Answer:
Choice A
Step-by-step explanation:
Base = 10
Perpendicular = 10
Hypotenuse = x
On applying Pythagoras theorem:
\( \rm \: B^2+P^2 = H^2\)
B = baseP = perpendicularH = heightOn substituting,
\(10 {}^{2} + 10 {}^{2} = x {}^{2} \)Simplifying,
\(100 + 100 = x {}^{2} \)\(20 0 = {x}^{2} \)\( \sqrt{200} = {x}^{} \)\(10 \sqrt{2} = x\)Hence,the value of x using Pythagoras theorem is 10√2.
Choice A
The measure of length of x of the triangle is x = 10√2
What is a Triangle?A triangle is a plane figure or polygon with three sides and three angles.
A Triangle has three vertices and the sum of the interior angles add up to 180°
Let the Triangle be ΔABC , such that
∠A + ∠B + ∠C = 180°
The area of the triangle = ( 1/2 ) x Length x Base
For a right angle triangle
From the Pythagoras Theorem , The hypotenuse² = base² + height²
if a² + b² = c² , it is a right triangle
if a² + b² < c² , it is an obtuse triangle
if a² + b² > c² , it is an acute triangle
Given data ,
Let the triangle be represented as ΔABC
Now , the measure of side AB = 10
The measure of side BC = 10
And , For a right angle triangle
From the Pythagoras Theorem , The hypotenuse² = base² + height²
On simplifying , we get
The measure of side AC = x
x = √ ( 10 )² + ( 10 )²
x = √200
x = 10√2
Hence , the measure of x of triangle is x = 10√2
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Consider the following joint probability density function of the random variables X and Y: f(x, y) = 3x−y/9 , 1
(a) Find the marginal density functions of X and Y
(b) Evaluate P(X > 2, Y > 1.5)
(c) Are X and Y independent?
The marginal density functions of the joint probability density functions, X and Y (a) \(f(x) = \frac{2x-1}{6}, f(y) = \frac{2}{9} (6-y)\)
(b) P(X>2, Y>1.5 ) = 0.3194
(c) X and Y are not independent
The given function is :
\(f(x) =\frac{3x-y}{9} , 1 < x < 3 , 1 < y < 2 and 0 , eleswhere\)
(a) Marginal Density Functions of X and Y are
\(f_{x}(x) =\int\limits^2_1{f(x,y)} \, dy =\int\limits^2_1{\frac{3x-y}{9} } \, dy =\frac{1}{9} [2xy -\frac{y^{2} }{2} ]^{2} _{1} = \frac{1}{9}(3x-\frac{3}{2}=\frac{2x-1}{6} , 1 < x < 3\\ f(x) = \frac{2x-1}{6}, 1 < x < 3\)
\(f_{y}(y) = \int\limits^3_1{f(x,y)} \, dx = \int\limits^3_1{\frac{3x-y}{9} } \, dx =\frac{2}{9}(6-y)\\ f_{y}(y) = \frac{2}{9}(6-y) , 1 < y < 2\)
(b) P(X>2, Y>1.5)
\(=\int\limits^2_\frac{3}{2} \int\limits^3_2 {f(x,y)} \, dxdy \\ =\int\limits^2_\frac{3}{2} {[\int\limits^3_2 {\frac{3x-y}{9} } \, dx }] \, dy \\=0.3194\)
(c) To check whether X and Y are independent, we have:
\(f_{x}(x) =\frac{2x-1}{6} ,f_{y} (y) =\frac{2(6-y)}{9} \\ X,Y are independent if \\f_{xy} =f_{x}*f_{y} = \frac{2x-1}{6}*\frac{2(6-y)}{9} \\=\frac{1}{27}(12x+y-2xy-6)\\ \neq f(x,y)\)
Therefore, X and Y are not independent.
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Given the following point on the unit circle, find the angle, to the nearest tenth of a
degree (if necessary), of the terminal side through that point, 0° ≤0 < 360°.
The angle, which is on the third quadrant, is 233.13°
How to find the angle?
Here we want to find an angle whose terminal side passes through the point (-3/5, -4/5)
Notice that both coordinates are negative, thus, this is on the third quadrant.
