What is the vertical motion of an object?

The speed an object needs to move away from the gravitational pull of the earth is called escape velocity.

Escape velocity is defined as the minimum speed an object must reach to escape the gravitational pull of a celestial body. For example, the escape velocity from Earth is about 11.2 km/s (or 40,320 km/h or 25,022 mph).

This means that an object needs to reach a speed of at least 11.2 km/s to break free from the Earth's gravitational field and continue traveling into space. If an object does not reach escape velocity, it will either enter into orbit around the celestial body or will be pulled back down to the surface.

The concept of escape velocity is important in space exploration and is used to determine the trajectories of spacecraft and rockets.

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Answer:

x component = 79.86

Y component = 60.18

Explanation:

x component  = 100cos37 = 79.86

y component = 100sin37 = 60.18

The swimmer can swim at a speed of 1.05 m/s in still water. Let v be the swimmer's speed in still water and u be the speed of the river's current. Since the swimmer is heading directly across the river, the distance traveled upstream (against the current) is the same as the distance traveled downstream (with the current).

Using the formula distance = speed x time, we can write two equations:

200 = (v - u) x (6 min 40 s)

200 = (v + u) x (t), where t is the time it takes to swim across the river without any current

We need to convert 6 min 40 s to minutes:

6 min 40 s = 6 + 40/60 = 6.67 min

Substituting this value into the first equation and solving for u, we get:

200/(6.67) = v - u

30 = v - u

Substituting this value of u into the second equation and solving for v, we get:

200/(t) = v + 30

v = 200/(t) - 30

Since we want to find the swimmer's speed in still water, we need to find t. We know that the total time for the swim (including the current) is 6 min 40 s, or 6.67 min. We also know that the distance traveled in the direction perpendicular to the river (the "crossing" distance) is equal to the hypotenuse of a right triangle with legs of 200 m and 480 m. Using the Pythagorean theorem, we can find the crossing distance:

crossing distance^2 = 200^2 + 480^2

crossing distance = sqrt(200^2 + 480^2) = 520.2 m

The time it takes to cross the river can be found using the formula distance = speed x time:

520.2 = v x (t - 6.67)

t - 6.67 = 520.2/v

Substituting this value of t into the expression for v that we derived earlier, we get:

v = 200/[(520.2/v) + 6.67] - 30

Solving this equation for v gives us:

v = 1.05 m/s

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(a) This is because the lowest three standing wave vibration frequencies for a closed-open pipe correspond to odd harmonics (1st, 3rd, and 5th).

As for the length of the pipe, we can use the formula L = (n/4) * wavelength, where n is the harmonic number and wavelength is the distance between two adjacent nodes. For the first harmonic (n=1) with a frequency of 120 Hz, the wavelength is four times the length of the pipe. Thus, L = (1/4) * wavelength = (1/4) * (4L) = L. Solving for L, we get L = wavelength/4 = (speed of sound)/(4 * frequency) = 0.71 meters (assuming the speed of sound in air is 343 m/s).

(b), the frequencies of the first two harmonic vibrations on a pipe of the same length but of the other type (open-closed) can be found using the formula f = (n * v)/(2L), where v is the speed of sound in air and n is the harmonic number. For the first harmonic (n=1), we have f = v/(2L) = (343 m/s)/(2 * 0.71 m) = 242 Hz. For the second harmonic (n=2), we have f = 2v/(2L) = (2 * 343 m/s)/(2 * 0.71 m) = 485 Hz.

Therefore, the frequencies of the first two harmonic vibrations on an open-closed pipe of the same length are 242 Hz and 485 Hz, respectively.

Hence, The formula for the frequency of a standing wave in a pipe depends on the speed of sound, the length of the pipe, and the harmonic number.

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Answer:

9.8 meters per second squared

Explanation:

Answer:

9.8 meters per second squared

Explanation:

edge

Answer:

An example of changes in people based on their age, are mood changes,playfulness and as of objects you can say old or broken, animals can use the same reference as humans, the more mature you are can suggest your older, such as the more worn down your are based on a object

Answer:

no one ever amswers my questions

Answer:

40 m/s

Explanation:

F = ma (force = mass * acceleration)

a = F/m

a = 200 N / 50 kg

a = 40 m/s

The refractive index of the eye cannot be determined with the information provided.

