost shell since it is a member of group one. Hence the element must be sodium.
the focal length of a converging lens is 0.50 meters. an object is placed 1.0 meters from the lens. the distance between the lens and the image is
Answers
The distance between the lens and the image is 1.0 meter.
To find the distance between the lens and the image formed by a converging lens, we can use the lens formula:
1/f = 1/v - 1/u
Where:
f is the focal length of the lens
v is the distance of the image from the lens (positive if the image is on the same side as the observer, negative if the image is on the opposite side)
u is the distance of the object from the lens (positive if the object is on the same side as the observer, negative if the object is on the opposite side)
In this case:
Focal length (f) = 0.50 meters
Distance of the object (u) = 1.0 meter
Let's substitute the given values into the lens formula:
1/0.50 = 1/v - 1/1.0
2 = 1/v - 1
2v = v - 1
v = 1
Therefore, the distance between the lens and the image = 1.0 m.
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water is not used to control fires involving electrical equipments
Answers
Answer:
because electricity electrolyte water from which hydrogen and oxygen is produced. oxygen is responsible to burn and to blast.so water is not useful .
Animal studies indicate that
Answers
Answer: mammals may be relatively better at solving problems than birds.
Answer: A
Explanation:
mammals may be relatively better at solving problems than birds
A man standing on the top of a tower 60m high throws a ball with a velocity of 20m/s in the vertically u[wards direction.
(a) How long will it take the ball to pass the man moving in the downwards direction ?
(b) What is the maximum height attained by the ball ?
(c) How long will it take the ball to hit the ground ? ( Take g = 10 m/s^2 )
Answers
(a) It will take 2 seconds for the ball to pass the man moving in the downward direction.
(b) The maximum height attained by the ball is 20 meters.
(c) The ball will take 2+2\sqrt{2} seconds to hit the ground.
(a) How long will it take the ball to pass the man moving in the downward direction?
We can use the equation of motion:
v = u + at,
where:
v = final velocity (0 m/s since the ball will momentarily stop when passing the man),
u = initial velocity (20 m/s upwards),
a = acceleration (due to gravity, -10 m/s²),
t = time.
Substituting the known values we get:
0 = 20 - 10t.
Simplifying the equation:
10t = 20,
t = 20/10,
t = 2 seconds.
Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.
(b) What is the maximum height attained by the ball?
To find the maximum height attained by the ball, we can use the following equation:
v² = u² + 2as,
where:
v = final velocity (0 m/s at the maximum height),
u = initial velocity (20 m/s upwards),
a = acceleration (acceleration due to gravity, -10 m/s²),
s = displacement.
The maximum height will be achieved when v = 0. Rearranging the equation, we get:
0 = (20)² + 2(-10)s.
Simplifying the equation:
400 = -20s.
Dividing both sides by -20:
s = -400/-20,
s = 20 meters.
Therefore, the maximum height attained by the ball is 20 meters.
(c) How long will it take the ball to hit the ground?
To find the time it takes for the ball to hit the ground, we can use the following equation:
s = ut + (1/2)at²,
where:
s = displacement (60 meters downwards),
u = initial velocity (20 m/s upwards),
a = acceleration (acceleration due to gravity, -10 m/s²),
t = time.
Rearranging the equation, we get:
-60 = 20t + (1/2)(-10)t².
Simplifying the equation:
-60 = 20t - 5t².
Rearranging to form a quadratic equation:
5t² - 20t - 60 = 0.
Dividing both sides by 5:
t² - 4t - 12 = 0.
Solving the equation using the quadratic formula, we get:
t = (4 ± sqrt(16 + 4 x 12)) / 2
t = (4 ± 4sqrt(2)) / 2
t = 2 ± 2sqrt(2)
Since time cannot be in negative terms, we ignore the negative value of t. Therefore, the time it takes for the ball to hit the ground is:
t = 2 + 2sqrt(2) seconds
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(a) How long will it take the ball to pass the man moving in the downwards direction ?