To get the angle we need to take the inverse tangent of the quotient between the y-coordinate and the x-coordinate.
angle = Atan(-4/5/-3/5)
angle = 53.13°
And the angle is on the third quadrant, so we need to add 180°, then we will get:
angle = 53.13° + 180° = 233.13°
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Use the given function and the given interval to complete parts a and b. f(x)=2x 3 −30x 2+126x on [2,8] a. Determine the absolute extreme values of f on the given interval when they exist. b. Use a graphing utility to confirm your conclusions. a. What is/are the absolute maximum/maxima of f on the given interval? Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The absolute maximum/maxima is/are at x= (Use a comma to separate answers as needed. Type exact answers, using radicals as needed.) B. There is no absolute maximum of f on the given interval.
The absolute maximum of f on the given interval is at x = 8.
We have,
a.
To determine the absolute extreme values of f(x) = 2x³ - 30x² + 126x on the interval [2, 8], we need to find the critical points and endpoints.
Step 1:
Find the critical points by taking the derivative of f(x) and setting it equal to zero:
f'(x) = 6x² - 60x + 126
Setting f'(x) = 0:
6x² - 60x + 126 = 0
Solving this quadratic equation, we find the critical points x = 3 and
x = 7.
Step 2:
Evaluate f(x) at the critical points and endpoints:
f(2) = 2(2)³ - 30(2)² + 126(2) = 20
f(8) = 2(8)³ - 30(8)² + 126(8) = 736
Step 3:
Compare the values obtained.
The absolute maximum will be the highest value among the critical points and endpoints, and the absolute minimum will be the lowest value.
In this case, the absolute maximum is 736 at x = 8, and there is no absolute minimum.
Therefore, the answer to part a is
The absolute maximum of f on the given interval is at x = 8.
b.
To confirm our conclusion, we can graph the function f(x) = 2x³ - 30x² + 126x using a graphing utility and visually observe the maximum point.
By graphing the function, we will see that the graph has a peak at x = 8, which confirms our previous finding that the absolute maximum of f occurs at x = 8.
Therefore,
The absolute maximum of f on the given interval is at x = 8.
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What is an example of a positive and negative correlation?
positive correlation :relationship between the number of hours a student studies and their grade point average (GPA).
negative correlation :relationship between the number of hours a student spends watching television and their grade point average (GPA).
Correlation is a statistical term that describes the relationship between two variables. When two variables are positively correlated, it means that as one variable increases, the other variable also increases. When two variables are negatively correlated, it means that as one variable increases, the other variable decreases.
An example of a positive correlation is the relationship between the number of hours a student studies and their grade point average (GPA). As the number of hours a student studies increases, their GPA also tends to increase. This is a positive correlation because both variables are increasing together.
An example of a negative correlation is the relationship between the number of hours a student spends watching television and their grade point average (GPA). As the number of hours a student spends watching television increases, their GPA tends to decrease. This is a negative correlation because one variable is increasing while the other is decreasing.
It's important to note that correlation does not imply causation. Just because two variables are correlated it does not mean that one variable causes the other. It could be that some other variable is causing both variables to change, or that the relationship is not causal at all.
In summary, correlation is a statistical term that describes the relationship between two variables. Positive correlation means that as one variable increases, the other variable also increases.
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Madison bought a bike that was marked down by $25.00. If the percent it was marked
down was 20%, what did the bike originally cost
The original cost of the bike is $20
What is percentage ?
A percentage is a figure or ratio stated as a fraction of 100 in mathematics. Although the abbreviations "pct," the percent sign, "%," is frequently used to indicate it. A % is a number without dimensions and without a standard measurement.
In essence, percentages are fractions with a 100 as the denominator. We place the percent symbol (%) next to the number to indicate that the number is a percentage. For instance, you would have received a 75% grade if you answered 75 out of 100 questions correctly on a test (75/100).
A fraction of 100 is represented as a number or ratio known as a percentage. A dimensionless relationship between two numbers can be represented in a variety of ways, such as through ratios, fractions, and decimals.