This refers to the value obtained from the ratio of the speed of light in a vacuum to that in a second medium of greater density.

The refractive index is also equivalent to the velocity of light c of a given wavelength in empty space divided by its velocity v in a substance.

It can be calculated using the formula:

n = c/v.

where,

n = the refractive index of the eye

c = wavelength in empty space

v = the  velocity of light

From the question:

r = 0.78 cm

i = 3 cm

The radius of curvature and the location of the image formed by an object at infinity is related to the eye's optics, but the refractive index also depends on the materials of the various parts of the eye, such as the cornea and lens.

Hence, the refractive index can also vary depending on the specific wavelength of light being considered.

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The speed of the wave pulse in the second rope does not change compared to the first rope.

The wave speed in the second rope made of the same material but twice as thick and held at the same tension as the first rope will be the same as that of the first rope.

This is because the wave speed in a rope depends on the tension and the linear mass density of the rope. The linear mass density is directly proportional to the thickness of the rope. Since the second rope is twice as thick as the first, its linear mass density will also be twice that of the first rope.

However, since both ropes are made of the same material and held at the same tension, the wave speed will be the same for both ropes. Therefore, the speed of the wave pulse in the second rope does not change compared to the first rope.

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Answer: See Explanation

Explanation:

Did the car travel at a constant speed?

This means "Is the speed at each interval the same?"

There are 10 intervals for which to calculate from.

For each one, the speed is the distance traveled divided by the time.

Each interval is 1 meter long (distance).

1st: 1 meter / 2.00 s = 0.5 m/s

2nd: 1 meter / (4.00 - 2.00) s = 0.5 m/s

3rd: 1 meter / (6.2 - 4.0) s = 0.454 m/s

Right here you can see that the speed is different, NO is the answer.

Average Speed = total distance divided by total time

v = d / t     v = (10 m) / (20:00 s) = 0.5 (m/s)

Describe the overall motion: (continue on with step one to see the total motion over the 10 meters)

4th: 0.552

5th: 0.472

6th: 0.5

7th: 0.5

8th: 0.4975

9th: 5.39

10th: 0.55

Overall motion stayed steady from 0-2 meters, slowed for the 3rd meter, sped up for the 4th, slowed down the 5th, stayed steady until slowing down in the 8th meter, then increased speed til the 10th meter.

Races would be practical applications to see where people/cars pace themselves, push themselves, etc.

Answer:

La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.

Explanation:

Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río.  Este movimiento posee una composición en dos dimensiones: uno horizontal sin aceleración, y el otro vertical con aceleración constante debido a la gravedad.  Por lo que se trata de un movimiento rectilíneo uniforme (MRU) en su trayectoria horizontal o eje horizontal (es decir, su velocidad es constante) y un movimiento uniformemente variado (MRUV) en su trayectoria vertical o en el eje vertical (es decir, su aceleración es constante).

En este caso, son conocidos los datos, considerando el sistema de referencia de la imagen:

En el caso del MRUV, la posición puede calcularse mediante la expresión:

Posición final= Posición inicial + Velocidad inicial*t + \(\frac{1}{2}\)*a*t²

donde a es la aceleración y t el tiempo transcurrido.

En este caso, reemplazando los datos conocidos, teniendo en cuenta que el MRUV sucede en la trayectoria vertical y que la aceleración es el valor de la gravedad:

0 m= 340 m + 0 m/s*t + \(\frac{1}{2}\)* (-9.8 m/s²)* t²

Resolviendo:

-340 m= \(\frac{1}{2}\)* (-9.8 m/s²)* t²

\(\frac{-340 m}{\frac{1}{2} *(9.8\frac{m}{s^{2} } )} =t^{2}\)

69.39 s²= t²

t= √69.39 s²

t= 8.33 s

La posición en MRU se obtiene mediante:

Posición final= Posición inicial + velocidad* tiempo

Con los datos conocidos y el tiempo calculado previamente, es posible calcular la distancia horizontal que recorrerá la caja con medicina antes de caer al río, siendo la posición inicial en x igual a cero:

Posición final= 0 m + 70m/s* 8.33 s

Posición final= 583.1 m

La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.