Using Equation of Motion:-
\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{v = u + at}}}}}\)
where:-
→ v denotes final velocity→ u denotes initial velocity→ a denotes acceleration→ t denotes timePlugging in Values:-
\( \large \sf \longrightarrow \: v = u + at\)
\( \large \sf \longrightarrow \: 0 = 20 + ( - 10)t \: \)
\( \large \sf \longrightarrow \: 0 - 20=( - 10)t \: \)
\( \large \sf \longrightarrow \: - 10t = - 20\: \)
\( \large \sf \longrightarrow \: t = \frac{ - 20}{ - 10} \\ \)
\( \large \sf \longrightarrow \: t = 2 \: secs \\ \)
Therefore, it will take 2 seconds for the ball to pass the man moving in the downward direction.
________________________________________
\( \\\)
(b) What is the maximum height attained by the ball ?
→ To solve the given problem, we can use the equations of motion
Using Equation of Motion:-
\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ {v}^{2} = {u}^{2} + 2as}}}}}\)
where:
→ v denotes final velocity→ u denotes initial velocity→ a denotes acceleration→ s denotes displacementPlugging in Values:-
\( \large \sf \longrightarrow \: {v}^{2} = {u}^{2} + 2as\)
\( \large \sf \longrightarrow \: {(0)}^{2} = {(20)}^{2} + 2( - 10)s\)
\( \large \sf \longrightarrow \: 0 = 400 + 2( - 10)s\)
\( \large \sf \longrightarrow \: 400 + (- 20)s = 0\)
\( \large \sf \longrightarrow \: 400 - 20 \: s = 0\)
\( \large \sf \longrightarrow \: - 20 \: s = - 400\)
\( \large \sf \longrightarrow \: \: s = \frac{ - 400}{ - 20} \)
\( \large \sf \longrightarrow \: \: s = 20 \: metres\)
Therefore, the maximum height attained by the ball is 20 meters.
________________________________________
\( \\\)
(c) How long will it take the ball to hit the ground ?
Using Equation of Motion:-
\( \large\bigstar \: \: \: { \underline { \overline{ \boxed{ \frak{ s= ut + \frac{1}{2}a{t}^{2}}}}}}\)
where:
→ s denotes Displacement → u denotes initial velocity→ a denotes acceleration→ t denotes timePlugging in Values:-
\( \large \sf \longrightarrow \: s= ut + \frac{1}{2}a{t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t + \frac{1}{2}(-10){t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t + \frac{-10}{2}\times{t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t + (-5)\times{t}^{2}\)
\( \large \sf \longrightarrow \: -60= 20t-5\times{t}^{2}\)
\( \large \sf \longrightarrow \: 20t-5{t}^{2}+60\)
\( \large \sf \longrightarrow \: {t}^{2}-4t-12\)
\( \large \sf \longrightarrow \: t=\frac{-b \pm\sqrt{{b}^{2}-4ac}}{2a} \)
\( \large \sf \longrightarrow \: t=\frac{-(-4) \pm\sqrt{{(-4)}^{2}-4(1)(-12)}}{2(1)} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-4(-12)}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16-(-48)}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{16+48}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm\sqrt{64}}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 \pm 8}{2} \)
\( \large \sf \longrightarrow \: t=\frac{4 + 8}{2} \qquad or \qquad t=\frac{4 - 8}{2} \)
\( \large \sf \longrightarrow \: t=\frac{12}{2} \qquad or \qquad t=\frac{-4}{2} \)
\( \large \sf \longrightarrow \: t=6 \qquad or \qquad t= -2 \)
Since time cannot be negative , Therefore, it will take 6 secs to hit the ground!!
________________________________________
\( \\\)
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While traveling along a highway a driver slows from 31 m/s to 15 m/s in 8 seconds. What is the automobile’s acceleration? (Remember that a negative value indicates a slowing down or deceleration.)