Let x be the discount
20/100 = x / 25
1/5 = x/25
x = 25/5
x = 5
The discount is 5
The original cost is
$25 - $5
= $20
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-x + 3y = -27 3x - 3y = 39
Answer: Is there any answer choices?
Step-by-step explanation:
Answer Both Questions
Frankiln are 3/4 of an energy bar before his baseball game. Trey ate 2/3 of what Franklin ate. What fraction of an energy bar did Trey eat?
Colin was helping his uncle clean up a construction site. Colin's job was to make a neat stack of scrap wood. Each piece of wood was 1 3/8 inches thick. At the end if the day, Colin's stack was 57 3/4 inches tall. How many pieces of wood were in Colin's stack?
Answer:
a) 1/2 of an energy bar
b) 42 pieces
Step-by-step explanation:
a) Here, Franklin are 3/4 of an energy bar while Trey are 2/3 of what Franklin ate
The fraction are by Trey is 2/3 * 3/4 = 6/12 = 1/2
b) To find the number of pieces of wood present, we will need to divide the height of Colin’s stack by the thickness of each piece of wood
Mathematically, that will be;
57 3/4 divided by 1 3/8
= 231/4 * 8/11 = 42 pieces
Answer:
kejorrerprpfffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
Find the exact value of the expression whenever it is defined. (If an answer is undefined, enter UNDEFINED.) (a) arcsin(sin13π/12) (b) arccos(cos 8π/5) (c) arctan(tan 11π/9)
a. the exact value of arcsin(sin(13π/12)) is **π/12**. b. the value of arccos(cos(8π/5)) is **UNDEFINED**. c. the exact value of arctan(tan(11π/9)) is **5π/9**.
(a) To find the exact value of arcsin(sin(13π/12)), we need to determine the angle whose sine is equal to sin(13π/12). However, it's important to note that the range of the arcsin function is [-π/2, π/2].
The reference angle for 13π/12 is π - (13π/12) = π/12, which lies in the range of the arcsin function. Furthermore, the sine function is positive in both the first and second quadrants, so the angle will be positive.
Therefore, the exact value of arcsin(sin(13π/12)) is **π/12**.
(b) For arccos(cos(8π/5)), we need to find the angle whose cosine is equal to cos(8π/5). The range of the arccos function is [0, π].
The reference angle for 8π/5 is 8π/5 - 2π = -2π/5, which is negative and not within the range of the arccos function. Hence, the expression is undefined.
Therefore, the value of arccos(cos(8π/5)) is **UNDEFINED**.
(c) In the case of arctan(tan(11π/9)), we are looking for the angle whose tangent is equal to tan(11π/9). The range of the arctan function is (-π/2, π/2).
The reference angle for 11π/9 is 11π/9 - 2π = 5π/9, which is within the range of the arctan function. Therefore, the exact value of arctan(tan(11π/9)) is **5π/9**.
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answer emergency pleaseee
Answer:number D
Step-by-step explanation:
50 55 and keep going up
Please help me on my assignment I have to do it before taking the test
Answer:
26
Step-by-step explanation:
w = 5 so 7w is 7 x 5 = 35 and x = 9 so it’s 35 - 9 which is 26
Are the two shapes similar?
Answer:
Yes they are same shape but different size
Step-by-step explanation:
Which rule describes the composition of transformations that maps δbcd to δb"c"d"? translation of 5 units x, negative 6 units y composition reflection across y = negative x reflection across y = negative x composition translation of 5 units x, negative 6 units y. translation of 6 units x, negative 5 units y composition reflection across the y-axis reflection across the y-axis composition translation of 6 units x, negative 5 units y
The rule which describe the composition of transformations that
maps ΔBCD to ΔB"C"D" is:
Reflection across the y-axis composition translation of 6 units x,
negative 5 units y ⇒ last answer
Step-by-step explanation:
Let us revise the reflection across the y-axis , horizontal translation
and vertical translation
1. If point (x , y) is reflected across the y-axis, then its image is (-x , y)
2. If point (x , y) is translated h units to the right, then its image is
(x + h , y), if translated h units to the left, then its image is (x - h , y)
3. If point (x , y) is translated k units up, then its image is (x , y + k),
if translated k units down, then its image is (x , y - k)
∵ The vertices of triangle BCD are (1 , 4) , (1 , 2) , (5 , 3)
∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)
∵ The x-coordinates of the vertices of Δ B'C'D' have the same
magnitude of x-coordinates of Δ BCD and opposite signs
∴ Δ B'C'D' is the image of Δ ABC after reflection across the y-axis
∵ The vertices of triangle B'C'D' are (-1 , 4) , (-1 , 2) , (-5 , 3)
∵ The vertices of triangle B''C''D'' are (5 , -1) , (5 , -3) , (1 , -2)
∵ The image of -1 is 5 and the image of -5 is 1
∴ The x-coordinates of the vertices of triangle B'C'D' are added by 6
∵ The image of 4 is -1 , image of 2 is -3 and the image of 3 is -2
∴ The y-coordinates of the vertices of triangle B'C'D' are subtracted
by 5
∴ Δ B"C"D" is the image of Δ B'C'D' by translate 6 units to the right
and 5 units down ⇒ (x + 6 , y - 5)
The rule which describe the composition of transformations that
maps ΔBCD to ΔB"C"D" is:
Reflection across the y-axis composition translation of 6 units x,
negative 5 units y
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The composition of transformations that maps BCD to B"C"D" is described by the following rule:
Composition translation of 6 units x, negative 5 units y across the y-axis last response
Let us rewrite the y-axis reflection, horizontal translation, and vertical translation.
1. If point (x, y) is mirrored across the y-axis, the image of that point is (-x , y)
2. If point (x, y) is translated h units to the right, its image is (x + h, y), and if it is translated h units to the left, its image is (x + h, y) (x - h , y)
3. If point (x, y) is translated k units up, its image is (x, y + k), but if it is translated k units down, its image is (x , y - k)
∵ Triangle BCD has (1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. Triangle B'C'D' has (-1, 4) vertices, (1, 2) vertices, and (5, 3) vertices. The x-coordinates of the B'C'D' vertices have the same magnitude as the x-coordinates of BCD and opposite signs. B'C'D' is the picture of ABC after it has been reflected across the y-axis.
The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3), (1, -2)
The vertices of triangle B"C"D" are (5, -1), (5, -3), (1, -2)
The x-coordinates of the triangle B'C'D' vertices are added by 6.
The image of 4 is -1, the image of 2 is -3, and the image of 3 is -2.
The y-coordinates of triangle B'C'D' vertices are subtracted by 5.
∴ Δ B"C"D" is the image of Δ B'C'D' by translating 6 units to the right
and 5 units down ⇒ (x + 6 , y - 5)
The rule which describe the composition of transformations that
maps ΔBCD to ΔB"C"D" is:
Reflection across the y-axis composition translation of 6 units x,
negative 5 units y
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What are the x and y values?
Answer: x=55, y=65
Step-by-step explanation:
What’s the answers ?
hope this helps! feel free to clarify if unsure
Any help, please!
I dont understand
During the year, Green, Inc., incurs the following research expenditures:In-house wages, supplies, computer time $60,000Paid to Blue Foundation for research $30,000Green's qualifying research expenditures for the year are:a. $60,000b. $75,000c. $79,500d. $90,000e. None of these
Green, Inc.'s qualifying research expenditures for the year can be calculated by adding the in-house research expenditures to the payments made to a qualified research organization, such as the Blue Foundation.
Using this formula, we can calculate the qualifying research expenditures for the year as follows:
$60,000 + $30,000 = $90,000
Therefore, the answer is (d) $90,000.
In-house research expenditures, such as wages, supplies, and computer time, qualify as research expenditures for tax purposes. Payments made to a qualified research organization also qualify as research expenditures. To determine the total qualifying research expenditures for the year, these two types of research expenditures must be added together.
In the given scenario, Green, Inc. incurred $60,000 in in-house research expenditures and paid $30,000 to the Blue Foundation for research. Adding these two amounts together, the qualifying research expenditures for the year are $90,000.
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What way of warming up is preferred after exercise?
A. Static
B. Dynamic
C. Calestitic
D. Isometric
Answer:
Static
Step-by-step explanation:
By process of elimination, static is the only one that would work.
Answer:
static.
Step-by-step explanation:
\(\\ \leq \int\limits^a_b {x} \, dx x^{2} \sqrt{x} \sqrt[n]{x} \leq \geq \neq \lim_{n \to \infty} a_n \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right.\)
Solve the following expressions. Write your answer in scientific notation. 13. (6.125×10 3
)×(2.345×10 4
) 14. (6.125×10 3
)×(2.345×10 −4
) 15. 3700.13×(6.04×10 4
) 16. (6.2×10 4
)/(0.4×10 −5
)
13) The scientific notation is 1.4354125 * 10⁸. 14) The scientific notation is 1.4354125 * 10⁻¹. 15) The scientific notation is 22366.0992. 16) The scientific notation is 1.55 * 10¹⁰.
Let's solve the given expressions and write the answers in scientific notation:
13) \((6.125*10^3) * (2.345*10^4)\)
To multiply the numbers in scientific notation, we multiply the coefficients and add the exponents:
\((6.125 * 2.345) * (10^3 * 10^4) = 14.354125 * 10^(3 + 4) = 14.354125 * 10^7 = 1.4354125 * 10^8\)
\(= 1.4354125 * 10^8\)
14) \((6.1258*10^3) * (2.345*10^{-4})\)
To multiply the numbers in scientific notation, we multiply the coefficients and add the exponents:
\((6.125 * 2.345) * (10^3 * 10^{-4}) = 14.354125 * 10^{3 - 4} = 14.354125 * 10^{-1} = 1.43541258* 10^{-1}\)
\(= 1.4354125 * 10^{-1}\)
15) \(3700.13 * (6.04*10^4)\)
To multiply a decimal number and a number in scientific notation, we simply multiply the decimal by the coefficient of the scientific notation:
3700.13 × 6.04 = 22366.0992
Since the answer does not need to be expressed in scientific notation, the result is 22366.0992.
= 22366.0992
16) \((6.2*10^4) / (0.4*10^{-5})\)
To divide numbers in scientific notation, we divide the coefficients and subtract the exponents:
\((6.2 / 0.4) * (10^4 / 10^{-5}) \\= 15.5 * 10^{4 - (-5}) \\= 15.5 * 10^9 \\= 1.55 * 10^{10}\\= 1.55 * 10^{10}\)
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(A) Find the midpoint of the segment
(B) Find the length of the segment
Answer:
The midpoint is (1, 3) and the length of the segment (let's call it AB) is 6.32
Step-by-step explanation:
Answer:
A) (1, 3)
B) \(2\sqrt{10}\\\)
Step-by-step explanation:
A) We are finding the averages of the x and y values. The midpoint formula is as so:
(x1 + x2/2, y1 + y2/2)
(-2+4/2 , 4+2/2)
(2/2 , 6/2)
(1.3)
With distance, the formula is\(\sqrt{(x_{1} -x_{2})^{2} + (y_{1} -y_{2})^{2}\)
\(\sqrt{(4-(-2))^{2} + (2-4)^{2}\)
\(\sqrt{(6)^{2} + (-2)^{2}\)
\(\sqrt{36 + 4}\)
\(\sqrt{40}\)
\(2\sqrt{10}\)
THIS FORMULA OPTION GAVE ME THE HARDEST TIME-
Find the height of a cuboid if it's length is 15cm, it's breath is 12cm and it's total surface are is 900cm
Answer: \(h=8.33\ cm\)
Step-by-step explanation:
Given
The length of a cuboid is \(l=15\ cm\)
breadth is \(b=12\ cm\)
Total surface area is \(S.A.=900\ cm^2\)
Surface area is given by \(2(lb+hl+bh)\)
Insert the values
\(\Rightarrow 900=2(15\times 12+15h+12h)\\\Rightarrow 450=225+27h\\\Rightarrow 225=27h\\\Rightarrow h=8.33\ cm\)
Determine the length of the line segment shown. line segment from negative 2 comma 2 to 2 comma negative 1
Answer:
5
Step-by-step explanation:
You want the length of the line segment between (-2, 2) and (2, -1).
Pythagorean theoremThe relation between the side lengths of a right triangle is given by the Pythagorean theorem. It tells you ...
c² = a² +b²
where c is the hypotenuse of the triangle, and 'a' and 'b' are the legs.
Leg lengthsWhen you plot the points on a grid, you can identify the vertical and horizontal distances between them by counting grid squares, or by finding the difference of coordinates:
AB = B -A = (2, -1) -(-2, 2) = (2 +2, -2 -2) = (4, -3)
The point on the right is 4 horizontal units and 3 vertical units from the point on the left.
Segment lengthThe above relation tells us the segment length is ...
c² = 4² +3² = 16 +9 = 25
c = √25 = 5
The length of the line segment is 5 units.
__
Additional comment
The integer triple of segment lengths that form a right triangle is called a "Pythagorean triple." The one relevant to this problem is {3, 4, 5}. Others often seen in algebra, trig, and geometry problems are ...
{5, 12, 13}, {7, 24, 25}, {8, 15, 17}, {9, 40, 41}
and multiples of these. If you become familiar with these triples, you can often write down the answer to a question like this simply by recognizing the dimensions involved.
What is the result of converting 60 ounces to punds remember there are 16 ounces in a pound pleasdnsjjsjs
Answer:
A. 3.75 pounds
Step-by-step explanation:
16 ounces = 1 pound
converting 60 ounces to pounds
Let x = number of pounds
60 ounces = x pounds
Find the proportion
16 / 1 = 60 / x
Cross product
16 * x = 1 * 60
16x = 60
Divide both sides by 16
x = 60/16
x = 3.75
Therefore,
60 ounces = 3.75 pounds
if $x$ is an element of the set $\{ -1, 1, 2 \}$ and $y$ is an element of $\{ -2, -1, 0, 1, 2 \}$, how many distinct values of $x^y$ are positive?
If \($x$\) is an element of the set \($\{ -1, 1, 2 \}$\) and \($y$\) is an element of \($\{ -2, -1, 0, 1, 2 \}$\), the number of distinct values of \($x^y$\) that are positive is 5.
When the base is positive, the exponent produces positive powers.
Now, let's evaluate the power for each possible combination of \($x$\) and \($y$\):
For \($x = -1$\) and \($y$\) being an even number, we get a positive power. Here are the possible even values for \($y$\):
\($y = -2$\) and \($y = 0$\). Therefore, \($x^y$\) is positive for two possible combinations: \($(-1)^{-2} = 1$\) and \($(-1)^{0} = 1$\).
For \($x = 1$\) and any value of \($y$\), the power of \($x$\) is always positive, and the value of \($x$\) is always 1. Therefore, there's only one possible combination: \($1^y = 1$\).
For \($x = 2$\) and \($y$\) being an even number, we get a positive power. Here are the possible even values for \($y$\):
\($y = -2$\) and \($y = 0$\). Therefore, \($x^y$\) is positive for two possible combinations: \($2^{-2} = 1/4$\) and \($2^{0} = 1$\)
For \($x = 2$\) and \($y$\) being an odd number, we get a negative power. Here are the possible odd values for \($y$\):
\($y = -1$\) and \($y = 1$\). Therefore, \($x^y$\) is positive for zero possible combinations.
Therefore, the total number of distinct values of \($x^y$\) that are positive is \($2+1+2 = 5$\).
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During a walk, walkers discover a car that has fallen to the bottom of a 20m high vertical cliff. It is 10m from the foot of the cliff. The police investigation reveals that the braking marks (perpendicular to the edge) start at 7.5m from the upper (horizontal) edge of the cliff and that the acceleration (braking!) was -5m/s. The chief sergeant concludes an accident. Calculate the speed of the car before the start of braking and the duration of the driver's anxiety (braking & fall).After the calculation, I got t1 from cliff = 2 sec, I got the Vf from the baking = 5m/s, I need to find V0 before baking (using this formula = d=v0t+1/2at^2),
Given, Height of the cliff = 20 m Distance of the car from the foot of the cliff = 10 m.