Veremos que la distancia horizontal que recorre la caja es 583.1 metros.

Recordar que la velocidad vertical y horizontal son independientes.

Aqui, lo primero que debemos hacer es encontrar el tiempo que la caja tarda en llegar al suelo.

Para ello usamos la ecuación de movimiento vertical:

p(t) = (-4.9 m/s^2)*t^2 + v*t + h

Donde el primer termino representa la gravedad, el segundo la velocidad inicial (que es cero en este caso) y el tercero la altura inicial, que es 340m.

p(t) = (-4.9 m/s^2)*t^2 + 340m

La caja llegara al suelo cuando la función de arriba sea igual a cero:

(-4.9 m/s^2)*t^2 + 340m = 0

t = √(340m/(4.9 m/s^2)) = 8.33 s

Es decir, la caja tarda 8.33 segundos en llegar al suelo.

Esto significa que la caja se va a mover horizontalmente durante 8.33 segundos con una velocidad de 70m/s (la que tenía el avion). Es decir, la distancia horizontal que se mueve la caja es :

D = 8.33s*(70m/s) = 583.1 m

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A.

In order to calculate the kinetic energy of the box, we can use the formula below:

Where m is the mass and v is the velocity.

Using m = 12 kg and v = 3 m/s, we have:

B.

The work done by Jim can be calculated with the formula below:

Where F is the force and d is the distance.

The force applied is equal to the weight force of the box, so:

The equation for energy in the context of fluid dynamics, specifically in Computational Fluid Dynamics (CFD), is typically represented by the conservation of energy equation, also known as the energy equation or the first law of thermodynamics. The equation can be expressed as:

ρ * (du/dt + u * ∇u) = -∇p + ∇⋅(μ * (∇u + (∇u)^T)) + ρ * g + Q

where:

ρ is the density of the fluid

u is the velocity vector

t is time

∇u represents the gradient of velocity

p is the pressure

μ is the dynamic viscosity

g is the gravitational acceleration vector

Q represents any external heat source/sink

The physical meaning of energy in CFD is the total energy of the fluid system, which includes kinetic energy (associated with the motion of the fluid), potential energy (associated with the elevation of the fluid due to gravity), and internal energy (associated with the fluid's temperature and pressure). The energy equation describes how this total energy is conserved and transformed within the fluid system.

In CFD simulations, the energy equation plays a crucial role in modeling the energy transfer, heat transfer, and flow characteristics within the fluid. It helps in understanding how energy is distributed, dissipated, and exchanged within the fluid domain. By solving the energy equation numerically, CFD simulations can predict temperature profiles, flow patterns, heat transfer rates, and other important parameters that are essential for various engineering applications, such as designing efficient cooling systems, optimizing combustion processes, and analyzing thermal behavior in fluid flows.

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To find the sign and magnitude of the charge Q, we can use the equation for the electrostatic force between two point charges by Coulomb's law which come out to be 33.51 x \(10^-^3\)C.

The electrostatic force between two point charges can be calculated using Coulomb's law: F = \(k * (|Q1| * |Q2|) / r^2\), where F is the force, k is the electrostatic constant\((8.99 x 10^9 N m^2/C^2)\), |Q1| and |Q2| are the magnitudes of the charges, and r is the separation between the charges.

In this case, we are given the magnitude of the force (0.755 N) and the separation between the charges (1.71 m). We can substitute these values into the equation and solve for |Q1| * |Q2|.

0.755 N =\((8.99 x 10^9 N m^2/C^2) * (|Q1| * |Q2|) / (1.71 m)^2\)

Simplifying the equation, we find:

|Q1| * |Q2| =\((0.755 N * (1.71 m)^2) / (8.99 x 10^9 N m^2/C^2)\)

|Q1| * |Q2| = \(2.02 x 10^-^8 C^2\)

Since we are given that one of the charges is \(5.76 x 10^-6\)C, we can solve for the magnitude of the other charge, |Q|.