Answers
Answer:
The automobile's acceleration in that time interval is -2 m/s^2
Explanation:
The acceleration is defined as the rate of change of the velocity.
The average acceleration in a given lapse of time is calculated as:
A = (final velocity - initial velocity)/time.
In this case, we have:
initial velocity = 31 m/s
final velocity = 15 m/s
time = 8 seconds.
Then the average acceleration is:
A = (15m/s - 31m/s)/8s = -2 m/s^2
2.
A dolphin can hear sounds with frequencies up to 280 kHz. What is the
speed of sound in water if a wave with this frequency has a wwavelength
of 0.51 cm?
Answers
Answer:
1428 m/s
Explanation:
Given that,
The frequency hear by a dolphin, f = 280 kHz
We need to find the speed of sound in water if a wave with this frequency has a wavelength of 0.51 cm.
The formula for the speed in terms of wavelength and frequency is given by :
\(v=f\lambda\\\\v=280\times 10^3\times 0.51\times 10^{-2}\\\\v=1428\ m/s\)
So, the speed of sound in water is 1428 m/s.
no atomic ___ is a picture of an atom but only helps explain the ___ of one
Answers
No atomic model is a picture of an atom but only helps explain the behavior of one
What is the atom?We know that the atom is the smallest particle of a substance that is able to take part in a chemical reaction. We know that in the atom there are certain smaller particles that we can be able to refer to as the subatomic particles.
In this case, we are talking about the different models that we can be able to use to show the atom. None of these models can be said to show the atom exactly but can approximate how the atom behaves.
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How would a roller coaster be different if it were on the moon, where the gravitational field is weaker?
Answers
Answer:
it would accelerate more slowly so you'd have to wait a while for it to go to full speed
Explanation:
Answer:
A roller coaster would definitely not depend gravity to be fast. Roller coasters are usually designed to use gravitational energy in the first peak to generate enough inertia to have the speed to go really fast throughout the rest of the ride without much more propellant power from the actual engineering of the track. So a roller coaster would probably have to continuously pull the cars in order to fight the weak gravitation field that would prevent the cars from accelerating when falling.
if a boat is traveling a distance of 60 km at a speed of 13km/s how long will it take to reach its destination
Answers
Answer:
4.61
60/13=4.61 so that is your answer : )
ightning is an electrostatic discharge between two electrically charged regions that allows electrons in a negatively charged region to flow back to the positive region. how did these regions in thunderstorms get oppositely charged to begin with?
Answers
The process of charge separation, driven by updrafts and downdrafts in a thunderstorm, causes regions within the storm cloud to become oppositely charged, leading to the Electrostatic discharge known as lightning.
Lightning occurs due to electrostatic discharge between two electrically charged regions within a thunderstorm. These regions become oppositely charged through a process called charge separation.
Charge separation begins when updrafts and downdrafts within a thunderstorm cause ice particles, hail, and water droplets to collide. During these collisions, electrons are transferred between particles, resulting in some particles becoming positively charged while others become negatively charged.
The lighter, positively charged ice particles are carried upward by the updrafts, accumulating at the top of the storm cloud. Conversely, the heavier, negatively charged particles, such as hail, are carried downward by gravity and downdrafts, accumulating at the base of the cloud.
This separation of charges creates an electric field between the top and bottom regions of the cloud. When the electric field becomes strong enough, it overcomes the air's insulating properties, allowing electrons to flow from the negatively charged region to the positively charged region. This flow of electrons results in a lightning discharge.
In summary, the process of charge separation, driven by updrafts and downdrafts in a thunderstorm, causes regions within the storm cloud to become oppositely charged, leading to the electrostatic discharge known as lightning.
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Highlight the transformation of Polaroid in recent years
Answers
The transformation of Polaroid in recent years has been characterized by a shift from analog instant photography to embracing digital technologies and modernizing its product offerings. This transformation has allowed Polaroid to adapt to the changing market and cater to the needs and preferences of today's consumers.
