What is the value of x?

A. 108
B. 37
C. 72
D. 18

The solutions to the equation -30x² + 9x + 60 = 0 are x = 5/2 and x = -4/5.

To solve the equation, we can start by bringing all the terms to one side to have a quadratic equation equal to zero. Let's go step by step:

-5/3 x² + 3x + 11 = -9 + 25/3 x²

First, let's simplify the equation by multiplying each term by 3 to eliminate the fractions:

-5x² + 9x + 33 = -27 + 25x²

Next, let's combine like terms:

-5x² - 25x² + 9x + 33 = -27

-30x² + 9x + 33 = -27

Now, let's bring all the terms to one side to have a quadratic equation equal to zero:

-30x² + 9x + 33 + 27 = 0

-30x² + 9x + 60 = 0

Finally, we have the quadratic equation in standard form:

-30x² + 9x + 60 = 0

Dividing each term by 3, we get:

-10x² + 3x + 20 = 0

(-2x + 5)(5x + 4) = -10x² + 3x + 20

So, the factored form of the equation -30x² + 9x + 60 = 0 is:

(-2x + 5)(5x + 4) = 0

Now we can set each factor equal to zero and solve for x:

-2x + 5 = 0 --> x = 5/2

5x + 4 = 0 --> x = -4/5

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The error made by the student is in simplifying the expression inside the square root.

What is the quadratic equation?

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

The student made an error in simplifying the expression inside the square root.

The expression should be simplified as follows:

25 + 4(2)(-12) = 25 - 96 = -71

So the correct expression inside the square root is -71, not 121.

Therefore, the correct solution using the Quadratic Formula is:

x = (-(-5) ± √((-5)² - 4(2)(-12)))/(2(2))

x = (5 ± √(25 + 96))/4

x = (5 ± √121)/4

x = (5 ± 11)/4

Hence, the solutions are x = -3 and x = 4/2, which simplifies to x = 2.

Therefore, the error made by the student is in simplifying the expression inside the square root.

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The sample that is most likely to yield a representative sample for the poll is "twenty names from each grade pulled blindly from a container filled with the names of the entire student body written on slips of paper."

A representative sample is one that accurately reflects the characteristics of the population from which it is drawn. In this case, Miranda wants to determine how many students would attend a students-only school dance. To achieve this, she needs a sample that represents the entire student body.

The option of selecting twenty names from each grade ensures that the sample includes students from all grades, which is important to capture the diversity of the student body.

By pulling the names blindly from a container filled with the names of the entire student body, the selection process is unbiased and random, minimizing any potential biases that could arise from alternative methods.

The other options have certain limitations that may result in a non-representative sample. For example, selecting every tenth person walking down Main Street may introduce a bias towards students who live or frequent that particular area.

Students who write into the school newspaper may have different interests or characteristics compared to the general student body, leading to a biased sample. Similarly, selecting all the students from Miranda's classes would not represent the entire student body, as it would only include students from those specific classes.

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Answer:

Geometric sequences are the long way to show an exponential function. The initial amount in both exponential functions and geometric sequences do the same thing, which is state the initial value and the value by which it is multiplied. What is called the common ratio in a geometric sequence is basically the second part of what the initial amount does in an exponential function. The nth term in a geometric sequence is the same as the power in an exponential function, that is to say that it shows how many times the sequence is repeated.

Step-by-step explanation:

There are 28 ways to choose 6 teams for the playoffs if there are 8 college basketball teams in a certain sub-division.

To determine the number of ways to choose 6 teams for the playoffs out of the 8 college basketball teams in a certain Sub-Division, we can use the combination formula. The formula for combinations is given by

nCr = n! / (r! * (n-r)!),

where n represents the total number of teams and r represents the number of teams to be chosen.

In this case, n = 8 and r = 6.

Plugging in these values, we have

8C6 = 8! / (6! * (8-6)!) = 8! / (6! * 2!) = (8 * 7) / (2 * 1) = 28.

Therefore, there are total 28 ways to choose 6 teams.

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Answer:

answer Is A.............

The probability of all three golden tickets going to members of the statistics class by chance is low, leading to suspicion that the lottery was rigged.

The probability of one student from the statistics class winning a golden ticket is 30/95. The probability of a second student from the same class winning is 29/94, since one student has already won and there are now 29 eligible students in the class. The probability of a third student from the same class winning is 28/93, given that two students from the class have already won. Therefore, the probability of all three golden tickets going to members of the statistics class is (30/95) × (29/94) × (28/93) ≈ 0.00018, which is a very low probability. This supports the suspicion that the lottery may have been rigged. However, it is important to note that this is only a probability, and further investigation would be necessary to determine if the lottery was actually rigged or if this was just a rare occurrence.

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The expression simplify value is \(48x ^{-9} * y^{10}\)

Simple Rules and Procedures for Any Algebraic Expression

Remove brackets and parentheses by multiplying the appropriate factors.

If the words have exponents, use the exponent rule to eliminate grouping.

By adding or removing coefficients, combine like terms.

Add the constants together.

An expression constructed using integer constants, variables, and algebraic operations is known as an algebraic expression.

In mathematics, an expression that incorporates variables, constants, and algebraic operations is known as an algebraic expression (addition, subtraction, etc.). Terms comprise expressions.

Simplify and Multiply the numbers.

\(6x ^{-9} * 8y^{10} \\48x ^{-9} * y^{10}\)

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Answer:

-20.59=40

+20.59  +20.59

$60.69

hope this helps

Answer: She would need to deposit $60.59

Step-by-step explanation:

She has: -20.59

She needs: 40

-20.59 + x = 40

+ 20.59 on each side

x = 60.59

The required answer is equation of the line is y = -3x.

Explanation:-

To find the equation of the line passing through the points (0,0) and (3,-9), follow these steps:
1. Calculate the slope (m) of the line using the coordinates of the two points:
m = (y2 - y1) / (x2 - x1)
m = (-9 - 0) / (3 - 0)
m = -9 / 3
m = -3

2. Since the line passes through the origin (0,0), the y-intercept (b) is 0.

3. Use the slope-intercept form (y = mx + b) to write the equation of the line:
y = -3x + 0
The equation of the line passing through (0,0) and (3,-9) can be found using the slope-intercept form. First, find the slope using the formula: slope = (y2 - y1)/(x2 - x1) = (-9 - 0)/(3 - 0) = -3.
The equation of the line is y = -3x.

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a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

We have,

a) To calculate the pressure in the production well at 12 hours of a shut-in, we can use the equation for pressure transient analysis during shut-in periods, known as the pressure buildup equation:

P(t) = Pi + (Q / (4πKh)) * log((0.14ϕμCt(t + Δt)) / (Bo(ΔP + Δt)))

Where:

P(t) = Pressure at time t

Pi = Initial reservoir pressure

Q = Flow rate

K = Permeability

h = Reservoir thickness

ϕ = Porosity

μ = Viscosity

Ct = Total compressibility

t = Shut-in time (12 hours)

Δt = Time since the start of the flow period

Bo = Oil formation volume factor

ΔP = Pressure drop during the flow period

Given:

Pi = 3100 psi

Q = 200 STB/day

K = 45 md

h = 60 ft

ϕ = 15%

μ = 1.2 cp

Ct = 15x10^-6 psi^-1

Bo = 1.3 bbl/STB

t = 12 hours

Δt = 48 hours

ΔP = Pi - P(t=Δt) = Pi - (Q / (4πKh)) * log((0.14ϕμCt(Δt + Δt)) / (Bo(ΔP + Δt)))

Substituting the given values into the equation:

ΔP = 3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15x\(10^{-6}\) * (48 + 48)) / (1.3 * (3100 - (200 / (4π * 45 * 60)) * log((0.14 * 0.15 * 1.2 * 15 x \(10^{-6}\) * (48 + 48)) / (1.3 * (0 + 48))))))

After evaluating the equation, we can find the pressure in the production well at 12 hours of shut-in.

b) Superposition in time is a principle used in pressure transient analysis to analyze and interpret pressure build-up tests.

It involves adding or superimposing the responses of multiple transient tests to simulate the pressure behavior of a reservoir.

The principle of superposition states that the response of a reservoir to a series of pressure changes is the sum of the individual responses to each change.

Superposition allows us to combine the information obtained from multiple tests and obtain a more comprehensive understanding of the reservoir's behavior and properties.

It is a powerful technique used in reservoir engineering to optimize production strategies and make informed decisions regarding reservoir management.

Thus,

a) To calculate the pressure at 12 hours of shut-in:

substitute the given values into the pressure buildup equation and solve for P(t=12).

b) Superposition in time is used in pressure buildup analysis by adding or summing the responses of multiple transient tests to analyze and interpret reservoir behavior and properties.

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The equations that have one solution are: 5x – 1 = 3(x + 11) and 4 = 2(x – 3). (option a and c)

Linear equations are mathematical expressions involving variables raised to the power of 1, and they form a straight line when graphed.

5x – 1 = 3(x + 11)

To determine if this equation has one solution, we need to simplify it:

5x – 1 = 3x + 33

Now, let's isolate the variable on one side:

5x – 3x = 33 + 1

2x = 34

Dividing both sides by 2:

x = 17

Since x is uniquely determined as 17, this equation has one solution.

4(x – 2) = 4x

Expanding the parentheses:

4x – 8 = 4x

The variable x cancels out on both sides, resulting in a contradiction:

-8 = 0

This equation has no solution. In mathematical terms, we say it is inconsistent.

8(x – 9) = 4(x – 6)

Expanding the parentheses:

8x – 72 = 4x – 24

Subtracting 4x from both sides:

4x – 72 = -24

Adding 72 to both sides:

4x = 48

Dividing both sides by 4:

x = 12

As x is uniquely determined as 12, this equation has one solution.

4 = 2(x – 3)

Expanding the parentheses:

4 = 2x – 6

Adding 6 to both sides:

10 = 2x

Dividing both sides by 2:

5 = x

Since x is uniquely determined as 5, this equation has one solution.

2(x – 4) = 5(x – 3)

Expanding the parentheses:

2x – 8 = 5x – 15

Subtracting 2x from both sides:

-8 = 3x – 15

Adding 15 to both sides:

7 = 3x

Dividing both sides by 3:

7/3 = x

The value of x is not unique in this case, as it is expressed as a fraction. Therefore, this equation does not have one solution.

2(x – 1) + 3x = 5(x – 2) + 3

Expanding the parentheses:

2x – 2 + 3x = 5x – 10 + 3

Combining like terms:

5x – 2 = 5x – 7

Subtracting 5x from both sides:

-2 = -7

This equation leads to a contradiction, which means it has no solution.

Hence the correct options are a and c.

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There is not sufficient evidence to claim that the average age of a US adult getting married is different than 27 years old.

μ₀ = 27

h = 30

X = 26

σ = 7

Hypothesis test at α = 0.025

Null & Alternative hypothesis

H₀: μ = 27

Ha: μ = 27

Test statistics = Z

Z= x-μ/(σ/√h)

= 26-27/(7/√30)

Z = -0.78

p-value

p-value from Z-table at |Z|= 0-78,

two-tailed is p-value = 0.4354

decision-

here p-value = 0-4354 > α=0·025 Since we fail to reject H₀ at 2.5%

Hence, there is not sufficient evidence to claim that the average age of a US adult getting married is different than 27 years old.

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\((\stackrel{x_1}{1}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{\textit{\large run}} {\underset{x_2}{3}-\underset{x_1}{1}}} \implies \cfrac{ 2 }{ 2 } \implies 1\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ 1}(x-\stackrel{x_1}{1})\implies y-1=x-1\implies \boxed{y=x}\)

Answer: y=x+2

Step-by-step explanation: to find the slope use the formula y2-y1/x2-x1 which will get 3-1/3-1= 2/2= 1 so the slope is one. then take formula (y-y1)=m(x-x1) m is slope so you will get (y-3)=1(x-1) distribute the one y-3=x-1 add three to both sides to get y=x+2

You don't have to only use the ends! Please check the attached image:)

Answer:

1.33

Step-by-step explanation:

4/3 use triangle method

Answer: -35x + 10

Step-by-step explanation:

Since there is no equal sign, you can only simplify the expression.

-5 (7x - 2)

You need to use distributive property (multiply the number outside the brackets by the numbers inside the bracket.

-5 x 7x = -35x

-5 x -2 = 10

Therefore, the answer is -35x + 10

Answer:

20

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

15/3 x 4/1 = 60/3  

60/3 simplified is 20/1 or 20! Hope this helps!

Remember that

The rule of a reflection over the line y=-x is equal to

(x,y) ------> (

The lines intersect to form a rectangular prism, therefore the plane that is parallel to EFG is BCD. option D

We should know that in plane geometry, parallel lines do not intersect and intersecting lines form angles at the points of intersection.

To determine the similarity of the lines, Let us consider the following lines

From the rectangular prism

EF//AB

BC//FG

GH//CD

AD//EH

Each of the lines lies on opposite side of the rectangular prism.

Also, quadrilateral ABCD ≡ Quadrilateral EFGH

In conclusion, the plane that is parallel to EFG is BCD.

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Answer:

12 x 12 = 144 divided by 2 = 72, 72 is your answer formula of a triangle: BH x 1/2

Step-by-step explanation:

72 square cm

I was just about to ask this question

Step-by-step explanation:

Im on this question rn, i need help to :(

Answer:  just guess :)

Step-by-step explanation:

Answer:

180 m

Step-by-step explanation:

Answer:

Answer

4.9/5

345

author link

audreyburkett12

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Assuming the time changes at a constant rate, the equation for this is linear (so has the equation y=mx +c)

8am = -2

9am = -0.5

10am = 1.0

11am = 2.5

12pm = 4

m = change in each value or the slope , for this it is m=1.5

c = the y intercept, we find this by: when x=8 y must = 1.5 , which it isn't , y has to = -2 . So c = -3.5

The equation then is: y= 1.5*x - 3.5

The gradient/slope/m value is 1.5. The answer is 1.5

Answer:

Don't fail

Step-by-step explanation:

9514 1404 393

Answer:

  WR ≅ WX

Step-by-step explanation:

To use the SAS postulate, you need congruent sides bounding a congruent angle.

Here, side WP is one side of one of the vertical angles, ∠PWR, so you need the other side of that angle: WR. The corresponding side in triangle VWX is WX. That is, for SAS, you need WR ≅ WX.

We need to determine the cost of the ring if it was sold for $325, and the profit made on selling it for $63 more than that was $89.

The formula to find out the original price of the ring is:

Cost price of the ring = Sale price of the ring - Profit earned.

Substituting the values we get:

Cost price of the ring = $325 - $89 - $63.

Cost price of the ring = $173.

Therefore, the cost of the ring was $173.

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The required Matlab code to find the greatest common divisor of a number using the Euclidean algorithm is shown.

To find the greatest common divisor (GCD) of two numbers using the Euclidean algorithm in MATLAB, you can use the following code:

% Replace '12345678' with your actual student number

studentNumber = '12345678';

% Extract the first 4 digits as the first number

firstNumber = str2double(studentNumber(1:4));

% Extract the last 3 digits as the second number

secondNumber = str2double(studentNumber(end-2:end));

% Find the GCD using the Euclidean algorithm

gcdValue = gcd(firstNumber, secondNumber);

% Display the result

disp(['The GCD of ' num2str(firstNumber) ' and ' num2str(secondNumber) ' is ' num2str(gcdValue) '.']);

Make sure to replace '12345678' with your actual student number. The code extracts the first 4 digits as the first number and the last 3 digits as the second number using string indexing. Then, the gcd function in MATLAB is used to calculate the GCD of the two numbers. Finally, the result is displayed using the disp function.

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Answer:

only the inverse is a function

Answer:

0.02941176...

— Used a calculator for this, so it is guarantied correct! Hope this helps. Brainliest appreciated (and very much needed)

Answer:

d=6 2/3 or 6.6666

Step-by-step explanation:

3(d+4)=32

3d+12=32

3d=32-12

3d=20

d=6 2/3 or 6.6666