\((5.76 x 10^-^6 C) * |Q| = 2.02 x 10^-^8 C^2\)

|Q| =\(2.02 x 10^-^8 C^2\)

Calculating this expression, we find:

|Q| = \(3.51 x 10^-^3 C\)

Therefore, the magnitude of the charge Q is \(3.51 x 10^-^3\) C. To determine the sign of the charge, we need additional information or context as the sign of the charge cannot be determined solely from the given information.

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The linear homogeneous recurrence relation with constant coefficients that the sequence is: An = -(-1)n + (3)n or An = (1)n + (3)n

The sequence An = (n-3)(2n) + n(2n) satisfies the linear homogeneous recurrence relation with constant coefficients. In order to prove this, we need to first find the general formula of the sequence.

The formula can be found by replacing n with n+1 as follows:

An+1 = (n+1-3)(2n+2) + (n+1)(2n+2)

An+1 = n(2n+4) + (n+1)(2n+2)

An+1 = 2n² + 4n + 2n² + 4n + n + 2n + 2

An+1 = 4n² + 7n + 2

The characteristic equation of the linear homogeneous recurrence relation is given by:

r² - 2r - 3 = 0

Solving this quadratic equation, we get:r = -1 or r = 3

Hence, the general formula of the sequence is given by:An = A(-1)n + B(3)n

Now, we need to find the values of A and B using the initial values of the sequence. The first two terms of the sequence are given by:

A0 = -6 and A1 = 2

Substituting these values in the general formula, we get:

-6 = A + B2 = -A + 3B

From the above two equations, we can solve for A and B to get:

A = -1 and B = 1

Hence, the linear homogeneous recurrence relation with constant coefficients that the sequence An = (n-3)(2n) + n(2n) satisfies is given by:

An = -(-1)n + (3)n or An = (1)n + (3)n

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The speed of blood through the aorta is 0.265 m/s.

The speed of blood flow through aorta is termed as volumetric flow rate. The formula is -

Q = Av, where Q is volumetric flow rate, A is area and v represents speed.

Area = πr²

As we know, 1 m = 100 cm

So, 1 cm = 0.01 m

Area = π(0.01)²

Area = 3.1× \( {10}^{ - 4} \) m²

Q = 5 l/min

Converting to m³/sec

Q = 5/1000×1/60

Q = 8.3 × \( {10}^{ - 3} \) m³/s

Now calculating v or speed of blood

v = Q/A

v = 8.3 × \( {10}^{ - 3} \) ÷ 3.1× \( {10}^{ - 4} \)

v = 0.265 m/s

Thus, the blood flows at 0.265 m/s through aorta.

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This question involves the concepts of centripetal force and centripetal acceleration.

a) The centripetal acceleration for the piece of gum stuck to the outside edge of the record will be "6.67 m/s²".

b) The gum will have to overcome "0.033 N" centripetal force to remain stuck to the vinyl.

a)

The centripetal acceleration of the gum can be found using the following formula:

\(a_c=\frac{v^2}{r}\)

where,

\(a_c\) = centripetal acceleration = ?

v = linear speed of record = 1 m/s

r = radius of the record = \(\frac{diameter}{2}=\frac{0.3\ m}{2}=0.15\ m\)

Therefore,

\(a_c=\frac{(1\ m/s)^2}{0.15\ m}\\\\a_c = 6.67\ m/s^2\)

b)

Now, the centripetal force can be given as follows:

\(F_c=ma_c\\F_c=(0.005\ kg)(6.67\ m/s^2)\\F_c=0.033\ N\)

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The attached picture shows the centripetal force.

Answer: It's mostly found near Jamestown , New York

A ball is dropped from the leaning tower of Piazza. The ball will drop 13.2 meters within 1.68 seconds (the distance it falls is directly proportional to the square of the time it takes).

The formula for the distance covered by an object during free fall is: d=½gt² Where: g is the acceleration due to gravity (9.8 m/s²), and t is the time taken by the object to reach the ground.