In recent years, Polaroid has introduced a range of digital instant cameras that combine the nostalgic appeal of instant photography with the convenience and versatility of digital imaging. These cameras typically feature built-in printers that produce instant prints, capturing the essence of Polaroid's iconic instant photography experience. Additionally, Polaroid has embraced the smartphone era by developing products like the Polaroid Lab, which allows users to turn digital photos from their smartphones into classic Polaroid-style prints.
Furthermore, Polaroid has expanded its product lineup to include various accessories, such as portable printers and film formats compatible with both analog and digital devices. By embracing digital technologies while staying true to its instant photography heritage, Polaroid has successfully repositioned itself in the market, appealing to a new generation of photography enthusiasts seeking a blend of nostalgia and modern functionality.
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A bus contains a 1420 kg flywheel (a disk that has a 0.65 m radius) and has a total mass of 10800 kg.
Calculate the angular velocity the flywheel must have to contain enough energy to take the bus from rest to a speed of 18 m/s in rad/s, assuming 90.0% of the rotational kinetic energy can be transformed into translational energy. How high a hill can the bus climb with this stored energy and still have a speed of 3.15 m/s at the top of the hill in m?
Answers
The angular velocity of the flywheel must be approximately 184.79 rad/s. The bus can climb a hill with a height of approximately 114.68 m and still have a speed of 3.15 m/s at the top.
To calculate the angular velocity of the flywheel, we first determine its moment of inertia (I) using the formula (1/2) * m * r^2, where m is the mass (1420 kg) and r is the radius (0.65 m). This gives us I = 290.725 kg·m^2.The kinetic energy required to accelerate the bus from rest to a speed of 18 m/s is calculated by multiplying 90% of the rotational kinetic energy by 0.9 * (1/2) * I * ω^2. Solving for ω, we find ω = 184.79 rad/s. To determine the maximum hill height, we equate the initial rotational kinetic energy (0.9 * K) to the potential energy at the top of the hill, which is m * g * h, where m is the total mass of the bus (10800 kg), g is the acceleration due to gravity, and h is the height. Solving for h, we find the bus can climb approximately 114.68 m while maintaining a speed of 3.15 m/s at the top.
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What is the magnitude of the velocity of a 25 kg mass that is moving with a momentum of 100 kg*m/s?
Answers
Answer:
v= 4 m/s
Explanation:
Momenutm is, by definition, the product of mass and velocity.
\(p = mv\)
Let's replace what we know and solve for whatever's left
\(100 kg\cdot m/s = 25kg \cdot v \rightarrow v= 4 m/s\)
we've seen that squid can escape from predators by ejecting water. some squid do this at the surface of the ocean, thus launching themselves into the air-a particularly effective escape strategy. (figure 1) suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.
Answers
The law of conservation of momentum states that when two or more bodies act on each other in an isolated system, their total momentum remains constant unless an external force acts on them. Therefore, it can neither be created nor destroyed.
m₁v₁ = m₂v₂
For the given question:
m₁ = mass of squid (36 kg)
v₁ = velocity of squid (3.5 m/s)
m₂ = mass of water (3.0 kg)
v₂ = velocity of water
Substitute the values:
36 × 3.5 = 3.0 × v₂
v₂ = 42 m/s
The maximum range:
R = (v₂)²/ g
where,
g = 9.8 m/s² and launch angle 45°
R = 3.5²/9.8
R = 1.25 m
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The complete question is as follows:
We've seen that squid can escape from predators by ejecting water. Some squid do this at the surface of the ocean, thus launching themselves into the air-a particularly effective escape strategy. Suppose a 36 kg squid (not including water) at rest at the surface of the water brings in and quickly ejects 3.0 kg of water to achieve a takeoff speed of 3.5 m/s; these are typical numbers.
At what speed does the squid eject the water?
If we ignore lift and drag forces as the squid flies through the air, what is the maximum horizontal range that the squid can achieve before splashing down?
1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Answers
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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Longitudinal seismic waves are known as
a primary waves.
b. secondary waves.
surface waves.
d. transverse waves.
Please select the best answer from the choices provided
О А
ОВ
ОС
D
Answers
Answer:
A. primary waves
Explanation:
An object moves along a straight line so that at any time t greater than or equal to 0 it's velocity is given by v(t)= 2cos(3t). What is the distance traveled by the object from t=0 to the first time that it stops?
A. 0
B. Pi/6
C. 2/3
D. Pi/3
E. 4/3
Answers
The distance traveled by the object from t=0 to the first time that it stops is 2/3. So, option C. is correct.
To find the distance traveled by the object from t=0 to the first time it stops, we first need to determine when the object stops. The object stops when its velocity v(t) is equal to 0:
v(t) = 2cos(3t) = 0
This occurs when cos(3t) = 0.
The first positive value for t that satisfies this equation is when 3t = π/2, which gives us t = π/6.
Now, we need to find the distance traveled. Since we know the velocity function v(t), we can find the position function s(t) by integrating v(t):
s(t) = ∫v(t)dt = ∫2cos(3t)dt
Integrating the function gives:
s(t) = (2/3)sin(3t) + C
As the initial condition is s(0) = 0, we find C = 0.
So, the position function is:
s(t) = (2/3)sin(3t)
Now, we can find the distance traveled by the object from t=0 to t=π/6:
Distance = s(π/6) - s(0)
= (2/3)sin(3(π/6)) - (2/3)sin(0)
= (2/3)sin(π/2) - 0
= (2/3)(1)
= 2/3
So, the correct answer is C option.
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if two firecrackers produce a sound level of 86 db when fired simultaneously at a certain place, what will be the sound level if only one is exploded? [hint: add intensities, not db 's.] express your answer to two significant figures and include the appropriate units.
Answers
The sound level of 86dB when fired simultaneously will have sound level of 82.9898dB.
Theory-
According to the Beta factor model, the common cause will have an equal impact on every member of a component group that shares a common cause.
The beta factor model is simple to use, models common cause failures, and only requires one parameter to be determined.
A drawback of the beta factor model is that it is impossible to quantify the failure of k–m components within a common cause component group.
As a result of multiplying the partial beta factors, the beta factor is calculated.
Mathematics-
\(\beta =10log\frac{2I}{i} \\\\\beta 1=10log\frac{I}{i} \\\\\beta =10log2 +\beta 1\\\\\beta 1=\beta -10log2\)
Calculation-
\(\beta 1=86-10log2\\\\\beta 1=86-3.0102\\\\\beta 1= 82.9898dB\)
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What is a concentrated solution
Answers
Answer:
A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute.
the teacher said to the students you can go home change the folowing sentence into indirect
Answers
Explanation:
The teacher said to the students you can go home.
Into indirect speech
The teacher told the students that they could go home.
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After falling for 5.5 seconds, what would be the final velocity of the object?
(Picture Provided)
Please I need help on this!
Answers
The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.
What is Final velocity?
The second approach determines the amount of velocity change brought on by acceleration over a given period of time.
Finally, the average velocity formula is used in the third section of the velocity calculator, which may be helpful if you need to examine trips with varying speeds across different distances.
According to the definition of velocity, it is the rate at which an object's position changes over time. Consideration of body motion is one of the fundamental ideas in classical mechanics.
Therefore, The first one is based on the fundamental definition of velocity that employs the widely used velocity equation.
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7. What is the kinetic energy when the moving cart is 2/3 the way down (height=5 m) when the total mechanical energy is _____________
Please I need someone to help me with this?!
Answers
(a) The kinetic energy of the cart when it moves is 2/3 the way down is 1/3mgh.
(b) The total mechanical energy of the cart at the given height of 5 m is 5mg.
