What is the vapor pressure (in kPa) of CH3OH, methanol, over a solution which is composed of 7.50 mL of methanol and 3.23 g of C6H5COOH, benzoic acid, at 25ºC ?Pº methanol at 25ºC = 16.915 kPaDensity of methanol is 0.792 g/mLMolar mass of benzoic acid is 122.12 g/mol

The electron could be excited to a higher energy level and then returned to ground state as shown in the image attached.

According to the Bohr model of the atom, electrons are arranged in energy levels. The electrons that are in the lower energy levels then to absorb energy and move up to the excited states which are higher energy levels which is the crux of the model here.

Subsequently, the electron that was excited would drop down to the ground state and then loose the energy that was absorbed during excitation in the form of a visible light.

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Answer:

4Fe(s) + 3O₂(g) = 2Fe₂O₃(s)

Answer:

Sonoluminescence can occur when a sound wave of sufficient intensity induces a gaseous cavity within a liquid to collapse quickly. [...] The bubbles are very small when they emit the light—about 1 micrometer in diameter—depending on the ambient fluid (e.g., water) and the gas content of the bubble (e.g., atmospheric air).

Explanation:

Source is Google

Answer:

It has two sigma bonds ( the single bonds between each H and C) plus one pi bond and one sigma bond that consitute the double bond between C and O. It contains three covalent bonds, one . Hydrogen Bond Donor Count: 0: Computed by Cactvs 3.4.

Explanation:

Hope it helps you!

Answer:

A) IV: number of hours DV: score

Explanation:

Coz,

IV- is the variable that u change

DV- is the variable that u test or measure

In this case, we need to change the hours of studying to see how studying for different hours [1 hr, 2hr, etc (( Independant variable coz we're changing the no. of hours)) ] is going to affect the student's score, and in the end, we are measuring the score of each student [this is the dependant variable].

Answer:

Explanation:

Percentage by mass of Nitrogen: 47%

Molar mass of Nitrogen: 14

Portion of moles of Nitrogen: 47/14 = 3.36

Percentage by mass of Oxygen: 53%

Molar mass of Oxygen: 16

Portion of moles of Oxygen: 53/16 = 3.31

3.36 : 3.31 is approximately 1 : 1 so the empirical formula is:

A. NO

Answer:

u said 100 points not 50 u should hold up ur end of the deal

Explanation:

According to the stoichiometry of the chemical reaction,0.713 moles of water can be made when 134.9 grams of HNO₃ are consumed.

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

378.24 g nitric acid gives 36 g water, thus 134.9 g nitric acid gives 134.9×36/378.24=12.83 g which is 12.83/18= 0.713 moles.

Thus,0.713 moles of water can be made when 134.9 grams of HNO₃ are consumed.

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Answer:

D

Explanation:

NO is the molecule nitrogen monoxide while No is the atomic symbol for the element nobelium

Answer:

i dont know

Explanation:

Answer:

Silicon conducts electricity as well as copper does.

Explanation:

you didn't gave any statements to choose the answer from.

but otherwise, what all I my knowledge says that Silicon conducts electricity as well as copper does.

Answer:

The electronic configuration of ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Explanation:

Lithium metal, Li will lose 1 electron to lithium ion Li+. Chlorine atom, Cl will receive the 1 electron to form the chloride ion Cl- as shown by the following equation below:

Li —> Li+ + e

Cl+ e —> Cl-

Combine both equation

Li + Cl + e —> Li+ + Cl- + e

Cancel out 'e'

Li + Cl —> Li+ Cl-

Thus, we can write the electronic configuration for the reaction as follow:

Before reaction:

Li (3) => 1s2 2s1

Cl (17) => 1s2 2s2 2p6 3s2 3p5

After reaction

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Therefore, the electronic configuration of the ions formed are:

Li+ (2) => 1s2

Cl- (18) => 1s2 2s2 2p6 3s2 3p6

Answer:

oxygen consists of 3 isotopes and carbon consists of 2 isotopes

Explanation:

oxygen: O16, O17 and O18

Carbon: C12 and C13

B. 2Na:Cl2

2 moles of sodium react with 1 mole of chlorine to generate 2 moles of sodium chloride.

5 moles of sodium will react with 2/51 =2.5 moles of chlorine to form 5.0 moles of NaCl.

Because 3.0 moles of chlorine are present, chlorine is an excess reagent.

As a result, the Cl is the oxidising agent since it pushed the 2I to lose one electron while also gaining two electrons. 2I is the reducing agent.

Sodium is in the 0 oxidation state on the LHS and changes to +1 in the product, therefore it is oxidised. Hydrogen was +1 on the reactant side and goes to 0 oxidation state on the RHS, hence it is reduced.

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The following which has metallic bonding is Au and is therefore denoted as option D.

This is referred to as a type of chemical bonding that arises from the electrostatic attractive force between conduction electrons and positively charged metal ions.

Gold is an element which engages in metallic bonding so long as it is bonding to other atoms of metallic elements of itself thereby making it the correct choice.

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The resulting empirical formula is Na2CrO4.

The empirical formula of a compound is the simplest whole-number ratio of the elements it contains. To calculate the empirical formula, we must first determine the molar ratio of the elements by dividing their masses by their respective molar masses.

For sodium, the molar mass is 22.99 g/mol. Therefore, the molar ratio of sodium is 29.84 g / 22.99 g/mol = 1.30 mol.
For chromium, the molar mass is 51.99 g/mol. Therefore, the molar ratio of chromium is 39.7 g / 51.99 g/mol = 0.76 mol.
For oxygen, the molar mass is 16.00 g/mol. Therefore, the molar ratio of oxygen is 72.67 g / 16.00 g/mol = 4.54 mol.
To get the empirical formula, we must divide each of the molar ratios by the smallest molar ratio, which in this case is 0.76 (for chromium). The resulting empirical formula is Na2CrO4.

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Main answer:ln(T2/T1) +ΔS°mix The change in entropy of the reaction (ΔS°) can be calculated by using the formula, ΔS°= ΔS°(products) - ΔS°(reactants).

Given; moles of hydrogen (H2)=72 moles of oxygen (O2)=44 moles of the mixture=n(H2) + n(O2)=72+44=116The initial temperature= 40°C = 313 KThe final temperature= 60°C = 333 KThe initial pressure= 2 barThe process is isobaric process where pressure is constant and therefore work done is zero.

From the ideal gas equation PV = nRT we can rearrange it to V = nRT/PThe volume of the mixture can be calculated as follows;V= nRT/P= (72 + 44) * 8.31 * 313 / (2 * 10^5)= 6.28 LThe final volume, V2 = 6.28LThe change in temperature is ΔT = 333 - 313 = 20 KThe change in entropy of the mixing process (ΔSmix) can be calculated using the formula;ΔSmix= -nR(xlnx + (1-x)ln(1-x))= -116*8.31[(72/116)ln(72/116)+(44/116)ln(44/116)]= 47.01 J/K.

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C. Continuous metabolic production of free hydrogen ions

The processes of creating and breaking down glucose molecules are both examples of metabolic pathways. A metabolic pathway is a chain of related chemical reactions that feed each other. The pathway takes in a single or extra beginning molecule and, through a sequence of intermediates, converts them into merchandise.

Metabolism (stated: meh-TAB-uh-Liz-um) is the chemical reactions within the body's cells that alternate meals into power. Our bodies want this strength to do the entirety from moving to wondering to growing. particular proteins in the body manipulate the chemical reactions of metabolism.

A metabolic product is a compound produced via the cells and is excreted to the extracellular medium. it can be produced in the number one metabolism, e.g. carbon dioxide, ethanol, acetate, or lactate, or an extra complicated one, e.g. a secondary metabolite or a heterologous protein secreted to the extracellular medium.

The question is incomplete. Please read below to find the missing content.

Which normal physiologic process contributes most to the need for acid-base balance

A. Continuous organ production of bicarbonate from carbonic acid

B. Continuous alveolar exchange of oxygen and carbon dioxide

C. Continuous metabolic production of free hydrogen ions

D. Continuous kidney formation of urine from blood

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You would need 740.1 grams of oxygen to completely react with 254 grams of tristearin, C₅₇H₁₁₀O₆, in the given reaction.

To find out how many grams of oxygen are needed to completely react with 254 g of tristearin, C₅₇H₁₁₀O₆, in the given reaction, follow these steps:

1. Calculate the molar mass of tristearin (C₅₇H₁₁₀O₆) and oxygen (O₂).
2. Convert grams of tristearin to moles using its molar mass.
3. Use stoichiometry to find the moles of oxygen needed.
4. Convert moles of oxygen to grams using its molar mass.

Molar mass of tristearin: (57 * 12.01) + (110 * 1.01) + (6 * 16.00) = 891.62 g/mol
Moles of tristearin: 254 g / 891.62 g/mol = 0.285 moles
Moles of oxygen needed: 0.285 moles * (163 O₂ / 2 C₅₇H₁₁₀O₆) = 23.16 moles
Molar mass of O₂: 2 * 16.00 = 32.00 g/mol
Grams of oxygen needed: 23.16 moles * 32.00 g/mol = 740.1 g

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The answer cannot be determined without knowing the pKa value of HCO2H.

To determine the pH when NaOH is added to a buffer containing HCO2H and NaCO2H, we need to consider the reaction between the base (NaOH) and the weak acid (HCO2H) in the buffer solution.

\(HCO2H + NaOH → HCO2Na + H2O\)

First, we need to determine the moles of NaOH added:

The total moles of the weak acid in the buffer solution will be the sum of moles of \(HCO2H\) and \(NaCO2H\).

Finally, we can calculate the concentrations of the acid and its conjugate base in the buffer solution, and use the Henderson-Hasselbalch equation to determine the pH:

\(pH = pKa + log([A-]/[HA])\)

where pKa is the acid dissociation constant of \(HCO2H\).

Given the concentration of \(HCO2H\) and \(NaCO2H\), we can calculate the moles of each component in the buffer solution, then determine their concentrations.

However, without the value of \(pKa\)for \(HCO2H\), we cannot accurately calculate the pH in this specific scenario.

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Answer:

His kinetic energy when he runs at that 5 m/s is 750 joules

Explanation:

The given information are;

The mass of, Lance, the runner = 60-kg

The speed by which Lance is running = 5 m/s

The kinetic energy, KE, is given by the relation;

KE = 1/2×m×v²

Where;

m = The mass = 60-kg

v = The instantaneous speed of motion = 5 m/s

The kinetic energy can be found by substituting the values of the variables in the kinetic energy equation as follows;

KE = 1/2 × 60 kg × (5 m/s)² = 750 joules

His kinetic energy when he runs at that 5 m/s is 750 joules.

The kinetic energy when he runs at that 5 m/s is 750 joules.

Given information are:-

The mass of, Lance, the runner = 60-kg

The speed by which Lance is running = 5 m/s

The kinetic energy, KE, is given by the relation;

\(Kinetic\ energy=\frac{1}{2} mv^{2}\)  

Where;

m = The mass = 60-kg

v = The instantaneous speed of motion = 5 m/s

The kinetic energy can be found by substituting the values in the kinetic energy equation as follows;

\(KE = 1/2 \times 60 kg\times (5\ m/s)^{2} \\= 750 joules\)  

His kinetic energy when he runs at that 5 m/s is 750 joules.

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Answer:

Single replacement

Explanation: Al is replacing Cu

Based on the pOH of the solution, the hydroxide ion concentration, [OH-] of the solution is 1.778 × 10^-11 M

The pOH of a solution-

The pOH of a solution is the negative logarithm to base ten of the hydroxide ions concentration of the solution.

pOH = -log[OH-]

The pOH of the solution = 10.75

[OH-] = 10^(-pOH)

Hydroxide ion concentration, [OH-] = 10^-10.75

Hydroxide ion concentration, [OH-] = 1.778 × 10^-11 M

Therefore, the hydroxide ion concentration, [OH-] of the solution is 1.778 × 10^-11 M

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Answer:

I hope this helps :D

Explanation:

Newton's first law expresses that each object  will stay very still or in uniform movement in an orderly fashion except if constrained to change its state by the activity of an outside power. ... The third law expresses that for each activity (power) in nature there is an equivalent and inverse response.

Methanol's combustion enthalpy can be calculated at -540 (kJ mol-1).

Methanol, the most basic form of alcohol (CH3OH), serves as the chemical basis for countless items used in daily life, such as paints, plastics, auto parts, and building supplies. Additionally, methanol is a renewable resource that powers fuel cells, boilers, cook stoves, ships, automobiles, trucks, and buses.

Energy required to dissociate the bonds connecting reactants

3 × 413 + 358 + 464 + 1.5 × 498 (kJ mol-1) / 2808 (kJ mol-1);

Total energy released when products form bonds

4 × 464 + 2 × 746 (kJ mol-1) / 3348 (kJ mol-1);

∆H = -540 (kJ mol-1).

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The complete question is -

Methanol is made in large quantities as it is used in the production of polymers and in fuels.

The enthalpy of combustion of methanol can be determined theoretically or experimentally.

CH₃OH(l) + 1 O₂(g) → CO₂(g) + 2H₂O(g)

Using the information from Table 10 of the Data Booklet, determine the theoretical enthalpy of combustion of methanol.

Halite, gypsum, and graphite are the three names for the three common non-silica minerals. Plaster uses gypsum, common salt uses halite, and pencil lead once used graphite.

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Magnesium have two valence electrons. Because the outer energy level  for the magnesium atom is 3 and it has two electron in this energy level.

The Valence electrons are defined as the electrons that located in the outermost electron shell of an atom. These valence electrons being the furthest from the nucleus and thus the least tightly held by the atom are the electrons that participate in bonds and reactions. The number of valence electrons that an element has determines its reactivity, electronegativity and the number of bonds it can form. We can use the periodic table to help to determine how many valence electrons an element specifically a neutral atom of the element has. Looking at the group that the element is in as the group number indicates the number of valence electrons that the element has.

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Answer:

b. \(\% diss =4.4x10^{-2}\%\)

Explanation:

Hello there!

In this case, given the ionization reaction of HClO as weak acid:

\(HClO\rightleftharpoons H^++ClO^-\)

We can write the equilibrium expression as shown below:

\(Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}\)

In such a way, via the definition of x as the reaction extent, we can write:

\(3.5x10^{-8}=\frac{x^2}{[HClO]}\)

As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

\(x=\sqrt{3.5x10^{-8}*0.18} =\\\\x=7.94x10^{-5}M\)

And finally the percent dissociation:

\(\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%\)

Which is choice b.

Best regards!

Answer: A) 3 / C) all objects / D) reference point / C) velocity

Explanation: I did some research before answering, I hope this helps.

Answer:

5308.16J

Explanation:

Using the formula;

Q = m × cp × ∆T

Where;

Q = change in heat (J)

m = mass of substance (g)

cp = specific heat capacity (4.184 J/g°C)

∆T = change in temperature (°C)

According to the information given in this question;

Q = ?

m = 27.58 grams

cp = 4.184 J/g°C

∆T = 62°C - 16°C = 46°C

Using Q = m × cp × ∆T

Q = 27.58 × 4.184 × 46

Q = 5308.157

Q = 5308.16J