Distance covered by the ball during free fall after 1.68 s is as follows: d= ½ × 9.8 m/s² × (1.68 s)²= 13.2 meters

Therefore, the ball will drop 13.2 meters within 1.68 seconds (the distance it falls is directly proportional to the square of the time it takes).

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Answer:

the answer is b

Explanation:

Three factors that have an effect on the centripetal force are the mass of the object; its speed; the radius of the circle. Therefore speed increases the magnitude of the centripetal force acting on an object traveling in a horizontal, circular path

Centripetal force is the pressure on an item on a circular path that keeps the item shifting on the route. it's far usually directed in the direction of the middle and its value is constant, based totally on the mass of the item, its tangential speed, and the space of the object (radius) from the middle of the circular direction.

The centripetal force is proportional to the square of the rate, implying that a doubling of pace would require four times the centripetal pressure to keep the motion in a circle. because centripetal acceleration is tangential speed squared divided by way of the radius, and the tangential pace is increasing from relaxation, the centripetal acceleration should then be growing as properly.

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Answer:

The most reactive element is fluorine, the first element in the halogen group. The most reactive metal is francium, the last alkali metal (and most expensive element)

Explanation:

The force of earth’s gravity on the payload is w2 when the rocket’s distance from the center of earth is r = ✓2R

From the information, the rocket lifts a payload upward from the surface of earth. The radius of earth is r, and the weight of the payload on the surface of earth is w.

The equation to illustrate the information will be:

W = GmM / r² = w / 2

w / 2 = GmM / r²

Matching the equation together

GmM / R² = 2 GmM / r²

1 / R² = 2 / r².

r = ✓2R

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As a result, the magnetic field changes throughout time. The coil's resistance is 640 ohms.

An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A moving charge in a magnetic field is subject to a force that is perpendicular to the magnetic field and has its own speed. The magnetic field is the area that is affected by magnetism and is located around a magnet. When describing the distribution of the magnetic force within and around a magnetic object in nature, the magnetic field is a useful tool.

Similar poles repel one another, whereas diametrically opposed poles are attracted together. When an iron object is brushed against a magnet, its atoms' north-seeking poles align in the same direction. The force that the aligned atoms generate creates a magnetic field. The iron object has transformed into a magnet.

Given that,

Coil's radius, r = 4.2 cm

N is the coil's turn count, which is 500.

The following equation provides the magnetic field:

The coil's resistance is 640 ohms.

The size of the coil's induced emf as a function of time must be determined. It's origin is:

Due to that,

Coil's radius, r = 4.2 cm

N is the coil's turn count, which is 500.

The magnetic field is described by the formula:

B=1.2×〖10〗^(-2) t+2.6×〖10〗^(-5) t^4

The coil's resistance is 640 ohms.

The size of the induced emf in the coil as a function of time must be determined. It is provided by:

€=(-dΦ)/dt

€=(-d(NBA))/dt

€=Nπr^2 (-dB)/dt

€=Nπr^2×(-d(1.2×〖10〗^(-2) t+〖2.6×10〗^(-5) t^4)/dt

€=Nπr^2×(1.2×〖10〗^(-2) t+10.4×〖10〗^(-5) t^3

€=500π×(4.2×〖10〗^(-2) )^2×(1.2×〖10〗^(-2)+10.4×〖10〗^(-5) t^3)

€=2.77(1.2×〖10〗^(-2)+10.4×〖10〗^(-5) t^3 )V

This is the necessary solution as a result.

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The correct the question

A coil 4.20 cm radius, containing 500 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10−2 T/s )t+( 2.60×10−5 T/s4 )t4. The coil is connected to a 640-Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.

a)Find the magnitude of the induced emf in the coil as a function of time.

a)Velocity vector of child can be expressed as v = v_parallel + v_perpendicular. b) Velocity vector of child is v = v_parallel + v_perpendicular. c)Net force acting on the child is approximately -20.7 kg m/s in the direction opposite to direction of  velocity vector.

An influence that causes motion of an object with mass to change its velocity is called force.

