What is the volume of this rectangular pyramid?
9 cm
8 cm
15 cm
_______ cubic centimeters

Answer:

12.56 =13

Step-by-step explanation:

Area of Circle is =

\(\pi \: r ^{2} \)

R=2 in

Putting value of r in formula.

Area of Circle =12.56=13

Please mark branliest if you satisfied with the answer. Thanking you in anticipation.

The forecasted sales in August 2021, using exponential smoothing with a smoothing constant of 0.31, is approximately 52.3251 units.

Exponential smoothing is a forecasting method that assigns weights to historical data points, giving more importance to recent observations. The forecasted value for a specific period is calculated by combining the actual value for that period with the forecasted value for the previous period. The formula for exponential smoothing is:

Ft = α * At-1 + (1 - α) * Ft-1

Where Ft is the forecasted value for period t, At-1 is the actual value for the previous period, Ft-1 is the forecasted value for the previous period, and α is the smoothing constant.

Given that the forecast in April 2021 was 39 units and the monthly sales data from April to September 2021 are 48, 55, 46, 54, 53, and 52 units, we can calculate the forecasted sales for each subsequent month using the exponential smoothing formula.

Using the given values and the formula, we can calculate the forecasted sales for August 2021 as follows:

Ft = 0.31 * 52 + (1 - 0.31) * 52.3251 = 52.3251

Therefore, the forecasted sales in August 2021, rounded to at least 4 decimals, is approximately 52.3251 units.

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The given information is:

- They surveied 164 pet owners

- 61 own a dog

- 66 own a cat

- 11 own both a dog and a cat

We have to find how many owned neither a cat nor a dog.

We can represent this survey in the following diagram:

To find the solution we need to subtract the number of people who said they own a dog, own a cat, and own both, from the total number of people in the survey, so:

The people who own neither a dog nor a cat are 26.

Answer:

113F

Step-by-step explanation:

......................

Answer:

113F

Step-by-step explanation:

(a) correctly describes the relationship between a parameter and a statistic.

The correct description is:

a) A statistic is calculated from sample data and is generally used to estimate a parameter.

In statistics, a parameter refers to a characteristic or measure that describes a population, while a statistic is a characteristic or measure calculated from sample data. Statistics are often used to estimate or infer the corresponding parameters of the population. Therefore, option (a) correctly describes the relationship between a parameter and a statistic.

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Answer:

down below

Step-by-step explanation:

Top left: X is greater than or equal to 3. Top right: X is less than or equal to 3. Bottom left: X is greater than 3. Bottom right: X is less than 3.

The greater than or equal to sign and the less than or equal to sign has a closed circle because it is marking the point and moving forward or back. Ex: less than or equal to 3. It would be a closed circle because it is the specific point and what ever is beyond or behind it. The less than or greater than sign would have a closed circle because it is only what is beyond or behind the certain number.

Hope this helps! :)

(a) For y''+4y=sin2t+(2t+1)cos2t+tsint, we need to find a particular solution Y(t) using the method of undetermined coefficients.

Since the right-hand side of the equation contains sin(2t), cos(2t), and tsin(t), we can assume that the particular solution has the form:

Y(t) = A sin(2t) + B cos(2t) + Ct sin(t) + Dt cos(t) + Et + F

where A, B, C, D, E, and F are undetermined coefficients to be determined.

(b) For y''-4y'+4y=t^2(e^(2t)-1), we need to find a particular solution Y(t) using the method of undetermined coefficients. Since the right-hand side of the equation contains t^2e^(2t) and t^2, we can assume that the particular solution has the form:

Y(t) = (At^2 + Bt + C)e^(2t) + Dt^2 + Et + F

where A, B, C, D, E, and F are undetermined coefficients to be determined.

(c) For y''+2y'+2y=3e^(-t)+2e(-t)cos(t)+4(t^2)e^(-t)sin(t), we need to find a particular solution Y(t) using the method of undetermined coefficients. Since the right-hand side of the equation contains e^(-t), e^(-t)cos(t), and t^2e^(-t)sin(t), we can assume that the particular solution has the form:

Y(t) = Ae^(-t) + (Bt + C)e^(-t)cos(t) + (Dt + Et^2) e^(-t)sin(t) + F

where A, B, C, D, E, and F are undetermined coefficients to be determined.

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Unfortunately your teacher is using x as both a variable and a multiplication sign. This is something that can be avoided by using something like the asterisk symbol to indicate multiplication.

Anyways, notice how the expression \(3^x*2^{2x}+1\) shows up twice. Once in the numerator (the entire numerator) and once again in the denominator (nearly the whole thing)

Let's replace that messy expression with the variable y. So we're letting \(y = 3^x*2^x+1\)

This means,

\(\frac{3^x*2^2+1}{3^x\left(3^x*2^2+1\right)} = \frac{y}{3^x*y}\)

At this point you can probably see how to get \(\frac{1}{3^x}\) from here. The y terms cancel out when we divide leaving 1 up top and 3^x down below.

Answer: 0.34439?