Potential energy of the cart
The potential energy of the cart when it is 2/3 way down the given height of 5 m is calculated as follows;
ΔP.E = mghf - mgh₀
ΔP.E = mg(hf - h₀)
ΔP.E = mg(2h/3 - h)
ΔP.E = -¹/₃mgh
Kinetic energy of the cartΔK.E = -ΔP.E
ΔK.E = ¹/₃mgh
Total mechanical energy of the cartM.A = P.E + K.E
M.A = ²/₃mgh + ¹/₃mgh
M.A = mgh
M.A = mg(5)
M.A = 5mg
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The reason Senators are in office for 6 years is...
No links pls or I’m reporting you :)
1) To separate Senators from the whims of the
general public.
2) to save money in elections
3) Because Senators are required to be older
than representatives
Answers
True or false? if we want to build a telescope that detects radio waves, we must build it with a very large dish since radio waves have very large wavelengths,
Answers
Building a telescope that detects radio waves must be built with a very large dish since radio waves have very large wavelengths is regarded as a true statement.
Wavelength can be defined as the spatial period of a periodic wave—the distance over which the wave's shape repeats.
It is the distance between consecutive corresponding points of the same phase on the wave, such as two adjacent crests, troughs, or zero crossings, and is a characteristic of both traveling waves and standing waves, as well as other spatial wave patterns.
Radio waves are a type of electromagnetic radiation with the longest wavelengths in the electromagnetic spectrum, typically with frequencies of 300 gigahertz (GHz) and below.
Radio waves are generated artificially by an electronic device called a transmitter, which is connected to an antenna which radiates the waves. They are received by another antenna connected to a radio receiver, which processes the received signal.
Radio waves are very widely used in modern technology for fixed and mobile radio communication, broadcasting, radar and radio navigation systems, communications satellites, wireless computer networks and many other applications.
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1. Calculate the total binding energy of 12
6 C.
Answer in units of MeV.
2. Calculate the average binding energy per nucleon of 24
12Mg.
Answer in units of MeV/nucleon.
3. Calculate the average binding energy per nucleon of 85
37Rb.
Answer in units of MeV/nucleon.
4. Find the binding energy per nucleon of 238
92U.
Answer in units of MeV/nucleon.
5. Calculate the total binding energy of 20
10Ne.
Answer in units of MeV.
6. Calculate the total binding energy of 40
20Ca.
Answer in units of MeV.
Answers
Answer:
1. B = 79.12 MeV
2. B = -4.39 MeV/nucleon
3. B = 2.40 MeV/nucleon
4. B = 7.48 MeV/nucleon
5. B = -18.72 MeV
6. B = 225.23 MeV
Explanation:
The binding energy can be calculated using the followng equation:
\( B = (Zm_{p} + Nm_{n} - M)*931 MeV/C^{2} \)
Where:
Z: is the number of protons
\(m_{p}\): is the proton's mass = 1.00730 u
N: is the number of neutrons
\(m_{n}\): is the neutron's mass = 1.00869 u
M: is the mass of the nucleus
1. The total binding energy of \(^{12}_{6}C\) is:
\( B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u \)
\( B = (6*1.00730 + 6*1.00869 - 12.011)*931.49 MeV/u = 79.12 MeV \)
2. The average binding energy per nucleon of \(^{24}_{12}Mg\) is:
\( B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u \)
Where: A = Z + N
\( B = \frac{(12*1.00730 + 12*1.00869 - 24.305)}{(12 + 12)}*931.49 MeV/u = -4.39 MeV/nucleon \)
3. The average binding energy per nucleon of \(^{85}_{37}Rb\) is:
\( B = \frac{(Zm_{p} + Nm_{n} - M)}{A}*931.49 MeV/u \)
\( B = \frac{(37*1.00730 + 48*1.00869 - 85.468)}{85}*931.49 MeV/u = 2.40 MeV/nucleon \)
4. The binding energy per nucleon of \(^{238}_{92}U\) is:
\( B = \frac{(92*1.00730 + 146*1.00869 - 238.03)}{238}*931.49 MeV/u = 7.48 MeV/nucleon \)
5. The total binding energy of \(^{20}_{10}Ne\) is:
\( B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u \)
\( B = (10*1.00730 + 10*1.00869 - 20.180)*931.49 MeV/u = -18.72 MeV \)
6. The total binding energy of \(^{40}_{20}Ca\) is:
\( B = (Zm_{p} + Nm_{n} - M)*931.49 MeV/u \)
\( B = (20*1.00730 + 20*1.00869 - 40.078)*931.49 MeV/u = 225.23 MeV \)
I hope it helps you!
Information travels at 120 metres per second in neurones. Calculate the time it would take for the information to travel 2.3 m along a neurone. Give your answer in milliseconds.
Answers
Answer:
5 remainder 5
Explanation:
divide 120 by 2.3
To calculate the time it would take for information to travel a certain distance along a neuron, you can use the formula: Time = Distance / Speed.
Given that the information travels at 120 meters per second and the distance is 2.3 meters:
Time = 2.3 m / 120 m/s
Time ≈ 0.019167 seconds
To convert seconds to milliseconds, multiply by 1000:
Time in milliseconds ≈ 0.019167 s * 1000 ms/s ≈ 19.167 ms
So, it would take approximately 19.167 milliseconds for the information to travel 2.3 meters along a neuron.
To know more about neuron:
https://brainly.com/question/29462317
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Directions. Read and understand each item carefully. Write your answers on the space provided.
1. Create a graphic representation based on the following data tabulated on Table 2 and make an interpretation of
the graph. Make sure to coordinate points correctly and trace line to show motion of the object.
Table 2. The distance travelled by a car in a given time.
(Dudes I need this today, pls answer this correctly)
Answers
Answer:
Please find attached the required graph of the data points
The graph can be interpreted as showing that which was at rest starts moving at a constant speed of 2 km/min
Explanation:
The table is presented as follows;
\(\begin{array}{lcl}Time \ (min)&& Distance \ (km)\\0&&0\\5&&10\\10&&20\\15&&30\\20&&40\\25&&50\\30&&60\end{array}\)
The graphic representation of the above data can be created by plotting the Time on the x-axis and the Distance on the y-axis on a graph paper
The graph of the data can be created also using a spreadsheet application such as MS Excel by using the Chart function under the Insert menu, after selecting the points input into cells on the spreadsheet as shown in the attached drawing
The distance travelled by the car in a given time is found by obtaining the rate of change of the values of the graph, m, as follows;
\(m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
Where (y₁, x₁), and (x₂, y₂) are a pair of chosen points on the given line
When, the chosen points are (y₁, x₁) = (0, 0), and (x₂, y₂) = (30, 60), we get;
\(m =\dfrac{60 \, km-0 \, km}{30 \, min-0 \, min} = 2 \, km/min\)
The graph can be interpreted as showing that the rate of change of the distance travelled by the car per unit time which is the speed of the car starting from rest is 2 km/min
A hospital has a back-up generator to power the medical devices in case of a
power failure. Which of the following is the most likely source of mechanical
energy for the generator?
A. Burning coal
B. Sunlight
C. Gasoline or diesel fuel
D. Falling water
Answers
Answer:
C
Explanation:
what would happen to the pressure of gas particles suddenly stopped moving
Answers
If the gas particles suddenly stopped moving, the pressure of the gas would drop to zero.
Pressure is caused by the collisions of gas particles with the walls of a container. When gas particles are moving, they collide with the walls of the container and exert a force on them, creating pressure. If the gas particles suddenly stopped moving, they would no longer collide with the walls of the container and the pressure would drop to zero.
However, it is important to note that in reality, it is impossible for gas particles to suddenly stop moving. This is because gas particles are always in motion due to their kinetic energy. If the gas particles were to stop moving, they would need to lose all of their kinetic energy, which is not possible according to the laws of thermodynamics.