(a) The child is moving in a circle with radius 5.7 m, so the circumference of the circle is 2π(5.7) ≈ 35.8 m. The child completes one revolution every 10.3 seconds, so their speed is 35.8/10.3 ≈ 3.48 m/s. The velocity vector of child can be expressed as v = v_parallel + v_perpendicular.

dp/dt = m(dv_parallel/dt), m is the mass of child. As magnitude of the velocity is constant, dv/dt = 0, so dv_parallel/dt = -v_perpendicular/r, where r is radius of the circle. Therefore, dp/dt = -mv_perpendicular/r = -(34 kg)(3.48 m/s)/5.7 m ≈ -20.7 kg m/s. Direction of dp/dt is opposite to direction of v_perpendicular, which is perpendicular to radius vector.

(b)The child is moving in a circle, so their acceleration is given by a = v²/r, where v is the speed of the child and r is the radius of the circle. Therefore, a = (3.48 m/s)^2/5.7 m ≈ 2.14 m/s².

a_perpendicular = dv_perpendicular/dt,  v_perpendicular is constant velocity vector perpendicular to radius vector. As a_perpendicular = 0. Therefore,  perpendicular component of dp/dt is zero.

(c) The net force acting on the child is given by F = dp/dt. From part (a), we know that parallel component of dp/dt is approximately -20.7 kg m/s. From part (b), we know that the perpendicular component of dp/dt is zero. Therefore, the net force acting on the child is approximately -20.7 kg m/s in the direction opposite to the direction of the velocity vector.

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If two objects a and b have the same kinetic energy but a has the momentum of the ratio of their inertias will be 1 / (2(mb/ma))

The kinetic energy of an object is given by

K = \((1/2)mv^2\)

where m is the mass and v is the velocity. The momentum of an object is given by

p = mv.

Given that object a has twice the momentum of object b but they have the same kinetic energy, we can set up the following equation:

(1/2)ma va^2 = (1/2)mb \(vb^2\) (since both have the same kinetic energy)

ma va = 2mb vb (since object a has twice the momentum of object b)

We can solve for va/vb to find the ratio of their velocities:

va/vb = 2(mb/ma)

We can use the definition of inertia as the ratio of the mass to solve for the ratio of their inertias:

inertia of a / inertia of b = ma / mb

From the equation above, we can substitute ma/mb with 1/(2(mb/ma)) to get:

inertia of a / inertia of b = 1 / (2(mb/ma))

Therefore, the ratio of their inertias is 1 / (2(mb/ma)), or equivalently, ma / (2mb).

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Answer:

hello and thank you

Explanation:

The existence of coal beds in Antarctica is evidence that the region once experienced significant warming and was home to vast amounts of plant life.

One of the earliest hypotheses put up by geologists for how continents might migrate through time is called continental drift. The science of plate tectonics has now supplanted the theory of continental drift.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century. He referred to it as continental drift.

What is known about Antarctica's changing climate is that it didn't begin to cool until roughly 34 million years ago, when the continent was severed from the others which supports Continental Drift theory.

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The magnitude of the electric field at point P which is 0.20 m to the right of the positive charge is 3,3375 N/C.

The electric field(E) due to an isolated point charge is

E= KQ/r^2

Here K is the Electrostatic Constant = 1/4π∈ = 9 x 10^9 N m^2/C^2

Q is the magnitude of the charge

r is the distance of the point from the charge

Putting q= 15 nC and r = 0.20 m in the given equation

E = 9 x 10^9 x 15 x 10^-9/(0.20)^2

E = 3375 N/C

Hence, the magnitude of the electric field at point p which is 0.20 m to the right of the positive charge is 3,3375 N/C.

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The answers are:

Kinetic energy is a form of energy associated with the motion of an object. It is the energy an object possesses due to its velocity or speed. The kinetic energy of an object depends on both its mass and its velocity. The equation to calculate kinetic energy is:

Kinetic Energy = (1/2) * mass * velocity^2

In simpler terms, kinetic energy represents the energy that an object possesses by virtue of its motion.

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