Happy To help :)

Step-by-step explanation:

Answer:

0.34439  or if you put it the other way its

344.39

The function f(x) = x² - 7 is an example of a function that is neither even nor odd, as it does not exhibit either type of symmetry.

To determine whether a function is even, odd, or neither, we need to examine its algebraic form and look for a particular type of symmetry.

Let's apply this concept to the given function, f(x) = x² - 7. To determine whether f(x) is even or odd, we need to evaluate f(-x) and compare it to f(x).

f(-x) = (-x)² - 7 // substitute -x for x

= x² - 7 // simplify

Comparing f(-x) to f(x), we can see that they are not equal:

f(-x) = x² - 7

f(x) = x² - 7

Since f(-x) is not equal to f(x), the function is not even. To determine whether it is odd, we need to evaluate f(-x) + f(x) and see if the result is zero.

f(-x) + f(x) = (x² - 7) + (x² - 7) // substitute -x for x in the second term

= 2x² - 14

Since f(-x) + f(x) is not equal to zero for all values of x, the function is not odd either.

Therefore, we can conclude that the given function, f(x) = x² - 7, is neither even nor odd.

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The number -17/20 belongs to the set of real numbers.

What is the set of real numbers?

The set of real numbers is made by combining the set of rational numbers and the set of irrational numbers. Real numbers include natural numbers or counting numbers, whole numbers, integers, rational numbers (fractions and repeating or terminating decimals), and irrational numbers.

All real numbers, including fractions and decimals, are part of the set of real numbers.

The set of real numbers includes all numbers that can be expressed on the number line, including positive and negative numbers, as well as all fractions and decimals.

This set is often denoted by the symbol "ℝ".

Hence, The number -17/20 belongs to the set of real numbers.

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The high temperature for today using a 3-day moving average is 92 degrees.

To calculate the high temperature for today using a 3-day moving average, we take the average of the temperatures from the past three days, including today.

Given the daily high temperatures in St. Louis for the last week:

92, 92, 93, 95, 95, 86, 95 (yesterday)

To find the 3-day moving average for today's high temperature, we consider the temperatures from yesterday, the day before yesterday, and three days ago.

(95 + 86 + 95) / 3 = 92

Therefore, the high temperature for today, calculated using a 3-day moving average, is approximately 92 degrees Fahrenheit, rounded to one decimal place.

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Answer:

y = 3x + 4

Step-by-step explanation:

A parallel line has the same slope as the reference line.

y = mx + b  (m is the slope and b is the y-intercept)

The reference line, y = 3x + 2, has a slope of 3.

We need another line of the form y = 3x + b,  So all we need is a new b.  Any value we choose for b will result in a straight line.  But our line needs to go through point (2,10), so we need a specific value for b that will move the line to the appropriate position.

We can find b by entering the point and solving for b:

y = 3x + b      (2,10)

10 = 3*(2) + b

b = 4

The equation becomes y = 3x + 4

Answer:

y=-3/5-3

Step-by-step explanation:

Answer: constant of proportionality

Explanation: Assuming that we have two proportional quantities; one is x and one is y. If you know whether the relationship between them is direct or inverse proportion, then the ratio of the two quantities y/x gives us a constant generally known as the constant of proportionality.

The patient will pay $452.20 in full today after applying the 15% discount.

If the patient receives a 15% discount for a visit to the healthcare provider and the total charge for the service is $532.00, the patient will pay 100% - 15% = 85% of the total charge.

To calculate the amount the patient will pay in full today, we need to find 85% of $532.00.

85% of $532.00 can be calculated as:

(85/100) * $532.00 = $452.20

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Answer:

Simple interest:

Compound interest:

Sum of the balances:

Answer:

n is greater than - 6.

Step-by-step explanation:

4+n>-2

subtract 4 on both sides

4-4+n>-2-4

n>-6

n is greater than - 6

The statement that best proves that <XWY ≅ <ZYW is that two parallel lines are cut by a transversal, then the alternate interior angles are congruent

To determine the correct statement, we need to know the properties of a parallelogram.

These properties includes;

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(√(2)t^4 - 6√(2)/t) i - √(2)t^3j + (√(2)t^2 - √(2)/t)k is the cross product (a × b).

We have,  a = t, 6, 1/t and b = t², t², 1,

The cross product a × b. In vector algebra, the cross product of two vectors is another vector that is perpendicular to both of them.

A vector product is also known as the vector product of two vectors or the exterior product of two vectors.

The cross product of two vectors a and b is given by:

a × b = |a| |b| sin(θ) n

where |a| and |b| are the magnitudes of vectors a and b, θ is the angle between them, and n is a unit vector perpendicular to both a and b.