The time taken by the car to fall from the cliff can be found using the formula:
\(`h = (1/2) g t^2`\)
Where h is the height of the cliff, g is the acceleration due to gravity and t is the time taken by the car to fall from the cliff.
Substituting the given values,`20 = (1/2) × 9.8 × t^2`
Solving for t, `t = sqrt(20/4.9)` = 2.02 s
Let the initial velocity of the car be V0 and the time taken for the car to come to rest after applying brakes be t1.
Distance covered by the car before coming to rest can be found using the formula: `\(s = V0t1 + (1/2) (-5) t1^2\)`
Where s is the distance covered by the car before coming to rest.
Simplifying the above equation,\(`2.5 = V0 t1 - (5/2) t1^2`\)
Substituting the given values,`5 = V0 - 5 t1`
Solving the above two equations,\(`V0 = 32.5/2 t1`\)
Simplifying the above equation,`V0 = 16.25 t1`
Substituting the value o\(f t1,`V0 = 16.25 × 2` = 32.5 m/s\)
Therefore, the speed of the car before the start of braking is 32.5 m/s.
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i just need it solve thats all
Answer:
A and 1/3
Step-by-step explanation:
Which of these is the standard form of the following function?
f(x) = -9(x + 5)2 + 4
f(x) = 9x2 − 90x − 221
f(x) = -9x2 − 90x − 221
f(x) = 9x2 − 180x + 221
f(x) = -9x2 − 180x − 221
Answer:
We conclude that the standard form of the given function is:
\(f(x)=-9x^2-90x-221\)
Hence, option B is correct.
Step-by-step explanation:
We know that the standard form of the quadratic function is of the form
\(f\left(x\right)\:=\:ax^2\:+\:bx\:+\:c\)
Given the function
\(f(x)=-9\left(x\:+\:5\right)^2\:+\:4\)
as (x+5)² = x² + 10x + 25
\(f(x)=-9\left(x^2+10x+25\right)+4\)
Expanding -9(x² + 10x + 25) = -9x² - 90x - 225
\(f\left(x\right)\:=-9x^2-90x-225+4\)
simplifying
\(f(x)=-9x^2-90x-221\)
Therefore, we conclude that the standard form of the given function is:
\(f(x)=-9x^2-90x-221\)
Hence, option B is correct.
Answer:
Hope this helps!
Step-by-step explanation:
Please please help me
Step-by-step explanation:
please mark me as brainlest
A rectangular balcony is 14 feet long and 6 feet wide. What is its area?
Answer:
I will do
Step-by-step explanation:
length of balcony: 14 feet
Breadth of balcony:6 feet
area of rectangular balcony: length ×breadth
answer 14ft × 6ft = 84ft²
BREADTH MEANS WIDE
ILL BRAINLIEST YOU IF YOU HELP ME PLEASE
option C is correct because a line bisecting parallel lines makes the same angle on each line at the point of intersection
so they all will make 61°
Mrs Majhi deposited a certain amount in her bank account at the rate of
6.5% p.a. If she paid 5% of her interest as income tax and received Rs 4940 net
interest after 4 years, how much money was deposited by her?
Answer:
Rs 20000------------------
Let the amount deposited be x. It is assumed we are talking about simple interest.
After 4 years the interest amount is:
4*0.065*x = 0.26x95% of this amount is Rs 4940:
0.95(0.26x) = 4940x = 4940/0.247x = 20000Mrs Majhi deposited Rs 20000.
Mrs. Majhi deposited Rs 20000 in her bank account. This was calculated by first finding the total interest (before tax) and then using the formula for simple interest to determine the principal amount.
Explanation:The question is based on the concepts of Simple Interest and taxation. We know that Mrs Majhi received Rs 4940 as net interest after 4 years and this amount is 95% of the total interest (since 5% was paid as income tax). The total interest can be calculated as (4940 / 95) * 100 = Rs 5200.
The rate of interest is given as 6.5% per annum. Thus, the money deposited (Principal) by her can be calculated using the formula for simple interest (I = PRT/100), where P is the Principal, R is the rate of interest, and T is the time. Re-arranged to calculate the Principal (P), it becomes P = I / (R*T) = 5200 / (6.5*4) = Rs 20000.
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