what is the value of x?
please I need step by step solution​

Answer:

b

Step-by-step explanation:

Answer:

12.5 hrs

Step-by-step explanation:

For auto body charges, the equation will be

cost = 125 + 18 h..............eq 1

For car care charges, the equation will be

cost = 200 +12 h.............eq 2

for the cost to be equal,

From eq 1 and eq 2

125 + 18 h = 200 + 12h

18h - 12h = 200-125

6h = 75

h = 75/6 = 12.5 hrs

12.5 hrs both shops need to work for the prices to be equal

Answer:

The question is not clear the picture is cut off

Step-by-step explanation:

Answer:

Identify the terms and coefficients of each expression. 1. ... Frank buys p pounds of oranges for $2.29 per pound and the same number of pounds of apples for $1.69 per pound. ... .690 = total cost ... Write an expression to represent each situation. 9. Eliza earns $400 per week plus $15 for each new customer she signs up.

Step-by-step explanation:

Answer:

\(\displaystyle h'(x) = \cos (x) f'(\sin x)[2 + f(\sin x)]'''\)

General Formulas and Concepts:

Calculus

Differentiation

Derivative Property [Addition/Subtraction]:                                                         \(\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]\)

Derivative Rule [Basic Power Rule]:

Derivative Rule [Chain Rule]:                                                                                 \(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)

Step-by-step explanation:

Step 1: Define

Identify.

\(\displaystyle h(x) = [2 + f(\sin x)]''\)

Step 2: Differentiate

From here, if you would like, you can take the 3rd derivative of the last piece.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

The counterclockwise circulation around c is 12 and the outward flux through c is zero.

Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.

In this case,

we have a field f=(7x−4y)i+(9y−4x)j and

a square curve c bounded by x=0, x=4, y=0, y=4.

To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.

The curl of f is given by (0,0,3), so the line integral evaluates to 12.

To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.

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To answer this question, we must calculate the size of the pipe required to carry oil with a kinematic viscosity of 0.0002 ft^2/s at a rate of 8 ft^3/s, if the frictional head loss is 0.4 ft over 100 ft length of the pipe.

Assuming element of = 0.00015 ft, we can use Moody's chart to solve this problem.

To begin, let's convert the given units to SI units. We can do this by multiplying the viscosity (V) by 0.0929 and the length (L) by 0.3048. This gives us the following values:

V = 0.00018 ft^2/s

L = 30.48 m

Now that we have our converted values, we can use Moody's chart to determine the size of pipe required. We must calculate the Reynold's number (Re) to do this. We can calculate Re using the following equation:

Re = (V*Q)/(L*A)

Where V is the viscosity, Q is the flow rate, L is the length, and A is the area. Plugging in the values we get:

Re = (0.00018*8)/(30.48*A)

Solving for A, we get:

A = 0.0024 m^2

Using Moody's chart, we can determine that the required size of pipe is 0.25 inch (6.35mm).

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Answer:

1.05821886 ounces

Step-by-step explanation:

To convert 30 grams to ounces, use the conversion factor 1 ounce = 28.3495 grams.

Answer:

60%

Step-by-step explanation:

Answer:

  x = -8 and x = 2

Step-by-step explanation:

The given equation resolves into two:

The solution to the first can be found by subtracting 3:

  x = 2

The solution to the second can be found by multiplying by -1, then subtracting 3.

  x +3 = -5

  x = -8

The solution set is {-8, 2}.

Answer:

R and s are parallel as they are the same size and length

i would think 2 and 5 or 2 and 6

hope this helps! (:

Answer:

<CTS=180-(35+31) (sum of <s in a triangle)

=180-66

=114 degrees

x=180-114 (angles on a straight line)

x=66 degrees

<TSR=180-(30+36)

=180-66

=114 degrees

<TSA=180-114

=66 degrees

y=180-(66+66)

y=180-132

y=48 degrees

The awnswer is (1,-3) (if I'm not right try typing it it an app called math away it can solve that no problems)

Consider using 3D printing technology to create the spherical fountain. This would allow for precise and customizable designs, and could potentially be more cost-effective than traditional manufacturing methods for complex shapes.

Use a mathematical formula to design the fountain. Here are the steps to design a spherical fountain:

Determine the desired size of the fountain. This will be the diameter of the sphere. Let's say your client wants a fountain with a diameter of 6 feet.

Calculate the radius of the sphere by dividing the diameter by 2. In this case, the radius is 3 feet.

Use the formula for the surface area of a sphere to determine the surface area of the fountain. The formula is: SA = 4π\(r^2\), where r is the radius of the sphere and π is a mathematical constant (approximately 3.14). In this case, the surface area is:

SA = 4π\((3)^2\)

SA = 4π(9)

SA = 36π

SA ≈ 113.1 square feet

Use the desired water flow rate to determine the volume of water that will flow through the fountain per minute. Let's say your client wants a flow rate of 50 gallons per minute.

Use the formula for the volume of a sphere to determine the volume of the fountain. The formula is: V = (4/3)π\(r^3\). In this case, the volume is:

Calculate the amount of time it will take for the fountain to cycle through all of its water. This is known as the turnover time, and it is important to maintain water quality. The turnover time is calculated by dividing the volume of water in the fountain by the flow rate. In this case, the turnover time is:

Use these calculations to design the fountain, taking into account any necessary adjustments for the manufacturer's limitations.

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Full Question: Your client wants you to design a spherical fountain for a new garden bed. It is hard to find a manufacturer that can create perfect curved surfaces. You will need to modify the sphere to a series of cylindrical slabs with gradually decreasing radii.

To show that there is no € > 0 such that the E-neighborhood of X in R" is contained in U, we first need to understand what the E-neighborhood of X in R" means. There is no ε > 0 such that the ε-neighborhood of X in R² is contained in U.

The E-neighborhood of X in R" is the set of all points in R" that are within a certain distance E of X. In other words, it is the set of all points that are within E units of distance from any point in X.

Now, we know that X is a subset of (-1, 1) x 0 in R², which means that X consists of all points that lie between the interval (-1, 1) on the x-axis and 0 on the y-axis. We also know that U is an open ball of radius 1 centered at the origin in R², which means that U consists of all points that are within a distance of 1 unit from the origin.

If we assume that there is some € > 0 such that the E-neighborhood of X in R" is contained in U, then we can choose a point in X that is on the x-axis and is at a distance of E units from the origin. Let's call this point A.

Since A is in X, it lies between the interval (-1, 1) on the x-axis and 0 on the y-axis. However, since A is at a distance of E units from the origin, it must lie outside the open ball U of radius 1 centered at the origin.

This contradicts our assumption that the E-neighborhood of X in R" is contained in U. Therefore, there is no € > 0 such that the E-neighborhood of X in R" is contained in U.

To show there is no ε > 0 such that the ε-neighborhood of X in R² is contained in U, consider the following:

Let X denote the subset (-1, 1) x 0 of R², and let U be the open ball B(0, 1) in R², which contains X. Now, let's assume there exists an ε > 0 such that the ε-neighborhood of X is contained in U. This would mean that every point in X has a distance of less than ε to some point in U.

However, consider the point (-1, 0) in X. Since U is the open ball B(0, 1), the distance from (-1, 0) to the center of U, which is the point (0, 0), is equal to 1. Any ε-neighborhood of (-1, 0) in R² would have to include points that are further than 1 unit away from the center of U. This contradicts the assumption that the ε-neighborhood of X is contained in U.

Thus, there is no ε > 0 such that the ε-neighborhood of X in R² is contained in U.

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Answer:

616.788

   OR

616.79 (rounded answer)

Step-by-step explanation:

Answer:

616.78891

Step-by-step explanation:

1 liter is 1.05669 quarts

Good luck!

The length of the two diagonals of a rhombus if one is twice as long as the other are 10 and 20.

Given that the length of two diagonals of the rhombus are 10 and 20.

Let d1 and d2 be the lengths of the diagonals of the rhombus. Since the area of the rhombus is 100, we have:

d1 * d2 / 2 = 100

We are also given that one diagonal is twice as long as the other, so:

d1 = 2d2

Substituting d1 = 2d2 into the first equation, we get:

2d2 * d2 / 2 = 100

d2^2 = 100

d2 = 10 or -10 (we ignore the negative solution)

Since d1 = 2d2, we have d1 = 20.

Therefore, the length of the two diagonals of the rhombus are 10 and 20.

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Answer:

(x+9)(x-9)

Step-by-step explanation:

Answer:

Integer - 72

Decimal - 72.3

Answer:

.here is the answer ............

The inequalities that can represent this situation if m is the number of songs he can buy are:

The above given  inequality accounts for the cost of each song ($1.50) plus the $1.00 activation fee, and it need to be less than or equal to the total amount of $25 on the gift card.

So: 1.5m ≤ 25

Note that this inequality stands for the cost of each song ($1.50) multiplied by the number of songs (m), and it has to  be less than or equal to the total amount of $25 on the gift card.

Hence the options given below are correct.:

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Answer:

oops

Step-by-step explanation:

Answer:

(n+7)x2

Step-by-step explanation:

Based on the given scatterplot the best prediction of weight of the 28 week old dog will be approximately 75 lb pounds.

In the given scatterplot in the x-axis we find the age of the dog in weeks and on the y-axis there is the weight of the dog per each week.

From the given scatterplot after observing closely, we can see that at 28 weeks which is in between 26 and 30, the weight of the dog will be approximately present at 75 lb which is in between 70 lb and 80 lb pounds on the y-axis.

From the above explanation, we can conclude that the weight of the 28 week old dog is 75 lb pounds.

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Given question is not having enough information, so I am attaching the complete question below:

Answer: B. David gained 100 subscribers every 3 months.

Step-by-step explanation:

       The slope of the line shows us the change. First, we will need to find the slope. We will use "rise over run" to do this, resulting in a slope of 100/3. This represents 100 subscribers every three months leading us to answer option B;

             B. david gained 100 subscribers every 3 months

Answer:

I am pretty sure it is the third one

Step-by-step explanation:

Answer:

yea for sure the third one

Step-by-step explanation:

The firm should produce 50 units in order to maximize profit by solving quadratic equations.

To determine the number of units, x, the firm should produce in order to maximize profit, we can start by finding the profit function. Profit is calculated by subtracting the total cost (C) from the total revenue (R).

Profit = Revenue - Cost

The total cost function is given as C = 700 + 1000x dollars, and the total revenue function is given as \(R = 1100x - x^2\) dollars.

Substitute the given functions into the profit equation:

Profit \(= (1100x - x^2) - (700 + 1000x)\)

\(= 1100x - x^2 - 700 - 1000x\\= -x^2 + 100x - 700\)

To find the maximum profit, we need to find the value of x that maximizes the profit function. This can be achieved by finding the vertex of the quadratic equation \(-x^2 + 100x - 700\).

The x-coordinate of the vertex can be found using the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic equation in the form of \(ax^2 + bx + c\).

In this case, a = -1, b = 100, and c = -700.

Plugging these values into the formula, we get:

\(x = -100 / (2 * -1)\\x = 50\)

Therefore, the firm should produce 50 units in order to maximize profit by solving quadratic equations.

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