To find the cross product of a and b, we first need to calculate the magnitudes of a and b:

|a| = √(t^2 + 6^2 + (1/t)^2) = √(t^4 + 36 + 1/t^2)

|b| = √(t^4 + t^4 + 1) = √(2t^4 + 1)

Next, we need to find the angle between a and b. We can use the dot product to do this:

a · b = |a| |b| cos(θ)

a · b = t(t^2) + 6(t^2) + (1/t)(1) = t^3 + 6t^2 + 1/t

|a| |b| = √(t^4 + 36 + 1/t^2) √(2t^4 + 1)

cos(θ) = (t^3 + 6t^2 + 1/t) / (√(t^4 + 36 + 1/t^2) √(2t^4 + 1))

θ = arccos((t^3 + 6t^2 + 1/t) / (√(t^4 + 36 + 1/t^2) √(2t^4 + 1)))

Now, the cross-product using the formula:

a × b = |a| |b| sin(θ) n

where n is a unit vector perpendicular to both a and b. We can find n by taking the determinant of the matrix:

i j k

t 6 1/t

t^2 t^2 1

n = (t^2 - 6/t)i - (t^3 - t/j)j + (t^2 - t/k)k

a × b = |a| |b| sin(θ) n

a × b = √(t^4 + 36 + 1/t^2) √(2t^4 + 1) sin(θ) ((t^2 - 6/t)i - (t^3 - t/j)j + (t^2 - t/k)k)

Therefore, the cross-product of a and b is:

a × b = (√(2)t^4 - 6√(2)/t) i - √(2)t^3j + (√(2)t^2 - √(2)/t)k

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True. The variables x, y, and z have each been assigned an integer value.

Here is a fragment of code that assigns the least of three integer variables to another variable named min:

min = x  # initialize min to the value of x

if y < min:  # check if y is less than min

   \(min = y\) # \(update min to the value of y if y is less than min\)

if z < min:  # check if z is less than min

   \(min = z\) # \(update min to the value of z if z is less than min\)

In this code, the variable 'min' is first initialized to the value of 'x'. Then, the code checks if 'y' is less than 'min', and if so, updates the value of 'min' to 'y'. Finally, the code checks if 'z' is less than 'min', and if so, updates the value of 'min' to 'z'. At the end of this code fragment, the variable 'min' will contain the least of the three variables 'x', 'y', and 'z'.

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Answer:

D) systematic

Step-by-step explanation:

Systematic sampling. With systematic random sampling, one creates a list of every member of the population, and from the list, one can randomly select the first sample element from the first Nth elements on the population list. Thereafter, we select every Nth element on the list. Selection is done according to a random starting point but with a fixed, periodic interval. This interval, which is called the sampling interval, is calculated by dividing the population size by the desired sample size.

Answer:

b = 8 ft

Step-by-step explanation:

Formula we use,

→ (AC)² = (BC)² + (AB)²

Now the value of a will be,

→ (10)² = b² + (6)²

→ 100 = b² + 36

→ b² = 100 - 36

→ b = √64

→ [ b = 8 ft ]

Hence, value of b is 8 ft.

The average value fave of the function f(x) = x on the interval [0, 16] is 8. This means that if we were to draw the graph of f(x) on this interval, the line y = 8 would be the horizontal line .

To find the average value fave of the function f on the given interval [0, 16], we need to use the formula:

fave = (1/(b-a)) * ∫(a to b) f(x) dx

Here, a = 0 and b = 16, and f(x) = x. So, we have:

fave = (1/(16-0)) * ∫(0 to 16) x dx

= (1/16) * [x^2/2] (from 0 to 16)

= (1/16) * [(16^2)/2 - (0^2)/2]

= (1/16) * [128]

= 8

Therefore, the average value fave of the function f(x) = x on the interval [0, 16] is 8. This means that if we were to draw the graph of f(x) on this interval, the line y = 8 would be the horizontal line that divides the area above the graph from the area below the graph into two equal parts.

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Solution :-

We know that-

\( \small \underline{ \boxed{ \sf{ \frak{Area_{(rectangle )} = \frak{( Length \times Breadth )\:sq.units}}}}}\)

On substituting the values-

\( \longmapsto \sf Area_{(rectangle )} =3^{x-y}\times 3^{y-x} \\\)

\( \longmapsto \sf Area_{(rectangle )} = 3^{x-y+y-x}\\\)

\( \longmapsto \sf Area_{(rectangle )} =3^{\cancel{ x}-\cancel{y}+\cancel{y}-\cancel{x}}\\\)

\( \longmapsto \sf Area_{(rectangle )} = 3^0\\\)

\( \longmapsto \sf Area_{(rectangle )} = 1\\\)

\( \longmapsto \boxed{ \tt{ \pmb{ \red{Area_{(rectangle )} = 1 \: sq.units}}}}\)

\( \\ \therefore \underline{ \cal{ \pmb{The \:area \: of \:the \: rectangle \: is \: \frak{\purple{1\: sq.units }. }}}}\)

The vertex of the graph of f(x) = |x - 5| - 6 is (5, -6). It lies in the fourth quadrant.

Therefore the answer is (5, -6).

The graph f(x) = |x - 5| - 6 is symmetrical about the axis  x = 5.

A vertex of a graph is a node of a graph. For a graph of the form f(x) = a|x - h| + k, the vertex is (h, k). So in this case where f(x) = |x - 5| - 6, a = 1, h = 5 and k = -6. Therefore the vertex of the given graph f(x) is

(5, -6)

--The question is incomplete, answering to the question --

"What is the vertex of the graph of f(x) = |x - 5| - 6?"

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Answer:

4

Step-by-step explanation: